By rectangular box formula, the surface area is 8/h
We need to know about rectangular box volume to solve this problem. The volume of the rectangular box can be calculated by multiplying the base area by height. It can be written
V = SA . h
where V is volume, SA is base area and h is height
From the question above, we know that
SA = square
V = 8 m³
Hence, the surface area is
SA = x²
where x is side of the base length
Substitute to rectangular box volume equation
V = SA . h
8 = x².h
h = 8/x²
x = √(8/h) ...... (1)
Substitute (1) to find surface area function
SA = x²
SA = (√(8/h))²
SA = 8/h
Hence, the surface area is 8/h
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L= 1 H and R = 3.9 KQ. V (w) Vi (w) b) Sketch the magnitude of the frequency response function H(w). c) Determine what type of ideal filter is approximated by this circuit. a) Find H (w) = + vi(t) L R + vo(t)
The circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. To find the frequency response function H(w) for the given circuit, we need to determine the transfer function H(w) = V0(w) / Vi(w), where V0(w) is the output voltage and Vi(w) is the input voltage in the frequency domain.
L = 1 H (inductance)
R = 3.9 KΩ (resistance)
The circuit can be represented by the following equation:
H(w) = (jwL + R) / (jwL + R + 1)
To sketch the magnitude of the frequency response function H(w), we need to plot the magnitude |H(w)| as a function of frequency w.
Taking the magnitude of the transfer function, we have:
|H(w)| = |(jwL + R) / (jwL + R + 1)|
Next, let's analyze the type of ideal filter approximated by this circuit. We can examine the transfer function to determine the filter characteristics.
From the transfer function:
H(w) = (jwL + R) / (jwL + R + 1)
As w approaches infinity, the jwL term dominates the transfer function, and the transfer function becomes:
H(w) ≈ jwL / jwL = 1
This indicates that the circuit has a constant gain of 1 for high frequencies, implying that it acts as a low-pass filter. It allows low-frequency signals to pass through relatively unattenuated while attenuating high-frequency signals.
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A curium-242 (Z= 96) can be produced by positive-ion bombardment when an alpha particle collides with which of the following nuclei? Note: A neutron is also a product of this bombardment, in addition to the curium-242.
A. Pu -239
B. U -239
C. Am-241
D. Cf-249
E. Pu-241
Answer:
A. Pu -239
Explanation:
An isotope is an element with the same atomic number but different mass number. most isotope are unstable, having short half life.
Curium-242 is an isotope produced when Plutonium 239 is bombarded by an alpha particle. This reaction between Plutonium 239 and alpha particle gives curium-242, neutron and a high amount of energy as the products.
Curium oxidizes easily, and it is a dangerous metal which can cause cancer initiation when absorbed by biological materials e.g bones or tissue.
Solve for the indicated variable
mass (m):
200 N = m (3.5 %)
Answer:
5714.29
Explanation:
The given expression is:
200 = m(3.5% )
To solve this problem, we use the concept of multiplicative inverse;
The multiplicative inverse involves using the reciprocal of 3.5% to multiply both side of the expression;
200 = m x \(\frac{3.5}{100}\)
m = \(\frac{100}{3.5}\) x 200 = 5714.29
will give brainliest
Answer:
a = 5 m/s^2
Explanation:
The force is constant. The distance does not matter if there is no friction. This is an example of Newton's second law.
F = m * a
F = 10 N
m = 2 kg
a = ?
10 = 2 * a Divide by 2
10/2 = a
a = 5 m/s^2 second from the bottom.
0.20 kg block is suspended from a vertically hanging spring it stretches the spring from its original length of 0.050m to 0.060 m. the same block is attached to the same spring and placed on a horizontal frictionless surface. The block is then pulled so that the spring stretches to a total length of 0.10 m. The block is released at time Band undergoes simple harmonic motion. What is the frequency of the motion?
Frequency of motion is 4.98 Hz.
Given that ;
Mass of bock (m) = 0.2 kg
As, vertically hanging spring it stretches the spring from its original length of 0.050m to 0.060 m
So, Change in length (∆x) = 0.06-0.06 = 0.01 meter
Applying Hooks Law ;
F = K∆x {where F is force} and {K is spring constant}
We know that F = mg {where, m and g are mass and gravitational force respectively}
Thus, mg = K∆x
K = mg/∆x
K = (0.2×9.8) /0.01
K = 196 N/m
Angular velocity, ω = \(\sqrt{\frac{K}{m} }\)
ω = \(\sqrt{\frac{196}{0.2} }\)
ω = 31.305 rad/s
For Frequency, F = ω/2\(\pi\)
F = 31.305/2π
F = 4.98 Hz
Hence ,frequency of motion is 4.98 Hz
What is simple harmonic motion-
repeated movement through a center, or equilibrium, position in physics where the maximum displacement on one side of the position is equal to the maximum displacement on the other. Each whole vibration occurs at the same time interval.
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the density of mercury is 13.5 g/ml. what is the mass in kg of mercury that fills a 0.250-l flask?
Answer:
Density of water = 1 (1 g / ml)
.25 L = 250 ml (milleters)
mass of flask = 250 ml * 1 g / ml = 250 g (water to fill flask)
Equivalent mass of Hg = 13.5 * 250 g = 3375 g = 3.375 kg
Rewrite the following sentence in the negative form >Each library contains 3000 brand new books
The electron affinity of thulium has been measured by a technique known as laser photodetachment electron spectroscopy. In this technique, a gaseous beam of the anions of an element is bombarded with photons from a laser. Electrons from the anion are then ejected and their energies are detected. The incident radiation had a wavelength of 1064 nm, and the ejected electrons were found to have an energy of 0.137 eV. The electron affinity is the difference in energy between the incident photons and the energy of the ejected electrons. Determine the electron affinity of thulium in units of electron volts per atom.
Answer:
ΔE = 1.031 eV
Explanation:
For this exercise let's calculate the energy of the photons using Planck's equation
E = h f
wavelength and frequency are related
c = λ f
f = c /λ
let's substitute
E = h c /λ
let's calculate
E = 6.63 10⁻³⁴ 3 10⁸/1064 10⁻⁹
E = 1.869 10⁻¹⁹ J
let's reduce to eV
E = 1.869 10⁻¹⁹ J (1 eV / 1.6 10⁻¹⁹ J)
E = 1.168 eV
therefore the electron affinity is
ΔE = E - 0.137
ΔE = 1.168 - 0.137
ΔE = 1.031 eV
The electron affinity of thulium in units of electron volts per atom is; ΔE ≈ 1.031 eV
From Planck's equation, we can find the energy of the photons when given wavelength as;
E = hc/λ
Where;
h is Planck's constant = 6.626 × 10⁻³⁴ J.s
c is speed of light = 3 × 10⁸ m/s
λ is wavelength
We are given;
wavelength; λ = 1064 nm = 1064 × 10⁻⁹ m
Thus;
E = (6.626 × 10⁻³⁴ × 3 × 10⁸)/(1064 × 10⁻⁹)
E2 = 1.868 × 10⁻¹⁹ J
Converting to eV gives;
E2 = (1.868 × 10⁻¹⁹)/(1.6 × 10⁻¹⁹)
E2 = 1.1675 eV
We are given E1 = 0.137 eV.
Now, electron affinity is simply change in energy. Thus;
ΔE = 1.1675 - 0.137
ΔE ≈ 1.031 eV
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Which kind of energy do flowing electrons have?
O A. Nuclear
B. Gravitational
C. Electrical
D. Elastic
Answer:
Gravitational
Explanation:
They are on the outside of a nucleus
Answer: C
Explanation: Electricity is basically the movement of electrons through a substance,
Which of the following X-Y tables agrees with
the information in this problem?
A)
A puck moves 2.35 m/s in a -22.0° direction. A hockey
stick pushes it for 0.215 s, changing its velocity to 6.42
m/s in a 50.0° direction. What was the acceleration?
Vi
Vf
a
ΔΧ
X
2.18
4.13
?
t 0.215
Y
-0.880
4.92
?
0.215
B) X
V₁
Vf
2.35
6.42
a
?
Ax 0.215
t
Y
2.35
6.42
?
a
0.215 ΔΧ
t
C)
X
V; 0.880
V₁ 4.92
?
0.215
Y
-2.18
4.13
?
0.215
This value agrees with the value we would obtain from the Y-axis in table B, which represents the acceleration as 18.98 m/s^2. Therefore, table B is the correct X-Y table.
In this problem, we are given the initial velocity (Vi = 2.35 m/s, direction = -22.0°), final velocity (Vf = 6.42 m/s, direction = 50.0°), and time interval (t = 0.215 s). We are asked to find the acceleration (a).
The X-Y table B shows the initial velocity (V₁ = 2.35 m/s), final velocity (Vf = 6.42 m/s), and time interval (t = 0.215 s) along the X-axis. The acceleration (a) is represented by an unknown value in the Y-axis.
Using the equation a = (Vf - Vi)/t, we can substitute the given values and calculate the acceleration:
a = (6.42 m/s - 2.35 m/s)/0.215 s = 18.98 m/s^2
This value agrees with the value we would obtain from the Y-axis in table B, which represents the acceleration as 18.98 m/s^2. Therefore, table B is the correct X-Y table.
What is an acceleration?
Acceleration is a physical quantity that describes the rate at which an object changes its velocity over time. It is defined as the change in velocity (Δv) per unit of time (Δt), or more formally, as the second derivative of position with respect to time. The unit of acceleration is meters per second squared (m/s^2).
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When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet.
When earth catches up to a slower-moving outer planet and passes it in its orbit, in the same way that a faster runner overtakes a slower runner in an outside lane, the outer planet exhibits a retrograde motion
When a planet is far from another planet and observed from it, it rotates at a slower rate, making it appear that it is "retrograding" with regard to the other planet.
Early astronomers were perplexed when they observed motion in the sky because they attempted to explain it in terms of the geocentric idea.
Due to their commitment to the geocentrical paradigm, which stated the Earth was the center of the solar system, early astronomers were perplexed and unable to explain the phenomena.
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In the figure, a
4.4 kg
block is accelerated from rest by a compressed spring of spring constant
640 N/m
. The block leaves the spring at the spring's relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction
μ k
=0.296
. The frictional force stops the block in distance
D=7.7 m
. What are (a) the increase in the thermal energy of the block-floor system, (b) the maximum kinetic energy of the block, and (c) the original compression distance of the spring? (a) Number Units (b) Number Units In the figure, a
4.4 kg
block is accelerated from rest by a compressed spring of spring constant
640 N/m
. The block leives the spring at the spring's relaxed length and then travels over a horizontal floor with a coefficient of kinetic friction
μ 2
=0.296
. The frictional force stops the block in distance
D=7.7 m
. What are (a) the increase in the thermal energy of the block-floor system, (b) the maximum kineticenergy of the block, and (c) the original compression distance of the spring? (a) Number Units (b) Number Units
The (a) increase in the thermal energy of the block-floor system 139.3 J
(b), the maximum kinetic energy of the block 614.3 J
(c), and the original compression distance of the spring 0.625 m
(a) The increase in thermal energy of the block-floor system is equal to the work done by the friction force. This can be calculated using the equation
Work = Force × Distance,
where the friction force is equal to the coefficient of kinetic friction multiplied by the normal force, and the distance is equal to the stopping distance (7.7 m).
Therefore, the increase in thermal energy of the block-floor system is equal to
(0.296 x 4.4 kg x 9.8 m/s² x 7.7 m) = 139.3 J.
(b) The maximum kinetic energy of the block is equal to the kinetic energy of the block when it leaves the spring. This can be calculated using the equation
Kinetic Energy = ½ mv²,
where m is the mass of the block (4.4 kg) and v is the velocity of the block when it leaves the spring. This velocity can be found by using the equation
Force = Mass x Acceleration with the spring constant (640 N/m) and the mass of the block (4.4 kg).
Therefore, the maximum kinetic energy of the block is equal to
(0.5 x 4.4 kg x (640 N/m / 4.4 kg)²) = 614.3 J.
(c) The original compression distance of the spring can be found by using the equation
K.E (spring) 1/2 Kx² + Work done = 0
-1/2 * 640 N/m * x² + 99.93 J = 0
Solving for x, we get:
x = √(99.93 J / (1/2 * 640 N/m))
x = 0.625 m
Therefore, the original compression distance of the spring is 0.625 m.
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impulse-momentum: a 0.500-kg ball traveling horizontally on a frictionless surface approaches a very massive stone at 20.0 m/s perpendicular to wall and rebounds with 70.0% of its initial kinetic energy. what is the magnitude of the change in momentum of the stone?
The change in momentum of the stone is equal to the change in momentum of the ball, which is 3.0 kg m/s.
What is momentum?Momentum is the product of an object's mass and velocity. It is a measure of the amount of motion an object has and is calculated by multiplying the mass of an object by its velocity. Momentum is a vector quantity, meaning it has both magnitude and direction. Momentum is conserved in closed systems, meaning the total momentum of a system remains the same before and after any given reaction or interaction. Momentum is used to describe the behavior of objects in motion, such as how quickly a ball rolls down a hill, or how fast a car accelerates. Momentum can also be used to calculate the impact of collisions and other interactions.
The initial momentum of the ball is given by its mass and velocity, which is 0.500 kg x 20.0 m/s = 10.0 kg m/s.
When the ball rebounds, it has 70.0% of its initial kinetic energy, which corresponds to a velocity of 14.0 m/s.
This means that the final momentum of the ball is 0.500 kg x 14.0 m/s = 7.0 kg m/s.
Therefore, the change in momentum of the stone is equal to the change in momentum of the ball, which is 10.0 kg m/s - 7.0 kg m/s = 3.0 kg m/s.
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Is it true that an object moves in a a circle at a constant speed will also have a constant velocity ?
Answer:
true
Explanation:
because the speed at which the object is moving in the circle depends on the effort used
On vacation, your 1300-kg car pulls a 500-kg trailer away from a stoplight with an acceleration of 1.70m/s2.
What force does the trailer exert on the car?
Assume that the positive x axis is directed toward the direction of motion.
This means that the trailer exerts a force of 3060 N on the car in the opposite direction to the car's motion.
How to find total foce on the system?This is the total force acting on the system, but we want to know the force that the trailer exerts on the car. To find this, we can use Newton's third law of motion, which states that for every action, there is an equal and opposite reaction. In this case, the action is the force that the car exerts on the trailer, and the reaction is the force that the trailer exerts on the car.
To solve this problem, we'll need to use Newton's second law of motion, which states that the force acting on an object is equal to its mass times its acceleration:
F = ma
where F is the force, m is the mass, and a is the acceleration.
First, we need to find the total mass of the system:
m_total = m_car + m_trailer
m_total = 1300 kg + 500 kg
m_total = 1800 kg
Next, we can use the given acceleration to find the total force acting on the system:
F_total = m_total * a
F_total = 1800 kg * 1.70 \(m/s^2\)
F_total = 3060 N
Therefore:
F_trailer_on_car = -F_car_on_trailer
where the negative sign indicates that the force exerted by the trailer is in the opposite direction to the force exerted by the car.
We already know that the force exerted by the car is equal to the total force acting on the system:
F_car_on_trailer = F_total
F_car_on_trailer = 3060 N
Therefore:
F_trailer_on_car = -3060 N
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A basketball referee tosses the ball straight up for the starting tip-off. At what velocity must a basketball player leave the ground to rise 1.15 m above the floor in an attempt to get the ball
Answer:
the basketball player must leave the ground with a velocity of 4.748 m/s
Explanation:
Given that data in the question;
From the third equation of motion;
v² - u² = 2as
such that;
u² = v² - 2as
where u is the initial velocity, v is the final velocity, s is the displacement and a is acceleration
so initial velocity of the basket ball player will be;
u = √( v² - 2as )
so from the question; s is 1.15 m and a = - 9.8 m/s² { player is under negative acceleration to get to the ball } and final velocity of the player will be 0.
so we substitute
u = √( (0)² - (2 × -9.8 × 1.15 )
u = √ -( - 22.54 )
u = √ ( 22.54 )
u = 4.748 m/s
Therefore, the basketball player must leave the ground with a velocity of 4.748 m/s
You are handed a spring that is 0.50m long. You hang the spring from a hook on the ceiling and attach a 0.75-kg mass to the other end of the spring. The stretched spring length is 0.65 m. What is the spring constant?
The spring constant is 4900N/m
We are given that,
The mass of the ceiling = m = 0.75kg
The total length of the spring = x = 0.65cm - 0.50cm = 0.15cm
Therefore , to get the value of the spring constant (k) by applying Hook's law that can be given as,
F = kx
Where, F is the total force on the spring , k is the spring constant and x is the length of the spring.
Since , to get the F i.e. force of the spring by Newton's second law of motion, for mass m and acceleration due to gravity is g i.e. 9.8m/s²
F = mg
F = 0.75kg × 9.8m/s²
F = 7.35 N
Then, the spring constant is given as,
k = F/x
k = (7.35N)/(0.0015m)
k = 4900N/m
Therefore, the spring constant may be given as 4900N/m
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The photoelectric effect describes when light shines on a piece of metal, and the metal releases electrons. Which characteristic of light behavior best helps explain this effect?
Light carries particles called photons.
Light moves as waves.
Light has an electric field and a magnetic field.
Light has waves with different frequencies.
Answer:
The characteristic of light behavior that best helps explain the photoelectric effect is that light carries particles called photons. When the photons of light strike the metal surface, they transfer their energy to the electrons in the metal, and if the energy of the photons is high enough, they can cause electrons to be emitted from the metal surface. This phenomenon is known as the photoelectric effect, and it was first explained by Albert Einstein in 1905.
In terms of vectors why does an object slow down? (physics question)
A student is creating a model of a concave lens. The diagram shows her incomplete model.
Which action would best complete her model?
A
The student should draw the light moving into the lens and then exiting in converging lines.
B
The student should draw the rays of light moving into the lens and then exiting at right angles.
C
The student should draw the rays of light moving into the lens and then exiting in a straight path.
D
The student should draw the light moving into the lens and then exiting in lines that are spreading out.
Answer:
D
Explanation:
I’m pretty sure it’s correct but I don’t really know. Just trying to pass science
Answer:
The correct answer is D trust me I did the test
When the concave lens moves in it exit by spreading out like water
What force will cause a displacement of 2m, while doing a work of 50J
Using the work done relation, the value of force is 25 Newton.
When a force is applied along a displacement, "work" in physics refers to the energy that is transported to or away from an object. The following situations include work: relocating a table. a door being pulled and pushed. Walking. raising a stone.
The work W that a force F traveling across a distance x exerts on an object is calculated using the formula W=Fs. If the object is moving in the opposite direction from how we expect it to, we add a minus sign.
Work done is equal to displacement times force.
50J = force × 2
f=50/2
Force = 25 Newton.
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a planet with the same mass as earth orbiting at a distance of 1 au from a star with thirty six times the sun's mass.
To determine the orbital period of a planet with the same mass as Earth orbiting at a distance of 1 AU from a star with thirty-six times the mass of the Sun, we can use Kepler's third law of planetary motion.
Kepler's third law states that the square of the orbital period (T) is proportional to the cube of the semi-major axis (a) of the orbit. The semi-major axis of the Earth's orbit is approximately 1 AU, which is equivalent to about 149.6 million kilometers. Given: Mass of the star (M_star) = 36 times the mass of the Sun. To calculate the orbital period, we need to find the value of the semi-major axis of the planet's orbit around the star. Using Kepler's third law equation: T^2 = (4π^2 / G * M_star) * a^3 Where: T is the orbital period in seconds, G is the gravitational constant (approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2), M_star is the mass of the star in kilograms, a is the semi-major axis of the orbit in meters. We need to convert the distance from AU to meters: 1 AU = 149.6 million kilometers = 149.6 x 10^9 meters. Substituting the values: T^2 = (4π^2 / (6.67430 x 10^-11) * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 Simplifying the equation and solving for T: T^2 = 4π^2 * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 / (6.67430 x 10^-11) Taking the square root of both sides to find T: T = √(4π^2 * (36 * (1.989 x 10^30)) * (149.6 x 10^9)^3 / (6.67430 x 10^-11)) Evaluating this expression will give us the orbital period of the planet.
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To calculate the gravitational force between a planet with the same mass as Earth and a star with thirty-six times the sun's mass at a distance of 1 AU, we can use Newton's law of universal gravitation.
Explanation:If a planet with the same mass as Earth orbits at a distance of 1 AU from a star with thirty-six times the sun's mass, we can calculate the gravitational force between them using Newton's law of universal gravitation. The formula is F = G * (m1 * m2) / r^2, where G is the gravitational constant, m1 and m2 are the masses of the two bodies, and r is the distance between them.
In this case, the mass of the planet is the same as Earth's mass (let's call it m), the mass of the star is 36 times the sun's mass (36M), and the distance between them is 1 AU. Plugging these values into the formula, we get F = G * (m * 36M) / (1 AU)^2.
To find the force, we need the values of G and the masses. The value of G is approximately 6.67430 × 10^-11 N(m/kg)^2. The mass of the sun is about 1.989 × 10^30 kg. Substituting these values, we can calculate the force between the planet and the star.
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if brakes were applied to a already moving car with a speed of 72 kilometre per hour to reduce it to the speed of 18 kilometre per hour in 10 seconds calculate
Answer:
Acceleration, a = -0.5 m/s²
Explanation:
Given the following data;
Initial velocity = 72 km/h
Final velocity = 18 km/h
Time = 10 seconds
To find the acceleration of the car;
Conversion:
72 km/h to m/s = 72*1000/3600 = 20m/s
18 km/h to m/s = 18*1000/3600 = 5 m/s
In physics, acceleration can be defined as the rate of change of the velocity of an object with respect to time.
This simply means that, acceleration is given by the subtraction of initial velocity from the final velocity all over time.
Hence, if we subtract the initial velocity from the final velocity and divide that by the time, we can calculate an object’s acceleration.
Mathematically, acceleration is given by the equation;
\(Acceleration (a) = \frac{final \; velocity - initial \; velocity}{time}\)
Substituting into the equation;
\(a = \frac{5 - 20}{10}\)
\(a = \frac{-5}{10}\)
Acceleration, a = -0.5 m/s²
Therefore, the car is decelerating.
At a certain time a particle had a speed of 17 m/s in the positive x direction, and 3.0 s later its speed was 28 m/s in the opposite direction. What is the average acceleration of the particle during this 3.0 s interval
Answer:
i wanna say 11 forgive me if wrong.
Explanation:
Let's begin by determining the equilibrium position of a seesaw pivot. You and a friend play on a seesaw. Your mass is 90 kg and your friend's mass is 60 kg. The seesaw board is 3.0 m long and has negligible mass. Where should the pivot be placed so that the seesaw will balance when you sit on the left end and your friend sits on the right end? Part A let's look at the same scenario we just worked through, but instead the board now has a non-zero mass of 29 kgkg . where should the pivot be placed for balance?
The pivot should be placed 1.31 m from the left end of the board to balance the seesaw when you sit on the left end and your friend sits on the right end, taking into account the mass of the board.
T1 = 90 kg * g * (x - 1.5 m)
T2 = 60 kg * g * (1.5 m - x).
T3 = Mg * (L/2 - x)
In the equilibrium position, we set the sum of the torques equal to zero:
T1 + T2 + T3 = 0
90 kg * g * (x - 1.5 m) + 60 kg * g * (1.5 m - x) + Mg * (L/2 - x) = 0
Simplifying and solving for x, we get:
x = (45 kg * L + 1.5 m * (90 kg - 60 kg)) / (M + 150 kg)
Substituting the values given in the problem, with M = 29 kg, we get:
x = (45 kg * 3.0 m + 1.5 m * 30 kg) / (29 kg + 150 kg)
x = 1.31 m
Torque is a measure of the force that causes an object to rotate around an axis or pivot point. It is often described as the rotational equivalent of force. The amount of torque an object experiences is dependent on both the magnitude and direction of the applied force, as well as the distance between the axis of rotation and the point where the force is applied.
The formula for torque is τ = r × F, where τ is the torque, r is the distance between the axis of rotation and the point of force application, and F is the magnitude of the applied force. Torque is typically measured in units of Newton meters (Nm) or pound-feet (lb-ft). Torque is an important concept in many areas of physics, including mechanics, engineering, and robotics. It plays a critical role in the operation of machines and engines, as well as in the movement and control of vehicles and aircraft.
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A 2m 3m m of masses m, 3m, and 2m resting on 15. Three blocks frictionless horizontal surface are connected to above. A force of identical ideal springs, as shown F directed to the left is then applied to magnitude thegefttend of spring A: Which spring is stretched the most when the biocks are all moving with the same acceleration? (A) A (B) B (C) C (D) None, because the springs do not stretch. (E) None, because the springs all stretch the same amount:
Spring (c) C is stretched the most when the blocks are all moving with the same acceleration.
To determine which spring is stretched the most when the blocks are all moving with the same acceleration, we need to consider the forces acting on each block and the resulting spring forces.
Let's analyze the situation:
1. Block of mass m: The force F applied to the left will create a net force of 2F to the right (since there are two masses of m on the right). This net force will accelerate the block to the right. The spring connected to this block (spring A) will experience a force of 2F to the left.
2. Block of mass 3m: This block is pulled to the right by the two blocks of mass m. The net force acting on this block is also 2F to the right. The spring connected to this block (spring B) will experience a force of 2F to the left.
3. Block of mass 2m: This block is being pulled to the right by the block of mass 3m. The net force acting on this block is F to the right. The spring connected to this block (spring C) will experience a force of F to the left.
Based on the analysis, we can conclude that spring C is stretched the most when the blocks are all moving with the same acceleration. This is because it experiences the highest magnitude of force (F) compared to spring A and spring B, which experience forces of 2F.
Therefore, the correct answer is (C) C: spring C.
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A bowling ball collides with a tennis ball. Which object has the larger impact force on the other considering that they have the same acceleration? Why?
This is for an exam could you please answer fast
Answer:
The tennis ball experiences a larger impact force due to its smaller mass.
Explanation:
Considering that they have the same acceleration, and F = ma where F is force and m = mass, the object with the smaller mass has a greater impact force on it.
This is because since force F = ma and a = constant, the object with a larger mass (the bowling ball)has a larger impact force with which it acts on the object with the smaller mass (the tennis ball). So, the tennis ball experiences a larger impact force due to its smaller mass.
Pilots on IFR flights seeking ATC in flight weather avoidance assistance should keep in mind that A. circumnavigating severe weather can only be accommodated in the en route areas away from terminals because of congestion. B. ATC Narrow Band Radar does not provide the controller with weather intensity capability. C. ATC radar limitations and, frequency congestion may limit the controllers capability to provide this service.
When pilots on Instrument Flight Rules (IFR) flights seek Air Traffic Control (ATC) in-flight weather avoidance assistance, they should keep in mind that ATC radar limitations and frequency congestion may limit the controller's capability to provide this service. The correct answer is C.
This means that while ATC can provide weather information and assistance in avoiding hazardous weather conditions, their ability to do so may be limited by factors such as the number of planes in the area, the capabilities of the radar equipment, and the available frequencies. Pilots should therefore be prepared to make their own weather-related decisions and take appropriate action if necessary, even if they are unable to obtain assistance from ATC.
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Why do the interiors of saturn and jupiter contain large amounts of liquid metallic hydrogen?
The interiors of Saturn and Jupiter contain a large amount of large metallic hydrogen because liquid hydrogen transforms into liquid metallic hydrogen as one descends, reaching a depth of 12,000 kilometers as the radius of Jupiter is 71,000 kilometers the hydrogen is below the cloud layers.
Helium and hydrogen make up the majority of the atmospheres of Jupiter and Saturn. The hydrogen changes from a high-pressure gas to liquid hydrogen a few hundred kilometers below the cloud levels. It would take some fairly intense pressures to create this on Earth, but it is possible. It's a component of rocket fuel.
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not moving or moving at a constant speed in the same direction is called
Moving at a constant speed in the same direction is called uniform motion.
Uniform motion occurs when an object is moving in a straight line with a constant speed. Motion is the change in an object's location with respect to time. Mathematically, motion is described in terms of the body's location with regard to the observer's frame of reference through time, as well as displacement, distance, velocity, acceleration, and speed.. Kinematics is the area of physics that studies how motion is affected by forces, whereas dynamics is the area that studies how motion is affected by forces.For example, if a car is traveling down a straight road at a speed of 50 km/h, the car is said to be in uniform motion.
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complete question:Not moving or moving at a constant speed in the same direction is called
a. Steady Motion
b. Linear Motion
c. Constant Velocity
d. Uniform Motion