Amplify Chemical reactions lesson 1.5

Based on the atomic-scale models of the samples, which of the following claims do you think is best?


Does the evidence from the Sim support the claim you choice?


What evidence did you find I'm the sim to support your answer?

HELP ME QUICKKKKK I NEED THE ANSWERS RNNN

To prepare the desired NaHCO₃⁻ Na₂CO₃ buffer solution with pH=10.38, we would mix 0.212 M NaHCO₃ and 0.1 M Na₂CO₃ in the appropriate ratio.

To prepare a NaHCO₃⁻ Na₂CO₃ buffer solution with pH=10.38, we need to choose the appropriate ratio of NaHCO₃ and Na₂CO₃.

First, we need to calculate the pKa values for the two dissociation steps of H₂CO₃: pKa1=-log(4.3×10⁻⁷)=6.37 and pKa2=-log(5.6×10⁻¹¹)=10.25.

Since we want the pH of the buffer to be 10.38, which is closer to pKa2, we will use the Henderson-Hasselbalch equation for the second dissociation step:

pH = pKa2 + log([NaHCO₃]/[Na₂CO₃])

We can rearrange this equation to solve for the ratio [NaHCO₃]/[Na₂CO₃]:

[NaHCO₃]/[Na₂CO₃] = 10^(pH - pKa2)

Plugging in the given values, we get:

[NaHCO₃]/[Na₂CO₃] = 10^(10.38 - 10.25) = 2.12

This means that the ratio of [NaHCO₃] to [Na₂CO₃] in the buffer should be 2.12. We can then use this ratio to determine the actual concentrations of the two components in the buffer solution. For example, if we choose to make a 1 L buffer solution, we can set [Na₂CO₃] to be 0.1 M, and then calculate [NaHCO₃] as follows:

[NaHCO₃] = [Na₂CO₃] x [NaHCO₃]/[Na₂CO₃] = 0.1 M x 2.12 = 0.212 M

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The missing subscript that will balance the equation is 92.

The given Radioactive decay chemical equation is,

²³⁴U → ²³⁰Th₉₀ + ⁴He₂ + Energy

In the above reaction, the Uranium atom is decayed into the Thorium atom and a helium nucleus is released from Uranium along with energy.

When a bigger atom is unstable, it decays into smaller stable atoms by radioactive decay, one such decay is Alpha Decay.

In Alpha Decay, the mass number of the decaying particle gets reduced by four units and the atomic number of the decaying particle reduces by two. i.e. A helium nucleus is released from the the particle.

So the atomic of the not decayed uranium will be 2 more then the atomic number of thorium.

So, our balanced reaction will be,

²³⁴U₉₂ → ²³⁰Th₉₀ + ⁴He₂ + Energy.

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Answer:

Well, you'd have 1 electron more than protons (since there are 10 protons and 11 electrons). So the previously neutral ion has now become an ion with a -1 charge

Answer:

Not doubled

Explanation:

The equation below represent the ideal gases relationship

PV ÷ T = constant

Here

P denotes pressure,

V denotes volume,

T denotes temperature in degrees Kelvin

Now

20 ° c = 273 + 20

= 293 K

And,

40 ° c = 313 K

So,

V = Vo. 313 K ÷  293 K = 1.07 Vo

So,  the volume is NOT doubled.

In the case when the temperature would be determined in degrees celsius at 0 degrees so the volume would be zero

Answer:

32

Explanation:

There cannot be more in a number than the number. Therefore, the answer has to be D, or 32.

Hope this helps! :)

Answer:

stratus​

Explanation:

The type of cloud that forms close to the ground when the temperature is just above the dew point would be stratus.

Stratus cloud forms when moisture condenses at low-level as a result of light air current pushing cold air above a pocket of warm air.

Stratus clouds are the most similar to fog among all the cloud types because both are formed at low altitudes. However, while fogs are formed from ground moisture, stratus clouds are formed from air moisture.

Answer: C-fog

Explanation: Cirrus, cumulus, and stratus, all form high. Fog forms low.

The average atomic mass of the element, given the various isotopic mass of the element, is 87.71 amu

The following data were obtained from the question given above:

The average atomic mass of the element is defined by the following formula:

Average atomic mass = [(Mass of 1st × 1st%) / 100] + [(Mass of 2nd × 2nd%) / 100] + [(Mass of 3rd × 3rd%) / 100] + [(Mass of 4th × 4th%) / 100]

Inputting the given parameters, we have:

= [(84 × 0.56) / 100] + [(86 × 9.86) / 100] + [(87 × 7) / 100] + [(88 × 82.58) / 100]

= 0.4704 + 8.4796 + 6.09 + 72.6704

= 87.71 amu

Thus, the average atomic mass of the element is 87.71 amu

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Answer:

Water is a remarkable substance, and its unique properties are largely due to the presence of polar covalent bonds and hydrogen bonds in its structure. These characteristics play a crucial role in the physical and chemical properties of water, making it essential for life as we know it.

Explanation:

The polar covalent bonds in water arise from the unequal sharing of electrons between oxygen and hydrogen atoms. This results in the oxygen atom having a partial negative charge (δ-) and the hydrogen atoms having partial positive charges (δ+). These charges create polarity within the water molecule, leading to the formation of hydrogen bonds.

Hydrogen bonds occur when the partially positive hydrogen atom of one water molecule is attracted to the partially negative oxygen atom of another water molecule. These hydrogen bonds are relatively weak individually, but when present in large numbers, they contribute to the cohesion, surface tension, and high boiling point of water.

The importance of these bonds is manifold. The cohesion between water molecules due to hydrogen bonding enables water to form droplets, have a high surface tension, and flow freely, facilitating transport within organisms and in the environment. Additionally, hydrogen bonding leads to the high specific heat capacity and heat of vaporization of water, making it an effective regulator of temperature in living organisms and ensuring stable environmental conditions.

Furthermore, hydrogen bonds play a crucial role in the unique properties of water as a solvent. The polar nature of water allows it to dissolve a wide range of substances, including ionic compounds and polar molecules, facilitating various biological processes such as nutrient transport and chemical reactions in cells.

Answer:

sp³-s sigma bond.

Hope that was the answer

Mass of potassium bromide must be dissolved to prepare 100 ml of a 0.164 m aqueous solution is 1.95 gram

It is given that

volume of aqueous solution = 100 ml

molarity of solution = 0.164 m

We have to find mass of potassium bromide

Molarity (M) is the amount of a substance in a certain volume of solution. Molarity is defined as the moles of a solute per liters of a solution. Molarity is also known as the molar concentration of a solution

Molarity = (given mass/molar mass) x (1/volume of solution)

0.164 = (mass/119) x 1000/100

0.164 = mass/119 x 10

0.164 x 119/10 = mass

mass = 1.95 gram

Hence, Mass of potassium bromide must be dissolved to prepare 100 ml of a 0.164 m aqueous solution is 1.95 gram

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Answer:

A

Explanation:

Because it got smaller so that mean it had a chemical reaction

The equilibrium constant for the decomposition of PCl₅ to PCl₃ and Cl₂ at this temperature is 0.600.

The balanced equation for the decomposition of PCl₅ to PCl₃ and Cl₂ is:

At equilibrium, the number of moles of PCl₃ and Cl₂ are equal, which is 0.36 mol each. Therefore, the number of moles of PCl₅ that reacted is:

Using the equilibrium expression, Kc, we can solve for the equilibrium constant:

Therefore, the value of the equilibrium constant for the decomposition of PCl₅ to PCl₃ and Cl₂ at this temperature is 0.600.

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Answer:

I don't know what are the options but I just took it from net

Explanation:

A) 2NO (g) + O2 (g) →2NO2 (g)

Reactant have 2+1= 3 moles, whereas product have 2 moles

Since no of moles of reactant is greater than product, entropy is decreasing

Answer:

pharynx

Explanation:

The pharynx, usually called the throat, is part of the respiratory system and digestive system. It carries air, food and fluid down from the nose and mouth. The pharynx is the site of common illnesses, including sore throat and tonsillitis.

Explanation:

Pharynx (Throat) The pharynx, usually called the throat, is part of the respiratory system and digestive system. It carries air, food and fluid down from the nose and mouth. The pharynx is the site of common illnesses, including sore throat and tonsillitis.

The materials that pick up positive charge are nylon rubbed with wool and which pick up negative charge is glass rubbed with silk. You can determine this by degree of electron affinity.

When different materials are rubbed together, one material will gain electrons from the other and become negatively charged. The material that loses electrons will become positively charged. Here are some examples: Materials that pick up negative charge include glass rubbed with silk, wool rubbed with amber, and rubber rubbed with fur.

Materials that pick up positive charge include nylon rubbed with wool, and polythene rubbed with rabbit fur. The determination of whether a material will become positively or negatively charged depends on the degree of electron affinity.

When two different materials are rubbed together, the electrons move from one material to another due to the difference in electron affinity and one material gains an electron while the other loses an electron. This is the reason why certain materials become positively charged and others become negatively charged.

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Answer:

Part (1a): The number of moles are 2.14 moles.

Part (1b): The number of moles are 12.2 moles.

Part (1c): The number of moles are 0.545 moles.

Part 2: The number of molecules are 1.38 × 10²⁵.

Part 3: The number of moles are 5.65 moles.

Part 4: The number of atoms are 1.81 × 10²⁴.

Part 5: The number of molecules are 1.20 × 10²⁶.

Explanation:

According to the mole concept:

1 mole of substance contains 6.022 × 10²³ number of atoms or molecules.

Part (1a): 1.29 × 10²⁴ hydrogen atoms in H

As, 6.022 × 10²³ number of hydrogen atoms present in 1 mole

So, 1.29 × 10²⁴ number of hydrogen atoms present in \(\frac{1.29\times 10^{24}}{6.022\times 10^{23}}=2.14\) mole

Part (1b): 7.36 × 10²⁴ oxygen atoms

As, 6.022 × 10²³ number of oxygen atoms present in 1 mole

So, 7.36 × 10²⁴ number of oxygen atoms present in \(\frac{7.36\times 10^{24}}{6.022\times 10^{23}}=12.2\) mole

Part (1c): 3.28 × 10²³ Na atoms

As, 6.022 × 10²³ number of Na atoms present in 1 mole

So, 3.28 × 10²³ number of Na atoms present in \(\frac{3.28\times 10^{23}}{6.022\times 10^{23}}=0.545\) mole

Part 2:

As, 1 mole of oxygen contains 6.022 × 10²³ number of molecules

So, 23.0 moles of oxygen contains 23.0 × 6.022 × 10²³ = 1.38 × 10²⁵ number of molecules

Part 3:

As, 6.022 × 10²³ number of H₂SO₄ molecules present in 1 mole

So, 3.4 × 10 number of H₂SO₄ molecules present in \(\frac{3.4\times 10}{6.022\times 10^{23}}=5.65\) mole

Part 4:

As, 1 mole of Na contains 6.022 × 10²³ number of atoms

So, 3.0 moles of Na contains 3.0 × 6.022 × 10²³ = 1.81 × 10²⁴ number of atoms

Part 5:

As, 1 mole of O₃ contains 6.022 × 10²³ number of molecules

So, 200 moles of O₃ contains 200 × 6.022 × 10²³ = 1.20 × 10²⁶ number of molecules

By using Dalton’s law of partial pressure, it is calculated that the \(CO_2\)collected in the experiment has a pressure of 725.35 mm Hg.

A gas mixture's total pressure is equal to the total of the partial pressures of its component gases, according to Dalton's law of partial pressures.

Looking at the pressure in a closed container of gas and water is a frequent application of the Dalton's law of Partial Pressures. The pressure that the gas puts on the liquid is the system's overall pressure.

Real gases do not behave in an ideal manner; instead, they behave in an ideal manner only at low pressures and high temperatures. As a result, Dalton's law of partial pressure is only relevant at low pressures and low temperatures; it is not applicable at high pressures and low temperatures.

Given:

Pressure of mixture = 744 mm Hg

Temperature = 21℃

Pressure of Water vapour = 18.65 mm Hg

To find:

Pressure of \(CO_2\) = ?

Formula:

Pressure of mixture = Pressure of \(CO_2\) + Pressure of water vapour

Pressure of \(CO_2\) = 744 - 18.65

P of \(CO_2\) = 725.35 mm Hg

Result:

The pressure of \(CO_2\) collected in the experiment is 725.35 mm Hg, according to Dalton’s law of partial pressure.

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The strength of an acid depends on its ability to donate a hydrogen ion (H+) in an aqueous solution. In binary acids, the strength of the acid is largely determined by the polarity of the bond between the hydrogen and the non-metallic element.

In the first pair of binary acids, HCl and HI, the stronger acid is HI. This is because the bond between hydrogen and iodine in HI is longer and weaker than the bond between hydrogen and chlorine in HCl. This makes it easier for the H+ ion to dissociate from HI in an aqueous solution, making it a stronger acid.

In the second pair of binary acids, H2O and HF, the stronger acid is HF. This is because fluorine is more electronegative than oxygen, which means that the bond between hydrogen and fluorine is more polar than the bond between hydrogen and oxygen. This makes it easier for the H+ ion to dissociate from HF in an aqueous solution, making it a stronger acid.

In the third pair of binary acids, H2Se and H2S, the stronger acid is H2Se. This is because selenium is larger than sulfur, which means that the bond between hydrogen and selenium is longer and weaker than the bond between hydrogen and sulfur. This makes it easier for the H+ ion to dissociate from H2Se in an aqueous solution, making it a stronger acid.

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The compound that will readily react with a solution of bromine consisting of 48% hydrobromic acid and 30% hydrogen peroxide is acetic acid.Hydrobromic acid is a solution of hydrogen bromide (HBr) in water.

It is a strong acid that can be used for several industrial purposes. Hydrogen peroxide is a reactive chemical with the chemical formula H2O2. When combined with hydrobromic acid, hydrogen peroxide forms a solution known as hydrobromic acid. Bromine is a non-metallic element that reacts with many compounds to form new substances.Acetic acid (CH3COOH) is a weak organic acid that is commonly found in vinegar and is used in the production of cellulose acetate.

When acetic acid is mixed with a solution of bromine containing 48% hydrobromic acid and 30% hydrogen peroxide, it reacts readily. This reaction will produce a new compound.The other three options (cyclohexane, dichloromethane, t-butyl alcohol, and cyclohexene) do not have any active functional groups such as an alcohol, carboxylic acid, or an unsaturated bond that can undergo halogenation or oxidation reactions. Therefore, they will not react with a solution of bromine consisting of 48% hydrobromic acid and 30% hydrogen peroxide.

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Answer:

D

Explanation:

Solvent is the material that is dissolving another material​. Thus, option D is correct.

A solvent is a substance that dissolves another substance to form a solution. The substance that is being dissolved is called the solute, and the substance that is doing the dissolving is called the solvent. The solute is usually present in a smaller amount than the solvent, and it is the solvent that determines the physical properties of the solution, such as its density, viscosity, and boiling point.

For example, when salt is dissolved in water, the salt is the solute and the water is the solvent. The water molecules surround the salt molecules and break them apart, so that the salt ions are free to move around in the solution. The solution is then a homogeneous mixture of salt ions and water molecules.

Thus, option D is correct.

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Answeruuuuu it's b I think

Answer:

(dunno exactly but i put:)

3.8 m/s the reaction rate at 1000 k when the concentration of no is increased to 0.14 m , while the concentration of h2 is 1.80×10−2 m

The computation of the reaction rate in case when NO is increased to 0.12 M is shown below: According to the question, data provided is as follows

NO = 0.12M

H2= 1.80×10−2 m

Based on the above information

Reaction rate is

= 6*10-4 (0.14)²(1.80×10−2 m)

= 3.8 m/s

Hence, the reaction rate of 1,000 k is 3.8 m/s and the same is to be considered.

When the rates of the forward and reverse processes are similar and the concentrations of the reactants and products are stable, a chemical equilibrium condition is reached. We say the reaction has reached equilibrium when the concentrations of the reactants and products do not vary any further. A mixture of reactants and products is discovered at equilibrium.

what is the reaction rate at 1000 k when the concentration of no is increased to 0.14 m , while the concentration of h2 is 1.80×10−2 m ?

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Answer:

Boron and argon have 3 and 8 valence electrons respectively.

Aluminum and calcium have 3 and 2 valence electrons respectively.

Explanation:

Please give the brainliest.

a. Lewis structure of acetate ion is drawn in accordance with resonance forms of the molecule.

b. There is only one possible structure due to delocalization of carbon and oxygen atoms.

c. The bond order of the C-O bonds in the acetate ion is 1/2, which is 0.5.

d. The C-O bond lengthens in the acetate ion compared to the C-O bond in carbon dioxide.

e. The double bond character of the C-O bond is stronger, making it a shorter and stronger bond compared to the C-O bonds in the acetate ion.

a. To draw the Lewis structures of the acetate ion (CH3COO-), we need to consider the resonance forms of the molecule. Here are the possible equivalent resonance structures:

H H

| |

H-C=C-O⁻ ↔ O⁻C=C-H

| |

H H

b. In the above resonance structures, the double bond between the carbon and oxygen atoms can be delocalized, resulting in the charge being spread over the entire molecule.

c. The bond order of the C-O bonds in the acetate ion can be calculated by dividing the total number of bonds between carbon and oxygen by the number of resonance structures. In this case, there are two resonance structures, and each structure has one C-O bond. Therefore, the bond order of the C-O bonds in the acetate ion is 1/2, which is 0.5.

d. The C-O bonds in the acetate ion (CH3COO-) are longer than the C-O bond in carbon dioxide (CO2). This is because the delocalization of the negative charge in the acetate ion leads to a partial negative charge on both oxygen atoms, causing increased repulsion between the electron pairs. As a result, the C-O bond lengthens in the acetate ion compared to the C-O bond in carbon dioxide.

e. The C-O bonds in the acetate ion (CH3COO-) are weaker than the C-O bond in carbon dioxide (CO2). The delocalization of the negative charge in the acetate ion reduces the strength of the individual C-O bonds because the negative charge is spread over a larger region. In carbon dioxide, the double bond character of the C-O bond is stronger, making it a shorter and stronger bond compared to the C-O bonds in the acetate ion.

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Taking into account the reaction stoichiometry, 11.2 grams of BaSO₄ are produced from 10 g of barium chloride.

In first place, the balanced reaction is:

BaCl₂ + H₂SO₄ → BaSO₄ + 2 HCl

By reaction stoichiometry, the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

By reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: if by reaction stoichiometry 208.24 grams of BaCl₂ form 233.34 grams of BaSO₄, 10 grams of BaCl₂ form how much mass of BaSO₄?

mass of BaSO₄= (10 grams of BaCl₂× 233.34 grams of BaSO₄) ÷208.24 grams of BaCl₂

mass of BaSO₄= 11.2 grams

Finally, 11.2 grams of BaSO₄ are formed.

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Answer:

\(\boxed {\boxed {\sf 0.0014 \ mol \ Cu}}\)

Explanation:

We are asked to convert particles to moles.

1 mole of any substance contains the same number of particles (atoms, molecules, formula units). This is Avogadro's Number or 6.022*10²³.

In this problem, the particles are atoms of copper. So, 1 mole of copper contains 6.022*10²³ atoms of copper

Use Avogadro's Number to make a ratio.

\(\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} \ atoms \ Cu}\)

We are trying to convert 8.3*10²⁰ atoms of copper to moles, so we multiply that value by the ratio.

\(8.3*10^{20} \ atoms \ Cu*\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} \ atoms \ Cu}\)

The units of "atoms Cu" will cancel.

\(8.3*10^{20}\frac{ 1 \ mol \ Cu}{ 6.022*10^{23} }\)

Condense the expression into 1 fraction.

\(\frac{8.3 *10^{20}}{ 6.022*10^{23} } \ mol \ Cu\)

\(0.001378279641 \ mol \ Cu\)

The original measurement of atoms has 2 significant figures, so our answer must have the same. For the number we calculated that is the ten-thousandths place.

The 7 in the hundredth thousandth place tells us to round the 3 up to a 4.

\(0.0014 \ mol \ Cu\)

8.3*10²⁰ atoms of copper are equal to 0.0014 moles of copper.

Given: Volume of solution, V = 10 mLConcentration of solution, C = 0.5 mol/L.

With this, we can convert the volume from mL to L by dividing it by 1000. Therefore,V = 10 mL = 10/1000 L = 0.01L. Now, we can use the formula: n = C x V where,n = number of moles C = concentration of solutionV = volume of solution. Plugging in the values, we get,n = 0.5 mol/L x 0.01 L= 0.005 mol. In chemistry, mole is defined as a unit for measuring amount of substance. The symbol used for mole is 'mol'. This unit helps to express the number of particles in a sample of substance. For instance, one mole of a substance contains 6.022 x 10²³ particles of that substance.A solution is a homogeneous mixture of two or more substances. The concentration of a solution refers to the amount of solute present per unit volume of the solution. It is usually expressed in moles per litre (mol/L) or molarity.

Molarity is defined as the number of moles of solute present in one litre of solution. It is given by the formula:M = n/Vwhere,M = molarity of the solutionn = number of moles of solute presentV = volume of the solution in litresIn the given question, we are given the volume of solution and its concentration. Therefore, we can use the formula:M = n/Vto find the number of moles of HCl present in 10 mL of a solution with a concentration of 0.5 mol/L. There are 0.005 moles of HCl present in 10 mL of a solution with a concentration of 0.5 mol/L.

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decay rate of approximately 1.69x10^17 Bq (becquerels),

The decay rate of a radioactive sample is determined by the number  of radioactive atoms present and the decay constant, which represents the probability of decay per unit of time.

To calculate the decay rate, we multiply the number of atoms in the sample by the decay constant. In this case, the sample has 8.31x10^17 atoms and a decay constant of 0.203/s. Multiplying these values gives a decay rate of approximately 1.69x10^17 Bq (becquerels), which represents the number of decays per second in the sample.

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