an 87-g arrow is fired from a bow whose string exerts an average force of 100 n on the arrow over a distance of 78 cm

Answer:

The answers are B and D.

Explanation:

This is because neutralisation process that contain sodium, potassium and ammonium will produce salt and water.

Answer:

A

Explanation:

Horner-Wadsworth-Emmons (HWE) reaction is an important synthetic reaction in organic chemistry. It is widely used for synthesizing various compounds. The reaction is between an aldehyde or ketone and a phosphonate or phosphonate ester in the presence of a strong base.

The Horner-Wadsworth-Emmons reaction is one of the most convenient and well-known methods of constructing carbon-carbon double bonds. The reaction proceeds via the formation of an ylide intermediate. The HWE reaction is particularly useful for the synthesis of compounds with a Z-configuration.

The mechanism for the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, can be explained in the following steps:

Step 1: Formation of the ylide intermediate

The reaction starts with the formation of an ylide intermediate. This is achieved by the reaction of diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of a strong base like NaOH or KOH. In this reaction, a deprotonated species called an ylide intermediate is generated.

Step 2: Addition of the ylide intermediate to the aldehyde

The ylide intermediate then attacks the aldehyde, leading to the formation of a betaine intermediate.

Step 3: Formation of the phosphonate ester

The betaine intermediate undergoes elimination to form the final product, 3,4-methylenedioxystilbene, and the by-product phosphonate ester.

The mechanism of the Horner-Wadsworth-Emmons (HWE) reaction between diethyl benzylphosphonate and 3,4-methylenedioxybenzaldehyde in the presence of aqueous NaOH, forming 3,4-methylenedioxystilbene as the product, is complete. This reaction is significant in organic chemistry and finds applications in the pharmaceutical industry.

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It can be said that June in Dodge City, Kansas, is most like late spring or early summer in Melbourne, Australia.

It is vital to take into account the climatic distinctions and seasonal variations between two areas in order to compare the weather between them. The climates of Dodge City, Kansas and Melbourne, Australia are very different, making a direct comparison difficult. We can, however, estimate broadly.

A continental climate characterizes Dodge City, Kansas, with scorching summers and chilly winters. With average high temperatures ranging from 29°C (85°F) to 33°C (92°F), June is typically summer in Dodge City.

Melbourne, Australia, experiences cold winters and warm summers due to its moderate oceanic climate. Melbourne experiences winter in June, with daily highs often hovering around 14°C (57°F).

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\([Hello,BrainlyUser]\)

Answer/Explanation:

well, you might have or you have possibly heard the advice to drinking 8 glasses of water a day. Often people, especially those who exercise in hot weather, are more worrying about not drinking enough water.

So are some below;

Exercise: If you do any activity that makes you sweat, you need to drink extra water to cover the fluid loss. It's important to drink water before, during and after a workout.

Environment : Weather like hot weather can make you sweat and requires additional fluid. Dehydration also can occur at high altitudes.

Overall health: Your body loses fluids when you have a fever, vomiting or diarrhea. Drink more water or follow a doctor's recommendation to drink oral rehydration solutions. Other conditions that might require increased fluid intake include bladder infections and urinary tract stones.

Pregnancy and breast-feeding: If you are pregnant or breast-feeding, you may need additional fluids to stay hydrated.

How do I know if you are drinking enough?

To prevent dehydration and make sure your body has the fluids it needs, make water your beverage of choice. It's a good idea to drink a glass of water:

[CloudBreeze]

3 moles of electrons are transferred and the total charge per mole of Cr(s) produced is 2.894 × 10^5 C during the electrolysis of aqueous Cr2(SO4)3.

To determine the number of electrons transferred and the total charge per mole of Cr(s) produced during the electrolysis of aqueous Cr2(SO4)3, follow these steps:

1. Identify the half-reaction: Cr3+ + 3e- → Cr(s).

2. Determine the moles of electrons transferred: 3 moles of electrons are required for each mole of Cr3+ ions to form 1 mole of Cr(s).

3. Calculate the total charge: Multiply the moles of electrons by the elementary charge (1.602 × 10^-19 C). For 1 mole of electrons, the charge is 1 mol × (1.602 × 10^-19 C/mol) = 9.648 × 10^4 C.

4. Multiply the charge by the number of moles of electrons: 3 moles of electrons × 9.648 × 10^4 C/mol = 2.894 × 10^5 C.

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The correct answer is a.) Emulsion.

When two or more immiscible substances are combined with a special binding ingredient, they form an emulsion. This is a type of mixture in which one liquid is dispersed throughout another liquid in small droplets, creating a homogeneous and stable mixture. Examples of emulsions include mayonnaise, milk, and salad dressing. The special binding ingredient in emulsions is often a surfactant, which helps to stabilize the mixture and prevent the droplets from separating over time.

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Answer: a) The pH of the MES buffer prepared using 0.3616 g NaOH is 6.5. b) 0.3616 g NaOH is required to be added to the MES solution to make a buffer at pH 6.5

pH of 1 liter of a 200 mM MES aqueous solution can be obtained as follows: Let x be the quantity of NaOH in grams needed to be added to the MES solution to create a buffer at pH 6.5.The volume of the solution (assuming a density of 1 g/mL) can be determined as follows :

To prepare 1 L of the buffer, the total quantity of NaOH required will be:The final concentration of MES in the buffer can be calculated as follows:To calculate the pH of the buffer, we can make use of the Henderson-Hasselbalch equation. Hence, the pH of the MES buffer prepared using 0.3616 g NaOH is 6.5.

The mass of NaOH that needs to be added to prepare the MES buffer at pH 6.5 can be calculated as follows:To prepare a buffer with a pH of 6.5, 0.3616 g NaOH is required.

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My hypothesis regarding the change in urine volume was that subjects who drank water would have a higher urine volume compared to those who drank a sports drink. This is because water is a pure hydrating agent that does not contain any added sugars or electrolytes, unlike sports drinks.

Electrolytes in sports drinks cause the body to retain more water and decrease urine output, while added sugars increase urine output. Therefore, the physiologic basis for my prediction is that drinking water would lead to more frequent urination and higher urine volume due to the absence of any added electrolytes and sugars.

In terms of the results, they supported my prediction as the subjects who drank water had a significantly higher urine volume compared to those who drank a sports drink. However, there were a few subjects who had unexpected results where they had a higher urine volume after drinking a sports drink. This could be due to individual variations in their physiology, hydration status, or even their fluid intake before the study. Therefore, it is important to take into account individual variations when interpreting the results.

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Answer:

urine

Explanation:

urine tastes good :oP

Answer:

maybe the third option?

The automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeRearranging the equation gives; Mass= Density × VolumeSubstitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galWe know that; 1 L = 1 dm³Thus,Mass = 0.737 g/mL × 19.0 gal × 3.78541 dm³/LMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeThe above equation can be rearranged as; Mass= Density × Volume Substitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

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Based on the data provided, the electric circuit is completed when the key is closed.

An electric circuit is a complete path through which electric current flows

An electric circuit can either be:

An electric circuit consists of :

Therefore, an electric circuit is completed when all the components are connected and the key closed.

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Answer:

Explanation: HAVE A GREAT DAY EVERYONE <3

Answer:

Rate cup 1: 36.00 tsp/h.

Rate cup 2: 59.50 tsp/h.

Rate cup 3: 70.13 tsp/h.

Explanation:

Based on the given example, the units must be in tsp/hour. To do this we just have to divide tsp by seconds and then convert it to hours remembering that 1 hour equals 3600 seconds.

Let's calculate each case:

- Cup 1: 1 tsp, 1 minute 40 seconds. Remember that 1 minute equals 60 seconds, so 1 minute and 40 seconds equals 100 seconds. The calculation of the rate will look like this:

The rate of cup 1 is 36.00 tsp/h.

- Cup 2: 2 tsp, 2 minutes 1 second. As we saw before 1 minute equals 60 seconds, so 2 minutes equals 120 seconds. 2 minutes and 1 second equals 121 seconds. The rate of cup 2 will be calculated as:

The rate of cup 2 is 59.50 tsp/h.

- Cup 3: 3 tsp, 2 minutes 34 seconds. 2 minutes are the same that 120 seconds, so 2 minutes 34 seconds equals 154 seconds. The rate of cup 3 is calculated as follows:

The rate of cup 3 is 70.13 tsp/h.

In order to answer the question first we must write the atomic number of each element:

Zirconium (Zr): 40

Cadmium (Cd): 48

Iridium (Ir): 77

Iron (Fe): 26

Then, we have to complete the distribution of electrons in each orbital for each atom:

The first 4 levels have the following distribution:

Level1: 1s

Number of electrones: 2

Level 2: 2s, 2p

Number of electrones 8 (2 in the s orbital and 6 in the p orbitals).

Level3: 3s, 3p, 3d

Number of electrones 18 (2 in the s orbital, 6 in the p orbital and 10 in the d orbitals)

Level 4: 4s, 4p, 4d, 4f

Number of electrones 32 (2 in the s orbital, 6 in the p orbitals, 10 in the d orbitals and 14 in the f orbitals)

The order in which the orbitlas are completed depends on the energy of each level. For example the 4s orbitals will be completed before the 3d orbitals because their energy is lower.

The order is as follows:

1s, 2s, 2p, 3s, 3p, 4s, 3d, 4p, 5s, 4d, 5p...

Now, knowing the atomic number we can answer the question:

For Zirconium (total 40 electrones):

2 electrones are predicted in the 4d orbital

For Cadmium (total 48 electrones):

10 electrones are predicted in the 4d orbital

For iridium, as it has an atomic number higher than Cadmium we can predict tha it also complets the 4d orbital, then it has also 10 electrones in it.

For iron (total 26 electrones)

Iron has no electrones in the 4d orbitals

The reaction you provided, C2H6(g) → C2H2(g) + 2H2(g), involves the decomposition of ethane (C2H6) into acetylene (C2H2) and hydrogen gas (H2).

To calculate ΔH for this reaction using Hess's Law, we need to consider a series of reactions for which the enthalpy changes (ΔH) are known.

First, we can consider the combustion of ethane, which is an exothermic reaction:

C2H6(g) + 7/2O2(g) → 2CO2(g) + 3H2O(g) ΔH1

Next, we can consider the combustion of acetylene, which is also exothermic:

C2H2(g) + 5/2O2(g) → 2CO2(g) + H2O(g) ΔH2

Lastly, we can consider the combustion of hydrogen gas, which is exothermic as well:

H2(g) + 1/2O2(g) → H2O(g) ΔH3

To obtain the target reaction, we can subtract the known reactions in such a way that the reactants on one side cancel out with the products on the other side. In this case, we need to reverse the second reaction and multiply the third reaction by 2:

2CO2(g) + H2O(g) → C2H2(g) + 5/2O2(g) -ΔH2

2H2O(g) → 2H2(g) + O2(g) 2ΔH3

By adding these reactions together, the intermediate products and reactants cancel out, leaving us with the desired reaction:

C2H6(g) → C2H2(g) + 2H2(g)

The enthalpy change for the desired reaction, ΔH, is the sum of the enthalpy changes for the individual reactions. Therefore:

ΔH = ΔH1 + (-ΔH2) + 2ΔH3

By substituting the known values of ΔH1, ΔH2, and ΔH3, you can calculate the value of ΔH for the reaction using Hess's Law.

In summary, Hess's Law allows us to calculate the enthalpy change for a desired reaction by manipulating known reactions with known enthalpy changes.

By canceling out intermediate products and reactants, we can arrive at the desired reaction and determine its enthalpy change.

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The pillar of sustainability broken by recycling electronics in India is environmental sustainability. Implementing a law that restricts electronics recycling to the US would not necessarily be the most effective solution, as it overlooks the complex global dynamics of electronic waste management.

Recycling electronics in India often involves improper disposal methods, such as burning or dismantling without proper safety measures. This leads to environmental pollution, including the release of hazardous substances into the air, soil, and water, thus violating the principle of environmental sustainability.

However, simply mandating that electronics can only be recycled in the US may not be the most optimal solution. Electronic waste is a global issue, and restricting recycling to a single country disregards the fact that electronic products are manufactured and consumed worldwide. A more comprehensive approach to addressing electronic waste would involve international cooperation, strict regulations, and monitoring of recycling practices to ensure they meet environmental standards.

Efforts should focus on improving recycling practices globally, including promoting responsible electronic waste management, developing sustainable recycling infrastructure in multiple countries, and encouraging the adoption of safe and environmentally friendly recycling practices. This approach would foster global sustainability and address the challenges associated with electronic waste disposal more effectively than a geographically limited restriction.

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A pi bond is the result of the d) sideways overlap of two parallel p orbitals.

Pi bonds are bonds that occur as a result of overlapping orbitals of atoms that are not in the bond axis. Each p orbital that contributes to a pi bond has two lobes and has a node at the core.

The pi orbital can hold a maximum of two pairs of electrons. Whereas each electron in a pi bond is also called a pi electron, the pi electrons are used for double bonds or triple bonds. The 2p orbital of carbon has slightly higher energy than the sp2 orbital, so the pi bond formed from two 2p orbitals has somewhat higher energy and is slightly less stable than the sp2-sp2 sigma bond.

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Answer:

B

Explanation:

first find the no. Of moles of H2SO4

=  75/98.1

= 0.7645

Next step

In on mole of H2SO4 the no.of oxygen atom is 4.

1 H2SO4 : 4 O

0.7645  : x                     x= 0.7645x4= 3.0581

next multiply avogadros constant

3.0581 x 6.022× 10^23 =1.84x10^24

Mass present in 1 gram of mole substance is called molar mass. Molar mass is calculated by: dividing the mass of the compound in grams by the number of moles present in the substances.

The correct answer is:

option B. 1.84 × 10²⁴

Given,

1.The moles of sulfuric acid can be calculated by

M = m ÷ n

where M is molar mass, m is mass and n moles.

moles of sulfuric acid = mass ÷ molar mass

= 75 g ÷ 98.1 g/mol  

=0.7645 moles

Hence moles of sulfuric acid present is 0.7645 moles.

2. 1 mole of sulfuric acid = 4 oxygen atoms.

Then, 0.7645 moles of sulfuric will contain: 0.7645 × 4 = 3.0581 atoms of oxygen

3. Oxygen atoms present in 75.0 g of H₂SO₄ will be calculated by multiplying it with Avogadro's constant:

= 3.0581 x 6.022× 10²³

= 1.84x10²⁴

Therefore, 1.84 × 10²⁴ oxygen atoms will be found in 75.0 g of H₂SO₄.

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Answer :

a series of experiments carried out towards the end of the 19th century and early 20th century led to the discovery of the fundamental sub particles of the atom :

The Proton has a positive charge and a relative mass of 1 ( using carbon 12 as standard).

The neutron has no charge but has a relative mass of 1.

In fact is characteristic of the neutron is a some of that of the Proton and the electron.

Atomic number represent the number of protons in the nucleus of an atom.

the mass number of an atom of an element is the sum of the protons and neutrons in it.

The student obtained an optically active product after exposing r-1-bromo-2-propanol to sodium hydroxide. The proton NMR of the product is also provided.

The structure of the compound that the student isolated is:CH3 – CH (OH) – CH2 – Br

In the given compound r-1-bromo-2-propanol, the bromine atom is attached to the first carbon atom. When this compound is treated with sodium hydroxide, the hydroxide ion attacks the carbon atom attached to the bromine atom and forms a negatively charged oxygen atom.This negatively charged oxygen atom further attracts the proton of the adjacent carbon atom (second carbon atom). After the transfer of a proton, the negatively charged oxygen atom gets neutralized and an alkoxide ion is formed. This alkoxide ion further attacks the third carbon atom and the compound is formed.In the compound obtained, there is no plane of symmetry or center of symmetry. This makes the compound optically active.

Further, the proton NMR shows the presence of a singlet at chemical shift 1.1 ppm due to the presence of three equivalent methyl groups. The presence of a broad singlet at chemical shift 3.7 ppm is due to the presence of –OH group. The singlet at chemical shift 4.2 ppm is due to the presence of –CH2 group.The structure of the compound that the student isolated is CH3 – CH (OH) – CH2 – Br.

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Williamson ether synthesis would give a poor yield of product as the halide is on a 2° carbon. is true about the synthesis of 1-isopropoxy-1-methylcyclopentane.

The Williamson ether synthesis is a method for the synthesis of ethers using an alcohol and an alkyl halide. The reaction proceeds through a nucleophilic substitution mechanism and the ether product is obtained with the alcohol and halide groups in the anti-Markovnikov orientation. The reactivity of the alkyl halides used in this reaction follows the order: primary > secondary >> tertiary. Therefore, the reaction of a secondary halide such as 2° carbon halide will give a poor yield of product as the reactivity of 2° carbon halide is less compared to primary halide. As a result, the reaction is less efficient and the yield of the product is lower.

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Answer:

I'm sorry, but I don't see an equation in your question to provide a specific answer. However, I can answer your general question.

Nitrogen has one more proton than Carbon because it has one more positively charged particle (proton) in its nucleus. This difference in the number of protons determines the atomic number and identity of the element.

Protons can only come from the nucleus of another atom, through a nuclear reaction. In nature, nitrogen is usually created by nuclear fusion in stars, where lighter elements combine under high pressure and temperature to form heavier elements.

Regarding the second part of your question, without the specific equation you are referring to, I cannot determine the type of reaction depicted. There are many types of chemical reactions, including synthesis, decomposition, combustion, acid-base, and redox reactions, among others.

Answer: The answer is the Pharynx I believe

Explanation: please correct me if I’m wrong

Answer:

"Protons only"

Explanation:

Hydrogen has one proton in its nucleus. It does have one electron rotating outside of the nucleus, BUT NOT IN THE NUCLEUS. 'A' is the correct answer.

After 72 days, a 1050 mg sample of Iodine-131 would have decayed to approximately 46.87 mg.

A half-life is the time it takes for half of a sample of a radioactive isotope to decay. It is a characteristic property of each isotope and can be used to predict how long it will take for a given sample to decay to a certain amount. The amount of an isotope remaining after a certain amount of time can be calculated using the half-life and the formula N = N0 * (1/2)^(t/T).

Iodine-131 is used in medical treatments because it emits beta particles that can destroy cancerous cells. Its short half-life is an advantage because it allows for a higher dose of radiation to be delivered to the tumor while minimizing the amount of radiation exposure to healthy tissues. After a few weeks, the Iodine-131 decays to a negligible amount and the patient is no longer radioactive.

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Answer:

1.48×10²⁴ Cu atoms

Explanation:

For this question you need to use Avogadro's number 6.022×10²³atoms.

2.45 moles of Cu ×\(\frac{6.022x10x^{23} atoms }{1 mole}\)= 1.47539×10²⁴ atoms.

The moles cancel out so you are left with atoms.

Since there are 3 significant figures in the question there should be 3 significant figures in your answer, which is 1.48×10²⁴ Cu atoms.

Chemical substances known as oxygenates have oxygen as one of their constituent parts. Tech B is correct

Although technically any substance containing oxygen qualifies as an oxygenate, the term is most frequently used to refer to substances added to internal combustion engine vehicles.

Oxygenate fuel additives are either alcohols, like ethanol, or ethers, with methyl tertiary butyl ether, or MTBE, being the most often used. Any chemical compound that has at least one hydroxyl group, which is made up of oxygen and hydrogen and is connected to the carbon atom in an alkyl group, is referred to as alcohol. Alkyl groups are made up of hydrogen and carbon atom chains.

Alcohols are a crucial group in organic chemistry despite their lack of chemical specificity because of how many different compounds they can originate from and be transformed into.

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Answer:

1300cm3.

Explanation:

Step 1:

Data obtained from the question.

Initial temperature (T1) = K

Initial volume (V1) = 650 cm3

Final temperature (T2) = double the original = 2K

Final volume (V2) =..?

Step 2:

Determination of the new volume of the gas.

The new volume of the gas can be obtained by using Charles' law as follow:

V1/T1 = V2/T2

650/K = V2/2K

Cross multiply

K x V2 = 650 x 2K

Divide both side by K

V2 = 650 x 2K /K

V2 = 650 x 2

V2 = 1300cm3.

Therefore, the new volume of the gas is 1300cm3

The new volume of the gas is 1300cm³.

Given:

Initial temperature (T₁) = K

Initial volume (V₁) = 650 cm3

Final temperature (T₂) = double the original = 2K

To find:

Final volume (V₂) =?

Determination of new volume:

V₁/T₁ = V₂/T₂

650/K = V₂/2K

K x V₂ = 650 x 2K

V₂ = 650 x 2K /K

V₂ = 650 x 2

V₂ = 1300cm³

Therefore, the new volume of the gas is 1300cm³.

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