To remove an ice plug from a production pipe, you can follow these general steps:
Safety precautions: Ensure you are wearing appropriate personal protective equipment (PPE) such as gloves and eye protection. Ice removal procedures can involve using sharp tools or applying pressure, so safety is paramount.
Identify the location of the ice plug: Determine the exact location of the ice plug in the production pipe. This information will help you plan the removal procedure effectively.
Thawing the ice plug: There are several methods to thaw the ice plug, depending on the circumstances and available resources. Here are a few commonly used techniques:
a. Heat application: Use a heat source such as a heat gun or an electric heat blanket to warm the pipe and melt the ice. Be cautious not to apply excessive heat, as it could damage the pipe or create safety hazards.
b. Hot water circulation: If possible, circulate hot water through the pipe to gradually melt the ice plug. This method is often used when dealing with larger ice blockages.
c. Steam injection: Injecting steam into the pipe can provide efficient heat transfer and accelerate the melting process. However, this method requires specialized equipment and should be performed by trained personnel.
d. Chemical agents: In some cases, specific chemicals may be used to lower the freezing point of the ice or promote melting. However, this method should be used cautiously, considering the potential environmental impact and the compatibility of chemicals with the pipe material.
Monitor progress: As you apply the thawing method, periodically check the pipe to monitor the progress. Be patient and avoid using excessive force, as sudden releases of pressure can be hazardous.
Assist the melting process: To expedite the melting of the ice plug, you can gently tap the pipe or use non-abrasive tools to break up any loose ice. This can help facilitate the flow of water and aid the thawing process.
Maintain a controlled environment: If possible, create a controlled environment around the affected pipe section. Insulating the pipe or providing external heat sources can help maintain a higher temperature and prevent further freezing.
Resume production: Once the ice plug has completely melted, inspect the pipe for any damage or residual ice fragments. Ensure the pipe is clear before resuming production.
It is important to note that the specific procedure may vary depending on the size and material of the production pipe, as well as the available resources and safety protocols. When dealing with critical systems or complex ice plug situations, it is advisable to consult with experts or professionals with experience in ice plug removal.
For more such questions on Ice plug
https://brainly.com/question/30262975
#SPJ8
What spectacles are required for reading purposes by a person whose near point is 2.0m
Answer:Convex lens spectacles is required for reading purpose..
Explanation:
I don't say you have to mark my ans as brainliest but if it has really helped you please don't forget to thank me...
4. A 40.0 kg child swings in a swing supported by two chains, each 3.00 m long. If the tension in each at the lowest point is 350N, find (i) The child’s speed at the lowest point ,
The child's speed at the lowest point is 5.42 m/s.
At the highest point of the swing, the child is momentarily at rest and has only potential energy. At the lowest point, the child has only kinetic energy.
Using the conservation of mechanical energy, we can write:
Potential energy at highest point = Kinetic energy at lowest point
mgh = (1/2)mv²
where m is the mass of the child, g is the acceleration due to gravity, h is the height of the swing at the highest point, and v is the speed of the child at the lowest point.
First, we need to find the height of the swing at the highest point. Since the swing is supported by two chains, the height of the swing at the highest point is half the length of the chains:
h = (1/2)3.00 m = 1.50 m
Next, we can solve for the child's speed at the lowest point:
mgh = (1/2)mv²
40.0 kg * 9.81 m/s² * 1.50 m = (1/2) * 40.0 kg * v²
588 J = 20.0 kg * v²
v² = 29.4 m²/s²
v = 5.42 m/s
To know more about speed, here
brainly.com/question/28224010
#SPJ1
Drag is usually ignored because its effect on the horizontal velocity is usually negligible due to the short time of flight.
An object's surface area and geometry, along with the object's surrounding wind speed will affect the drag force.
In most cases, drag force will cause the object to land horizontally closer to the predicted landing point as drag is a resistive force.
Drag is ignored in projectile predictions because projectiles usually have a relatively short time of flight.
The surface area of the object, the wind speed, as well as the relative velocity of the airplane will affect the drop of relief packages.
The drag force will cause the projectile to take a longer time to land and may cause to land far from its expected drop point.
What is drag?Drag is a force that acts in opposition to the motion of an object moving through a fluid.
Drag can be thought of as friction in fluids because similar to friction, it acts in an opposite direction of the relative motion of a moving object.
For example, airplanes moving through air experience a drag; ships and boats moving through water experience drag too.
Drag also occurs in projectiles moving through the air. However, because of the relatively short time of flight, it is usually ignored in projectile motion.
Learn more about drag force at: https://brainly.com/question/11442373
#SPJ1
Complete question:
While studying projectile motion, we consider ideal scenarios, where the projectile travels along its trajectory only under the influence of gravity. In real-world situations, however, other forces act on the projectile.
Consider a cargo plane that is dropping relief packages to flood victims. In predicting and studying this motion, we might consider gravity, but ignore the horizontal and vertical forces associated with drag (or air friction). Discuss this simplification. Specifically address these questions:
•Why do we often ignore drag in projectile predictions?
•What conditions (of the object, its surroundings, and its launch) do you think might make drag a significant factor in the relief package drop?
•How would drag affect the projectile's motion if it really were a significant factor in the relief package drop?
Write all the different ways you can think of that describe what it means to be healthy
Answer:
Eat more healthy foods. Workout and build your immune system.
Explanation:
Eat Healthy foods like Carrots, Apples, Bannas, Pears, and anything that deals with not much of any sugar. An example of unhealthy foods is Cakes, Chocolates, Candy, and more. Drink a lot of water.
Air at 273K and 1.01x10³Nm2 pressure contains 2.70x1025 molecules per cubic meter. How many molecules per cubic meter will there be at a place where the temperature is 223K and pressure is 1.33x10 Nm-2
The molecules of O2 that are present in 3.90 L flask at a temperature of 273 K and a pressure of 1.00 atm is 1.047 x 10^23 molecules of O2
Step 1: used the ideal gas equation to calculate the moles of O2
that is Pv=n RT where;
P(pressure)= 1.00 atm
V(volume) =3.90 L
n(number of moles)=?
R(gas constant) = 0.0821 L.atm/mol.K
T(temperature) = 273 k
by making n the subject of the formula by dividing both side by RT
n= Pv/RT
n=[( 1.00 atm x 3.90 L) /(0.0821 L.atm/mol.k x273)]=0.174 moles
Step 2: use the Avogadro's law constant to calculate the number of molecules
that is according to Avogadro's law
1 mole = 6.02 x10^23 molecules
0.174 moles=? molecules
by cross multiplication
the number of molecules
= (0.174 moles x 6.02 x10^23 molecules)/ 1 mole =1.047 x 10^23 molecules of O2
Learn more about molecules on:
https://brainly.com/question/32298217
#SPJ1
Find the capacitance of a parallel-plate capacitor made of two 4.0 cm x 4.0 cm metal plates if the plates are separated by 5.0 mm.Group of answer choices2.8x10-10 F1.0x10-6 F2.8x10-12 F2.0x10-5 F
Given the area is:
A=4.0 cmx4.0 cm
The seperation distance is d=5.0 mm
The capacitance is :
\(\begin{gathered} C=\frac{\epsilon_oA}{d} \\ \Rightarrow C=8.85\times10^{-12}\frac{4.0\times10^{-2}\times4.0\times10^{-2}}{5\times10^{-3}} \\ \Rightarrow C=2.83\times10^{-12}F \end{gathered}\)Thus the answer is
\(2.8\times10^{-12}F\)A 2.80 kg mass is dropped from a
height of 4.50 m. Find its potential
energy (PE) when it is 3.00 m
above the ground.
Answer:
PE = 82.32J
Explanation:
PE = m*g*h
PE = 2.80kg*9.8m/s²*3m
PE = 82.32J
PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?
The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N
The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.
Given:
Initial distance between the planets = 1 million miles
Initial gravitational force = 1,000,000 N
Final distance between the planets = 2 million miles
To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.
Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.
According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:
(F2/F1) = (d1/d2)²
Substituting the given values:
(F2/1,000,000 N) = (1 million miles / 2 million miles)²
Simplifying:
(F2/1,000,000 N) = (1/2)²
(F2/1,000,000 N) = 1/4
F2 = (1/4) * 1,000,000 N
F2 = 250,000 N
for more questions on force
.https://brainly.com/question/12970081
#SPJ11
Solve this question plz!
A
6N
11 N
What is the net force ?
Answer:
66n
Explanation:
4376
____ is factual information not subject to bias.
Interpretation
Analysis
Data
Opinion
Answer:
Data
Explanation:
Data is factual information not subject to bias.
This ultimately implies that, data connotes fact, thus, it is an information that is credible, accurate, a statement of truth, evidential and proven.
In Computer programming, a data dictionary can be defined as a centralized collection of information on a specific data such as attributes, names, fields and definitions that are being used in a computer database system.
In a data dictionary, data elements are combined into records, which are meaningful combinations of data elements that are included in data flows or retained in data stores.
This ultimately implies that, a data dictionary found in a computer database system typically contains the records about all the data elements (objects) such as data relationships with other elements, ownership, type, size, primary keys etc. This records are stored and communicated to other data when required or needed.
What is MOST likely to be TRUE about asynchronous communication?
It is rarely used in businesses in today's society.
It offers many opportunities to ask clarifying questions in real time.
It is helpful when employees work across multiple time zones.
It only works when all employees work in the same time zone.
The most likely true statement about asynchronous communication is that it is helpful when employees work across multiple time zones.
Asynchronous communication refers to a mode of communication where participants do not need to be present or engaged simultaneously. Instead, they can send and receive messages at their convenience.In today's globalized society, businesses often have teams distributed across different geographical locations and time zones. Asynchronous communication becomes invaluable in such scenarios as it allows team members to collaborate effectively without the constraints of real-time interactions. By utilizing tools like email, project management platforms, or messaging apps, individuals can communicate and exchange information regardless of their location or the time differences.
Asynchronous communication also offers benefits such as flexibility and increased productivity. Team members have the freedom to work at their own pace and prioritize tasks accordingly. It provides opportunities for thoughtful and well-crafted responses, as individuals can take time to gather information or reflect on complex matters before replying.While asynchronous communication is advantageous for teams operating across multiple time zones, it does not rely on all employees working in the same time zone. In fact, it is designed to accommodate diverse schedules and allow individuals to collaborate efficiently despite their varying work hours.
for such more questions on time
https://brainly.com/question/4931057
#SPJ8
You are going 30 m/s in a car of mass 1000 kg when you reach a red light and stop your car.
a. how much heat energy is released by the brakes of your car
Answer:
Explanation:
The kinetic energy will convert to heat energy (provided the car has friction brakes and not regenerative brakes as might be found on an electric or hybrid) Also assuming level road.
E = ½mv² = ½(1000)30² = 450,000 J
An experiment is performed to determine the specific heat of a 110.0 g metal sphere. The metal sphere is frozen in 40.0 g of ice and cooled to -10.0 °C. An insulated container is filled with 400.0 g of water at 42.0 °C. The ice containing the metal is added to the insulated container and the system comes to thermal equilibrium. At thermal equilibrium, the temperature of the water is now 30.0 °C. Determine the specific heat capacity of the metal sample.
When the temperature of the combination hits 0°C, 20g of ice remains unmelted. The quantity of ice added to the water was approximately (Specific heat of water =4.2J/gC)
Specific heat of ice =2.1J/gC,
Heat of fusion of water at 0C=334J/g.
ΔT=Tfinal−Tinitial=40.6°C−173°C=−132.4°C
What exactly is thermal equilibrium, and how does it occur?Thermal equilibrium is reached when two bodies come into thermal contact with each other, allowing heat transfer (i.e., the transfer of energy through heat) to occur. Thermal equilibrium cannot be achieved if two systems cannot freely exchange energy.
Thermal equilibrium happens after a length of time when the engine temperature equals the air temperature.
learn more about Thermal equilibrium
https://brainly.com/question/14556352
#SPJ1
PLS HELP EZ QUESTION
List 3 examples of potential to kinetic energy
Light of intensity I0 passes through 4 ideal polarizing sheets. Unpolarized light enters the 1st sheet that has a horizontal transmission axis. Light continues to the 2nd sheet that has its transmission axis at 25 degrees with respect to the 1st sheet, then to the 3rd sheet that has its transmission axis at 47 degrees with respect to the 1st sheet then to the 4th sheet that has its transmission axis at 10 degrees with respect to the 3d sheet. The intensity of the emerging light as percentage of I0 is close to:
Answer:
34.24 %
Explanation:
Since I₀ is the intensity of the un-polarized light, the intensity I₁ of the light polarized by the 1st sheet is (by the one-half rule) I₁ = I₀/2.
The intensity of polarized light I from a polarized source I' is I = I'cos²Ф where Ф is the angle between the direction of I' and I. Since the second sheet has its transmission axis at 25° with respect °o the 1st sheet, the intensity of light I₂ from the second sheet is I₂ = I₁cos²25°.
Also, the 3rd sheet has its transmission axis 47° with respect to the 1st sheet. So, the angle between the transmission axis of the 2nd sheet and 3rd sheet is 47° - 25° = 22°. So, the intensity I₃ from the 3rd sheet is I₃ = I₂cos²22°
Finally, the 4th sheet has its transmission axis 10° with respect to the 3rd sheet. So, the intensity I₄ from the 4th sheet is I₄ = I₃cos²10°.
So, I₄ = I₃cos²10°
I₄ = I₂cos²22°cos²10°
I₄ = I₁cos²25°cos²22°cos²10°
I₄ = (I₀/2)cos²25°cos²22°cos²10°
I₄/I₀ = cos²25°cos²22°cos²10°/2
I₄/I₀ = (cos25°cos22°cos10°)²/2
I₄/I₀ = (0.9063 × 0.9272 × 0.9848)²/2
I₄/I₀ = 0.8275²/2
I₄/I₀ = 0.6848/2
I₄/I₀ = 0.3424
So, as a percentage,
I₄/I₀ × 100% = 0.3424 × 100% = 34.24 %
The natural abundance of boron-11 is 80.1%. If you have 7,000 boron atoms, how many of them are the boron-11 isotope?
Answer:
If the natural abundance of boron-11 is 80.1%, then the natural abundance of boron-10, the other stable isotope of boron, is 100% - 80.1% = 19.9%.
To determine how many of the 7,000 boron atoms are the boron-11 isotope, we can use the following steps:
Calculate the number of boron-10 atoms:
19.9% x 7,000 = 1,393
Calculate the number of boron-11 atoms:
80.1% x 7,000 = 5,607
Therefore, out of 7,000 boron atoms, 5,607 are the boron-11 isotope.
Explanation:
In an experiment to measure the acceleration due to gravity g, two independent equally reliable measurements gave 9.67 m/s2 and 9.88 m/s2. Determine (i) the percent difference of the measurements (ii) the percent error of their mean. [Take the theoretical value of g to be 9.81 m/s2]
Answer and Explanation:
a. The computation of the percent difference between the measurements is shown below:-
The first value of g is 9.67 and the second value is 9.88
So, difference = 9.88 - 9.67
= 0.21
Percentage difference in measurement is
\(= \frac{0.21}{9.88}\times100\)
= +/-2.13
Percent difference with 9.88
Difference = 9.88 - 9.81
= 0.07
\(= \frac{0.07}{9.81}\times100\)
= +/-0.71%
b. The Computation of percent error of their mean is shown below:-
Mean of two values is
= \(\frac{9.67 + 9.88}{2}\)
= 9.775
Difference = 9.81 - 9.775
= 0.035
Percentage difference is
\(= \frac{0.035}{9.81}\times 100\)
= +/- 0.36%
This problem concerns the properties of circular orbits for a satellite of mass m orbiting a planet of mass M in an almost circular orbit of radius r. In doing this problem, you are to assume that the planet has an atmosphere that causes a small drag due to air resistance. "Small" means that there is little change during each orbit so that the orbit remains nearly circular, but the radius can change slowly with time. The following questions will ask about the net effects of drag and gravity on the satellite's motion, under the assumption that the satellite's orbit stays nearly circular. Use G if necessary for the universal gravitational constant.
What is the potential energy U of the satellite?Express your answer in terms ofm, M, G, and r.What is the kinetic energy K of the satellite?Express the kinetic energy in termsof m, M, G, and r.
Answer:
A) U = - GMm/r
B) K = 0.5 mGM/r
Explanation:
A) The potential energy U of the satellite
U = - GMm/r
G = universal gravitational constant which is ( 6.67e-11 Nm^2/c^2 )
M = mass of the planet
m = mass
r = distance ( radius )
B) Kinetic energy
kinetic energy expressed as K = 0.5 m Vo^2
NOTE : Vo^2 = GM / r
hence kinetic energy will be expressed as
K = 0.5 mGM/r
whem completing an emergency Roaside stop,it is necessary to put on your parking brake
A. True
B. False
Answer:
trueeeeeeee..........mmmm...........
A box is sliding along a frictionless surface and gets to a ramp. Disregarding friction, how fast should the box be going on the ground in order to slide up the ramp to a height of 2.5 meters, where it stops? (Use g = 9.8 m/s2.)
Answer:
7.0 m/s
Explanation: I just did it
What kind of wave interactions is caused by a change in the speed of the wave
Answer:Refraction
Explanation:
or the bending of the path of the waves, is accompanied by a change in speed and wavelength of the waves.
Question 11 of 15
What units are used for work done? Give the full name, not the symbol.
Answer:
The joule (symbol: J) in SI and metric systems, and the foot pound-force in customary systems.
Explanation:
Work is the force applied over some distance; that is, newtons per square/cubic meter. Therefore, work is calculated by diving the force (newtons) by the distance (meters). The resulting unit would normally be written down as N/m², but for brevity's sake, we just call it the joule.
An object is dropped on earth (g=10m/s/s (meters per second per second or m/s^2)) and it falls for five seconds draw a speed vs time graph
Answer:
v = 10t
Explanation:
The velocity of an object after time t is given by the equation
v(t) = u + at
Here u, the initial velocity is 0
a = acceleration = g = 10 m/s²
Therefore at any time,
v(t) = 0 + 10t
v = 10t
After 5 seconds, v = 10 m/s² x 5s = 50 m/s
The graph of this equation is given
Two cars collide head-on and stick together.
Car A, with a mass of 2000 kg, was initially
moving at a velocity of 10 m/s to the east. Car
B, with an unknown mass, was initially at rest.
After the collision, both cars move together at
a velocity of 5 m/s to the west. What is the
mass of Car B?
OF
The mass of Car B is -6000 kg.
To solve this problem, we can apply the principle of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.
Therefore, we can write the equation for the conservation of momentum as:
(mass of Car A * velocity of Car A) + (mass of Car B * velocity of Car B) = (mass of Car A + mass of Car B) * velocity after collision
Let's substitute the given values into the equation:
(2000 kg * 10 m/s) + (mass of Car B * 0 m/s) = (2000 kg + mass of Car B) * (-5 m/s)
Simplifying the equation:
20000 kg*m/s = -5 m/s * (2000 kg + mass of Car B)
Dividing both sides by -5 m/s:
-4000 kg = 2000 kg + mass of Car B
Subtracting 2000 kg from both sides:
mass of Car B = -4000 kg - 2000 kg
mass of Car B = -6000 kg
know more about momentum here:
https://brainly.com/question/30487676
#SPJ8
What are the magnitude and the direction of the electric field that will allow an electron to fall with an acceleration of 4.3 m/s2?
Answer:
Explanation:
The acceleration of an electron in an electric field is given by the equation:
a = qE/m
where a is the acceleration, q is the charge of the electron, E is the electric field, and m is the mass of the electron.
Given that the acceleration of the electron is 4.3 m/s^2, and the mass of the electron is 9.11 × 10^-31 kg, and the charge of the electron is -1.6 × 10^-19 C, we can solve for the electric field E:
E = ma/q
E = (4.3 m/s^2) × (9.11 × 10^-31 kg) / (-1.6 × 10^-19 C)
E = -2.44 × 10^4 N/C
The negative sign indicates that the direction of the electric field is opposite to the direction of the electron's motion. Therefore, the magnitude of the electric field required to accelerate an electron with an acceleration of 4.3 m/s^2 is 2.44 × 10^4 N/C and the direction is opposite to the direction of motion of the electron.
The toy car in the diagram runs off the edge of the table that is 1.225m high. The car lands 0.400m from the base of the table.
a. How long did it take the car to fall
b. how fast was the car going on the table
Anyone?????help with this questions!!!
Answer:
A) Drag is when a resistive force (in this case, air resistance) causes the moving vehicle to decrease its speed.
0. •Given that the apparent expansivity of a liquid is 0.00015³ 1² and the linear expansivity of the container is 0.00012
The real expansion of the apparent expansion of 0.00015 x 10⁻³ per Kelvin and the linear expansion of the container 0.00012 x 10⁻³ per kelvin is 1.8 x 10⁻¹³ per Kelvin.
Apparent expansion is the expansion we see when a liquid is heated without a vessel is called true expansion. The expansion of a liquid that is felt without taking into account the expansion of its container is called apparent expansion. The actual expansion of a liquid is always greater than the apparent expansion.
For actual expansion, the following formula is used:
real area = apparent area x linear area
So,
real expansivity = 0.00015 x 10⁻³ x 0.00012 x 10⁻³
real expansivity = 0.000000018 x 10⁻⁶
real expansivity = 1.8 x 10⁻¹³
The answer is 1.8 x 10⁻¹³ per Kelvin.
Your question is incomplete but most probably your full question was:
Given that apparent expansivity of a liquid is 0.00015x10(raised to power -3) per Kelvin and the linear expansivity of the container is 0.00012 x 10(raised to power -3) per Kelvin, calculate the real expansivity.
Learn more about real expansivity at https://brainly.com/question/14325928
#SPJ1
An 80 N rightward force is applied to a 10 kg object to accelerate it to the right.
The object encounters a friction force of 50 N.
net force = 30 N
mass = 8.16 kg
acceleration = 3.68 m/s²
Further explanationGiven
80 N force applied
mass of object = 10 kg
Friction force = 50 N
Required
Net force
mass
acceleration
Solution
net forceNet force = force applied(to the right) - friction force(to the left)
Net force = 80 - 50 = 30 N
massGravitational force(downward) : F = mg
m = F : g
m = 80 : 9.8
m = 8.16 kg
accelerationa = F net / m
a = 30 / 8.16
a = 3.68 m/s²