An object accelerates from rest (v0), with a constant acceleration of 8.6 m/s^2 (a), what will its velocity (v) be after 7.2 s (t)?

Our muscles need more oxygen to make energy (in the form of ATP) while we workout.

When the respiratory rate picks up to fulfill this need, more oxygen can enter the body and more carbon dioxide can be exhaled.

Student 3 is breathing more forcefully than usual in this situation because of the high temperature and physical activity.

The respiratory system is the organ system engaged in this process.

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# complete question:

A group of students were playing basketball together during recess. The temperature outside was 30.5 oC (87 oF) and the sun was out. The students ran, shot baskets, and dribbled the ball for 30 minutes. When they finished their game some of the students made the following comments:

Student 1: Wow! I am so hot and sweaty! I need some water to cool down.

Student 2: My cheeks are really red.

Student 3: I am breathing so hard, I can barely catch my breath!

Explain what is happening to the students and how their bodies are trying to maintain homeostasis. Be sure to include any of the organ systems involved with each student.

Answer:

8 Hz, 0.125 sec, 0.75 m

Explanation:

frequency f = 8 Hz

period T = 1/f = 1/8 sec = 0.125 sec

speed v = 6 m/s

wavelength = v/f = 6/8 = 0.75 m

One of the conclusion about the history of sports that can be drawn from the movie "Champions" is that sports have a long and rich history that is intertwined with the history of human civilization.

From the ancient Olympic Games to the modern-day Olympics, sports have been a way for people to come together and compete in a spirit of sportsmanship and competition. Sports have also been a way for people to express themselves, to build community, and to achieve personal goals.

The movie "Champions" tells the story of a group of young men who come together to form a football team. The team is made up of boys from different backgrounds and with different abilities. However, they are all united by their love of football and their desire to win.

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Answer:

One way to increase acceleration is by changing the velocity.

Answer:

shreya Sister's answer is correct hope it's help you have a good day

Answer:

It is necessary to search for new sources of energy because the sources we have now are non-renewable and exhaustible. The usage of these sources are increasing day by day and if this continues then one day we wlii be left with none so it is necessary to search for new sources of energy

A cell of inter resistance of 0.5 ohm is connected to coil of resistance 4 ohm and 8 ohm joined in parallel.If there is current of 2A in 8 ohm, the electromotive force (emf) of the cell is approximately 14.5 volts.

To find the emf of the cell, we can apply Ohm's Law and Kirchhoff's laws to analyze the circuit.

Given:

Resistance of the coil, R1 = 4 ohm

Resistance of the other resistor, R2 = 8 ohm

Current passing through the 8-ohm resistor, I = 2A

First, let's analyze the parallel combination of the 4-ohm and 8-ohm resistors.

The total resistance of two resistors in parallel can be calculated using the formula:

1/Rp = 1/R1 + 1/R2

Substituting the given values, we have:

1/Rp = 1/4 + 1/8

1/Rp = 2/8 + 1/8

1/Rp = 3/8

Rp = 8/3 ohm

Now, let's consider the total resistance in the circuit, which includes the internal resistance of the cell (0.5 ohm) and the parallel combination of the resistors (8/3 ohm).

R_total = R_internal + Rp

R_total = 0.5 + 8/3

R_total = 1.833 ohm

Now, we can find the emf of the cell using Ohm's Law:

emf = I * R_total

emf = 2 * 1.833

emf ≈ 3.667 volts

Therefore, the emf of the cell is approximately 3.667 volts.

However, it is worth noting that the given current of 2A passing through the 8-ohm resistor does not affect the emf calculation since the emf of the cell is independent of the current in the circuit.

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Answer:

An object moves in a straight line along a horizontal surface.

Answer:

A and D

Explanation:

A:the kinetic energy does decrease due to the decrement of the velocity i.e the slope is negative velocity.

it is true

B.the change of moment is not zero cause there is difference between initial and final velocity

it is false

c.also work done is not zero you can chaekc it using the formula 1/2m (vf -vi)² and choice

it is flase

D. the impulse is the applied force per time Which is mass of the object multiplied by it's the change in momentum. it is true

Answer:

The acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

Explanation:

We want to find the acceleration due to gravity on the planet Fregie. Let it be g m/s^2.

Now, the acceleration due to gravity is defined through the following equation:

\(mg = GMm/R^2\)

where m is the mass of an object on the surface of the planet, M is the mass of the planet, R is the radius of the planet, and G is the universal Gravitational constant.

Subsituting values for M = 6.23*10^23, R = 5.79*10^7, G = 6.67*10^(-11), we get

g = 0.0123 m/s^2.

Thus the acceleration due to gravity on the planet Fergie is 0.0123 m/s^2.

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Answer:

Acceleration and mass.

Explanation:

Depends on how heavy the car is and how fast it is going.

F=MA

The weight of an  astronaut on the Moon compare to that of an astronaut on Earth or Mars as: D. The astronaut weighs the most on Earth and the least on the Moon.

Given the following data:

We know that acceleration due to gravity (a) for an object on Earth is equal to 9.8 meter per seconds square.

Mathematically, the weight of an object is calculated by using the following formula;

\(Weight = mg\)

Where:

In order to determine the weight of an astronaut on the Moon, we would assume a value for his mass as 100 kilograms.

\(Weight \; on\; Moon = 100\) × \(1.6\)

Weight on Moon = 160 Newton

For Mars:

\(Weight \; on\; Mars = 100\) × \(3.7\)

Weight on Mars = 370 Newton

For Earth:

\(Weight \; on\; Earth = 100\) × \(9.8\)

Weight on Earth = 980 Newton

Therefore, we can deduce from the above calculations that, the astronaut weighs the most on Earth and the least on the Moon.

The frequency calculator will let you find a wave's frequency given the wavelength and its velocity or period in no ... velocity equals 320 m/s and its wavelength is 8 m. Find its frequency. f = 320 m/s / 8 m. f = 40/s. f = 40 Hz.

Answer:

Explanation:

Speed= distance/time

Or time = distance/speed

According to your question

Speed=15m/s

and. Distance=1.2km. ,we must change kilometer in meter because given speed is in m/s

D= 1.2km = 1.2×1000m =1200meter

Time = distance/ speed

1200/15 =80second

Or. 1min and 20 sec will be your answer.

Answer:

At a personal level, barriers to critical thinking can arise through: ... self-centred or societal/cultural-centred thinking (conformism, dogma and peer-pressure) unconscious bias, or selective perception. an inability to be receptive to an idea or point of view that differs from your own (close-mindedness)

Explanation:

Answer:

B

Explanation:

The answer is B

Answer:

never

Explanation:

Answer:

Explanation:

The mass of cube = 700 kg

volume = 1 m³

density = 700 kg / m²

Its density is less than that of water so it will try to float on the surface .

Tension in rope will be equal to net upward force

upthrust = volume x density of water x g

= 1 x 10³ x 9.8

= 9800 N

weight of cube = mass x g

= 700 x 9.8

= 6860 N .

Net upward force = 9800 - 6860

= 2940 N.

Tension in the rope = 2940 N.

Rope will hold the cube inside and not allow it to go outside water .

b )

If rope is cut , cube being lighter , will float on surface of water .

Part of cube inside water while floating

= 6860 / 9800

= .7

.7 m will remain inside water

part floating outside

= 1 - 0.7

= 0.3 m .

Explanation:

Because it is the easiest branch of science to understand

Knowing the exits are exactly 7 km apart, the cars pass each other at 9:29 and 15 seconds a.m.

The relative velocity of the cars is 30 m/s - 26 m/s = 4 m/s.

The distance between the cars is 7 km = 7000 m.

The time it takes for the cars to pass each other is 7000 m / 4 m/s = 1750 seconds.

1750 seconds is 29 minutes and 15 seconds.

To calculate the time in minutes;

Let:

v_p = the speed of car P (m/s)

v_q = the speed of car Q (m/s)

d = the distance between the cars (m)

t = the time it takes for the cars to pass each other (s)

Given that:

v_p = 30 m/s

v_q = 26 m/s

d = 7000 m

Use the equation for relative velocity to find the velocity of the cars relative to each other:

v_r = v_p - v_q

v_r = 30 m/s - 26 m/s = 4 m/s

Use the equation for distance to find the time it takes for the cars to pass each other:

d = v_r × t

7000 m = 4 m/s × t

t = 7000 m / 4 m/s = 1750 s

Convert 1750 seconds to minutes and seconds:

1750 s = 29 minutes and 15 seconds

Therefore, the cars pass each other at 9:29 and 15 seconds a.m.

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Answer:

F' = 162 units

Explanation:

The gravitational force of attraction between the two objects is given by Newton's Gravitational law through the following formula:

\(F = \frac{Gm_{1}m_{2}}{r^{2}}\\\\\)

where,

F = gravitational force = 18 units

G = Gravitational Constant

m₁ = mass of object 1

m₂ = mass of object 2

r = distance between objects

Therefore,

\(18 = \frac{Gm_{1}m_{2}}{r^{2}}------ eqn (1)\\\\\)

Now, if we change the value of distance to one-third of original value, then:

r' = r/3

\(F' = \frac{Gm_{1}m_{2}}{(\frac{r}{3})^{2}}\\\\F' = (9)(\frac{Gm_{1}m_{2}}{r^{2}})\)

using eqn (1):

F' = 9(18 units)

F' = 162 units

Answer:

Explanation:

y = 3x + 5

dy/dx = 3

d2y/dx2 = 0

Given :

A mover slides a refrigerator weighing 650 N at a constant velocity across the floor a distance of 8.1 m.

The force of friction between the refrigerator and the floor is 230 N.

To Find :

How much work has been performed by the mover on the refrigerator.

Solution :

Since, refrigerator is moving with constant velocity.

So, force applied by the mover is also 230 N ( equal to force of friction ).

Now, work done in order to move the refrigerator is  :

\(W = Force\times distance\\\\W = 230 \times 8.1\ N\ m\\\\W = 1863\ N\ m\)

Hence, this is the required solution.

The acceleration of the object in the inclined plane is g sinθ.

The velocity of the object on the inclined plane is √(2gL sinθ).

Given that the inclined surface is a frictionless surface. So, the force of friction is zero. Hence the components of the weight of the object provides the necessary forces to slide the object over the inclined plane.

a) Newton's second law is applied to masses on inclination.

Acceleration due to multiplied by the sine of the angle of inclination provides the acceleration for a frictionless slope of angle in degrees.

The acceleration of the object in the inclined plane is,

a = g sinθ

b) Applying the third equation of motion,

v²- u² = 2as

v² = 2as

v² = 2 x g sinθ x L

Therefore, the velocity of the object on the inclined plane is given by,

v = √(2gL sinθ)

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Answer:

Explanation:

Applying the law of collision:

Sum of momentum before collision = sum of momentum after collision

Both object move with the same velocity after collision

Momentum = mass × velocity

Sum of momentum before collision;

= 5.65(5.4)+(8)(-5.5)

= 30.51-44

= -13.49kgm/s

Sum of momentum after collision

= (8.0+5.65)v

= 13.65v

Equate;

-13.49 = 13.65v

v = -13.49/13.65

v = -0.988m/s

Hence the velocity of the otter after collision is 0.988m/s ( both moving towards the left)

Answer:

24 cm/s

Explanation:

Applying

Pythagoras theorem,

a² = b²+c²............. Equation 1

Where a = resultant, b = vertical component, c = horizontal component

From the question,

Given: a = 26 cm/s, c = 10 cm/s

Substitute these values into equation 1

26² = b²+10²

676 = b²+100

b² = 676-100

b² = 576

b = √576

b = 24 cm/s

After the impact, the two players are moving side by side at a speed of roughly 4.12 m/s.

Momentum is never created or destroyed inside a problem domain, according to the principle of momentum conservation. Momentum is only changed by the action of forces as they are described by Newton's equations of motion.

\(p1 = m1 * v1 + m2 * v2\)

\(p1 = 165 kg * 0 m/s + 178 kg * 8 m/s = 1424 kg*m/s\)

\(p2 = (m1 + m2) * v\)

Substituting the values, we get:

\(p2 = (165 kg + 178 kg) * v = 343 kg * v\)

Since the total momentum is conserved, we can equate p1 and p2:

p1 = p2

\(165 kg * 0 m/s + 178 kg * 8 m/s = 343 kg * v\)

\(v = (165 kg * 0 m/s + 178 kg * 8 m/s) / 343 kg ≈ 4.12 m/s\)

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