The probability that a male passenger can fit through the doorway without bending is 0.9983.
To solve this problem, we need to find the probability that a randomly selected male passenger has a height less than or equal to 78 inches. We can use the standard normal distribution to do this by standardizing the height:
z = (78 - 69) / 2.8 = 3.214
Using the standard normal distribution table or calculator, we can find that the probability of a z-score less than or equal to 3.214 is approximately 0.9992.
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Help me solve this ASAP please
Answer:
3
Step-by-step explanation:
Remember BEDMAS!!
Brackets first:
(15) / (1+(2)^2)
Exponents next:
(15) / (1+4)
15 / 5 = 3
Hope that helps, feel free to ask questions
The answer is 3 use BODMAS, BEDMAS or PEDMAS
Find the 63rd term. 5, 8, 11, 14...
Answer:
191
Step-by-step explanation:
An = a1 + (n-1)d
An = 5 + (63-1)3 = 191
Answer:
191
Step-by-step explanation:
Since it's an A.P, the formular = a+(n-1)d
a = first term = 5
n = 63
d = common difference
After, putting the values, you'll have that:
T63= 5+(63-1)3
T63= 5+(62)3
T63= 5+ 186
T63= 191
EASY MULTIPLE CHOICE. PLEASE HELP!!!!!
Answer:
6xsquared - 2x - 1
Step-by-step explanation:
A project has five activities with the durations (days) listed
below:
Activity
Precedes
Expected
Duration
Variance
Start
A, B
-
-
A
C
40
0.31
B
E
32
0.25
C
D
21
0.35
The critical path is the path with the longest duration, which in this case is A -> B -> D -> E with a duration of 11 days.
To determine the critical path of the project, we need to find the longest path of activities that must be completed in order to finish the project on time. This is done by calculating the earliest start time (ES) and earliest finish time (EF) for each activity.
Starting with activity A, ES = 0 and EF = 4. Activity B can start immediately after A is complete, so ES = 4 and EF = 7. Activity C can start after A is complete, so ES = 4 and EF = 6. Activity D can start after B is complete, so ES = 7 and EF = 9. Finally, activity E can start after C and D are complete, so ES = 9 and EF = 11.
The variance for each activity is also given, which allows us to calculate the standard deviation and determine the probability of completing the project on time. The critical path is the path with the longest duration, which in this case is A -> B -> D -> E with a duration of 11 days.
Using the expected durations and variances, we can calculate the standard deviation of the critical path. This information can be used to determine the probability of completing the project on time.
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Under certain conditions, the number of diseased cells N(t) at time t increases at a rate N'(t) = Ae^kt, where A is the rate of increase at time 0 (in cells per day) and k is a constant.
a. Suppose A = 40, and at 5 days, the cells are growing at a rate of 120 per day. Find a formula for the number of cells after t days, given that 200 cells are present at t = 0.
b. Use your answer from part a to find the number of cells present after 11 days.
The formula for the number of cells after t days, given that 200 cells are present at t = 0 is \(N(t) = 40(3^t - 1) + 200\;ln(3)\), whereas the number of cells present after 11 days is approximately 7,085,864.
The given differential equation \(N'(t) = Ae^{kt}\) describes the rate of increase in the number of diseased cells N(t) at time t, where A is the rate of increase at time 0 and k is a constant. The solution to this differential equation is \(N(t) = (A/k) \times e^{kt} + C,\) where C is an arbitrary constant that can be determined from an initial condition.
a. Using the given information, A = 40 and N'(5) = 120. Substituting these values into the equation \(N'(t) = Ae^{kt}\), we get:
\(120 = 40e^{(5k)}\)
Solving for k, we have:
k = ln(3)
Substituting A = 40 and k = ln(3) into the equation for N(t), and using the initial condition N(0) = 200, we get:
\(N(t) = (40/ln(3)) \times e^{(ln(3)t)} + 200\)
Simplifying this expression, we obtain:
\(N(t) = 40(3^t - 1) + 200ln(3)\)
b. To find the number of cells present after 11 days, we substitute t = 11 into the expression for N(t) that we obtained in part a:
\(N(11) = 40(3^{11} - 1) + 200ln(3)\)
Simplifying this expression, we get:
\(N(11) = 40(177146) + 200ln(3) \approx 7,085,864\)
Therefore, the number of cells present after 11 days is approximately 7,085,864.
In summary, the given differential equation \(N'(t) = Ae^{kt}\) describes the rate of increase in the number of diseased cells N(t) at time t, and the solution to this equation is \(N(t) = (A/k) \times e^{kt} + C,\) where C is an arbitrary constant that can be determined from an initial condition.
We used this equation to find a formula for the number of cells after t days, given A, k, and an initial condition, and used it to find the number of cells present after 11 days.
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need answers to this!!
Answer:
Yes, it's a function!
Step-by-step explanation:
(The domain represents the x-intercept and the range represents the y-intercept)
You can tell this mapping diagram is a function because each x-intercept (input) has only one y-intercept (output.)
Solve each equation. 4 y-6=2 y+8
The solution of the linear equation in one variable 4y - 6 = 2y + 8 is at y = 7.
According to the given question.
We have a linear equation in one variable.
4y - 6 = 2y + 8
As we know that, the linear equations in one variable is an equation which is expressed in the form of ax+b = 0, where a and b are two integers, and x is a variable and has only one solution.
Thereofre, the solution of the linear equation in one variable 4y - 6 = 2y + 8 is given by
4y - 6 = 2y + 8
⇒ 4y - 2y - 6 = 8 ( subtracting 2y from both the sides)
⇒ 2y -6 -8 = 0 (subtracting 8 from both the sides)
⇒ 2y - 14 = 0
⇒ 2y = 14
⇒ y = 14/2
⇒ y = 7
Hence, the solution of the linear equation in one variable 4y - 6 = 2y + 8 is at y = 7.
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Given that ‘z’ is in set of complex number and ‘a’ is any real numbers. Solve the trigonometric equation sin(z) = a for all general solutions.
Recall that for all \(z\in\Bbb C\),
\(\sin(z) = \dfrac{e^{iz} - e^{-iz}}{2i}\)
so that
\(\sin(z) = a \iff e^{iz} - e^{-iz} = 2ia\)
Multiply both sides by \(e^{iz}\) to get a quadratic equation,
\(e^{2iz} - 2iae^{iz} - 1 = 0\)
Solve for \(e^{iz}\). By completing the square,
\(e^{2iz} - 2ia e^{iz} + i^2a^2 = 1 + i^2a^2\)
\(\left(e^{iz} - ia\right)^2 = 1 - a^2\)
\(e^{iz} - ia = \pm \sqrt{1-a^2}\)
\(e^{iz} = ia \pm \sqrt{1-a^2}\)
\(iz = \log\left(ia \pm \sqrt{1-a^2}\right)\)
\(iz = \ln\left|ia \pm \sqrt{1-a^2}\right| + i \left(\arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n\right)\)
\(\boxed{z = -i \ln\left|ia \pm \sqrt{1-a^2}\right| + \arg\left(ia \pm \sqrt{1-a^2}\right) + 2\pi n}\)
where n is any integer.
We are given with:
\({\quad \qquad \longrightarrow \sin (z)={\sf a}\:,\:z\in \mathbb{C}}\)
Recall the identity what we have for the sine function of complex numbers
\({\boxed{\bf{\sin (z)=\dfrac{e^{\iota z}-e^{-\iota z}}{2\iota}}}}\)Put the values to thus obtain:
\({:\implies \quad \sf \dfrac{e^{\iota z}-e^{-\iota z}}{2\iota}=a}\)
\({:\implies \quad \sf e^{\iota z}-e^{-\iota z}=2a\iota}\)
Multiply both sides by \({\sf e^{\iota z}}\)
\({:\implies \quad \sf e^{\iota z}\cdot e^{\iota z}-e^{-\iota z}\cdot e^{\iota z}=2a\iota e^{\iota z}}\)
\({:\implies \quad \sf (e^{\iota z})^{2}-2a\iota e^{\iota z}-1=0}\)
Put x = \({\sf e^{\iota z}}\):
\({:\implies \quad \sf x^{2}-2a\iota x-1=0}\)
Find the discriminant, here D will be, D = (-2ai)² - 4 × 1 × (-1) = 4 - 4a² = 4(1-a²)
Now, By quadratic formula:
\({:\implies \quad \sf x=\dfrac{-(-2a\iota)\pm \sqrt{4(1-a^{2})}}{2}}\)
\({:\implies \quad \sf x=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}\)
\({:\implies \quad \sf e^{\iota z}=\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}}\)
\({:\implies \quad \sf \iota z=log\bigg(\dfrac{a\iota \pm \sqrt{1-a^{2}}}{2}\bigg)}\)
Using the formula for logarithms, we have:
\({:\implies \quad \sf \iota z=log(a\iota \pm \sqrt{1-a^{2}})-log(2)}\)
\({:\implies \quad \sf z=\dfrac{1}{\iota}log(a\iota \pm \sqrt{1-a^{2}})-\dfrac{1}{\iota}log(2)}\)
The sine function is periodic on 2πn and zero on (π/2), and the logarithmic expression becomes undefined for all ia±√(1-a²) < 0, so we will take modulus of it
\({:\implies \quad \boxed{\bf{z=\dfrac{1}{\iota}log\bigg|a\iota \pm \sqrt{1-a^{2}}\bigg|-\dfrac{1}{\iota}log(2)+\dfrac{\pi}{2}+2\pi n\:\:\forall \:n\in \mathbb{Z}}}}\)
Please help me to complete this questions.
Answer:
1. Because school is important and someone at school can help you.
2. because they are less likely to to attack in-font of a group.
Answer:
1. I think we shouldn't skip school even tho we are getting bullied because we can be greater in life if we keep going and working hard and just letting people hate
2. I don't think that if we surround ourselves with friends we won't get bullied because know for a fact that people will talk, and talk so even if i do have a lot of friends it won't really matter because people will still take stuff out on you
hope this helped
Find the area of the shape shown below.
9
3
3
units?
Answer:
81
Step-by-step explanation:
9 x 3 x 3 is 81
Answer:
18
Step-by-step explanation:
Area=3x3=9 units
9+9=18
The line of symmetry is involved in which transformation?TranslationRotationReflectionMigration
Given:
The line symmetry.
Aim:
We need to find the transformation that line symmetry involved.
Explanation:
Recall that line symmetry is the line in the middle acts as a mirror.
the figure flips to make a mirror image of itself in reflection.
Hence the line of symmetry is involved reflection transformation.
Final answer:
The line of symmetry is involved in reflection transformation.
mustafa is putting a sidewalk using two diffrent style bricks, one style brick is 8 inches long, and the other style brick is 6 inches long ,and he intends to use y of these. his sidewalk is to be 288 inches long write down an equation to represent the situation
Answer:
8y+6y=288
Step-by-step explanation:
8y+6y= 12y
12y=288
12y divide by 12 = 288 divided by 12 =
y=24
A regular hexagon is inscribed in a circle of radius 1 inch. what is the area of the shaded region?
Answer:
176.1
units
2
Explanation:
A
shaded
=
A
circle
−
A
hexagon
A
circle
=
π
r
2
=
π
⋅
18
2
=
324
π
We can split up the hexagon into 6 regular triangles.
A
hexagon
=
6
⋅
A
triangle
=
6
⋅
1
2
b
h
Since the triangles are regular, the base is equal to the radius,
18
. We can represent the height by taking one of the triangles and drawing a line down the middle. The newly formed triangle is a
30
°
−
60
°
−
90° right triangle.
The lengths of the three sides of a triangle are x +3,2x, and 5x - 35. What is the value of x if the perimeter of the triangle is 112?
A.17
B.18
C.12
D.14
E.26
Ashley had 4/ 5 of a spool of yarn. She used 2/5 of it for her project. What fraction of the spool was used for her project? Write your answer in simplest form
Ashley used 8/25 of the spool for her project.
To determine the fraction of the spool that Ashley used for her project, we need to multiply the fraction of the spool she had (4/5) by the fraction she used (2/5):
(4/5) * (2/5) = 8/25
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Write x > 6 in interval notation.
Answer:
x > 6 in interval notation is: (6, ∞)
NOTE:
Interval notation is a way to represent an interval as a set of numbers. The numbers are the endpoints of the interval.
-----
Build the interval notation for x:
Since you did not enter an equal sign, this translates to ( since we will not be including the number 6
Based on the > you entered, the right side of the interval notation will extend to positive infinity, which is denoted as +∞
(6,+∞)----- (answer)
Set Builder Notation for x:
{ x | x>6 } where | denotes such that
Display the literal representation for x
7,8,9,10,11,12,13,14,15,16,...,∞
Danny has at least $15 more than his big brother. Danny's brother has 72. How much money does Danny have?
Answer:
at least 87
\( \geqslant 87\)
Step-by-step explanation:
danny has at least $15 more than his brother and his brother has $72 that means Danny has at least 15 + 72(his brothers money) it can be 87 or more than 87
Danny's money is
\( \geqslant 87\)
perfect square number less than 10
Answer:
2
Step-by-step explanation:
if that is not it please let me know i like feedback
The Powerball lottery works as follows
A. There is a bowl of 69 white balls. Five are randomly chosen without replacement. For purpose of being the winner , order does not count.
B. A second bowl contains 29 red balls. One red ball is chosen randomly. That red ball is called the power ball .
C. The winner of the grand prize will chosen correctly all five of the white balls and the one correct red ball .
ale correct red ball.
Use the factional (I) bused formula to find the likelihood of being the winner of the Powerball lottery
The probability of choosing all five white balls correctly from a bowl of 69 white balls and the probability of choosing the correct red ball from a bowl of 29 red balls is \({}^{69}C_5/29\) .
The probability of choosing all five white balls correctly can be calculated using the formula for combinations, where the order does not matter and the balls are chosen without replacement. The probability is given by:
P(Choosing all 5 white balls correctly) = (Number of ways to choose 5 white balls correctly) / (Total number of possible combinations)
The number of ways to choose 5 white balls correctly is 1, as there is only one correct combination.
The total number of possible combinations can be calculated using the formula for combinations, where we choose 5 balls out of 69. It is given by:
Total number of combinations = \({}^{69}C_5\)
Next, we need to calculate the probability of choosing the correct red ball from a bowl of 29 red balls. Since there is only one correct red ball, the probability is 1/29.
Finally, to find the likelihood of being the winner of the Powerball lottery, we multiply the probability of choosing all five white balls correctly by the probability of choosing the correct red ball:
Likelihood = P(Choosing all 5 white balls correctly) * P(Choosing correct red ball)
=\({}^{69}C_5 \times 1/29\\\)
This gives us the probability of being the winner of the Powerball lottery.
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if x=13 what is 5x - 2 =
Answer:
63
Step-by-step explanation:
5(13)-2 is 65-2 or 63.
There are 10 students in a class: 6 boys and 4 girls.
If the teacher picks a group of 3 at random, what is the probability that everyone in the group is a boy?
Answer:
1/ 6
Step-by-step explanation:
Therefore, the required probability is 1/6.
Answer:
1/6
Step-by-step explanation:
Think of drawing 1 student at a time without replacement.
First drawing:
p(boy) = 6/10
Second drawing:
p(boy) = 5/9
Third drawing:
p(boy) = 4/8
p(3 boys) = 6/10 * 5/9 * 4/8 = 3/5 * 5/9 * 1/2 = 3/18 = 1/6
Answer: 1/6
Select all valid probabilities.
a. 110%
b. 0.25
c. 50%
d. 50/49
e. 49/50
f. 1.01
g. 1
Probability is a measure of the likelihood of an event occurring. It is a number between 0 and 1 that is used to indicate the chances of an event occurring. It can be expressed in either decimal or percentage form. A probability of 0 means the event will not happen, and a probability of 1 means it will happen.
Therefore, valid probabilities are those that fall within the range of 0 and 1, inclusive. Thus, the following are valid probabilities:
b. 0.25
c. 50%
d. 50/49
e. 49/50
g. 1
Option A (110%) is invalid because it is greater than 1 (100%). Option F (1.01) is also invalid because it is slightly greater than 1, and probabilities must always be between 0 and 1 inclusive. Thus, the valid probabilities are: b, c, d, e, and g.
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Solve for x. Round your answer to the nearest tenth if necessary.
Step-by-step explanation:
sin90 = sinx
19 17
sin x=0.8947
x=63.47°
A teacher wants to test the effectiveness of two
different math textbooks. She divides her class
into two groups. One group studies out of
textbook A and the other out of textbook B. At
the end of the year she tests both groups to
see which one scores higher. This is an
example of
Answer: an experiment
Answer:
The answer is B
Acellus Sux
Step-by-step explanation:
If the length of the side of a square is 11cm. Then find its area and also find the total length of its boundary.
Answer:
\(\displaystyle 44\:cm. = P \\ 121\:cm.^2 = A\)
Step-by-step explanation:
All angles and edges are congruent in a square, so first, find the total boundary by multiplying the length of the edge by 4:
\(\displaystyle 4l = P \\ 4[11] = P \\ \\ 44 = P\)
Now, for the area, you square the length of the edge:
\(\displaystyle s^2 = A \\ 11^2 = A \\ \\ 121 = A\)
I am joyous to assist you at any time.
Find the measurement of both supplementary angles if one is twice the measurement of the other one.
Answer: 60, 120
Step-by-step explanation:
Let one angle be x
The other angle is 2x
x + 2x = 180°
3x = 180°
x = 180/3 = 60
Other angle is 2 * 60 = 120
What is mackinsey Ge Matrix explain in detail
The McKinsey GE Matrix, also known as the General Electric Matrix, is a strategic management tool used to assess and prioritize a company's portfolio of business units.
The McKinsey GE Matrix evaluates business units based on two key dimensions: market attractiveness and competitive strength.
1. Market Attractiveness: This dimension assesses the attractiveness of the market in which the business unit operates. Factors considered may include market size, growth rate, profitability, industry trends, competitive dynamics, and regulatory environment. The market attractiveness score helps identify the potential for growth and profitability in a particular market.
2. Competitive Strength: This dimension evaluates the competitive strength of the business unit within its market. It takes into account factors such as market share, brand reputation, technological capabilities, distribution channels, product quality, cost structure, and customer loyalty. The competitive strength score helps assess the business unit's ability to outperform competitors and achieve sustainable competitive advantage.
The McKinsey GE Matrix consists of a 9-cell grid, with market attractiveness on the y-axis and competitive strength on the x-axis. Each business unit is plotted on the matrix based on its scores in these dimensions. The matrix is divided into three zones: Invest/Grow, Select/Earn, and Harvest/Divest.
- Invest/Grow: Business units located in this zone have high market attractiveness and strong competitive strength. They are considered promising opportunities for growth and investment. Companies should allocate resources to these units to capitalize on their potential and drive market expansion.
- Select/Earn: Units in this zone have moderate market attractiveness and competitive strength. Companies need to carefully evaluate and decide whether to selectively invest in these units to enhance their performance or maintain their current level of earnings.
- Harvest/Divest: Units in this zone have low market attractiveness and weak competitive strength. They may be in declining markets or face strong competition. Companies should consider divestment or strategic restructuring to minimize losses and reallocate resources to more promising areas.
The McKinsey GE Matrix provides a visual representation of a company's business unit portfolio and helps prioritize resource allocation based on market attractiveness and competitive strength. It assists in identifying growth opportunities, managing risks, and making strategic decisions to enhance overall business performance.
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which expression is equivalent to (3^-1)^2
Answer:
A. 1/9
Explanation:
Given the expression
\((3^{-1})^2\)This is also expressed as;
\(\begin{gathered} =\text{ (}\frac{1}{3^1})^2 \\ =\text{ (}\frac{1}{3})^2 \\ =\text{ }\frac{1^2}{3^2} \\ =\text{ }\frac{1}{9} \end{gathered}\)Hence the result of the expression is 1/9
Charlie and Daniel are playing darts.
The winner will be the one with the
highest average score after 6 games.
Charlie has completed 6 games and
has an average score of 190. So far,
Daniel has played 5 games and has an
average score of 183. What score does
Daniel need in his final game to have
the same average score as Charlie?
HELP LIKE NEED RN!!
Answer:
7
Step-by-step explanation:
Charlie's average score after playing 6 games = 190
Daniel's average score after playing 5 games = 183
190 - 183 = 7
Charlie is 7 points a head from Daniel
thus, Daniel needs to score 7 points in his final game to have the same average score as Charlie.
There is three-fourths of a shell pile left, and Terrence has sorted four-sixths of it.
How much of the shells did he sort?
twelve twenty-fourths
sixteen-eighteenths
twelve-sixteenths
seven-tenths
Based on the fractional value, the amount of the shells that Terrence sorted is A. twelve twenty-fourths.
What is a fractional value?A fractional value is a value that represents a portion or part of the total value.
Fractional values can be depicted as proper, improper, or complex fractions. They can also be depicted as decimals or percentages.
The remaining quantity of the shell pile = ³/₄
The quantity sorted by Terrence = ⁴/₆
The fractional value sorted by Terrence = (⁴/₆ x ³/₄) = ¹²/₂₄ = 0.5 or 50%
Thus, we can conclude that Terrence sorted 50% or ¹²/₂₄ of the shell pile.
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