An ingot of lead is dropped with an initial velocity of 14 ft/s. When it hits the ground, its temperature has been increased by 0.25 oF. From what height was the ingot dropped (in ft)? Neglect air resistance. [h = 2.79 ft]

Answers

Answer 1

Answer:

The ingot was dropped at a height of 2.81 feet.

Explanation:

The ingot is released from a height \(h\) and accelerated by gravity, it hits the ground and stops abruptly by impact, which contributes to the temperature increase of the material. We can model this systems by means of the First Law of Thermodynamics, which is generalized form of Principle of Energy Conservation:

\(U_{g,1}-U_{g,2} +K_{1}-K_{2} = \Delta U_{sys}\) (Eq. 1)

Where:

\(U_{g,1}\), \(U_{g,2}\) - Initial and final gravitational potential energies, measured in pound-feet per second.

\(K_{1}\), \(K_{2}\) - Initial and final translational kinetic energies, measured in pound-feet per second.

\(\Delta U_{sys}\) - Change in internal energy of the lingot of lead, measured in pound-feet per second.

By applying definitions of gravitational potential, translational kinetic and internal energies, we expand the expression above, eliminate mass in both sides and clear the final temperature of the ingot:

\(g\cdot (z_{1}-z_{2})+ \frac{1}{2}\cdot (v_{1}^{2}-v_{2}^{2}) = c_{p}\cdot (T_{2}-T_{1})\)

\(z_{1}-z_{2}=\frac{c_{p}}{g} \cdot (T_{2}-T_{1})-\frac{1}{2\cdot g}\cdot (v_{1}^{2}-v_{2}^{2})\)

If we know that \(c_{p} = 753\,\frac{lbm\cdot ft}{lbm\cdot ^{\circ}F}\), \(g = 32.174\,\frac{ft}{s^{2}}\), \(T_{2}-T_{1} = 0.25\,^{\circ}F\), \(v_{1} = 14\,\frac{ft}{s}\) and \(v_{2} = 0\,\frac{ft}{s}\), the height from which the lingot dropped is:

\(z_{1}-z_{2} = \left(\frac{753\,\frac{lbm\cdot ft}{lbm\cdot ^{\circ}F} }{32.174\,\frac{ft}{s^{2}} }\right)\cdot (0.25\,^{\circ}F)-\left[\frac{1}{2\cdot \left(32.174\,\frac{ft}{s^{2}} \right)} \right] \cdot \left[\left(14\,\frac{ft}{s} \right)^{2}-\left(0\,\frac{ft}{s} \right)^{2}\right]\)

\(z_{1}-z_{2} = 2.81\,ft\)

The ingot was dropped at a height of 2.81 feet.


Related Questions


PLEASE HELP AND SHOW WORK,THANK YOU!!
4) Suppose that two identical
mass planets are sitting
million miles apart. At that
distance the planets have a
gravitational force of 1,000,000 N.
If the planets are moved
to two million miles apart, what
is the new gravitational force
between them?

Answers

The new gravitational force between the two planets, when they are moved to two million miles apart, is 250,000 N

The gravitational force between two objects can be calculated using Newton's Law of Universal Gravitation, which states that the force is directly proportional to the product of their masses and inversely proportional to the square of the distance between their centers.

Given:

Initial distance between the planets = 1 million miles

Initial gravitational force = 1,000,000 N

Final distance between the planets = 2 million miles

To determine the new gravitational force, we need to compare the ratios of the distances and apply the inverse square law.

Let's denote the initial distance as d1, the initial gravitational force as F1, the final distance as d2, and the unknown final gravitational force as F2.

According to the inverse square law, the ratio of the gravitational forces is the square of the ratio of the distances:

(F2/F1) = (d1/d2)²

Substituting the given values:

(F2/1,000,000 N) = (1 million miles / 2 million miles)²

Simplifying:

(F2/1,000,000 N) = (1/2)²

(F2/1,000,000 N) = 1/4

F2 = (1/4) * 1,000,000 N

F2 = 250,000 N

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Sandra pays $11 for 2.75 pounds of cheese. What is the cost per pound?
$0.40
x
$0.44
$4.00
$4.40
Hi

Answers

Answer:

$4.00

Explanation:

The cost per pound is $4.00, $11 divided by 2.75 is 4.

Answer:

Th cost per pound is $4.00.

Explanation:

11/2.75= 4


Joe kicks a ball with a force of 12 Newtons. If the ball has mass of .25 kg,
how much will the ball accelerate?

Answers

Answer:

Explanation:

F = ma

a = F/m

a = 12/0.25

a = 48 m/s²

A crate with a mass of 161.5 kg is suspended from the end of a uniform boom with a mass of 72.3 kg. The upper end of the boom is supported by a cable attached to the wall and the lower end by a pivot (marked X) on the same wall. Calculate the tension in the cable.

Answers

Answer:

The correct answer is "2205.72 N".

Explanation:

Given:

m₁ = 161.5 kg

m₂ = 72.3 kg

By taking moment about point A, we get

⇒ \(m_1 g Cos \theta.\frac{l}{2 Cos \theta} + m g Cos \theta.\frac{l}{ Cos \theta} -T Cos(90-2 \theta).\frac{l}{2 Cos \theta} = 0\)

By substituting the values, we get

⇒ \(\frac{161.5\times 9.8\times 13}{2}+72.3\times 9.8\times 13-T.2 Sin \theta.l =0\)

⇒ \(10287.55+9211.02-T 2\times 0.34\times 13=0\)

⇒                                            \(T\times 8.84=19498.57\)

⇒                                                       \(T= 2205.72 N\)

A pitot tube (the figure) is used to determine the airspeed of an airplane. It consists of an outer tube with a number of small holes B (four are shown) that allow air into the tube; that tube is connected to one arm of a U-tube. The other arm of the U-tube is connected to hole A at the front end of the device, which points in the direction the plane is headed. At A the air becomes stagnant so that VA = 0, At B, however, the speed of the air presumably equals the airspeed B of the plane. Use Bernoulli's equation to derive a formula giving the air speed in terms of the difference h in the liquid levels in that tube, the density rho of the liquid in the U-tube, and the density of air Pair. Suppose that the tube contains alcohol and the level difference h is 34.0 cm. What is the plane's speed relative to the air? The density of the air is 1.14 kg/m3 and that of alcohol is 810 kg/m3. Air Hole A Liquid Number Units

Answers

The plane's speed relative to the air is 63.3m/s.

What is relative speed?

When two or more bodies (objects) travel at the same or different speeds in the same or different directions, the concept of relative speed is applied. As a result, relative speed can be defined as a concept that calculates the speed of one moving body in relation to another moving body traveling at the same speed.

For example, if two people are running in opposite directions, the relative speed of one of them to the other stationary body can be calculated because the bodies are moving in opposite directions at the same time. Thus, relative speed can be defined as the speed of a moving body in relation to another stationary body.

The difference between the bodies is calculated while calculating the relative speed of bodies moving in the same direction.

) Bernoulli's equation gives p A =p b+    1   ρ air  v²

​                                                                  2

However, △=p A −p B =ρgh

in order to balance the pressure in the two arms of the U-tube.

Thus ρgh= 1  ρ air v²

                  2

, or v =  √2ρgh

             √  ρ air

(b) The plane's speed relative to the air is

v= ρ air 2ρgh  =√2(810kg/m 3 )(9.8m/s 2 )(0.260m) =63.3m/s

                                √ 1.03kg/m³

Hence, the plane's speed relative to the air  is 63.3m/s.

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Paleontologists are experts on the rock cycle true or false

Answers

Answer:

I cannot do the laws of physics cuz I hate science but I'm just dance

Explanation:

it's it's true

A paleontologist is a scientist who studies the history of life on Earth through the fossil record.

What is paleontologist?

A paleontologist is a scientist who studies the history of life on Earth through the fossil record. Fossils are the evidence of past life on the planet and can include those formed from animal bodies or their imprints

Invertebrate Paleontology: Study of invertebrate animal fossils, such as mollusks, echinoderms, and others. Vertebrate Paleontology: Study of vertebrate fossils, from primitive fishes to mammals. Human Paleontology (Paleoanthropology): The study of prehistoric human and proto-human fossils.

Paleontologists are scientists who study the history of life on Earth from fossils. Fossils are evidence of past life on Earth and can include those formed from animal bodies or their casts (body fossils). Trace fossils are another type of fossil.

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If an object is 16.76 cm in front of a convex mirror that has a focal length of 67.1 cm, how far behind the mirror will the image appear to an observer ?

Answers

F = focal lenght = 67.1 cm

u= distance between mirror and object = 16.76 cm

1/f = 1/v + 1/u

1/67.1 = -1/16.76 + 1/u

1/67.1 + 1/16.76 = 1/u

u = 13.41

13. An 80.0 kg climber with a 20.0 kg pack climbs 8848 m to the top of Mount Everest. What is the climber's
potential energy?
a 6.94 x 106
2.47 106
b. 4.16 x 106
d. 1.00 X 106

Answers

The answer to your question is B

The potential energy of the climber is 6.94 × 10⁶. It is the energy which is present in the body of an object which is at rest. Thus, the correct option is A.

What is Potential energy?

Potential energy is the energy which is present in the body of an object which is at rest. This energy is transformed into kinetic energy when the body experiences any force and undergo motion. The SI unit of potential energy is Joule (J).

PE = m × g × h

where, PE = Potential energy,

m = mass of the object,

g = acceleration due to gravity,

h = height

PE = 80 × 9.8 × 8848

PE = 80 × 9.8 × 8848

PE = 784 × 8848

PE = 6936832

PE = 6.94 × 10⁶

Therefore, the potential energy of the climber is 6.94 × 10⁶.

Therefore, the correct option is A.

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If a cube that has a length, height, and width of 4 cm is broken down into 8 cubes of equal size, what is the surface area of the 8 new cubes?

Answers

Answer: When a cube is divided into smaller cubes of equal size, the length, height, and width of each new cube are one-third of the original cube.

So each new cube will have a length, height, and width of 4/3 cm.

To calculate the surface area of each new cube, we need to find the area of each face and then add them up. Each cube has six faces, so we can calculate the surface area of one cube by multiplying the area of one face by six.

The area of one face of the new cube is (4/3)*(4/3) = 16/9 cm².

So the surface area of one new cube is 6*(16/9) = 96/9 cm² = 10.67 cm² (rounded to two decimal places).

Since we have 8 new cubes, the total surface area is 8 times the surface area of one new cube:

Total surface area = 8 * 10.67 cm² = 85.33 cm² (rounded to two decimal places).

Therefore, the surface area of the 8 new cubes is 85.33 cm².

Let to the right be the positive direction.
A 25.8 g marble sliding to the right at 21.0
cm/s overtakes and collides with a 12.4 g
marble moving in the same direction at 13.8
cm/s. After the collision, the 12.4 g marble
moves to the right at 23.9 cm/s.
Find the velocity of the 25.8 g marble after
the collision.
Answer in units of cm/s. Answer in units
of cm/s.

Answers

The final velocity of the 25.8 g marble after the collision is 16.15 cm/s.

What is the velocity of the 25.8 g marble after the collision?

The velocity of the 25.8 g marble after the collision is calculated as follows;

m₁u₁ + m₂u₂ = m₁v₁ + m₂v₂

where;

m₁ is the mass of 25.8 g marblem₂ is the mass of 12.4 g marbleu is their initial speedsv is their final speeds

The final velocity of the 25.8 g marble after the collision is calculated as;

( 25.8 x 21 ) + ( 12.4 x 13.8 ) = ( 12.4 x 23.9 ) + ( 25.8v )

712.92 = 296.36 + 25.8v

25.8v = 416.56

v = 416.56 / 25.8

v = 16.15 cm/s

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Someone help me I’ll give brainliest

Someone help me Ill give brainliest

Answers

Answer:

2.83 m/s

Explanation:

you have the right answer

A soccer goal is 2.44 m high. A player kicks the ball at a distance 13 m from the goal at an angle of 40°, and the ball just hits the top of the goal. What is the initial speed of the soccer ball (in m/s)?

Answers

Let v denote the initial speed of the ball. The ball's position at time t is given by the vector

\(\mathbf r(t)=v\cos40^\circ\,t\,\mathbf i+\left(v\sin40^\circ\,t-\dfrac g2t^2\right)\,\mathbf j\)

where g is the acceleration due to gravity with magnitude 9.80 m/s^2.

The ball reaches the goal 13 m away at time t such that

\(10\,\mathrm m=v\cos40^\circ t\implies t=\dfrac{10\,\mathrm m}{v\cos40^\circ}\)

at which point it attains a height of 2.44 m, so that

\(2.44\,\mathrm m=v\sin40^\circ\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)-\dfrac g2\left(\dfrac{10\,\mathrm m}{v\cos40^\circ}\right)^2\)

\(2.44\,\mathrm m=(10\,\mathrm m)\tan40^\circ-\dfrac12\left(9.80\dfrac{\rm m}{\mathrm s^2}\right)\left(\dfrac{100\,\mathrm m^2}{v^2\cos^240^\circ}\right)\)

\(\implies\boxed{v\approx3.75\dfrac{\rm m}{\rm s}}\)

A thin half ring with a radius of R = 10 cm is uniformly charged with a linear density of = 1 Mikrokulon/m and located in a vacuum. Determine the force F of interaction between the half ring and a point charge q = 20 nC located at the center of curvature. (don't use chatgpt please)

Answers

Answer:

Explanation:

F = k * q * lambda * R * π * (1 - √2/2)

Substituting the given values of q, lambda, R, and k, we get:

F = (9 x 10^9 N*m^2/C^2) * (20 x 10^-9 C) * (1 x 10^-6 C/m) * (0.1 m) * π * (1 - √2/2)

F ≈ 8.58 x 10^-4 N

Therefore, the force of interaction between the half ring and the point charge is approximately 8.58 x 10^-4 N.

The strength of gravity between two objects depends on:aWeight of the objects and distance between the two objectsbMass of the objects and the volume of the objectscThe Mass of the objects and the distance between the two objectsdThe volume of the object and the weight of the objects

Answers

According to newton gravitational law any particle of matter in the universe attracts any other with a force varying directly as the product of the masses and inversely as the square of the distance between them:

\(F=G\cdot\frac{m1\cdot m2}{r^2}\)

Where m1 and m2 are the masses of the objects, r is the distance between the objects and G is the gravitational constant. Therefore, the answer is:

a. Weight of the objects and distance between the two objects

Question 11
5 pts
Gas Laws: A balloon is carefully filled with one breath of air (about 500ml) underwater at
a depth of 100ft, then tied shut. At this depth, the balloon is under 4 atmospheres of
pressure. Assuming negligible compression by the rubber of the balloon, what is the
volume of the air (in m³) once the balloon rises to the surface of the water and
experiences 1 atm of pressure? Modify the Ideal Gas Law to solve this conservation
problem.
1 Liter 0.001 Cubic Meter
1 atm = 1.01x 105 Pascals

Answers

The volume of the gas once it reaches the surface of water is 2 liters.

The volume of the air in balloon at depth of 100ft (30m) is 500ml.

The pressure at this point is 4 atm.

Assuming that the balloon have no compression by rubber of balloon the volume of air at the water surface is V.

The pressure at the surface of water is 1 atms.

As we know, from the ideal gas equation,

PV = nRT

Where,

P is the Pressure of gas,

V is the volume of the gas,

n is the number of moles,

R is the gas constant whose value is 0.082057 L atm mol-1 K-1,

T is the temperature.

Assuming that the temperature is constant,

We know,

PV = nRT

All quantities on the right side are constants,

So, we can write,

P₁V₁ = P₂V₂

Putting all the the values,

4(0.5) = 1V₂

V₂ = 2 Liters.

The volume of the air at the surface is 2 liters.

1 liter = 0.001 m

Hence,

2 liters = 0.002 m³

So the volume of air at the surface is 0.002m³.

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When heat is added or removed from a substance, it's temperature and thermal energy will be ______.

Answers

Directly Proportional

Temperature is directly proportional to heat. The more the heat more the temperature there are a number of scales like degree Celsius,  Fahrenheit, and Kalvin (SI Unit) of temperature which is calculated by the mercury.

As on high heat, mercury expands and on its expansion, we measure on a scale which simply means more the heat more the expansion, and more the temperature on the scale, and wise- versa.

And if we talk about thermal energy(Q) is also directly proportional to a change in temperature (negative when temperature decreases and increases on increasing the temperature). where Q = mc*(change in temperature). where m for the mass, and C is the constant for the type of substance we are taking to transfer the heat.

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The Complete Question is -

How Heat is related to temperature and thermal energy?

A 80 kg
bicyclist is coasting down a long hill that has a 5.0 ∘
slope. His cross-section area is 0.35 m2
, his drag coefficient is 0.85, his bicycle's coefficient of rolling friction is 0.02, and the air temperature is 20∘C
.

Answers

the Speed reached by the bicyclist is given by, v = 26 m/s

What are the types of friction?

There are mainly four types of friction: static friction, sliding friction, rolling friction, and fluid friction. Friction and normal force are directly proportional to the contacting surfaces, and it doesn't depend on the hardness of the contacting surface.

Given that,

Gravitational acceleration = 9.81 m/s²

Mass of bicyclist = 80 kg

Slope(θ) = 5°

Cross-sectional area of bicyclist = 0.35 m²

μ = coefficient of rolling friction = 0.02

t = air temperature = 20 °C

Let ρ be the density of air at 20oC = 1.2041 kg/m3

ρ = 1.2041 kg/m3

We have the balancing equation:

F₁ = F₂ + F₃

where,

F₁ = component of the weight of the bicyclist down the plane,

F₂ = frictional force up the plane, and

F₃ = air drag force up the plane.

Thus, F₃ = F₁ - F₂

sinθ = sin(5°) = 0.087

cosθ = cos(5°) = 0.996

Now we will calculate the forces,

F₁ = m g sinθ = 80 kg x 9.81 m/s2 x 0.087 = 68.227 N

F₁ = 68.227 N

F₂ = μ m g cosθ = 0.02 x 80 kg x 9.81 m/s2 x 0.996 = 15.63 N

F₂ = 15.63 N

Put the values of F1 and F2 in eqn (1) and we get:

F₃ = F1 - F2

F₃ = 68.227 - 15.63

F₃ = 52.597 N

Let v be the speed reached by a bicyclist,

From the general formula of velocity:

V = ((2 xF₃ / (ρ x CD x A))1/2

v = ((2 x F₃ / (ρ x CD x A))1/2

v = ((2 x 120.78 N / (1.2041 kg/m3 x 0.85 x 0.35))1/2 = 25.97 m/s

v = 26 m/s

Therefore, the Speed reached by the bicyclist is given by, v = 26 m/s

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Which statement about personal strength is TRUE?
1. It is inborn and cannot be developed with training or practice.
2. It is something you can acquire with hard work and lots of practice.
3. It is strictly a physical quality, like beauty, or physical ability, like the ability to swim fast.
4. It is such a natural part of a person that they may not even recognize it.

Answers

I think the answer would be 2 because strength can be learned and acquired with weights or other equipment

Hope this helps

Have a great day/night

Feel free to ask any questions

Order the substances from least dense at the top (1) to most dense at
the bottom (5).
Carbon
dioxide
Lead
Water
Helium
Gold
1
O
O
O
O
2
O
O
O
O
3
O
O
O
4
O
O
O
O
O
*
50 puntos
5
O
O
O
O

Answers

The most denser among the given materials is gold and the least dense one is helium. The order of density from least to most dense is helium, carbon dioxide, water, lead and gold.

What is density?

Density of a substance is the measure of its mass per unit volume. It describes how  closely packed its particles. density depends on the bond type, temperature and pressure.

The density of helium is very low and it is the lightest element after hydrogen. It density is about 0.00017 g/ml. Density of carbon dioxide is 0.0019 g/ml and the density of water is 1 g/ml.

Gold is a denser metal and its density is about 19.3 g/ml and that of lead is 11.3 g/ml. Hence, the order of density from least to most dense is He < carbon dioxide< water< lead < gold.

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Two identical plastic cups contain the same amount of water at two different temperatures, as shown to the left. Both cups are placed in a room at 25° Celsius. At the time cups were placed in the room, in which cup do the water molecules have higher average kinetic energy? ( Cup 1 © Cup 2​

Answers

Answer:

the molecules will begin to move slowly and will turn to ice

Explanation:

hope this was good or not not sure if am right but yeah

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. How much nonconservative work (in kJ) was done on the boy?

Answers

A 66.1-kg boy is surfing and catches a wave which gives him an initial speed of 1.60 m/s. He then drops through a height of 1.59 m, and ends with a speed of 8.51 m/s. The nonconservative work done on the boy is approximately -42.7 kilojoules.

To find the nonconservative work done on the boy, we need to consider the change in the boy's mechanical energy during the process. Mechanical energy is the sum of the boy's kinetic energy (KE) and gravitational potential energy (PE).

The initial mechanical energy of the boy is given by the sum of his kinetic energy and potential energy when he catches the wave:

E_initial = KE_initial + PE_initial

The final mechanical energy of the boy is given by the sum of his kinetic energy and potential energy after he drops through the height:

E_final = KE_final + PE_final

The nonconservative work done on the boy is equal to the change in mechanical energy:

Work_nonconservative = E_final - E_initial

Let's calculate each term:

KE_initial = (1/2) * m * v_initial^2

= (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = m * g * h_initial

= 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * m * v_final^2

= (1/2) * 66.1 kg * (8.51 m/s)^2

PE_final = m * g * h_final

= 66.1 kg * 9.8 m/s^2 * 0

Since the boy ends at ground level, the final potential energy is zero.

Substituting the values into the equation for nonconservative work:

Work_nonconservative = (KE_final + PE_final) - (KE_initial + PE_initial)

Simplifying:

Work_nonconservative = KE_final - KE_initial - PE_initial

Calculating the values:

KE_initial = (1/2) * 66.1 kg * (1.60 m/s)^2

PE_initial = 66.1 kg * 9.8 m/s^2 * 1.59 m

KE_final = (1/2) * 66.1 kg * (8.51 m/s)^2

Substituting the values:

Work_nonconservative = [(1/2) * 66.1 kg * (8.51 m/s)^2] - [(1/2) * 66.1 kg * (1.60 m/s)^2 - 66.1 kg * 9.8 m/s^2 * 1.59 m]

Calculating the result:

Work_nonconservative ≈ -42.7 kJ

Therefore, the nonconservative work done on the boy is approximately -42.7 kilojoules. The negative sign indicates that work is done on the boy, meaning that energy is transferred away from the boy during the process.

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Which of the following is NOT a human blood type?
a.
O
c.
B
b.
AB
d.
R

Answers

Answer:

d. R

Explanation:

There are 4 main types of blood – A, B, AB and O.

Blood is the most important component of our life. It is a fluid connective tissue which consists of plasma, blood cells and platelets. It circulates throughout the body and delivers oxygen. Among the given options R is not a blood type. The correct option is D.

What are blood types?

It was Karl Landsteiner who discovered the ABO blood group system. There are 4 main blood groups,  they are A, B, AB and O. Your blood group is determined by the genes you inherit from your parents. Each blood group may be either RhD positive or RhD negative.

Blood group A has antigens on the red blood cells with anti-B antibodies in the plasma. Blood group B has B antigens with anti-A antibodies in the plasma. The blood group O has no antigens but both antibodies are present whereas AB has no antibodies.

Group O is the universal donor and AB is universal recepient.

Thus the correct option is D.

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please answer this 6 marker

please answer this 6 marker

Answers

The student can use a glass prism fixed on a paper. Pass the light rays through it and mark the line of incidence and refraction on the paper and carefully measure the angle using a protractor.

What is refraction ?

Refraction is the process of bending of light ray when passes from a medium to the other medium of different density. The measure of bending is called refractive index of the medium.

The bending of light depends on the speed of light in that medium and density of the medium.

To measure the angle of incidence and angle of refraction, the student can use a prism. Draw a pencil line connecting the incident and emerging rays using the ruler.

The refracted ray is this. Mark r, the angle of refraction between the refracted light and the normal, with great care. Using a protractor, calculate the angle of refraction and write the results in the table.

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creating a system to effectively solve problems can help you out in many ways. what are some benefits you would like to see in your own life as you begin to apply the 4 step problem solving process you read about this week

Answers

Creating a system to effectively solve problems is important as it helps an individual or organization to accomplish the goals and objectives.

The 4 step problem solving process is an important approach for effective problem-solving.The 4 step problem solving process involves the following steps:Identifying the problemGathering information and analyzing the problemIdentifying possible solutionsEvaluating and selecting the best solution to the problem.Some of the benefits that one would like to see in their own life as they begin to apply the 4 step problem solving process are as follows:1. Better decision-making skills: The 4 step problem solving process helps individuals to make better decisions in their personal and professional lives. The process helps an individual to evaluate all possible solutions before choosing the best solution to the problem.2. Effective time management: The 4 step problem solving process helps an individual to solve problems quickly and efficiently, leading to effective time management. It helps an individual to focus on the important aspects of the problem and make quick decisions.3. Improved communication: The 4 step problem solving process involves gathering information, analyzing the problem, and identifying solutions. It also involves communicating with others to get more information or to help evaluate solutions.

Effective communication skills are important in this process, and this can be improved through practicing the 4 step problem solving process.4. Improved problem-solving skills: The 4 step problem solving process helps individuals to develop better problem-solving skills, which is important in both personal and professional life. It helps an individual to think critically and creatively to identify the best possible solutions to a problem. This skill can be useful in various situations, including work, school, and personal relationships.

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A ladder 6.80 m long leans against the side of a building. If the ladder is inclined at an angle of 74.5° to the horizontal, what is the horizontal distance from the bottom of the ladder to the building? ______________m

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We will have the following:

\(\begin{gathered} x=(6.80m)cos(74.5)\Rightarrow x=1.817220957...m \\ \\ \Rightarrow x\approx1.82m \end{gathered}\)

So, the distance from the bottom of the ladder to the building is approximately 1.82 m.

Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing Time in seconds on the x-axis and position in miles on the y-axis. The line starts at point A (0, 20), and passes points B (20, 20), C (40, 40), D (60, 60), E (80, 60), and F (100, 80) A. A to B B. B to C C. C to D D. D to E E. E to F

Answers

The portion that shows a decreasing velocity is  D to E.

What is a position - time graph?

The position time graph is used to describe the motion of a body. We know that the slope of a velocity time graph is the velocity of the graph.

If we look at the graph as shown in the image attached to the answer, we can see that the portion that shows a decreasing velocity is  D to E.

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Select the correct answer. Which segment of this graph shows a decreasing velocity? Graph representing

Answer:

D - E

Explanation:

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the paperwork needed to start a corporation is extensive and a corporation must also keep detailed records documenting all financial transactions in detail.

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"The paperwork needed to start a corporation is extensive and a corporation must also keep detailed financial records documenting all financial transactions in detail."

Incorporation enables enterprises to raise money through the sale of stock. This is a significant benefit as a business expands and requires more funding to function and compete. In comparison to other business entities, the corporation may have an advantage in obtaining bank loans depending on its size and financial stability.

When a firm or person gets taxed twice on the same income, this is known as double taxation. One instance of this is when a business pays corporate taxes on earnings or profits before paying dividends to shareholders who then have to pay personal taxes on the money.

The given question is inappropriate. Corrected question is 'The paperwork needed to start a corporation is extensive and a corporation must also keep detailed ___ records documenting all financial transactions in detail.'

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The volume of a gas decreases from 15.7 mºto 11.2 m3 while the pressure changes from 1.12 atm to 1.67 atm. If the
initial temperature is 245 K, what is the final temperature of the gas?
O 117 K
230 K
261K
.
O 512K

Answers

Answer:

Approximately \(261\; \rm K\), if this gas is an ideal gas, and that the quantity of this gas stayed constant during these changes.

Explanation:

Let \(P_1\) and \(P_2\) denote the pressure of this gas before and after the changes.

Let \(V_1\) and \(V_2\) denote the volume of this gas before and after the changes.

Let \(T_1\) and \(T_2\) denote the temperature (in degrees Kelvins) of this gas before and after the changes.

Let \(n_1\) and \(n_2\) denote the quantity (number of moles of gas particles) in this gas before and after the changes.

Assume that this gas is an ideal gas. By the ideal gas law, the ratios \(\displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1}\) and \(\displaystyle \frac{P_2 \cdot V_2}{n_2 \cdot T_2}\) should both be equal to the ideal gas constant, \(R\).

In other words:

\(R = \displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1}\).

\(R =\displaystyle \frac{P_2 \cdot V_2}{n_2 \cdot T_2}\).

Combine the two equations (equate the right-hand side) to obtain:

\(\displaystyle \frac{P_1 \cdot V_1}{n_1 \cdot T_1} = \frac{P_2 \cdot V_2}{n_2 \cdot T_2}\).

Rearrange this equation for an expression for \(T_2\), the temperature of this gas after the changes:

\(\displaystyle T_2 = \frac{P_2}{P_1} \cdot \frac{V_2}{V_1} \cdot \frac{n_1}{n_2} \cdot T_1\).

Assume that the container of this gas was sealed, such that the quantity of this gas stayed the same during these changes. Hence: \(n_2 = n_1\), \((n_2 / n_1) = 1\).

\(\begin{aligned} T_2 &= \frac{P_2}{P_1} \cdot \frac{V_2}{V_1} \cdot \frac{n_1}{n_2}\cdot T_1 \\[0.5em] &= \frac{1.67\; \rm atm}{1.12\; \rm atm} \times \frac{11.2\; \rm m^{3}}{15.7\; \rm m^{3}} \times 1 \times 245\; \rm K \\[0.5em] &\approx 261\; \rm K\end{aligned}\).

A 53-years old lady was found by imaging to have 50% narrowing in her left renal artery. The change in blood flow for that artery is: (poiseuille Law)
A. 1⁄3 reduction in flow
B. 1⁄2 increase in flow
C. 1/16 increase in flow
D.1/16 reduction in flow

Answers

Answer:

D. 1/16 reduction in flow

Explanation:

Poiseuille's law says that the flow rate in a tube or pipe is:

\(Q=\frac{\pi P r^4}{8 \eta L}\)

where P is the pressure difference, r is the radius, η is the viscosity, and L is the length.

Assuming that P, η, and L are constant, then we can say Q is proportional to r⁴.

Q ∝ r⁴

A 50% narrowing means the new radius is r/2. Thus the new flow is:

Q₀ / r⁴ = Q / (r/2)⁴

Q₀ / r⁴ = 16 Q / r⁴

Q = Q₀ / 16

There is a 1/16 reduction in flow.

One of the advantages of alternating current (ac) over direct current (dc) is the ease with which voltage levels can be increased or decreased.

a. True
b. False

Answers

Answer:

True

Explanation:

In an alternating current, voltage levels can be easily increased or decreased as per the requirements of the energy distribution in practical world.

Hence, the given statement is true

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