An insulated piston–cylinder device contains 100 L of air at 400 kPa and 25°C. A paddle wheel within the cylinder is rotated until 15 kJ of work is done on the air while the pressure is held constant. Determine the final temperature of the air. Neglect the energy stored in the paddle wheel. (Page 172)

Answers

Answer 1

The final temperature of the air is 406.5 K. the process is isobaric, we can use the ideal gas law to find the final temperature of the air:

PV = nRT

T = PV / (nR)

Substituting the given values, we have:

T = (400 kPa)(100 L + 0.0375 m3) / (nR)

To find n, we can use the ideal gas law at the initial conditions:

PV = nRT

Substituting the given values, we have:

n = PV / (RT) = (400 kPa) (100 L) / [(8.314 J/mol·K)(298 K)] = 16.57 mol

Substituting this value into the equation for T, we have:

T = (400 kPa) (100 L + 0.0375 m3) / (16.57 mol) (8.314 J/mol·K) = 406.5 K

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Related Questions

if you drive your car at 20 miles per hour and then accelerate at a rate of 3 miles per hour every second how fast will you be going after 8 seconds? PLEASE I NEED HELP NOW

Answers

The velocity of the car after 8 seconds of the drive will be 20.0066 miles/hr.

What is Acceleration?

Acceleration is defined as the rate of change of velocity with respect to time.

Given that you are driving your car at 20 miles per hour and then accelerate at a rate of 3 miles per hour every second.

We can calculate the acceleration using the formula -

a = Δv/Δt

a = (v - u)/t

Now -

t = 8 seconds = 0.0022 hrs

Then -

3 = (v - 20)/0.0022

3 x 0.0022 = v - 20

v = 20.0066 miles/hr

Therefore, the velocity of the car after 8 seconds of the drive will be 20.0066 miles/hr.

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A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the cable for the following case:

How far will the load move if it starts from rest and accelerates for 20 seconds?

Answers

Answer:

The answer is below

Explanation:

A 140 kg load is attached to a crane, which moves the load vertically. Calculate the tension in the

cable for the following cases:

a. The load moves downward at a constant velocity

b. The load accelerates downward at a rate 0.4 m/s??

C. The load accelerates upward at a rate 0.4 m/s??

Solution:

Acceleration due to gravity (g) = 10 m/s²

a) Given that the mass of the crane (m) is 140 kg. If the load moves downward, the tension (T) is given by:

mg - T = ma

Since the load has a constant velocity, hence acceleration (a) = 0. Therefore:

mg - T = m(0)

mg - T = 0

T = mg

T = 140(10) = 1400 N

T = 1400 N

b)  If the load moves downward, the tension (T) is given by:

mg - T = ma

T = mg - ma = m(g - a)

T = 140(10 - 0.4) = 140(9.96) = 134.4

T = 134.4 N

c)  If the load moves upward, the tension (T) is given by:

T - mg = ma

T = ma + mg = m(a + g)

T = 140(0.4 + 10) = 140(10.4)

T = 145.6 N

2) To find the distance (s) if the load move from rest (u= 0) and accelerates for 20 seconds (t = 20). We use:

s = ut + (1/2)gt²

s = 0(20) + (1/2)(10)(20)²

s = 2000 m

Assume that the cart is free to roll without friction and that the coefficient of static friction between the block and the cart is ?s. Derive an expression for the minimum horizontal force that must be applied to the block in order to keep it from falling to the ground.

Answers

The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling is:  F = μs * mg

To derive an expression for the minimum horizontal force (F) that must be applied to the block to keep it from falling to the ground, we will use the following terms: cart, roll without friction, coefficient of static friction (μs), and minimum horizontal force.

Assuming that the cart is free to roll without friction and the coefficient of static friction between the block and the cart is μs, we can analyze the forces acting on the block.

There are two forces acting on the block: gravitational force (mg) acting vertically downward and the static friction force (fs) acting horizontally opposite to the applied force. To keep the block from falling, the static friction force must balance the gravitational force.

Using Newton's second law of motion, we can write the equations for the horizontal and vertical components:

1) fs = μs * N (where N is the normal force)
2) N = mg (since there is no vertical acceleration)

Substituting equation (2) into equation (1), we get:

fs = μs * mg

The minimum horizontal force (F) that must be applied to the block is equal to the static friction force (fs) to keep it from falling. Therefore:

F = μs * mg

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Match each sound feature to its description

amplitude

the density of the medium's particles

at the compressions of the wave

compression

the part of a wave where the particles

of the medium are farther apart

wavelength

the distance between compressions

or rarefactions

rarefaction

the part of a wave where the particles

of the medium are closer together

Intro

Done

tivity

be here to search

GOS

Answers

Answer:

1. Amplitude.

2. Rarefaction.

3. Wavelength.

4. Compression.

Explanation:

Sound are mechanical waves that are highly dependent on matter for their propagation and transmission. Some of the properties of sound waves as it travels through a medium such as solid, liquid and gas includes the following;

1. Amplitude: the density of the medium's particles at the compressions of the waves.

2. Rarefaction: the part of a wave where the particles of the medium are farther apart. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are separated by a greater distance.

3. Wavelength: the distance between compressions or rarefactions i.e the distance between two successive compressions or refractions.

4. Compression: the part of a wave where the particles of the medium are closer together. This ultimately implies that, it is part of a longitudinal wave in which the particles that make up the matter for the movement of the wave are closer together.

Answer:

here is the answers .......

Match each sound feature to its descriptionamplitudethe density of the medium's particlesat the compressions

Drop the ball from 12 inches and record how high the ball bounces. Repeat this 3 more times at the 12 inch height.

Answers

What’s the material of the ball? Let’s pretend it’s a tennis ball; 5, 6, 5.5

What happens to the Doppler effect in air (i.e., the shift in frequency of a sound wave) as the temperature increases?

1. It is greater at higher temperatures, but only in the case of a moving source and a stationary observer.

2. It is greater at higher temperatures, but only in the case of a moving observer and a stationary source.

3. The Doppler effect does not change as the temperature increases.

4. It is less at higher temperatures than at lower temperatures.

5. It is greater at higher temperatures than at lower temperatures.

Answers

The correct option is 2. It is greater at higher temperatures, but only in the case of a moving observer and a stationary source. The Doppler effect is a change in the frequency of a wave caused by the relative motion of the source and observer.

This effect can be noticed in both sound waves and light waves. Sound waves require a medium for transmission and it is not applicable to vacuum. The frequency of the sound wave depends on the medium in which the wave is traveling. As the temperature of the medium increases, the speed of sound also increases. This means that the frequency of sound waves also changes, and hence the Doppler effect changes.

The Doppler effect is greater at higher temperatures but only in the case of a moving observer and a stationary source. The reason is that the temperature of the medium affects the speed of sound, but not the relative motion of the source and observer.

Therefore, option 2, which states that the Doppler effect is greater at higher temperatures, but only in the case of a moving observer and a stationary source.

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Sensors inside loT wearable devices typically collect information such as (A) pH and air pressure B D volume and light levels location and heart rate temperature and humidity

Answers

Sensors inside IoT wearable devices typically collect information such as location and heart rate, temperature and humidity.

IoT wearable devices are designed to monitor various aspects of human health and the surrounding environment. They incorporate sensors that can collect data to provide valuable insights and enable personalized experiences.

Location and heart rate monitoring are common features in many wearable devices. Location tracking allows users to track their movements and enables applications like fitness tracking or navigation. Heart rate monitoring provides real-time information about the user's heart rate, which is crucial for fitness monitoring, stress management, and detecting abnormal heart rhythms.

Temperature and humidity sensors are also commonly integrated into wearable devices. These sensors measure the ambient temperature and humidity levels, providing information about the surrounding environment. This data can be used for various purposes such as monitoring comfort levels, assessing heat stress, or tracking environmental conditions for specific applications like agriculture or sports.

Collecting pH and air pressure data is less common in consumer wearable devices but may be used in specialized applications. pH sensors can be used for monitoring sweat or other bodily fluids to gain insights into hydration levels or assess certain health conditions. Air pressure sensors can provide information about altitude changes, weather patterns, or even be used for indoor air quality monitoring.

Overall, the sensors integrated into IoT wearable devices are selected based on the specific purpose and application of the device, aiming to provide meaningful data for the intended use case.

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4. What is the acceleration of a car traveling at 65 mph that keeps a constant speed over
75 seconds?
a. 0.0 mphis
b. 65 m/s2
c. 75 mphis
d. 75 m/s2
e. Not enough data is given.

Answers

Answer:

a.

Explanation:

Remeber speed and velocity are the same concept, it just speed is scalar, meaning it doesn't have a direction nor it negative.

So technically thr car had a constant speed over 75 seconds.

If thr car has a constant speed, the car isn't speeding up or slowing down so it has accleration of 0 so the answer is a.

All scientific inquiry is done using the ______________ method.

Answers

Answer:

The scientific method

Make an observation.

Ask a question.

Form a hypothesis, or testable explanation.

Make a prediction based on the hypothesis.

Test the prediction.

Iterate: use the results to make new hypotheses or predictions.

Explanation:

why is acquisition a necessary part of the crm strategy cycle? what steps should be taken to ensure an acquisition strategy is implemented successfully?

Answers

Acquisition is a critical component of the CRM strategy cycle and a successful acquisition strategy is necessary to attract and convert potential customers into actual ones. By following the steps outlined above, a company can ensure a successful acquisition strategy is implemented and achieve its growth and sustainability goals.

Acquisition is a critical component of the customer relationship management (CRM) strategy cycle because it involves the process of attracting and converting potential customers into actual ones. A successful acquisition strategy is necessary to maintain a steady flow of new customers, which is crucial for a company's growth and sustainability. In this article, we'll discuss why acquisition is necessary and the steps that should be taken to ensure a successful acquisition strategy is implemented.

Acquisition is the first step in the CRM strategy cycle and sets the foundation for the entire cycle. A successful acquisition strategy ensures that a company is attracting and converting potential customers into actual ones. This process is essential for a company's growth and sustainability as it helps to increase its customer base and revenue.

To ensure a successful acquisition strategy is implemented, the following steps should be taken:

Define the target audience: The first step in creating a successful acquisition strategy is to clearly define the target audience. This includes identifying the demographic, geographic, and psychographic characteristics of the target audience.

Determine the acquisition channels: The next step is to determine the channels through which the target audience will be reached. This could include traditional marketing channels such as print or broadcast advertising, or digital channels such as social media, email, or search engine optimization.

Measure and optimize the acquisition process: Once the acquisition channels have been established, it is important to measure the effectiveness of the acquisition process. This involves tracking key metrics such as the cost per acquisition and the conversion rate. Based on this information, the acquisition process can be optimized to improve its efficiency and effectiveness.

Personalize the customer experience: Personalizing the customer experience is key to a successful acquisition strategy. This involves understanding the needs and preferences of the target audience and tailoring the acquisition process to meet their specific needs.

Continuously evaluate and refine the acquisition strategy: Finally, it is important to continuously evaluate and refine the acquisition strategy. This involves regularly reviewing the acquisition process, tracking key metrics, and making changes as necessary to ensure the acquisition process remains effective and efficient.

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An airplane is traveling at an altitude of 15,490 meters. A box of supplies is dropped from its cargo hold. What is the cargo's velocity when it hits the ground? (Show your work and do not forget units)

Answers

Answer :

556.59 m/s.

Explanation:

Given that,

An airplane is traveling at an altitude of 15,490 meters.

A  box of supplies is dropped from its cargo hold. We need to find the velocity of cargo when it hits the ground.

The initial velocity of the box is 0 as it as at rest. Let v is the velocity of cargo when it hits the ground. We can find it using third equation of motion as follows :

\(v^2-u^2=2as\)

Put u = 0 and a = g

\(v^2=2gs\\\\v=\sqrt{2gs} \\\\v=\sqrt{2\times 10\times 15490 } \\\\v=556.59\ m/s\)

So, when it hits the ground its velocity is 556.59 m/s.

How can the density of an object be determined?”

Answers

Answer:

First you need to know the mass (grams) of the object and its volume, then what you do is  Divide the mass by the volume in order to get an object's Density.

Explanation:

hope that helped good luck :)

Answer:

m/p, aka mass/volume.

Explanation:

for example if you had an object that had a mass of 10 and volume of 5, the density of that object would be 10/5, or 2.

what is a concentration?​

Answers

Answer/Explanation:

In chemistry, concentration is the abundance of a constituent divided by the total volume of a mixture. Several types of mathematical description can be distinguished: mass concentration, molar concentration, number concentration, and volume concentration.

A concentration refers to a subject or study within a specific major. As part of the degree coursework, concentration classes count toward your major requirements as well.

To lift a transformer straight up from the floor to a truck bed located 1.30 m above the floor requires 180 J of work. What is the weight of the transformer?

Answers

The weight of the transformer is 138.46 N.

How to calculate weight?

Weight can be calculated by dividing workdone by height

To calculate the weight of the transformer, we use the formula below.

Formula:

W = E/h................... Equation 1

Where:

W = Weight of the transformerE = Work done to lift the transformer from the floor = 180 Jh = Height at which the transformer was lifted = 1.3 m

Substitute these values into equation 1

W = 180/1.3W = 138.46 N

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a proton and electron are released at the same speed traveling in the same direction into a region with a uniform b-field. compared to the circular path traveled by the electron, what can we say about the path traveled by the proton?

Answers

The path traveled by the proton will be larger than that of the electron due to its larger mass and charge. When a proton and an electron are released at the same speed traveling in the same direction into a region with a uniform magnetic field, they will both experience a force due to the magnetic field.

The direction of this force is perpendicular to the direction of motion of the particle and the direction of the magnetic field, and its magnitude is proportional to the charge of the particle, its velocity, and the strength of the magnetic field. As a result, both the proton and the electron will follow a circular path in the magnetic field. However, since the mass of the proton is much greater than that of the electron, the proton will have a much larger momentum and a larger radius of curvature than the electron.

This means that the proton will travel in a larger circular path compared to the electron. Additionally, since the force on the proton is proportional to its charge, which is much greater than that of the electron, the proton will experience a much greater force than the electron, causing it to move in a larger circle than the electron. When released at the same speed and direction into a uniform magnetic field, the proton, and the electron will both move in circular paths, but the path traveled by the proton will be larger than that of the electron due to its larger mass and charge.

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A
is the order in which things are arranged.
O plan
sequence
O process
O goal

Ais the order in which things are arranged.O plansequenceO processO goal

Answers

A sequence is the order in which things are arranged.

Answer:

sequence

Explanation:

sequences are the way in which things are ordered, for example: 1, 2, 3, 4 is a sequence:)

Problem 4: Two charges lie in a line along the x axis. Charge 1 is q1 = 1. 5 C and charge 2 is q2 = 2. 4 C. They are each a distance of d = 0. 063 m from the origin

Answers

The total electric field at the origin due to the two charges is 9.9 x 10^11 N/C.

To solve this problem, we need to find the electric field created by the two charges at the origin.

The electric field created by a point charge q at a distance r from the charge is given by Coulomb's Law:

E = k * q / r^2

where E is the electric field, k is the electrostatic constant (9 x 10^9 N*m^2/C^2), q is the charge, and r is the distance from the charge.

In this case, we have two charges, q1 = 1.5 C and q2 = 2.4 C, located at a distance of d = 0.063 m from the origin. The charges are aligned along the x-axis.

The electric field at the origin due to charge 1 is given by:

E1 = k * q1 / d^2

The electric field at the origin due to charge 2 is given by:

E2 = k * q2 / d^2

To find the total electric field at the origin, we need to consider the vector sum of the electric fields created by the two charges:

E_total = E1 + E2

Substituting the given values and calculating:

E1 = (9 x 10^9 N*m^2/C^2) * (1.5 C) / (0.063 m)^2

E1 = 3.81 x 10^11 N/C

E2 = (9 x 10^9 N*m^2/C^2) * (2.4 C) / (0.063 m)^2

E2 = 6.09 x 10^11 N/C

E_total = 3.81 x 10^11 N/C + 6.09 x 10^11 N/C

E_total = 9.9 x 10^11 N/C

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Light can escape a black hole eventually. Question 1 options: True False.

Answers

Answer:

False

Explanation: not even light can escape through the event horizon from the black hole. At its center, each black hole is thought to have a singularity, a point of infinite density, and zero volume.

False because light can’t escape from a black hole because it’s a black hole DUH

A roller coaster is traveling at 80m/hr until the emergency breaks turn on, causing it to come to a complete stop in 10s. What is the acceleration of the roller coaster?

Answers

This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.

What is decelerating?

Decelerating is the process of slowing down or decreasing the speed of a vehicle, person, or object. It is the opposite of accelerating, which is the process of increasing speed. Deceleration can be caused by the force of friction from the road or other surfaces, or by reducing the amount of engine power or braking. Deceleration is necessary to safely slow down and stop a vehicle and to negotiate turns or curves in the road.

The acceleration of the roller coaster can be calculated using the equation
a = (Vf - Vi)/t, where Vf is the final velocity, Vi is the initial velocity, and t is the time taken for the change in velocity to occur.
In this case, Vf = 0m/hr, Vi = 80m/hr, and t = 10s.
Therefore, the acceleration of the roller coaster is -8m/s².
This means that the roller coaster is decelerating at a rate of 8m/s² until it comes to a complete stop.

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Set sampling period Ts=1/1000 (sec), and time axis 0 ~ 5 (sec).
Generate signals: x1(t)=10cos(ω1t); x2(t)=6sin(ω2t); x3(t)=cos(ω3t)+ 10sin(ω3t);
where ω1=50 Hz; ω2=95 Hz; ω3=120 Hz;
plot x1(t) within the maximum amplitude and time of 0~0.5 second,

Let y1(t)= x1(t)+ x2(t)+ x3(t), plot y1(t) within the maximum amplitude and time of 0~0.5 second.
ndicate the labels in x-axis and y-axis

Answers

The x-axis should be labeled with the time values in seconds from 0 to 0.5, and the y-axis should be labeled with the values of x1(t) ranging from -10 to 10, considering the maximum amplitude of the signal.

To plot the signal x1(t) within the time range of 0 to 0.5 seconds, we need to determine the corresponding values of x1(t) for that time range.

Given that x1(t) = 10cos(ω1t) with ω1 = 50 Hz, we can calculate the values of x1(t) using the formula.

For the time range of 0 to 0.5 seconds:
- At t = 0 seconds, x1(t) = 10cos(ω1 * 0) = 10cos(0) = 10 * 1 = 10.
- At t = 0.5 seconds, x1(t) = 10cos(ω1 * 0.5) = 10cos(25π) ≈ -7.071.

Plotting these values on the y-axis against the corresponding time values on the x-axis will give us the graph of x1(t) within the time range of 0 to 0.5 seconds.

The x-axis should be labeled with the time values in seconds from 0 to 0.5, and the y-axis should be labeled with the values of x1(t) ranging from -10 to 10, considering the maximum amplitude of the signal.

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Which of the following is not a way to make exercising on a cold day safer?
A. Wear gloves and thick socks.
B. Dress in several layers instead of wearing one bulky garment for warmth.
C. Drink hot tea during your workout.
D. Wear a synthetic or wool hat.
I NEED HELP ASAP FIRST ANSWER GETS BRAINLIEST

Answers

Answer:

D.

Explanation:

I think its D. because Tea during a cold workout isnt safe at all. Drinking tea while working out adds weight and you just simply dont need tea when working out.. Hope this helps man :)

C. You shouldn't exercise while drinking hot tea because you can spill it and burn yourself especially while on a treadmill.

If this helped please mark me as brainliest!

\(\left[\begin{array}{ccc}Thanks,\\JustSomeIdiot\end{array}\right]\)

You are in a car and go around a corner very fast. What happens to you?

Answers

Answer:

You may tip the car over or crash.

Explanation:

Going really fast at high speeds and turn a corner might make the car crash into an object or fall over.

A microphone is attached to a spring that is suspended from the ceiling, as the drawing indicates. Directly below on the floor is a stationary 375-Hz source of sound. The microphone vibrates up and down in simple harmonic motion with a period of 1.80 s. The difference between the maximum and minimum sound frequencies detected by the microphone is 2.75 Hz. Ignoring any reflections of sound in the room and using 343 m/s for the speed of sound, determine the amplitude (in m) of the simple harmonic motion.

Answers

Answer:

\(0.361\ \text{m}\)

Explanation:

\(f_s\) = Frequency of source = 375 Hz

\(\Delta f\) = Difference between the maximum and minimum sound frequencies = 2.75 Hz

v = Speed of sound in air = 343 m/s

T = Time period = 1.8 s

\(v_m\) = Maximum speed of the microphone

We have the relation

\(\Delta f=2f_s\dfrac{v_m}{v}\\\Rightarrow v_m=\dfrac{\Delta fv}{2f_s}\\\Rightarrow v_m=\dfrac{2.75\times 343}{2\times 375}\\\Rightarrow v_m=1.26\ \text{m/s}\)

Amplitude is given by

\(A=\dfrac{v_mT}{2\pi}\\\Rightarrow A=\dfrac{1.26\times 1.8}{2\pi}\\\Rightarrow A=0.361\ \text{m}\)

The amplitude of the simple harmonic motion is \(0.361\ \text{m}\).

At perihelion, the Earth is 96% of the Earth-sun distance at aphelion. Which of the following statements would be correct?

a-At aphelion, because the gravitational attraction is greater, the speed of the Earth is lower.

b-At aphelion, because the gravitational attraction is lower, the speed of the Earth is higher.

c-At perihelion, because the gravitational attraction is lower, the speed of the Earth is lower.

d-At perihelion, because the gravitational attraction is higher, the speed of the Earth is higher.

Answers

At aphelion, the Earth is 96% of the Earth-sun distance at aphelion which means that the correct statement is that at aphelion, because the gravitational attraction is lower, the speed of the Earth is higher and is denoted as option B.

What is Aphelion?

This is referred to as the  farthest point in the orbit of a planet such as the earth from the sun.

In a a scenario where the Earth is 96% of the Earth-sun distance at aphelion, then it means that the orbit has almost been completed which means that a high amount of speed was involved in the process.

This is as a result of the gravitational attraction being lower which has an inverse relationship with the speed of the Earth which is why it was higher and is therefore the reason why option B was chosen.

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A car has a momentum of -456 kg*m/s. What direction is it moving?

Answers

backward movement

because momentum = mass × speed

And mass must be in positive value..

so negative value is speed

which moving backward..

A car accelerates uniformly from rest and
reaches a speed of 9.2 m/s in 9.7 s. The
diameter of a tire is 47.8 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slip-
ping
Answer in units of rev.

Answers

Answer:

29.75 revolutions

Explanation:

The kinematic formula for distance, given a uniform acceleration a and an initial velocity v₀, is

\(d=v_0t+\frac{1}{2}at^2\)

This car is starting from rest, so v₀ = 0 m/s. Additionally, we have a = 9.2/9.7 m/s² and t = 9.7 s. Plugging these values into our equation:

\(d=0t+\frac{1}{2}\left(\frac{9.2}{9.7}\right)(9.7)^2\\d=\frac{1}{2}(9.2)(9.7)\\d=4.6(9.7)\\d=44.62\)

So, the car has travelled 44.62 m in 9.7 seconds - we want to know how many of the tire's circumferences fit into that distance, so we'll first have to calculate that circumference. The formula for the circumference of a circle given its diameter is \(c=\pi{d}\), which in this case is 47.8π cm, or, using π ≈ 3.14, 47.8(3.14) = 150.092 cm.

Before we divide the distance travelled by the circumference, we need to make sure we're using the same units. 1 m = 100 cm, so 105.092 cm ≈ 1.5 m. Dividing 44.62 m by this value, we find the number of revs is

\(44.62/1.5\approx29.75\) revolutions

An air conditioner uses a compressor to raise the temperature and pressure of _____. A. The outside air
B. The refridgerant
C. The inside air

Answers

Answer:

B. The refridgerant

Explanation:

this allows the refrigerant to absorb or release heat

A 100g ball moving to the right at 4.5m/s catches up and collides with a 420g ball that is moving to the right at 1.2m/s .
If the collision is perfectly elastic, what is the speed of the 100g ball after the collision?
If the collision is perfectly elastic, what is the direction of motion of the 100g ball after the collision?
If the collision is perfectly elastic, what is the speed of the 420g ball after the collision?
If the collision is perfectly elastic, what is the direction of motion of the 420g ball after the collision?

Answers

The speed of the 100g ball after the collision is 2.52 m/s. The direction of motion of the 100g ball after the collision is still to the right. The speed of the 420g ball after the collision is 0.71 m/s. The direction of motion of the 420g ball after the collision is still to the right.

To solve this problem, we can use the conservation of momentum and the conservation of kinetic energy. Since the collision is perfectly elastic, the total momentum and total kinetic energy of the system will be conserved before and after the collision.

Let's denote the 100g ball as ball 1 and the 420g ball as ball 2. The initial momenta and kinetic energies of the system are:

Initial momentum: P = m1v1 + m2v2 = (0.1 kg)(4.5 m/s) + (0.42 kg)(1.2 m/s) = 0.51 kg m/s

Initial kinetic energy:\(K = (1/2)m1v1^2 + (1/2)m2v2^2 = (1/2)(0.1 kg)(4.5 m/s)^2 + (1/2)(0.42 kg)(1.2 m/s)^2 = 1.08 J\)

After the collision, the total momentum and kinetic energy of the system will still be conserved. Let's denote the final velocities of ball 1 and ball 2 as v1' and v2', respectively.

Conservation of momentum: P = m1v1' + m2v2'

0.51 kg m/s = (0.1 kg)v1' + (0.42 kg)v2'

Conservation of kinetic energy: \(K = (1/2)m1v1'^2 + (1/2)m2v2'^2\\1.08 J = (1/2)(0.1 kg)v1'^2 + (1/2)(0.42 kg)v2'^2\)

To solve for v1' and v2', we need to solve the two equations above simultaneously. One way to do this is to solve for one variable in one equation and substitute it into the other equation.

Solving for v2' in the momentum equation:

v2' = (0.51 kg m/s - (0.1 kg)v1') / (0.42 kg)

Substituting v2' into the kinetic energy equation:

\(1.08 J = (1/2)(0.1 kg)v1'^2 + (1/2)(0.42 kg)[(0.51 kg m/s - (0.1 kg)v1') / (0.42 kg)]^2\)

Simplifying and solving for v1':

v1' = 2.52 m/s

To find the final velocities of ball 1 and ball 2, we can substitute v1' into the momentum equation to find v2':

v2' = (0.51 kg m/s - (0.1 kg)(2.52 m/s)) / (0.42 kg) = 0.71 m/s

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• Build Simulink Model of Amplitude Modulator and Square Law Demodulator • Fm = 1 Khz = • Fc = 30 Khz • Simulation time=0.10, 1, 2 sec respectively.

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To build a Simulink model of an amplitude modulator and square law demodulator, you can follow these steps:

Open Simulink in MATLAB.Create a new model by selecting File -> New -> Model.Add the necessary blocks for the amplitude modulator. This will include a sinusoidal signal source (to represent the message signal), a carrier signal source, a multiplier block (to perform the modulation), and an output display or scope block.Set the frequency of the message signal (Fm) to 1 kHz and the frequency of the carrier signal (Fc) to 30 kHz using appropriate blocks or parameters.Connect the blocks properly to create the modulation process.Save the amplitude modulator subsystem within the model for future use.Add the necessary blocks for the square law demodulator. This will include a square law device (to demodulate the signal), a low-pass filter (to remove the high-frequency components), and an output display or scope block.Connect the blocks properly to create the demodulation process.Save the square law demodulator subsystem within the model for future use.Set the simulation time to 0.10 seconds, 1 second, and 2 seconds respectively by specifying the appropriate simulation time parameters in the simulation settings.Run the simulation to observe the output of the amplitude modulator and square law demodulator for the specified simulation times.

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the speed of light in sapphire is 1.69 x 10^8 m/s. determine the index of refraction for sapphire.​

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Answer:

1.775 is the answer

Explanation:

We can figure out the index of refraction of the sapphire by using the following equation n = c/v

n  =  index of refraction

c  =  speed of light in a vacuum

v  =  speed of light traveling in medium

Step 1 :

v = 1.69 × 10^8

c = 3 × 10^8

Step2: Substitute values

n = c/v -----> n = 3 × 10^8 / 1.69 × 10^8 = 3/1.69 = 1.775

Index of refraction of sapphire is 1.775

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