Answer:
To solve this problem, we can use the formula:
time = distance / speed
where distance is the distance between you and the source of the sound, and speed is the speed of sound.
In this case, the distance is 3400m and the speed of sound is 340 m/s. So, we have:
time = 3400m / 340 m/s = 10 seconds
Therefore, it will take 10 seconds for the sound of the explosion to reach you.
Two objects with the same mass and same speed, but moving in opposite directions, have the same kinetic energy. Explain why this is true. A. Kinetic energy changes as an object falls in a gravitational field. B. Kinetic energy has units of joules. C. Kinetic energy is a scalar quantity that depends only on the speed but not direction of velocity. D. It is false. The two objects have opposite kinetic energies
We are given that two objects of same mass have the same velocity but in opposite directions. The kinetic energy of each object is given by:
\(K=\frac{1}{2}mv^2\)Where:
\(\begin{gathered} m=\text{ mass} \\ v=\text{ magnitude of velocity} \end{gathered}\)Since the kinetic energy depends on the mass and the magnitude of the velocity, this means that the object will have the same kinetic energy regardless of the direction of the velocity. Therefore, option C is correct.
What is the magnetic force on a 2.0-m length of (straight) wire carrying a current of 30 A in a region where a uniform magnetic field has a magnitude of 55 mT and is directed at an angle of 20° away from the wire?
To determine the magnetic force on a straight wire carrying a current in a uniform magnetic field, we can use the formula for the magnetic force:
F = I * L * B * sin(θ)
where:
F is the magnetic force,
I is the current in the wire,
L is the length of the wire,
B is the magnitude of the magnetic field, and
θ is the angle between the wire and the magnetic field.
In this case, the values are:
I = 30 A (current in the wire)
L = 2.0 m (length of the wire)
B = 55 mT = 0.055 T (magnitude of the magnetic field)
θ = 20° (angle between the wire and the magnetic field)
Substituting the values into the formula:
F = 30 A * 2.0 m * 0.055 T * sin(20°)
Calculating sin(20°):
F = 30 A * 2.0 m * 0.055 T * 0.3420
F ≈ 1.5714 N
Therefore, the magnetic force on the 2.0-meter length of wire carrying a current of 30 A in a region with a uniform magnetic field of magnitude 55 mT and at an angle of 20° away from the wire is approximately 1.5714 N.
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identify impacts of air pollution
Answer:
Explanation:
High levels of air pollution can cause an increased risk of heart attack, wheezing, coughing, and breathing problems, and irritation of the eyes, nose, and throat. Air pollution can also cause worsening of existing heart problems, asthma, and other lung complications.
Ambient air pollution accounts for an estimated 4.2 million deaths per year due to stroke, heart disease, lung cancer and chronic respiratory diseases. Around 91% of the world's population lives in places where air quality levels exceed WHO limits.
Serious Effects of Pollution on Our Humans and Environment
Environment Degradation. The environment is the first casualty for the increase in pollution weather in air or water. ...
Human Health. ...
Global Warming. ...
Ozone Layer Depletion. ...
Infertile Land.
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Miss Hawaii
When astronomers look at stars outside of our galaxy, they have noticed that the color of the stars appears to be shifted slightly to the red end of the visible spectrum; this means that the wavelength of the light coming from those distant stars is longer than expected. If this red shift is assumed to be caused by the relative motion of the stars, what does that tell us about their movement?
They are moving toward the Earth.
They are moving away from the Earth.
They are not moving relative to the Earth.
Both the Earth and the star are stationary.
Answer:
moving away
Explanation:
They are moving AWAY from earth making the wavelengths longer than what was emitted....this is called 'Red Shift'.... longer waves is a shift toward the RED end of the spectrum .. (ROY G BIV)
Two cars are traveling toward one another with the same speed of 20 m/s and collide head-on. Car 1 (traveling from left to right) has a mass of 2000 kg. Car 2 (traveling from right to left) has a mass of 3000 kg. If the collision is perfectly inelastic, what is the velocity of car 1 after the collision?
Question 2 options:
2 m/s, moving to the right.
3.33 m/s, moving to the right.
4 m/s, moving to the left.
6.67 m/s, moving to the left
None of the above.
Answer:
Answer number 3
Explanation:
REALLY HOPE im right:)
What is the mass of the cannon
Mass cannonball = 5Kg
Velocity of the fired cannonball = 90m/s
Velocity of the cannon = -2.25m/s
Mass of the cannon will be 200 kg
m1 = mass of cannonball
m2 = mass of cannon
u1 = initial velocity of cannonball
u2 = initial velocity of cannon
v1 = final velocity of cannonball
v2 = final velocity of cannon
using conservation of momentum
m1u1 + m2u2 = m1v1 + m2v2
5 * 0 + m2 * 0 = 5 * 90 + m2 * -2.25
m2 = 200 kg
mass of the cannon will be 200 kg
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BRAINLIEST PLZ HELP!
Accuracy is judged by Select one: a. how close a value is to the true value. b. the precision of the tool used for measurement. c. the reputation of the scientist. d. None of the options
Question 3 of 10
The Moon has much less gravitational force than Earth. What would happen
if you went to the Moon?
OA. Your mass would decrease.
O
B. Your weight would increase.
O
C. Your mass would increase.
O
D. Your weight would decrease.
SUBMIT
Answer:
D
Explanation:
Mass is the amount of matter your body has ....does not change on the Moon.
there is less gravity .....so your WEIGHT would decrease
A 40 kg rock is rolling toward a town at 4 m/s after an earthquake. Calculate the KE.
Be sure to show your work and include units!
Use the formula KE = 1/2mv2 will brainlist
Answer:
320 J
Explanation:
From the question,
KE = 1/2mv².................. Equation 1
Where KE = Kinetic Energy, m = mass of the rock, v = velocity of the rock
Given: m = 40 kg, v = 4m/s
Substitute these values into equation 1
KE = 1/2(40)(4²)
KE = 20×16
KE = 320 J
Hence the kinetic energy of the rock is 320 J
A garden hose attached with a nozzle is used to fill a 20-gallon bucket. The inner diameter of the hose is 1 inch and it reduces to 0.5 inch at the nozzle exit. If the average velocity in the hose is 8ft/s, determine (a) the volume and mass flow rates of water through the hose (4-point), (b) how long it will take to fill the bucket with water (3-point), and (c) the average velocity of water at the nozzle exit (3-point).
Answer:
a. i. 0.044 ft³/s ii. 2.75 lb/s
b. 62.3 s
c. 32 ft/s
Explanation:
(a) the volume and mass flow rates of water through the hose
i. The volume flow rate
The volume flow rate, Q = Av where A = cross-sectional area of nozzle at inlet = πd²/4 where r = diameter of nozzle at inlet = 1 inch = 1/12 ft and v = average velocity in the nozzle = 8 ft/s.
So, Q = Av
= πd²v/4
= π(1/12 ft)² × 8 ft/s/4
= 0.175/4 ft³/s
= 0.044 ft³/s
ii. The mass flow rate
The mass flow rate, M = ρQ where ρ = density of water = 62.4 lb/ft³ and Q = volume flow rate = 0.044 ft³/s
So, M = ρQ
= 62.4 lb/ft³ × 0.044 ft³/s
= 2.745 lb/s
≅ 2.75 lb/s
(b) how long it will take to fill the bucket with water
Since we have 20 gallons = 20 × 1 gallon, we convert if to cubic feet. So, 20 gallons = 20 × 1 gallon = 20 × 0.137 ft³ = 2.74 ft³.
Since V = Qt where V = volume, Q = volume flow rate and t = time, making t subject of the formula, we have
t = V/Q
= 2.74 ft³/0.044 ft³/s
= 62.27 s
≅ 62.3 s
(c) the average velocity of water at the nozzle exit
Using the continuity equation,
A₁v₁ = A₂v₂ where A₁ = cross-sectional area of nozzle at inlet = πd₁²/4 where d₁ = diameter of nozzle at inlet = 1 inch = 1/12 ft, v₁ = average velocity in the nozzle = 8 ft/s, A₂ = cross-sectional area of nozzle at inlet = πd₂²/4 where d₂ = diameter of nozzle at inlet = 0.5 inch = 0.5/12 ft, v₂ = average velocity at exit nozzle.
So, A₁v₁ = A₂v₂
(πd₁²/4)v₁ = (πd₂²/4)v₂
πd₁²v₁/4 = πd₂²v₂/4
Dividing through by π/4. we have
So, d₁²v₁ = d₂²v₂
making v₂ subject of the formula, we have
v₂ = d₁²v₁/d₂²
v₂ = (d₁²/d₂²)v₁
v₂ = (d₁/d₂)²v₁
substituting the values of the variables into the equation, we have
v₂ = (1/0.5)² × 8 ft/s
v₂ = (2)² × 8 ft/s
v₂ = 4 × 8 ft/s
v₂ = 32 ft/s
in each of the images, two blocks are attached to a balance. Use the position and size of the blocks to determine which block is more dense in each image.
A scale weighs two boxes. The green box on the left has a large volume and pulls lower on the scale. The blue box on the right has a smaller volume and is higher on the scale.
Which block is more dense in the first image?
Which block is more dense in the second image?
Which block is more dense in the third image?
First image: Green block is larger and heavier than the blue block.
Second image: Blue and green block are the same size, but blue is heavier
Third image: Green block is smaller and heavier than the blue block
It is impossible to estimate the relative density of the blocks. The rightmost blue chunk is denser. The chunk of green on the left is denser. The mass of a material per unit volume is the definition of density.
Describe density with an example:Its density refers to how much material can fit into a specific quantity of space. For instance, a block of lead (Pb), which is heavier and less durable, will have a lower density than a block of gold (Au), which is stronger and lighter (Au).
Mass and density: what are they?The term "mass" refers to a thing's total amount of matter. The term "density" describes how tightly atoms are packed or how close together they are in a material. To calculate inertia, utilize the idea of mass.
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what is the most effortless walking speed for a person with 90cm long legs if the length of each step is 90cm
Answer:
75 cm/second.
Explanation:
Formula:
Walking speed = stride length / time per step
Walking speed = 90cm/time per step
= 90cm/1.2 seconds (a common estimate time per step)
= 75cm/second.
1. What is transferred from place to place by waves?
Answer:
Energy
Explanation:
A wave is a disturbance that transfers energy from one place to another without transferring matter. Waves transfer energy away from the source, or starting place, of the energy.
(a) Express the following in their respective units
12nm to pm
Answer:
To convert nanometers (nm) to picometers (pm), you need to multiply the value by 1,000. Therefore, to convert 12 nanometers to picometers, you would perform the following calculation:
12 nm * 1,000 pm/nm = 12,000 pm
So, 12 nanometers is equal to 12,000 picometers.
The figure(Figure 1) is a graph of Ex. The potential at the origin is -180 V . What is the potential at x=3.0m?
The electric potential at x=3.0m is - 180 Volt according to the figure 1.
What is electric field?An electric field is a physical field that surrounds electrically charged particles and acts as an attractor or repellent to all other charged particles in the vicinity. Additionally, it refers to a system of charged particles' physical field.
Electric charges and time-varying electric currents are the building blocks of electric fields.
The electric potential at x=3.0m is given by = initial potential energy + electric field× distance
= - 180 Volt + 0 Volt/meter×3 meter
= - 180 Volt.
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In a DC generator, the generated emf is directly proportional to the
In a DC generator, the generated electromotive force (emf) is directly proportional to the rotational speed of the generator's armature and the strength of the magnetic field within the generator.
This relationship is described by the equation for the generated emf in a DC generator:
Emf = Φ * N * A * Z / 60
Where:
Emf is the generated electromotive force (in volts),
Φ is the magnetic flux density (in Weber/meter^2\(meter^2\) or Tesla),
N is the number of turns in the armature winding,
A is the effective area of the armature coil (in square meters),
Z is the total number of armature conductors, and
60 is a constant representing the conversion from seconds to minutes.
From this equation, we can see that the generated emf is directly proportional to the magnetic flux density (Φ) and the product of the number of turns (N), effective area (A), and the total number of armature conductors (Z). This means that increasing any of these factors will result in a higher generated emf.
The magnetic flux density (Φ) can be increased by using stronger permanent magnets or increasing the strength of the field windings in the generator.
The number of turns (N) and the effective area (A) are design parameters and can be optimized for a specific generator. Increasing the number of turns or the effective area will result in a higher generated emf.
Similarly, the total number of armature conductors (Z) can be increased to enhance the generated emf.
By controlling and optimizing these factors, the generated emf in a DC generator can be increased, resulting in higher electrical output. However, it is important to note that there are practical limits to these factors based on the design and construction of the generator.
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In Figure 4.27 four particles form a square of edge length
a=5cm and have charges q1=+10nc, q2=-20nc,q3 = +20nc, q4=-10.0nc. In unit-rector notation, what net
electric field do the particles produce at the centre of square?
Answer:
so sorry
don't know but please mark me as brainliest please
If you drop an egg off of the Empire State Building, which of the following things will happen first?
O The egg will appear to hover
O Gravity and drag will fall into balance
O Drag will increase
O The net force will be zero
Collision practice
Running at 2.0 m/s, Bruce, the 45.0-kg quarterback, collides with Biff, the 90.0 kg tackle, who is traveling at 7.0 m/s in the other direction. Upon collision,
Biff wraps up Biff for the tackle. What is the resultant velocity of the players.
V=————— m/s
Answer:
\(v_f=4\:\mathrm{m/s\: in\:Biff's\:direction}\)
Explanation:
Using the Law of Conservation of Momentum, we can set up the following equation:
\(m_2v_2-m_1v_1=m_fv_f\), where \(m_1v_1\) is Bruce's momentum and \(m_2v_2\).
Plugging in given values, we get:
\(90\cdot7-45\cdot2=(90+45)v_f, \\v_f=\frac{540}{135}=\fbox{$4\:\mathrm{m/s}$}\).
Object 1 with mass 1=3.25 kg
is held in place on an inclined plane that makes an angle
of 40.0∘
with the horizontal. The coefficient of kinetic friction between the plane and the object is 0.535.
Object 2 with mass 2=4.75 kg
is connected to object 1 with a massless string over a massless, frictionless pulley. The objects are then released.
Calculate the magnitude
of the initial acceleration.
Calculate the magnitude
of the tension in the string once the objects are released.
The magnitude of the initial acceleration of the object is 4.2 m/s².
The tension in the string once the object starts moving is 13.65 N.
What is the magnitude of the initial acceleration?The magnitude of the initial acceleration of the object is calculated by applying Newton's second law of motion as follows;
F(net) = ma
m₂g - μm₁g cosθ = a(m₁ + m₂)
where;
m₁ and m₂ are the masses of the blocksg is acceleration due to gravityμ is coefficient of frictionθ is the angle of inclinationa is the acceleration(4.75 x 9.8) - (0.535 x 3.25 x 9.8 x cos40) = a(3.25 + 4.75)
33.5 = 8a
a = 33.5/8
a = 4.2 m/s²
The tension in the string once the object starts moving is calculated as;
T = m₁a
T = 3.25 x 4.2
T = 13.65 N
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The mass of 12 protons is approximately equal to ?
1 atomic mass unit
12 atomic mass units
The mass of 1 electron
The mass of 12 electrons
Answer:
Option 1, 1 atomic mass unit
1. Explain home a dial test indicator (DTI) reading is adjusted when the gange is not positioned at right angle to the contact surface.
When using a dial test indicator (DTI), it is essential to ensure that the gauge is positioned at a right angle to the contact surface for accurate readings.
However, in certain situations, it may be challenging to achieve a perfect right angle alignment. In such cases, adjustments can be made to compensate for the misalignment and obtain accurate measurements.To adjust the DTI reading when the gauge is not positioned at a right angle to the contact surface, the following steps can be taken:Determine the misalignment angle: Measure the angle at which the DTI is misaligned from the right angle position. This can be done using a protractor or by estimating the deviation visually.Calculate the correction factor: Based on the misalignment angle, calculate the correction factor using trigonometric functions such as sine or cosine. The correction factor accounts for the difference between the actual displacement and the displacement measured by the DTI.Apply the correction factor: Multiply the correction factor by the DTI reading to adjust the measurement. This compensates for the misalignment and provides a more accurate reading.It's important to note that adjusting the DTI reading can introduce some degree of error, especially if the misalignment is significant. Therefore, it is always preferable to position the gauge at a right angle to the contact surface whenever possible to obtain the most precise measurements.
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A small stone is kicked from the edge of a cliff. Its x- and y-coordinates as functions of time are given by x = 16.4t and y = 3.80t − 4.90t2, where x and y are in meters and t is in seconds. (Do not include units in your answer.)
(a) Write a vector expression for the stone's position as a function of time (in m), using the unit vectors î and ĵ. (Give the answer in terms of t.)
(b)Obtain the expression for the velocity vector v as a function of time (in m/s). (Give the answers in terms of t.)
(c) Obtain the expression for the acceleration vector a as a function of time (in m/s2). (d)Next, use unit-vector notation to write expressions for the position, the velocity, and the acceleration of the stone at t = 2.88 s. (Assume the position is in m, the velocity is in m/s and the acceleration is in m/s2.)
(a) Position vector expression ⇒ r = 16.4t i + ( 3.8t - 4.9t² ) j m
(b) Velocity vector expression ⇒ v = 16.4 i + ( 3.8 - 9.8t ) j m/s
(c) Acceleration vector expression ⇒ a = - 9.8 j m/s²
x-coordinate ⇒ x = 16.4t
y-coordinate ⇒ y = 3.8t - 4.9t²
(a) Position vector expression ⇒ r = 16.4t i + ( 3.8t - 4.9t² ) j m
(b) Velocity is the rate of change of position with respect to time. So differentiating the position vector expression,
v = dr / dt = d / dt [ 16.4t i + ( 3.8t - 4.9t² ) j ]
v = 16.4 i + ( 3.8 - 2 * 4.9 * t ) j
v = 16.4 i + ( 3.8 - 9.8t ) j m/s
(c) Acceleration is the rate of change of velocity with respect to time. So differentiating the velocity vector expression,
a = dv / dt = d / dt [ 16.4 i + ( 3.8 - 9.8t ) j ]
a= 0 i + ( 0 - 9.8 ) j
a = - 9.8 j m / s²
(d) t = 2.88 s
r ( 2.88 s ) = 16.4 ( 2.88 ) i + ( 3.8 * 2.88 - 4.9 ( 2.88 )² ) j
r ( 2.88 s ) = 47.23 i - 29.7 j m
v ( 2.88 s ) = 16.4 i + ( 3.8 - 9.8 * 2.88 ) j
v ( 2.88 s ) = 16.4 i - 24.42 j m / s
a ( 2.88 s ) = - 9.8 j m / s²
Therefore, the required vectors are as follows
(a) Position vector expression ⇒ r = 16.4t i + ( 3.8t - 4.9t² ) j m
(b) Velocity vector expression ⇒ v = 16.4 i + ( 3.8 - 9.8t ) j m/s
(c) Acceleration vector expression ⇒ a = - 9.8 j m/s²
(d) r ( 2.88 s ) = 47.23 i - 29.7 j m
v ( 2.88 s ) = 16.4 i - 24.42 j m / s
a ( 2.88 s ) = - 9.8 j m / s²
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The atomic of nitrogen is 7. The number of electrons a neutral atom has is_, and its atomic mass is approximately_amu.
A falling 0.60 kg object experiences a frictional force due to air resistance of 1.5 N. What is the object's acceleration?
Answer:
7.5 m/s².
Explanation:
From the question given above, the following data were:
Mass (m) of object = 0.6 Kg
Force of friction (Fբ) = 1.5 N
Acceleration (a) =?
Next, we shall determine the force of gravity on the object. This can be obtained as follow:
Mass (m) of object = 0.6 Kg
Acceleration due to gravity (g) = 10 m/s²
Force of gravity (F₉) =?
F₉ = mg
F₉ = 0.6 × 10
F₉ = 6 N
Next, we shall determine the net force acting on the object. This can be obtained as follow:
Force of friction (Fբ) = 1.5 N
Force of gravity (F₉) = 6 N
Net force (Fₙ) =?
Fₙ = F₉ – Fբ
Fₙ = 6 – 1.5
Fₙ = 4.5 N
Finally, we shall determine the acceleration of the object. This can be obtained as follow:
Mass (m) of object = 0.6 Kg
Net force (Fₙ) = 4.5 N
Acceleration (a) of object =?
Fₙ = ma
4.5 = 0.6 × a
Divide both side by 0.6
a = 4.5 / 0.6
a = 7.5 m/s²
Therefore, the acceleration of the object is 7.5 m/s²
Under what conditions does moving electric charge produce a magnetic force
in a copper wire?
A. Under any conditions
B. Only when the wire is connected to the magnet
C. Only when the wire is wrapped around an iron bar
D. Only when the wire is coiled
Answer:
I'm pretty sure that the answer is C. Hope this helps.
Explanation:
Answer:
Answer is A. Under any conditions
Explanation:
Just got it correct on A p e x
A box slides to the right along a horizontal surface which is true about the friction force
It act perpendicular to the surface and is determined by the speed of the box
It is a force in the direction of the motion that allows the box to move
It is a force that is determined by the normal force in the acts in opposition to the direction of motion
It is a force that is determined by the surface area of contact and ask opposite the direction of motion
Answer:
It is a force in the direction of the motion that allows the box to move
Explanation:
Compare sound and earthquake waves
When materials vibrate, waves are created that travel through the substance, and this energy is what we hear as sound. Earthquakes are earth vibrations that cause the (potential) energy held within rocks to be released (as a result of their pressure-generating relative positions). Seismic waves are produced by earthquakes.
How do sound waves and earthquakes compare?
The waves lose energy as they move through the air with sound or through the ground with shaking during an earthquake. Therefore, a band can be heard louder close to the stage than farther away, and an earthquake can be felt more strongly close to the fault than farther away.
In actuality, sound in the air cannot match how quickly earthquake waves move. In rock, the compressional or "P" wave of an earthquake moves at the In actuality, sound in the air cannot match how quickly earthquake waves move. The speed of a P wave is typically 10,000 mph. The speed of sound through air is roughly 750 mph.
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What are the benefits of evolution for the human population?
Answer:
I hope you fall down a 40 floor hotel resort onto the porch, and explode into the gushing body you are!
Explanation:
Assume that a car with a full tank of gasoline is closed system. Which two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same? The car's engine makes sounds as it runs. The car's engine gets hot as it burns gasoline. The car remains full of gasoline if its engine stays off. The car uses more gasoline as it goes faster.
The two evidence are the car's engine gets hot as it burns gasoline are the car remains full of gasoline if its engine stays off.
Which two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same?The car's engine gets hot as it burns gasoline and the car remains full of gasoline if its engine stays off are the two pieces of evidence support the conclusion that the total amount of energy in a close system remains the same because when the gasoline burns, the engine gets hotter and when the car remains full of gasoline if its engine stays off which means no energy leaves the system.
So we can conclude that The two evidence are the car's engine gets hot as it burns gasoline are the car remains full of gasoline if its engine stays off.
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