An object is thrown upward with a speed of 15 m/s on the surface of planet X where the acceleration due to gravity is 2.5 m/s2. How long does it take for the object to return to where it is thrown?

The activity of the sample after 5 hours is 2.5 * 10^9 dps or 2.5 * 10^9 Bq

The activity of a radioactive sample refers to the rate at which its nuclei decay, and it is typically measured in units of disintegrations per second (dps) or becquerels (Bq).

To determine the activity of the sample after 5 hours, we need to consider the concept of half-life. The half-life of a radioactive substance is the time it takes for half of the nuclei in a sample to decay.

Given that the half-life of the nuclei in the sample is 2.5 hours, we can calculate the number of half-lives that occur within the 5-hour period.

Number of half-lives = (Time elapsed) / (Half-life)

Number of half-lives = 5 hours / 2.5 hours = 2

This means that within the 5-hour period, two half-lives have occurred.

Since each half-life reduces the number of nuclei by half, after one half-life, the number of nuclei remaining is (1/2) * (10^10) = 5 * 10^9 nuclei.

After two half-lives, the number of nuclei remaining is (1/2) * (5 * 10^9) = 2.5 * 10^9 nuclei.

The activity of the sample is directly proportional to the number of remaining nuclei.

Therefore, After 5 hours, the sample has an activity of 2.5 * 109 dps or 2.5 * 109 Bq.

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Answer:

motion; position; reference; speed; velocity; forces; gravity; friction; direction; acceleration (in order)

Explanation:

The object will complete 4,500 revolutions in 15 seconds, assuming it rotates at a constant frequency of 300 Hz.

The frequency of rotation is given as 300 Hz, which means the object completes 300 revolutions in one second. To calculate the total number of revolutions in 15 seconds, we can multiply the frequency by the time in seconds, giving us 300 x 15 = 4,500 revolutions.

Therefore, the object will complete 4,500 revolutions in 15 seconds if it maintains a constant frequency of 300 Hz.

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The magnetic field surrounding a current-carrying wire points radially away from the wire.True or False?First give main ans in the form of 'The given statement ''write whole statememt)''is true of false because (give reason) and then  explanation in exact 110 words total

and explanation in exact 110 words total

ChatGPT

The given statement "The magnetic field surrounding a current-carrying wire points radially away from the wire" is false because the magnetic field surrounding a current-carrying wire forms concentric circles around the wire.

Explanation:

If a student used a wet metal to measure its specific heat capacity, the resulting measured value would be too high.

The specific heat capacity of a material refers to the amount of heat energy required to raise the temperature of a unit mass of the material by a certain amount. When a metal is wet, it means that it has absorbed some amount of water, which can affect the measured value of its specific heat capacity.

Water has a higher specific heat capacity compared to most metals. When the metal is wet, the presence of water on its surface can lead to an increased thermal conductivity between the metal and the surrounding environment. This increased thermal conductivity can result in faster heat transfer during the measurement process.

As a result, when heat is applied to the wet metal, the water on its surface will absorb the heat more readily, leading to an overall higher heat capacity measurement. The water will act as an additional heat sink, causing the measured value of the specific heat capacity to be higher than the actual value of the metal alone.

Therefore, if a student used a wet metal to measure its specific heat capacity, the resulting value would be too high due to the influence of the water's higher specific heat capacity and increased thermal conductivity.

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This experiment setup allows you to observe the behavior of an RC circuit when the capacitor is not charging.

The experiment setup involves setting up an RC circuit with an open switch, so the capacitor is not charging at time t.

To understand this experiment setup, let's break it down into steps:

1. Start by setting up an RC circuit. An RC circuit consists of a resistor (R) and a capacitor (C) connected in series or parallel. The resistor limits the flow of current, while the capacitor stores electrical charge.

2. In this setup, the switch is open, which means it is not closed or connected. This prevents the flow of current in the circuit.

3. Since the switch is open, the capacitor is not charging at time t. Charging a capacitor involves the flow of current through it, which is hindered by the open switch in this case.

Overall, this experiment setup allows you to observe the behavior of an RC circuit when the capacitor is not charging. By examining the circuit's response in this state, you can gain insights into the characteristics of capacitors and their interaction with resistors in the circuit.

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Answer:

Yes

Explanation:

Your solution is correct

Answer:

I think yeah, you did

Answer:

B

Explanation:

This is because we don't no how much force we need to make the speed of a bike

Answer:

180 [J].

Explanation:

1) the required work [W] can be calculated as difference of the energy: W=E₂-E₁, where E₁=mgh₁ - the energy before lifting, E₂=mgh₂ - the energy after lifting;

2) W=mgh₂-mgh₁, where m - mass; g=10 [N/kg], h - height;

3) then the required work [W]:

W=mg*(h₂-h₁)=30*6=180 [J].

Answer:

the final velocity of the skater after throwing the snowball is 3.17 m/s.

Explanation:

Given;

mass of the ice skater, m₁ = 72 kg

initial velocity of the ice skater, u₁ = 3.1 m/s

mass of the snowball, m₂ = 0.21 kg

initial speed of the snowball, u₂ = 28.0 m/s

Let the final velocity of the skater after throwing the snowball = v

Apply the principle of conservation of linear momentum to determine v;

m₁u₁ + m₂u₂ = v(m₁ + m₂)

72 x 3.1   +  0.21 x 28  = v(72 + 0.21)

229.08 = v(72.21)

v = 229.08 / 72.21

v = 3.17 m/s

Therefore, the final velocity of the skater after throwing the snowball is 3.17 m/s.

Answer:

m = 1,975 m / kg , b = 38.05 m

Explanation:

In this experiment, the elongation is plotted against the applied mass

getting a straight line

            y = m x + b

where b would be the initial length of spring let's calculate the slope for which we use two well separated points

           m = (56.3 -48.4) / (8 - 4)

           m = 1,975 m / kg

the equation remains

         y = 1,975 x + b

for x = 2 kg y = 42.0 m

we substitute in the equation

           42 = 1,975 2 + b

           b = 42 - 3.95

           b = 38.05 m

With a temperature change of 31°C, the mercury column's height changes by 0.0106 cm.

As the temperature rises, the mercury will expand in the capillary tube, increasing its volume. V = VT = (1.8*10-4 (oC)-1)(0.100 cm3)(20 oC) = 3.6*10-4 cm3 = 0.36 mm3, or the formula V = VT.

\(A1 * h1 = A2 * h2\)

\(A1 = πr1^2 = π(0.005 cm/2)^2 = 7.85 × 10^-5 cm^2\)

The cross-sectional area of the bulb is:

\(A2 = πr2^2 = π(0.31 cm/2)^2 = 0.0755 cm^2\)

\(ΔV = V0 * β * ΔT\)

\(V0 = A1 * h1\)

\(h2 = (A1/A2) * h1 + (ΔV/A2)\)

\(h2 = (7.85 × 10^-5 cm^2)/(0.0755 cm^2) * h1 + (0.000182 (°C)^-1 * 31°C *\) 7.85 × \(10^-5 cm^2)/(0.0755 cm^2)\)

\(h2 = 0.0106 h1 + 0.00000122 cm\)

\(Δh = h2 - h1 = 0.0106 h1 + 0.00000122 cm - h1 = 0.0106 cm\)

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All things we touch are made of matter

particles are small compund that make up matter

the particle theory states that small particels are moving constantly

they move faster based on which state of matter they are in

Explanation:

All things we touch are made of matter

particles are small compund that make up matter

the particle theory states that small particels are moving constantly

they move faster based on which state of matter they are in

Answer: the answer given below

(a) Explanation: The impulse on an object is given by the change in momentum of the object. Before the collision, the bullet has momentum p1 = mv0 and the brick has momentum p2 = 0, since it is stationary. After the collision, the combined bullet-brick system has momentum p3.

Conservation of momentum requires that the total momentum before the collision is equal to the total momentum after the collision:

p1 + p2 = p3

mv0 + 0 = (m + M)V

where V is the velocity of the combined bullet-brick system after the collision. Solving for V, we get:

V = (mv0) / (m + M)

The impulse on the bullet during the collision is equal to the change in momentum of the bullet:

J_bullet = p3 - p1 = (m + M)V - mv0

Substituting the expression for V we found earlier:

J_bullet = (m + M)(mv0) / (m + M) - mv0 = 0

Therefore, the impulse on the bullet is zero during the collision.

On the other hand, the impulse on the brick during the collision is:

J_brick = p3 - p2 = (m + M)V - 0 = (m + M)(mv0) / (m + M) = mv0

Therefore, the magnitude of the impulse acting on the brick is equal to the initial momentum of the bullet, mv0, and it is in the same direction as the initial velocity of the bullet.

In summary, during the collision of the bullet and the brick, the impulse acting on the bullet is zero, while the impulse acting on the brick is mv0 in the direction of the initial velocity of the bullet.

(b) We can use the principle of conservation of momentum to solve for the velocity of the brick-bullet combination just after the collision. The total momentum of the system (bullet, brick, and Earth) is conserved before and after the collision. Initially, only the bullet has momentum, which is given by p1 = m*v0, and the momentum of the brick and Earth is zero. After the collision, the bullet becomes embedded in the brick, and the combined system of the brick-bullet has momentum p2. Since the momentum of the Earth is negligible compared to that of the bullet and brick, we can treat the system as closed and apply conservation of momentum:

p1 = p2

m*v0 = (M + m)*v

where v is the velocity of the combined system just after the collision.

Solving for v, we get:

v = (m*v0) / (M + m)

Therefore, the magnitude of the velocity of the brick-bullet combination just after the collision is:

|v| = |(m*v0) / (M + m)|

The direction of the velocity is upward, as the system swings up after the collision due to the conservation of momentum.

(c) The initial kinetic energy of the system is the kinetic energy of the bullet just before the collision, which is given by:

KE1 = (1/2)mv0^2

The final kinetic energy of the system is the kinetic energy of the combined brick-bullet system just after the collision, which is given by:

KE2 = (1/2)*(M + m)*v^2

Substituting the expression we found for v:

KE2 = (1/2)(M + m)[(mv0) / (M + m)]^2

KE2 = (1/2)(m*v0^2) / (1 + M/m)

The ratio of the final kinetic energy to the initial kinetic energy is:

KE2 / KE1 = [(1/2)(mv0^2) / (1 + M/m)] / [(1/2)mv0^2]

KE2 / KE1 = 1 / (1 + M/m)

Therefore, the ratio of the final kinetic energy of the brick-bullet combination immediately after the collision to the initial kinetic energy of the brick-bullet combination is:

KE2 / KE1 = 1 / (1 + M/m)

(d)To determine the maximum vertical position reached by the brick-bullet combination, we can use conservation of energy, assuming there is no energy loss due to friction or other dissipative forces. At the maximum height, the kinetic energy of the system is zero, and all the initial kinetic energy has been converted to potential energy due to the height above the initial position.

The initial total energy of the system is the sum of the initial kinetic energy of the bullet and the gravitational potential energy of the brick:

E1 = (1/2)mv0^2 + Mgh1

where h1 is the initial height of the brick above the ground, and g is the acceleration due to gravity.

At the maximum height, the final total energy of the system is the potential energy due to the height above the ground:

E2 = (M + m)gh2

where h2 is the maximum height reached by the brick-bullet combination above the initial position.

Since there is no energy loss, we can set the initial energy equal to the final energy:

E1 = E2

Substituting the expressions for E1 and E2 and solving for h2, we get:

(M + m)gh2 = (1/2)mv0^2 + Mgh1

h2 = [(1/2)mv0^2 + Mgh1] / [(M + m)*g]

Simplifying, we get:

h2 = (1/2)v0^2 / g + h1(M/m) / (1 + M/m)

Therefore, the maximum vertical position above the initial position reached by the brick-bullet combination is:

h2 = (1/2)v0^2 / g + h1(M/m) / (1 + M/m)

Hope this helps :)

Answer:

FN=-Fg -> Fg=mg -> Fg = 238 kg*9.8 m/s^2 ->

Fg = -2432.4 so FN = 2432.4 -> FF = μs*FN ->

FF = 0.22*2332.4 N -> FF = 513.128 ->

Fapplied > 513.128 N

Explanation:

...

Answer:

True

Explanation:

Hope it help

Mark me as brainliest

Answer:

True

Explanation:

!mark me as brainliest

Explanation:

Osmosis is the movement of solvent particles across a semipermeable membrane from a dilute solution into a concentrated solution.

Diffusion is the movement of particles from an area of higher concentration to lower concentration.

Answer:

Explanation:

your answer is c bro but if not then it's b

because you just choose c or b either one should work if you right it down right

The capacitance of a parallel plate capacitor is 4.8 μF when charged with a potential difference of 1.25 V and a charge of 6.0 μC. In this calculation, the units are consistent.

The capacitance of a parallel plate capacitor can be calculated using the formula C = Q/V, where C is the capacitance, Q is the charge, and V is the potential difference. In this case, the charge is given as 6.0 μC and the potential difference is 1.25 V.

Substituting the given values into the formula, we have C = (6.0 μC) / (1.25 V). To simplify the units, we convert microcoulombs to coulombs by dividing by 10⁶, which gives C = (6.0 × 10⁻⁶ C) / (1.25 V).

Evaluating the expression, we find C = 4.8 × 10⁻⁶ F. Therefore, the capacitance of the parallel plate capacitor is 4.8 microfarads.

It is important to note that in this calculation, the units are consistent. The charge is in coulombs, the potential difference is in volts, and the capacitance is in farads.

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Answer:

I don't rlly know anyone in harry Potter so I simp for........MYSELF :)

Answer:

Either Draco Malfoy or Harry Potter

Explanation:

UvU

Answer:

D. Interference patterns of electrons

Explanation:

The magnitude of this vector is 9.43 and the direction angle of the vector is 58°.

The initial point and the terminal point of the vectors are (3 - 5) and (-2, 3) respectively.

The characteristics of the vector mainly includes the magnitude and the direction of the angle of the vector.

The magnitude of this vector will be given by,

M = √((-2-3)²+(3+5)²)

M = √(25+64)

M = √89

M = 9.43

The direction angle of this vector with the x-axis will be given by,

Tan A = (8/-5)

Tan A = -1.6

A = 58°.

The direction angle of this vector is 58 degree.

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Answer: D. The magnitude is StartRoot 89 EndRoot, and the direction angle is about 122°.

Explanation:

Answer:

1) Time period

2) amplitude

3) Hertz or hz

4) Noise

5) frequency

6) infrasonic and ultrasonic

7) solid liquid and gas

8) A man

9) energy

10)1 vibration per minute

Answer: Time taken by an object to complete one oscillation is called time PERIOD.

Explanation:Hope this helps!! Brainlist?plz I need it

When the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

CO2 → CO + O

This is the basic reaction expected to happen by carbon dioxide molecules are heated. However it may also disintegrate into C2, O2, C, etc.

Since heat is absorbed in this reaction, it is an example of endothermic reaction. In an exothermic reaction heat is released. These are the basic two types of chemical reactions on basis of heat.

Therefore, when the molecules of carbon dioxide is heated, it is disintegrated into molecules of carbon monoxide and oxygen atoms.

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Answer: 20 minutes

Explanation:

Given the following :

Average speed of train = 120km/hr

Distance = 40km.

The time take by the train moving at an average speed of 120km/hr to cover a distance of 40km due is ;

Recall:

Speed = distance / time

Therefore,

Time taken = distance covered / speed

Time taken = 40km / 120km/hr

Time taken = 1/ 3 hr

Therefore, 1/3 rd of an hour equals

1/3 × 60 = 20 minutes.

Time taken) 20 minutes

Time taken by tain to cover distance is 20 minutes as:

Distance= 40 km

Speed= 120 km/h

Time= distance/speed

= 40/120

= 1/3 hour

= 20 min

or  =0.33 hrs

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Answer:

(a) The wavelength of the x-ray used to observe the first-order diffraction maximum is approximately 0.413 nm.

(b) The maximum number of orders that can be observed for this crystal at this wavelength is 1.

Explanation:

(a) To determine the wavelength of the x-ray used to observe the first-order diffraction maximum, we can use the Bragg's law, which relates the wavelength of the incident x-ray, the spacing between planes of atoms, and the angle of diffraction.

Bragg's law is given by:

nλ = 2d sinθ

Where:

n is the order of diffraction (in this case, n = 1 for the first-order diffraction)

λ is the wavelength of the x-ray

d is the spacing between planes of atoms

θ is the angle of diffraction (given as 12.6°)

Rearranging the equation to solve for λ, we have:

λ = (2d sinθ) / n

Substituting the given values:

d = 0.250 nm = 0.250 × 10^(-9) m

θ = 12.6° = 12.6 × π / 180 radians

n = 1

λ = (2 * 0.250 × 10^(-9) m * sin(12.6 × π / 180)) / 1

λ ≈ 0.413 × 10^(-9) m

(b) To determine the number of diffraction orders that can be observed, we need to consider the condition for constructive interference. For a given crystal, the number of orders that can be observed depends on the maximum value of n, which is determined by the crystal's characteristics and the wavelength of the incident x-ray.

In general, the number of orders that can be observed is given by:

n_max = 2d / λ

λ = 2 * 0.250 × 10^(-9) m * sin(12.6°)

λ ≈ 0.087 × 10^(-9) m

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Answer:

10.71 mL

Explanation:

We know,

=> density= mass/volume

=> 1.4 = 15 / Volume

=> volume= 15/1.4 mL

=> volume= 10.71 mL

Answer:

4 J

Explanation:

From the image attached, we can see 2 horizontal forces acting on the box albeit in opposite directions.

Now, the net force will be;

F_net = 3 - 1

F_net = 2 N

To move a distance of 2 metres, kinetic energy is;

K.E = Force × Distance = 2 × 2 = 4 J