An engineer is building a device to open and close a door. He's using a 48V power supply and needs 3A present at the door motor to open it properly. What combination of resistors should he use?
Question 10 options:

A)

Two 6 ohms and a 10 ohm

B)

Four 8 ohms and two 4 ohms

C)

Four 2 ohms

D)

Three 8 ohms

Answer:

what am i suppose to answer o.o

Explanation:

Answer:

None of them: the direction of the pressure fluctuations is parallel to the direction of motion of the wave

Explanation:

The maximum height achieved by the ball is 51.03 meters, and the position of the ball after 4 seconds is 240 meters.

When an item is moving, its velocity indicates how quickly its location is changing as seen from a specific point of view and as measured by a specific unit of time.

If a point travels a specific distance along its path in a predetermined amount of time, its average speed throughout that time is equal to the traveled distance divided by the travel time. For instance, a train traveling 100 km in two hours is moving at an average speed of 50 km/h.

Given:

The initial velocity, u = 40 m/s,

The projected angle, a = 53°,

Calculate the maximum height as shown below,

Maximum height = u²sin²a/2g

Maximum height = 40² × sin²53 / 2 × 10

Maximum height = 1600 × 0.64 / 20

Maximum height =1020.5 / 20

Maximum height = 51.03 meters.

Calculate the position of the ball after 4 sec as shown below,

Position = 40 × 4 + 1 / 2 × 10 × 4²

Position = 160 + 5 × 16

Position = 160 + 80

Position = 240 meters

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We are asked to determine the intensity of 80.9 dB of a sound wave. To do that we will use the following formula:

Where:

The reference value is the following:

Substituting the values:

Solving the operation we get:

Therefore, the intensity is 1.2 x 10 ^-4 W/m^2.

The average value for g is 3.97%. The average of the column is found by dividing the sum of entries in column with the number of entries in column. The average deviation and the results are stated below:

Gravitational acceleration is the acceleration that an object experiences as a result of the gravitational field. It has the SI unit m/s². It is hence the vector quantity since it has both magnitude and direction. g is a unit used to measure gravitational acceleration. 9.8 m/s² is the standard value of g at sea level on the surface of the earth.

Trial         t(s)              g(m/s²)             d

1             0.3205           9.74               0.31

2            0.3255           9.44               0.02

3            0.3234            9.56               0.14

4            0.3345            8.94               0.48

5            0.3256            9.43               0.01

Column Average          9.42               0.19

% Error of average g    3.97

The average of the column is found using :

Average of column = sum of entries in column ÷ number of entries in column

Average of g = \(\frac{9.74+9.44+9.56+8.94+9.43}{5}=\frac{47.11}{5}= 9.42\;m/s^2\)

Average of d = \(\frac{0.31+0.02+0.14+0.48+0.01}{5} =\frac{0.96}{5}= 0.19\;m/s^2\\\)

% error= \(\frac{Actual\;value-Measured\;value}{Actual\;value}\times100\%\)

% error = (9.81 - 9.42) / 9.81  x 100%

% error = 0.39 / 9.81 x 100%

% error = 3.97%

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The complete question is:

Using the times recorded and the distance of your drop y, determine the acceleration due to gravity, g for each trial. Calculate the average of the five trial values of g. Using your average value for g, calculate the percent error of your measurement (Accepted value: g = 9.81 m/s2). Record these results in Data Table

Using the average value of g, calculate the deviation for each trial using the equation: d= absolute value of (average g - g) where g is the average value of g. Calculate the average deviation and record your results in Data Table 1, that is attached below.

Answer:

Photovoltaic detection is a technique that converts light into electrical energy. It is a process that involves the use of a photovoltaic cell, which is made up of semiconductor materials, to generate an electric current when exposed to light.

The photovoltaic cell absorbs the photons of light, which then knock electrons out of their orbits, creating a flow of electricity. The amount of electricity produced is proportional to the intensity of the light. The photovoltaic cell is commonly used in solar panels to generate electricity from sunlight. The efficiency of the photovoltaic cell is dependent on several factors, including the type of semiconductor material used, the purity of the material, and the thickness of the cell.

The photovoltaic cell has many applications, including in solar power generation, telecommunications, and remote sensing. The technique of photovoltaic detection is an important area of research, as it has the potential to provide a clean and renewable source of energy that can help mitigate climate change.

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The horizontal force applied to the lower block is approximately 1,420.85 Newtons

The known parameters are;

The mass of the block, m₁ = 400 kg, weight, W₁ = 3,924 N

The mass of the block resting on the first block, m₂ = 100 kg, weight, W₂ = 981 N

The length of the string attached to the block, W₂, l = 6 m

The horizontal distance from the point of attachment of the second block to the block W₂, x = 5 m

The coefficient of friction between the surfaces, μ = 0.25

Let T represent the tension in the string

The upward force on W₂ due to the string = T × sin(θ)

The normal force of W₁ on W₂, N₂ = W₂ - T × sin(θ)

The tension in the string, T = N₂ × μ × cos(θ)

∴ T = (W₂ - T × sin(θ)) × μ × cos(θ)

sin(θ) = √(6² - 5²)/6

cos(θ) = 5/6

∴ T = (981 - T × √(6² - 5²)/6) × 0.25 × 5/6

Solving, we get;

T ≈ 183.27 N

The normal reaction on W₂, N₂ = T/(μ × cos(θ))

∴ N₂ = 183.27/(0.25 × 5/6) = 879.7

N₂ ≈ 879.7 N

The friction force, \(F_{f2}\) = N₂ × μ

∴ \(F_{f2}\) = 879.7 N × 0.25 = 219.925 N

The total normal reaction on the ground, \(\mathbf{N_T}\) = W₁ + N₂

\(N_T\) = 3,924 N + 879.7 N = 4,803.7 N

The friction force, on the ground \(\mathbf{F_T}\) = \(\mathbf{N_T}\) × μ

∴  \(F_T\) = 4,803.7 N × 0.25 = 1,200.925 N

The horizontal force applied to the lower block, P = \(\mathbf{F_T}\) + \(\mathbf{F_{f2}}\)

Therefore;

P = 1,200.925 N + 219.925 N = 1,420.85 N

The horizontal force applied to the lower block, P ≈ 1,420.85 N

The terminal velocity of gold sphere is 39.2 cm/s

Terminal velocity is the maximum velocity attainable for an object as it falls through a fluid.

The terminal velocity of the gold sphere is given by v = 2gr²(ρ - σ)/9η where

So, susbtituting the values of the variables into the equation, we have that

v = 2gr²(ρ - σ)/9η

v = 2 × 9.8m/s²× (10⁻² cm)²(19 g/cm³ - 1.0 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 9.8 m/s² × 10⁻⁴ cm² × (18 g/cm³)/(9 × 10⁻³ Pa-s)

v = 2 × 980 cm/s² × 10⁻⁴ cm² × 2 g/cm³/(1 × 10⁻³ Pa-s)

v = 3920 g/s² × 10⁻⁴/(1 × 10⁻³ Pa-s)

v = 392 cm/s × 10³ × 10⁻⁴

v = 392 × 10⁻¹ cm/s

v = 39.2 cm/s

So, the terminal velocity is 39.2 cm/s

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As the crew is adding one mile to the road each day, so the length of the road after 27 days is 79 miles.

A collection of skilled workers, including a supervisor, a construction manager, a distinct maintenance staff, and a team of specialist labourers, make up an efficient construction crew. Employees must actively participate in the prevention of hazardous situations as they have a significant role to play.

A road construction crew assists with new road and sidewalk creation, repairs to or improvements to current roads, and the burying of wires underneath the local roads. They are also known as vehicle restraining operators and highway maintenance operators.

The question is incomplete, find the complete question here

A construction crew is lengthening a road that originally measured 52 miles. The crew is adding one mile to the road each day. The length, L (in miles), after d days of construction is given by the following function. L = 52 + d. what is the length of the road after 27 days?

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The locations where the riders feel less than their normal weight are Location A, Location C and Location D.

The given parameters;

The normal weight of the riders is calculated by applying Newton's second law of motion as follows;

W = mg

W = 9.8m

The apparent weight of the riders for the upward acceleration is calculated  as follows;

\(R = m(g + a)\)

The apparent weight of the riders for the downward acceleration is calculated  as follows;

\(R = m(g - a)\)

The apparent weight of the riders at location A is calculated as follows;

\(R_ A = m(9.8 - 10)\\\\R_ A = -0.2 m\)

The apparent weight of the riders at location B is calculated as follows;

\(R_B = m(9.8 + 2)\\\\R_B = 11.8 m\)

The apparent weight of the riders at location C is calculated as follows;

\(R_C = m(9.8 - 6)\\\\R_C = 3.8 m\)

The apparent weight of the riders at location D is calculated as follows;

\(R_D = m(9.8 - 12)\\\\R_D = -2.2 m\)

The apparent weight of the riders at location E is calculated as follows;

\(R_E = m(9.8 + 6)\\\\R_E = 15.8 m\)

Thus, the locations where the riders feel less than their normal weight are;

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The kinetic energy of a projectile of mass 8.30 g traveling with a speed of 1.10 km/s in the unit kiloJoules will be (a) 5.0215 KJ (b) 1.2553 KJ (c) 45.1935 KJ.

In the given question, following quantities of the projectile are given:

mass of the projectile, m= 8.30 g= 0.0083 kg

speed of the projectile, v= 1.10 km/s= 1100m/s

Since, according the Newton's law of motion, the formula for Kinetic Energy of an object is:

K.E.= 1/2 x mass of the object x (speed of the object)² Joules

K.E.= 1/2mv²

So,

(a) K.E.= 1/2 x 0.0083 kg x (1100 m/s)² = 5021.5 Joules = 5.0215 KJ.

(b) Since speed is reduced by a factor of 2, then,

new speed= 1100 m/s ÷2= 550 m/s

Now, K.E.= 1/2 x 0.0083 kg x (550 m/s)²= 1255.375 Joules= 1.2553 KJ.

(c) Since speed is increased by a factor of 3, then,

new speed= 1100 m/s x 3= 3300 m/s

Now, K.E.= 1/2 x 0.0083 kg x (3300 m/s)²= 45193.5 Joules= 45.1935 KJ.

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Answer:

4 ohms

Explanation:

R = PL/A

P is resistivity

L is length and is halved

A cross sectional area, the same so

R = P(L/2)/A = 4

The resistance of the wire when the length is half will be 4 ohms. Resistance is directly propotional to the length in the given condition,

Resistance is a type of opposition force due to which the flow of current is reduced in the material or wire. Resistance is the enemy of the flow of current.

The given data in the problem is;

The resistance in a piece of wire is R = 8 ohms.

D₁=D₂

T₁=T₂

L₂=0.5L₁

The formulas for the resistance in the wire will be;

\(\rm R= \frac{\rho L}{A} \\\\ \rm R= \frac{\rho L}{\frac{\pi}{4D^2} }\)

If all the given values are constant the resistance is inversly propotional to the length.

If the length is half the value of the resistance is also half;

\(\rm R'=\frac{R}{2} \\\\ \rm R'=\frac{8}{2} \\\\ \rm R'=4 \ ohm\)

Hence the resistance of the wire when the length is half will be 4 ohms.

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The area in square meters and the uncertainty is 9768 ± 18.33 m².

To calculate the area of the field, we need to multiply the length by the width:

Area = length x width

Using the values given, we have:

Length = 132 ± 2.2 m

Width = 74 ± 1.6 m

To include the uncertainty in the area calculation, we need to use error propagation. The formula for error propagation in multiplication is:

δz = z * √((δx/x)^2 + (δy/y)^2)

where δz is the uncertainty in the result z, δx and δy are the uncertainties in x and y respectively, and x and y are the measured values.

Using this formula, we can calculate the uncertainty in the area as:

δA = A * √((δlength/length)^2 + (δwidth/width)^2)

Substituting the values, we get:

δA = (132 x 74) * √((2.2/132)^2 + (1.6/74)^2)

δA ≈ 18.33

Therefore, the area of the field is:

A = length x width

A = 132 m x 74 m

A ≈ 9768 m²

And the uncertainty in the area is approximately 18.33 m².

Therefore, we can express the area as:

Area = 9768 ± 18.33 m²

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(a) The initial energy of the mass is 76.485 J.

(b) The compression of the spring in the absence of friction is 21.2 cm.

(c)  The compression of the spring in the presence of friction is 19.4 cm.

The initial energy of the mass is determined as follows;

E = K.E + P.E

E = ¹/₂mv² + mgh

where;

E = ¹/₂mv²  + mg x Lsinθ

P.E = ¹/₂(9.4)(2.5)² +  (9.4)(9.8)(0.87)(sin36)

P.E = 76.485 J

The compression of the spring in the absence of friction is calculated as follows;

Ux = E

¹/₂kx² = 76.485

kx² = 2(76.485)

x² = (2 x 76.485)/k

x = √(2 x 76.485)/k

x = √(2 x 76.485 / 3413.7)

x = 0.212 m

x = 21.2 cm

The compression of the spring in the presence of friction is determined by applying the principle of conservation of energy.

E - Fd = Ux

E - μmgd = ¹/₂kx²

76.11 - (0.27 x 9.4 x 9.8 x 0.48) = ¹/₂(3413)x²

64.17 = 1706.5x²

x² = 0.0376

x = √0.0376

x = 0.194

x = 19.4 cm

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When there is a net force exerted on an object, the magnitude of the acceleration of the object is proportional to the magnitude of the net force and has a magnitude that is inversely proportional to the mass.--The statement is true.

Newton's second law of motion states that the acceleration of an object depends upon two variables i.e the net force which is acting upon the object and the mass of the object. The acceleration of an object is dependent directly upon the net force which is acting upon the object, and inversely upon the mass of the object. If the force acting upon an object is increased, the acceleration of the object is increased. If the mass of an object is increased, the acceleration of the object is decreased.

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The complete question is:

State whether a given statement is True or False.

When a net external force acts on an object of mass m, the acceleration that results is directly proportional to the net force and has a magnitude that is inversely proportional to the mass.

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To solve this problem, we need to determine the frictional force acting on the block with different magnitudes of the applied force.

First, we need to find the normal force on the block, which is equal to the weight of the block. The weight of the block is given by:

W = mg = 2.5 kg x 9.8 m/s^2 = 24.5 N

Next, we need to find the force of the applied vertical force, which is given in the problem as "is". We can use trigonometry to find the vertical component of the force:

Fv = is sinθ

where θ is the angle between the force and the horizontal surface. Since the problem does not give us the value of θ, we will assume it to be 0°, which means the force is purely horizontal.

(a) If the magnitude of the applied force is 8.0 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 0) = 9.8 N

(b) If the magnitude of the applied force is 10 N, then the frictional force can be calculated as:

Ff = μsFn = μs(mg - Fv) = 0.40(24.5 - 10) = 5.8 N

(c) If the magnitude of the applied force is 12 N, then the frictional force can be calculated as:

Ff = μkFn = μk(mg - Fv) = 0.25(24.5 - 12) = 3.1 N

Therefore, the magnitude of the frictional force acting on the block is 9.8 N, 5.8 N, and 3.1 N, for applied forces of 8.0 N, 10 N, and 12 N, respectively.

(a) When the horizontal force is 8 N the frictional force is 11.8 N.

(b) when the applied force is 10 N; the frictional force is 13.8 N.

(c) when the applied force is 12 N; the frictional force is 15.8 N.

(a) The magnitude of the frictional force on the block when the horizontal force is 8 N is calculated as;

F - Ff = ma

where;

F - μmg = ma

6 - 0.4 x 2.5 x 9.8 = 2.5 a

2.5 a = -3.8

a = -3.8/2.5

a = -1.52 m/s²

when the applied force is 8 N;

8 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 11.8 N

(b) when the applied force is 10 N;

10 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 13.8 N

(c) when the applied force is 12 N;

12 N - Ff = -1.52 m/s² x 2.5 kg

Ff = 15.8 N

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The electric field strength between A and B 90x20=1800.

The physical field that surrounds electrically charged particles and exerts force on all other charged particles in the field, either attracting or repelling them, is known as an electric field (also known as an E-field. It can also refer to a system of charged particles' physical field.  

Electric charges and time-varying electric currents are the building blocks of electric fields. The electromagnetic field, one of the four fundamental interactions (also known as forces) of nature, manifests itself in both electric and magnetic fields.

Electrical technology makes use of electric fields, which are significant in many branches of physics. For instance, in atomic physics and chemistry, the electric field acts as an attractive force to hold atoms' atomic nuclei and electrons together.

Therefore, The electric field strength between A and B 90x20=1800.

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Answer:

The kinetic theory of matter can be used to explain how solids, liquids and gases are interchangeable as a result of increase or decrease in heat energy. When an object is heated the motion of the particles increases as the particles become more energetic

Considering the Ohm's law, the correct answer is option B. the current is 0.048 A.

The flow of electricity through an object, such as a wire, is known as current (I). Its unit of measure is amps (A). So the current is a measure of the speed at which the charge passes a given reference point in a specified direction.

The driving force (electrical pressure) behind the flow of a current is known as voltage and is measured in volts (V) (voltage can also be referred to as the potential difference or electromotive force). That is, voltage is a measure of the work required to move a charge from one point to another.

Resistance (R) is the difficulty that a circuit opposes to the flow of a current and it is measured in ohms (Ω).

Ohm's law establishes the relationship between current, voltage, and resistance in an electrical circuit.

This law establishes that the intensity of the current that passes through a circuit is directly proportional to the voltage of the same and inversely proportional to the resistance that it presents.

Mathematically, Ohm's law is expressed as:

\(I=\frac{V}{R}\)

Where I is the current measured in amps (A), V the voltage measured in volts (V); and R the resistance that is measured in ohms (Ω).

In this case, you know that the voltage between two points in a circuit is 3.6 V and the resistance between the points is 75 Ω.

Replacing in the Ohm's Law:

\(I=\frac{3.6 volts}{75 ohm}\)

Solving:

I= 0.048 amps

Finally, the correct answer is option B. the current is 0.048 A.

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Answer:

shivering raises your body temperature

]A force called the effort force is applied at one point on the lever in order to move an object, known as the resistance force, located at some other point on the lever.

The way levers work is by multiplying the effort exerted by the user. Specifically, to lift and balance an object, the effort force the user applies multiplied by its distance to the fulcrum must equal the load force multiplied by its distance to the fulcrum. Consequently, the greater the distance between the effort force and the fulcrum, the heavier a load can be lifted with the same effort force.

Yes, the force of the engine does work on the car as it accelerates the car forward. Work is defined as the transfer of energy that occurs when a force is applied over a distance, and in this case, the force of the engine is causing the car to move, so it is doing work.

As the car gains speed, its kinetic energy increases, which means it has more energy of motion. Kinetic energy is defined as one-half of the mass of an object times its velocity squared, so as the car's speed increases, so does its kinetic energy.

The gravitational potential energy of the car will remain constant as long as it stays on a horizontal road, assuming there is no change in elevation. Gravitational potential energy is the energy an object possesses due to its position in a gravitational field, and since the car's position relative to the ground is not changing, its gravitational potential energy will remain constant.

The tractive force of the engine may change depending on the speed of the car and the resistance to motion that the car is encountering. As the car speeds up, the air resistance acting on the car will increase, which will require more force from the engine to maintain the same acceleration. Additionally, if the road surface is rough or there are inclines, the tractive force required to maintain the same speed or acceleration will also increase.

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Answer:

C) The book's inertia carried it forward.

When the bus stops suddenly, the book tends to remain in motion due to its inertia. The book was at rest on the seat of the bus, and when the bus stopped suddenly, the book continued moving forward with the same speed and direction it had before the bus stopped. As a result, the book slid off the seat and onto the floor.

 The speed of a bobsled is increasing because it has an acceleration of 2.4 m/s2. at a given instant in time 1363.6N.

Acceleration refers to the rate at which the velocity and direction of a moving object change over time. Anything is said to be sped when it goes straighter and faster or slower. Therefore, even though the speed is constant, travel on a circle increases due to the constant change in direction.

The rate at which a displacement varies is measured by its velocity. Speed changes occur at an accelerated rate. Its magnitude and orientation are both present, making it a vector quantity. As the rate at which velocity changes, acceleration is likewise a vector quantity.

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Answer:

\(\huge\boxed{\sf v_o=3.1\ m/s}\)

Explanation:

Given Data:

Acceleration due to gravity = g = -9.8 m/s²

Maximum Height = h = 0.490 m

At h, \(v_f\) = 0

Required:

\(v_o=?\)

Formula:

\(2gh=v_f^2-v_o^2\)

Solution:

Put the givens

\(2 (-9.8) (0.490) = (0)\² - v_o^2\\\\-9.604=-v_o^2\\\\9.604=v_o^2\\\\Take \ sqrt\ on \ both \ sides\\\\\sqrt{9.604}=v_o^2\\\\3.1 \ m/s=v_o\\\\v_o=3.1\ m/s\\\\\rule[225]{225}{2}\)

Answer:

Explanation:

1. eectromagnetic Fields. Most of the processes that accelerate particles to relativistic speeds work with electromagnetic fields to the same force that keeps magnets on your fridge!

Magnetic Explosions

Wave-Particle Interaction's