Answer: For example, if you drop a water balloon onto the ground, its kinetic energy is converted mostly to thermal energy.
Explanation: When the temperature of an object increases, the average kinetic energy of its particles increases. When the average kinetic energy of its particles increases, the object's thermal energy increases. Therefore, the thermal energy of an object increases as its temperature increases.
iron is electroplated with------ to protect it from corrosion.
a) tin
b). copper
c) silver
d) chromium
Answer:
B) cooper
Explanation:
the Cooper will protect the iro from attack by reagents such as acid
how to calculate mass using area and density
If medium 1 is glass, could medium 2 be zircon? Explain your answer with reference to index of refraction.
Answer:
So the answer would be no, because the medium 1 value must be greater than the value of medium 2.
Explanation:
The value of n1 must be greater than the value of n2.
Medium 1 - Index of Refraction (n1): 1.52
Medium 2 - Index of Refraction (n2): 1.92
I think that is correct
Calculate the torque produced by a motor that has 500 windings across a 30cm diameter rotating core. The core is 0. 6 M long inside a 50 tesla magnetic field. The resistance of the wire is 30 ohms when 12 volts are applied
The torque produced by the motor is approximately 706 Nm. The motor mentioned in the question is an electrical device that converts electrical energy into mechanical energy.
To calculate the torque produced by the motor, we need to use the formula:
Torque = Magnetic Field Strength × Current × Area × Number of Windings
Given:
Magnetic field strength (B) = 50 Tesla
Number of windings (N) = 500
Diameter of the rotating core (d) = 30 cm = 0.3 m
Length of the rotating core (L) = 0.6 m
Resistance of the wire (R) = 30 ohms
Voltage applied (V) = 12 volts
First, let's calculate the current (I) flowing through the wire using Ohm's Law:
I = V / R
I = 12 V / 30 Ω
I = 0.4 Amperes
Next, let's calculate the area (A) of the rotating core:
A = πr^2
= π(d/2)^2
= π(0.3/2)^2
= π(0.15)^2
≈ 0.0707 square meters
Now, we can calculate the torque (T) produced by the motor:
T = B × I × A × N
T = 50 T × 0.4 A × 0.0707 m^2 × 500
T ≈ 706 Newton-meters (Nm)
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Select the choice that best fits the measurement, scalar or vector.
vector
10 m
Answer:
Explanation:
Because scalars are physical quantities that are unaffected by changes to a vector space basis and because vectors require having a magnitude and a direction, one can deduce that "10m" is a measurement.
You can think of the scalar being a plain number, the vector being the direction accompanied with the scalar (giving the vector magnitude), and then the measurement are the units you apply.
"Ten feet north."
Scalar -- Ten
Vector -- North
Measurement -- Feet
you can safely hold your fingers on both sides of a candle flame due mainly to group of answer choices convection. radiation. conduction. none of the above
You can safely hold your fingers on both sides of a candle flame due mainly to convection.
Convection is the process by which heat is transferred through the movement of fluids or gases, such as air. In this case, the heated air around the candle flame rises upwards, which means the heat is not directly transferred to your fingers when they are on both sides of the flame. Therefore we can correctly say that you can safely hold your fingers on both sides of a candle flame mainly due to convection.
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A bicyclist rides 2.93 km due east, while the resistive force from the air has a magnitude of 8.65 N and points due west. The rider then turns around and rides 2.93 km due west, back to her starting point. The resistive force from the air on the return trip has a magnitude of 8.65 N and points due east. Find the work done by the resistive force during the round trip. Number Type your answer here Units Choose your answer here
Answer:
-50.6 kJ
Explanation:
The work done (W) on an object is given by:
W = (Fcosθ) * S
where F is the force, S is the displacement and θ is the angle between the force and displacement.
i) During the first trip riding east, S₁ = 2.93 km = 2930 m, F₁ = 8.65 N.
The displacement is due east and the force is due west, hence θ₁ = 180°. Therefore:
W₁ = (F₁ * cosθ₁)S₁ = (8,65 * cos(180))2930 = -25.3 kJ
ii) i) During the second trip riding west, S₂ = 2.93 km = 2930 m, F₂ = 8.65 N.
The displacement is due west and the force is due east, hence θ₂ = 180°. Therefore:
W₂ = (F₂ * cosθ₂)S₂ = (8,65 * cos(180))2930 = -25.3 kJ
work done by the resistive force during the round trip is:
W = W₁ + W₂ = -25.3 kJ + (-25.3 kJ) = -50.6 kJ
Two charges of 5 x 10-6 C are a certain distance apart. These two positive charges experience 3.6 N of repelling electrical force between them. How far apart are these charges?
Answer:
25 cm
Explanation:
F = k q₁q₂/r²
Substituting values : let the distance be x.
3.6 = (9 x 10^9) (5 x 10^(-6) (5 x 10^(-6)) / x²
3.6 = (225 x 10^(9-6-6) )/x²
3.6 = (225 x 10^(-3) / x²
x² = 225/3.6 x 10^(-3)
x² = 62.5x10x10^(-4) [10^(-3)=10x10^(-4)]
x = √(625 x 10^(-4) )
x = 25 x 10^(-2)
Or, x = 25 cm
A point charge of +10 μC is at (+3 m, 0 m) on the x-axis and a point charge of +10 μC is at (-3 m, 0 m).
1) Determine the work required to assemble this charge distribution.
Hi there!
Recall the equation for electric potential energy for point charges:
\(\boxed{U = \frac{1}{4\pi \epsilon_0} \frac{q_1q_2}{r}}\)
U = Electric potential energy (J)
ε₀ = Permittivity of Free Space (8.85 × 10⁻¹² C/Vm)
q₁, q₂: Charges (C)
r = distance between charges (m)
Solving for r:
3 - (-3) = 6m
Now, plug in the values:
\(U = \frac{1}{4\pi \epsilon_0} \frac{(.00001)(.00001)}{6} = \boxed{1.498 J}\)
Vinny is on a motorcycle at rest, 200 m away from a ramp that jumps over a gully. Calculate the minimum constant acceleration Vinny must have to get to the ramp in 8 s before his pursuers catch up with him.
Answer: 6.25 m/s^2
Explanation:
The distance between Vinny and the ramp is 200m
And he has 8 seconds (At max) to reach that distance.
The initial velocity is 0m/s
The initial position is 0m
Now, we want to find the constant acceleration in order to do this, so suppose that we have a constant acceleration A.
a(t) = A.
To have the velocity, we must integrate over time, and remember that the constant of integration is equal to zero because the initial velocity is zero.
v(t) = A*t
For the position, we integrate again over time.
p(t) = 0.5*A*t^2
And we want to travel 200m in 8 seconds, then:
p(8s) = 200m
0.5*A*(8s)^2 = 200m
A*32s^2 = 200m
A = 200m/32s^2 = 6.25 m/s^2
This is the minimum acceleration in order to do this, if Vinny has a larger acceleration he will travel the 200m in a smaller time.
a guitar string is placed under 250 n tension. the length of the vibrating portion is 60.0 cm and has a mass of 1.00 g. what is the fundamental frequency of the string?
Answer:
The frequency of a standing wave on a guitar string is given by f = v 2 L where v is the velocity, and L is the length of the string. The length of a guitar string is related mathematically to the wavelength of the wave which resonates within it. Thus the strategy for solving for length will be to first determine the wavelength of the wave using the wave equation and the knowledge of the frequency and the speed.
These natural frequencies are known as the harmonics of the guitar string. As mentioned earlier, the natural frequency at which an object vibrates at depends upon the tension of the string, the linear density of the string and the length of the string.
The length of the string is 70.0 cm. Calculate the speed of the standing wave in the guitar string.
Explanation:
I need help in this please
The net force along the origin is zero in image (3).
What would make the net force at the origin to be zero?We know that the image in the question shows us three charges that have been shown according to the diagram in the image. It is important that we note that the net force is the resultant force that is acting at the origin zero in each of the cases.
We would now have to look at the magnitudes of the charges in each of the cases so as to obtain the resultant force of zero at the origin. Thus we can see that in the case we have, the set up in (3) is such that the resultant at the origin would give a zero magnitude.
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A spring with a spring constant of 34 N/m is stretched 14 m. What is the energy stored in the
spring?
Answer:
Elastic potential energy
Elastic potential energy is stored in the spring. Provided inelastic deformation has not happened, the work done is equal to the elastic potential energy stored.
Explanation:
becuse
Answer:10
Explanation:
Allison stands 180 meters away from a steep canyon wall. She shouts and hears the echo of her voice one second later. What is the speed of the wave?
Answer:
V = S / t speed of wave
V = 2 * 180 m / 1 sec = 360 m/s speed of sound wave
in a single-slit experiment, a beam of monochromatic light of wavelength 693 nm passes through a single slit of width 19.0 m. the diffraction pattern is displayed on a screen that is 2.15 m away. what is the distance between the third dark fringe and the center of the diffraction pattern? give your answer in cm.
The distance between the third dark fringe and the center of the diffraction pattern is 1.05 cm. The diffraction pattern is displayed on a screen that is 2.15 m away. We need to find the distance between the third dark fringe and the center of the diffraction pattern.
To solve this problem, we can use the formula for the position of the dark fringes:
y = mλL/d
where y is the distance from the center of the pattern to the \(m^{th}\) dark fringe, λ is the wavelength of the light, L is the distance between the slit and the screen, d is the width of the slit, and m is the order of the fringe.
Plugging in the values given in the problem, we get:
y = 3 × 693 × 10⁻⁹ × 2.15 / 19.0 = 1.05 × 10⁻³ m
Converting to centimeters, we get:
y = 1.05 × 10⁻¹ cm
Therefore, the distance between the third dark fringe and the center of the diffraction pattern is 1.05 cm.
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Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!
An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm.
Determine the horizontal distance travelled by the electron when it hits the plate.
Answer:
Given that
speed u=4*10^6 m/s
electric field E=4*10^3 N/c
distance b/w the plates d=2 cm
basing on the concept of the electrostatices
now we find the acceleration b/w the plates to find the horizontal distance traveled by the electron when it hits the plate.
acceleration a=qE/m=\(1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}\)=\(7*10^{14}\) m/s
now we find the horizontal distance traveled by electrons hit the plates
horizontal distance
\(X=u[2y/a]^{1/2}\)
=\(4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}\)
=\(3*10^{-2}\)= 3 cm
Which statements are true regarding refraction? Check all that apply.
a) Light bends towards the normal when entering a higher index of refraction
b) Light bends towards the normal when entering a lower index of refraction
c) Light bends away from the normal when entering a higher index of refraction
d) Light bends away from the normal when entering a lower index of refraction
Light bends away from the normal when entering a higher index of refraction.
What is refraction ?In physics, refraction is the change in direction produced by a wave's speed as it travels from one medium to another. Waves, for example, travel quicker in deep water than in shallow water. When an ocean wave approaches a beach obliquely, the portion of the wave farther from the beach moves quicker than the portion closer to the beach, causing the wave to swing around until it moves perpendicular to the shoreline. Sound waves travel faster in warm air than in frigid air. At night, the surface of a lake cools, and any sound that moves upward is refracted down by the higher layers of air that are still warm. As a result, sounds such as speech and music.
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a. Consider a light bulb connected to a battery with wires. How must the light bulb be connected in order for it to light?
b. Identify the relevant parts of the bulb and battery. Explain, using the concept of potential difference, why and how your configuration causes the bulb to light. Do not use the phrase "complete circuit".
To light the bulb, it must be connected to the battery in a way that the positive terminal of the battery connects to one end of the bulb's filament and the negative terminal connects to the other end of the filament.
The relevant parts of the bulb are the filament and the two contact points, while the battery has a positive terminal and a negative terminal.
When the bulb is connected in the configuration described above, a potential difference is created between the positive and negative terminals of the battery.
This potential difference causes an electric current to flow through the wires and the filament of the bulb.
The filament, made of a material with a high resistance, heats up due to the current flow and begins to emit light as a result.
Hence, A light bulb must be connected to a battery such that its filament is connected between the positive and negative terminals of the battery. This creates a potential difference, allowing the current to flow through the filament and causing it to emit light.
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How much work would it take to swing a 6kg sledgehammer over a distance of 2m if 100n of force is applied?
Answer:
200J
Explanation:
Given parameters:
Mass of sledgehammer = 6kg
Distance = 2m
Force applied = 100N
Unknown:
Work done = ?
Solution:
Workdone is the force applied to move a body through a certain distance;
Work done = Force x distance
Work done = 100 x 2 = 200J
When is the electric flux on a section of a closed surface positive?.
URGENT WILL GIVE BRAINLIEST TO BEST ANSWER
Which is not one of the properties of air?
mass
pressure
volume
density
Answer:
volume is not a property of air
mention 4 layers of the atmosphere
Answer:
These layers are the troposphere, the stratosphere, the mesosphere and the thermosphere.
A further region, beginning about 500 km above the Earth's surface, is called the exosphere.
Explanation:
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A volume of 200.0 cm3 of water at a temperature of 4°C is in a container with a 1000-cm3 capacity. The container and its contents are heated to 95°C. What is the final volume of water in the container? Disregard any expansion of the container itself. βwater = 210 x 10-6 (°C)-1.
The final volume of water in the container after increasing the temperature is 203.8 m³.
From the given,
The initial volume of water (Vο) = 200 cm³
Initial temperature = 4°C = 4+273 = 277K
Final temperature = 95°C = 273+95 = 368 K
Volume expansion co-efficient = 210×10⁻⁶(°C)⁻¹
Final volume =?
β = 1/Vο (ΔV/ΔT), β represents the volume expansion coefficient, ΔV change in volume, ΔT is the change in temperature, and Vο is the initial volume.
ΔV = β×Vο×ΔT
= 210×10⁻⁶×200×(368-277)
= 210×10⁻⁶×200×91
ΔV = 3.83 m³
ΔV = final volume - initial volume
final volume = ΔV + 200
= 3.82 +200
= 203.82 m³
Final volume = 203.82 m³.
Thus, the final volume of the water is 203.82 m³.
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A crate of mass 140 kg is being pulled upward
by a rope at a constant acceleration of 3 m/s2.
If the crate starts from rest, what power is
the rope delivering to the crate when it has
been pulled upward a distance of 5 m? The
acceleration due to gravity is 10 m/s2.
Answer in units of W
The power of the rope pulling the crate when raised 5 meters is 9.97 * 10³ W.
Assuming it's being pulled straight up at 3 m/s²
P = Fv so we need the force and the velocity.
F = ma and since it is accelerating upwards, the rope has to deliver a force greater than gravity sufficient to make it accelerate. F = mg + ma = m(g + a) = (140 kg)(13 m/s²) = 1820 N.
From kinematics, v = (2ad)\(^{1/2}\) = ((2 * 3 m/s²)(5 m))\(^{1/2}\) = 5.48 m/s
So at that point, power = (1820 N)(5.48 m/s) =9.97 * 10³ W.
It is defined as the amount of energy expended per unit of time and is measured in watts (W). Power is essential in many areas of physics, from mechanical systems to electrical circuits. It can be calculated using various formulas, depending on the specific situation. The concept of power is closely related to energy and is an essential consideration in many engineering and technological applications.
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Question 2 of 10
A football is kicked with a velocity of 18 m/s at an angle of 20". What is the
ball's acceleration in the horizontal direction as it flies through the air?
O A. 16.9 m/s2
O B. 0 m/s2
O C. 9.8 m/s2
O D. 6.1 m/s2
Answer:
B
Explanation:
The question does not specify any outside forces that could slow down the ball horizontally. There fore the ball does not accelerate or decelerate horizontally. Therefore, a = 0m/s2
A man is sitting on a chair with wheels. He grabs a 2.1 kg book from the desk and throws
the book at a speed of 7.2 m/s. His chair moves backward. The man has a mass of 70 kg and
the chair has a mass of 9.2 kg. What is the speed of the man and the chair after the book is
thrown?
The speed of the man and the chair after the book is thrown is 0.2 m/s.
The given parameters:
mass of the book, m₁ = 2.1 kgspeed of the book, u₁ = 7.2 m/smass of the man, M = 70 kgmass of the book, m = 9.2 kgThe total mass of the man and the book is calculated as follows;
m₂ = 70 kg + 9.2 kg
m₂ = 79.2 kg
The speed of the man and the chair after the book is thrown is determined by applying the principle of conservation of linear momentum;
\(m_1 u_1 = m_2u_2\\\\u_2 = \frac{m_1u_1}{m_2} \\\\u_2 = \frac{2.1 \times 7.2}{79.2} \\\\u_2 = 0.2 \ m/s\)
Thus, the speed of the man and the chair after the book is thrown is 0.2 m/s.
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Why would a person who handles electronic components wear a grounded wrist strap?
A. To reduce or eliminate static charges
B. To remove dust particles
C. To avoid a buildup of magnetic forces
D. To increase the resistance in the components.
The correct answer is A. To reduce or eliminate static charges. Wearing a grounded wrist strap when working with electronic components is done largely to reduce static charges and guard against component damage.
A grounded wrist strap would be worn by someone who works with electronic components in order to reduce or get rid of static charges. The risk of static electricity when working with electronics is substantial. Static charges may accumulate on a person's body, and if they discharge through an electronic component, they may interfere with delicate circuitry and harm the device.
The grounded wrist strap creates a pathway for static charges to flow to the ground, preventing them from building up on the wearer's body. It efficiently dissipates any static energy, reducing the possibility of discharge that can damage the electronic parts. It is not directly related to removing dust particles, preventing a buildup of magnetic forces, or boosting component resistance to wear a grounded wrist strap. Its main goal is to assure electrostatic discharge (ESD) safety by reducing static charge damage to delicate devices.
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You have a 1.0-m-long copper wire. You want to make an
N-turn current loop that generates a 1.0 mT magnetic field at the
center when the current is 1.0 A. You must use the entire wire.
'What will be the diameter of your coil?
If the coil is needed to generate a 1.0 mT magnetic field at the center with a 1.0 A current, the diameter of your coil will be approximately 8.14 cm.
To determine the diameter of the coil needed to generate a 1.0 mT magnetic field at the center with a 1.0 A current, follow these steps:
1. First, we need to find the number of turns (N) in the coil. Use the formula for the magnetic field at the center of a current loop: B = (μ₀ * N * I) / (2 * R), where B is the magnetic field, μ₀ is the permeability of free space (4π × 10^-7 T·m/A), N is the number of turns, I is current, and R is the radius of the coil.
2. Rearrange the formula to find the radius: R = (μ₀ * N * I) / (2 * B).
3. Next, we need to find the length of the wire required to make N turns. The length (L) of the wire is equal to the circumference of the coil (2πR) multiplied by the number of turns (N): L = N * 2πR.
4. Rearrange this formula to find N:
N = L / (2πR).
5. Substitute this expression for N in the formula for R from step 2:
R = (μ₀ * (L / (2πR)) * I) / (2 * B).
6. Solve this equation for R, using the given values of L = 1.0 m, I = 1.0 A, and B = 1.0 mT (or 0.001 T): R ≈ 0.0407 m.
7. Finally, find the diameter of the coil by multiplying the radius by 2:
Diameter = 2 * R ≈ 0.0814 m, or approximately 8.14 cm.
So, the diameter of your coil will be approximately 8.14 cm.
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Calculate the force generated by a car that hits the wall at an
acceleration of 4 m/s^2 and has a mass of 45 kg? (INCLUDE UNITS)
This is a defective question. It was WRITTEN by someone who is unclear on the concepts. DON'T try and answer it.
It's trying to get us to use Newton's second law ... F = m • a.
But that only tells us how much force must act ON THE CAR in order to accelerate it. (45 kg) • (4 m/s^2) = 180 newtons.
This is NOT the force exerted BY the car when it hits something. THAT force depends on its speed WHEN it hits, AND how long it takes for the wreckage to actually come to rest, AND how hard or soft the wall is.
DON'T try to answer this question. Your answer will be wrong, you won't understand why, and the teacher you try to argue with probably won't either.
============================================
More explanation:
Think about jumping off of a ladder in your back yard. Several times.
Your mass is the same every time. Your acceleration is the same every time . . . 9.8 m/s² down, the acceleration of Earth gravity, every time.
BUT ...
-- I'll bet you would rather land on wood than on concrete. The force of landing would be less.
-- I'll bet you would rather land on dirt than on wood. The force of landing would be less.
-- I'll bet you would rather land on grass than on dirt. The force of landing would be less.
-- I'll bet you would rather land on a pile of blankets than on dirt. The force of landing would be less.
-- I'll bet you would rather land on a trampoline than on a pile of blankets. The force of landing would be less.
-- I'll bet you would rather jump from a short ladder than from a tall one. Your speed would be less when you landed, and the force of landing would be less.
==> Your mass is the SAME every time, and your acceleration is the SAME every time. But the force when you hit is DIFFERENT every time.
The mass and acceleration of the car DON'T tell us the force of the hit when the car hits a wall.
the main intake air duct of a forced air gas heater is 0.31 m in diameter. the inside volume of the house is equivalent to a rectangular solid 11 m wide by 20.5 m long by 3.15 m high. What is the average speed of air in the duct if it carries a volume equal to that of the house’s interior every 15 min?
To determine the average speed of air in the duct, we can use the formula:
Average speed = Volume flow rate / Cross-sectional area of the duct
First, we need to find the volume of the house and the volume flow rate:
Volume of house = width × length × height = 11 m × 20.5 m × 3.15 m = 709.725 m³
Since the air is replaced every 15 minutes, we need to convert it to an hourly rate:
Volume flow rate (hourly) = 709.725 m³ × (60 min / 15 min) = 2838.9 m³/h
Next, we calculate the cross-sectional area of the duct:
Area of duct = π × (diameter / 2)² = π × (0.31 m / 2)² ≈ 0.0754 m²
Finally, we can calculate the average speed of air in the duct:
Average speed = Volume flow rate / Cross-sectional area of the duct = 2838.9 m³/h / 0.0754 m² ≈ 37,687 m/h
To convert this to a more standard unit, we'll change it to meters per second (m/s):
Average speed = 37,687 m/h × (1 h / 3600 s) ≈ 10.47 m/s
Therefore, the average speed of air in the duct is approximately 10.47 m/s.
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