Alex had 23.74 to spend on clothes. He bought a T-shirt that cost 12.50. Write and equation to represent how much money (m) Alex has left. Then solve for m.

Answer:

MN = 25

Step-by-step explanation:

If LN=45, then the addition of both quantities will be 45.

LN = 3x + 2 + x + 19

3x + 2 + x + 19 = 45

4x + 21 = 45

4x = 45 - 21 = 24

x = 6

Now that we found the value of "x", we can find the lenght of MN

MN = x + 19

MN = 6 + 19

MN = 25

Hope it was helpful ;)

Answer: MN = 25

Step-by-step explanation:

Since the length is already given we just add the equations equal to it.

45 =  3x + 2 + x + 19  Combine like terms

45 = 4x + 21               Subtract 21 from both sides

24 = 4x                       Divide by 4

x = 6

Now we plug x into the equation needed.

X + 19

6 + 19 = 25

Answer: 25

Step-by-step explanation:

Answer:

49min

Step-by-step explanation:

Answer:

c. 49min

Step-by-step explanation:

The total number of pounds of nitrogen that is found in the lawn fertilizer would be = 20 pounds of nitrogen.

To calculate the quantity of pounds of nitrogen, the ratio of nitrogen to phosphorus is used as follows;

Nitrogen: phosphorus = 5:2

Total = 5+2=7 pounds in each bag.

The total number of bags = 4 bags

The total number of pounds = 7×4=28

For nitrogen;

= 5/7× 28/1

= 20 pounds of nitrogen.

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Answer:

The initial value of the function y = 5.7x + 6 is 6.

The  step that  is included in the construction of a perpendicular line through a point off the line is  B: Connect arcs that are either above or below the original line and a point off the line with a straightedge.

Perpendicular lines can be regarded as the lines that intersect at a 90-degree angle.

for  instance,  line AB is perpendicular to line CD, hence, The  step that  is included in the construction of a perpendicular line through a point off the line is  B: Connect arcs that are either above or below the original line and a point off the line with a straightedge.

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CHECK THE COMPLETE QUESTIOPN BELOW:

Question 1 Multiple Choice Worth 1 points)

(01.03 LC)

Which of the following steps is included in the construction of a perpendicular line through a point off the line?

A: Connect arc above the line with arcs below the given line

B: Connect arcs that are either above or below the original line and a point off the line with a straightedge

C: Create arcs on either side of a point that is off the given line

D: Create a copied angle by using the first two lines as the original angle

Answer: b

Step-by-step explanation:

Answer:

-3

Step-by-step explanation:

{2/3 × 0} -3

{0} -3

0-3 = -3

The acceleration vector can be represented as a(t) = dv(t)/dt = m/s² (î + j). The expression for the acceleration vector as a function of time (in m/s²) is given by a(t) = m/s²(î + j).

Let the position of the ball at time t be given by vector r(t). Using the given information ,r(t) = mî + mj

Here, î and j are the unit vectors. Taking the first derivative of position gives the expression for velocity.

The derivative of the position function with respect to time gives the velocity function. The velocity vector can be represented as v(t) = dr(t)/dt = m(î + j)

Differentiating the velocity vector with respect to time gives the expression for acceleration, which is the second derivative of position function with respect to time.

The acceleration vector can be represented as a(t) = dv(t)/dt = m/s² (î + j)

Therefore, the vector expression for the ball's position as a function of time (in m) using the unit vectors î and j is given by r(t) = mî + mj.

The expression for the velocity vector as a function of time (in m/s) is given by v(t) = m(î + j).

The expression for the acceleration vector as a function of time (in m/s²) is given by a(t) = m/s²(î + j).

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Answer:

A) 2.58 pounds

Step-by-step explanation:

To solve you would have to subtract the pounds of tomatoes from the pounds of lettuce. The equation would look like this,

4.36 - 1.78 = 2.58

Hope that helps and have a great day!

Answer:

2520

Step-by-step explanation:

42000 x .06=2,520

Answer:

A. x(x + 7)²

Step-by-step explanation:

Step 1: Write out polynomial

x³ + 14x² + 49

Step 2: Factor out x

x(x² + 14x + 49)

Step 3: Factor out quadratic

x(x + 7)²

Answer:

Step-by-step explanation:

Answer:

D.

Step-by-step explanation:

that is the answer to the question above

TRUNCATED to one decimal place, it's 50.2

ROUNDED to one decimal place, it's 50.3

The round-off of 50.272 to 1 decimal place using rules of rounding

numbers are 50.3.

Rounding off numbers means making a number simpler by adjusting it to its nearest place according to certain rules.

Rounding a number to one decimal place means keeping only the first digit after the decimal point and neglecting the rest. In this case, the digit in the second decimal place is 7, which is greater than or equal to 5. As per the rounding rules, if the digit is greater than 5, the preceding digit is increased by 1.

So, 50.272 becomes 50.3 when rounded to one decimal place.

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Answer:

speed=distance/time

speed=3600/3

speed=1200m/s

Answer:

The car is going 1200 miles per hour.

Step-by-step explanation:

Answer:

I believe the answer is

\(y = \frac{2}{3} x + 1\)

slope = 2/3x

y-intercept = 1

Step-by-step explanation:

Hope this helps!

Value of ∠5 is 140°

Given that;

∠5 and ∠6 are a linear pair

∠5 = (4x - 20)°

∠6 = x°

Find:

Value of ∠5

Computation:

We know that, sum of linear pair angle is 180°

So,

∠5 + ∠6 = 180°

(4x - 20)° + x° = 180°

4x - 20 + x = 180

5x - 20 = 180

5x = 180 + 20

5x = 200

x = 200 / 5

x = 40

So,

Value of ∠5 = (4x - 20)°

Value of ∠5 = 4(40) - 20

Value of ∠5 = 160 - 20

Value of ∠5 = 140°

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The answer is 1.95 or 1.95 = 1.95. The probability that a randomly selected student is taking a math class or an English class can be found using the formula for the union of two events:

P(A or B) = P(A) + P(B) - P(A and B)

where A is the event of taking a math class and B is the event of taking an English class.

Given that 66% of students are taking a math class, P(A) = 0.66. Given that 74% of students are taking an English class, P(B) = 0.74. Given that 45% of students are taking both, P(A and B) = 0.45.

Therefore, the probability that a randomly selected student is taking a math class or an English class can be calculated as follows:

P(A or B) = 0.66 + 0.74 - 0.45 = 1.95

Rounding to 2 decimal places, the answer is 1.95 or 1.95 = 1.95.

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The center of the circle is (7, 10),

The radius of the circle is 4.

Option A is the correct answer.

A circle is a two-dimensional figure with a radius and circumference of 2πr.

The area of a circle is πr².

The equation of a circle is (x - h)² + (y - k)² = r²

Where (h, k) is the center of the circle and r is the radius of the circle.

We have,

(x - 7)² + (y - 10)² = 16

This can be written as,

(x - 7)² + (y - 10)² = 4² ______(1)

This is an equation of a circle.

The equation of a circle is (x - h)² + (y - k)² = r² ______(2)

Comparing (1) and (2).

We get,

(h, k) = (7, 10) and r = 4

The center of the circle is (7, 10),

The radius of the circle is 4.

Thus,

The center of the circle is (7, 10),

The radius of the circle is 4.

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Answer:

1 1/20 is the correct way

Step-by-step explanation:

I don't know how to get it but i just looked it up .

Answer:2 2/100

Step-by-step explanation:

2 2/100

Answer:

Step-by-step explanation:

Answer:

I got 3.60

Step-by-step explanation:

I used a^2 + b^2 = c^2.

2^2 + 3^2 = c^2 which is the hypotenuse ( the slide)

^^^^^^^^^^these are the legs that make up the right angle. FIRST get the square root of those and add them. THEN the total of that which is 13. Square root 13...√13 and it gives you 3.6055512etc.

The inverse of the transpose of matrix A is equal to the transpose of the inverse of matrix A.

To verify that the inverse of A transpose (A^T) is equal to the transpose of the inverse of A (A^-1), we can use the multiplication rule for transposes, which states that (CD)^T = D^T * C^T.

Let's assume that A is an invertible matrix. We want to show that (A^T)^-1 = (A^-1)^T.

First, let's take the inverse of A^T:

(A^T)^-1 * A^T = I,

where I is the identity matrix.

Now, let's take the transpose of both sides:

(A^T)^T * (A^T)^-1 = I^T.

Simplifying the equation:

A^-1 * (A^T)^T = I.

Since the transpose of a transpose is the original matrix, we have:

A^-1 * A^T = I.

Now, let's take the transpose of both sides:

(A^-1 * A^T)^T = I^T.

Using the multiplication rule for transposes, we have:

(A^T)^T * (A^-1)^T = I.

Again, since the transpose of a transpose is the original matrix, we get:

A * (A^-1)^T = I.

Now, let's take the transpose of both sides:

(A * (A^-1)^T)^T = I^T.

Using the multiplication rule for transposes, we have:

((A^-1)^T)^T * A^T = I.

Simplifying further, we get:

A^-1 * A^T = I.

Comparing this with the earlier equation, we see that they are identical. Therefore, we have verified that the inverse of A transpose (A^T) is equal to the transpose of the inverse of A (A^-1).

In conclusion, (A^T)^-1 = (A^-1)^T.

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The antiderivative of 7ex is 7ex, and the antiderivative of 6 sec2(x) is 6 tan(x). Thus, the most general antiderivative is F(x) = 7ex + 6 tan(x) + C, where C represents the constant of integration.

To find the antiderivative of the given function f(x) = 7ex 6 sec2(x), we integrate each term separately. The antiderivative of 7ex is simply 7ex, as the exponential function ex is its own antiderivative.

Next, we consider the antiderivative of 6 sec2(x). The derivative of the tangent function tan(x) is sec2(x), so the antiderivative of sec2(x) is tan(x). However, there is a coefficient of 6 in front of sec2(x), so the antiderivative becomes 6 tan(x).

Combining these results, we have F(x) = 7ex + 6 tan(x) as the antiderivative of the original function f(x) = 7ex 6 sec2(x). The "+ C" at the end represents the constant of integration, as any constant added to the antiderivative remains undetermined. Therefore, the most general antiderivative of f(x) is F(x) = 7ex + 6 tan(x) + C, where C is a constant.

To verify this result, we can differentiate F(x) and confirm that it indeed yields the original function f(x). Taking the derivative of F(x) with respect to x will give us back 7ex 6 sec2(x), thus confirming the correctness of the antiderivative.

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Answer:$43

Step-by-step explanation:

65 -22 =43

The Poisson distribution becomes a good approximation to the Binomial distribution when the number of trials is large, the probability of success is small, and the expected number of successes is λ = np.

(a) The probability mass functions (PMF) of Bino(np) and Pos(np) with the parameters n = 100, p = 0.2,0.8 for the interval k [0, 100) can be plotted using the MATLAB functions binopdf and poisspdf.

(b) To show that Poisson distribution approximates Binomial distribution when n is large, p is small, and λ = np, we can use the Poisson approximation to Binomial distribution. Using the fact that n-k/k → 1 as n →[infinity], we can simplify the Binomial distribution to:

Bino(n,p) ≈ (np)^k e^(-np)/(k!)

By letting λ = np and replacing in the above expression, we get:

Bino(n,p) ≈ (λ/k)^k e^(-λ)/k!

This expression is the PMF of a Poisson distribution with parameter λ, which proves that Poisson distribution approximates Binomial distribution under the given conditions.

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The vector (nu) x is an eigenvector of A and corresponds to each nonzero complex scalar (nu) (lambda).

Let x in Cn be an eigenvector of A that corresponds to an eigenvalue. Assume that A is a n x n matrix (lambda). Ax = (lambda)x follows.

Let (nu) now be a complex scalar that is nonzero. A((nu)x) = A((nu)x) = A((nu)x) = A((nu)x) = A((nu)x) = A((nu)x)

As a result, (nu)x is an eigenvector of A that corresponds to (nu) (lambda).

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Question 37:  The following is a solution to the differential equation y = t - 1. d.

Question 38:  The tea temperature be after a very long time is dT/dt = k(S - T); T ≈ 20 degrees after a very long time. a.

To determine the solution to the given differential equation: t²(d²y/dt²) - 6t(dy/dt) + 12 = 0, we can solve the equation by assuming a solution in the form of y = tⁿ, where n is a constant.

By differentiating y with respect to t, we can substitute the derivatives into the differential equation to determine the value of n.

Let's differentiate y = tⁿ with respect to t:

dy/dt = n × tⁿ⁻¹

d²y/dt² = n(n-1) × tⁿ⁻²

Substituting these derivatives into the differential equation:

t²(n(n-1)tⁿ⁻²) - 6t(ntⁿ⁻¹) + 12 = 0

Simplifying the equation:

n(n-1)tⁿ - 6ntⁿ + 12 = 0

n(n-1)tⁿ - 6ntⁿ = -12

Since this equation must hold for all values of t, the coefficients of the tⁿ terms on both sides of the equation must be equal.

We can equate the coefficients:

n(n-1) = 0

n = 0 or n = 1

The general solution to the differential equation is y = c₁ + c₂ × t, where c₁ and c₂ are constants.

According to Newton's law of cooling, the rate of change of the temperature T of an object is proportional to the temperature difference between the object's temperature T and the surroundings' temperature S.

We can write the differential equation as follows:

dT/dt = k(S - T)

dT/dt represents the rate of change of temperature, k is the proportionality constant, and (S - T) represents the temperature difference between the object and the surroundings.

The cup of tea starts at 100 degrees and cools to 50 degrees in 3 minutes, with the room temperature at 20 degrees.

We can assume that the temperature of the tea will tend toward the room temperature as time goes to infinity.

This option correctly represents that as time goes to infinity, the temperature T of the tea will approach the temperature S of the surroundings, which is approximately 20 degrees.

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