Algebra 7th grade please explain answers

The IH states that the sum of the angles in convex polygon C(which, by the IH, is (n - 2)·π) and the sum of the angles in triangle B (180°) is the same as the sum of the angles in A.

Using induction all convex polygons with n vertices have angles that add to (n - 2)·π, therefore let P(n) be that. We will demonstrate that P(n), where n≥3, holds for every n ∈ N. We demonstrate P(3), which states that any convex polygon with three vertices has an angle total of 180 degrees. Any triangle formed by such a polygon has angles that add up to 180°.

Assume that P(n) holds for some n ≥ 3 and that all convex polygons with n vertices have angles that add to (n-2) 180° for the inductive step. We demonstrate P(n+1), which states that each convex polygon with n+1 vertices has an angle sum of (n-1)·π. Let A represent any n+1-vertex convex polygon.

The IH states that the sum of the angles in convex polygon C (which, by the IH, is (n - 2)·π) and the sum of the angles in triangle B (180°) is the same as the sum of the angles in A. As a result, the total angle in A is (n-1) 180°. Thus, the induction is complete and P(n + 1) holds.

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You know the answer is the third choice (C) because 7^2 is 49 and 8^2 is 56, the two closest squared numbers to 54.

49 < 54 < 56

The square root of 54 is  roughly 7.4

I hope that helps :)

Step-by-step explanation: First, we create a table using the equation provided: "y = -2/3x + 1". If x is 0, then y = 1. If x = 3, y = -1. Thus, we plot the points (0, 1) and (3, -1). Then, we draw a line through them.

It will be 38 feet long

The perimeter is the space surrounding a shape's edge.

The sum of the lengths of all the sides in a rectangular shape is its perimeter. P = 2( L+B)

Given that a rectangle's width is 17 feet and its perimeter is 110 feet, the length will be P = 2 (L + B)

110 = 2 (L + 17)

55 - 17 = L.

The pool is therefore 38 feet long.

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The correct answer to when interpreting Cohen's d, it's important to remember that, is: (C) : all of the above.

When interpreting Cohen's d, it's important to remember that Cohen's suggestions for small, medium, and large effects are only general rules of thumb, and what counts as a small, medium, or large effect varies quite a bit by field.

Therefore, it is probably best to consider an effect size relative to other similar findings in the field. In summary, all the options listed are important considerations when interpreting Cohen's d, and none of them should be overlooked. Hence, the correct answer is option (C).

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Two different tools that the students can use to simulate choosing a game include:

The gaming club could use a random number generator to simulate the selection of a game. They could assign a unique number to each of the 10 games (for example, 1-10), and then use a random number generator to generate a number between 1 and 10. The game that corresponds to the generated number would be the game that is selected for play.

The gaming club could also create a physical game spinner with 10 sections, each labeled with the name of a game. They could spin the spinner to select the game for play at each meeting.

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Answers:

1.) 1 and 1/2

2.) 1/2

Strictly increasing functions:

Let a function f(a) for x = a, then,

f(a + h), for x = a + h,

If f(a + h) > f(a), we say this a strictly increasing function, as with increase in x, f(x) also increases.

In the given graph, there are straight lines so you can say increasing interval would have +ve slope.

For x = -5 to -4, it increases = [-5, -4]

For x = 1 to 3, it increases = [1, 3]

Answer: [-5, -4] , [1, 3]

By using the concept of weighted averages, the weighted average of the given values is equal to 7.35.

Weighted average is a kind of average in which each element has an specific weight in contrast with uniform average, where each element has the same weight. In this problem we have three values associated to three distinct weights, whose weighted average is:

x = 0.75 · 7 + 0.15 · 8 + 0.10 · 9

x = 7.35

By using the concept of weighted averages, the weighted average of the given values is equal to 7.35.

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Answer:

The car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Step-by-step explanation:

Let be \(d(s) = 0.0056\cdot s^{2} + 0.14\cdot s\), where \(d\) is the stopping distance measured in metres and \(s\) is the speed measured in kilometres per hour. The second-order polynomial is drawn with the help of a graphing tool and whose outcome is presented below as attachment.

The procedure to find the speed related to the given stopping distance is described below:

1) Construct the graph of \(d(s)\).

2) Add the function \(d = 7\,m\).

3) The point of intersection between both curves contains the speed related to given stopping distance.

In consequence, the car must have a speed of 25 kilometres per hour to stop after moving 7 metres.

Based off of the information given , we can concluded this contradicts Rolle's Theorem, since f(?8) = f(8), there should exist a number c in (?8, 8) such that f?'(c) = 0. The correct answer is c.

We have:

f(x) = 4 - x^(2/3)

f(-8) = 4 - (-8)^(2/3) = 4 + 4 = 8

f(8) = 4 - 8^(2/3)

To find all values c in (-8, 8) such that f'(c) = 0, we first find the derivative of f(x):

f'(x) = -(2/3)x^(-1/3)

Setting f'(c) = 0, we get:

-(2/3)c^(-1/3) = 0

c^(-1/3) = 0

This has no solutions since c cannot be raised to a negative power and equal zero.

Therefore, the correct answer is:

This contradicts Rolle's Theorem, since f(?8) = f(8), there should exist a number c in (?8, 8) such that f?'(c) = 0. The correct answer is c.

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As the project progresses, the actual finish times (AFs) of completed activities play a crucial role in determining various aspects of the project schedule.

The AFs are used to calculate the earliest start and earliest finish times for the remaining activities in the network diagram. These calculations are based on the dependencies between activities and the actual durations of completed activities.

By considering the AFs, the project team can determine the earliest possible start and finish times for the remaining activities, taking into account the sequence of activities and any imposed constraints. This information helps in managing the project schedule and identifying any potential delays or critical paths.

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Answer:

22.5

Step-by-step explanation:

since 2.25 divided by 0.10 is 22.5 so she can message 22.5 friends

The number of people who would prefer Choco chocolate chip  is 120.

Ratio expresses the relationship between two or more numbers. It shows the frequency of the number of times that one value is contained within other value(s).

In order to determine the number of people who would prefer Choco chocolate chip , multiply the given ratio of people who prefer Choco chocolate chip by the total number of people in the group.

The number of people who would prefer Choco chocolate chip = (ratio of people who prefer choco / sum of ratios) x number of people

(3/5) x 200 = 120

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Answer:

The two possible outcomes are 4 and -12, so 4

Step-by-step explanation:

The greatest value of x  is 4.

Factorization is when you break a number down into smaller numbers that, multiplied together, give you that original number. When you split a number into its factors or divisors, that's factorization.

Given equation

⇒ \(x^{2} +8x-30 = 18\)

⇒ \(x^{2} +8x-30-18=0\)

⇒ \(x^{2} +8x-48=0\)

⇒ \(x^{2} +12x-4x-48=0\)

⇒ \(x(x+12)-4(x+12)=0\)

⇒ \((x+12)(x-4)=0\)

x = -12 and x = 4

Hence, the greatest value of x  is 4.

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To determine if a line is parallel or perpendicular, we can place each line on a sloped intersection shape (y = mx + b) and observe the slope m of each line. Equal slopes result in parallel lines. If the slope is multiplied by -1, then the line is vertical.

Parallel Lines:

Two or more lines that lie in the same plane and do not intersect are called parallel lines. They are equidistant from each other and have the same slope. A straight line equation is usually written in the form of a slope intercept represented by the equation y = mx + b. where "m" is the slope and "b" is the y-intercept. The "m" value defines the slope and tells how steep the line is.

Perpendicular Lines:

A vertical line or perpendicular line is two separate lines that intersect at an angle of 90° to each other. These are straight lines known as perpendiculars that meet each other at certain angles (right angles).

We have already seen what a vertical line looks like. If a shape has an "L" shape, its vertex angles are right angles. Vertical lines always intersect each other, but not all intersecting lines are always perpendicular to each other.

Two main properties of vertical lines:

1. Perpendicular lines always intersect or intersect each other.

2. The angle between two vertical lines is always 90°.

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Answer:

$57

Step-by-step explanation:

12*4.75=57

To conduct a hypothesis test to analyze whether the proportion of stocks that offer dividends is different from 0.14, a two-tailed hypothesis test should be used.

To analyze whether the proportion of stocks that offer dividends is different from 0.14, the trader should use a two-tailed hypothesis test.

In a two-tailed hypothesis test, the null hypothesis states that the proportion of stocks offering dividends is equal to 0.14. The alternative hypothesis, on the other hand, is that the proportion is different from 0.14, indicating a two-sided test.

The trader wants to test whether the proportion is different, without specifying whether it is greater or smaller than 0.14. By using a two-tailed test, the trader can assess whether the proportion significantly deviates from 0.14 in either direction.

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Answer:assuming this is strictly proportional, 16/3>9/4 so I’d assume the 16kg object has greater kinetic energy

Step-by-step explanation:

Answer:

1793.75 m²

Step-by-step explanation:

Given that :

Total amount of land leased = 2050 m²

Fraction of land given to brother = 1/8

Amount of land given to brother :

1/8 * 2050 = 256.25 m²

Amount of land left :

2050 m² - 256.25 m²

= 1793.75 m²

Answer:

honestly sorry what subject that

Answer:

a=11 and b=12

Step-by-step explanation:

1) 106=9b-2 (Angles B and D are congruent)

2)b=12 (Find answer)

3)180-106=74 (Angle C + Angle D= 180)

4)7a-3=74 (Find Angle C)

5) a=11 (Find Answer)

Answer:

y=2/3x-3

Step-by-step explanation:

first we fill in the values for y=2/3x to find y intercept

-5=2/3(-3)

-5=-6/3

-5=-2

We know in order to make this equation true we have to subtract 3 so we write the new equation like this

y=2/3x-3

And we can test it

-5=2/3(-3)-3

-5=-6/3-3

-5=-2-3

-5=-5

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Answer:

To find the amount of gold leaf needed to cover the pendant, we can calculate the area of the rhombus. The area of a rhombus is given by the formula: area = (diagonal 1 * diagonal 2) / 2.

In this case, the diagonals are given as follows:

Left side of the horizontal diagonal: 7.5 mm

Right side of the horizontal diagonal: 7.5 mm

Top of the vertical diagonal: 11 mm

Bottom of the vertical diagonal: 11 mm

Now, we can calculate the area:

Area = (7.5 mm * 11 mm) / 2

Area = 82.5 mm²

Therefore, the amount of gold leaf needed to cover the pendant is approximately 82.5 mm².

Answer:

x = 120°

Step-by-step explanation:

We are given;

sec²x + 4secx = -4

Rearranging gives;

sec²x + 4secx + 4 = 0

Factorizing the left hand side gives;

(sec x + 2)(sec x + 2) = 0

This means that;

(sec x + 2) = 0

From trigonometry, we know that sec x = 1/cos x

Thus;

(1/cos x) + 2 = 0

1/cos x = -2

cos x = -1/2

cos x = -0.5

x = cos^(-1) -0.5

x = 120°

The entry required to account for the change in office supplies would depend on the accounting method used. Assuming the company follows the periodic inventory system, where office supplies are expensed as they are used, the entry would be as follows:

At the beginning of the period:

Debit: Office Supplies Expense - $4,000

Credit: Office Supplies - $4,000

At the end of the period:

Debit: Office Supplies - $3,900

Credit: Office Supplies Expense - $3,900

Explanation:

1. At the beginning of the period, the company records the office supplies as an asset (Office Supplies) and recognizes an expense (Office Supplies Expense) for the same amount. This reduces the value of the asset and reflects the cost of supplies used during the period.

2. At the end of the period, when it is determined that $3,900 worth of supplies remains, the company adjusts the office supplies account by reducing it by the remaining amount. This adjustment is necessary to reflect the correct value of supplies on hand at the end of the period.

The entry ensures that the net effect of the transactions is an expense of $100 ($4,000 - $3,900), which represents the cost of supplies consumed during the period.

Answer:

\(f(x) = \frac{5x^2 + 4x - 1}{x - 2}\)

Step-by-step explanation:

Given

VA; \(x = 2\)

SLA: \(y = 5x - 1\)

Zero of function: \((-1,0)\)

Required

Determine the rational function in expanded form

Analyzing the vertical asymptote

The vertical asymptote is given as:

\(x = 2\)

Subtract 2 from both sides

\(x - 2 = 2 - 2\)

\(x - 2 = 0\)

This means that the denominator must be \(x - 2\)

Analyzing the zero of the function

The zero of the function is given as: \((-1,0)\)

This means that \(x = -1\), when \(y = 0\)

Equate \(x = -1\) to 0 by add 1 to both sides

\(x + 1 =- 1 + 1\)

\(x + 1 =0\)

This means that one of the numerators must be \(x + 1\)

Analyzing the slant asymptote:

\(y = 5x - 1\)

This means that one of the numerators must be \(5x - 1\)

Hence, the function is:

\(f(x) = \frac{(5x - 1)(x+1)}{x - 2}\)

Expand the numerator

\(f(x) = \frac{5x^2 + 5x - x - 1}{x - 2}\)

\(f(x) = \frac{5x^2 + 4x - 1}{x - 2}\)

Answer:

=x^2 +4x+11

Step-by-step explanation:

f(x) = x^2 + 7,

Replace x with x+2

f(x+2) = (x+2)^2 + 7

         = (x+2)(x+2) +7

     FOIL

     = x^2 +2x+2x+4 +7

Combine like terms

    =x^2 +4x+11

Answer:

\(f(x+2)=x^2+4x+11\)

Step-by-step explanation:

In \(f(x)=x^2+7\), for all values of \(x\), we substitute \(x\) (what is in the parentheses) into \(x^2+7\) to output a \(y\) value.

In \(f(x+2)\), the term \((x+2)\) is in the parentheses. Therefore, substitute \((x+2)\) for \(x\) in \(x^2+7\) to find \(f(x+2)\):

\(f(x+2)=(x+2)^2+7\)

Expand using \((a+b)^2=a^2+2ab+b^2\),

\(f(x+2)=x^2+4x+4+7\)

Combine like terms:

\(\boxed{f(x+2)=x^2+4x+11}\)

Answer:

i dont know do it yourself chump

Step-by-step explanation:

Answer:

3π/2 is halfway between π and 2π.

Step-by-step explanation:

3π/2 is halfway between π and 2π.

Answer:

3π/2 is halfway between π and 2π

Hope this helps u

Solution

A function is a relation where each input value is assigned to AT LEAST one output value

The DOMAIN of a function is the set of all input values, or x-values, for which the function is defined.

The RANGE of a function is the set of all output values, or y-values, for which the function is defined.

To write the equation y = ax + b in function notation, substitute f(x) for y.