Amy practice yoga 20 minutes each day before school and 30 minutes each day after school she is in school Monday through Friday how many minutes does Amy practice yoga in four weeks please show your work

The monthly income of the first person is $600.

Given that, the average monthly income of three persons is RS 3,600.

The income of the first is 1/5 of the combined income of the other two.

Here, Let income of the first be A, let income of the second be B and let Income of the third be C.

A+B+C=3600 -----(i)

Income for the first person = 1/5(B+C) -----(ii)

Substitute equation (ii) in equation (i), we get

(B+C)/5 +B+C =3600

B+C+5B+5C=3600×5

6B+6C=18000

6(B+C)=18000

B+C=3000 ------(iii)

Substitute (iii) in equation (i), we get

A=$600

Therefore, the monthly income of the first person is $600.

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Answer:

a-25

b-243

5^3 = 125/3 = 25

3^6 = 729/3 = 243

Hello!

4.63 x 10^-3 = 0,00463

Answer:

Every investment carries some degree of risk, All investments carry some degree of risk. Stocks, bonds, mutual funds, and exchange-traded funds can lose value, even all their value, if market conditions sour. Even conservative, insured investments, such as certificates of deposit (CDs) issued by a bank or credit union, come with inflation risk. They may not earn enough over time to keep pace with the increasing cost of living.

Step-by-step explanation:

We know that

• A scientist uses 10 grams every 15 minutes.

To find the kilograms used in 3 hours, first, we transform 10 grams into kilograms

Then, we use the following proportion

Because 3 hours is equivalent to 180 minutes. Let's solve for x

Answer:

Ok, "steeper than y = x^2" means that the function grows "faster" than y = x^2. and we can look at this by looking at the derivates, if the derivate is larger, then it is steeper.

The derivate of y = x^2 is: y´= 2x.

Now let's look at the other functions.

a) y = (1/2)*x^2

the derivate is:

y' = 2*(1/2)*x = x

this function is less steep than y = x^2

b) y = -x^2

the derivate is:

y' = -2x

So we have, in absolut value, exactly the same than for y = x^2.

The difference is that here the function decays instead of growing, so this is "less steep than y = x^2)

c) y = (2x)^2 = 4*x^2

the derivate is:

y´= 2*4*x = 8*x

this is steeper than y = x^2-

d) y = 2x^2

the derivate is:

y´= 2*2*x = 4x.

this is steeper than y = x^2

e) y = (x/2)^2 = (1/4)*x^2

the derivat is:

y' = (2/4)*x = (1/2)*x

so this is lees steep than y = x^2

The coordinates of the image of quadrilateral DEFG after being reflected about the origin include the following:

D' = (9, 5).

E' = (-5, -4).

F' = (6, 2).

G' = (-4, -2).

In Geometry, a reflection can be defined as a type of transformation which moves every point of the object by producing a flipped but mirror image of the geometric figure.

Generally speaking, reflecting a point about the origin is a a type of transformation which causes both the x-coordinate and the y-coordinate to become negated (the signs are changed);

(x, y)                              →               (-x, -y)

Ordered pair D  = (-9, -5) →   Ordered pair D' = (9, 5).

Ordered pair E  = (5, 4) →   Ordered pair E' = (-5, -4).

Ordered pair F  = (-6, -2) →   Ordered pair F' = (6, 2).

Ordered pair G  = (4, 2) →   Ordered pair G' = (-4, -2).

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Answer:volume=hpir^2d/2=r, 24/2=12=rh=40v=40pi12²v=40pi144v=5760pi cubic inches per section

Step-by-step explanation:

Answer:

C

Step-by-step explanation:

First press 9, then the exponent key, then 6, and finally press the equal sign.

Answer:

Step-by-step explanation:

Let us denote probability of   spoilage as follows

Transformer spoilage = P( T ) ; line spoilage P ( L )

Both P ( T ∩ L ) .

Given

P( T )  = .05

P ( L ) = .08

P ( T ∩ L ) = .03

a )

For independent events

P ( T ∩ L ) =  P( T ) x  P ( L )

But  .03  ≠  .05 x .08

So they are not independent of each other .

b )

i )

Probability of line spoilage given that there is transformer spoilage

P L/ T ) = P ( T ∩ L ) / P( T )

= .03 / .05

= 3 / 5 .

ii )

Probability of transformer spoilage but not line spoilage.

P( T ) - P ( T ∩ L )

.05 - .03

= .02

iii )Probability of transformer spoilage given that there is no line spoilage

[ P( T ) - P ( T ∩ L ) ] / 1 - P ( L )

=  .02 / 1 - .08

= .02  / .92

= 1 / 49.

i v )

Neither transformer spoilage nor there is no line spoilage

= 1 - P ( T ∪ L )

1 - [  P( T ) +  P ( L ) - P ( T ∩ L ]

= 1 - ( .05 + .08 - .03 )

=  0 .9

In the statement "There were 79.6 persons per square mile in the United States in 2008" Descriptive statistics is used. So , the Option A is correct answer.

The statement provides a summary statistic (mean or average) that describes a characteristic of a large set of data (population) without making any inferences about the population based on a sample. Descriptive statistics provide a way to organize, summarize, and describe data by calculating measures such as the mean, median, mode, and range, among others.

Descriptive statistics is a branch of statistics that deals with the collection, organization, analysis, interpretation, and presentation of data. It provides a way to summarize and describe the main features of a set of data, without making inferences about the population based on a sample.

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Answer:

0.40 I'm pretty sure tbh

Answer:

Slope : -1/4

Equation: y = -x + 1/4

Step-by-step explanation:

You start by finding the slope using the slope formula. Then after finding the slope you use one of the pairs to substitute in the equation y = mx+b then after doing that you solve for your b since it will be the only missing variable. Then you have your equation.

Answer:

X=18.0

Step-by-step explanation:

It says round to the nearest tenth, which is 1 digit after the . Even though 18.02 is correct it wants you to round so X= 18.0

Final answer is X=18.0

The value of x is 18.0 rounded to nearest tenth.

Cosine law is a formula relating the length of the sides of a triangle to the cosine of one angle of the triangle.

u² = s² + t² - 2(s)(t)·cos U

We are Given Triangle with sides, 16, 30, and x, and a measure of an angle corresponding to x = 30°

Required: Value of x to the nearest tenth

Using the Cosine rule:

c² = a² + b² - 2abcos(C)

Let c = x, a = 16, b = 30

C = 30°

Thus,

c² = 16² + 30² - 2 x 16 x 30 x cos 30°

c² = 256 + 900 - 960 x 0.8660

c² = 1,156 - 831.36

c² = 324.64

c = √324.64

c = 18.017769

x ≈ 18.0 (rounded to nearest tenth)

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Answer:

see below

Step-by-step explanation:

(1.3) ^ 2= (1.3) (1.3) = 1.69

(1.4) ^ 2= (1.4) (1.4) = 1.96

(1.5) ^ 2= (1.5) (1.5) = 2.25

2 is close to 1.96 so the square root of 2 is close to 1.4

Answer:

A) 10m + 4

Step-by-step explanation:

3(m + 6) + 7(m − 2).

3m + 7m = 10m

18 - 14 = 4

10m + 4

Hope this helps

Answer:

the flight is i think 3 hours and 38 min long

Step-by-step explanation:

Answer:

33.33%

Step-by-step explanation:

We Take

(35 ÷ 105) x 100 ≈ 33.33%

So, 35 is 33.33% of 105

Answer:

v - u = 10t

t = 1/10x(v-u)

2. 1/6 x (m - 19) = n

3. u = d/t - at

4.- 1/6 x (A - P)

T = 2.5

Step-by-step explanation:

v = u + 10t

v- u = 10t

divide both sides of the equation by 10

t = 1/10x(v-u)

2. m = 6n + 19

subtract 19 from both sides of the equation

m - 19 = 6n

divide both sides of the equation by 6

1/6 x (m - 19) = n

3. d = ut + at²

subtract  at² from both sides of the equation

d - at² = ut

divide both sides of the equation by t

(d/t) - at = u

4. P = A - 6D

subtract A from both sides of the equation

P - A = -6D

divide both sides of the equation by -6

-1/6(P - A) = D

Answer:

33:44

Step-by-step explanation:

4*11=44

3*11=33

1 . The following formula can be used to determine the likelihood that a pupil is proficient in arithmetic but not reading:

P(math proficient and not reading proficient) = P(math proficient) - P(math and reading proficient)

We are aware that 65% of kids are fluent in both reading and mathematics, and 78% of children are proficient in arithmetic.

So, the probability that a student is proficient in mathematics but not reading is:

78% - 65% = 13%.

2 . The following formula can be used to determine the likelihood that a pupil is proficient in reading but not mathematics:

P(reading proficient and not math proficient) = P(reading proficient) - P(math and reading proficient)

We are aware that 65% of children are proficient in both reading and mathematics, and 85% of pupils are proficient readers.  So, the probability that a student is proficient in reading but not mathematics is:

85% - 65% = 20%.

3 . The formula P(math and reading proficient) = P(math proficient) + P(reading proficient) - P can be used to determine the likelihood that a student is proficient in both reading and math (math proficient or reading proficient)

We are aware that 78% of pupils demonstrate arithmetic proficiency, 85% demonstrate reading proficiency, and 65% demonstrate reading and math proficiency. Therefore, there is a 65% chance that a student will be proficient in both reading and mathematics.

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The probability that a student is proficient in mathematics but not reading is 13%. The probability that a student is proficient in reading but not mathematics is 20%.There is a 65% chance that a student will be proficient in both reading and mathematics.

1 . The following formula can be used to determine the likelihood that a pupil is proficient in arithmetic but not reading:

P(math proficient and not reading proficient) = P(math proficient) - P(math and reading proficient)

We are aware that 65% of kids are fluent in both reading and mathematics, and 78% of children are proficient in arithmetic.

So, the probability that a student is proficient in mathematics but not reading is:

78% - 65% = 13%.

2 . The following formula can be used to determine the likelihood that a pupil is proficient in reading but not mathematics:

P(reading proficient and not math proficient) = P(reading proficient) - P(math and reading proficient)

We are aware that 65% of children are proficient in both reading and mathematics, and 85% of pupils are proficient readers.  So, the probability that a student is proficient in reading but not mathematics is:

85% - 65% = 20%.

3 . The formula P(math and reading proficient) = P(math proficient) + P(reading proficient) - P can be used to determine the likelihood that a student is proficient in both reading and math (math proficient or reading proficient)

We are aware that 78% of pupils demonstrate arithmetic proficiency, 85% demonstrate reading proficiency, and 65% demonstrate reading and math proficiency. Therefore, there is a 65% chance that a student will be proficient in both reading and mathematics.

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Answer:

(probably) 96

Step-by-step explanation:

2 buildings, 3 floors, 16 windows.

first, 16x3=48

and then 48x2=96

So, the total number is 96.

Answer:

f(x) has a greater slope.

Step-by-step explanation:

The slope of the image line

= difference in y coordinates / difference in x coordinates

= (7-3) / (3-2)

= 4.

The  slope of f(x) = 6x + 1 is  6.

The function f(x) has a greater slope because the slope of the f(x) is 6, and g(x) is 4.

What is mean by straight line?

A straight line is a combination of endless points joined on both sides of the point.

Given that;

The function, f(x) = 6x + 1

And the function g(x) is a linear function which passes through the points (2 , 3) and (3, 7).

Since, The slope 'm' of any straight line is given by:

m = (y₂ - y₁) / (x₂ - x₁)

And, m = d/dx (f(x))

So, The slope of function f (x) will be;

f(x) = 6x + 1

M = d/dx (f(x))

M = d/dx (6x + 1)

M = 6

And, Slope of linear function which passes through the points (2 , 3) and (3, 7) is;

m = (7 - 3) / (3 - 2)

m = 4/1

m = 4

Thus, The function f(x) has a greater slope because the slope of the f(x) is 6, and g(x) is 4.

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Answer:

Step-by-step explanation:

Given z = x+iy

The polar form of a complex number \(z = r(cos\theta + isin\theta)\)

The nth root of the complex number is expressed according to de moivre's  theorem as;

\(z^{\frac{1}{n} } = [r(cos\theta + isin\theta)]^{\frac{1}{n} } \\z^{\frac{1}{n} } = \sqrt[n]{r} (cos(\frac{\theta+2nk}{n} ) + isin(\frac{\theta+2nk}{n}))\)

r is the modulus of the complex  number and \(\theta\) is the argument

r = √x²+y²

\(\theta = tan^{-1} \frac{y}{x}\)

Given z = -9i

r = √0+(-9)²

r = √81

r = 9

\(\theta = tan^{-1}\frac{-9}{0} \\\theta = tan^{-1}-\infty\\\theta = -90^{0}\)

The argument will be equivalent to 180-90 = 90°

The forth root of -9i will be expressed as shown according to de moivre's theorem;

\(z_k^{\frac{1}{4} } = \sqrt[4]{9} (cos(\frac{90+2(4)k}{4} ) + isin(\frac{90+2(4)k}{4}))\\z_k^{\frac{1}{4} } = \sqrt[4]{9} (cos(\frac{90+8k}{4} ) + isin(\frac{90+8k}{4}))\\\)

The complex roots are at when k = 0, 1, 2 and 3

When k = 0;

\(z_0 = \sqrt[4]{9} (cos(\frac{90}{4} ) + isin(\frac{90}{4}))\\z_0 = \sqrt[4]{9} (cos(23) + isin(23))\\\\when\ k =1\\z_1 = \sqrt[4]{9} (cos(\frac{90+8}{4} ) + isin(\frac{90+8}{4}))\\z_1 = \sqrt[4]{9} (cos(25 ) + isin(25))\\\\when\ k =2\\z_2 = \sqrt[4]{9} (cos(\frac{90+16}{4} ) + isin(\frac{90+16}{4}))\\z_2 = \sqrt[4]{9} (cos(27 ) + isin(27))\\\\when\ k =3\\z_3 = \sqrt[4]{9} (cos(\frac{90+24}{4} ) + isin(\frac{90+24}{4}))\\z_3 = \sqrt[4]{9} (cos(29 ) + isin(29))\\\)

Note that all the degrees are rounded to the nearest whole number.

The rate of change of the function h(x) = 2x on the interval 2 ≤ x ≤ 4 is 6.

Answer:

A

Step-by-step explanation:

\(f(x) = (x + 2)^2(x-4)(x + 1)^3\)

x+2=0

x+2-2=0-2

x=-2.....(x+2) was squared...exponent of 2...multiplicity of 2

x-4=0

x-4+4=0+4

x=4....(x-4) has no visible exponent which means it is essentially to the power of 1...multiplicity of 1

x+1=0

x+1-1=0-1

x=-1....(x+1) was cubed...exponent was 3...multiplicity of 3

The roots and their respective multiplicity are –2 with multiplicity 2, 4 with multiplicity 1, and –1 with multiplicity 3 thus option (A) is correct.

The roots of an equation are the solution of that equation, since an equation consists of hidden values of the variable so to determine them by different processes and then the resultant is called roots.

For example root of x -4 = 0 is x = 4 so 4 will be the only root of this linear equation.

As per the given function,

f(x) = (x + 2)²(x - 4)(x + 1)³

The roots are the points at which the value of the function is zero.

f(x) = 0

(x + 2)²(x - 4)(x + 1)³ = 0

(x + 2)² = 0

x = -2 (with a multiplicity of 2)

(x - 4) = 0

x = 4  (with a multiplicity of 1)

(x + 1)³ = 0

x = -1  (with a multiplicity of 3)

Hence "The roots and their respective multiplicity are –2 with multiplicity 2, 4 with multiplicity 1, and –1 with multiplicity 3 thus option (A) is correct".

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Answer:

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 5x -10 + y\²\)

Step-by-step explanation:

Given

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y)\)

Required

Simplify

We have:

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y)\)

Open brackets

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 2x\²+xy+5x - 2x\²-2xy-10 + xy + y\²\)

Collect like terms

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 2x\²- 2x\²+xy-2xy+ xy+5x -10 + y\²\)

\(x(2x+y+5) - 2(x\²+xy+5) + y(x + y) = 5x -10 + y\²\)