An engine absorbs 1809 J from a hot reservoir and expels 982 J to a cold reservoir in each cycle. What is the engine's efficiency? Answer with an efficiency in decimal form.

How much work is done in each cycle? Answer in units of J.

What is the mechanical power output of the engine if each cycle lasts for 0.159 s? Answer in units of kW.​

Answers

Answer 1

The efficiency of an engine is 0.457  and the work done in each cycle is 827 J and the mechanical power is 5.2×10³ W.

The efficiency of a heat engine is calculated between the heat and cold reservoir.

Efficiency,η = 1 - (T(cold) / T(hot))

T(hot) = 1809 J

T(cold) =  982 J

η = 1 - (982 J /1809 J)

  = (1809 -982) / 1809

  = 0.457

The efficiency of the engine,η = 0.457

The work done, W = (T(hot) - T(cold))

W = 1809 - 982

   = 827 J

The work done on the engine, W = 827 J.

The mechanical power, P = Work / time

P = 827 / 0.159

  = 5.201×10³W

The power of the heat engine, P = 5.201kW.

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Related Questions

Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is travelling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.

Answers

Explanation:

The question is not complete, here is the complete question

"Beatrice and the Elevator Beatrice, a middle school student, is visiting a very tall office building and notices that she feels heavier when the elevator car is traveling up and lighter when the elevator car is traveling down. After making these observations, Beatrice comes back to the building and stands on a bathroom scale that measures her weight as she travels up and down in the elevator.

1. . What question is Beatrice trying to answer?

2. What is one variable Beatrice could change in her investigation? What might she figure out if this

variable was changed"

1. Beatrice is trying to observe the influence of the elevator movement on her weight, Hence the question is "will the elevator  movement cause her weight to change"

therefore moving upward the reading on the scale will increase

Reading=mg+ma

downward

Reading will reduce

Reading=mg-ma

2. The independent variable is the acceleration due to gravity g=9.81m/s^2

while the dependent variables are

    i. The elevators acceleration

    ii. Beatrice's mass

During the swing of a frictionless pendulum, what energy form(s) remain constant?

Answers

The potential energy and the total mechanical energy of a frictionless pendulum remain constant during its swing.


In a frictionless pendulum, there are two main forms of energy: potential energy and kinetic energy. As the pendulum swings back and forth, the total mechanical energy, which is the sum of the potential and kinetic energy, remains constant.

At the highest point of the swing, when the pendulum is momentarily at rest, all of its energy is in the form of potential energy. This potential energy is gravitational in nature and is determined by the height of the pendulum bob above its lowest point.

As the pendulum descends from the highest point, the potential energy is gradually converted into kinetic energy. At the lowest point of the swing, when the pendulum is at its maximum speed, all of its energy is in the form of kinetic energy. The kinetic energy is determined by the mass of the pendulum bob and its velocity.

As the pendulum swings back upward, the kinetic energy decreases, and the potential energy increases. This continuous interchange between potential and kinetic energy repeats throughout the swing of the pendulum.

Since there is no friction in a frictionless pendulum, no energy is lost to non-conservative forces such as friction or air resistance. Therefore, the total mechanical energy of the pendulum remains constant throughout its motion. The potential energy and kinetic energy may vary at different points in the swing, but their sum remains constant.

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Why is there more pressure the deeper you go in water?

Answers

I think because water gives pressure and if u go even deeper theres more pressure

A motor car tyre contained a fixed mass of air at 27 °C. Its pressure was 220 kN m2 above atmospheric pressure. After a 60-minute drive, the air pressure rose to 250 ken m-² above atmospheric pressure. What was the new pressure of the air in the tyre, in degrees Celsius, if the volume of air remained constant? [Atmospheric pressure = 200 k N m-²] The general gas equation is P1V1 = P2V2 T1 T2​

Answers

Answer:

in this situation we have given a car note engine whose efficiency is 40%. Now it is told that it is desired to have an efficiency of 60%. Then we have to find the thing temperature force him intact temperature as we know that efficiency is given by that is neat is equal to this is one minus the lower temperature upon t higher temperature here lower temperature is the temperature of think and higher temperature is the temperature of source. So we can say that in the first case we are given the efficiency that is 40%. So this is 4100 is equal to, this is one minus deal upon, this is 500 From here we can find the value of lower 10%. This will comes out to be 300 Calvin. No, we have given that the efficiencies 60%. So we can the lower temperature remains him that is 300 Calvin. And we have to find the higher temperature. So we can say that this is 60 upon 100 is equal to this is one minus 300 upon th from here we can find the value of higher temperatures. So this is 300 upon th is equal to disease 40 by 100. Or we can say yes, you'll come out to be 7 50 Calvin. So this is the temperature and this is our answer for this. Given to shin. So we can say for that option, B is the correct choice. Thank you

Explanation:

in trial 1 of an experiment, a cart moves with speed v0 on a frictionless, horizontal track and collides elastically with another cart that is initially at rest. in trial 2, the setup is identical except that the carts stick together during the collision. how does the speed of the two-cart system’s center of mass change, if at all, during the collision in each trial?

Answers

In trial 1, the speed of the center of mass does not change, while in trial 2, the speed of the center of mass decreases.

In trial 1, the carts collide elastically, which means that the total kinetic energy of the system is conserved during the collision. The two carts will bounce off each other with the same kinetic energy that they had before the collision. Since the center of mass is a point of reference for the total kinetic energy of a system, and its speed is related to its kinetic energy, the speed of the center of mass does not change during the collision. The final kinetic energy of the two-cart system after the collision is the same as the initial kinetic energy. The two carts will move away from each other with the same speed they had before the collision.

In trial 2, the collision is inelastic, which means that some of the kinetic energy is converted into internal energy, this causes the total kinetic energy of the two-cart system to decrease. Since the center of mass is a point of reference for the total kinetic energy of a system, and speed is related to kinetic energy, the decrease in total kinetic energy causes a decrease in the speed of the center of mass. As the carts stick together after the collision, the final speed of the two-cart system is lower than the initial speed. The final speed of the two-cart system after the collision is slower than the initial speed of the first cart.

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Your question seems to be incomplete, but I assume the question was:

"In trial 1 of an experiment, a cart moves with speed v0 on a frictionless, horizontal track and collides elastically with another cart that is initially at rest. In trial 2, the setup is identical except that the carts stick together during the collision. How does the speed of the two-cart system's center of mass change, if at all, during the collision in each trial?"

Suppose you inflate your car tires to 38 psi on a 25 ∘C day.
Later, the temperature drops to 0∘C. What is the pressure in your tires now?

Answers

The pressure in your tires would decrease due to the decrease in temperature. The relationship between temperature and pressure is known as the ideal gas law.

which states that pressure and temperature are directly proportional to each other. As the temperature drops, so does the pressure in the tires. The ideal gas law formula is P1/T1 = P2/T2, where P1 is the initial pressure, T1 is the initial temperature, P2 is the final pressure, and T2 is the final temperature.


Using this formula and assuming that the volume of the tires remains constant, we can calculate the final pressure in the tires. P1 is 38 psi, T1 is 25°C + 273.15 (to convert to Kelvin) = 298.15 K, T2 is 0°C + 273.15 = 273.15 K. Plugging in the values, we get P2 = (38 psi * 273.15 K) / 298.15 K = 34.9 psi. Therefore, the pressure in your tires would be approximately 34.9 psi when the temperature drops to 0°C.

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Which of the following is an example of a non-contact force? CHOOSE ALL THAT APPLY.

A duck floating on water

The moon orbiting the earth

Your Chromebook sitting on the desk

Pushing a child in a swing at the playground

Gravity pulls skydiver down towards the surface of the earth from an airplane

Answers

The moon orbiting the earth and Gravity pulls skydiver down towards the surface of the earth from an airplane are examples of a non-contact force

Non-contact forces are forces that act between two objects that are not physically touching each other.

That means that there is no contact but there exist force between them .The moon orbiting the earth due to gravitational force between both the bodies , this is a non contact force . Because moon is in not in contact with the earth , still both the bodies are exerting force on each other

Also Gravity pulls skydiver down towards the surface of the earth from an airplane is also an example of non contact force because there is no contact between skydiver and earth , still due to earth's gravitational force , it is been attracted towards the ground

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The density of water is 1g/cm³ . If an object with a mass of 100g has a weight of 1 N on Earth, calculate the volume of water displaced by the object​

Answers

If an object with a mass of 100g has a weight of 1 N on Earth, the volume of water displaced by the object​ is 100 cm³.

To find the volume of water displaced by the object, take the formula:

Volume = Mass ÷ Density

According to question:

Mass of the object = 100g

Density of water = 1g/cm³

Change the mass to kilograms:

Mass = 100g ÷ 1000 = 0.1kg

By using the formula, it is possible to find the volume of water displaced:

Volume = 0.1kg / 1g/cm³

= 0.1kg / 1g/cm³ × 1000g/1kg × 1cm³/1g

= 0.1 × 1000 cm³

= 100 cm³

Thus, the volume of water displaced by the object​ is 100 cm³.

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A cart of mass 10 kg is rolling on a level floor at 5 m/s. A 4 kg mass dropped from rest lands in the cart.


what is the momentum of the system before the object drops?


what is the momentum of the system after the object drops?


what is the final speed of the cart and the mass?

Answers

The momentum of the system before the object drops is 50 kg m/s.

The momentum of the system after the object drops is 50 kg m/s.

The final speed of the cart and the mass is 3.57 m/s.

We know that, momentum is the product of mass and velocity of the system.

Mathematically,

P = m* v

where,

m is the mass

v is the velocity

Given that,

Mass of the cart m₁ = 10 kg

Velocity of the cart before the object drops v₁ = 5 m/s

Mass of the object dropped m₂ = 4 kg

Velocity of the cart after the object drops v₂ = ?

According to the principle of conservation of linear momentum,

Total momentum of the system before the object drops = total momentum of the system after the object drops

So, mathematically,

m₁* v₁ = (m₁ + m₂)* v₂

10 * 5 = (10 + 4) v₂

14 v₂ = 50

v₂ = 3.57 m/s

Thus, Final speed of the cart = 3.57 m/s

Final mass of the cart = 10 + 4 = 14 kg

The momentum of the system before the object drops = m₁* v₁ = 10* 5 = 50 kg m/s

The momentum of the system after the object drops = (m₁ + m₂)* v₂ = 14* 3.57 = 49.98 ≈ 50 kg m/s

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If a 0.5 kg pair of shoes weighs 0.3 N on Pluto, what is the strength of gravity on Pluto?

Answers

Answer:

0.2

Explanation:

0.5 - 0.3 = 0.2

A race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the
same track is made in 26.0 s.
(a) What is the average velocity of the car in m/s for the first leg of the run?
m/s
(b) What is the average velocity (in m/s) for the total trip?
m/s

Answers

The average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s

What is Speed and Velocity ?

Speed is the distance travelled per time taken. The S.I unit is m/s. The average speed is the ratio of the total distance travelled to the to time taken. While velocity is the distance travelled in a specific direction per time taken

Given that a race car traveling northward on a straight, level track at a constant speed travels 0.760 km in 21.0 s. The return trip over the same track is made in 26.0 s.

(a) The average velocity of the car in m/s for the first leg of the run will be

Velocity = (0.760 x 1000)/ 21

Velocity = 760 / 21

Velocity = 36.2 m/s

(b) The average velocity (in m/s) for the total trip will be

36.2 - (0.760 x 1000)/ 26

36.2 - (760) / 26

36.2 - 29.2

7 m/s

Therefore, the average velocity of the car in m/s for the first leg is 36.2 m/s and the average velocity (in m/s) for the total trip is 7 m/s

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In a cylinder, 1.20mol of an ideal monatomic gas, initially at 3.60×105Pa and 300K, expands until its volume triples.Part ACompute the work done by the gas if the expansion is isothermal.Part BCompute the work done by the gas if the expansion is adiabatic.Part CCompute the work done by the gas if the expansion is isobaric.

Answers

If the expansion is isobaric, the work performed by the gas is 6* 10³ J. An perfect monatomic gas with a starting pressure of 3.60* 10⁵ Pa and a temperature of 300 K expands in a cylinder until its volume triples.

The maximum amount of work that the gas can do in absolute terms is during isobaric expansion. A thermodynamic process known as an isobaric process occurs at a fixed pressure. Greek words "iso" and "baros," which both signify equal pressure, were used to create the phrase "isobaric." One-atom gas The term "monatomic" in physics and chemistry refers to a single atom and is a mixture of the terms "mono" and "atomic." Usually used in reference to gases, a monatomic gas is one in which atoms are not physically connected to one another.

W = P(v2 - v1)=2pv1=2(N*R*T)=6* 10³ J

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How much heat energy does it take to boil 2.35 kg of water at 100oC completely to steam at 100oC ?  Show Your WORK!   This is Laten Heat

Answers

ANSWER

Q = 5303.95 kJ

EXPLANATION

We are looking for the energy needed to evaporate 2.35kg of water. Since the water is already at evaporation temperature, which is 100°C, we just have to use latent heat. Also, we just want the steam to be at 100°C, so we don't need to find the energy to change its temperature.

The energy needed to evaporate water of mass m is:

\(Q=m\cdot L\)

L is the latent heat of the material, in this case water. There are two latent heats, one of fusion and one of vaporization. We have to use the second one, which for water is approximately 2257 kJ/kg

Therefore, to boil 2.35 kg of water at 100°C to steam at 100°C we need:

\(Q=2.35kg\cdot2257\frac{kJ}{\operatorname{kg}}=5303.95kJ\)

If an object is accelerating toward a point, then it must be getting closer and closer to that point. True or false?.

Answers

False, If an object is accelerating toward a point, then it must not be getting closer and closer to that point.

What do you mean by acceleration?

Acceleration is the rate at which speed and direction of velocity vary over time. A point or object going straight ahead is accelerated when it accelerates or decelerates. An object has positive acceleration if it is accelerating and traveling in the right direction. Positive acceleration was demonstrated in the first example by the speeding car. The acceleration is occurring in the same direction as the car's motion, which is forward and speeding up. The meter per second squared (m s2) is the unit of acceleration used in the SI system.

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Three circuit elements with resistances R1, R2, and R3 are connected in parallel to a voltage source. Which circuit element will use the most power if R1 < R2 < R3?
(1 point)
A. The circuit element with resistance R2 will use the most power.
B. The circuit element with resistance R3 will use the most power.
C. Because they are in parallel, all three elements will use the same power.
D. The circuit element with resistance R1 will use the most power.

Answers

Answer:

D. The circuit element with resistance R1 will use the most power.

Explanation:

In a parallel circuit, each circuit element has the same voltage across it. Therefore, the power used by each circuit element can be calculated using the formula P = V^2/R, where V is the voltage across the element and R is the resistance of the element.

Since R1 < R2 < R3, the resistance of R1 is the smallest of the three. This means that R1 will draw the largest current of the three elements.

Using the formula P = V^2/R, we can see that the power used by each circuit element is inversely proportional to its resistance. This means that the circuit element with the smallest resistance, R1, will use the most power, and the circuit element with the largest resistance, R3, will use the least power. Therefore, the answer is D. The circuit element with resistance R1 will use the most power.

- During a certain period, the angular position of a rotating object is given by: = − + , where  is in radian and t is in seconds. Determine the angular position, angular speed, and angular acceleration of the rotating object at = Sec.

Answers

The question is not complete. The complete question is :

During a certain period of time, the angular position of a rotating object is given by \($\theta =2t^2 +10t+5$\), where θ is in radians and t is in seconds.  Determine the angular position, angular speed, and angular acceleration of the door (a) at t = 0.00 seconds, (b) at t = 3.00 seconds.

Solution :

Given :

Displacement or angular position of the object, \($\theta =2t^2 +10t+5$\)

∴ Angular speed is   \($\omega = \frac{d \theta}{dt}$\)

                                 ω = 10 + 4t

And angular acceleration is \($\alpha = \frac{d \omega}{dt}$\)

                                              α = 4

a). At time, t = 0.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(0)^2 +10(0)+5$\)

                                               = 5 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(0)

                                     = 10 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

b). At time, t = 3.00 seconds :

   Angular displacement is \($\theta =2t^2 +10t+5$\)

                                            \($\theta =2(3)^2 +10(3)+5$\)

                                               = 53 rad

  Angular speed is  ω = 10 + 4t

                                 ω = 10 + 4(3)

                                     = 22 rad/s

Angular acceleration is α = 4 \($rad/s^2$\)

                                   

                                           

You want the pizza to be both crispy and hot. Based on what you learned about the different types of heat transfer, which appliance–the oven, stovetop, or microwave oven–will you use to reheat your lunch?

Answers

Answer:

microwave because it will heat it very well

A spring is compressed, increasing its tension. The work done compressing the spring is 1.32 J.While being compressed, the spring heats the hand of the person pushing on it by a net of 0.15 J.What is the change in the spring’s internal energy?

Answers

When a spring is compressed, its tension increases, and the potential energy stored in the spring also increases. The work done in compressing the spring is equal to the change in potential energy stored in the spring.

In this case, the work done is 1.32 J. Therefore, the change in potential energy is also 1.32 J. However, we know that the spring also heats the hand of the person pushing on it by a net of 0.15 J. This means that some of the potential energy stored in the spring is converted into thermal energy, and hence lost. This energy loss can be accounted for by the change in internal energy of the spring. Therefore, the change in the spring's internal energy is equal to the difference between the change in potential energy and the energy lost as heat. Change in internal energy = Change in potential energy - Energy lost as heat, Change in internal energy = 1.32 J - 0.15 J, Change in internal energy = 1.17 J. So, the change in the spring's internal energy is 1.17 J. To calculate the change in a compressed spring's internal energy, we need to consider the work done on the spring and the energy transferred as heat. In this case, the work done compressing the spring is 1.32 J, and the net heat transferred to the person's hand is 0.15 J.

The first law of thermodynamics states that the change in internal energy (ΔU) of a system is equal to the work done on the system (W) minus the heat transferred from the system (Q). Therefore, we can write the equation as: ΔU = W - Q. Substitute the given values into the equation: ΔU = 1.32 J - 0.15 J. ΔU = 1.17 J. The change in the spring's internal energy is 1.17 J.

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One mole of an ideal gas is confined to a container with a movable piston. The questions below refer to the processes shown on the PV diagram at right. Process I is a change from state Xto state Y at constant pressure. Process II is a change from state W to state Z at a different constant pressure. 2. Rank the temperatures of states W, X, Y, and Z. If any temperatures are equal, state that explicitly. Explain. a. xl Process l、 ly In the two processes, does the piston move inward, move outward, or not move? Explain.

b. Based on your answer to part b, state whether the following quantities are positive, negative, or zero. Explain your reasoning by referring to a force and a displacement. c. Process II i. the work done on the gas during Process I (W) ii. the work done on the gas during Process II (W d. In Process I, is the heat transfer to the gas positive, negative, or zero? Explain.

Answers

Rank temperatures of states on PV diagram and explain. Determine direction of piston movement in two processes and identify sign of work and heat transfer in one of the processes.

This question requires analysis of two processes, I and II, on a PV diagram of an ideal gas confined to a container with a movable piston. Process I is a change from state X to state Y at constant pressure, and process II is a change from state W to state Z at a different constant pressure. To rank the temperatures of states W, X, Y, and Z, we need to use the ideal gas law which states that PV = nRT, where n is the number of moles, R is the gas constant, and T is the absolute temperature. The temperature is directly proportional to the pressure and inversely proportional to the volume. Based on this, the temperatures can be ranked in the order W > X = Y > Z. In both processes, the piston moves outward, and therefore the work done is positive. In process I, the heat transfer to the gas is positive, as the volume of the gas increases, and therefore the internal energy increases.

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Which of the following vocal behaviors is a dimension of nonverbal communication?
a. tone of voice
b. rate of speech
c. loudness
d. all of these

Answers

All of the listed vocal behaviors, including tone of voice, rate of speech, and loudness, are dimensions of nonverbal communication. So, the correct answer is (d) all of these.

Nonverbal communication refers to the transmission of messages through nonverbal cues, which can include vocal elements in addition to facial expressions, body language, and gestures.

Tone of voice refers to the quality or emotional expression conveyed through the pitch, timbre, and modulation of one's voice. It can convey emotions such as anger, happiness, sadness, or excitement.

Rate of speech refers to the speed or pace at which an individual speaks. It can vary from fast to slow, and the rate of speech can communicate different meanings or affect the perception of the message being conveyed.

Loudness refers to the volume or intensity of one's voice. It can convey emotions, indicate emphasis, or influence the perception of assertiveness or authority.

These vocal behaviors, along with other nonverbal cues, play a significant role in communication, as they can provide additional meaning, context, and emotional expression to verbal messages.

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what do you mean by orbit?​

Answers

Answer:

An orbit is a regular, repeating path that one object in space takes around another one. An object in an orbit is called a satellite. A satellite can be natural, like Earth or the moon. ...Planets, comets, asteroids and other objects in the solar system orbit the sun

Explanation:

In physics, an orbit is the gravitationally curved trajectory of an object, such as the trajectory of a planet around a star or a natural satellite around a planet. Normally, orbit refers to a regularly repeating trajectory, although it may also refer to a non-repeating trajectory.

What is 3,278,000 as scientific notation?

Answers

3.278*10^6 I think. Sorry if it’s wrong.


A bowling ball of mass 10.2 kg moves in a
straight line at 3.03 m/s.
How fast must a Ping-Pong ball of mass
3.309 g move in a straight line so that the two
balls have the same momentum?
Answer in units of m/s.

Answers

Answer:

v = 9341.19 [m/s]

Explanation:

Linear momentum is defined as the product of mass by Velocity. In this way by means of the following equation, we can calculate the momentum.

\(P=m*v\)

where:

P = momentum [kg*m/s]

m = mass = 10.2[kg]

v = velocity = 3.03 [m/s]

Now replacing, we have:

\(P=10.2*3.03\\P = 30.91 [kg*m/s]\)

Now the ping-pong mass is 3.309 [g] or 0.003309 [kg]

We can clear the value for v from the equation above.

\(v = P/m\\v = 30.91/0.003309\\v = 9341.19 [m/s]\)

Just like traditional film cameras, the small opening that allows light to pass through the lens of a digital camera is called the

Answers

Answer:

dsadadas

Explanation:

dadadda

Which of the following characteristics of a single star (one that moves through space alone) is it difficult to measure directly

Answers

Determining the mass of a star that moves through space alone cannot be done through direct observation and requires indirect methods based on gravitational interactions and theoretical models.

Measuring the mass of a single star directly is challenging because it cannot be directly observed or measured. Unlike other characteristics such as luminosity, temperature, and chemical composition, which can be determined through observations and spectral analysis, measuring the mass of a star requires indirect methods.

One approach to estimating a star's mass is through studying its gravitational interactions with other celestial objects. This involves observing the motion of the star within a binary system or its effects on nearby objects. By measuring the orbital characteristics and applying Kepler's laws of motion, scientists can infer the mass of the star based on its gravitational influence.

Another method is through theoretical models that incorporate observable properties of the star, such as its luminosity and temperature, and compare them with stellar evolutionary tracks. These models provide estimates of the star's mass based on the understanding of stellar physics and evolutionary processes.

However, both these methods have inherent uncertainties and limitations, making the direct measurement of a single star's mass a challenging task in astrophysics.

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A wooden beam is 6.50 m long and weighs 325 N. It rests on two supports that are 3.00 m apart. Jane weighs 575 N. She stands on the beam in the center and then walks toward one end. How close to the end can she come before the beam begins to tip?

Answers

Suki can go 0.854 meters to the end before the beam starts to tilt.

Beam length: L = 6.5 m

Beam weight: W b = 336 N

Suki's weight is W s = 590 N.

Suki stands in the middle of the steel beam and moves toward the end. Since the beam is supported by two posts that are spaced three meters apart, the distance she may go before the beam starts to lean is determined by how far she moves from the left support.

Thus;

according to formula

Wb × (3/2) = (Ws × x)

where:

Wb= Beam weight

Ws= Suki's weight

Adding the necessary values results in;

336 × 1.5 = 590 × x

x = (336 × 1.5)/590

x = 0.854 m

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A force of 100 n is acting vertically on a body. find the horizontal component f x

Answers

Answer:

If there is no horizontal component to the force then it is just 0N

Explanation:

How many digits are in front of the decimal in scientific notation?



0


2


1


3

Answers

Answer:

1

Explanation:

How many digits are in front of the decimal in scientific notation?

what is angle of dip?

Answers

Answer:

The angle of dip is called the magnetic dip.

Explanation:

It is defined as the angle which is made by the earth's magnetic field lines with the horizontal. When the component that is horizontal and the vertical component of the earth's magnetic field are equal the angle of dip is equal to 45°.

Answer: Angle of dip is also known as the magnetic dip and is defined as the angle that is made by the earth’s magnetic field lines with the horizontal.

The angle of dip varies from point to point by providing the information related to the movement of the earth’s magnetic field. The angle of dip is said to be positive when the magnetic field points downwards. When the magnetic field points upwards, the angle of dip is said to be negative.

The angle of dip is 0° when the dip needle rests horizontally while the angle of dip is 90° when the dip needle rests vertically.

When the horizontal component and the vertical component of the earth’s magnetic field are equal, the angle of dip is equal to 45°.

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Why is velocity proportial to pressure?​

Answers

Answer:

Pressure and velocity are inversely proportional to each other because if pressure increase, the velocity decrease to keep the algebraic sum of potential energy, kinetic energy and pressure constant.

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