An alternator that has a separate small alternator mounted on the shaft of its rotor is equipped with a(n) _____.
a. electruc starter
b. primary exciter
c. brushless energizer
d. brushless exciter

Answer:

a rock is made up of two or more minerals but a mineral is a natural substance with chemical and physical properties

Answer: aerofoil type blades

Explanation: they are more difficult to make but offer better performance and higher rotational speeds making them ideal for electrical energy generation.

The common-emitter amplifier is current gain and voltage gain, but no power gain. The correct option is 2).

By inverting, a common emitter amplifier operates. The input impedance is low. It has a high output impedance despite having a low input impedance.

When it serves as a current buffer, the common base circuit operates at its peak efficiency. It has the capacity to accept a low input impedance input current and transfer almost the same current to a greater output impedance.

Therefore, the correct option is 2) current gain and voltage gain, but no power gain.

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The question is incomplete. Your most probably complete question is given below:

1) current gain and power gain, but no voltage gain 2) current gain and voltage gain, but no power gain 3) voltage gain, current gain, and power gain 4) voltage gain and power gain, but no current gain.

Answer:

uehgeg7djw7heidiisosowiuisiejei2k

US import oil because it is cheaper to import oil than to produce it

Importation is a way of bringing in goods and services from neighbouring country into your country.

Countries import because it helps them to supply high cost and scarce resources to its market with products from other countries at a very cheap rate.

Hence we can conclude that US import oil because it is cheaper to import oil than to produce it.

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Answer:

because it is cheaper to import oil than to produce it

Explanation:

d on edge2023

The total variable cost per unit is $170, and the total fixed costs are $1,464,000.

Total variable cost per unit:

Direct materials = 336,000/14,000 units = $24 per unit

Direct labor = 588,000/14,000 units = $42 per unit

Indirect materials = 392,000/14,000 units = $28 per unit

Sales commissions = 98,000/14,000 units = $7 per unit

Shipping = 210,000/14,000 units = $15 per unit

Total variable cost per unit = $24 + $42 + $28 + $7 + $15 = $116

Total fixed costs = $2,828,000 - ($24 x 14,000) - ($42 x 14,000) - ($28 x 14,000) - ($7 x 14,000) - ($15 x 14,000) = $1,464,000

Flexible budget at activity levels of 12,000 units and 16,000 units:

12,000 units: Total variable cost = 12,000 units x $116 = $1,392,000

Total fixed cost = 1,464,000

Total budget = $2,856,000

16,000 units: Total variable cost = 16,000 units x $116 = $1,856,000

Total fixed cost = 1,464,000

Total budget = $3,320,000

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Answer:

y = 0.834X - 1.58015

Slope = 0.8340 ; Intercept = - 1.5802

y = 40.9539

19.93

0.9765

Explanation:

X: Rainfall volume

6

12

14

16

23

30

40

52

55

67

72

81

96

112

127

Y : Runoff

4

10

13

14

15

25

27

48

38

46

53

72

82

99

100

The scatterplot shows a reasonable linear trend between the Rainfall volume and run off.

The estimated regression equation obtained using a linear regression calculator is :

y = 0.834X - 1.58015

y = Runoff ; x = Rainfall volume

Slope = 0.8340 ; Intercept = - 1.5802

Point estimate for Runoff, when, x = 51

y = 0.834X - 1.58015

y = 0.834(51) - 1.58015

y = 40.95385

y = 40.9539

d.)

Point estimate for standard deviation :

s = 5.145

σ = s * √n

σ = √15 * 5.145

= 19.93

e.)

r² = Coefficient of determination gives the proportion of explained variance in Runoff due to the regression line. From the model output, the r² value = 0.9765. Which means That about 97.65% Runoff is due to Rainfall volume.

Potential difference need to be apply to plates of capacitors is 5.63.

The capacitor is a two-terminal electrical device that stores energy in the form of electric charges.

C=55.0μf

E=155j

E=1/2cv^2

E=1/2*55.0*v^2=155

v=155*2/55.0=5.63v

potential difference is 5.63v.

The energy stored in a capacitor is nothing but the electric potential energy and is related to the voltage and charge on the capacitor. If the capacitance of a conductor is C, then it is initially uncharged and it acquires a potential difference V when connected to a battery.

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An affordance in an object's design is how well the user loves the interface. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface).

A user's ability-based potential with an object is referred to as its affordance. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface). A user's ability-based potential with an object is referred to as its affordance. An affordance is not an object's "attribute" as a result (like a physical object or a User Interface). An affordance is instead defined by the interaction between the user and the thing: A door can be opened if you can get to the handle. The door cannot be opened if a young child cannot grasp the handle. An affordance is essentially a potential for an action in the interaction between a user and an object.

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Answer:

4.75m^2

Explanation:

Given:-

- Temperature of hot fluid at inlet:  \(T_h_i = 300\) °C

- Temperature of cold fluid at outlet: \(T_c_o = 120\) °C

- Temperature of cold fluid at inlet: \(T_c_i = 35\) °C

- The overall heat transfer coefficient: U = 1500 W / m^2 K

- The flow rate of cold fluid: m_c = 10,00 kg/ h

- The flow rate of hot fluid: m_h = 5,000 kg/h

Solution:-

- We will evaluate water properties at median temperatures of each fluid using table A-4.

Cold fluid:   Tci = 35°C , Tco = 35°C

                            Tcm = 77.5 °C ≈ 350 K  --- > \(C_p_c = 4195 \frac{J}{kg.K}\)

 Hot fluid:     Thi = 300°C , Tho = 150°C ( assumed )

                             Thm = 225 °C ≈ 500 K --- > \(C_p_h = 4660 \frac{J}{kg.K}\)

- We will use logarithmic - mean temperature rate equation as follows:

                             \(A_s = \frac{q}{U*dT_l_m}\)

Where,

                 A_s : The surface area of heat exchange

                 ΔT_lm: the logarithmic differential mean temperature

                 q: The rate of heat transfer

- Apply the energy balance on cold fluid as follows:

                   \(q = m_c * C_p_c * ( T_c_o - T_c_i )\\\\q = \frac{10,000}{3600} * 4195 * ( 120 - 35 )\\\\q = 9.905*10^5 W\)

- Similarly, apply the heat balance on hot fluid and evaluate the outlet temperature ( Tho ) :

                   \(T_h_o = T_h_i - \frac{q}{m_h * C_p_h} \\\\T_h_o = 300 - \frac{9.905*10^5}{\frac{5000}{3600} * 4660} \\\\T_h_o = 147 C\)

- We will use the experimental results of counter flow ( unmixed - unmixed ) plotted as figure ( Fig . 11.11 ) of the " The fundamentals to heat transfer" and determine the value of ( P , R , F ).

- So the relations from the figure 11.11 are:

                  \(P = \frac{T_c_o - T_c_i}{T_h_i - T_c_i} \\\\P = \frac{120 - 35}{300 - 35} \\\\P = 0.32\)    

                 \(R = \frac{T_h_i - T_h_o}{T_c_o - T_c_i} \\\\R = \frac{300 - 147}{120 - 35} \\\\R = 1.8\)

Therefore,         P = 0.32 , R = 1.8 ---- > F ≈ 0.97

- The log-mean temperature ( ΔT_lm - cf ) for counter-flow heat exchange can be determined from the relation:

                        \(dT_l_m = \frac{( T_h_i - T_c_o ) - ( T_h_o - T_c_i ) }{Ln ( \frac{( T_h_i - T_c_o )}{( T_h_o - T_c_i )} ) } \\\\dT_l_m = \frac{( 300 - 120 ) - ( 147 - 35 ) }{Ln ( \frac{( 300-120 )}{( 147-35)} ) } \\\\dT_l_m = 143.3 K\)

- The log - mean differential temperature for counter flow is multiplied by the factor of ( F ) to get the standardized value of log - mean differential temperature:

                       \(dT_l = F*dT_l_m = 0.97*143.3 = 139 K\)

- The required heat exchange area ( A_s ) can now be calculated:

                     \(A_s = \frac{9.905*10^5 }{1500*139} \\\\A_s = 4.75 m^2\)

Answer:

Engine oil level.

Brake fluid.

Power steering fluid.

Answer:

you can't eat your school computer or a pencil.

To stop water leakage from coming into your basement, there are several measures you can take.

First, ensure proper grading around your home's foundation to direct water away. Install and maintain gutters and downspouts to carry water away from the foundation.

Seal any cracks or gaps in the basement walls or floors. Consider installing a sump pump system to pump out water that enters the basement.

Also, improve exterior drainage by installing French drains or landscaping features to divert water away from the foundation.

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The way that chain branching affects a) degree of crystallinity, b) strength, and c) elongation of polyethylene is given below.

Polyethylene is a type of polymer that is made up of long chains of repeating units of ethylene. The properties of polyethylene can be influenced by the size and shape of these chains, as well as the way that the chains are organized within the polymer. One way to alter the properties of polyethylene is to introduce chain branching into the polymer.

a) Degree of crystallinity: Chain branching can have a significant effect on the degree of crystallinity of polyethylene. Crystallinity refers to the degree to which the polymer molecules are organized in a regular, repeating pattern. In general, the more crystalline a polymer is, the stronger and stiffer it will be. In unbranched polyethylene, the molecules are able to pack together tightly, which leads to a high degree of crystallinity.

b) Strength: The strength of a polymer is related to its degree of crystallinity. As a result, the strength of polyethylene will typically be lower when chain branching is present. This is because the chain branches disrupt the regular, repeating pattern of the polymer molecules, making it more difficult for the polymer to resist deformation.

c) Elongation: Elongation refers to the ability of a polymer to stretch or elongate before breaking. Polymers that are more crystalline tend to be less elongation, while polymers that are less crystalline tend to be more elongation. Therefore, when chain branching is present in polyethylene, the polymer will tend to be more elongation. This is because the chain branches disrupt the regular, repeating pattern of the polymer molecules, making it easier for the polymer to stretch.

Therefore, note that properties of Polyethylene can vary depending on the type of polyethylene and the way the polymerization process is carried out, thus the effects of chain branching on it's properties may be different depending on the context.

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Answer:

Explanation:

If the museum is running short of funds, and you decide to increase revenue. An increase or decrease in the price of admission into the museum depends on the following:

1. If demand for admission into the museum is elastic there are two possible outcomes

a. An increase in the price of admission leads to a decrease in the quantity demand of admission into the museum

b. A decrease in price of admission into the museum leads to an increase in the quantity demand of admission into the museum.

This follows the law of demand which states that "the higher the price, the lower the quantity demanded and the lower the price, the higher the quantity demanded".

2. If the demand for admission into the museum is inelastic, then an increase in price will lead to an increase in revenue of the museum.

Therefore, before the curator increase the price of admission into the museum, he should first determine the price elasticity of demand of the museum.

Answer:

Please check the photo (solve)

Using the frequency of the radio signal given, the length of the half-wave dipole antenna is 30m

The formula to calculate the length of a half-wave dipole antenna is:

Length (L) = (c / f) / 2

where:

We are given that the frequency of the radio signal is 10 MHz (10,000,000 Hz). Substituting these values into the formula, we get:

L = 3 * 10⁸ / 10 * 10 * 10⁶

L = 30m

Therefore, the length of a half-wave dipole antenna to be used to receive a 10 MHz radio signal is 30 meters.

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Answer:

Supply, demand, global markets, imports and exports, and government Regulation.

Explanation:

Answer:

D. Collects radiation reflected from Earth.

Explanation:

The weight of the concrete column is approximately XXX pounds.

To calculate the weight of the concrete column, we need to determine its volume and then multiply it by the density of concrete.

The diameter of the column is given as 350 mm, which can be converted to meters by dividing it by 1000: 350 mm / 1000 = 0.35 m.

The formula to calculate the volume of a cylinder is V = πr²h, where r is the radius and h is the height. Since we have the diameter, we need to divide it by 2 to obtain the radius: 0.35 m / 2 = 0.175 m.

Substituting the values into the volume formula, V = π(0.175 m)²(2 m) = 0.3066 m³.

Next, we multiply the volume by the density of concrete to find the mass: 0.3066 m³ * 2.45 mg/m³ = 0.75087 mg.

Finally, to convert the mass to pounds, we can use the conversion factor that 1 mg is approximately equal to 3.5274e-9 pounds: 0.75087 mg * 3.5274e-9 pounds/mg = XXX pounds (rounded to the appropriate precision).

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Answer:

V= 90h cm³ where h is the height of the rectangular prism.

Explanation:

The formula for volume of a rectangular prism is ;

V=l*w*h  where;

V=volume in cm³

l= length of prism=10cm

w =width of the prism = 9 cm

Assume the height of the prism as h cm then the volume will be;

V= 10* 9*h

V= 90h cm³

when the value of height of the prism is given, substitute that value with h to get the actual volume of the prism.

A centralized intelligent lighting control system enables the management and control of multiple lighting fixtures from a single centralized location, providing greater efficiency and flexibility.

What is lightning?
Lightning is a sudden and powerful electrical discharge that occurs in the atmosphere, often accompanied by thunder. It is caused by the buildup and discharge of static electricity within clouds or between a cloud and the ground. Lightning can produce intense light, heat, and electromagnetic radiation, and can cause damage or injury if it strikes a person or object.

A distinguishing feature of a centralized intelligent lighting control system is that it allows for the control and management of multiple lighting fixtures from a single centralized location or system, typically through the use of a networked control system or software. This can provide greater flexibility, efficiency, and ease of use, as well as allow for the monitoring and adjustment of lighting levels and energy usage across a building or facility. Additionally, some centralized intelligent lighting control systems may incorporate features such as occupancy sensors or daylight harvesting to further optimize energy efficiency and cost savings.

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The answer is, a distinguishing feature of a centralized intelligent lighting control system is that it allows all the lighting fixtures in a building to be controlled from a central location, such as a computer or a control panel.

A computer is an electronic device that can perform a variety of tasks based on instructions provided to it in the form of software programs. It consists of various hardware components, including a central processing unit (CPU), memory, storage devices, input/output devices, and communication devices.

This means that the system can be programmed to turn lights on or off automatically based on various factors, such as time of day, occupancy, or ambient light levels.

The system can also be controlled manually by a user, who can adjust the brightness or color temperature of the lights, create custom lighting scenes, or turn lights on or off in specific areas of the building. Centralized control also allows for the collection of data on energy usage, occupancy patterns, and other metrics, which can be used to optimize the lighting system for maximum efficiency and comfort.

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There are a total of six formats of units that can be chosen.

The correct answer to the given question is option c.

In the Drawing Units dialog box, there are a total of six formats of units that can be chosen. These formats provide flexibility in selecting the desired unit system for measurements within a drawing. The options available are as follows:

1. Decimal:

  This format represents measurements in decimal units, such as meters, millimeters, inches, or feet. It allows for precise measurements with decimal values.

2. Engineering:

  The engineering format is commonly used in technical fields. It represents measurements using a combination of whole numbers and fractions, such as feet and inches.

3. Architectural:

  The architectural format is specific to the field of architecture. It represents measurements using feet, inches, and fractions, following the conventions used in architectural drawings.

4. Fractional:

  This format expresses measurements exclusively in fractions, such as inches and fractions of an inch.

5. Scientific:

  The scientific format is used for scientific and engineering calculations. It represents measurements using exponential notation, such as meters or millimeters.

6. Surveyor:

  The surveyor format is commonly used in land surveying. It represents measurements using degrees, minutes, and seconds, allowing for accurate representation of angles and distances.

These six formats provide options suitable for various industries and applications, catering to the specific needs of different disciplines. By selecting the appropriate format, users can ensure accurate and consistent representation of measurements within their drawings.

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Answer:

you have to think then go scratch and then calculate and the design  

Explanation:

The statistical analysis of a dataset inform a design process.

Statistical analysis is a kind of tool which helps collect and analyze large amounts of data. This is helpful to identify common patterns of dataset and make trends to convert them into meaningful information.

Designers do make use of statistical analysis of dataset in design process.

Analysis is a key part of design process.  Without analysis, nothing can be done in designing process.

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The minimum time for the vacuum-propelled capsule to make the 10 km trip is t = 1.81 minutes.

To determine the minimum time for the capsule to make the 10 km trip, we need to consider the limiting factors of maximum acceleration, maximum deceleration, and velocity limitation.

Maximum acceleration and deceleration:

Given that the maximum acceleration and deceleration have a limiting magnitude of 0.6g, we can convert this to meters per second squared (m/s^2) for calculations. One g is equivalent to 9.8 m/s^2.

Therefore, the maximum acceleration and deceleration are 0.6 * 9.8 = 5.88 m/s^2.

Velocity limitation:

The velocity is limited to 400 km/h. To convert this to meters per second (m/s), we divide by 3.6 (since 1 km/h = 1/3.6 m/s).

Therefore, the velocity limitation is 400 / 3.6 = 111.11 m/s.

Now, let's calculate the time using the equations of motion:

a. Calculate the time taken to accelerate from 0 m/s to the maximum velocity:

Using the formula v = u + at, where v is the final velocity, u is the initial velocity, a is the acceleration, and t is the time.

Initial velocity (u) = 0 m/s

Final velocity (v) = 111.11 m/s

Acceleration (a) = 5.88 m/s^2

Time taken to accelerate (t1) = (v - u) / a

b. Calculate the time taken to decelerate from the maximum velocity to 0 m/s:

Using the same formula v = u + at, where v is the final velocity, u is the initial velocity, a is the deceleration (the same as acceleration but with a negative sign), and t is the time.

Initial velocity (u) = 111.11 m/s

Final velocity (v) = 0 m/s

Deceleration (a) = -5.88 m/s^2 (negative sign because it is deceleration)

Time taken to decelerate (t2) = (v - u) / a

c. Calculate the time taken to travel at a constant velocity:

The distance traveled at a constant velocity is the remaining distance after acceleration and deceleration, which is 10 km - (2 * 10 km) = 0 km.

Time is taken at constant velocity (t3) = Distance / Velocity

d. Calculate the total time:

The total time taken is the sum of the time taken for acceleration (t1), deceleration (t2), and travel at a constant velocity (t3).

Total time = t1 + t2 + t3

By plugging in the values and performing the calculations, we arrive at the minimum time for the capsule to make the 10 km trip, which is t = 1.81 minutes.

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The k - 1 order statistics that partition the sorted set into k sets of equal size are known as the kth quantiles of an n-element set (to within 1). To list the kth quantiles of a set, provide an O(n lg k)-time algorithm.

The simple approach would be to pick the lowest element out of each k, 2k, 3k, etc., whose running time is O(kn) (k calls to the select method of O(n)). But, this could be improved to outperform O (kn). We execute the following recursive call after the select function finds the median of medians at the index I. Recursively call choose the kth lowest element in the left subarray if the index of the median of medians, I is greater.

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Where the above conditions are given,  the specimen of S-590 alloy will elongate by 1.76 mm after 5900 hours of exposure to a tensile stress of 80 MPa at 815°C.

To solve this problem, we need to use the Larson-Miller parameter to relate time, temperature, and creep strain. The Larson-Miller parameter is defined as:

LM = (T + 273) * log(t + C)

where T is the absolute temperature in Kelvin, t is the time in hours, and C is a material constant.

To calculate the constant C, we can use the given data for the S-590 alloy:

log(C) = 20.0 - 19300/(T + 273)

At a temperature of 815°C, T = 1088 K, so:

log(C) = 20.0 - 19300/1361 = 15.29

C = 2.1 x 10^15

Now we can use the Larson-Miller parameter to find the time-temperature equivalence for the given stress and creep elongation:

LM = (T + 273) * log(t + C)

LM = (1088 + 273) * log(5900 + 2.1 x 10^15) = 42.3

Therefore, we can calculate the equivalent temperature and time as:

T_eq = LM / log(t + C) - 273 = 1384°C

t_eq = exp(LM / (T_eq + 273) - C) - C = 3.5 x 10^8 hours

At this temperature and time, we can assume that the total creep elongation is equal to the given value of 1.4 mm. Therefore, the primary creep elongation is:

epsilon_p = (1.4 mm) / (1 + epsilon_i)

where epsilon_i is the instantaneous creep elongation. We are given that the instantaneous and primary creep elongation add up to 1.4 mm, so:

epsilon_i + epsilon_p = 1.4 mm

epsilon_i + (1.4 mm) / (1 + epsilon_i) = 1.4 mm

Solving for epsilon_i, we get:

epsilon_i = 0.36 mm

Therefore, the total elongation after 5900 hours is:

epsilon_total = epsilon_i + epsilon_p = 0.36 mm + 1.4 mm = 1.76 mm

Therefore, the specimen of S-590 alloy will elongate by 1.76 mm after 5900 hours of exposure to a tensile stress of 80 MPa at 815°C.

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