An art supply cabinet contains a total of 75 charcoal pencils, oil pastel crayons, and sketch pads. twice the number of oil pastel crayons is one more than the number of pencils. four times the number of oil pastel crayons plus twice the number of pencils equals eight more than three times the number of sketch pads. right and solve a system of equations to determine the number of each type of the supplies in the cabinet?

The missing value is approximately 64.12 degrees, which is closest to option D: 21.25 using inverse cos.

The inverse cosine (or arccosine) of both sides of the equation must be taken in order to locate the missing value in the equation cos = 7/18 to the closest tenth. We will then be able to convert the value of to degrees and round it to the closest hundredth using the value of the radian that is produced.

cos θ = 7/18

= arccos(7, 18, 7)

A 1.1181 radian angle

We can use the conversion factor /180 to convert radians to degrees.

θ = 1.1181 × 180/π

64.12 degrees.

As a result, the figure that is lacking is roughly 64.12 degrees, which is closest to choice D: 21.25.

Due to the periodic nature of the cosine function, there are often two solutions when determining the inverse cosine of a value. But, since the problem states that we should round to the closest hundredth, which suggests a single answer, we can disregard the second option in this instance. By reinserting the value we discovered into the original equation and making sure it equals 7/18, we can further confirm that the result is accurate.

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The equation that represents the linear relationship between the x-values and the y-values in the table is y = 3x + 2.

The slope of the line passing through the points (0, 2) and (1, 5) is given by:

slope = (change in y) / (change in x) = (5 - 2) / (1 - 0) = 3

Using the point-slope form of the equation of a line, we have:

y - 2 = 3(x - 0)

y = 3x + 2

Therefore, the equation that represents the linear relationship between the x-values and the y-values in the table is y = 3x + 2.

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5. To solve the first question related to triangle, we can use Pythagorean theorem and  by using the formula, A = 1/2 * b * h

Area of the triangles are 48.5, 28.4 and 20.1.

6) The three side lengths of 9ft, 14ft, and 15ft form an acute triangle.

7) The three side lengths of 6km, 8km, and 10km form a right triangle.

This type of triangle is determined by the length of the sides and the measure of the angles. Acute triangles have all angles measuring less than 90 degrees.

5. To solve the first question related to triangle, we can use Pythagorean theorem.

By following the given information, let us divide the triangle into 2 sections.

Triangle 1 with 11 as the longest side. It is shown that the height of the triangle is perpendicular to its base.

For Triangle 1, two of its sides are given, 9 is the base and 11 is the hypotenuse.

So, according to the Pythagorean theorem,

hypotenuse² = base²+ perpendicular²

11² = 9² + perpendicular²

11² - 9² = perpendicular²

40 = perpendicular²

perpendicular = √40

perpendicular = 6.3

Now, for Triangle 2, we found the value of the perpendicular and the hypotenuse is given as 9.

So, by again using Pythagorean theorem,

hypotenuse² = base²+ perpendicular²

9²- 6.3² =  base²

41.6 =  base²

base = √41.6

base =6.4

Thus, the value of the base of the Triangle is 9+6.4=15.4

Now, the area of the overall triangle can be found by using the formula,

A = 1/2 * b * h

Here, the base is 15.4 and the height is 6.3.

A = 1/2 * 15.4 * 6.3

A = 1/2 * 97

A = 48.5 square

Area of triangle 1=

A = 1/2 * 9 * 6.3

A = 1/2 * 56.7

A = 28.4 square

Area of triangle 2=

A = 1/2 * 6.4 * 6.3

A = 1/2 * 40.3

A = 20.1 square

6) The three side lengths of 9ft, 14ft, and 15ft form an acute triangle. This can be determined by using the Pythagorean Theorem.

In this case, the squares of the two shorter sides are 9² + 14² = 277, and the square of the hypotenuse is 15² = 225.

Therefore, the three side lengths form an acute triangle, as the sum of square of two shorter sides is greater than the square of the longer side.

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7) The three side lengths of 6km, 8km, and 10km form a right triangle. This can be determined by using the Pythagorean Theorem.

In this case, the squares of the two shorter sides are 6² + 8² = 100, and the square of the hypotenuse is 10² = 100. Therefore, the three side lengths form a right triangle, as the sum of square of two shorter sides is equal to the square of the longer side.

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Answer:

(A). 5,-25,125,-625

Answer:

⅖

Step-by-step explanation:

please like my answer and brainliest me... hshshshshs

Answer:

18

Step-by-step explanation:

Explanation is in photo

Answer:

D. 2x - 2 + 3x

Step-by-step explanation:

First, add 2x and 3x. Then you get 5x. Then you get the equivalent expression 5x-2.

Answer:

Add all of them together. 1/5 + 2/4 + 4/3 + 3/2 = 53/15 miles

Step-by-step explanation:

1/5 + 2(1/4) + 4(1/3) + 3(1/2)

If A and B are mutually exclusive events, P(A ∩ B) = 0, and the general addition law can be simplified to the sum of the individual probabilities for A and B

Given data ,

If events A and B are mutually exclusive, it means that they cannot occur simultaneously. In this case, the intersection of events A and B, denoted as A ∩ B, would indeed have a probability of 0

And , P(A ∪ B) = P(A) + P(B)

Therefore , if A and B are mutually exclusive, the probability of either event A or event B occurring is equal to the sum of their individual probabilities.

Hence , the probability is solved

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The term for the value that occurs most often in a series of numbers is called the mode.

The mode is one of the three main measures of central tendency, along with the mean and the median. It is a useful descriptive statistic that can provide insights into the characteristics of a dataset.

To find the mode of a set of data, you first need to arrange the data in order, either in increasing or decreasing order. Then, you simply identify the most frequent data point, which is the mode. In some cases, there may be more than one mode if multiple data points occur with the same maximum frequency.

The mode is particularly useful when dealing with categorical or nominal data, where there are distinct categories or values that cannot be ordered in a meaningful way. For example, the mode can help identify the most popular color among a group of people or the most common type of car on a given street. It can also be used for continuous data, although it may be less useful in this case than the mean or median.

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Answer:

try multiplication

Step-by-step explanation:

Answer:

Hi...☺

Here is your answer...✌

GIVEN THAT,

T8 = 17 and T19 = 39

T8 = 17

a + 7d = 17

a = 17 - 7d -----(1)

and

T19 = 39

a + 18d = 39

17 - 7d + 18d = 39 ___ [ from (1) ]

11d = 39-17 = 22

d = 22/11

d = 2

Putting d = 2 in eq(1)

we get

a = 17 - 7(2) = 17 - 14

a = 3

Now,

T25 = a + 24d

= 3 + 24×2 = 3 + 48

= 51

HENCE,

25th term of Given AP is 51

(1.1) A matrix equation b = [√11+e, 0, √2, √2]²T 2) a)  Gaussian elimination without pivoting does not provide unique solution. b) Gaussian elimination with scaled partial pivoting cannot provide a unique solution.(c) Basic LU decomposition is x = [0.788, -3.12, 0.167, 4.55]²T.

The given linear system can be written in matrix form as:

A × x = b

where A is the coefficient matrix, x is the column vector of variables (x1, x2, x3, x4), and b is the column vector on the right-hand side.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

The variable vector x is:

x = [x1, x2, x3, x4]²T

The right-hand side vector b is:

b = [√11+e, 0, √2, √2]²T

(1.2) Solving the system using:

(a) Gaussian elimination without pivoting:

To solve the system using Gaussian elimination without pivoting, we perform row operations on the augmented matrix [A | b] until it is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations, the row-echelon form:

[π², e, -e², 3/7 | 0]

[0, -e, √2, -√3 | √11+e]

[0, 0, 0, 0 | 0]

[0, 0, 0, 0 | 0]

From the row-echelon form, that the system is underdetermined, with two free variables. Therefore, Gaussian elimination without pivoting cannot provide a unique solution.

(b) Gaussian elimination with scaled partial pivoting:

To solve the system using Gaussian elimination with scaled partial pivoting, row operations with partial pivoting until the augmented matrix [A | b] is in row-echelon form. Then back-substitute to find the values of x.

The augmented matrix [A | b] is:

[0, -e, √2, -√3 | √11+e]

[π², e, -e², 3/7 | 0]

[√5, -√6, 1, -√2 | √2]

[π³, e², -√7, -1/9 | √2]

Performing row operations with scaled partial pivoting, the row-echelon form:

[π³, e², -√7, -1/9 | √2]

[0, -e, √2, -√3 | √11+e]

[0, 0, -0.03, -1.02 | 0.027]

[0, 0, 0, 0 | 0]

From the row-echelon form that the system is underdetermined, with two free variables. Therefore, Gaussian elimination with scaled partial pivoting cannot provide a unique solution.

(c) Basic LU decomposition:

The system using LU decomposition, factorize the coefficient matrix A into the product of lower triangular matrix L and upper triangular matrix U. Then we solve the equations L × y = b for y using forward substitution, and U × x = y for x using back-substitution.

The coefficient matrix A is:

A = [[0, -e, √2, -√3],

[π², e, -e², 3/7],

[√5, -√6, 1, -√2],

[π³, e², -√7, -1/9]]

Performing LU decomposition,

L = [[1, 0, 0, 0],

[π², 1, 0, 0],

[√5, 0.3128, 1, 0],

[π³, 4.3626, 2.4179, 1]]

U = [[0, -e, √2, -√3],

[0, e + π², -e² + e × π², 3/7 - e × √2],

[0, 0, 0.9693, -0.3651],

[0, 0, 0, -2.2377]]

Solving L × y = b for y using forward substitution:

[1, 0, 0, 0] ×y = √11+e

[π^2, 1, 0, 0] × y = 0

[√5, 0.3128, 1, 0] × y = √2

[π^3, 4.3626, 2.4179, 1] × y = √2

Solving the above equations,

y = [0.788, -3.12, 0.167, 4.55]²T

Now, solving U × x = y for x using back-substitution:

[0, -e, √2, -√3] × x = 0.788

[0, e + π², -e² + e × π², 3/7 - e ×√2]× x = -3.12

[0, 0, 0.9693, -0.3651] ×x = 0.167

[0, 0, 0, -2.2377] ×x = 4.55

Solving the above equations,

x = [0.788, -3.12, 0.167, 4.55]²T

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The equation that represents the situation shown in the bar diagram will be 4n+2 = 15. Option B is correct.

A linear equation is an algebraic equation of the form y=mx+b. involving only a constant and a first-order term, where m is the slope and b is the y-intercept.

A equation with one variable is called Linear equation with one variable.

The bar diagram is given in which the sum is 15 and it is divided into 5 parts as n,n,n,n, and 2 which is represented as,

n+n+n+n+2 =15

4n+2=15

Hence, the equation that represents the situation shown in the bar diagram will be 4n+2 = 15. Option B is correct.

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If a storage facility charges $1 per cubic yard and the storage space is 32 ft. The storage charge is $1999.97.

What is mathematical conversions?

Mathematical conversions refer to the process of changing one unit of measurement to another unit of measurement that is equivalent in value.

First, we need to convert the dimensions from feet to yards, since the rate is given per cubic yard.

32 feet = 10.6667 yards (dividing by 3)

160 feet = 53.3333 yards (dividing by 3)

10 feet = 3.3333 yards (dividing by 3)

Next, we can calculate the volume of the storage space in cubic yards by multiplying the three dimensions:

Volume = 10.6667 yards x 53.3333 yards x 3.3333 yards

Volume = 1999.97 cubic yards (rounded to two decimal places)

Finally, we can calculate the storage charge by multiplying the volume by the rate:

Charge = 1999.97 cubic yards x $1/cubic yard

Charge = $1999.97

Therefore, the storage charge is $1999.97.

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\(a(c - b) = d \\ \frac{a(c - b}{a} = \frac{d}{a} \\ c - b = \frac{d}{a} \\ c = \frac{d}{a} + b \\ c = \frac{d}{a} + \frac{b}{1} \times \frac{a}{a} \\ c = \frac{d}{a} + \frac{ab}{a} \\ c = \frac{d + ab}{a} \)

THIRD OPTION IS THE ANSWER.

HOPETHIS HELPS

Answer:

∠ 3 = 127°, ∠ 4 = 37°

Step-by-step explanation:

53° and ∠ 3 are adjacent angles and are supplementary, sum to 180°, so

∠ 3 + 53° = 180° ( subtract 53° from both sides )

∠ 3 = 127°

-----------------------------------------------------------

∠ 5 and 53° are corresponding angles and are congruent, so

∠ 5 = 53°

∠ 5, ∠ 4 and 90° lie on a straight line and sum to 180° , that is

53° + ∠ 4 + 90° = 180°

∠ 4 + 123° = 180° ( subtract 123° from both sides )

∠ 4 = 37°

Answer:

10. 127°

11. 37°

Step-by-step explanation:

We have two perpendicular angles and two diagonal angles.

The horizontal one, we will mark A.

The vertical one, we will mark B.

The lower diagonal, we will mark C.

The upper diagonal, we will mark D.

We can see that the diagonals are parallel.

Angle ∠ACat3* has an angle of 53°.

*There are two angles on AC. The "at3" part means that the angle is located at the mark of three.

Since line C is straight, the two angles that are split by line A will be supplementary*.

*Meaning that the angles will add up to 180°.

180 - 53 = 127

Angle ∠ACat3 has an angle of 127°.

So, for ten, 127° is your answer.

Now for eleven.

We know that A and B intersect, and make 90° angles. Let's flip this to the other side of A and B.

Angle ∠AB affects 4 and 5. This means that the angle of 4 plus the angle of 5 will be complementary*.

*Meaning that the angles will add up to 90°

Since we know that C and D are parallel, and that the bottom side is 53°, and that the angles will be complementary, we can subtract 53 from 90 to get our answer.

90 - 53 = 37

Angle ∠ACatBat4 has an angle of 37°.

So, for eleven, 37° is your answer.

Hope this helps. Have a nice day.

The linear equation that describes the total wait time(y) based on the number of family groups in the line(x) is given by:

\(y = 3.5x\)

A linear equation is modeled by:

\(y = ax + b\)

In which:

In this problem:

Hence, the equation is:

\(y = 3.5x\)

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To calculate the amount Briana saved by purchasing a backpack with a sales promotion, we need to find the difference in prices between the two backpacks after applying the respective discounts.

For the first backpack that originally costs $45 with a sales promotion of 20% off:

Discounted price = $45 - (20% * $45) = $45 - $9 = $36

For the second backpack that originally costs $42 with a sales promotion of 10% off:

Discounted price = $42 - (10% * $42) = $42 - $4.2 = $37.8

Now we can calculate the savings:

Amount saved = Original price - Discounted price

Amount saved = $42 - $37.8 = $4.2

Therefore, Briana saved $4.2 by purchasing the backpack that cost $45 with a 20% off promotion instead of the backpack that cost $42 with a 10% off promotion.

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The prediction of a falling value of the US dollar would lead to a rise in prices of imported goods, making them less competitive and increasing the demand for domestic goods.

However, this may also result in a decline in exports as US goods become relatively more expensive in foreign markets. In the context of NAFTA, the concern about job loss in the US economy arises from the fear that increased competition from Mexico and Canada could lead to the relocation of production and jobs to these countries.

The impact of NAFTA on jobs is a complex issue and depends on various factors such as industry, labor regulations, and overall economic conditions. While NAFTA has led to the loss of some jobs in the US, it has also created new opportunities and improved efficiency in certain sectors.

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Vertical ship up three and two to the right and the square root will flip

so options I is wrong

II is right

III is right

IV is wrong

THUS THE ANSWER IS OPTION II III

4

       For C1(Q) = 3 - 2Q.

        For C2(Q) =  4.

     2. The AVC function

           For C1(Q) = 5/Q + 3 + 20/Q - Q.

           For C2(Q) = 3/Q + 4 + 2/Q.

     3. The AFC function

              For C1(Q)= 5/Q - 20/(5 + 3Q + 20/Q - Q)

              For C2(Q) = 0.

     4.  To find the AC function

        For C1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

         For C2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

    5.To find the ATC function

    For C1(Q)= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²)

     For C2(Q)= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

1. To find the MC function, we take the derivative of the cost functions with respect to Q.

For C1(Q) = 5 + 3Q + 202 - Q^2, MC1(Q) = 3 - 2Q.

For C2(Q) = 3 + 4Q + 2, MC2(Q) = 4.

2. To find the AVC function, we divide the cost functions by Q.

For C1(Q), AVC1(Q) = (5 + 3Q + 202 - Q^2)/Q = 5/Q + 3 + 20/Q - Q.

For C2(Q), AVC2(Q) = (3 + 4Q + 2)/Q = 3/Q + 4 + 2/Q.

3. To find the AFC function, we subtract the AVC function from the ATC function.

For C1(Q), AFC1(Q) = (5 + 3Q + 202 - Q^2)/Q - (5 + 3Q + 202 - Q^2)/(5 + 3Q + 20/Q - Q)

= 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AFC2(Q) = (3 + 4Q + 2)/Q - (3 + 4Q + 2)/(3/Q + 4 + 2/Q) = 0.

4. To find the AC function, we add the AVC function to the AFC function.

For

C1(Q), AC1(Q) = (5 + 3Q + 202 - Q^2)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q).

For

C2(Q), AC2(Q) = (3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q.

5. To find the ATC function, we divide the AC function by Q.

For

C1(Q), ATC1(Q) = [(5 + 3Q + 202 - Q²)/Q + 5/Q - 20/(5 + 3Q + 20/Q - Q)]/Q

= 5/Q² + 3/Q + 20/Q² - Q/Q + 5/Q - 20/(5Q + 3Q² + 20 - Q²).

For

C2(Q), ATC2(Q) = [(3 + 4Q + 2)/Q + 3/Q + 4 + 2/Q]/Q

= 3/Q² + 4/Q + 2/Q² + 3/Q + 4/Q + 2/Q.

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Answer:

x+y= idk

Step-by-step explanation:

sorry i need the points

Answer:

15

Step-by-step explanation:

so you know that the hypotenuse for the triangle with "x"'s is 5 square root two, and because we know that the triangle is an isoceles triangle we know the other two side are equal and as a result x=5. Now for the next triangle it is 5 square root 2 on both sides and that is also an isoceles triangle and y is the hypotenuse so it 5 square root 2 times square root 2 which just becomes 2 so then it is 5 times 2 which is 10. So Y=10 and X=5 so X+Y=15.