aluminum allows for the flow of electrons, while glass does not. would an aluminum wire surrounded by glass be an effective design for a device that will need to carry an electric current?

The three examples of situations in which mass is the main factor determining an object's momentum are, a moving truck, a moving trailer and a rolling block.

P = mv

where;

The three examples of situations in which mass is the main factor determining an object's momentum is below;

The three examples given above shows three objects with heavy mass.

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Answer: 63.43 m

Explanation:

Given

Car lands 68.38 m away from the base of the garage

Stuntman drove the car with speed \(u=19\ m/s\)

Since there is no acceleration in the horizontal direction, so there is no change in velocity

\(\Rightarrow 68.38=19\times t\\\Rightarrow t=3.598\ s\)

time taken to cover 68.38 m is 3.598 s

In this time car travels a vertical distance of h

Such that we can write

\(\Rightarrow h=u_vt+\frac{1}{2}at^2\\\\\Rightarrow h=\frac{1}{2}gt^2\\\\\Rightarrow h=0.5\times 9.8\times (3.598)^2=63.43\ m\)

Answer:

5

Explanation:

100 newtons pulling a 500 newton object has the mechanical advantage of 5 since it pulled 5x its weight

the expression is simple: 500/100= 5 (5 is the mechanical advantage)

pls mark me brainliest if this is right lol ty

Answer:The weight of an object may be thought of as acting at a single point called its centre of mass

Explanation:

In summary, the amount of time a low mass star will stay on the main sequence is determined by its mass, radius, and temperature. Typically, a low mass star will remain on the main sequence for billions of years.

A low mass star is a star that is small in size, mass, and brightness. It is typically around 0.5-2 solar masses and is relatively cool compared to other types of stars. On the main sequence, which is the period when the star is fusing hydrogen into helium in its core, a low mass star can remain for a very long time. The length of time that a low mass star remains on the main sequence is determined by the rate at which it fuses hydrogen into helium in its core. This rate is determined by the star's mass, radius, and temperature. Generally, the lower the mass of the star, the longer it will remain on the main sequence. For example, a star with a mass of 0.5 solar masses will remain on the main sequence for around 20-30 billion years, while a star with a mass of 1 solar mass will remain on the main sequence for around 10 billion years.

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The given statement " rotating the tree at branch point 2 would change the relationship between taxa d and a " is True. Because,  Rotating the tree at branch point 2 would change the relationship between taxa d and a.

In a phylogenetic tree, taxa are represented as nodes and branches, with each node representing a common ancestor and each branch representing evolutionary relationships. The placement of taxa on a branch is based on  similarity of their characteristics or genetic sequences. Rotating a tree at a branch point involves changing position of the nodes and branches while maintaining relationship between taxa. In given scenario, rotating  tree at branch point 2 would change order in which the taxa are related to each other .

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If the rods P and Q repel each other, that means they have the same charge signs (both are positive or both are negative)

Since the rods P and R attract each other, that means they have opposite charge signs (one is positive and the other is negative).

Looking at the options, the only one that can represent the signs of the charges on the rods is the third option. (P and Q have the same charge sign, P and R have different charge signs)

Answer:

two people trying to punch the eachother and then their fists collide

The rise in the mercury level in the capillary tube of a thermometer, when the temperature increases from 10°C to 32°C, is approximately 5.75 cm.

To determine the rise in the mercury level in the capillary tube of a thermometer, we can use the principle of thermal expansion. The change in volume of the mercury is related to the change in temperature and the coefficient of volume expansion of mercury.

Volume of the bulb (V) = 0.200 cm³

Cross-sectional diameter of the capillary tube (d) = 0.120 mm

First, we need to calculate the cross-sectional area of the capillary tube.

Area (A) = π * (d/2)²

Since the diameter is given in millimeters, we need to convert it to centimeters:

d = 0.120 mm = 0.012 cm

Substituting the values into the formula for the area:

A = π * (0.012 cm/2)²

A ≈ 0.000113 cm²

Next, we need to calculate the change in volume of the mercury using the coefficient of volume expansion of mercury. The coefficient of volume expansion for mercury is approximately 0.000181 °C⁻¹.

Change in volume (ΔV) = V * α * ΔT

Where:

V = Volume of the bulb

α = Coefficient of volume expansion of mercury

ΔT = Change in temperature

Substituting the values into the formula:

ΔV = 0.200 cm³ * 0.000181 °C⁻¹ * (32 °C - 10 °C)

ΔV ≈ 0.000651 cm³

Finally, we can calculate the rise in the mercury level by dividing the change in volume by the cross-sectional area of the capillary tube:

Rise in mercury level = ΔV / A

Rise in mercury level ≈ 0.000651 cm³ / 0.000113 cm²

Rise in mercury level ≈ 5.75 cm

Therefore, the mercury rises approximately 5.75 cm in the capillary tube when the temperature increases from 10°C to 32°C.

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Answer:

Explanation:

this is my android auto

Answer:

it is 1250 because it moves 5000 in four hours then it means that it is moving  at 1250 an hour

Explanation:

The correct answer for how the albedo of polar regions affect insolation is: Low temperatures are maintained because of the high amount of reflection.

The albedo of a surface refers to its ability to reflect sunlight. Higher albedo means more sunlight is reflected, while lower albedo means more sunlight is absorbed. Polar regions, such as the Arctic and Antarctic, have high albedo due to the presence of ice and snow, which reflect a significant portion of incoming sunlight.

When sunlight hits the polar regions with high albedo, a large portion of it is reflected back into space rather than being absorbed by the surface. As a result, less solar energy is available to heat the surface, leading to lower temperatures in these regions.

Therefore, low temperatures are maintained in polar regions because of the high amount of reflection caused by their high albedo.

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how many washers or paper clips can be picked up by each magnet. The one which picks up the most is the strongest.

-Slowly bring each magnet close to a magnetic material (such as an iron pin). The one which attracts the pin from the farthest distance is the strongest.

-Construct a device such as in class (place a tongue depressor between two plastic cups, place each magnet on top of the tongue depressor, and then suspend a paperclip beneath it to see how many washers each magnet can hold

Toyota Answer:too

Explanation:

You all

Answer:

waves

Explanation:

they are both waves

The potential energy of an object diminishes while its kinetic energy rises. The increase in kinetic energy perfectly offsets the reduction in potential energy. The idea of work is another crucial one.

The mass of the object and the square of its velocity are directly related to its kinetic energy: K.E. = 1/2 m v2. When a mass is measured in kilograms and a speed is measured in meters per second, the kinetic energy is measured in kilogram-meters squared per second squared.

due to the rule of conservation of energy, which states that total energy is always constant. Kinetic energy will therefore rise, whereas potential energy will fall.

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Answer: +/- 71,65 Calorías

Explanation: Se deduce que la fuerza aplica para aumentar o disminuir la energía del generador.

+/- x Calorías

X = Equivalente de 300 Joules en calorías

Para poder pasar Joules a calorías.

Hacemos una regla de 3 simple

1 Calorías = 4,18 Julios

0,2392 calorías = 1 Julio

(  1 / 4,18 = 0,2392 calorías)

300 Julios = 71,65 calorías

(0,2392 calorías x 300 julios = +/- 71,65 calorías)

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Actually Welcome to the Concept of the Projectile Motion.

Since, here given that, vertical velocity= 50m/s

we know that u*sin(theta) = vertical velocity

so the time taken to reach the maximum height or the time of Ascent is equal to

T = Usin(theta) ÷ g, here g = 9.8 m/s^2

so we get as,

T = 50/9.8

T = 5.10 seconds

thus the time taken to reach max height is 5.10 seconds.

Answer:

No, It hasn't acceleration because it doesn't change the velocity with respect to time.

Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N.

Given,Mass of a single raindrop in a cloud, m = 0.0340 g = 0.0340 × 10-3 kg

Distance from the center of mass of the cloud, r = 7.00 km = 7.00 × 10^3 mMass of the cloud, M = 511,000 kg

The formula for the gravitational force between two objects isF = G Mm / r2

Here,G = 6.67 × 10-11 Nm2 / kg2Plugging in the values, we get:F = 6.67 × 10-11 × 511000 × 0.0340 × 10-3 / (7.00 × 103)2F = 8.16×10−5 NTherefore, Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N.

Summary:Gravitational force that the raindrop experiences due to the cloud once it has fallen 7.00 km from the center of mass of the cloud is 8.16×10−5 N. The formula for the gravitational force between two objects is F = G Mm / r2.

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Answer: \(75000kg*m/s\)

Explanation:

\(p=mv\)

where;

p = momentum

m = mass = 3000kg

v = velocity = 25m/s

--------------------------------------------------------------------------------------------------

The first thing we need to do is convert 90km/h to m/s. Our conversion factors here are: 1km = 1000m and 1h = 3600s

\(90km/h(\frac{1000m}{1km})(\frac{1h}{3600s} )=25m/s\)

Plug your values in the formula:

\(p=(3000kg)(25m/s)\\p=75000kg*m/s\)

The relative efficiency of ˆλ1 to ˆλ2 is 1/n. This means that as the sample size n increases, the relative efficiency of ˆλ1 to ˆλ2 decreases, indicating that ˆλ2 (the sample mean) becomes a more efficient estimator for λ in comparison to ˆλ1 (the first observation).

To calculate the relative efficiency of two unbiased estimators ˆλ1 and ˆλ2 for λ, we need to compare their variances. The estimator with the smaller variance is more efficient.

Let's denote the variances of ˆλ1 and ˆλ2 as V(ˆλ1) and V(ˆλ2), respectively.

Given a random sample of size n from a Poisson distribution, the mean and variance of the distribution are both equal to λ.

For ˆλ1 = x1 (the first observation), the variance V(ˆλ1) is simply the variance of a single observation, which is λ.

For ˆλ2 = x (the sample mean), the variance V(ˆλ2) is the variance of the sample mean, which is λ/n.

Now, let's calculate the relative efficiency of ˆλ1 to ˆλ2:

Relative Efficiency = V(ˆλ2) / V(ˆλ1) = (λ/n) / λ = 1/n

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Answer:

the Value of angle is 78.5

I hope this help

ANSWER

A. 100 Hz

EXPLANATION

Given:

• The velocity of the wave, v = 300 m/s

• The wavelength, λ = 3 m

Find:

• The wave's frequency, f

The frequency of a wave with a wavelength λ and a velocity v is,

Replace the known values and solve,

Hence, the frequency of the wave is 100 Hz.

Answer:

Antacids.

Explanation:

Magnesium hydroxide is commonly used for sicknesses and etc.

Answer:

monochromator

Explanation:

Answer:

Below

Explanation:

Use formula for EPE :

EPE  =  1/2 k x^2  

480 j = 1/2 (60 N/m) x^2      shows x = 4 meters

More 400-nm light would be reflected, because some of the light transmitted through the first layer could be reflected by the second layer, light transmitted by the second layer could be reflected by the third, etc. is the correct answer. The correct option is option (2).

In the case of multiple thin films stacked together in a butterfly's wing scale, interference effects play a crucial role in determining the light that is reflected. As light passes through each thin film layer, some of it is transmitted through the film, and some is reflected. The transmitted light then interacts with the subsequent layers and can be further reflected or transmitted.

The multiple layers of thin films create a complex interference pattern where the reflected light waves from each layer either reinforce or cancel out each other. This interference pattern depends on the thickness and refractive indices of the films.

For certain wavelengths of light, constructive interference occurs, causing those wavelengths to be enhanced and reflected more strongly.

Therefore, more 400-nm light (or other specific colors) would be reflected due to the constructive interference of light waves from the multiple layers of thin films in the butterfly's wings. This phenomenon is responsible for the vibrant and iridescent colors seen in butterfly wings. The correct option is option (2).

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The complete question is:

Several thin films are stacked together in each butterfly wing scale. How would these multiple layers of thin films affect the light reflected by the butterfly's wings?

1) There would be no change, because all of the 400−nm light would be reflected by the first scale, and so the light is unaffected by the remaining scales.

2) More 400-nm light would be reflected, because some of the light transmitted through the first layer could be reflected by the second layer, light transmitted by the second layer could be reflected by the third, etc.

3) Less 400−nm light would be reflected because light reflected from the second layer can interfere destructively with light reflected by the first layer.

4) There would be no change because the interference effects would all occur at the first layer.

5) More 400-nm light would be reflected because the effective gap would be three times as wide.

6) Less 400−nm light would be reflected because the effective gap would be three times as wide.