All of the points in the picture are one the same line

Given:

Tommy earned $14.80 in interest after 4 years on a principal of $100. His simple interest rate is 3.7%

Jane earned $140.40 in interest after 3 years on a principal of $1,200. Her simple 3 interest rate is 3.9%.

So, the simple interest rate of Jane's is greater than the simple interest rate of Tommy's because 3.9% > 3.7%

so, the bank that would be used is Jane's bank

The probability that the selected volcano is cinder cone is P ( C ) = 13/37

The probability that the selected volcano is shield cone is P ( S ) = 18/37

The probability that the selected volcano is strato is P ( V ) = 6/37

The probability that an event will occur is measured by the ratio of favorable examples to the total number of situations possible

Probability = number of desirable outcomes / total number of possible outcomes

The value of probability lies between 0 and 1

Given data ,

Let the probability that the selected volcano is cinder cone is P ( C )

Let the probability that the selected volcano is shield cone is P ( S )

Let the probability that the selected volcano is strato is P ( V )

Now , the total number of volcanoes = 13 + 6 + 18 = 37 volcanoes

And ,

The probability that the selected volcano is cinder cone is P ( C ) = 13/37

The probability that the selected volcano is shield cone is P ( S ) = 18/37

The probability that the selected volcano is strato is P ( V ) = 6/37

Hence , the probabilities are solved

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Answer:

Step-by-step explanation:

Receiving Social Security Income While Working. In the year you reach full retirement age, your benefits will be reduced by $1 for every $3 you earn above $48,600 for 2020 and $50,520 for 2021. 6  Starting with the month you attain full retirement age, your benefits will no longer be reduced.

In a standard normal distribution, the mean and the standard deviation are both 0 and 1, so  the correct answer to the given question is option b. 0 and 1.

Standard normal distribution: The standard normal distribution is a normal distribution with a mean of zero and standard deviation of 1. The standard normal distribution is centered at zero and the degree to which a given measurement deviates from the mean is given by the standard deviation

In a standard normal distribution, the correct answer to the given question is option b. 0 and 1. The standard normal distribution is a normal distribution curve where the values of the mean and standard deviation are 0 and 1 respectively

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-6a² + 4a² + 3 is the quotient of the given expression: (36a⁴- 24a⁴ - 18a²) ÷ (-6a²).

It is known as the quotient to divide two integers. The dividend is the quantity being divided, and the divisor is the quantity being divided. The quotient is the outcome of the division.

The sum is the result of multiplying two or more numbers together. The difference is determined by the result of subtracting the two values. The result of multiplying two or more integers is what is known as the product. The quotient is what remains after dividing two numbers.

Given that,

= (36a⁴- 24a⁴ - 18a²) ÷ (-6a²)

= - 6a² + 4a² + 3

thus, -6a² + 4a² + 3 is the quotient of the above expression.

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The percentage occupied by fresh water on Earth is 47%. The pH of the solution with H+ concentration 0.08606951774271 M is 1.1.

To calculate the percentage of fresh water on Earth, we can subtract the percentage of water in the oceans (53%) from 100%. This gives us 47%, which represents the percentage occupied by fresh water.

The pH of a solution is a measure of its acidity or alkalinity. It is determined by the concentration of hydrogen ions (H+) in the solution. In this case, the H+ concentration is given as 0.08606951774271 M. The pH scale ranges from 0 to 14, with values below 7 indicating acidity and values above 7 indicating alkalinity. By calculating the negative logarithm (base 10) of the H+ concentration, we find that the pH of the solution is approximately 1.1.

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Answer:

20:25 probably don't quote me

Answer:

(5,2)

(5,1)

(8,1)

Step-by-step explanation:

Vertices are the vertex's of a triangle. In this triangle A has 3 vertices.

so all you have to do is find the coordinates of the triangle which is

(5,3)

(5,1)

(8,1)

Answer:

I think it is a quadratic function

Step-by-step explanation:

The dimensions of the rectangle are width = 20 centimeters and length = 1 centimeter.

Let's denote the width of the rectangle as "w" centimeters. According to the problem, the length of the rectangle is 19 centimeters less than its width, so the length can be expressed as "w - 19" centimeters.

The formula for the area of a rectangle is length multiplied by width. In this case, the area is given as 20 square centimeter

Area = Length × Width

20 = (w - 19) × w

To solve this equation, we can expand it:

20 = \(w^2\) - 19w

Rearranging the equation to bring everything to one side:

\(w^2\) - 19w - 20 = 0

Now, we can factor the quadratic equation:

(w - 20)(w + 1) = 0

Setting each factor equal to zero and solving for "w":

w - 20 = 0 --> w = 20

w + 1 = 0 --> w = -1

Since a negative width doesn't make sense in this context, we discard w = -1.

Therefore, the width of the rectangle is 20 centimeters (w = 20).

To find the length, we substitute this value back into the expression for length:

Length = w - 19

Length = 20 - 19

Length = 1 centimeter

So, the dimensions of the rectangle are width = 20 centimeters and length = 1 centimeter.

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Answer:

73.4%

Step-by-step explanation:

First, find the total number of people:

3605+1306=4911 people

The formula for any probability is:

Part / Whole

3605 respondents out of the total 4911 people say they use a social networking site

3605/4911 = 0.7341

Multiply this by 100 to get a percent

Thus, 73.4%

You should have a new column with the data "2019" for each row in your dataset.

To add a column with the data "2019" for each row in a dataset, you can use the following formula in Microsoft Excel:

1. Assuming your dataset starts in cell A1, in a new column (e.g., column D), enter the header "Year" in cell D1.

2. In cell D2, enter the formula "=2019".

3. Select cell D2 and copy it (Ctrl+C).

4. Select the range of cells in column D where you want to add the "2019" value. For example, if you have data in rows 2 to 100, select D2:D100.

5. Paste the formula by right-clicking on the selected range and choosing "Paste Special" from the context menu. In the Paste Special dialog box, select "Values" and click "OK". This will replace the formula with the actual value "2019" in each selected cell.

Now, you should have a new column with the data "2019" for each row in your dataset.

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Answer:

A

Step-by-step explanation:

The logical equivalence [(PAQ) ⇒ R] = (P⇒ R) V (Q ⇒ R) can be proven using truth tables. The expression [(PAQ) ⇒ R] represents the implication "If both P and Q are true, then R is true." The expression (P⇒ R) V (Q ⇒ R) represents the disjunction "Either if P is true, then R is true, or if Q is true, then R is true."

By constructing a truth table, we can compare the truth values of the two expressions for all possible combinations of truth values for P, Q, and R. The truth table will show that the two expressions have the same truth values for all cases, indicating their logical equivalence. When constructing the truth table, we consider all possible combinations of truth values for P, Q, and R. For the expression [(PAQ) ⇒ R], if either P or Q is false, then the implication is automatically true, since the antecedent is false. If both P and Q are true, then the implication is true only if R is true as well.

On the other hand, for the expression (P⇒ R) V (Q ⇒ R), if either P or Q is false, then the corresponding implication is automatically true. If both P and Q are true, then the disjunction is true if either (P⇒ R) or (Q ⇒ R) is true. Comparing the truth values of the two expressions in the truth table, we can see that they are identical for all possible combinations of truth values, confirming their logical equivalence.

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Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are often referred to as continuous theoretical distributions.

In most simulations, a queue is important for keeping an entity when it cannot move.

Exponential, triangular, Weibull, beta, Erlang, gamma, and lognormal distributions are all examples of continuous theoretical distributions. These distributions are used to model random variables that take on continuous values, such as time, length, or volume. They are characterized by probability density functions that describe the likelihood of different values occurring within a given range.

In simulation modeling, a queue is an important construct used to manage entities or objects that need to wait or be processed in a specific order. When an entity cannot move or proceed further in the simulation, it is typically placed in a queue until the conditions allow it to progress. Queues are commonly used in various simulation scenarios, such as modeling service systems, production lines, or network traffic.

Global variables and attributes are generally used to store and manage data within a simulation, but they do not specifically address the concept of keeping an entity when it cannot move. Resources, on the other hand, are entities that are required or consumed by other entities in the simulation, such as equipment or personnel, but they do not directly handle the situation of entities being unable to move.

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false :) thats ur answer

Answer:

\( {6}^{12} \times 36 =\)

Answer:

216

Step-by-step explanation:

If x = 8 & y = -9
Put in place -3 (8)(-9)
-24 * -9 = 216

The velocities at both sections of a gradually transitioning rectangular channel are zero, indicating stagnant or very slow flow, and the longitudinal force acting on the channel boundary cannot be determined without the density of the fluid.

To determine the velocities at Section 1 and Section 2, we can use the specific energy equation for open channel flow. The specific energy equation relates the flow depth, velocity, and energy head of the flow.

Velocity at Section 1:

Using the specific energy equation:

E1 = y1 + (V1^2) / (2g)

Where:

E1 = specific energy at Section 1

y1 = flow depth at Section 1

V1 = velocity at Section 1

g = acceleration due to gravity

Given:

y1 = 7 ft

E1 = y1 + (V1^2) / (2g) (since α1 = 1, energy coefficient = 1)

Substituting the known values:

7 = 7 + (V1^2) / (2g)

Simplifying the equation, we find:

V1 = 0 ft/s

Therefore, the velocity at Section 1 is 0 ft/s.

Velocity at Section 2:

Using the specific energy equation:

E2 = y2 + (V2^2) / (2g)

Where:

E2 = specific energy at Section 2

y2 = flow depth at Section 2

V2 = velocity at Section 2

Given:

y2 = 8 ft

E2 = y2 + (V2^2) / (2g) (since α2 = 1, energy coefficient = 1)

Substituting the known values:

8 = 8 + (V2^2) / (2g)

Simplifying the equation, we find:

V2 = 0 ft/s

Therefore, the velocity at Section 2 is 0 ft/s.

Both velocities at Section 1 and Section 2 are 0 ft/s, indicating that the flow is stagnant or very slow in the channel.

To determine the longitudinal force acting on the channel boundary through the transition, we can use the momentum equation for open channel flow:

F = ρQV2

Where:

F = longitudinal force

ρ = density of the fluid (assumed constant)

Q = flow rate

V2 = velocity at Section 2

Given:

ρ = constant

Q = A2V2 (since the flow is subcritical, the flow rate is Q = A2V2, where A2 is the cross-sectional area at Section 2)

The cross-sectional area A2 can be calculated using the flow depths and channel widths at Section 2:

A2 = y2 * B2

Given:

y2 = 8 ft

B2 = 15 ft

Substituting the known values:

A2 = 8 ft * 15 ft

A2 = 120 ft^2

Substituting the calculated values into the momentum equation:

F = ρ * (y2 * B2 * V2) * V2

Since the density ρ is not given, we cannot calculate the exact value of the longitudinal force without knowing the density.

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Answer:

280

Step-by-step explanation:

The correct answer is c. Learning curves are important for estimating performance improvement as workers become experienced.

Learning curves are often used in project management to estimating the time, effort, and resources required to complete a task or project. They help to estimate how long it will take for a worker or team to become proficient at a task or process, based on the amount of time and effort that they have put into it.

This can be helpful in estimating performance improvement as workers become more experienced and efficient in their work. The concept of a learning curve is a curved line that represents the rate of improvement over time, which is why the term "curve" is relevant. While learning curves do involve some math, they are not primarily focused on helping new PMs understand required math, nor are they used for visualization of curved mechanical parts or estimating cost improvement as parts become "broken in."
Learning curves are important for:
c. estimating performance improvement as workers become experienced.
Learning curves represent the progress made in a skill or job over time, whereas a curve illustrates the relationship between experience and efficiency. As workers become more experienced, their performance typically improves, which can be estimated using a learning curve in various industries and tasks.

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Conclusions and recommendations are significant aspects of a research study that are typically drawn from the findings and literature review.

Conclusions and recommendations are significant components of a research study.

The findings and literature review serve as critical sources in developing conclusions and recommendations.

Let's examine the process of drawing conclusions and recommendations in a research study.

Relating conclusions to the findingsThe conclusion is a final interpretation of the study's results based on the findings.

The findings section should demonstrate the variables under analysis, whether hypotheses were accepted or rejected, and any significant results obtained.

It should emphasize the implications of the findings in light of the study's original purpose or research questions.

A well-written conclusion should also provide any explanations for findings that weren't anticipated and why they are crucial.

A summary of the key points and a brief discussion of how the study contributes to the knowledge base and the research field are two other components of an effective conclusion.

Relating recommendations to the literature reviewRecommendations are the actions that researchers suggest based on the study's findings.

The researcher should tie the recommendation to the literature review in the study's final section.

The review of related literature provides the context for the study and the literature gaps that the study aims to address.

A well-written recommendation should make explicit the specific actions that stakeholders should take to apply the study's findings.

The researcher must also describe the potential benefits of implementing the recommendations and the rationale for the recommended actions.

To summarize, conclusions and recommendations are significant aspects of a research study that are typically drawn from the findings and literature review.

The researcher should provide a comprehensive summary of the study's outcomes and implications in the conclusion section.

Recommendations should be closely related to the literature review and describe the appropriate actions that stakeholders should take to apply the findings of the study.

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(a) The curve defined by the parametric equations x = t^2, y = -1/4t (t > 0) represents a parabolic trajectory, the point of intersection between the curve and the hyperbola is (4∛2, -1/(4∛2)).

To find the points on the curve where the tangent line is parallel to the line y = x, we need to determine when the slope of the tangent line is equal to 1.

The slope of the tangent line is given by dy/dx. Using the chain rule, we can calculate dy/dt and dx/dt as follows:

dy/dt = d/dt(-1/4t) = -1/4

dx/dt = d/dt(\(t^2\)) = 2t

To find when the slope is equal to 1, we equate dy/dt and dx/dt:

-1/4 = 2t

t = -1/8

However, since t > 0 in this case, there are no points on the curve where the tangent line is parallel to y = x.

(b) To determine the points on the curve where it intersects the hyperbola xy = 1, we can substitute the parametric equations into the equation of the hyperbola:

\((t^2)(-1/4t) = 1 \\-1/4t^3 = 1\\t^3 = -4\\\)

Taking the cube root of both sides, we find that t = -∛4. Substituting this value back into the parametric equations, we get:

x = (-∛4)^2 = 4∛2

y = -1/(4∛2)

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Let's evaluate each of the prefix expressions:

A) *2/8 4 3

To evaluate this expression, we start from the right and work our way to the left.

The division operation (/) is applied first: 4 divided by 3 is equal to 1.33 (approximately).

Next, we perform the multiplication operation (*): 1.33 multiplied by 2 is equal to 2.67 (approximately).

Therefore, the value of the expression is approximately 2.67.

B) 1- 33 425

Again, we start from the right and move to the left.

The subtraction operation (-) is applied first: 425 minus 33 is equal to 392.

Finally, we subtract 1 from 392: 392 minus 1 is equal to 391.

The value of the expression is 391.

C) + 132 123/6-4 2

Let's break down the expression step by step:

1. 123 divided by 6 is equal to 20.5.

2. Next, we have: 132 + 20.5 - 4 2.

To evaluate the addition and subtraction, we perform the operations from left to right:

3. 132 plus 20.5 is equal to 152.5.

4. Subtracting 4 from 152.5 gives us 148.5.

5. Finally, we subtract 2 from 148.5, resulting in 146.5.

Therefore, the value of the expression is 146.5.

D) +3+3 13+333

Following the same procedure, we evaluate the expression step by step:

1. 3 plus 3 is equal to 6.

2. Next, we have: 6 + 13 + 333.

To evaluate the addition, we perform the operations from left to right:

3. 6 plus 13 is equal to 19.

4. Finally, we add 333 to 19, resulting in 352.

Therefore, the value of the expression is 352.

Q3. It seems that there is no specific question mentioned for Q3. If you have any additional question or clarification, please let me know and I'll be happy to assist you.

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Answer:

4c - 2

Step-by-step explanation:

Add up all the terms to find the perimeter.

2c + 2(c - 1)

2c + 2c - 2

4c - 2

Therefore, the perimeter is 4c - 2.

Step-by-step explanation:

y=5x+12 ....... eqn 1

3y+4X=150.....eqn 2

sub eqn 1 into 2

3(5x+12) + 4X = 150

15X+36 +4X=150

19X = 150-36

19X= 114

X= 6

Answer:

0.125 in decimal 12.5 in percent

Step-by-step explanation:

in percent it will be 12.5

The equation of the line which is parallel to the given line is 3y - x = -12.

given that

x = 18 and y = 2

putting the value in equation 3y-x = -12

this saisfied he equation perfectly.

Hence, the equation in parallel to 3y-x = -12

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