What is 4-1-1/4, please and thank you
Answer:
1/2
Step-by-step explanation:
4-1-1/4
=4-2/4
=2/4
By simplifying
=1/2
Answer:
= 1/2.
Step-by-step explanation:
4 - 1 - 1/4
=3 - 1/4
=2/4
=1/2.
Hunter and three friends were going to the movies. The movie tickets cost $10 each, they bought three popcorns at $7.25, and three drinks at $2.75. How much money did they spend total?
Hunter and three friends spent a total $41 of money.
What is addition?Addition is the process used to combine things and count them as a single, large group. Addition in mathematics is the process of combining two or more numbers. The term "sum" refers to the result of the process, and "addends" refers to the numbers that are added.
Given, Hunter and three friends were going to the movies.
The movie tickets cost $10 each.
So, cost of movie ticket is 3 times $10 = $30.
And they bought three popcorn at $7.25, and three drinks at $2.75.
That means, the expenditure other than movie is;
$7.25 + $2.75 = $11
To find the total money they spent:
Add all the expenditures,
$30 + $11 = $41.
Therefore, they spent $41.
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the starting salaries of individuals with an mba degree are normally distributed with a mean of $55,000 and a standard deviation of $6,000. what percentage of mbas will have starting salaries of $47,000 to $63,000? a. 40.88% b. 50% c. 81.76% d. 31.76%
Answer:
The answer is c. 81.76%
15 POINTS!
Which expression is equivalent to 8(3x – 2)?
A.
5x – 6
B.
11x – 6
C.
24x – 16
D.
24x + 16
Answer:
D - 24x-16
Step-by-step explanation:
(8×3x) + (8×-2)
Answer:
8(3x – 2) multiply it
24x-16
Assume that the margin requirement on the S&P 500 futures contract is 10%, and the stock index future is settled in May 20, 2018 at 2,000. Each contract has a multiplier of $250. a) How much margin must be put up for holding each contract? (2 marks) b) Investor A shorted one contract in May 21 at 2,000. If the futures price settled at 2,020 in May 21, what will happen to the margin account of investor A at market close of May 21? (4 marks) c) What was the investor A’s percentage return based on the amount put up as margin in May 21 after market close? (4 marks) d) Investor B sent $200,000 to setup her margin account with her broker in May 19, and longed two S&P 500 index contracts in May 20 at 2000. In May 21, investor B closed one contract at 2,020. In May 22, investor B did nothing while the futures price settled at 1,960. What was the investor B’s percentage total investment return up to May 22 after market close?
Investor A shorted one contract in May 21 at 2000 and made a profit of 80%. Investor B bought two contracts in May 20 at 2000 and sold one in May 21 at 2020. However, the price of the contract decreased to 1960 in May 22, resulting in a loss of 2%.
a) The margin requirement on the S&P 500 futures contract is 10%. The multiplier of each contract is $250. Therefore, the margin that must be put up for holding each contract is $250 x 10% = $25.
b) Investor A shorted one contract in May 21 at 2,000. If the futures price settled at 2,020 in May 21, the margin account of investor A will increase by $20. This is because the short position will gain $20, which will be credited to the margin account.
c) Investor A's percentage return based on the amount put up as margin in May 21 after market close is 40%. This is calculated as follows:
\(\begin{equation}\frac{20}{25} \times 100 = 80\%\end{equation}\)
d) Investor B sent $200,000 to setup her margin account with her broker in May 19, and longed two S&P 500 index contracts in May 20 at 2000. In May 21, investor B closed one contract at 2,020. In May 22, investor B did nothing while the futures price settled at 1,960. Investor B's percentage total investment return up to May 22 after market close is -2%.
This is calculated as follows:
\(\begin{equation}\frac{200000 - (250 \times 2) - (250 \times 1)}{200000} \times 100 = -2\%\end{equation}\)
The investor's total investment return is negative because the value of the contracts decreased from 2000 to 1960.
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"Derive the demand function
Endowment (1,0)
U(x,y) = -e⁻ˣ — e⁻ʸ
To derive the demand function from the given utility function and endowment, we need to determine the optimal allocation of goods that maximizes utility. The utility function is U(x, y) = -e^(-x) - e^(-y), and the initial endowment is (1, 0).
To derive the demand function, we need to find the optimal allocation of goods x and y that maximizes the given utility function while satisfying the endowment constraint. We can start by setting up the consumer's problem as a utility maximization subject to the budget constraint. In this case, since there is no price information provided, we assume the goods are not priced and the consumer can freely allocate them.
The consumer's problem can be stated as follows:
Maximize U(x, y) = -e^(-x) - e^(-y) subject to x + y = 1.
To solve this problem, we can use the Lagrangian method. We construct the Lagrangian function L(x, y, λ) = -e^(-x) - e^(-y) + λ(1 - x - y), where λ is the Lagrange multiplier.
Taking partial derivatives of L with respect to x, y, and λ, and setting them equal to zero, we can find the values of x, y, and λ that satisfy the optimality conditions. Solving the equations, we find that x = 1/2, y = 1/2, and λ = 1. These values represent the optimal allocation of goods that maximizes utility given the endowment.
Therefore, the demand function derived from the utility function and endowment is x = 1/2 and y = 1/2. This indicates that the consumer will allocate half of the endowment to each good, resulting in an equal distribution.
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The staff of Mr. Wayne Wertz, VP of Operations at Portland Peoples Bank, prepared a frequency histogram of waiting time for walk-in customers. Approximately how many walk-in customers waited at least 6 minutes? (Note the position of the labels on the x-axis — the first column is the number of customers who waited 1 minute and the last column is the number of customers who waited 10 minutes)
The number of people who waited at least 6 minutes is given as follows:
50 people.
What is shown by the histogram?The height of each bin of the histogram represents the number of observations of the data-set in the desired interval.
The desired outcomes for this problem are given as follows:
Between 6 and 7 minutes: 20 people.Between 7 and 8 minutes: 15 people.Between 8 and 9 minutes: 10 people.Between 9 and 10 minutes: 5 people.Hence the number of people who waited at least 6 minutes is given as follows:
20 + 15 + 10 + 5 = 50 people.
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39 of the 52 students in choir A like musicals. 35 of the 44 students in choir b like musicals. Was there a higher percentage of students that like musicals in choir A or B?
Choir B has a higher percentage of students who like musicals.
what is percentage ?
Percentage is a way of expressing a proportion or a fraction out of 100. It is a widely used concept in mathematics, finance, statistics, and other fields. For example, if 20 out of 100 students in a class like pizza, we can say that the percentage of students who like pizza is 20%. To calculate the percentage, we usually multiply the given fraction by 100. For instance, if 3 out of 5 students like math, we can calculate the percentage of students who like math as follows:
(3/5) x 100 = 60%
Thus, 60% of the students in the class like math.
To determine which choir has a higher percentage of students who like musicals, we need to calculate the percentage of students in each choir who like musicals.
For choir A, 39 out of 52 students like musicals:
39/52 = 0.75 or 75%
For choir B, 35 out of 44 students like musicals:
35/44 = 0.795 or 79.5%
Therefore, choir B has a higher percentage of students who like musicals.
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A random sample of 9th-grade students was asked if they prefer taking notes on a computer or using a pencil. Of the 180 students who were surveyed, 75 said they preferred using the computer. The resulting 99% confidence interval of the proportion of students who prefer taking notes on the computer was (0. 322, 0. 511). The school newspaper ran a story saying that less than half of the body prefers taking notes on a computer. Based on the interval, is the newspaper justified in this statement?
The newspaper's assertion is unjustified. It can be shown that the interval does not contain 0.5 based on the 99% confidence interval of (0.322, 0.511). (which is half).
This indicates that the population parameter (mean, percentage, and standard deviation) is between a and b with x% confidence.
This indicates that at least half of students prefer using a computer to take their notes. Since the interval's lower limit (0.322) is higher than 0.5, there is a 99% likelihood that the actual percentage of students who prefer taking notes on computers is higher than 0.5.
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HELP PLEASEEEE
Zarea finds 3√6,000 and shows her work below.
a ______ is a way to organize qualitative data into categories and record the number of observations in each category.
Frequency distribution is a way to organize qualitative data into categories and record the number of observations in each category.
Differentiate between frequency distribution and relative frequency ?
A frequency distribution lists how frequently each category of data occurs, but a relative frequency analysis lists how frequently each types of information occurs.
One approach to organise data is to use a "frequency distribution," which can be done by listing the data, placing it in a table, or displaying it in a graph. Then, the list's entries (distinct values) are counted in terms of how frequently they have occurred.
Define relative frequency distribution
A "relative frequency distribution," on the other hand, refers to the percentage of the total number of observations that fall into a certain group. Divide each frequency by the total amount of data in the sample to obtain this.
what is qualitative data ?
Quantitative data are counts or measures, whereas qualitative data describe categories. Examples of qualitative data include eye colours and shoe brand names in a consumer survey. Examples of quantitative data are student heights and test results.
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In an application to estimate the mean number of miles that downtown employees commute to work roundtrip each day, a sample of 20 employees was chosen and the sample standard deviation was found to be 5.30 miles. Based on this information, the margin of error for a 95 percent confidence interval estimate for the true population mean is: ___________
The margin of error for a 95 percent confidence interval estimate for the true population mean is approximately 2.29 miles.
To calculate the margin of error, we need to use the formula:
Margin of Error = (Critical Value) x (Standard Deviation / √Sample Size)
For a 95 percent confidence level, the critical value can be obtained from the standard normal distribution table. The critical value corresponding to a 95 percent confidence level is approximately 1.96.
Given:
Sample Standard Deviation (s) = 5.30 miles
Sample Size (n) = 20
Using the formula:
Margin of Error = 1.96 x (5.30 / √20) ≈ 1.96 x (5.30 / 4.47) ≈ 1.96 x 1.18 ≈ 2.29 miles
Therefore, the margin of error for a 95 percent confidence interval estimate for the true population mean is approximately 2.29 miles.
The margin of error represents the range within which we can reasonably expect the true population mean to fall. In this case, with a 95 percent confidence level, we estimate that the true mean number of miles downtown employees commute to work roundtrip each day is within 2.29 miles of the sample mean.
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simplify the polynomial expression. (4x^2-2x+7)+(x^2-7x-2)
Given the following polynomial:
\(\mleft(4x^2-2x+7\mright)+\mleft(x^2-7x-2\mright)\)You can follow the steps shown below in order to simplify it:
Step 1. Remember the Signs rules for multiplication:
\(\begin{gathered} (-)_{}(-)_{}=(+)_{} \\ (-)_{}(+)=(-) \\ (+)(+)=(+) \end{gathered}\)Then, you can rewrite the expression as following:
\(=4x^2-2x+7+x^2-7x-2\)Step 2. Now you must add the like terms (Remember that "like terms" are those terms whose variables are exponents are the same). Then, you get:
\(=5x^2-9x+5\)The answer is:
\(5x^2-9x+5\)AC=A, C, equals
Round your answer to the nearest hundredth.
Answer:
We have the equation A*C = A
Now, as both sides of the equality are the same thing, we can do the same operation to both sides and the equality will remain true.
We can divide both sides by A and get:
(A*C)/A = A/A
C = 1
So here we finded the value of A.
If A and C are matrices, then C is the identity matrix.
Circumference and Area of Circles
A circle has an area of 1256 square inches. What is the diameter of the circle. Use 7 = 3.14
O 10 in
O 20 in
O 40 in
O 60 in
Step-by-step explanation:
Area of a circle = #r^2
1256 = 3.14 × r^2
r^2 = 1256/3.14
r^2 = 400
Square root of r = 20
Diameter = 2 × r = 2 × 20 = 40 inches
how you can graph an exponential function with the help of doubling time or half-life
The doubling time or half-life and understanding the properties of functions, you can graphically represent the behavior of the quantity over time.
To graph an exponential function using the doubling time or half-life, follow these steps:
Understand the exponential function: An exponential function is of the form f(x) = a * bx, where 'a' is the initial value, 'b' is the base, and 'x' is the independent variable.
Doubling time: If you know the doubling time, which is the time it takes for the quantity to double, you can use it to determine the value of 'b'. The formula to calculate 'b' is b = 2(1/doubling time).
Half-life: If you know the half-life, which is the time it takes for the quantity to reduce to half its initial value, you can use it to determine the value of 'b'. The formula to calculate 'b' is b = 0.5^(1/half-life).
Determine the initial value 'a' based on the given information or observation.
Use the values of 'a' and 'b' to create ordered pairs (x, y), where 'x' represents time and 'y' represents the quantity. Choose several values of 'x' to calculate 'y' using the exponential function formula.
Plot the ordered pairs on a graph, with 'x' on the horizontal axis and 'y' on the vertical axis.
Connect the plotted points with a smooth curve to represent the exponential growth or decay. By using the doubling time or half-life and understanding the properties of exponential functions, you can graphically represent the behavior of the quantity over time.
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Question 5
Which expression is equivalent to the expression shown?
3² x 34
Answer:
306
Step-by-step explanation:
3x3=9
9x34=306
hope it helps
the within-groups estimate of variance is the estimate of the variance of the population of individuals based on the variation among the:
Group of answer choices
Scores in each of the actual groups studied
Mean of the groups minus the mean of the scores of the actual groups
Equal to the between-groups estimate of population variance
Means of the groups studied
The within-group estimate of variance is the estimate of the variance of the population of individuals based on the variation among the scores in each of the actual groups studied.
The within-groups estimate of variance is the estimate of the variance of the population of individuals based on the variation among the:
Scores in each of the actual groups studied.
This estimate represents the variation within each group and helps in understanding the population's variance by looking at individual differences within the groups.
The estimated within-group variance is the sum of the within-group variances for each group in the model. Effectively, this is the sum of the variance of each value (j) from its group (i) divided by the sample size minus one.
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Someone help pleaseeeee
Answer:
The picture is not clear enough
EASY MATH PLEASE HELP
NO LINKS PLEASE
EXPLANATION REQUIRED
I WILL GIVE BRAINLIEST
: ) HINT: THE ANSWER IS NOT D
A child's sandbox is 6 ft. wide, 3 ft. long, and 2 ft. deep. The child's mother fills the sandbox so that it is 1 1/2 ft. deep. What is the volume of the sandbox?
A) 27 cubic feet
B) 7 1/2 cubic feet
C) 36 cubic feet
D) 20 cubic feet
In ΔJ L P, m ∠ J M P=3 x-6 J K=3 y-2 , and L K=5 y-8 .
If JM is an altitude of Δ J L P , find x .
In Δ JLP, m ∠ JMP = 3x - 6, JK = 3y - 2, and LK = 5y - 8 then the value of x = 32.
What is meant by the altitude of a triangle?In geometry, an altitude is a line that passes through two very specific points on a triangle: a triangle's vertex, or corner, and its opposite side at a right, or 90-degree, angle. The base is the opposite side. Triangles have three vertices and three opposite sides in common.
A triangle's altitude is the perpendicular drawn from the triangle's vertex to the opposite side. The altitude, also known as the triangle's height, forms a right-angle triangle with the base.
Since JM is at an altitude of ΔJLP, m ∠ JMP = 90
3x - 6 = 90
simplifying the above equation we get
3x = 96
Dividing both sides of the equation by 3, we get
x = 32
The value of x = 32.
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Plz help!!!!
Josh conducted an experiment with the bag of
marbles shown below. He will draw a marble out of the bag, record the result, return the marble to the bag, and draw another marble, continuing the process.
If he completes this process 600 times, about how many
times should he expect to draw a striped marble?
A.Approximately 400 times
B.Approximately 250 times
C.Approximately 200 times
D.Approximately 150 times
Answer:
Step-by-step explanation:
There are 12 marbles in total with three of them being striped. The chance of pulling out a striped marble is 3/12 which can be reduced to 1/4. And 1/4 of 600 is 150.
Mercury travels about 107,100 miles per hour as it resolves around the sun. How far does Mercury travel in 6 seconds?
Answer:
12
Step-by-step explanation:
Answer:
17,850
Step-by-step explanation:
5(x - 1) What is the value of the expression when x = 5
Answer:
20
Step-by-step explanation:
5(x-1)
Replace x with its value.
5(5-1)
Solve parenthesis first.
5(4)
Multiply.( multiply 5 times 4)
20
The length of a rectangle is 5 in longer than its width.
If the perimeter of the rectangle is 74 in, find its length and width.
Answer:
Length = 21
Width = 16
Step-by-step explanation:
We know that the formula for perimeter is:
P=2W+2L
And we also know that:
L=W+5
So then we put all that we know in the formula:
74=2W+2(W+5)
Now we expand the brackets and do some algebra:
74=4W+10 (-10)
64=4W (÷4)
16=W
Now that we know the width we can pop that into the length equation:
L=16+5
L=21
if we were able to perform totally accurate and precise measurements, what would be the standard deviation in these conditions?
If we were able to perform totally accurate and precise measurements, what would be the standard deviation in these conditions, then the greater the precision the smaller the standard deviation, there is no relationship between standard deviation and accuracy.
If an instrument or method has good precision, 95% of values should fall within 2 standard deviations of the mean. That means that no more than 1 of the 20 results should fall outside of 2 standard deviations.
The standard deviation is a measure of the width of the underlying distribution of measurements. The narrower the distribution, the more tightly clustered the measurements will be about the mean and the more precise those measurements are.
The standard deviation measures the precision of a single typical measurement. It is common experience that the mean of a number of measurements gives a more precise estimation than a single measurement.
Therefore,
If we were able to perform totally accurate and precise measurements, what would be the standard deviation in these conditions, then the greater the precision the smaller the standard deviation, there is no relationship between standard deviation and accuracy.
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I'll give brainliest!!! I need help fast please I just need someone to check my answers!!! Don't respond if you don't know what you're talking about!!!
LOOK AT THE SCREENSHOT!!
Answer:
your correct
Step-by-step explanation:
:D
A rectangle has a length of 5x+2 and a width of 3x-1. Write an Expression for the perimeter of the rectangle
Answer:
16x+6
Step-by-step explanation:
5x+2+3x+1+5x+2+3x+1 =
16x+6
Answer:
16x + 2
Step-by-step explanation:
\(\boxed{\begin{minipage}{4 cm}\underline{Perimeter of a rectangle}\\\\$P=2(w+l)$\\\\where:\\ \phantom{ww}$\bullet$ $w$ is the width. \\\phantom{ww}$\bullet$ $l$ is the length.\\\end{minipage}}\)
Given expressions:
\(\textsf{Length} = 5x + 2\)\(\textsf{Width} = 3x - 1\)To write an expression for the perimeter of the rectangle, substitute the given expressions for the width and length into the perimeter formula:
\(\begin{aligned}\implies \textsf{Perimeter} &=2\left(5x+2+3x-1 \right)\\ &= 2(5x+3x+2-1)\\&=2(8x+1)\\&=16x+2\end{aligned}\)
Which line segments in the diagram below are parallel?
Please help me! If u get it right I’ll brainliest u
does the interval covering the middle 95% of the new bootstrap estimates include n? if you ran that cell 100 times and generated 100 intervals, how many of those intervals would you expect to include n?
The value of n cannot be included in any of the intervals generated by the bootstrap method. The number of intervals including n depends on the distribution of the estimates and the true value of n.
As the value of n is fixed and is not a result of any estimation or sampling process, it cannot be included in any of the intervals generated by the bootstrap method. Therefore, none of the intervals covering the middle 95% of the bootstrap estimates would include n.
However, as the bootstrap method is a resampling technique, the estimates generated by it can vary from sample to sample. Therefore, the number of intervals covering the middle 95% of the bootstrap estimates that include n would depend on the distribution of the estimates and the true value of n.
In general, if the estimates are centered around the true value of n, we would expect a higher number of intervals to include n. Conversely, if the estimates are more dispersed, we would expect a lower number of intervals to include n. Without further information about the estimates, it is difficult to provide a more specific answer.
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The complete question is :
Suppose you have performed a new bootstrap estimate on a dataset with n=50 and generated 100 intervals covering the middle 95% of the estimates. Does any of these intervals include n? Also, how many of these intervals would you expect to include n?