an experiment to compare the tension bond strength of polymer latex modified mortar (portland cement mortar to which polymer latex emulsions have been added during mixing) to that of unmodified mortar resulted in x

Answers

Answer 1

In an experiment comparing the tension bond strength of polymer latex modified mortar (portland cement mortar with added polymer latex emulsions) to that of unmodified mortar, the result was x.

To conduct this experiment, you would need to follow these steps:

1. Prepare the materials: Gather all the necessary materials, including polymer latex emulsions, portland cement, sand, water, and any other additives required for the mortar mixture.

2. Prepare the polymer latex modified mortar: Mix the portland cement, sand, water, and polymer latex emulsions according to the specified proportions. Ensure thorough mixing to achieve a homogeneous mixture.

3. Prepare the unmodified mortar: Mix the portland cement, sand, and water according to the specified proportions. Again, ensure thorough mixing for a consistent mixture.

4. Perform the tension bond test: Apply both the polymer latex modified mortar and the unmodified mortar onto separate test surfaces, such as concrete blocks or metal plates. Make sure the surfaces are clean and free from any contaminants.

5. Allow the mortar to cure: Let both the modified and unmodified mortar cure for a specific duration, following the manufacturer's instructions or established industry standards.

6. Test the bond strength: Use a tension bond strength test apparatus, such as a hydraulic or mechanical testing machine, to apply a force perpendicular to the bond interface of the mortar. Apply increasing force until the bond fails and records the maximum force required for bond failure in both cases.

7. Compare the results: Analyze the data obtained from the tension bond test for both the polymer latex modified mortar and the unmodified mortar. Determine the maximum force or stress required for bond failure in each case.

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Related Questions

Which is true about about stable isotopes? (1 point)
Isotopes with more neutrons than protons are always stable.
Isotopes are always unstable because they are radioactive.
Isotopes that are naturally occurring in nature are always unstable.
A stable nucleus has a similar number of protons and neutrons.

Answers

The statement a stable nucleus has a similar number of protons and neutrons is true about stable isotopes (Option D).

What is a radioactive isotope?

A radioactive isotope can be defined as a chemical element that emits energy in form of different types of radiation such as alpha radiation or beta radiation, which is due they are unstable in normal conditions.

Therefore, with this data, we can see that the radioactive isotopes are unstable and they can emit energy based on diverse types of radioactive emissions such as alpha rays and or beta rays.

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Nitrogen is an essential element of which molecules?
O Amino acids and nucleic acids
O Carbohydrates and lipids
Lipids and hydrocarbons
O Nucleic acids and hydrocarbons

Answers

Amino acids and nucleic acids

Which of the following food preservation methods is the most effective for destroying pathogens, including viruses? A. Fermentation B. Sterilization C. Freezing D. Smoke curing

Answers

Sterilization is a food preservation method that involves subjecting food to high temperatures to eliminate all forms of microorganisms, including bacteria, viruses, and fungi.  Among the given options, sterilization is the most effective food preservation method for destroying pathogens, including viruses.

Sterilization is a food preservation method that involves subjecting food to high temperatures to eliminate all forms of microorganisms, including bacteria, viruses, and fungi. This process effectively destroys pathogens and ensures the safety of the food. It is commonly achieved through techniques such as pressure cooking, canning, or autoclaving.

Fermentation, on the other hand, is a preservation method that involves the growth of beneficial bacteria or yeast, which can inhibit the growth of harmful pathogens. While fermentation can reduce the risk of pathogen growth, it may not completely eliminate them.

Freezing is a method that slows down the growth of microorganisms, including pathogens, but it does not necessarily destroy them. Some pathogens can survive freezing temperatures and become active again when the food thaws.

Smoke curing involves exposing food to smoke, which can add flavor and inhibit the growth of certain bacteria. However, it may not be as effective in destroying viruses and other pathogens compared to sterilization.

In conclusion, sterilization is the most effective food preservation method for destroying pathogens, including viruses. It ensures the highest level of safety by eliminating all microorganisms from the food.

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During which changes of state do atoms that cannot move past one another become free to move?vaporization and sublimationboiling and depositionsublimation and meltingcondensation and melting.

Answers

Atoms that are unable to pass one another become free to migrate during state shifts such as sublimation and melting. While atoms also have a tendency to clash when a solid material melts.

This allows them to slip past one another. As a result, we may say that as an object melts or sublimation, its state changes, allowing atoms that can't travel past one another to do so. A substance can transfer directly from the solid to the gas state through sublimation, bypassing the liquid step. A substance can change its phase from a solid to a liquid by the physical process of melting or fusion. When the solid's internal energy increases, usually as a result of the application of heat causes melting.

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When 125 grams of FeO react with 25.0 grams of AI, how many grams of Fe can be produced?FeO+AI—>Fe+AI2O3

When 125 grams of FeO react with 25.0 grams of AI, how many grams of Fe can be produced?FeO+AI>Fe+AI2O3

Answers

Step 1

The reaction involved here:

3 FeO + 2 Al => 3 Fe + AI2O3 (Don't forget to completed it and balance it)

---------------

Step 2

Data provided:

125 grams of FeO react with 25.0 grams of AI

--

Data needed:

The molar masses of:

FeO) 71.8 g/mol

Al) 27.0 g/mol

Fe) 55.8 g/mol

---------------

Step 3

The limiting reactant:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

3 x 71.8 g FeO ----- 2 x 27.0 g Al

125 g FeO ----- X

X = 125 g FeO x 2 x 27.0 g Al/3 x 71.8 g FeO

X = 31.3 g Al

For 125 g of FeO, 31.3 g of Al is needed, but there is 25.0 g of Al, so the limiting reactant is Al.

-------------

Step 4

The amount of Fe produced:

By stoichiometry,

3 FeO + 2 Al => 3 Fe + AI2O3

2 x 27.0 g Al ---- 3 x 55.8 g Fe

25.0 g Al --- X = 77.5 g Fe

Answer: 77.6 g Fe (the closest value)

Determine the complete, balanced chemical reaction for the following reaction. Selenic acid (H2SeO4) is a powerful oxidizing acid and it dissolve silver and gold: Au + H2SO4 --> Au2(SeO4)3 + H2SO3 + H2O Then, proceed to answer the following questions: Reactants: Enter the coefficient number in front of Au in the reaction: | Enter the coefficient number in front of H2Se04 in the reaction: Products: Enter the coefficient number in front of Auz(SeO4)3 in the reaction: Enter the coefficient number in front of H2SeO3 in the reaction: Enter the coefficient number in front of H20 in the reaction: What type of chemical reaction is this? Enter one of the following: "synthesis", "decomposition", "single displacement", or "double displacement".

Answers

The complete, balanced chemical reaction for the reaction between gold (Au) and selenic acid (H2SeO4) is: 4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O. The coefficients for the reactants and products are as follows: 4 for Au, 3 for H2SeO4, 2 for Au2(SeO4)3, 1 for H2SO3, and 1 for H2O. The type of chemical reaction is a single displacement reaction.

The balanced chemical equation for the reaction between gold (Au) and selenic acid (H2SeO4) is:

4Au + 3H2SeO4 → 2Au2(SeO4)3 + H2SO3 + H2O

In this equation, the coefficient in front of Au is 4, indicating that 4 moles of gold are involved in the reaction. The coefficient in front of H2SeO4 is 3, indicating that 3 moles of selenic acid are present.

On the product side, the coefficient in front of Au2(SeO4)3 is 2, indicating the formation of 2 moles of gold selenate. The coefficient in front of H2SO3 is 1, representing the formation of 1 mole of sulfurous acid. The coefficient in front of H2O is also 1, indicating the production of 1 mole of water.

Based on the reactants and products involved, the type of chemical reaction is a single displacement reaction, as gold displaces hydrogen in selenic acid to form gold selenate.

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One of the products when aqueous Na, CO, reacts with aqueous
Sn(NO3), is
O a. Sn(CO3)2
O b. CNO3
O c. NaSn.
O d. NaNO3

Answers

Answer:

NaNO3

balanced equation - Na2CO3 + Sn(NO3)2 → 2NaNO3 + Sn(CO3)

Why do transition metals have similar properties in terms of electronic structure??

Why do transition metals have similar properties in terms of electronic structure??

Answers

Answer:

The reason that that elements in the same 'group' have similar chemical properties is because they have the same number of valence electrons. ... Iron when reacting in chemical reactions loses electrons from its 4s orbital instead of its d orbital

What is the answer for 250 K = ? °C

Answers

Answer:

This is your answer ☺️☺️☺️

What is the answer for 250 K = ? C

Answer:

-23.15

Explanation:

Which information best supports the idea that the universe began with rapid expansion?
O Measurements of cosmic microwave background radiation
O Measurements of rates of decay
O Calculation of the temperature and brightness of stars
Calculations of the distance from the sun to each planet

Answers

bbbbb x sidisjeiiwkwnsiwowownsxjid i’m so sorry but i need help in this one class i’m trying to get answers to hope you understand
Answer

I believe it’s A.

Explanation

Because the cosmic microwave background (CMB) is thought to be leftover radiation from the Big Bang, or the time when the universe began


The Cosmic Microwave Background radiation, or CMB for short, is a faint glow of light that fills the universe, falling on Earth from every direction with nearly uniform intensity.

What part of the plant takes up water and nutrients from the soil?

Answers

Answer:

the stem

Explanation:

yjsbsksvznzbfb

SEP Identify Limitations of a Model What is a limitation of using marbles as models
for atoms?

Answers

Answer: The major limitation of models is that they are 'idealizations' or 'simplification' of reality and thus cannot possibly replace reality.

Using marbles as models for atoms has limitations due to their inability to accurately represent the sizes, dynamic behaviors, subatomic structure, charges, masses, and energy levels that define the behavior of actual atoms.

Marbles are much larger than actual atoms, and the sizes of subatomic particles (such as protons, neutrons, and electrons) relative to the nucleus are significantly different from what marbles can portray. This size difference can lead to a distorted representation of how the subatomic particles are distributed within an atom.

Marbles are stationary objects, whereas subatomic particles within atoms are in constant motion. Electrons, for instance, move in specific energy levels around the nucleus, and their behavior is best described by quantum mechanics. Marbles cannot accurately depict this dynamic behavior.

Marbles do not allow for a visual representation of energy levels and electron orbits. Electron energy levels and their transitions play a crucial role in chemical reactions and interactions, which marbles cannot accurately depict.

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draw the lewis structure for the peroxynitrite ion, onoo−. label each atom with its state of hybridization and specify the composition of each of the different types of bond.

Answers

Lewis Structure for the peroxynitrite ion:

         O       O

            \ \     / /

             O-N-O

The hybridization of each atom is as follows:

Nitrogen (N): sp2 hybridized.

Oxygen (O): sp3 hybridized.

The composition of each bond is as follows:

Nitrogen-oxygen (N-O) bonds: These are sigma bonds.

Oxygen-oxygen (O-O) bond: This is a sigma bond.

To draw the Lewis structure of the peroxynitrite ion (ONOO-), we need to determine the arrangement of atoms and the distribution of valence electrons.

Start by identifying the central atom. In this case, the central atom is nitrogen (N) since it is less electronegative than oxygen (O).

Determine the total number of valence electrons. Nitrogen contributes 5 valence electrons, each oxygen contributes 6 valence electrons, and the negative charge adds an additional electron. So we have a total of 5 + 6 + 6 + 6 + 1 = 24 valence electrons.

Connect the atoms with single bonds. Nitrogen will form single bonds with both oxygen atoms:

             O       O

              \     /

               N

Distribute the remaining electrons around the atoms to satisfy the octet rule (except for hydrogen, which can have a duet).

a. Place two electrons on each oxygen atom to complete their octets:

             O       O

            \ \     / /

             O-N-O

b. We have used 6 electrons so far (2 on each oxygen atom). We have 24 - 6 = 18 electrons remaining.

c. Place the remaining electrons around the central nitrogen atom. Since nitrogen has 5 valence electrons, it will have 8 electrons around it (octet rule).

             O       O

            \ \     / /

             O-N-O

Check if all atoms have an octet. In this case, nitrogen has an octet, and each oxygen atom has an octet.

Finally, add the negative charge (-1) to the structure by placing the additional electron on one of the oxygen atoms:

             O       O

            \ \     / /

             O-N-O

The hybridization of each atom is as follows:

Nitrogen (N): sp2 hybridized. It forms three sigma bonds with three atoms (two oxygen and one nitrogen) and has one unhybridized p orbital containing a lone pair of electrons.

Oxygen (O): sp3 hybridized. Each oxygen atom forms one sigma bond with nitrogen and two sigma bonds with electrons in the lone pairs.

The composition of each bond is as follows:

Nitrogen-oxygen (N-O) bonds: These are sigma bonds formed by the overlap of sp2 hybrid orbitals of nitrogen and sp3 hybrid orbitals of oxygen.

Oxygen-oxygen (O-O) bond: This is a sigma bond formed by the overlap of sp3 hybrid orbitals of oxygen atoms.

It's important to note that Lewis structures provide a simplified representation of bonding and electron distribution, and the actual electronic structure may involve resonance or delocalization of electrons.

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How long should the food worker label chicken salad?.

Answers

the food worker label chicken salad as three days old according to the example given below.

In this case, the food worker should label the food as three days old. This is because food in the food industry must be labelled with the date of the oldest cooked ingredient. It would be the chicken in this case. When foods are unfrozen or cooked, microorganisms begin to grow on the surface and enzyme activity increases. This accelerates the rate at which the food spoils. According to the CDC, chicken is safe to eat up to four days after it has been cooked.

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calculate the mass of magnesium needed to make 25g of magnesium oxide​

mark brainliest of correct xx

calculate the mass of magnesium needed to make 25g of magnesium oxidemark brainliest of correct xx

Answers

Answer:

15g

Explanation:

First, you need to correct the answer to the previous question. The percentage by mass of Mg in MgO =

Mg = 24.3 amu

O = 16.0 amu

The total mass of MgO = 40.3 amu

To calculate the percent composition of Mg:

% = 24.3/40.3 x 100

% = 60

To calculate the mass of Mg needed to make 25g of MgO:

x/25g = 60%/100%

100x = (25)(60)

100x = 1500

x = 15g

there is a circular pool (1 m2 surface area) of ethylbenzene into a room (4 m × 4 m × 2.45 m) where the temperature is 80 f and the ventilation produces an air velocity of 0.5 m/s. calculate the concentration in the room under average and poor ventilation conditions and compare the results to the osha pel.

Answers

The PEL is usually given in units of parts per million (ppm) or milligrams per cubic meter (mg/m³). With the PEL value, we can compare it to the calculated concentrations to determine if they are within acceptable limits.

To calculate the concentration of ethylbenzene in the room, we need to use the formula for concentration, which is the amount of substance divided by the volume of the room.

First, let's calculate the volume of the room:
Volume = length × width × height
Volume = 4 m × 4 m × 2.45 m
Volume = 39.2 m³

Now, let's calculate the amount of substance:
Amount of substance = surface area of circular pool × height of ethylbenzene
Amount of substance = 1 m² × height of ethylbenzene

Since we don't know the height of ethylbenzene in the pool, we cannot calculate the exact amount of substance. However, we can still compare the concentrations under different ventilation conditions.

For average ventilation:
Concentration = Amount of substance / Volume
Concentration (average ventilation) = (Amount of substance under average ventilation) / 39.2 m³

For poor ventilation:
Concentration (poor ventilation) = (Amount of substance under poor ventilation) / 39.2 m³

To compare the results to the OSHA PEL (Permissible Exposure Limit), we would need to know the specific PEL for ethylbenzene. The PEL is usually given in units of parts per million (ppm) or milligrams per cubic meter (mg/m³). With the PEL value, we can compare it to the calculated concentrations to determine if they are within acceptable limits.

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Under average ventilation conditions, the concentration of ethylbenzene in the room can be calculated using the given information about the pool and the room's volume. However, without information on air velocity, we cannot determine the concentration under poor ventilation conditions or compare the results to the OSHA PEL (Permissible Exposure Limit) for ethylbenzene.

The concentration of ethylbenzene in the room can be calculated using the formula: Concentration = mass of ethylbenzene / volume of room.
1. Calculate the mass of ethylbenzene:
The surface area of the circular pool is 1 m2. Since the pool is circular, we can assume it has a diameter of 1 meter. To find the volume of ethylbenzene in the pool, we can use the formula for the volume of a cylinder: \(Volume = \pi * r^2 * h\), where r is the radius (0.5 meters) and h is the height (unknown). Since the surface area of the pool is 1 m2, the height can be calculated as follows: 1 \(m2 = \pi * (0.5 m)^2 * h\). Solving for h, we get h = 1.273 m. Now we can calculate the mass of ethylbenzene using the density of ethylbenzene, which is approximately 867 kg/m3: \(Mass = density * volume = 867 kg/m3 * (\pi * (0.5 m)^2 * 1.273 m)\).
2. Calculate the volume of the room:
The volume of the room is given as 4 m × 4 m × 2.45 m = 39.2 m3.
3. Calculate the concentration under average ventilation conditions:
Concentration = mass of ethylbenzene / volume of room.
4. Calculate the concentration under poor ventilation conditions:
To calculate the concentration under poor ventilation conditions, we need to take into account the air velocity. A higher air velocity will result in a higher dilution of the ethylbenzene. However, since the question does not provide any information on the effect of air velocity on the dilution, we cannot calculate the concentration under poor ventilation conditions without more information.
To compare the results to the OSHA PEL (Permissible Exposure Limit), we would need to know the specific PEL value for ethylbenzene, which is not provided in the question.
In conclusion, we can calculate the concentration of ethylbenzene in the room under average ventilation conditions, but we cannot calculate the concentration under poor ventilation conditions or compare the results to the OSHA PEL.

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Please! Compose structural formulas: a) two closest homologues of propanol; b) two isomers of pentanol according to the position of the multiple bond.

Answers

The structural formula of a chemical compound is a graphic representation of the molecular structure, which shows how atoms are arranged or spatially distributed. The chemical bonds within the molecule are shown, either explicitly or implicitly.

a) If we look at the structure of propanol then it is having single bonds with one alcohol (OH) group. In such a case, the closest homologues which cab be formed will be ketone and aldehyde.

b) Isomers can be of different types. In this the structural formula is talked about so we will take into account only about the structural isomer. Structural isomer is the arrangement of compound in which the number of bonds and elements remains same but the structure is different. In propanol, the OH group can come in the mid carbon and that carbon can also have a methyl group attached to it.

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Question 1
Which words in the passage help the reader understand the meaning of the word avid in the first paragraph?

A. What he found out
B. Many hours gardening
C.the curious and observant
D.he noticed

Answers

C.) is the answer thx!!!


SCIENCE I NEED HELP ASAP⭐️⚡️

SCIENCE I NEED HELP ASAP

Answers

Answer:

plants

Explanation:

A sample of oxygen at 45 degrees Celsius occupies 839 mL. If this sample later occupies 1032 mL at 58 degrees Celsius and 1.9 atm, what was its original pressure?
Answer in atm

Answers

Answer:

1.3 atm

Explanation:

To solve this problem, we can use the combined gas law, which relates the pressure, volume, and temperature of a gas:

(P1 x V1) / (T1) = (P2 x V2) / (T2)

where P1, V1, and T1 are the initial pressure, volume, and temperature of the gas, and P2, V2, and T2 are the final pressure, volume, and temperature of the gas.

We are given:

P1 is what we want to find

V1 = 839 mL

T1 = 45 degrees Celsius = 318 K

V2 = 1032 mL

T2 = 58 degrees Celsius = 331 K

P2 = 1.9 atm

Plugging these values into the formula, we get:

(P1 x 839 mL) / (318 K) = (1.9 atm x 1032 mL) / (331 K)

Simplifying and solving for P1, we get:

P1 = (1.9 atm x 1032 mL x 318 K) / (839 mL x 331 K)

P1 = 1.3 atm (rounded to one decimal place)

Therefore, the original pressure of the oxygen sample was 1.3 atm.

15 pts! Explain how the absorption of energy (heating) affects the speed of the particles in a substance.

Answers

Answer:

See explanation

Explanation:

Temperature has been severally defined as the measure of the average kinetic energy of the molecules of a body. Heat is a form of energy that exists due to temperature difference.

Given a body whose molecules has a speed = (3RT/M)^1/2; this implies that for a given mass of the substance, the velocity of its particles depends on the temperature of the substance.

However, absorption of heat increases the temperature of the body. Therefore, when heat is absorbed, the temperature increases and the speed of the particles of a substance increases according to the relation above.

the difference in electronegativity signifies that the hydrogen-oxygen bond is blank.target 2 of 10

Answers

The hydrogen-oxygen bond is ionic 3 because to the difference in electronegativity.

Why is electronegativity essential and what does it mean?

The capacity of such an atom to draw protons (or electronic structure) to itself is measured by its electropositive. It controls the distribution of the shared energy between two molecules in a bond. The bigger an atom's electropositive, the more aggressively it will draw electrons from its bonds.

High electronegativity: What does that mean?

The capacity of an element to draw electron density in a covalent connection is referred to as electron affinity. The stronger a material attracts other shared electrons, the greater its degree of electronegativity.

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A sheet of aluminium foil is held in front of a radioactive source. Two types of radiation are detected on the other side. What type of radiation will not be detected?.

Answers

When a radioactive source is in front of a plate of aluminum foil. On the opposite side, radiation of two different sorts is found. There won't be any indication of the alpha particle radiation.

What does "radioactive source" mean?

A known volume of a radionuclide that emits ionizing radiation—typically gamma radiation, alpha particles, beta particles, including neutron radiation—is referred to as a radioactive source.

What are the uses of radioactive sources?

The NHS, paper and steel manufacture, food irradiation, medical sterilization, the construction industry, and oil and gas exploration are just a few of the businesses that heavily utilize radioactive sources.

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If a ailor exhale 145. 0 mL of CO2 per minute at 22. 0°C and 0. 830 atm, what ma of odium peroxide i needed per ailor in a 24-hour period?

Answers

The amount of sodium peroxide needed per sailor in a 24-hour period is 7.68 moles.

What is sodium peroxide?
The solid form of sodium peroxide is a yellow-white to yellow granular substance. Combustible material-containing mixtures are easily ignited by friction, heat, as well as moisture contact. Under prolonged heat exposure, they might quickly decompose and rupture the containers.

The amount of sodium peroxide needed per sailor in a 24-hour period can be calculated using the ideal gas law. This law states that the product of pressure, volume, and temperature is equal to the product of the number of moles of a gas and the gas constant (R).

Therefore, we can rearrange the ideal gas law and solve for the number of moles of CO2 exhaled per minute:
(P x V x T) ÷ R = n
(0.830 atm x 145.0 mL x 22.0°C) ÷ 8.314 J/mol/K = 0.0052 moles CO2/min
To calculate the amount of sodium peroxide needed per sailor in a 24-hour period, we need to multiply the number of moles of CO2 exhaled per minute by the number of minutes in a 24-hour period (1440 minutes).

0.0052 moles CO2/min x 1440 minutes = 7.68 moles sodium peroxide/24 hours
Therefore, the amount of sodium peroxide needed per sailor in a 24-hour period is 7.68 moles.

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Given the chart of bond energies, calculate the enthalpy change for the reaction below. Show all work to receive full credit.

Answers

I'm sorry, but I cannot see the chart of bond energies that you are referring to. Can you please provide the reaction or the chart so that I can help you with the calculation?

Question: Which is the best analogy for classification? A.Classification is like setting up a phone tree in which one person calls the next two people, and those people call the next four people. B.Classification is like creating an alphabetized list of people based on their last names. C.Classification is like organizing a car wash where everyone brings needed items and then works. D.Classification is like organizing a closet by hanging clothes together based on their type, color, and season. *15 points cuz i'm low on points oof* *science NOT chemistry*

Answers

Answer:

The last one

Explanation:

When we are classifying we try to distinguish between the type, the properties just like clothes

Why is lead(II) nitrate: “Pb(NO3)2” and not “Pb3NO2”?

Just a bit confused because it looks a bit funny compared to how I learned how to write compounds.

Answers

Explanation:

this is because the combining capacity, ie valency, of Pb is 2 of which NO3 is 1. So, when they will combine by cross method, the compound become Pb(NO3)2 (lead II nitrate).

hope this helps you.

A sample of nitrogen gas is produced in a reaction and collected under water in a graduated cylinder. The temperature is 26.0 oC and the volume of the gas is 45.7 mL. During the experiment, the total pressure in the graduated cylinder is 757 mmHg. How many grams of nitrogen were collected

Answers

During the experiment, the total pressure in the graduated cylinder is 757 mmHg, and 0.0421 grams of nitrogen is collected.

To solve this problem, we need to use the ideal gas law equation: PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the gas constant, and T is the temperature.

First, we need to convert the temperature from Celsius to Kelvin:
T = 26.0 + 273.15 = 299.15 K

Next, we need to convert the pressure from mmHg to atm:
P = 757 mmHg / 760 mmHg/atm = 0.995 atm

Now we can rearrange the ideal gas law equation to solve for n, the number of moles of nitrogen gas:
n = PV/RT

Plugging in the given values, we get:
n = (0.995 atm)(0.0457 L)/(0.0821 L·atm/mol·K)(299.15 K) = 0.00150 moles of nitrogen gas

Finally, we can use the molar mass of nitrogen (28.01 g/mol) to convert moles to grams:
grams of nitrogen = 0.00150 moles x 28.01 g/mol = 0.0421 g

Therefore, 0.0421 grams of nitrogen were collected.

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Aaron bought a set of plastic ice cubes with a mixture of water and air inside. 2 rectangular pyramids are stacked on the bases. The pyramid has a rectangular base of 15 millimeters by 20 millimeters, and a height of 30 millimeters. What volume of water and air is inside each of the plastic ice cubes

Answers

The volume of water and air inside each plastic ice cube is **600 cubic millimeters**. The pyramid has a **rectangular base** of 15 millimeters by 20 millimeters and a height of 30 millimeters.

To find the volume of a single rectangular pyramid, we can use the formula: Volume = (1/3) * Base Area * Height. In this case, the base area is 15 millimeters * 20 millimeters = 300 square millimeters, and the height is 30 millimeters. So, the volume of one pyramid is (1/3) * 300 * 30 = 3000 cubic millimeters. Since there are 2 rectangular pyramids stacked on their bases inside the plastic ice cube, the total volume of water and air inside each ice cube is 3000 / 2 = **600 cubic millimeters**.

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You have a sample of a polymer based material that you are asked to characterize. Explain, briefly, how you would determine 1) if the polymer is in fact a thermoset, 2) how much filler is in it and 3) what the filler is, 4) what antioxidants and UV absorbents are present and in what quantity, 5) if there is dye or pigment coloring the material and whether or not it is the filler, and 6) how you would identify what thermoset it is. If you propose using an instrument or technique you need to specify what you will be measuring and how it will provide the required information.

Answers

A polymer-based material can be characterized using various techniques and instruments.

Here's how to determine whether the polymer is a thermoset, the amount of filler present in it, what the filler is, and the quantity of antioxidants and UV absorbents present:

1. To determine if the polymer is a thermoset, heat it. Thermosets don't melt, but thermoplastics do.

2. To determine the amount of filler in the polymer, weigh a sample of the polymer and then burn it. The residue will be the filler. Subtract the residue's mass from the polymer's initial weight to determine the filler's weight.

3. To determine what filler is present, observe the residue after burning.

4. UV absorbents can be detected using UV-Vis Spectroscopy, while antioxidants can be determined using FTIR Spectroscopy.

5. To determine if the material has dye or pigment coloring, use colorimetry to measure its color, then compare it to the reference color of the polymer. If the color is different, it has dye or pigment coloring.

6. The polymer's thermoset can be identified using Differential Scanning Calorimetry (DSC) to examine the melting temperature, which is unique to each thermoset.

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