an excimer laser produces radiation at 157 nm, and optics with a numerical aperture of 1.4 is available. what is the smallest size of feature you could make in a resist? how might smaller final features be made in the underlying silicon with the same optics?

Answer:

A , C , E

they are all multiples of 3

Answer:

W= F × d

W= 2kn × 3.6

W= 7.2 J

Work is measured in Joules!

Encontramos que la distancia recorrida en los primeros 9 segundos es 288 metros.

Los datos dados son:

El cuerpo tiene una rapidez inicial de 5 m/s

El cuerpo tiene una aceleración de 6 m/s^2

Queremos calcular la distancia recorrida durante los primeros 9 segundos de movimiento.

Lamentablemente no contamos con los gráficos ni las tablas, así que se procede a obtener las ecuaciones de movimiento.

La aceleración será:

a(t) =  6m/s^2

Para la ecuación de la velocidad tenemos que integrar la ecuación de arriba, obteniendo:

v(t) = (6m/s^2)*t  + v0

Donde v0 es la rapidez inicial, que conocemos es igual a 5 m/s, así tenemos:

v(t) = (6m/s^2)*t  + 5m/s

Para la ecuación de la posición debemos integrar nuevamente, así obtendremos:

p(t) = (1/2)*(6m/s^2)*t^2  + (5m/s)*t + p0

Donde la p0 es la posición inicial, la cual podemos definir como p0 = 0m

p(t) = (3m/s^2)*t^2  + (5m/s)*t

Para encontrar la distancia recorrida en los primeros 9 segundos, simplemente debemos remplazar t por 9s en la ecuación de posición:

p(9s) =  (3m/s^2)*(9s)^2  + (5m/s)*9s = 288 m

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Answer:Magnitude of the car's acceleration is 3.5 m/s²

Given:

Mass of car = 1,000 kg

Net force applied by car = 3,500 N

Find:

Magnitude of the car's acceleration

Computation:

Net force = Mass × Acceleration

So,

3,500 = 1,000 × Acceleration

Acceleration = 3,500 / 1,000

Acceleration = 3.5 m/s²

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The average current supplied to the car's motor is 0.036 A.

To find the average current supplied to the car's motor, we need to use the equation for the electrical power supplied to the motor, which is given by

P = IV

where P is the electrical power, I is the current, and V is the voltage. We can rearrange this equation to solve for the current

I = P/V

The electrical power supplied to the motor is the product of the battery voltage and the current, or

P = IV

We know the battery voltage is 9.00 V, and we can calculate the total energy used to accelerate the car from rest to its final speed using the work-energy principle

W = (1/2)mv^2

where W is the work done on the car, m is the mass of the car, and v is the final speed of the car.

Plugging in the given values, we have

W = (1/2)(0.364 kg)(2.35 m/s)^2 = 0.980 J

The effective energy conversion efficiency is 47.1%, meaning that only 47.1% of the electrical energy supplied to the motor is converted into kinetic energy of the car. Therefore, the total electrical energy supplied to the motor is

E = W / (efficiency) = 0.980 J / 0.471 = 2.08 J

The time interval over which the energy is supplied is 6.42 s. Therefore, the average power supplied to the motor is

P = E / t = 2.08 J / 6.42 s = 0.324 W

Finally, we can use the equation for the average current

I = P / V = 0.324 W / 9.00 V = 0.036 A

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force= mass × acceleration

When the crest of one wave passes through the trough of another wave, destructive interference takes place.

The crest and trough of a wave, respectively, are its highest and lowest surface portions. The wave height is the vertical distance between the peak and trough. The wavelength is the horizontal separation between two consecutive crests or troughs.

When the crest of one wave passes through the trough of another wave, interference takes place.

This interference can be constructive, where the amplitudes of the waves add up, resulting in a larger wave, or destructive, where the amplitudes of the waves cancel out, resulting in a smaller wave or no wave at all.

The type of interference that occurs depends on the relative amplitudes, wavelengths, and phases of the two waves.

Therefore, destructive interference takes place when the crest of one wave passes through the trough of another wave.

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Answer:

Kepler refined the Copernican model. Orbits are not circles along which planets move at a constant speed, but ellipses, in the central focus of which is the Sun. The planet moves in an ellipse with a variable speed depending on the distance to the Sun. On this basis, Kepler significantly simplified the Copernican model and formulated the laws of planetary motion in their orbits.

Answer:

v = 12.8 m/s

Explanation:

Applying the law of conservation of energy:

\(m_1u_1+m_2u_2=m_1v_1+m_2v_2\)

where,

m₁ = mass of baseball = 149 kg

m₂ = mass of catcher = 57 kg

u₁ = initial speed of ball = 17.7 m/s

u₂ = initial speed of catcher = 0 m/s

v₁ = v₂ = v = final speed of ball and the final speed of catcher = ?

both are same because ball is in hands of cathcer in the final state.

Therefore,

\((149\ kg)(17.7\ m/s)+(57\ kg)(0\ m/s)=(149\ kg)(v)+(57\ kg)(v)\\\\v = \frac{2637.3\ kgm/s}{206\ kg}\)

v = 12.8 m/s

Therefore, the uncertainty in the estimate of the sound velocity in the air at T = 300 ± 0.4 K is approximately ±0.232 m/s.  A. To estimate Velocity.

We can substitute T = 300 K into the given equation: v = 20.04√T; v = 20.04√300. v ≈ 346.54 m/s

Therefore, the estimated velocity of sound in air at T = 300 K is approximately 346.54 m/s. B. To find the uncertainty in the estimate, we can use the formula for propagation of uncertainties: Δv = |∂v/∂T| ΔT. where Δv is the uncertainty in v, ΔT is the uncertainty in T, and |∂v/∂T| is the absolute value of the partial derivative of v with respect to T. Taking the partial derivative of the given equation: ∂v/∂T = 20.04/(2√T)

Substituting T = 300 K: ∂v/∂T = 20.04/(2√300) ≈ 0.5792 m/(s·K)

Substituting the given uncertainty ΔT = 0.4 K:

Δv = |∂v/∂T| ΔT

Δv = 0.5792 × 0.4

Δv ≈ 0.232 m/s

Therefore, the uncertainty in the estimate of the velocity of sound in air at T = 300 ± 0.4 K is approximately ±0.232 m/s.

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The ostrich's average speed during the 3.0 km run is approximately 38.65 km/h.

The average speed of the ostrich during the entire 3.0 km run, we need to calculate  the total time taken for both segments and then divide the total distance by the total time.

Calculate the time for each segment:

Time taken for the first 1.5 km segment at 58 km/h:

Time = Distance / Speed

= 1.5 km / 58 km/h

≈ 0.02586 hours

Time taken for the second 1.5 km segment at 29 km/h:

Time = Distance / Speed

= 1.5 km / 29 km/h

≈ 0.05172 hours

Calculate the total time:

Total Time = Time for the first segment + Time for the second segment

Total Time ≈ 0.02586 hours + 0.05172 hours

≈ 0.07758 hours

Calculate the average speed:

Average Speed = Total Distance / Total Time

Average Speed = 3.0 km / 0.07758 hours

≈ 38.65 km/h

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The electrostatic force on A by B is 3.9 × 10⁻⁵ N and the force from C is -1.9× 10⁻⁵ N. Then the net electric  force acting on A is 5.8 × 10⁻⁵ N.

According to Coulomb's law of force, the electrostatic force between two charges separated by a distance of r is given as follows:

Fc = Ke q1 q2 /r²

where Ke = 8.9 × 10⁹ Nm²/C²

Given the charge of  A = 2.5 × 10⁻⁹ C

charge of B = 1 × 10⁻⁹ C

distance r = 7.50 cm = 0.075 m

then Fc =  8.9 × 10⁹ Nm²/C²  (2.5 × 10⁻⁹ C ) (1 × 10⁻⁹ C)/(0.075 m)² = 3.9 × 10⁻⁵ N

Similarly, the force on A by the charge C is calculated as follows:

distance to C = 0.075 m + 0.075 = 0.15 m

charge of C = - 17.5 × 10⁻⁹ C.

Then Fc =   8.9 × 10⁹ Nm²/C²  (2.5 × 10⁻⁹ C ) (-17.5× 10⁻⁹ C)/(0.075 m)² = - 1.9 × 10⁻⁵ N

The net electric force acting on A =  3.9 × 10⁻⁵ N - (-1.9 × 10⁻⁵ N) = 5.8 × 10⁻⁵ N.

Therefore, the net electric force acting on A is  5.8 × 10⁻⁵ N.

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The pressure inside the Earth increases as depth increases; The temperature drops. Here option B is the correct answer.

As depth increases, the weight of the overlying rock and soil increases, causing an increase in pressure. Additionally, the temperature inside the Earth increases with depth due to the heat generated by the radioactive decay of elements in the Earth's crust.

However, the rate of temperature increase with depth is not as steep as the rate of pressure increase, so the temperature will decrease as the depth increases.

The geothermal gradient is the pace at which Earth's temperature increases with depth. It suggests that the Earth's surface is receiving heat from the planet's heated center. For every kilometer of depth, the temperature rises by around 25°C on average.

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2000 N

Hi there !

Newton's second law

F = m×a

= 200kg×10m/s²

= 2000kg×m/s²

1kg×m/s² = 1 N

= 2000 N

Good luck !

Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Answer:

A mushroom rock, rock pedestal, or gour is a typical mushroom-shaped landform that is formed by the action of wind erosion. ... In some cases, harder rocks are arranged horizontally over a softer rock, resulting in such erosion.

Explanation:

Answer:

wind erosion

Explanation:

In a Reverse fault, the hanging wall block moves up with respect to the footwall block.

Reverse fault is a type of fault in which two blocks of earth's crust move away from each other, resulting in the upper block of crust being pushed up above the lower block. It is the opposite of a normal fault, in which two blocks of crust move towards each other. The reverse fault typically occurs when the Earth’s tectonic plates come together and a compressional force pushes up and over the lower plate. This type of fault is usually seen in regions of convergence between two plates and is common along convergent plate boundaries. The reverse fault is usually accompanied by large earthquakes as the plates move against each other. The reverse fault can also be caused by the bending of the Earth’s crust in response to forces such as erosion, volcanic activity and sedimentation. These forces can cause the crust to buckle and rise, resulting in a reverse fault.

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Answer: 31N

Explanation:F = m x a

F = 8.5 x 3.7

F = 31.45

F = 31 (rounded)

F = 31 N

Answer:current

Explanation:water flows down a river. Current flows down a wire (in the drude model, at least)

Answer:

electricity

Explanation:

An electron in an s orbital can be identified by these four quantum numbers, which specify its location, orientation, and spin.

The four quantum numbers that can apply to electrons in s orbitals are:

1. Principal quantum number (n): The principal quantum number (n) represents the principal energy level of the electron and describes the size and energy of the electron’s orbital.

An s orbital is a subshell with a value of 0 for the second quantum number (l).

2. Azimuthal quantum number (l): For an s orbital, the azimuthal quantum number (l) has a value of 0. It identifies the type of orbital an electron occupies.

3. Magnetic quantum number (ml):

The magnetic quantum number (ml) specifies the orientation of the electron’s orbital around the nucleus.

For an s orbital, the value of ml is 0.4. Spin quantum number (ms): The spin quantum number (ms) indicates the spin of the electron.

The two possible values of the spin quantum number are +½ and -½.

The electron spin is denoted by an arrow pointing up or down, and it is represented by the letter m in the Schrödinger equation.

An electron in an s orbital can be identified by these four quantum numbers, which specify its location, orientation, and spin.

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To determine the well's producing capacity and the required choke size, we need to analyze three scenarios: no choke, choke at the wellhead, and choke at the separator.

In the case of no choke, the well is unrestricted, and the pressure at the wellhead (Pwh) is equal to the flowing bottomhole pressure (Pwf). We can use the Tubing equation to calculate the producing capacity:

Pwh = 0.9Pwf - 0.95Q - 100

For the choke at the wellhead, we need to consider the critical flow condition. This means that the pressure at the wellhead is determined by the flow rate (Q) and the choke size (nozzle diameter). By rearranging the Tubing equation, we can solve for the required choke size:

Nozzle diameter = (0.9Pwf - Pwh - 100) / 0.95

For the choke at the separator, we use the Flowline equation to determine the well's producing capacity. Rearranging the equation, we find:

Pwh = (Psep + 0.35Q - 2.5) / q

Now, we can substitute the values for the given conditions (well depth, tubing size, Pr, fw, C, flowline length, flowline size, GLR, Psep, and n) into these equations to calculate the producing capacity and the required choke size for each scenario.

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Answer:

C. Wedge

Explanation:

Answer:

GIVE THE PERSON ABOVE BRAINLIEST UwU

Explanation:

Answer:

the answer would be strongest because just took this question

Explanation:

(a) Magnitude of the induced emf at t = 1.00 s is 12 mV. b The magnitude of the induced  - 112 mV(c) , c The emf zero at t = 0.875 seconds.

a The emf induced in an inductor is given as e = -L (di/dt)Where, L = Inductance di/dt = Rate of change of currentFrom the given equation, we have i = 4t² - 7t When t = 1.00 s, we have i = 4 (1.00)² - 7 (1.00)= -3.00 AAt t = 1.00 s, di/dt = d/dt [4t² - 7t] = 8t - 7= 1 s-1

Therefore, the induced emf is e = -L (di/dt)=- 20 mH × 1 s-1× (- 3.00 A)= 60 mV(b)

b The magnitude of the induced emf at t = 4.00 s is 112 mV.Using the same formula, at t = 4.00 s, i = 4 (4.00)² - 7 (4.00)= 25.00 AAt t = 4.00 s, di/dt = d/dt [4t² - 7t] = 8t - 7= 25 s-1Therefore, the induced emf is e = -L (di/dt)=- 20 mH × 25 s-1× (25.00 A)= - 112 mV(c)

c. At what time is the emf zero?The induced emf is zero when the rate of change of current is zero. So, we need to find the time t such that di/dt = 0. 8t - 7 = 0 => t = 7/8 s. Therefore, the emf is zero at t = 0.875 seconds.

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The average torque exerted on the wheel as it slows down has magnitude of 1.0 Nm

The rotational kinetic energy equation relates the rotational kinetic energy of an object to its moment of inertia and angular velocity. The work-energy theorem states that the work done on an object is equal to the change in its kinetic energy. We are given the radius of the wheel, its moment of inertia, and its initial angular speed.

We are also told that the wheel stops rotating after 6 seconds due to friction in the axle, which exerts a torque on the wheel. Using the rotational kinetic energy equation, we can calculate the initial rotational kinetic energy of the wheel. We can then use the work-energy theorem to find the work done by the frictional torque, which is equal to the change in the wheel's rotational kinetic energy.

Rotational inertia(I) = 2 kg m²

Radius (r) = 0.33 m

Initial angular speed W0 = 3 rad/s

time to stop (t) = 6 s

Angular acc. (α) = ?

We know that,

W = W₀ + at

0 = 3 - a × 6

a = 3/6

a = 1/2 rad/s²

   Average Torque = I*α

      Torque = 2 * 1/2 Nm

      Torque = 1 Nm

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Answer:

The correct answer is option D.

Explanation:

With an increase in temperature, the particles increase kinetic energy and move quicker. The normal speed of the particles relies upon their mass just as the temperature – heavier particles move more gradually than lighter ones at a similar temperature.

The temperature increase in this system since the average kinetic energy of the particles increases and particles move quickly. And after some time the temperature of the system is lower now than it was initially.

Thus, the correct answer is option D.

The impact of the change in motion should be option D.

In the case when there is an increase in temperature, the particles should increase kinetic energy and move faster. The normal speed of the particles believes their mass is like the temperature. The temperature rises in this system because the average kinetic energy of the particles should rised and particles move faster.

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To calculate the work done by the block on the spring, we can use the formula:

W = (1/2) k x²

where W is the work done, k is the spring constant, and x is the displacement of the spring from its relaxed position.

In this case, we are given that the spring is compressed by 0.080 m,

so x = 0.080 m. We are also given the spring constant,

which we will assume is given in units of N/m.

Let's call the spring constant k.

Plugging in these values into the formula, we get:

W = (1/2) k x²

W = (1/2) (k) (0.080 m)²

W = 0.000256 k J

So the work done by the block on the spring is equal to 0.000256 times the spring constant, in units of joules.

Note that the work done by the block on the spring is equal in magnitude but opposite in sign to the work done by the spring on the block.

This is because the work-energy principle tells us that the net work done on an object is equal to its change in kinetic energy. In this case, the block is initially at rest, so its initial kinetic energy is zero.

Therefore, the work done by the block on the spring is equal in magnitude but opposite in sign to the work done by the spring on the block, which causes the block to gain potential energy in the spring.

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When a block on a spring is compressed, the work done is calculated using the formula W = (1/2) kx2.

How to calculate the work W done by the block on the spring?

The work done W by the block on the spring can be calculated using the formula:

W = (1/2) kx^2

where k is the spring-constant, where x is the displacement of the spring from its given equilibrium-position.

Given that the spring is compressed 0.080 m and the spring-constant k is,

we can calculate the work done as follows:

W = (1/2) kx^2

W = (1/2)( )(0.080)^2

W = 0.08 J

Therefore, the work done by the block on the spring is 0.08 J.

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Answer:

76 cm southwest

Explanation:

The displacement of the mouse is 76.01 cm along south-west at an angle 57.35° with south direction.

In mechanics, displacement refers to the distance that a particle or body moves in a particular direction. Generally, point masses are used to describe particles and bodies. This means that, without sacrificing generality, bodies can be thought of as having all of their mass concentrated in a single mathematical point.

The mouse  scurries 41 cm south and then  takes a 90-degree turn and scurries 64 cm west.

Hence, magnitude of resultant displacement = √( 41² + 64²) cm = 76.01 cm.

The direction of displacement is along south-west with an angle with south direction= tan⁻¹(64/41) = 57.35°.

Hence, the displacement of the mouse is 76.01 cm along  south-west at an angle 57.35° with south direction.

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