An object is being acted on by a force of 20 N directed to the left and a force of 30 N directed to the right. What is the net force acting on the object

Answer:

The change in time for the first quarter is  seconds.  = 2.07

The change in time for the second quarter is  seconds.

=1.09

The change in time for the third quarter is  seconds.

=0.95

The change in time for the fourth quarter is  seconds.=0.81

Explanation:

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The overestimated distance traveled between t=0 and t=5 is 158 meters.

To estimate the distance traveled, we can use the trapezoidal rule to approximate the area under the curve of the velocity function v(t). The trapezoidal rule divides the interval [0, 5] into subintervals with a width of 1 second and approximates each subinterval as a trapezoid. The formula for the trapezoidal rule is ∫[a,b] f(x) dx ≈ ∑[(i=1 to n)] [f(x_i-1) + f(x_i)] * Δx / 2, where Δx is the width of each subinterval.

Using this formula, we can calculate the overestimated distance traveled:

s ≈ [f(0) + 2f(1) + 2f(2) + 2f(3) + 2f(4) + f(5)] * Δt / 2

≈ [0 + 2(1^2 + 6) + 2(2^2 + 6) + 2(3^2 + 6) + 2(4^2 + 6) + (5^2 + 6)] * 1 / 2

≈ 158 meters.

This provides an overestimate of the distance traveled between t=0 and t=5.

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The critical angle of the transparent material is 35.3 degrees.

The critical angle is the angle of incidence at which the angle of refraction is 90 degrees. In this case, the angle of refraction is 32 degrees. Therefore, the critical angle is calculated as follows:

sin(critical angle) = sin(90 degrees) / sin(angle of refraction)

sin(critical angle) = 1 / sin(32 degrees)

sin(critical angle) = 0.574

critical angle = arcsin(0.574)

critical angle = 35.3 degrees

Therefore, the critical angle of the transparent material is 35.3 degrees.

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The standard free energy change (ΔG°) and the equilibrium constant (K) are related through the equation ΔG° = -RTlnK, where R is the gas constant and T is the temperature in Kelvin.

This equation is known as the Gibbs-Helmholtz equation and it shows that the standard free energy change of a reaction is directly related to the equilibrium constant. In other words, the more negative the ΔG°, the larger the value of K and the greater the extent of the reaction towards the products. Conversely, a less negative ΔG° indicates a smaller value of K and a lower extent of the reaction towards the products. Therefore, the relationship between ΔG° and K is a fundamental aspect of thermodynamics and is used to predict the direction and extent of chemical reactions.

The standard free energy change (ΔG°) and the equilibrium constant (K) are related through the equation ΔG° = -RTlnK, where R is the gas constant (8.314 J/mol K) and T is the temperature in Kelvin. This equation shows the connection between the thermodynamic properties of a reaction and its equilibrium behavior.

1. Calculate the standard free energy change (ΔG°): If you know the equilibrium constant (K) and the temperature (T), you can use the equation to find the standard free energy change for the reaction.

2. Determine the equilibrium constant (K): If you know the standard free energy change (ΔG°) and the temperature (T), you can rearrange the equation to find the equilibrium constant for the reaction: K = e^(-ΔG°/RT).

The relationship between ΔG° and K tells us the following:

- If ΔG° is negative, the reaction is spontaneous and proceeds in the forward direction, and K > 1, meaning the products are favored at equilibrium.
- If ΔG° is positive, the reaction is non-spontaneous and proceeds in the reverse direction, and K < 1, meaning the reactants are favored at equilibrium.
- If ΔG° is zero, the reaction is at equilibrium, and K = 1, meaning the concentrations of reactants and products are equal.

In summary, the equation ΔG° = -RTlnK links the standard free energy change of a reaction with its equilibrium constant, allowing us to understand the direction and extent to which a reaction proceeds.

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Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.

To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.

The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).

Using the equation:

v = v₀ + at

where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:

v = 0 + (0.75 m/s²) * t

v = 0.75t m/s

The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:

v = ωr

Substituting the values:

0.75t = ω * 300

Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:

ω = ω₀ + αt

ω = 0 + (0.75 m/s²) * t

ω = 0.75t rad/s

We can now substitute the value of ω into the equation:

0.75t = (0.75t) * 300

Simplifying the equation gives:

0.75t = 225t

t = 0.75 seconds

The time elapsed is 0.75 seconds.

To calculate the distance traveled (s), we can use the equation:

s = v₀t + (1/2)at²

Since the initial velocity (v₀) is zero, the equation becomes:

s = (1/2)at²

s = (1/2)(0.75 m/s²)(0.75 s)²

s = (1/2)(0.75 m/s²)(0.5625 s²)

s = 0.2119 meters or approximately 21.19 centimeters

Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.

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Explanation:

The area under a displacement vs time graph is the absement.

Given,

The mass of the box, m=35.0 kg

The height to which the box was lifted, h=1.75 m

Potential energy is the energy possessed by an object due to its position.

The gravitational potential energy gained by the box is,

Where g is the acceleration due to gravity.

On substituting the known values,

Thus the gravitational potential energy gained by the box is 600.25 J

The buoyancy force on the boat in the water has a value of 107800 N.

The buoyant force on the boat in the water can be calculated using Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object. In this case, the fluid is water, which has a density of 1000 kg/m³.

The buoyant force (Fb) can be calculated using the formula:
Fb = density of water × volume of water displaced × acceleration due to gravity
Fb = (1000 kg/m³) × (11 m³) × (9.8 m/s²)
Fb = 107800 N

Therefore, the buoyant force on the boat in the water is 107800 N.

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The radius of the object in circular motion is 82.1 meters, under the condition that a tangential velocity of 18.5m/s in the given duration of 28 seconds.

Hence using all the given information to derive a particular formula:

v = 2πr/T

Here,

v = tangential velocity,

r = radius of the circular path

T= time period of circular motion.

Restructuring the formula to evaluate r

r = vT/2π

Staging the given values in the provided formula

r = (18.5 m/s) x (28 s) / (2π)

r = 518/2(3.14)

Applying simplification to the expression

r ≈ 82.1 m

Then, the radius of the object is approximately 82.1 meters.

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The complete question is

What is the radius of the object in circular motion with a tangential velocity of 18.5m/s that takes 28 seconds to make one revolution?

It  is eight times more than the star A.

The luminosity of an object is a measure of its intrinsic brightness and is defined as the amount of energy the object emits in a fixed time.

luminousity depends upon the two factors are:

1) The star's actual brightness

Some stars are naturally more luminous than others ,so the brightness level from one star to next star is significantly different.

2) The star distance from us

The more distance of an object the dimmer it appears.

Energy emitted = sAT⁴

where s is stefan constant

A is surface area and T is temperature  .  

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Both the assertion and the reason given are true.If the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

The given assertion: When astronauts throw something in space, that object would continue moving in the same direction and with the same speed; and the given reason: The acceleration of an object produced by a net applied force is directly related to the magnitude of the force, and inversely related to the mass of the object are both correct.Astronauts are capable of throwing objects in space because they are beyond Earth's gravity and do not have to deal with any significant air resistance. In the absence of other forces like friction or air resistance, the initial velocity will be conserved, and the object will continue to move with the same speed and direction. The object would continue to move in a straight line with the same speed because no external force acts on it to change the object's state of motion.Newton's second law states that the force of an object is directly proportional to its acceleration, but inversely proportional to its mass. F=ma, where F is force, m is mass, and a is acceleration. Therefore, if the mass of the object is less, the acceleration produced by the force will be more. Hence, the acceleration produced by the force is directly proportional to the magnitude of the force and inversely proportional to the mass of the object.

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Answer:

The amount of work the factory worker must to stop the rolling ramp is 294 joules

Explanation:

The object rolling down the frictionless ramp has the following parameters;

The mass of the object = 10 kg

The height from which the object is rolled = 3 meters

The work done by the factory worker to stop the rolling ramp = The initial potential energy, P.E., of the ramp

Where;

The potential energy P.E. = m × g × h

m = The mass of the ramp = 10 kg

g = The acceleration due to gravity = 9.8 m/s²

h = The height from which the object rolls down = 3 m

Therefore, we have;

P.E. = 10 kg × 9.8 m/s² × 3 m = 294 Joules

The work done by the factory worker to stop the rolling ramp = P.E. = 294 joules

•Most of the components that make up curcuits are conductors. Electricity flows easily thought conductors such as metal or water.Electricity does not flow easily thought insulators such as wood or rubber.

•When a battery is used to power a circuit, the circuit the current must travel from one pole of the battery to the opposite battery.

•Resisotors show the flow of Electricity throught a circuit this can prevent components of the circuit from 'brning out'. In a curcuit diagram, resistors are represented by bending lines.

Answer:

The speed of the box just as it hits the ground is 5.8 m/s

Explanation:

Given;

initial velocity of the box, u = 2 m/s

height of the table, h = 1.5 m

The speed of the box, just before it hits the ground is given by;

v² = u² + 2gh

v² = (2)² + 2 x 9.8 x 1.5

v² = 4 + 29.4

v² = 33.4

v = √33.4

v = 5.8 m/s

Therefore, the speed of the box just as it hits the ground is 5.8 m/s

Answer:

v = 7 m/s

Explanation:

p = m × v

42 = 6 × v

6v = 42

v = 42/6

v = 7 m/s

It's crucial to prioritize safety on the road and maintain a safe following distance to avoid such collisions. Remember, the impact speed in a real-life scenario can be significantly higher and have severe consequences.

The impact speed of the car moving at 100 km/h that bumps into the rear of another car traveling in the same direction at 98 km/h can be calculated by finding the relative speed between the two cars.

To find the relative speed, subtract the speed of the slower car (98 km/h) from the speed of the faster car (100 km/h):
\(100 km/h - 98 km/h = 2 km/h\)

Therefore, the relative speed between the two cars is 2 km/h.

However, it's important to note that this relative speed doesn't represent the impact speed. The impact speed will depend on various factors such as the braking efficiency, mass of the cars, and the angle at which the cars collide.

In general, when two cars collide in the same direction, the impact speed is typically less than the relative speed. This is because the collision involves a transfer of kinetic energy, causing the cars to decelerate.

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Yes, the groceries stay in the bag

What is newton's second law?

Newton's Second Law of Motion says that when a force acts on a mass, the mass will speed up (object). This law of motion can be seen at work when you ride your bike. The mass is your bike. The force is your leg muscles pushing on the pedals of your bike.

We calculate the force that is exerted on the bag using Newton's second law, which states that,

F= ma

m is the mass of the object in kilograms

a is the acceleration of the object in meters per second squared. And so, we got:

F= 20kg X 5 m^2

= 100 N

So, a force of 100 newtons is exerted on the bag. Since that is less than the required 250 newtons needed to rip the bag, then the bag doesn't rip, and so the groceries stay in the bag, due to the normal force exerted on them by the bag.

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Answer:

Are similar in pattern

Explanation:

edge 2021

The sound pressure ratio ranges from 10,000 to 1,00,000. The decibel level ranges from 80 dB to 100 dB.

The meaning of sound pressure is the discrepancy between the actual pressure and average pressure at any given instant at any place in the field of a sound wave.

The intensity of a sound, expressed in decibels, is known as sound pressure level (SPL) (dB).

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Answer:

Yes you  worked

Explanation:

You may have not seen a good outcome but you did put effort in.

When a force is applied on the car and it doesn't move then it simply means

work wasn't done.

The formula for work is given below:

Work = Force ₓ Displacement

For work to have been done , the applied force must cause the object to

change its position(displacement).

In situations where the force applied doesn't cause a change in position then work can't be calculated. This means no work was done on the car despite the applied force causing him to be tired.

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Answer:

1650 meters

145=75+a.15

Answer:

1400 m

Explanation:

Given:

v₀ = 175 m/s

v = 105 m/s

t = 10.0 s

Find: Δx

Δx = ½ (v + v₀) t

Δx = ½ (105 m/s + 175 m/s) (10.0 s)

Δx = 1400 m

According to the principle of continuity, the velocity of a fluid multiplied by the cross-section through which it flows at one point will equal the product of velocity and cross-section at another point.

The principle of continuity, also known as the continuity equation, is the fluid mechanic's principle. Simply put, what flows into a defined volume over a specified period of time minus what flows out of that volume over that specified period of time must accumulate in that volume. The substance in that volume is depleted if the accumulation's sign is negative.

This is so that our eyes, once they start to follow anything, will keep moving in that direction until they come across another thing or object. A line with an arrow at the end of it, for instance, is a great illustration of the continuity concept.

Note that three conditions must be met for a function to be continuous at a point: At that time, the limit must exist.

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Given,

u = 0.5 m/s

a=0.05 m/s²

and v=0

Now, v = u − at

=> 0 = 0.5−(0.05×t)

=> t = 10 s

after 10s it will stop

velocity after 5s is

v = 0.5-(0.05×5) = 0.25 m/s

Answer:

0.25 meter per second

Explanation:

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Starburst galaxies produce most of their light in the wavelength range of (B) the ultraviolet.

Starburst galaxies are characterized by intense bursts of star formation activity, where stars are formed at a much higher rate compared to normal galaxies. These bursts of star formation produce large amounts of ultraviolet (UV) radiation.

The high-energy radiation from the young, hot, and massive stars in starburst galaxies excites surrounding gas and dust, causing them to emit light primarily in the UV wavelength range. The UV radiation is produced by the ionizing radiation from the newly formed stars, which have surface temperatures in the range of thousands to tens of thousands of degrees Celsius.

The UV emission from starburst galaxies is of particular interest to astronomers because it provides valuable insights into the formation and evolution of stars and galaxies. However, since UV radiation is absorbed by the Earth's atmosphere, observations of starburst galaxies in the UV range require space-based telescopes or specialized instruments.

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The correlation coefficient of -0.98 is an indication of a strong negative linear relationship between two variables.

This means that when one variable increases, the other variable decreases, and vice versa. The fact that the coefficient is so close to -1 further indicates that the relationship between the two is very steep and that the slope of the line of best fit is very steep and has a large negative slope. That is, when one variable increases, the other variable decreases rapidly, signifying a strong inverse linear relationship.

This implies that when one variable is at its maximum, the other variable is at its minimum and vice versa. In conclusion, the correlation coefficient of -0.98 reflects a steep negative slope of the line of best fit.

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The Coefficient of Performance (COP) for a refrigeration cycle is defined as the ratio of the cooling effect produced to the work required to produce it. It can be expressed as:

COP = Qc / W

where Qc is the cooling effect (in watts) and W is the work input (in watts).

To find the COP of the R-410a air conditioning unit, we first need to determine the cooling effect produced and the work required to produce it.

From the given data, we know that the air conditioning unit cools a house at 22∘C when the ambient temperature is 30∘C. Therefore, the temperature difference across the evaporator (cooling coil) is:

ΔT = 30 - 22 = 8∘C

Using a refrigerant properties table, we can find the enthalpy difference between the refrigerant entering and leaving the evaporator (h2 - h1) for R-410a at 800 kPa and 22∘C. Let's assume that the mass flow rate of the refrigerant is 1 kg/s.

From the table, we find that h2 - h1 = 264.8 kJ/kg.

The cooling effect produced is then:

Qc = m * (h2 - h1) = 1 * 264.8 = 264.8 W

To find the work input, we need to determine the enthalpy difference between the refrigerant entering and leaving the compressor (h3 - h2) and the refrigerant entering and leaving the condenser (h4 - h3).

From the table, we find that h3 - h2 = 291.2 kJ/kg and h4 - h3 = -30.1 kJ/kg for R-410a at 2 MPa and 30∘C.

The work input required is then:

W = m * (h3 - h2 + h4 - h3) = 1 * (291.2 - 30.1) = 261.1 W

Finally, we can calculate the COP of the air conditioning unit:

COP = Qc / W = 264.8 / 261.1 = 1.015

Therefore, the COP of the R-410a air conditioning unit is approximately 1.015.

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(a) The systematic name for the formula \(K[Pt(NH_{3})Cl_{5}]\) is potassium pentachloridoplatinum(II) ammine complex.

(b) The systematic name for the formula \([Cu(en)(NH_{3})_{2}] [Co(en)Cl_{4}]\) is diammine-ethylenediamminecopper(II)tetrachloroethylene-diamminecobaltate(II) complex.

(c) The systematic name for the formula \([Pt(en)_{2}Br_{2}](ClO_{4})_{2}\) is bis(ethylenediamine)dibromoplatinum(IV) perchlorate complex.

The temporary name given to an undiscovered or recently synthesized chemical element is called a systematic element name. This name also has a systematic symbol attached to it. Only once its synthesis has been verified does a transuranic element in chemistry earn a permanent name and symbol.

Each substance has a name. This name should ideally include information about the compound's composition as well as possible characteristics. These names are known as systematic names and are founded on a set of guidelines created by IUPAC. All compounds have systematic names, but a lot of them also have trivial or popular names.

For instance lets take, the compound \([Cu(en)(NH_{3})_{2}] [Co(en)Cl_{4}]\),

Here,

\(NH_{3}\) ,en are neutral ligand , Cl = -1

So, charge on copper =+2 and charge on Co = +2

Hence, the systematic name of the compound will be diammine-ethylenediamminecopper(II)tetrachloroethylene-diamminecobaltate(II)

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The heat capacity of the silver spoon at the given temperature difference is 817.65 J.

The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;

Q = mcΔθ

where;

Q = 50 x 0.237 x (89 - 20)

Q = 817.65 J

Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.

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