An athlete leaves the base camp and hikes 10 km, north and then hikes 5 km east. Determine his resulting displacement.

5km East
125km NE
15 km SE
11.2 km NE

The hypothesis test is right-tailed. The P-value is 0.0329.Since the P-value is less than the significance level of 0.10, we should reject H0.

A hypothesis is an educated guess or a proposed explanation made on the basis of limited evidence as a starting point for further investigation. It is a statement that can be tested and is used as a foundation for experimentation, research, and data collection. Hypotheses are used to guide research and provide a framework for understanding the results of the research. Hypotheses are used to help determine what should be studied, how it should be studied, and what the results might be. They provide direction and focus to the research process and help to focus on the most important questions. A hypothesis is not a fact and can be disproved or accepted as new evidence is collected.

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The resultant force due to the cumulative forces acting on the body is 6i+6j N.

Force is a vector quantity and the direction in which they act affects the total magnitude of force. A vector quantity has both magnitude and direction.

And to add a vector one needs to take account of the direction as well.

The force acting on the body can be written as follow:

1. 10N along x-axis ---- 10i

2. 6N along y-axis ---- 6j

3. 4N along negative x-axis ----- -4i

The resultant force is the sum of the above vector:

10i +6j + (-4i) = 6i+6j N

The magnitude of the total force is

\(\sqrt{6^2+6^2}\\ =\sqrt{36+36}\\ =\sqrt{72}=6\sqrt{2} N\)

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The complete question is:

Find the resultant of the following forces

(i) 10 N along the x-axis

(ii) 6 N along the y-axis

(iii) 4 N along the negative x-axis

The speed of the boat relative to the water is 9.08 m/s, when the boat takes 14 minutes to cross the river.

We can decompose the velocity of the boat into two components: one parallel to the river, and one perpendicular to it. Let's call the parallel component \(v_p_a_r\) and the perpendicular component \(v_p_e_r_p\):-

\(v_p_a_r = v_b_o_a_t cos\theta\)

\(v_p_e_r_p = v_b_o_a_t sin\theta\)

The boat will travel a distance of 102 m across the river, which will take 14 minutes or 840 seconds. Therefore, the distance traveled parallel to the river will be:

\(d_p_a_r = v_p_a_r * t = v_b_o_a_t cos\theta * 840 s\)

The distance traveled perpendicular to the river will be:

\(d_p_e_r_p = v_p_e_r_p * t = v_b_o_a_t sin\theta * 840 s\)

The boat will end up at a point directly north of its departure point on the south bank, which means that \(d_p_e_r_p = 102 m\). Therefore, we can solve for \(v_b_o_a_t\) as follows:

\(v_b_o_a_t sin\theta * 840 s = 102 m\)

\(v_b_o_a_t sin\theta = 102 m / 840 s\)

\(v_b_o_a_t sin\theta = 0.1214 m/s\)

To solve for \(v_b_o_a_t\):-

\(tan\theta = d_p_a_r / d_p_e_r_p\)

\(tan\theta = (v_p_a_r * t) / (v_p_e_r_p * t)\)

\(tan\theta = v_p_a_r / v_p_e_r_p\\tan\theta = v_b_o_a_t cos\theta / (v_b_o_a_t sin(\theta))\\\)

Reserving the value of \(d_p_e_r_p\) and solving for \(\theta\):-

\(\theta = arctan(v_p_a_r / (102 m / 840 s))\\\theta = arctan(v_b_o_a_t cos(\theta) / 0.1214 m/s)\)

\(v_p_a_r^2 + v_p_e_r_p^2 = v_b_o_a_t^2\\(v_b_o_a_t cos(\theta))^2 + (v_b_o_a_t sin(\theta))^2 = v_b_o_a_t^2\)

\(v_b_o_a_t^2 (cos^2(\theta) + sin^2(\theta)) = v_b_o_a_t^2\\v_b_o_a_t^2 = 102^2 / (cos^2(\theta) + sin^2(\theta))\\v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]}\)

Reserving the value of \(\theta\):-

\(v_b_o_a_t = \sqrt{[102^2 / {cos^2(\theta) + sin^2(\theta)}]} \\v_b_o_a_t = 9.08 m/s\)

Therefore, the speed of the boat relative to the water is 9.08 m/s.

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Answer:

Explanation:

Battery is removed so its charge stored  becomes fixed .

Energy of capacitor E₁ = Q² / 2C

When dielectric is inserted , the capacity of the capacitor is increased to KC .

Charge on it still remains the same ie Q

So its new energy

E₂ = Q² / 2 KC

E₂ / E₁ = 1 / K

E₂ = E₁ / K

Change in energy

= E₂ - E₁

= E₁ / K - E₁

= E₁ [ (1 / K)  - 1 ]

Factor by which energy is changed

= [ (1 / K)  - 1 ] .

The final absolute humidity at 25°C and 60% relative humidity is 0.012 kg/kg. Volumetric flow rate of the inlet air is 60 m3/h.

a) Design the process for the activities described below:

a) Given values are:

Atmospheric air temperature T1 = 35 ∘C

Relative humidity H1 = 90%

Absolute humidity H1 = 0.033

Fresh air temperature T2 = 10 ∘C

Relative humidity H2 = 100%

Absolute humidity H2 = 0.0075

Final air temperature T3 = 25 ∘C

Relative humidity H3 = 60%

Absolute humidity H3 = 0.012

Here, the inlet air is first cooled to 10 °C to reduce its absolute humidity from 0.033 to 0.0075.

Then, it is heated to 25 °C to achieve 60% relative humidity.

So, the process includes two steps:

Step 1: Cooling the inlet air from 35 °C to 10 °C

Step 2: Heating the cooled air to 25 °C while maintaining its absolute humidity at 0.0075

Design of Cooler (Step 1)

In cooler, the inlet air is cooled to 10 °C.

During this cooling process, the absolute humidity changes from 0.033 to 0.0075.

The cooler can be designed as follows:

Design of Heater (Step 2)

The cooled air is then heated to 25 °C while maintaining its absolute humidity at 0.0075. This can be achieved by mixing the cooled air with the required amount of hot air.

Here, the inlet air flow rate is 60 m3/h.

Design of Heater:

Assuming all the inlet air is cooled to 10°C, then absolute humidity is 0.0075 kg/kg.

Design of Mixer:

In mixer, 60 m3/h of air at 10°C is mixed with the remaining 60 m3/h of air at 35°C to achieve the desired temperature of 25°C.

Design of Cooler:

From the psychrometric chart, the final absolute humidity at 25°C and 60% relative humidity is 0.012 kg/kg.

b) Calculation of Volumetric Flow Rate of the Inlet Air

Given values are:

Temperature T = 25 ∘C

Relative humidity H = 60%

Absolute humidity H = 0.012

Volume flow rate = 60 m3/h

The volume flow rate of air is constant throughout the process.

Therefore, Volumetric flow rate of the inlet air is 60 m3/h.

c) Calculation of Traction of the Air Passing Through the Cooler

Given values are:

Inlet air temperature T1 = 35 ∘C

Inlet air humidity H1 = 0.033

Inlet air flow rate Q1 = 60 m3/h

Outlet air temperature T2 = 10 ∘C

Outlet air humidity H2 = 0.0075

The Traction of the air passing through the cooler can be calculated as follows:

Hope it helps.

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Answer:

c

Explanation:

The expected ratio of free-hanging earlobes to attached earlobes in the offspring is 1:2.

The diagram depicts a Punnett square used to predict the earlobe shape of two parents' offspring. The capital A represents free-hanging earlobes, while the lowercase a represents attached earlobes.

The Punnett square is a square diagram used to predict genotypes of a specific cross or breeding experiment. It is named after Reginald C. Punnett, who invented it in 1905. Biologists use the diagram to calculate the likelihood of an offspring having a specific genotype.

In this case, the genotype rato based on the attached diagram is 1:2.

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Some examples of significant figures that can help you better understand them are:

Furthermore, some extra tips are:

This refers to the digits that carry meaning contributing to its measurement resolution and each of the digits of a number that are used to express it to the required degree of accuracy, starting from the first non-zero digit.

Hence, we can see that:

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Physical quantities which needs only magnitude to express itself, and doesn't need any specific direction.

Example - Speed, Distance, time, mass, and so on.

Physical quantities which needs magnitude as well as direction to express itself, and follows vector law of addition.

Example - force, acceleration, velocity, and so on.

Answer:

A

Explanation:

this is because the law of reflection states that the angle of incidence equals to the angle of the reflection.

hope this helps, if not please report it

someone else can try it

Answer:

heterogeneous mixture has components that are not evenly distributed. This means that you can easily distinguish between the different components.

For a UV radiation with a 200 nm wavelength is mathematically given as the maximum kinetic energy, in eV, of photoelectrons ejected from the gold

K.E=1.779*10^{19}J

K.E=1.112ev

Generally, the equation for the photo electric equation  is mathematically given as

\(hc/\lambda=K.E+\phi\)

Therefore

K.E=(6.626*10^{-34}*3*10^8/2*10^{-7})-5.1*1.6*10^{-19}

K.E=1.779*10^{19}J

In conclusion, in eV, of photoelectrons ejected from the gold

K.E=1.112ev

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Answer:

Infrared thermometers employ a lens to focus the infrared light emitting from the object onto a detector known as a thermopile. The thermopile is nothing but thermocouples connected in series or parallel. When the infrared radiation falls on the thermopile surface, it gets absorbed and converts into heat.

bending your arms

good luck bro

The magnification of a lens used with a relaxed eye if its focal length is 20 cm is 0.05x.

Explanation:

Magnification is defined as the ratio of the height of the image produced by a lens to the height of the object. It is given by the formula Magnification = height of the image/height of the object Magnification can be used to measure how much larger or smaller an object appears to be when viewed through a lens.

Magnification is given by the formula Magnification = height of the image/height of the objectIn this case, we are given the focal length of the lens, which is 20 cm. We can use this to find the magnification of the lens. The formula for magnification in terms of focal length is Magnification = - di / do Where, di is the image distance, and do is the object distance. If the lens is being used with a relaxed eye, then the object distance is infinite.

Therefore, we can simplify the formula to Magnification = - di/infinity = 0 Now, we know that the magnification of the lens is 0. We can use this information to find the height of the image produced by the lens.

The height of the image is given by the formula Height of the image = magnification x height of the object In this case, the height of the object is not given, but it does not matter since the magnification is zero. Therefore, the height of the image is also zero.

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Answer:

125 V

Explanation:

Given,

Power ( P ) = 500 W

Current ( I ) = 4 A

To fine : -

Potential difference ( V ) = ?

Formula : -

P = V I

V = P / I

= 500 / 4

V = 125 V

Therefore,

the potential difference across the ends of the heating element is 125 V.

The angle at which the roadway should be banked depends on the speed of the car, the radius of the curve, and the frictional force. So, the roadway should be banked at an angle of approximately 25.4 degrees

In this case, we know the speed of the car (15 m/s) and the radius of the curve (50 m), but we are told that the frictional force is zero due to icy conditions.

In the absence of friction, the only force that keeps the car moving in a circular path is the normal force exerted by the road on the car. This force acts perpendicular to the road surface and is proportional to the weight of the car. To keep the car moving in a circular path, the normal force must be directed toward the center of the curve. This can be achieved by banking the road.

The angle at which the road should be banked can be calculated using the following formula:

tan θ = v^2 / (r * g)

where θ is the angle of banking, v is the speed of the car, r is the radius of the curve, and g is the acceleration due to gravity (9.8 m/s^2).

Plugging in the given values, we get:

tan θ = (15 m/s)^2 / (50 m * 9.8 m/s^2)
tan θ = 0.459
θ = tan^-1 (0.459)
θ = 25.4 degrees

Therefore, the roadway should be banked at an angle of approximately 25.4 degrees to allow cars to negotiate the curve at 15 m/s even if the roadway is icy and the frictional force is zero.

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Answer: You could tell if you made an error in your calculations by repeating the steps.

Speed of light is the fastest/maximum in vacuum which is equal to 3 × 10^8 m/s, therefore speed of light through any material equal to 4 × 10^8 m/s is physically and theoretically impossible and therefore incorrect.

Explanation:

Answer:

Explanation:

Discussion

The ones that are certain are

If you have a normal, and the player slides into 2nd, and stops (which he must before he is tagged), then there must be friction involved. There must be gravity, or he would keep going up.

I don't think there is tension. There might be some Air Resistance, but that force is very tiny. Don't be surprised if you answer includes Air Resistance, but I won't try it to begin with.

Pressure decreases linearly with height. In fact, there is a faster  decrease of pressure with height near the Earth's surface than at higher altitudes (option c).

1. Pressure decreases with height because the weight of the air above decreases as we move higher in the atmosphere.

2. Near the Earth's surface, the decrease in pressure is more rapid compared to higher altitudes.

3. This rapid decrease is due to the fact that the atmosphere is denser near the surface, and there is a larger mass of air pressing down from above.

4. As we ascend to higher altitudes, the density of the atmosphere decreases, and there is less air pressing down from above.

5. Consequently, the decrease in pressure becomes slower at higher altitudes because there is less mass of air to exert a force on a given area.

6. The relationship between pressure and height near the Earth's surface is approximately linear, meaning that pressure decreases at a constant rate as we move upwards.

7. However, at higher altitudes, the relationship between pressure and height becomes logarithmic, indicating a slower rate of decrease.

8. Therefore, the correct answer is C) linearly, faster, indicating that pressure decreases linearly with height near the Earth's surface at a faster rate than it does at higher altitudes.

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Im pretty sure the answer is A)

When the low temperature reservoir has its temperature lowered in an ideal heat engine, the engine efficiency increases. The correct answer is (D).

Here's a step-by-step explanation:

1. The efficiency of a heat engine is determined by the temperatures of the high and low temperature reservoirs. The formula for the efficiency of an ideal heat engine, based on the Carnot cycle, is given by:

Efficiency = 1 - (T_low / T_high)

where T_low is the temperature of the low temperature reservoir and T_high is the temperature of the high temperature reservoir.

2. When the temperature of the low temperature reservoir (T_low) is lowered, the ratio (T_low / T_high) becomes smaller.

3. As a result, the value inside the parentheses (1 - ratio) increases, which means the overall efficiency of the heat engine increases.

So, with the temperature of the low temperature reservoir lowered and no other changes made, (D) the efficiency of the ideal heat engine increases.

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Using two circular, flat, clear plastic circles that he attaches at the edges, Camden creates a model of a double convex lens that appears thicker in the center and thinner at the edges.

Bi-convex (Double-convex) lenses focus parallel light rays to a single point similarly to plano-convex lenses because they have the same radius of curvature on both sides of the lens. As a general rule, bi-convex lenses work best with conjugate ratios between 5:1 and 1:5.

By twice refractively (bending) the light rays from a distant object, a double convex lens, also known as a converging lens, concentrates the diverging, or blurred, light rays.

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The reaction of oxygen with another element commonly forms binary compounds known as oxides. This reaction itself is called oxidation.

Combustion is an exothermic (heat release) oxidation-reduction (oxygenation) chemical reaction at high temperature between a fuel and an oxidant (usually oxygen in the atmosphere), which oxidizes into a mixture called smoke. , often gaseous products are produced. A combustion reaction is a combination of a compound and oxygen to produce oxides of other elements as products (but nitrogen atoms react to form N2). A decomposition reaction is a reaction in which a compound breaks down into two or more simpler substances. The general form of the decomposition reaction is

AB→A+B. Most decomposition reactions require energy input in the form of heat, light, or electricity.

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An alcohol-related motor vehicle crash in the U.S. kills one person every 3.5 hours. This statement is FALSE.

An alcohol-related motor vehicle crash in the U.S. does not necessarily kill one person every 3.5 hours. The frequency and impact of alcohol-related motor vehicle crashes can vary, and the number of fatalities can change over time and across different regions. It is important to consider up-to-date statistical data and specific circumstances to accurately assess the frequency of alcohol-related motor vehicle crash fatalities.

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I'm pretty sure this poor guy could never have been accepted for astronaut training, much less a mission to the Moon.  

He weighs something like 335 pounds when he's ON THE MOON !

If he has enough fuel, and survives a trip back to Earth, he'll weigh around 9,080 Newtons here.  That's like 2,040 pounds ... durn close to a ton ! !

Answer:

Gravitational field strength:

Moon is 1.6N/kg

Earth is 9.8N/kg or 10N/kg

Moon:

Weight = mass x gravitational field

1500N = m x 1.6N/kg

÷1.6 both sides

937.5 = m

Mass of astronaut is 937.5kg

(Your mass doesn't change, no matter where you go, in space)

Earth:

Weight = mass x gravitational field

= 937.5kg x 9.8 N/kg

= 9187.5N

Or

Weight = mass x gravitational field

= 937.5kg x 10 N/kg

= 9375N

Thus, the astronaut's weight will be 9187.5N or 9375N on Earth.

Hope this helps!

The frequency of the G allele in the population is 0.4, the correct option is B. 0.4.

The frequency of beetles with glabrous elytra in a population of ground beetles is 0.36. The frequency of the G allele is to be calculated, assuming that the population is in Hardy-Weinberg equilibrium.

What is Hardy-Weinberg equilibrium? The Hardy-Weinberg equilibrium is a model that describes the genetic makeup of a non-evolving population.

This model postulates that the genetic variation in a population remains constant from generation to generation in the absence of disturbing influences such as mutation, migration, or natural selection.

According to the Hardy-Weinberg equilibrium, the frequency of alleles and genotypes remains constant if certain conditions are met.

The Hardy-Weinberg equilibrium is represented by the following equation:p2 + 2pq + q2 = 1 Where:p2 = frequency of homozygous individuals (GG)2pq = frequency of heterozygous individuals (Gg)q2 = frequency of homozygous recessive individuals (gg)p + q = 1Now let's move on to the calculation of the frequency of the G allele.

The frequency of individuals with the gg genotype can be obtained from the following equation:q2 = 0.36q2 = 0.36^(1/2)q = 0.6

The sum of the frequency of all genotypes must be equal to 1, which can be used to calculate the frequency of the G allele:p + q = 1p = 1 - qp = 1 - 0.6p = 0.4The frequency of the G allele in the population is 0.4.Therefore, the correct option is B. 0.4.

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Therefore, the cart will be going 90 m/s at 30 sec This problem can be solved using kinematic equations. There are two ways to approach this problem

The main answer method is a shortcut, while the  method involves the use of formulas. method is as follows The impulse J equals the change in momentum p. The formula is as follows J = pSubstitute the values into the formula

J = p30 N × 60 s = p1,800

N·s = p

The change in momentum is equal to the mass times the velocity difference.

The problem can be solved using kinematic equations. The first step is to find the acceleration of the cart. The formula is as follows F = maSolve for a:a = F/mSubstitute the values into the formula:

a = 30 N/10 kg = 3 m/s²

The second step is to use the following formula to find the final velocity v = u + at The initial velocity u is 0 m/s because the cart is at rest

.v = u + at

Substitute the values into the formula:

v = 0 m/s + (3 m/s²)(30 s)v = 90 m/s

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Answer:

Objective(s): In your own words, what was the purpose of this lab?

The purpose of this lab is to get us familiar with the physical properties of different types of materials that are used for building.

Hypothesis: In this section, include the if/then statements you developed during your lab activity. These statements reflect your predicted outcomes for the experiment.

If we use clay brick to build the roof of the house, then the temperature inside the house will remain cooler.

If we use wood to build the walls and floors of the house, then the temperature inside the house will remain cooler.

If we use nickel to bring electricity into the home, then it will allow electricity to flow into the home at a faster rate.

If we use iron to construct the latches on the windows and doors, then the magnetism will keep the latches secure.

Procedure: The materials and procedures are listed in your virtual lab. You do not need to repeat them here. However, you should note if you experienced any errors or other factors that might affect your outcome.

Using the summary questions, clearly define the dependent and independent variables of the experiment.

Data: Record the results of each of your physical property tests in the table below.

Wood _  3/10 _0 _0.12 W/(m·K)  _0 S/m _ 4 g/cm3

Clay Brick _ 2/10 _1 _0.6 W/(m·K) _ 0 S/m _ 5.88235 g/cm3

Iron _ 4/10 _10 _80 W/(m·K)  _1x107 S/m  _9.09091 g/cm3

Aluminum_ 7/10 _ 0  _235 W/(m·K) _ 3.8x107 S/m _ 6.66667 g/cm3

Copper _ 6/10 _0 _400 W/(m·K)  _3.8x107 S/m  _9.52381 g/cm3

Nickel _ 5/10 _7 _ 91 W/(m·K)  _1.4x107 S/m  _9.43396 g/cm3

Conclusion: Your conclusion will include a summary of the lab results and an interpretation of the results. Please answer all questions in complete sentences using your own words.

In this, I investigated the effect that different types of physical properties had on six different materials. I also investigated which materials would be the best to build a house.  

     2. What building material did you use to build your house? Did your results support or fail to support your hypotheses?

For the roof of my house, I used clay bricks. For the walls and floors of the house, I used wood. To bring electricity into the home I used nickel. To construct the latches on the windows and doors, I used iron. My results supported my hypotheses because clay bricks and wood had the lowest thermal conductivity rates, nickel had the second highest electricity conductivity rate, and iron had the highest magnetism rate.    

      3. What were the densities of the materials you chose for the walls and floor for the home in Tiny World? Why do you think a building material's density is important when building homes or architectural structures?

The density of the material I chose for the walls and floors for the home in Tiny World was 4 g/cm3 (Wood). I think a buildings material density is important when building homes or architectural structures because in order for that structure to stay stable the materials that are used must be dense. If the materials are not dense, the structure would most likely collapse if it is placed under too much pressure.

      4. Why wouldn’t you choose wood or aluminum for the latches on your house?

I wouldn’t choose wood or aluminum for the latches on my house because neither of those two materials are magnetic.

    5. Which material has the highest thermal conductivity? Which material has the highest electrical conductivity? Explain why thermal and electrical conductivity is so high with this material.

Copper has the highest thermal conductivity. Aluminum and copper have the highest electrical conductivity. Thermal conductivity is high in copper because copper is a very thin type of material, and this allows heat to pass through it easily. Electric Conductivity is high in both aluminum and copper because they are both a very thin type of metal and because they are both so thin, electricity will pass through them quickly.  

I'm sorry if any of the answers are wrong, this was just assigned to me and my teacher hasn't graded it yet.

The distance from the axis of the force applied is 2.05 m.

The distance from the axis of the force applied is calculated as follows;

The formula for torque;

τ = Fr

where;

Another formula for torque is given as;

τ = Iα

where;

τ = (mr²)α

τ = (25 kg x (0.925 m)²) x (1.84 rad/s²)

τ = 39.36 Nm

The distance is calculated as;

r = τ/F

r = ( 39.36 Nm ) / (19.2 N)

r = 2.05 m

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