Ammonia will decompose into nitrogen and hydrogen at high temperature. An industrial chemist studying this reaction fills a 5.0 L flask with 4.4 atm of ammonia gas, and when the mixture has come to equilibrium measures the partial pressure of hydrogen gas to be 4.0 atm Calculate the pressure equilibrium constant for the decomposition of ammonia at the final temperature of the mixture. Round your answer to 2 significant digits.

Answer:

Compound

Explanation:

It has a definite composition throughout and can be made of more than one type of element.

Cu₂+ and Ni₂+ are expected to form low-spin complexes, while Co₂+ is not.

Negatively charged subatοmic particles called electrοns can be free—that is, nοt bοund—οr bοnded tο an atοm. There are three main types οf particles in an atοm: prοtοns, neutrοns, and an electrοn that is bοnded tο an atοm. The nucleus οf an atοm is cοmpοsed οf prοtοns and electrοns.

According to the statement provided, metal ions with d8 or more electrons will always be low-spin, regardless of the identity of the attached ligands. Based on this information, we can determine which of the ions would be expected to form low-spin complexes:

Cu₂+ (d9): Since Cu₂ + has 9 d-electrons, it falls within the range of d8 or more electrons. Therefore, Cu₂ + is expected to form low-spin complexes.

Ni₂ + (d8): Ni₂ + also has 8 d-electrons, which falls within the range mentioned. Therefore, Ni₂ + is also expected to form low-spin complexes.

Co₂ + (d7): Co₂ + has 7 d-electrons, which is less than the required d8 or more electrons for low-spin complexes. Hence, Co₂ + is not expected to form low-spin complexes.

In summary, Cu₂ + and Ni₂ + are expected to form low-spin complexes, while Co₂ + is not.

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Answer:

1-a

Explanation:

science to understand while tech. make the work easier

Explanation:

solute is the substance being dissolved so that is the 2 tablespoons of lemonade and the 2 cups of water is the solvent.

The amount of heat released by the iron is 1610 J.

To calculate the amount of heat released by the iron, we can use the equation:

q = m x c x ΔT

where q is the amount of heat released, m is the mass of the water, c is the specific heat capacity of water, and ΔT is the change in temperature of the water.

First, we can calculate the mass of the water using its density (1 g/mL):

mass of water = volume of water x density of water

mass of water = 50.0 mL x 1 g/mL

mass of water = 50.0 g

Next, we can calculate the change in temperature of the water:

ΔT = final temperature - initial temperature

ΔT = 26.4°C - 18.7°C

ΔT = 7.7°C

The specific heat capacity of water is 4.184 J/(g·°C). Therefore, the amount of heat released by the iron can be calculated as:

q = m x c x ΔT

q = 50.0 g x 4.184 J/(g·°C) x 7.7°C

q = 1610 J

Therefore, the heat produced by the iron is 1610 J. Option A is correct.

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Answer:

Without the respiratory system your blood would be useless. The circulatory and respiratory systems work together to circulate blood and oxygen throughout the body

Explanation:

Answer:

The mass of the atom, its atomic mass, depends upon the sum of the number of protons and the number of neutrons present in the nucleus. Since the properties of the electrons depend upon the number of protons in the nucleus of an atom, each different atomic number corresponds to a qualitatively different kind of atom.

Answer:

This is really an extended comment to Geoffrey's answer, so please upvote Geoffrey's answer rather than this.

The mass of a hydrogen atom is 1.67353270×10−27 kg. If you add the masses of a proton and electron together then they come to 1.67353272×10−27 kg. The difference is about 13.6eV, which is the ionization energy of hydrogen (though note that the experimental error in the masses isn't much less than the difference so this is only approximate).

This shouldn't surprise you because you have to add energy (in the form of a 13.6eV photon) to dissociate a hydrogen atom into a free proton and electron, and this increases the mass in accordance with Einstein's famous equation

Equilibrium concentrations are : Question 39: 0.000798 ;  Question 40: 0.001202 M ;  Question 41:  0.001596 M. To determine the values indicated in the grid above for the given reaction, we need to use the equilibrium constant expression: Kc = [H₂][F₂]/[HF]²   where [H₂], [F₂], and [HF] are the equilibrium concentrations of the respective species.

We are given that the initial concentrations of He and F are both 0.0020 M, and we are also given that the equilibrium constant (Kc) for the reaction is 115. Using this information, we can set up an ICE table to calculate the equilibrium concentrations:

H₂(g) + F₂(g) ⇌ 2HF(g)
I:    0.0020      0.0020         0
C:   -x            -x           +2x
E:    0.0020-x 0.0020-x 0+2x
where x is the change in concentration (in M) at equilibrium.

Using the equilibrium constant expression, we can write:
Kc = [H₂][F₂]/[HF]²
115 = (0.0020-x)(0.0020-x)/(2x)²
4x⁴ - 0.004x³ - 0.000004x² + 0.00000016x - 0.0000000004 = 0

This equation can be solved using numerical methods, such as a graphing calculator or computer program. Solving this equation gives us: x = 0.000798 M
[H₂] = 0.0020 - x = 0.001202 M
[F₂] = 0.0020 - x = 0.001202 M
[HF] = 2x = 0.001596 M

Therefore, the values in the grid are:
0.0017 0.0020 0.0034 0.011
0.0017 0.001202 0.000798 0.001202
0.0017 0.001596 0.001596 0.001596

Question 39: Determine x in the grid above.
x = 0.000798 M
Answer: 0.000798

Question 40: Determine the equilibrium concentration of F₂.
[F₂] = 0.001202 M
Answer: 0.001202 M

Question 41: Determine the equilibrium concentration of HF.
[HF] = 0.001596 M
Answer: 0.001596 M

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Answer: B

Explanation:

At equilibrium, the rate of the forward reaction is equal to the rate of the reverse reaction, and thus the concentrations of the reactants and products must be constant.

No, but Group 1 elements can. Group 1 elements (alkali metals such as Li, Na, K...) all have one valence electron that they donate when forming ionic bonds. This will cause them to have a charge of +1.

Out of the molecules F₂, B₂, O₂, N₂, only O₂ is paramagnetic. Therefore, the correct answer is (B) 1. Paramagnetic substances have unpaired electrons in their molecular orbitals.

In O₂, there are two unpaired electrons, which makes it paramagnetic. On the other hand, F₂, B₂, and N₂ have all of their electrons paired in their molecular orbitals, making them diamagnetic. Diamagnetic substances do not exhibit any unpaired electrons and are weakly repelled by a magnetic field.

O₂ is the only molecule among the given options that is paramagnetic due to its unpaired electron configuration, while F₂, B₂, and N₂ are diamagnetic as they have all of their electrons paired in their molecular orbitals.

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Answer:

Her speed is 6.8m/s.

Explanation:

K.E= 1/2mv²

or, 2543.2= 1/2×110×v²

or, 2543.2 = 55v²

or, 2543.2/55 = v²

or, 46.24 = v²

or, 6.8² = v²

v = 6.8 m/s

answer

6.8

explanation

k.e=1/2v^2

2543.2=55v^2

46.24=v^2

6.8^2=v^2

v=6.8

Answer:

A- Physical, B- Chemical, C- chemical, D- Physical

Explanation:

A is physical because you can see it changing its form is changing.

B is Chemical because a new substance is formed creating the orange color of rust.

C is a Chemical reaction because it is being broken down so the banana itself is changing not just how we see it.

D is physical because we are just changing the shape/ size of the item, not anything to do with its substances.

Answer:

a. physical change, it is reverse reversible since no new substance is created.

b.chemical change, The iron reacts with water and oxygen to form hydrated iron(III) oxide, which we see as rust.

c. chemical change, Bananas contain compounds known as polyphenol oxidases and iron-containing chemicals. These chemicals react with oxygen to turn the fruit brown.

d. physical change, there is no new substance created, and there is no change in the original composition of wood.

The reaction of the starch in the potato with the iodine solution gives a bluish black colour.

Option C is correct.

Iodine reacts with starch to form a deep blue-black complex. The reaction between starch and iodine is an example of an oxidation-reduction reaction. When iodine comes into touch with the starch, it oxidizes the starch's glucose components to form a polymeric sugar molecule.In the absence of starch, iodine is a brownish-red solid, and when dissolved in water or ethanol, it produces a purple solution.

Iodine reacts with starch, a polymer of glucose, to form a deep-blue-black compound. This reaction has been utilized to determine the presence of starch in solution. When iodine is introduced to a potato, the starch in the potato reacts with the iodine to form a bluish-black color.

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Answer:

2,5,4,1,3

Explanation:

Answer:

Ionic Bond

Explanation:

The mass of Cr₃⁺ in the original solution of 1.00 L of 1.51 M NaF solution causes the complete precipitation of  CrF₃(s) and MgF₂2(s) and the total mass of the precipitate is 49.6 g is 27.0 g.

To solve this problem, we need to use stoichiometry and the concept of limiting reagents. First, we need to write the balanced chemical equation for the precipitation reaction:

2 Cr₃⁺ + 3 Mg₂⁺ + 6 F⁻ → 2 CrF₃(s) + 3 MgF₂(s)

From the equation, we can see that the ratio of Cr₃⁺ to Mg₂⁺ to F⁻ is 2:3:6.

Next, we need to calculate the number of moles of NaF added to the solution:

1.00 L x 1.51 mol/L = 1.51 mol NaF

Since NaF is a soluble salt, it will dissociate completely in water to form Na⁺ and F⁻ ions. Therefore, the number of moles of F⁻ ions added to the solution is also 1.51 mol.

Now, we can use the ratio of Cr₃⁺ to F⁻ from the balanced equation to determine the limiting reagent:

2 mol Cr₃⁺ : 6 mol F⁻ = 1 mol Cr₃⁺ : 3 mol F⁻

1.51 mol F⁻ / 3 mol F⁻ per Cr₃⁺

= 0.5033 mol Cr₃⁺

Since we have only added 0.5033 mol of F⁻, Cr₃⁺ must be the limiting reagent. Therefore, all the Cr₃⁺ ions will react with the F⁻ ions to form a CrF₃ precipitate.

To find the mass of Cr₃⁺ in the original solution, we need to calculate the number of moles of CrF₃ precipitate formed:

2 mol CrF₃ : 2 mol Cr₃⁺ = 1 mol CrF₃ : 1 mol Cr₃⁺

49.6 g / 180.01 g/mol = 0.2755 mol Cr₃⁺

Therefore, the original solution must have contained 0.2755 mol of Cr₃⁺. To convert this to mass, we can use the molar mass of Cr₃⁺:

= 0.2755 mol x 97.99 g/mol

= 27.0 g Cr₃⁺

Therefore, the mass of Cr₃⁺ in the original solution was 27.0 g.

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Answer:

1. false

2. A

were is the question for the 3rd one?

4. B

5. B

6. C

Explanation:

Answer:

An organism's role within an ecosystem depends on how it obtains its food. Plants and animals obtain their food in very different ways, so they have very different roles in an ecosystem. The way in which an organism obtains food also affects its interactions with other organisms in the ecosystem.

Explanation:

The maximum amount of carbon dioxide that can be formed from 15.2 g of glucose is approximately 22.31 grams.

To determine the maximum amount of carbon dioxide (CO2) that can be formed from 15.2 g of glucose (C6H12O6), we need to use the stoichiometry of the balanced chemical equation for the combustion of glucose.

The balanced chemical equation for the combustion of glucose is:
C6H12O6 + 6O2 -> 6CO2 + 6H2O

From the equation, we can see that 1 mole of glucose reacts with 6 moles of oxygen to produce 6 moles of carbon dioxide.

First, we need to calculate the number of moles of glucose in 15.2 g:
Molar mass of glucose (C6H12O6) = (12.01 g/mol x 6) + (1.01 g/mol x 12) + (16.00 g/mol x 6) = 180.18 g/mol
Moles of glucose = Mass of glucose / Molar mass of glucose = 15.2 g / 180.18 g/mol ≈ 0.0845 mol

Since 1 mole of glucose reacts with 6 moles of oxygen, we need to multiply the number of moles of glucose by 6 to determine the moles of oxygen:
Moles of oxygen = 0.0845 mol x 6 = 0.507 mol

Finally, since 1 mole of glucose produces 6 moles of carbon dioxide, we can calculate the maximum amount of carbon dioxide formed:
Moles of carbon dioxide = Moles of glucose x 6 = 0.0845 mol x 6 = 0.507 mol

To convert the moles of carbon dioxide to grams, we can multiply by the molar mass of carbon dioxide:
Molar mass of carbon dioxide (CO2) = (12.01 g/mol x 1) + (16.00 g/mol x 2) = 44.01 g/mol
Mass of carbon dioxide = Moles of carbon dioxide x Molar mass of carbon dioxide = 0.507 mol x 44.01 g/mol ≈ 22.31 g

Therefore, the maximum amount of carbon dioxide that can be formed from 15.2 g of glucose is approximately 22.31 grams.

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Answer:

Hi

Please mark brainliest ❣️

Thanks

Explanation:

Correct answer is D

Energy A

Look at this

Energy required to break bonds that is intermolecular forces

Answer:

12

Explanation:

The pH of the solution prepared has been 1.25.

The pH of the solution resulting from the mixing of the two solutions can be given by:

Hydrogen ion concentration = \(\rm \dfrac{M_1V_1\;-\;M_2V_2}{V_1\;+\;V_2}\)

Where, M1 and M2 have been the molarity of the solution and V1 and V2 have been the volume of the solutions.

For the given resulted solution:

Hydrogen ion concentration = \(\rm \dfrac{0.1\;\times\;0.15L\;-\;0.2\;\times\;0.05L}{0.15\;+\;0.05\;L}\)

Hydrogen ion concentration = 0.055 M

pH can be defined as the negative logarithm of hydrogen ion concentration.

pH = - log (Hydrogen ion concentration)

pH = -log (0.055)

pH = 1.25

The pH of the solution prepared has been 1.25.

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In the Lewis structure of methanol (CH3OH), the OH group is placed on the outside because it is an important functional group that influences the chemical properties and reactivity of the molecule.

The Lewis structure is a representation of a molecule that shows the arrangement of atoms and valence electrons. In methanol, carbon (C) is the central atom bonded to three hydrogen (H) atoms and one oxygen (O) atom. The oxygen atom forms a single bond with carbon and also has two lone pairs of electrons.

The placement of the OH group (hydroxyl group) on the outside of the Lewis structure is significant because it determines the chemical behavior of methanol. The OH group consists of an oxygen atom bonded to a hydrogen atom and represents the presence of an alcohol functional group.

In organic chemistry, functional groups are specific arrangements of atoms within a molecule that give rise to characteristic chemical reactions and properties. The presence and position of functional groups can greatly influence the behavior and reactivity of a compound. In the case of methanol, the hydroxyl group provides the molecule with its characteristic properties.

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Answer:

hydrogen bonding among water molecules

Explanation:

The standard molar enthalpy of formation for sodium hydroxide is -55 kJ/mol.

The standard molar enthalpy of formation for a substance is the amount of energy required to form one mole of that substance from its component elements in their standard states.

In this case, the reaction given is 2 NaOCl(aq)+NH3(aq)⇆ NHCl2(aq)+2 NaOH(aq) with an overall enthalpy change of -470 kJ/mol. According to Hess's Law, the overall enthalpy change is equal to the sum of the enthalpy changes of each component.

In this case, we need to change the sign of the reactants as they are consumed, not formed, and thus will have a positive value. Therefore, the enthalpies of formation for ammonia and bleach are +350 kJ/mol and +45 kJ/mol respectively.

When adding these values and the enthalpy of formation of NHCl2(aq) which is 140 kJ/mol and using x as the value for the enthalpy of formation of NaOH(aq) we can find that x=-55 kJ/mol.

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Theoretical yield is calculated based on the stoichiometry of the reaction and the limiting reactant. Part A and Part B have equal moles of Mn and O₂, so the limiting reactant is either. The theoretical yield is 5 mol MnO₂. Part C has an excess of O₂, so Mn is the limiting reactant. The theoretical yield is 27 mol MnO₂.

The balanced chemical equation for the reaction is:

2Mn(s) + O₂(g) → 2MnO(s)

The stoichiometry of the reaction shows that 2 moles of Mn reacts with 1 mole of O₂ to form 2 moles of MnO. Therefore, we can use this information to calculate the theoretical yield of the product for each case:

Part A:

Mn is limiting reactant as we have 5 mol Mn and only 2.5 mol O₂ is needed to react with all the Mn. Therefore, O₂ is in excess and will remain after the reaction.

Theoretical yield of MnO₂ = 2 mol MnO₂ / 2 mol Mn = 1 mol MnO₂

Therefore, the theoretical yield of MnO₂ is 1 mol.

Part B:

O₂ is limiting reactant as we have 9 mol O₂ and only 1.5 mol Mn is needed to react with all the O₂. Therefore, Mn is in excess and will remain after the reaction.

Theoretical yield of MnO₂ = 2 mol MnO₂ / 1 mol O₂ = 2 mol MnO₂

Therefore, the theoretical yield of MnO₂ is 2 mol.

Part C:

Mn is limiting reactant as we have 27.0 mol Mn and only 13.5 mol O₂ is needed to react with all the Mn. Therefore, O₂ is in excess and will remain after the reaction.

Theoretical yield of MnO₂ = 2 mol MnO₂ / 2 mol Mn = 1 mol MnO₂

Therefore, the theoretical yield of MnO₂ is 1 mol.

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Answer:

A- Group 1/1A

Explanation:

In group 1A they are all highly reactive metals, which tarnish when exposed to air.

Answer:

Agree

Explanation:

Answer:

Agree

Explanation:

Answer:

Explanation:

Here, we want to write the net ionic equation

We start by writing the complete equation of reaction:

Now, we write out the ions as follows:

The Chromium and Nitrate ions are spectator ions

Thus, we have:

Answer:

Cobertura vegetal, mantillo y piedra triturada.

Explicación:

Para evitar la degradación del suelo, debemos plantar una cubierta vegetal perenne que proteja el suelo de la erosión del viento y el agua sujetándolo firmemente con sus raíces. El mantillo también se usa para prevenir la erosión del suelo. En aquellas zonas donde la cobertura vegetal no es posible, tenemos que utilizar piedras trituradas para cubrir el suelo con el fin de evitar el contacto directo con el viento. Entonces, estas acciones pueden prevenir la degradación del suelo y mantener el suelo en su estado original.