An aqueous solution is 2.00 M urea. The density of the solution is 1.029 g/ml. What is the molal concentration of urea in the solution?

Answers

Answer 1

The molal concentration of urea in the solution is 2.20 mol/kg.

How to find the molal concentration of a solute in solution?

To find the molal concentration of urea in the solution, follow these steps:

1. Convert the density from g/mL to g/L:
1.029 g/mL * 1000 mL/L = 1029 g/L

2. Calculate the mass of the solution:
2.00 mol/L * (1 L) = 2.00 mol of urea
Since urea has a molar mass of 60.06 g/mol:
2.00 mol * 60.06 g/mol = 120.12 g of urea

3. Determine the mass of the solvent (water) in the solution:
Total mass of the solution - mass of urea = mass of water
1029 g - 120.12 g = 908.88 g of water

4. Convert the mass of water to kg:
908.88 g * (1 kg/1000 g) = 0.90888 kg

5. Calculate the molal concentration:
Molality = moles of solute / mass of solvent (in kg)
Molality = 2.00 mol / 0.90888 kg

So, the molal concentration of urea in the solution is 2.20 mol/kg.

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Related Questions

The field of corn shown below was grown with 250 L/ha herbicide and no insecticide. Based what do you observe work what’s the resistance type of the corn?
A)None
B)Herbicide
C) Caterpillars
D) Caterpillars and herbicide

The field of corn shown below was grown with 250 L/ha herbicide and no insecticide. Based what do you

Answers

Based on the fact that only herbicide was used to grow the corn, this means that the resistance type of the corn are caterpillars.

What are herbicide and insecticide?

Herbicide are chemicals used to control and kill weeds that could hinder crop production while insecticides are chemicals used to control insect pests.

According to this question, a field of corn was grown with 250 L/ha herbicide and no insecticide. This means that only herbs or weeds are being controlled on the field.

Therefore, it can be said that the corn plants are the type that are resistant to caterpillars, which are examples of insects.

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When Earth receives energy from the Sun, ____. a. some energy is reflected back into space b. some is absorbed by the atmosphere c. some is absorbed by land and water on Earth's surface d. all of the above Please select the best answer from the choices provided A B C D

Answers

Answer:

D - all of the above

Explanation:

For the following molecule, what will be the ratio of the M to M+6 peaks (M:M+6, respectively)?
CI Br CI
1:1
10:1
3:1
27:1
12.5:1

Answers

For the molecules Cl Br Cl the ratio of the M to M+6 peaks is option D- 12:5:1.

The ratio of M to M+6 peaks in a mass spectrum of a molecule depends on the number of carbon and hydrogen atoms present in the molecule. The presence of carbon-13 isotopes in the molecule leads to a smaller M+6 peak relative to the M peak.

M = (2 × atomic mass of C) + (2 × atomic mass of Br) + (2 × atomic mass of I)

= (2 × 12.01) + (2 × 79.9) + (2 × 126.9)

= 345.6

The M+6 peak corresponds to the molecular weight of the molecule with one carbon-13 isotope, which is:

M+6 = (2 × atomic mass of C) + (2 × atomic mass of Br) + (2 × atomic mass of I) + (atomic mass of carbon-13)

= (2 × 12.01) + (2 × 79.9) + (2 × 126.9) + 13.003

= 358.6

The ratio of M to M+6 peaks can be calculated by dividing the intensity of the M peak by the intensity of the M+6 peak.

M:M+6 = (345.6 / 358.6) / 0.011 = 12.5:1

Therefore, the answer is 12.5:1.

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Determine the mass in grams of each of the following:
a. 3.00 mol Al
b. 2.56 × 10^24 atoms Li
c. 1.38 mol N
d. 4.86 × 10^24 atoms Au
e. 6.50 mol Cu
f. 2.57 × 10^8 mol S
g. 1.05 × 10^18 atoms Hg

Answers

Answer:

a. 3.00 mol Al = 3.00 x 27.0 g/mol = 81.0 g

b. 2.56 × 10^24 atoms Li = 2.56 × 10^24 x 6.939 g/mol = 17.75 g

c. 1.38 mol N = 1.38 x 28.0 g/mol = 38.64 g

d. 4.86 × 10^24 atoms Au = 4.86 × 10^24 x 197.0 g/mol = 961.3 g

e. 6.50 mol Cu = 6.50 x 63.5 g/mol = 410.75 g

f. 2.57 × 10^8 mol S = 2.57 × 10^8 x 32.1 g/mol = 82,567,600 g

g. 1.05 × 10^18 atoms Hg = 1.05 × 10^18 x 200.6 g/mol = 210,000 g

Explain how scientists study the Earth’s interior. PLEASE HELP :))))!

Answers

Answer:

Scientists study Earth's interior by studying

seismic waves. Seismic waves are waves of energy that travel

through Earth.

Explanation:

Please respond, will give brainliest to best answer! (multiple choice)
The ion with the smallest radius is

a. Br-
b. Cl-
c. I-
d. F-
e. O2-

Answers

Answer:

D. F-

Explanation:

Br - 185pm

Cl - 175pm

I - 198pm (I'm not sure what "I" is but I guess it is iodine)

F - 147pm

\(O_{2}\) - 152pm

=> The ion with the smallest radius is F - 147pm

What do voltage-gated ion channels open in response to?.

Answers

Answer:Voltage-gated channels open (activate) in response to changes in membrane potential because the electric field acts on the channel to change its protein conformation (or state). It is voltage-gated sodium (Na+) channels that initiate action potentials and voltage-gated K+ channels that cause them to end.

Voltage-gated ion channels are membrane-integral proteins that allow certain inorganic ions to pass through cell membranes. They play a crucial part in the electrical signaling process used by excitable cells like neurons, opening and closing in response to variations in transmembrane voltage.

The gate often opens in response to a particular stimulus. Ion channels are primarily known to open in response to changes in voltage across the membrane (voltage-gated channels), mechanical stress (mechanically gated channels), or ligand binding (ligand-gated channels).

Voltage-gated ion channels are those that open or close in response to changes in the electrical charge or voltage across the plasma membrane.

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Answers

Answer:

Full answer in explanation

Explanation:

High Tide - when tides are at their highest elevationLow Tide - when tides are at their lowest elevationSpring Tide - when tides experience the greatest range between high and low; occur at New and Full MoonsNeap Tide - when tides experience the least range between high and low; occur at 1st and 3rd Quarter MoonsGravitational Pull - the invisible force that exists between all objects that have mass. The greater the mass, the greater the effect of the forceTide - the daily change in ocean levels due to the gravitational force of the moon and the sun exerted on Earth

Hope this helps!

To make a saturated solution, 30 g of sodium chloride is dissolved in 100 g of


water at 293 K. Find its concentration at this temperature.

Answers

Answer:

30%

Explanation:

As the formula for finding concentration

= (mass of solute/mass of solution)×100

= (30/100)×100

= 0.3×100

= 30%

The concentration is 30%.

How to find concentration?

As the formula for finding concentration

= (mass of solute/mass of solution)×100

= (30/100)×100

= 0.3×100

= 30%

What is a concentration?

The amount of a substance, such as salt, is in a positive amount of tissue or liquid, along with blood. A substance turns into more concentrated whilst much less water is present.

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3. If a gas has a pressure of 32.1 psi at a temperature of 25°C, then what is the new pressure if the temperature is increased to 75°C?

Answers

Answer: 37.485 psi

Explanation: using the gas law and assuming that volume is constant due to nor being stated we use the formula

P1/T1=P2/T2

Note that the tempreture should be changed from °C to K by adding 273

A student runs 100 meters in 16 seconds. What is the speed of the student?

Answers

Answer:

6.25m/s

Explanation:

speed = distance/time

speed = 100/16 = 6.25m/s

1.0 M N2 and 1.5 M Cl2 were placed in a 4.0 L reaction container. They reacted until equilibrium was reached. Calculate the equilibrium concentration of N2, Cl2 and NCl3. Input these answers in the following 3 questions. N2 + 3 Cl2 ⇄ 2 NCl3 Kc = 1.2x10^-4
a. What is the equilibrium concentration of N2?
b. What is the equilibrium concentration of Cl2?
c. What is the equilibrium concentration of NCl3? (record answer with 2 significant figures)

Answers

Answer:  The equilibrium concentration of NCl₃ is 1.2x10⁻⁴ = (2x)² / ((1.0 - x) * (1.5 - 3x)³)

Explanation:

To solve this problem, we'll use the provided equilibrium constant (Kc) and the stoichiometry of the balanced equation to determine the equilibrium concentrations of N₂, Cl₂, and NCl₃.

The balanced equation for the reaction is:

N₂ + 3 Cl₂ ⇌ 2 NCl₃

Let's assume that at equilibrium, the change in the concentration of N₂ is x (M), the change in the concentration of Cl₂ is 3x (M), and the change in the concentration of NCl₃ is 2x (M).

Using the equilibrium concentrations, we can write the expression for the equilibrium constant as follows:

Kc = [NCl₃]₂ / ([N₂] * [Cl₂]₂)Given:

Initial concentration of N = 1.0 M

Initial concentration of Cl₂ = 1.5 M

Equilibrium constant (Kc) = 1.2x10^-4a.

Equilibrium concentration of N₂:

At equilibrium, the concentration of N₂ is given by the expression:

[N₂] = initial concentration of N₂ - change in concentration of N₂[N₂] = 1.0 M - xb. Equilibrium concentration of Cl₂:

At equilibrium, the concentration of Cl₂ is given by the expression:

[Cl₂] = initial concentration of Cl₂ - change in concentration of Cl₂[Cl₂] = 1.5 M - 3xc. Equilibrium concentration of NCl₃:

At equilibrium, the concentration of NCl₃ is given by the expression:

[NCl₃] = initial concentration of NCl₃ + change in concentration of NCl₃[NCl₃] = 2x

Now, substitute the expressions for [N₂], [Cl₂], and [NCl₃] into the equilibrium constant expression and solve for x:

Kc = [NCl₃]² / ([N₂] * [Cl₂]³)

1.2x10^-4 = (2x)^2 / ((1.0 - x) * (1.5 - 3x)^3)

Solve this equation to find the value of x. Once you have the value of x, you can calculate the equilibrium concentrations of N₂, Cl₂, and NCl₃ using the expressions derived earlier.

Please note that solving this equation involves a quadratic equation, and it may require numerical methods or approximations to find the value of x.

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calculate the mass of 25,000 molecules of nitrogen gas. (1 mole = 6.02 × 1023 molecules) group of answer choices 7.00 × 105 g 5.81 × 10−19 g 5.38 × 1026 g 1.16 × 10−18 g

Answers

The mass of the 25,000 molecules of Nitrogen gas is found to be 0.0000017 g (1.7 x 10⁻⁶ g).

We must use the molar mass of nitrogen and the Avogadro's number to get the mass of 25,000 molecules of nitrogen gas.

Nitrogen (N₂) has a molar mass of 28 g/mol.

The number of particles in one mole of any substance determined by Avogadro is 6.02 x 10²³.

One nitrogen gas molecule's mass can be determined as follows:

Nitrogen's (N₂) molecular weight is 28 g/mol.

Nitrogen gas molecules total 25,000.

Nitrogen gas moles equal (25,000 molecules) / (6.02 x 10²³ molecules/mol)

(Num. of moles) x = mass of nitrogen gas (molar mass)

[(25,000 molecules) / (6.02 x 10²³ molecules/mol)] is a formula for the mass of nitrogen gas. x (28 g/mol)

Nitrogen gas mass = 0.00000117 g

Therefore, 25,000 nitrogen gas molecules have a mass of about 0.00000117 g.

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write the chemical equation for the reaction whose enthalpy change is the standard enthalpy of formation of sucrose,

Answers

The chemical equation for the reaction, the enthalpy change of which is equal to the standard enthalpy of sucrose formation, C12H22O11;  C6H12O6 (s) + 6 O2 (g) + 11 H2O (l) Δ H is equal to -2,837 kJ/mol.

What is Chemical equation?

A chemical equation is a graphical representation of a chemical reaction, with the reactants (the starting materials) on the left and the products (the end materials) on the right. It uses chemical formulas to identify the reactants, products, and direction of the reaction.

As an example: 2H2 + O2 → 2H2O

In this equation, two molecules of hydrogen (2H2) react with one molecule of oxygen (O2) to form two molecules of water (2H2O).

What does Molecules mean?

Molecules are the tiniest particles of a substance that can still be identified as such. They are composed of atoms held together by chemical bonds. Molecules are the fundamental building blocks of matter and are required for life on Earth. Molecules are important for a variety of reasons. They play a role in how substances interact with one another and react to form new substances. They are also important in energy transfer and signal transmission within the body.

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what is the percent yield of sulfur dioxide if the burning of 25.0 g of carbon disulfide produces 40.5 g of sulfur dioxide?

Answers

Answer:

25-54-46-36 619-73 77-88-50

a sample of argon with a volume of 6.18 l, a pressure of 1.00 atm, and a temperature of 293 k expanded to a volume of 9.45 l and pressure of 0.49 atm. what was its final temperature?

Answers

The final temperature for the following sample of argon with a volume of 6.18 l, a pressure of 1.00 atm, is 219.5 K.

The ideal gas equation is generally PV =nRT but for the pressure and temperature the equation is P1V1 / T1 = P2V2 /T2. The P is pressure T is temperature and V us volume that us given along with the temperature and pressure in the ideal gas equation.

Here we have the ideal gas equation as ;

P1 ,= 1.00 atmP2= 0.49 atmV1= 6.18 LV2= 9.45 lT1= 293k T2= ?So the formula is P1V1 / T1 = P2V2 /T2= 1.00*6.18/293 = 0.49*9.45/T2= T2 = 0.49*9.45*293/1.00*6.18 = 219.5 KThen T2 is = 219.5 K

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Consider the following generic reaction for which k = 2. 54: 3 z q ⇄ 2 x what is the value of k for the following reaction: 4 x ⇄ 6 z 2 q.

Answers

The equilibrium constant of the second reaction is 0.155.

What is equilibrium constant?

The equilibrium constant is a numerical value that shows the extent to which reactants are converted into products at a given temperature.

Now, we have the reaction; 3Z + Q ⇄ 2 X  and  4 X ⇄ 6 Z + 2 Q.

In the first reaction;

K =[ X]^2/[Z]^3 Q

In the second reaction;

[Z]^6 [Q]^2/[X]^4

Let [ X]^2 = A

[Z]^3 Q = B

Then the second reaction can be;

K = (B)^2/(A)^2 = (B/A)^2

The equilibrium constant of the second reaction therefore is; (1/2.54)^2

K = 0.155

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Part A
Look at the graphical display for the group 1 elements. What pattern do you observe about atomic radii as you move from
ydrogen at the top of the table to francium at the bottom?

Part ALook at the graphical display for the group 1 elements. What pattern do you observe about atomic

Answers

The atomic radii of the atoms in the group 1 increases down the group as we go from Hydrogen to Francium.

What is atomic radii ?

The total distance from the nucleus of an atom to the outermost orbital of its electron is known as its atomic radii or atomic radius.

As we go down the group, the number of orbits or shell increases.

Hence, atomic radii of the atoms in the group 1 increases down the group as we go from Hydrogen to Francium.

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please help me. :)))

please help me. :)))

Answers

46.12 grams of water are produced when 35 grams of \(C_6H_1_0\) react with 45 grams of \(O_2\).

Stoichiometric problem

The balanced equation for the combustion of C6H10 (cyclohexene) with O2 is:

\(C_6H_{10} + O_2 - > CO_2 + H_2O\)

From the balanced equation, we can see that 1 mole of  \(C_6H_1_0\) reacts with 6 moles of O2 to produce 6 moles of water.

First, let's calculate the number of moles of C6H10 and O2:

Molar mass of C6H10 = 6(12.01 g/mol) + 10(1.01 g/mol) = 82.16 g/mol

Number of moles of C6H10 = mass / molar mass = 35 g / 82.16 g/mol ≈ 0.426 mol

Molar mass of O2 = 2(16.00 g/mol) = 32.00 g/mol

Number of moles of O2 = mass / molar mass = 45 g / 32.00 g/mol ≈ 1.406 mol

From the stoichiometry of the balanced equation, we can determine that 0.426 moles of C6H10 will produce 0.426 * 6 = 2.556 moles of water.

Now, let's calculate the mass of water produced:

Molar mass of H2O = 2(1.01 g/mol) + 16.00 g/mol = 18.02 g/mol

Mass of water = number of moles of water * molar mass of water

                        = 2.556 mol * 18.02 g/mol

                        ≈ 46.12 g

Therefore, approximately 46.12 grams of water are produced when 35 grams of C6H10 reacts with 45 grams of O2.

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if 4.36 mol of potassium phosphate react, how many grams of barium phosphate are produced?

If 39.5 g AlCl3 is produced, how many grams of HCl was used in the reaction?

PLEASE HELP DUE IN 20 MINS!!!! ;(

Answers

Answer: 64.1 grams of HCl were used in the reaction

For the first question:

= 1,312.5 g of Ba3(PO4)2

= 32.37 grams of HCl


Answer:

Step-by-step explanation:

The balanced chemical equation for the reaction between potassium phosphate (K3PO4) and barium chloride (BaCl2) is:

2 K3PO4 + 3 BaCl2 → Ba3(PO4)2 + 6 KCl

This means that for every 2 moles of K3PO4 that react, we get 1 mole of Ba3(PO4)2 produced.

So, if we have 4.36 mol of K3PO4, we can calculate the amount of Ba3(PO4)2 produced as follows:

4.36 mol K3PO4 × (1 mol Ba3(PO4)2 / 2 mol K3PO4) = 2.18 mol Ba3(PO4)2

To convert this to grams, we need to use the molar mass of Ba3(PO4)2, which is:

3 × 137.33 g/mol (3 Ba atoms) + 2 × 94.97 g/mol (2 P atoms) + 8 × 16.00 g/mol (8 O atoms) = 601.93 g/mol

So, the mass of Ba3(PO4)2 produced is:

2.18 mol Ba3(PO4)2 × 601.93 g/mol = 1,312.5 g

Therefore, 4.36 mol of potassium phosphate would produce 1,312.5 grams of barium phosphate.

For the second question:

The balanced chemical equation for the reaction between aluminum (Al) and hydrochloric acid (HCl) is:

2 Al + 6 HCl → 2 AlCl3 + 3 H2

This means that for every 6 moles of HCl used, we get 2 moles of AlCl3 produced.

We are given that 39.5 g of AlCl3 is produced, so we can use its molar mass to calculate the number of moles produced:

39.5 g AlCl3 / 133.34 g/mol = 0.296 mol AlCl3

Since 2 moles of AlCl3 are produced for every 6 moles of HCl used, we can use this ratio to calculate the number of moles of HCl used:

0.296 mol AlCl3 × (6 mol HCl / 2 mol AlCl3) = 0.888 mol HCl

Finally, we can convert the number of moles of HCl used to grams using its molar mass:

0.888 mol HCl × 36.46 g/mol = 32.37 g HCl

Therefore, 39.5 g of AlCl3 would require 32.37 grams of HCl to react.

Given the standard enthalpy changes for the following two reactions
Given the standard enthalpy changes for the following two reactions:



(1) 2C(s) + 2H2(g)C2H4(g)...... ΔH° = 52.3 kJ



(2) 2C(s) + 3H2(g)C2H6(g)......ΔH° = -84.7 kJ



what is the standard enthalpy change for the reaction:



(3) C2H4(g) + H2(g)C2H6(g)......ΔH° = ?

Answers

The standard enthalpy change for reaction (3) is 117.1 kJ.

The standard enthalpy change for reaction (3) can be calculated by using the enthalpy changes of reactions (1) and (2) and applying Hess's Law.

To do this, we need to manipulate the given equations so that the desired reaction (3) can be obtained.

First, we reverse reaction (1) to get the formation of C2H4(g) from C2H6(g):

C2H4(g)C2H6(g) ΔH° = -52.3 kJ

Next, we multiply reaction (2) by 2 and reverse it to obtain 2 moles of C2H6(g) reacting to form 3 moles of H2(g):

2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

Now, we add the two modified equations together:

C2H4(g)C2H6(g) ΔH° = -52.3 kJ
2C2H6(g)2C(s) + 3H2(g) ΔH° = 169.4 kJ

When adding these equations, the C2H6(g) on the left side cancels out with the C2H6(g) on the right side, leaving us with the desired reaction (3):

C2H4(g) + H2(g)C2H6(g) ΔH° = -52.3 kJ + 169.4 kJ = 117.1 kJ

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the movement carbon from which reservoir to another has the greatest potential to affect earth's climate
PLEASE HELP

Answers

The movement of carbon across oceans has the greatest potential to affect earth's climate

What  are Carbon reservoirs?

Carbon reservoirs are the parts of the Earth that store carbon, such as the ocean. Other examples of carbon reservoirs are the soil, land vegetation and the atmosphere. More so, fossil fuels are large reservoirs.

Carbon moves through nature in a balanced way. It moves from one reservoir to another in a carbon cycle. More so, the amount of carbon naturally released tends to be the same as the amount naturally absorbed. This so-called carbon balance allows life to thrive on the planet.

The ocean is there­fore the greatest of the carbon reservoirs, and essentially determines the atmospheric CO₂ content. The carbon, however, requires centuries to penetrate into the deep ocean, because the mixing of the oceans is a rather slow.

Therefore, the movement of carbon across oceans has the greatest potential to affect earth's climate

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Arrange the procedural steps, from start to finish, that are required to prepare indigo from nitrobenzaldehyde and acetone in base, and then test its ability as a dye.

Answers

Acetone has α-hydrogens (on both sides) and thus can be deprotonated to give a nucleophilic enolate anion. The aldehyde carbonyl is much more electrophilic than that of a ketone, and therefore reacts rapidly with the enolate.

What is nitrobenzaldehyde?Synthesis. The synthesis of 3-nitrobenzaldehyde is achieved via nitration of benzaldehyde, which yields especially the meta-isomer. Creation allocation is about 19% for the ortho-, 72% for the meta- and 9% for the para isomers.Acetone, propanone, or dimethyl ketone, is an organic combination with the formula (CH3)2CO. It is the easiest and smallest ketone. It is a colorless, highly volatile, and combustible liquid with a characteristic aromatic odor.Nitration of benzene with conc nitric acid and conc sulphuric acid gives nitrobenzene. Chlorination with chlorine in the existence of anhydrous aluminum chloride gives meta nitro chlorobenzene.

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How many particles are in 0.15 moles of Francium ?

Answers

I think it’s 86.66
sorry if it’s wrong though

What happens to the solubility of MgCO3 in water if 0.1 M HNO3 is added to the solution at 298 K? (Ksp = 4.0 x 10-5) The solubility decreases.
The solubility increases. The solubility is not affected.

Answers

The solubility of MgCO3 in water decreases when 0.1 M HNO3 is added.

What happens to the concentration of carbonate ions in the solution when HNO3 is added to a solution of MgCO3?

The concentration of carbonate ions decreases due to the formation of HCO3- and H2CO3.

How does the addition of HNO3 affect the solubility of MgCO3 in water?

The solubility of MgCO3 decreases due to the decrease in the concentration of carbonate ions in the solution.

H+ + CO32- → HCO3-

HCO3- + H+ → H2CO3

H2CO3 → H2O + CO2

The net effect of these reactions is to consume carbonate ions, which reduces the solubility of MgCO3.

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How many moles of O are there in 41.8 grams of O?

Answers

Answer:

\(\boxed {\boxed {\sf 2.61 \ mol \ O}}\)

Explanation:

To convert from grams to moles, the molar mass is used. This number tells us the grams per mole of a substance. It can be found on the Periodic Table. Look for oxygen.

Oxygen (O): 15.999 g/mol

Use this number as a ratio.

\(\frac {15.999 \ g \ O }{ 1 \ mol \ O }\)

Multiply by the given number of moles.

\(41.8 \ g \ O *\frac {15.999 \ g \ O }{ 1 \ mol \ O }\)

Flip the fraction so the grams of oxygen cancel.

\(41.8 \ g \ O *\frac { 1 \ mol \ O }{ 15.999 \ g \ O}\)

\(41.8 *\frac { 1 \ mol \ O }{ 15.999 }\)

\(\frac { 41.8 \ mol \ O }{ 15.999 }= 2.61266329146 \ mol \ O\)

The original measurement of grams has 3 significant figures (4, 1, and 8). Our answer must have the same. For the number we calculated, that is the hundredth place. The 2 in the thousandth place tells us to leave the 1.

\(2.61 \ mol \ O\)

41.8 grams of O has 2.61 moles of oxygen.

________ can be a big problem for manufacturers, due to the loss of controls that results once the product is in the hands of unauthorized distributors and resellers.

Answers

Counterfeiting or unauthorized distribution can be a significant problem for manufacturers, as it results in the loss of control over their products when they end up in the hands of unauthorized distributors and resellers.

Counterfeiting and unauthorized distribution pose serious challenges for manufacturers across various industries. When products fall into the hands of unauthorized distributors and resellers, manufacturers lose control over their distribution channels, pricing, and quality assurance. Counterfeit products, in particular, are imitations or replicas of genuine products, often designed to deceive consumers by mimicking the appearance and packaging of the original product.

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How many particles are in 2.50 moles of iron (II) chloride?

Answers

Answer:

1.505 × 10²⁴ particles

Explanation:

The number of particles in iron (II) chloride can be found by using the formula

N = n × L

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

N = 2.5 × 6.02 × 10²³

We have the final answer as

1.505 × 10²⁴ particles

Hope this helps you

When two ionic compounds are dissolved in water, a double replacement reaction can... Group of answer choices occur if two of the ions form an insoluble ionic compound, which precipitates out of solution occur if the ions react to form a gas, which bubbles out of the solution never occur since all ions are in water occur if the ions react to form a gas, which bubbles out of the solution ionic compounds only react with nonmetals

Answers

Answer:

occur if two of the ions form an insoluble ionic compound, which precipitates out of solution

Explanation:

When two ionic compounds are dissolved in water, a double replacement reaction takes place if two of the ions form an insoluble ionic compound, which precipitates out of solution. In double displacement reaction ions switch partners. And hence, produce an insoluble precipitate.

can someone help me please​

can someone help me please

Answers

Answer:

it's d

Explanation:

I took the test and got it right

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