The speed of the object after the interaction is approximately 2.24 m/s.
The total mechanical energy is conserved when no external forces, like friction or air resistance, act on a system. If energy is conserved, it means that the system's initial energy is equal to its final energy. The mechanical energy of a system is the sum of its kinetic energy and potential energy, which is written as follows:mechanical energy = kinetic energy + potential energy.
The mechanical energy of the system before interaction is the initial kinetic energy, which is expressed as follows:
\(KE_i = 0.5mv^2KE_i = 0.5(0.5 kg)(5 m/s)^2KE_i = 6.25 J\).
The mechanical energy of the system after the interaction is the final kinetic energy, which can be found by subtracting the work released from the initial kinetic energy:
\(KE_f = KE_i - WKE_f = 6.25 J - 5 JKE_f = 1.25 J\).
The final kinetic energy can now be used to find the final velocity of the object as follows:
\(KE_f = 0.5mv^2v^2\)
\(= (2KE_f) / mv^2\)
\(= (2 * 1.25 J) / 0.5 kgv^2\)
\(= 5 JV_f\)
\(= \sqrt{v^2V_f}\)
\(= \sqrt{5 JV_f}\)
\(= 2.24 m/s\)
Therefore, the speed of the object after the interaction is approximately 2.24 m/s.
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. A car accelerates uniformly from 0 to 72 km/h in 11.5 seconds.
a) What is the acceleration of the car in m/s2? b) What is the position of the car by the time it reaches the velocity of 72 km/h?
Answer:
Explanation:
First job is to convert 72 km/hr to m/s:
\(72\frac{km}{hr}\) × \(\frac{1000m}{1km}\) × \(\frac{1hr}{3600s}\) = 2.0 × 10¹ m/s
Now to find the acceleration which is
\(a=\frac{v_f-v_0}{t}\) and filling in:
\(a=\frac{2.0*10^1-0}{11.5}=1.7\frac{m}{s^2}\) That's part a. Part b want to know how far the car can get in 11.5 seconds (because that's the time it takes for the car to get to 72 km/hr). Since we know that the car can get 2.0 × 10¹ meters in 1 second, that means that in 11.5 seconds, the car can get 11.5(2.0 × 10¹) which is 230 meters.
PLEASE HELP 25 POINTS !!!!!!!!!!!!!!!! Add the following numbers and round your answer to the correct number of significant figures:
90.0 + 80 =
Show both the unrounded and rounded answer.
Answer:
90.0 + 80 = 170
2 signifigant figures
1.70 x 10^2
what is one physical force that can change an object from one phase to the next
One physical force that can change an object from one phase to the next is temperature. The phase of matter is determined by the arrangement and movement of its particles. As temperature changes, the average kinetic energy of the particles also changes, causing them to move faster or slower.
This change in movement can lead to a change in the arrangement of particles, which ultimately changes the phase of the matter.
For example, if a solid is heated, the particles gain energy and vibrate faster, causing the bonds between particles to weaken. Eventually, the bonds break, and the particles are able to move freely, resulting in a liquid phase. Similarly, if a liquid is cooled, the particles lose energy and move slower, causing the bonds between particles to strengthen. Eventually, the particles will become fixed in a rigid pattern, resulting in a solid phase.
Therefore, temperature can act as a physical force to change the phase of matter, and it is a fundamental concept in the study of thermodynamics and phase transitions.
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a student with a near-point distance of 44 cm uses a microscope having an eyepiece with a focal length of 3 cm. what is the magnification of the eyepiece?
The use of microscope, pick up a prepared slide by its edges and place it on the microscope's stage. Once the slide is in position, clip it into place.
What is the focal length of the objective of the microscope?A microscope has a 1 cm focal length objective and a 6 cm focal length eyepiece. If the tube length is 30 cm and the image is formed at the shortest distance of discernible vision.
The focal lengths of the objective and eye lens in a compound microscope are 2.5 cm and 5 cm, respectively. When an object is placed 3.75 cm in front of the objective and an image is formed at the shortest distance of distinct vision, the distance between the two lenses is equal to the length of the microscopic tube. B. 13.00 cmA. 12.67 cm D. 11.67 cm C. 12.00 cm.
The objective eyepieces of an astronomical telescope have focal lengths of 40 cm and 4 cm, respectively. To observe an object 200 cm from the objective lens.
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if the rotational inertia of a disk is 30 kg m2, its radius r is 7.1 m, and its angular velocity omega is 9.2 rad/s, determine the linear velocity v of a point on the edge of the disk.
The formula for the linear velocity v of a point on the edge of a disk is v = r x omega, where r is the radius of the disk and omega is the angular velocity. Therefore, the linear velocity of a point on the edge of the disk is 65.32 m/s.
Substituting the given values, we have:
v = 7.1 m x 9.2 rad/s
v = 65.32 m/s
To determine the linear velocity v of a point on the edge of the disk with a rotational inertia of 30 kg m², radius of 7.1 m, and an angular velocity of 9.2 rad/s, you can use the formula:
v = r * ω
where v is the linear velocity, r is the radius, and ω is the angular velocity.
Step 1: Plug in the given values:
v = 7.1 m * 9.2 rad/s
Step 2: Multiply the values:
v ≈ 65.32 m/s
So, the linear velocity of a point on the edge of the disk is approximately 65.32 m/s.
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DATE
CLASS
14. The Space Shuttle must achieve a velocity of 7,800 m/s in order to orbit the
Earth If the average acceleration of the Space Shuttle is 15.3 m/s², how long will
It take for the shuttle to reach orbital velocity? Convert your answer from seconds
to minutes. Show all your work for this calculation.
Answer:
8.49673 minutes ≈ 8.5 minutes
Explanation:
Acceleration, a is defined as the rate of change in velocity divided by the change in time to attain that velocity
\(\mathsf a = \dfrac{\Delta v}{\Delta t} \\\\\textsf {where } \mathsf {\Delta v = v-v_0} \textsf{ v being final velocity and v_0 initial velocity}\), v = final velocity and v₀ the initial velocity
and Δt is the time required to attain final velocity
Δt = number of seconds since launch = t since t₀ = 0
Therefore,
\(a = \dfrac{v-v_0}{t}\)
The space shuttle's initial velocity is 0 m/s and its final velocity must be 7800 m/s to escape earth's gravity
So v - v₀ = 7800 - 0 = 7800 m/s, t - t₀ = t = 0 = t seconds
a = 15.3 m/s²
We have the equation
a = 7800/t
a is given as 15.3 m/s² so
15.3 = 7800/t
t = 7800/15.3 = 509.80392 seconds
To convert to minutes, divide by 60
509.80392/60 = 8.49673 minutes ≈ 8.5 minutes
A student is pulling on an object that has a mass of 25 kg across the floor. Assuming gravity to be 10 m/s2, what is the weight of the object?
25 Kg
250 Kg
250 N
25 N
Answer:
250N
Explanation:
w = mg
m=25
g = 10
w=25x10
w=250
If a student is pulling on an object that has a mass of 25 kg across the floor. Assuming gravity to be 10 m/s², then the weight of the object would be 250 N , therefore the correct answer is option C.
What is gravity?It can be defined as the force by which a body attracts another body toward its center as the result of the gravitational pull of one body and another.
As given in the problem, a student is pulling on an object that has a mass of 25 kg across the floor. Assuming gravity to be 10 m/s2,
The weight of the object = 25 × 10
= 250 N
Thus, the weight of the object would be 250 N , therefore the correct answer is option C.
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hlo anyone help
a stone is thrown upward with the kinetic energy of 10 joule if it goes up to a maximum height of 5 M find the initial velocity and mass of the stone??
Ty no spam plz help rn
Explanation:
Here, kinetic energy of the body, K.E=10 J
Height attained by the body, h=5 m
h=5m
When the body attains maximum height, its kinetic energy is converted into potential energy.
P.E=K.E
⟹mgh=10
⟹m= 10/gh
= m = 10/(10×5) =0.2 kg (taking the value g as 10m/s²)
Now, ½mv²=10
0.2×v²=20
v²=20/0.2
v²=100
v=√100
v=10m/s.
hope this helps you.
\(\huge \bf༆ Answer ༄\)
Let's solve ~
As we know the total energy [P.E + K.E = C] of the system remains constant throughout the motion,
So, When a stone was thrown initially it didn't had any potential energy (P.E = 0) but had kinetic Energy of 10 joules.
So, total energy = P.E + K.E = 0 + 10 = 10 joules
As per the given information, equate it with the formula.
\( \sf \dfrac{1}{2}m {v}^{2} = 10\)\( \sf m {v}^{2} = 20\)Now, As it approaches 5m height it comes to rest, Therefore velocity = 0. And since velocity = 0 then Kinetic Energy = 0
Now, let's find the Potential Energy at that point ~
\( \sf mgh\)\( \sf m \times 10 \times 5\)\( \sf50m\)And here, the Total energy = P.E + K.E = 10 Joules
So,
\( \sf50m + 0 = 10 \)\( \sf50m = 10\)\( \sf m = 10 \div 50\)\( \sf m = 0.2\)Therefore, mass of the object is 0.2 kg = 200 grams
Now, plug the value of mass (m) in the equation of kinetic Energy to find the initial velocity of the stone ~
\( \sf m {v}^{2} = 20\)\( \sf0.2 \times {v}^{2} = 20\)\( \sf {v}^{2} = 20 \div 0.2\)\( \sf v = \sqrt{100} \)\( \sf v = 10 \: \: ms {}^{ - 1} \)Hence, velocity of the particle at the beginning was 10 m/s
In a hydroelectric power station, how much potential energy is lost by 100tonnes of water flowing down through the pipes, falling a vertical distance of 200metres? [1tonne=1000kg.]
Answer:
196000000 J
Explanation:
Potential Energy: This can be defined as the energy of a body due to its position in the gravitational field.
From the question,
P.E = mgh.................. Equation 1
Where P.E = potential Energy, m = mass of the water, h = height, g = acceleration due to gravity.
Given: m = 100 tonnes = (100×1000) = 100000 kg, h = 200 m
Constant: g = 9.8 m/s²
Substitute into equation 1
P.E = 100000(200)(9.8)
P.E = 196000000 J.
Note: When a object falls through a height he losses its potential energy.
Hence the potential energy lost = 196000000 J = 196 MJ.
Measurements of one Paramecium cell performing the barium dance show that it is moving to the left at 100 μm/s before adding barium; five seconds after adding the barium, it is moving to the right at 200 μm/s. The average acceleration of the cell is:
Measurements of one Paramecium cell performing the barium dance show that it is moving to the left at 100 μm/s before adding barium, the average acceleration of the cell is 20 μm/s².
The formula for average acceleration can be used to get the cell's average acceleration:
\(\[ \text{Average Acceleration} = \dfrac{\text{Change in Velocity}}{\text{Time Interval}} \]\)
Given values:
Initial velocity (\(\(v_i\)\)) = 100 μm/s (to the left)
Final velocity (\(\(v_f\)\)) = 200 μm/s (to the right)
Time interval (t) = 5 seconds
The change in velocity is the difference between the final velocity and the initial velocity:
\(\[ \text{Change in Velocity} = v_f - v_i \]\)
Substitute the values:
\(\[ \text{Change in Velocity} = 200 - 100 \\\\= 100\)
Now, plug this into the formula for average acceleration:
\(\[ \text{Average Acceleration} = \dfrac{\text{Change in Velocity}}{\text{Time Interval}}\\\\ = \dfrac{100 }{5 }\)
= 20 μm/s².
Therefore, the average acceleration of the cell is 20 μm/s².
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Question 1
A STUDENT TIES A STRING AROUND A WEIGHT AND SWINGS THE WEIGHT IN A CIRCLE AROUND HER BODY. IF
THE STUDENT REPRESENTS THE SUN AND THE WEIGHT REPRESENTS EARTH, WHAT DOES THE STRING
REPRESENT?
A. GRAVITY
B. RADIATION
C. ELECTRICITY
D. MAGNETISM
Answer:
A) Gravity.
Explanation:
Earth is stuck in orbit around the sun, because of the Sun's gravitational pull. In this scenario, the string represents gravity, keeping the Earth attracted towards the sun.
Hope this helps! Feel free to give me Brainliest if you feel this helped. Have a good day and good luck with your assignment :)
The student ties a string around a weight and swings the weight in a circle around her body. If the student represents the sun and the weight represents earth, the string will represent GRAVITY then.
What is gravity?In mechanics, gravity—also known as gravitation—is the constant force of attraction that pulls all things together. It has little impact on determining the intrinsic characteristics of common stuff because it is by far the weakest known force in nature.
In contrast, it governs the formations and evolution of stars, galaxies, and the entire cosmos by its extensive and ubiquitous action, which affects the trajectories of objects in the solar system and beyond the universe. All objects on Earth experience weight, or a gravitational pull that is proportionate to their mass and is imposed by the planet's mass.
As the student represents the sun and the weight represents earth, the string will represent GRAVITY then. Hence, option (A) is correct.
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A proton and an electron are placed in an electric field. Which undergoes the lesser acceleration?.
An Electron will undergoes the lesser acceleration
What is Proton and Electron ?An electron is a negatively charged particle of equivalent magnitude to a proton, which is positively charged. Therefore, they will feel the same amount of electric force when exposed to an electric field. As a result, the relationship between acceleration and mass will be inverse. An electron will accelerate more quickly than a proton because an electron has a lower mass.
Due to their opposite polarity, an electron and a proton are attracted to one another by an electrical force of equal strength when they are placed in an electric field. However, because of their opposing charges, the force will act in the opposite direction.
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. A boy wishes to make a catapult out of a rubber band of width 9mm and thickness 1.55mm. Determine the length of the band that he must use so that when he stretches it by 0.25 of its natural length and releases it the velocity of pebble of mass 0.006kg will be 30m/s. Take young modulus of the rubber to be 4×10^7 N/m^2
The length of the rubber band that the boy must use is 0.024 m or 24 mm.
What will be the length of the rubber required?To determine the length of the rubber band, we can use the formula for the potential energy stored in a stretched spring, which is also applicable to a stretched rubber band:
U = 1/2 kx²where U is the potential energy stored in the rubber band, k is the spring constant (or in this case, the rubber band constant), and x is the displacement of the rubber band from its natural length.
Since the rubber band is stretched by 0.25 of its natural length, the displacement x is 0.25 times the natural length of the rubber band.
We can solve for the rubber band constant k by using the formula for the velocity of a projectile launched by a spring (or in this case, a rubber band):
v = √(2mk/M)where v is the velocity of the projectile, m is the mass of the rubber band, M is the mass of the projectile, and k is the spring constant. We can rearrange this equation to solve for k:
k = (v² M) / (2 m)
We can now combine the two equations to solve for the length of the rubber band, L:
U = 1/2 k x²
U = 1/2 ((v² M) / (2 m)) (0.25 L)²
U = (v² M L²) / (32 m)
The potential energy stored in the rubber band must be equal to the kinetic energy of the projectile when it is launched:
U = 1/2 M v²
(v² M L²) / (32 m) = 1/2 M v²
L = ((16 m v²) / (k M))
L = ((16 m v²) / ((v² M) / (2 m) M))
L = √(32 m^2 / M)
L = (0.032 M)
Substituting the given values, we get:
L = √(0.032 * 0.006)
L = 0.024 m
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Hi, I'm trying to figure out #17 but I am having trouble on how to solve it. Any help would be greatly appreciated! Thank you.
Answer:
The mechanical advantage of the wheelbarrow is the product of the mechanical advantage of the lever, and the mechanical advantage of the wheel and axle. Therefore, the wheelbarrow has a mechanical advantage of 4.
hope this helps :D
which of the filling is a result of the transfer of energy?
answer: sound
why is it sound???
Explanation:
the speed of sound depends on the particles of the medium of the sound wave is moving through because the particles in the solid and tightly packed together South Wales weekly transfers energy from particle to particle in a solid
a hot-air balloon can lift a weight of 6453 n (counting the balloon itself). the density of the air outside the balloon is 1.205 kg/m3. the density of the hot air inside the balloon is 0.9671 kg/m3. what is the volume of the balloon? (in m^3)
To solve this problem, we need to use the fact that the weight lifted by the hot-air balloon is equal to the weight of the air displaced by the balloon. We can use the following formula to find the volume of the balloon:
Volume of balloon = Weight lifted / Density difference between hot air and outside air * gravitational acceleration
We are given the weight lifted by the balloon, which is 6453 N. The density of the outside air is 1.205 kg/m^3, and the density of the hot air inside the balloon is 0.9671 kg/m^3. The gravitational acceleration is 9.81 m/s^2.
Substituting these values into the formula, we get:
Volume of balloon = 6453 N / (1.205 kg/m^3 - 0.9671 kg/m^3) * 9.81 m/s^2
Volume of balloon = 6453 N / 0.238 kg/m^3 * 9.81 m/s^2
Volume of balloon = 22131.633 m^3
Therefore, the volume of the balloon is 22131.633 m^3.
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relative to sphere at the speed of sphere Z is _ m/s
We are given that a sphere Z moves with a relative speed of 1 m/s with respect to sphere X which moves at 5 m/s. Let's draw the velocity vectors of the spheres:
Where:
\(\begin{gathered} v_x=\text{ velocity of sphere x} \\ v_z=\text{ velocity of sphere z} \end{gathered}\)From the relative velocity equation we have:
\(v_z=v_r+v_x\)Where:
\(v_r=\text{ velocity of z relative to x}\)Since we are given the relative velocity we can plug in the values to get the velocity of "z":
\(\begin{gathered} v_z=1\frac{m}{s}+5\frac{m}{s} \\ \\ v_z=6\frac{m}{s}_{} \end{gathered}\)Now, we do the same but now using the sphere Y:
Now, we use the relative velocity equation for these velocities:
\(v_z=v_r+v_y\)In this case, we have that:
\(v_r=\text{ velocity of z with respect to y}\)Now, we subtract the velocity of "y" from both sides:
\(v_z-v_y=v_r\)Substituting the values:
\(6\frac{m}{s}-2\frac{m}{s}=v_r\)Solving the operations:
\(4\frac{m}{s}=v_r\)Therefore, the velocity of "Z" relative to "Y" is 4 m/s.
a long, thin solenoid has 800 turns per meter and radius 2.50 cm. the current in the solenoid is increasing at a uniform rate of 48.0 a/s.
The magnitude of the induced emf near the center of the solenoid is 0 V/m.
The given parameters;
number of turns of the solenoid, N = 700 turns/m
the solenoid's current, I = 48 A/s,
the wire's radius, r = 2.5 cm
The size of the induced emf near to the solenoid's center is calculated using the formula below:
B = µnI
dB/dt = µn*dI/dt
dB/dt = 0.032 T/s
Because of changes in the magnetic flux passing through a coil, a potential difference is created in the coil. To put it another way, it is claimed that electromotive force, or EMF, is created when the flux connecting with a conductor or coil changes.
\(E =\frac{r}{2} \frac{dB}{dr} \\\\E = \frac{0}{2} * (0.032) =0\)
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The magnetic field vector is tilted towards the +x direction (but its magnitude remains the same). a. Induced current is clockwise b. Induced current is counterclockwise c. There is no induced current 2
The information provided states that the magnetic field vector is tilted towards the +x direction, but its magnitude remains the same.
Based on this information, we can determine the direction of any induced current using Faraday's law of electromagnetic induction.
According to Faraday's law, when there is a change in magnetic flux through a loop of wire, an induced current is generated in the wire. The direction of the induced current is such that it opposes the change in magnetic flux.
In this case, since the magnetic field vector is tilted towards the +x direction, the change in magnetic flux through the loop would be a decrease. To oppose this decrease in magnetic flux, the induced current would generate its own magnetic field that tries to maintain the original magnetic field.
Using the right-hand rule, if we place our right hand with the thumb pointing in the direction of the original magnetic field (which is now tilted towards the +x direction), the induced current would circulate in the counterclockwise direction around the loop.
Therefore, the correct answer is:
b. The induced current is counterclockwise.
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Which of the following defines a wavelength
Group of answer choices
A. length of time the wave has been in motion
B. distance between trough and trough
C. distance between quiet water level and crest
D. distance between trough and crest
The answer is D. distance between trough and crest. Wavelength is the distance between two consecutive points of the same phase on a wave, such as two adjacent crests, troughs, or zero crossings.
Wavelength is the distance between two consecutive points of the same phase on a wave, such as two adjacent crests, troughs, or zero crossings. So the answer is the distance between the trough and crest.
The other options are incorrect. Option A is the length of time the wave has been in motion, which is not the same as wavelength. Option B is the distance between the trough and the trough, which is half of the wavelength. Option C is the distance between the quiet water level and the crest, which is not a physical measurement of the wave.
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Hello,
Please can I have some help with these questions? Many thanks!
You have already plotted the graph.
Solving unsolved one
#d
One result is anamolous
That's
(50,32)This is because
until 50 it's increasing 6 per step But at 50 it increased +7 i.e from 25 to 32As it broke the sequence hence this is anamolous1. Suppose a 10 N force is applied to the side of a 4.0 kg block that is sitting on a table what would be the minimum value of the coefficient of static friction in order for the block to remain motionless?
Answer:
\(\mu= 0.25\)
Explanation:
Given data
Force= 10N
mass= 4kg
r= 4*9.81
r= 39.24N
The expression for the force acting is expressed as
\(F=\mu*r\)
substitute
\(\mu=F/r\)
\(\mu= 10/39.24\)
\(\mu= 0.25\)
The minimum value of the coefficient of static friction in order for the block to remain motionless is 0.26.
Given the following data:
Force = 10 NewtonMass of block = 4.0 kgScientific data:
Acceleration due to gravity = 9.8 \(m/s^2\)To determine the minimum value of the coefficient of static friction in order for the block to remain motionless:
Note: The force that is required to make the block motionless must be lesser than or equal to the force of static friction.
Mathematically, the force of static friction is given by the formula;
\(Fs = uFn = umg\)
Where;
Fs represents the force of static friction.μ represents the coefficient of friction.\(F_n\) represents the normal force.g is the acceleration due to gravity.m is the mass of an object.Making u the subject of formula, we have:
\(u=\frac{F_s}{mg}\)
Substituting the given parameters into the formula, we have;
\(u=\frac{10}{4.0 \times 9.8} \\\\u=\frac{10}{39.2}\)
u = 0.26
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Inquiry Skill
A student constructs a model of a natural resource using a can with a small hole
in the bottom. With the hole plugged, the can is filled with sand. When the plug is
removed, the sand drains out. What kind of resource does this model illustrate?
you walk at a speed of 1.5 m/s and it takes you 1800 seconds to get to your friends house. if you follow the same route, how fast would you need to travel to get there un 600 seconds
Answer:
4 miles per hour
Explanation:
Your welcome
What metaphor (object) shows how Aristotle's Three Artistic Proofs hold up one's argument?
1. wagon
2. stool
3. hammock
4. easel
The metaphor (object) that shows how Aristotle's Three Artistic Proofs hold up one's argument is a stool. The correct option is 1.
The Three Artistic Proofs are Aristotle's fundamental concepts of argument that build a convincing case when utilized together:
Ethos: It is the ethical appeal; it establishes credibility with an audience.
Pathos: This refers to the emotional appeal; it appeals to the audience's emotions and sentiments.
Logos: It is the logical appeal; it uses reasoning and logical argument to persuade and convince the audience.
The metaphor (object) that shows how Aristotle's Three Artistic Proofs hold up one's argument is a stool. A stool is a three-legged object that can stand on its own with each leg equally supporting the weight. It is like the three artistic proofs, which are required in a good argument to hold it up. Without one of the three legs, the stool would be unstable and would fall apart. This metaphor is commonly used to explain how the three artistic proofs work together to build a convincing case. Option 1.
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Microbial food infections are usually not seen until ______ after eating contaminated food.
Answer:
2 to 4 hours
Explanation:
Given that,
Microbial food infections
We know that,
Food infection :
When we eat old food, uncooked, fermented food, more junk food and contaminated food then 2 to 4 hours after eating we started vomiting, headache then we affected by food infections.
So, we can say that microbial food infections are usually not seen until 2 to 4 hours after eating contaminated food.
which of the following characteristics of planets decreases as their distance from the Sun increases?
Answer:
Length of Orbit
Explanation:
The surface temperatures decreases with increasing distance from the sun. Venus is an exception because its dense atmosphere acts as a greenhouse and heats the surface to above the melting point of lead, about 880 degrees Fahrenheit (471 degrees Celsius).
Hopefully this helps!
What is the kinetic energy of a ball of mass 1.4 kg moving at a speed of 15 m/s?
Answer:
Explanation:
The energy possessed by a moving object is called kinetic energy.M=1kgV=2m/sKe= 1/2MV^2Ke=1/2×1×(2)^2Ke =2 joules
heyy! i’ll give brainliest please help
The 200-mm test tube also contained some water (besides the metal) that was subsequently added to the calorimeter (in Part A.4.). Considering a higher specific heat for water, will the temperature change in the calorimeter be higher, lower, or unaffected by this technique error?
Answer:
The temperature change in the calorimeter will be lower
Explanation:
Water is an example of a molecular substance. They have relatively low melting points and boiling points usually below 300° C . Water reacts with metals to a degree varying with their position in the electrochemical series.
The specific heat of water is 4179.6 Joules which is relatively high . This typically implies that water absorbs a larger amount of heat but the increase in temperature of its boiling points is relatively low. Thus; in the 200-mm test tube that contains water and was subsequently added to the calorimeter , the heat present was initially absorbed by the water and that does not result to an increase in the temperature change in the calorimeter. Thus the temperature change in the calorimeter will be lower.