An scientist located a nugget of an unknown substance. However, he determined that this nugget has a
mass of 63 g and a volume of 9 cm^3. What is the density of this nugget?

Answers

Answer 1

Answer: The density of this nugget is \(7\text{ g cm}^{-3}\) .

Explanation:

We are given that,

Mass of nugget = 63 g

Volume = \(9\ cm^3\)

The computation of density of a substance is given by :-

\(\text{Density}=\dfrac{\text{Mass}}{\text{Volume}}\\\\\Rightarrow\ \text{Density}=\dfrac{63}{9}\text{ g cm}^{-3}\)

\(\Rightarrow\ \text{Density =}7\text{ g cm}^{-3}\)

Therefore, the density of this nugget is \(7\text{ g cm}^{-3}\) .


Related Questions

what is perodic table list all the elements up to 30 with their valencies​

Answers

Answer:

a table of the chemical elements arranged in order of atomic number, usually in rows, so that elements with similar atomic structure (and hence similar chemical properties) appear in vertical columns.

what is perodic table list all the elements up to 30 with their valencies

Given:
2C8H18 + 250216CO2 + 18H20
In the combustion of octane, how many grams of oxygen are needed to completely react and produce 84.00 grams of
carbon dioxide? Use the periodic table to get the weights of the elements.
Drag the labels to the correct locations to complete the analysis. Each label can be used more than once.
1 mol
mol
8.
g
g
mol
1 mol
02
44.009
16
95.43
31.998
84.00
CO2
25

Given:2C8H18 + 250216CO2 + 18H20In the combustion of octane, how many grams of oxygen are needed to completely

Answers

how are you gonna compare how much 10,00

polycondensation reaction takes place between 1.2 moles of a dicarboxylic acid, 0.4 moles of glycerol (a triol) and 0.6 moles of ethylene glycol (a diol). A.Calculate the critical extents of reaction for gelation using (i) the statistical theory of Flory and (ii) the Carothers theory.B.Comment on the observation that the measured value of the critical extent of reaction is 0.866.

Answers

Answer:

(a). (I). 0.816; 0.816

(ii). 0.917.

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Explanation:

So, without mincing words let's get straight into the solution to the question above.

(a). Using the (i) statistical theory of Flory to Determine the critical extent of reaction gelation, one has to make use of the two equations given below;

P(1) = [ v + vb ( n - 2)^-1/2 ------------------(1).

P(2) = v^1/2 [ 1 + b ( n - 2)^-1/2 ----------(2).

The value for v = 1.2 + 1.2/ 1.2 × 2 = 1.

The value of b = (1.2 + 1.2)/ 1.2 = 0.5.

Thus, putting the values into the equation (1) and (2) above gives;

NB: n = 3.

P(1) = [ 1 + 1 × 0.5 ( 3 - 2)^-1/2 = 0.816.

P(2) = 1^1/2 [ 1 + 0.5 ( 3 - 2)^-1/2 = 0.816.

Using the (ii) carother's theory to Determine the critical extent of reaction gelation.

We have the following values for glycerol: k = 0.4, n = 3.

For ethylene glycol; k = 0.6, n = 2.

Therefore, the critical extent of reaction gelation =2/[ (0.6 × 2) + (0.4 × 3) + (1.2 × 2)/ (0.6 + 0.4 + 1.2)] = 2/ 2.18 = 0.917

(b). When the value for the critical extent of reaction is 0.866, then the number of moles of glycerol and the number of moles of di-carboxylic acid is the same. But, in this case the number of moles of glycerol is not the same with the number of moles of di-carboxylic acid.

Using the guideline for oxidation numbers, write the reduction half-reactions for the following:
• O
• P
• Cu

Answers

The reduction half-reactions for O, P, and Cu:

• O: O2 + 4 e- → 2 O2-

• P: HPO42- + 2 H+ + 2 e- → H3PO4

• Cu: Cu2+ + 2 e- → Cu+

To write the reduction half-reactions for O, P, and Cu, we need to determine the oxidation numbers for each element. The guidelines for assigning oxidation numbers are:

The oxidation number of an atom in its elemental form is 0.The oxidation number of a monatomic ion is equal to its charge.The sum of the oxidation numbers of all atoms in a neutral molecule must be 0.The sum of the oxidation numbers of all atoms in a polyatomic ion must be equal to the charge of the ion.

Using these guidelines, we can determine the oxidation numbers for O, P, and Cu:

O: Oxygen is a diatomic molecule, so its oxidation number is 0 in O2.P: The most common oxidation state for phosphorus is +5 in its compounds, but it can also have oxidation states ranging from -3 to +5.Cu: The most common oxidation state for copper is +2, but it can also have oxidation states ranging from +1 to +4.

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what are thetypes of luminous flame

Answers

Types of luminous flames:

1. Yellow Luminous Flame

2. Smoky Luminous Flame

3. Orange Luminous Flame

4. Blue Luminous Flame

Luminous flames are characterized by their visible glow, which is caused by the incomplete combustion of fuel. The presence of soot particles in the flame causes the emission of light. There are different types of luminous flames, which can be classified based on their fuel composition and burning conditions. Here are some common types of luminous flames:

1. Yellow Luminous Flame: This is the most common type of luminous flame, often seen in open fires, candles, and gas stoves. It appears yellow due to the presence of soot particles in the flame. Yellow flames indicate incomplete combustion of hydrocarbon fuels, such as methane, propane, or natural gas. The high carbon content in these fuels leads to the formation of soot, which emits visible light.

2. Smoky Luminous Flame: This type of flame is characterized by a significant amount of black smoke and soot production. It is commonly observed in poorly adjusted or malfunctioning burners or engines. The excessive presence of unburned fuel in the flame results in incomplete combustion and the emission of dark smoke particles.

3. Orange Luminous Flame: An orange flame indicates a higher combustion temperature compared to a yellow flame. It is often seen in more efficient burners or when burning fuels with a higher carbon content, such as oil or diesel. The higher temperature helps in burning more of the carbon particles, reducing the amount of soot and making the flame appear less yellow.

4. Blue Luminous Flame: A blue flame is typically associated with complete combustion. It indicates efficient burning of fuel, resulting in minimal soot formation. Blue flames are commonly observed in gas burners or Bunsen burners. The blue color is a result of the combustion of gases, such as methane, in the presence of sufficient oxygen.

It's important to note that the luminosity of a flame can vary depending on factors such as fuel-air mixture, combustion temperature, and the presence of impurities. Achieving complete combustion and minimizing the production of soot is desirable for efficient and cleaner burning processes.

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Plz help ASAP i will give brainlists

2AgNO3 + BaCl2 + 2AgCl + Ba(NO3)2
How many grams of silver chloride are produced from 15.0 g of silver nitrate reacting with an excess of barium chloride?
A)9.44 g Agci
B)16.4 g Agci
C)12.7 g Agci
D)0 20.1 g Agci

Answers

The correct answer is C!

a cube of iron pyrite is 0.31 cm on each side and has a mass of 0.040g. what is the density of the sample?

Answers

The density of the iron pyrite cube is 1.343 g/cm³.

Given,

Side of iron pyrite cube = 0.31 cm

Mass of iron pyrite = 0.040 g

The volume of iron pyrite cube = s³ cm³

Or, volume = 0.029791 cm³

We have to find the density of the sample.

Density is defined as the mass per unit volume. Or, it is the ratio of mass to the volume of the substance.

Using the formula for density, we get,

Density = mass/volume

Or, density = 0.40/0.029791

Or, density = 1.343 g/cm³

Hence, the density of the iron pyrite cube is 1.343 g/cm³.

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An insulin drip is mixed as 500.0 units in 250.0 mL Normal Saline (NS). Calculate the drip rate in mL/h needed to deliver 4.0 units/h?

Answers

Answer:

Drip rate = 2 ml/h

Explanation:

Given:

Amount of insulin = 500 unit

Amount of saline = 250 ml

Required infusion rate = 4.0 units/h

Find:

Drip rate

Computation:

Concentration = Units of insulin / Volume of saline

= 500 / 250

Concentration = 2 units/ml

Drip rate = Infusion rate / concentration

Drip rate = 4 / 2

Drip rate = 2 ml/h

The drip rate is \(5 \ mL/h\).

An amount of saline \(=250 mL\)

An amount of insulin\(=200 mL\)

Required infusion rate\(=4.00 \ units/h\)

Concentration\(=\frac{units \ of \ insulin}{Volume \ of \ saline}\)

                       \(=\frac{200}{250}\)

                       \(=0.8 \ units/mL\)

Drip rate\(=\frac{Infusion \ rate}{concentration}\)

             \(=\frac{4}{0.8} \\=5 \ mL/h\)

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How many molecules are there in a 42.3g sample of water

Answers

Answer:

This means that one mole of water molecules has a mass of 18.015g.

42.3g * 1 mole H2O/18.015g

= 2.3480 moles H2O

We are using the avogadros number to find the number of molecules of water

2.3480 H2O * 6.022*10^ 23moles/ 1mole of H2O

That's 2.3480 multiplied by 6.022*10^23 divided by 1 mole of H2O

Number of molecules = 1.4140 *10^24 molecules

A 25.0 g sample of warm water at 40.0⁰C was added to a 25.0 g sample of water in a Styrofoam coffee cup calorimeter initially at 20.0⁰C. The final temperature of the mixed water and calorimeter was 29.5⁰C. Calculate the heat capacity of the coffee cup calorimeter. The specific heat of water is 4.184 J/g∙⁰C.

a.
0.189 J/⁰C

b.
27.3 J/⁰C

c.
11.0 J/⁰C

d.
116 J/⁰C

Answers

Answer:

2024.70 J

Explanation:

The heat capacity of the coffee cup calorimeter can be calculated using the following formula:

q_calorimeter = q_water + q_water_final

where q_calorimeter is the heat absorbed by the coffee cup calorimeter, q_water is the heat lost by the warm water, and q_water_final is the heat gained by the cold water.

First, calculate q_water:

q_water = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the warm water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (40.0°C - 29.5°C) = 10.5°C is the change in temperature.

q_water = 25.0 g * 4.184 J/g°C * 10.5°C = 1057.35 J

Next, calculate q_water_final:

q_water_final = m_water * c_water * ΔT

where m_water = 25.0 g is the mass of the cold water, c_water = 4.184 J/g°C is the specific heat of water, and ΔT = (29.5°C - 20.0°C) = 9.5°C is the change in temperature.

q_water_final = 25.0 g * 4.184 J/g°C * 9.5°C = 967.35 J

Finally, calculate the heat capacity of the coffee cup calorimeter:

q_calorimeter = q_water + q_water_final = 1057.35 J + 967.35 J = 2024.70 J

So the heat capacity of the coffee cup calorimeter is 2024.70 J.

A 25.0 g sample of warm water at 40.0⁰C was added to a 25.0 g sample of water in a Styrofoam coffee cup calorimeter initially at 20.0⁰C. 2024.70 J is the heat capacity of the coffee cup calorimeter.

What is heat capacity?

A physical feature of matter known as heat capacity and thermal capacity is the quantity of heat that must be applied to an object in order to cause a unit change in temperature. Heat capacity is measured in joules per kelvin (J/K), the SI unit. A broad property is heat capacity.

The particular heat capacity, which can be calculated by dividing an object's heat capacity by its mass, is the comparable intense attribute. The molar heat capacity is obtained through dividing the specific heat even by molecular weight of the substance. The heat capacity per volume is gauged by the volumetric heat capacity. The term "thermal mass" is frequently used in civil engineering and architecture to describe a building's ability to hold heat.

q calorimeter = q water + q water final

q water = m ×c water ×ΔT

q water = 25.0 g×4.184 J/g°C ×10.5°C

              = 1057.35 J

q water final = m×c of water × ΔT

q water final = 25.0 g×4.184 J/g°C ×9.5°C

                   = 967.35 J

q calorimeter = q water + q water final

                      = 1057.35 J + 967.35 J

                      = 2024.70 J

Therefore,  2024.70 J is the heat capacity of the coffee cup calorimeter.

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How does the amount of sunlight affect the height of new plants ?
I need the topic please

Answers

Answer:

the more sun there is, the taller the plant

Explanation:

Explain how you would determine the charge of a metal, a non
metal and a transition metal for an ion within a compound. Be
prepared to provide the charge of an element on the periodic
table from each of these categories.

Answers

Answer:

In order to determine the charge of these elements you'll have to look at their placement in the periodic table by group number.

Explanation:

To further explain this, there is 18 groups of the periodic table.  These groups include:

Group 1: The alkali metals have a 1+ charge for their entire group.

For example: Sodium would have a charge of 1+.

Group 2: The earth alkali metals all have a charge of 2+. For example Mg has a charge of 2+.

Group 3-12: The transitions metals are a little harder to figure the charge of each, if given the compound they are bonded with you can use that to figure it out but only a few have distinct charges. Such as Ag (Silver) only have a 1+ charge. If you are still trying to figure the charge, try making an electron configuration to figure out it's spare electron count or charge.

Group 13: These elements in group 13 have a typical charge of 3+. For example Al has a charge of 3+.

Group 14: These elements in group 14 have a typical charge of 4+. For example Carbon has a charge 4+

Group 15: These elements start the shift towards a negative charge in the table, so for group 15 the elements have a 3- charge. For example Nitrogen has a 3- charge.

Group 16: These elements continue with a negative in group 16 with a negative charge of 2-. For example Oxygen's charge is 2-.

Group 17: The halogen elements in group 17 have a charge of 1-. For example Chlorine has a charge of -.

Group 18: The noble gases in group 18 do not have a charge because they are some of the most stable elements so they're not looking to gain or lose an electron (That is what a charge is basicaly). So, they're charge is none.  

Which of the following statements is true of the corona

A. It’s the visible surface of the sun
B. It’s where sunspots occur
C. It’s the outermost layer of the suns atmosphere
D. It’s responsible for the suns density

Answers

Answer:

C. It’s the outermost layer of the suns atmosphere

The answer is C.

Hopefully this helped...

Which of these is the best evidence that a chemical reactions occurs when coal burns?
A-Coal is made up of more than one element
B-a new substance is produced
C-Oxygen is present
D-The shape of coal changes

Answers

Answer:

B me get points

Explanation:

:(

Answer:

most likely A not sure

because coal let's off smoke that has carbon minoxidil and carbon gets into the oxygen o2

How many grams of Aspirin (acetylsalicylic acid) should we form in this reaction if we started with 2.08g of Salicyclic Acid?

Answers

Taking into account the reaction stoichiometry, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

Reaction stoichiometry

In first place, the balanced reaction is:

C₄H₆O₃ + C₇H₆O₃ (Salicyclic Acid) →C₉H₈O₄ (aspirin) + C₂H₄O₂

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

C₄H₆O₃: 1 moleC₇H₆O₃: 1 moleC₉H₈O₄: 1 moleC₂H₄O₂: 1 mole

The molar mass of the compounds is:

C₄H₆O₃: 102 g/moleC₇H₆O₃: 138 g/moleC₉H₈O₄: 180 g/moleC₂H₄O₂: 60 g/mole

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

C₄H₆O₃: 1 mole ×102 g/mole= 102 gramsC₇H₆O₃: 1 mole ×138 g/mole= 138 gramsC₉H₈O₄: 1 mole ×180 g/mole= 180 gramsC₂H₄O₂: 1  mole ×60 g/mole= 60 grams

Mass of aspirin formed

The following rule of three can be applied: if by reaction stoichiometry 138 grams of salicyclic acid form 180 grams of aspirin, 2.08 grams of salicyclic acid form how much mass of aspirin?

\(mass of aspirin=\frac{2.08 grams of salicyclic acidx 180 grams of aspirin}{138 grams of salicyclic acid}\)

mass of aspirin= 2.713 grams

Then, 2.713 grams of aspirin are formed when 2.08 grams of salicyclic acid reacts.

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Witch hazel solution, an astringent for skin,
contains 14% ethyl alcohol, C₂H5OH, by volume.
How many mL of ethyl alcohol are contained in a
16 fluid ounce bottle of witch hazel?

Answers

16 fluid ounce bottle of witch hazel will have 66.24ml of ethyl alcohol.

What is volume percentage?

volume percent of a solution is the ratio of the volume of a solute present in a solution to the volume of the solution as a whole.

Volume Percent  =  V solute(mL)/V solution(mL)  ×  100

Volume Percent  =  V solute(mL)/V solute(mL)+V solvent(mL)  ×  100

14% of 16 fluid ounce

=(14/100)×16

=0.14×16

=2.24 fluid ounce

=66.24ml

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water is important in chemical weathering because _______

Answers

Answer:

Water plays a very important role in chemical weathering in three different ways. First, it combines with carbon dioxide in the soil to form a weak acid called carbonic acid. ... Finally, the water can break up minerals through hydrolysis. The most common group of minerals, the silicates, is decomposed by this process.

How many molecules of carbon dioxide would be formed if 6.75 g of propane is burned in the following reaction?

Answers

dont mind me here for the points

How many molecules of carbon dioxide would be formed if 6.75 g of propane is burned in the following

How many moles of
Cts are needed to make
15.5 moles of CO₂? How
much O2 will be needed?
0₂
C₂Hs +50₂3CO₂ + 4H₂O

Answers

1. The number of mole of C₃H₈ needed to make 15.5 moles of CO₂ is 5.2 moles

2. The number of moles of O₂ needed is 25.8 moles

1. How do I determine the number of mole of C₃H₈ needed?

The number of mole of C₃H₈ needed can be obtained as illustrasted below:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 1 mole of C₃H₈

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 1) / 3 = 5.2 moles of C₃H₈

Thus, number of mole of C₃H₈ needed is 5.2 moles

2. How do I determine the number of mole of O₂ needed?

We can obtain the number of mole of O₂ needed as follow:

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

From the balanced equation above,

3 moles of CO₂ was obtained from 5 moles of O₂

Therefore,

15.5 moles of CO₂ will be obtain from = (15.5 × 5) / 3 = 25.8 moles of O₂

Thus, number of mole of O₂ needed is 25.8 moles

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Complete question:

How many moles of C₃H₈ are needed to make

15.5 moles of CO₂? How much O₂ will be needed?

C₃H₈ + 5O₂ -> 3CO₂ + 4H₂O

Calculate the value of ni for Hydrogen if a violet line from the Balmer series has a recorded wavelength of 410 nm.

Answers

Solution :

Given that the violet line from Balmer series having a recorded wavelength of 410 nm. As the recorded wavelength is 410 nm we know, the wavelength range of violet light is 380 nm -450 nm. So the 410 nm is corresponding to violet light wavelength.

We know, among all the series of lines spectrum of \($H_2$\) atom, only the Balmer series are in visible range. For Balmer series, the equation of wavelength associated with the e-transition of n = 2 orbit to n > 2 is

\($\frac{1}{\lambda}=R\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$\)

where, R = Rydberg constant = 109678 per cm

            λ = wavelength

Here the recorded λ = 410 nm = \($410 \times 14^{-7} \ cm$\)

∴ \($\frac{1}{410 \times 10^{-7}}=109678\left[\frac{1}{2^2}-\frac{1}{n^2}\right]$\)

\($\frac{1}{2^2}-\frac{1}{n^2}=\frac{1}{410 \times 10^{-7}\times 109678}$\)

\($\frac{1}{4}-\frac{1}{n^2}=0.222$\)

\($\frac{1}{n^2}=\frac{1}{4}-0.222$\)

\($n^2=\frac{1}{0.0276}$\)

\($n^2=36.2$\)

\($n^2 $\) ≈ 36

n = ±6

Here, n is the principle quantum number. It cannot be negative, so the value of n = 6 for hydrogen atom if the violet line from Balmer series that has a recorded wavelength of 410 nm.

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

The principal quantum number in the Balmer series transition has been given by n. The minimum transition for the Balmer series has been from the 2 energy level.

The expression for the wavelength transition can be given by:

\(\rm \dfrac{1}{\lambda}\;=\;R\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\lambda\) = Wavelength = 410 nm = 410 \(\rm \times\;10^-^7\) cm

R = Rydbreg constant = 109678/cm

\(\rm \dfrac{1}{410\;\times\;10^-^7}\;=\;109678\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm \dfrac{1}{410\;\times\;10^-^7\;\times\;109678}\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;=\;\;[\dfrac{1}{2^2}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;=\;\;[\dfrac{1}{4}\;-\;\dfrac{1}{n^2} ]\)

\(\rm 0.222\;-\;\dfrac{1}{4}\;=\;\dfrac{1}{n^2}\)

\(\rm n^2\;=\;36.2\)

n = 6

The value of n for the Hydrogen transition in the Balmer series with the wavelength 410 nm has been 6.

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Which statement correctly defines digestion

1.digestion is mixing food with Silva, which is when Mechanical digestion starts.
2.digestion is chewing food, which is a means of chemical digestion.
3.digestion is a reversible process due to mechanical digestion.
4.digestion is the process of breaking down food into smaller molecules

Answers

Answer: 4

Explanation: digestion is the process of breaking down food by mechanical and enzymatic action in the alimentary canal into substances that can be used by the body.

Answer:  

4.digestion is the process of breaking down food into smaller molecules

Explanation:

A graduated cylinder contains 50.0 ml of water. A 23.5 g piece of unknown metal is carefully dropped into the cylinder. When
the metal is completely covered with water, the water rises to the 53.4 ml mark. What is the density of the unknown piece of
metal in g/ml?

Answers

To find the density of the unknown piece of metal, we can use the formula:

Density = mass / volume.

How to find the density ?The volume of the metal can be calculated by deducting the starting water volume (50.0 ml) from the final water volume (53.4 ml) after the metal is introduced. We know the mass of the unknown metal is 23.5 g.Volume of metal = 53.4 ml - 50.0 ml = 3.4 ml.Now we can substitute the values into the density formula: Density = 23.5 g / 3.4 ml = 6.9 g/ml.Therefore, the density of the unknown piece of metal is 6.9 g/ml.

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The concentration of KBr in a solution prepared by dissolving 2.21g of KBr in 897g of water is ______ molala) 2.07 x 10^-5b) 0.0167c) 0.0186d) 0.0207e) 2.46

Answers

So, let's first remember that:

The molal concentration, m, is defined as the ratio between moles of solute (In this case, KBr) per kg of solvent (water):

We need to find the moles of solute. For this, we are going to divide the amount of solute given by the problem by the molar mass of KBr.

Now that we found moles of solute, what we need to do is to find the mass of solvent (In this case is water) in Kg. We have 897g so, to pass to Kg what we do is to divide by 1000:

Now, to find molality, we divide the moles of solute and the kilograms of solvent. Therefore, the concentration is:

So the correct answer is D.

The concentration of KBr in a solution prepared by dissolving 2.21g of KBr in 897g of water is ______
The concentration of KBr in a solution prepared by dissolving 2.21g of KBr in 897g of water is ______
The concentration of KBr in a solution prepared by dissolving 2.21g of KBr in 897g of water is ______

For the reaction

4PH3(g)↽−−⇀6H2(g)+P4(g)

the equilibrium concentrations were found to be [PH3]=0.250 M, [H2]=0.580 M, and [P4]=0.750 M.


What is the equilibrium constant for this reaction?

c=

Answers

The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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SOMEONE PLEASE HELP!!!!!!!! An element with 70 protons and a mass of 170 would be considered:
a. stable
b. radioactive
c. nonexistent

Answers

Answer:

Explanation:

An element with 70 protons and a mass of 170 would be considered radioactive.

In general, an element with an atomic number (number of protons) greater than 82 tends to be radioactive. Since the element in question has 70 protons, which is less than 82, it does not fall into the category of naturally radioactive elements. However, it is important to note that the stability of an element also depends on the balance between protons and neutrons in the nucleus. Without information about the number of neutrons in the nucleus, we cannot determine the stability of this specific element definitively.

KOH (aq) + HNO(little3) (aq) = KNO(little 3) (aq) + H20 (1)

Answers

The reaction already balanced

Further explanation  

Equalization of chemical reactions can be done using variables. Steps in equalizing the reaction equation:  

• 1. gives a coefficient on substances involved in the equation of reaction such as a, b, or c, etc.  

• 2. make an equation based on the similarity of the number of atoms where the number of atoms = coefficient × index (subscript) between reactant and product  

• 3. Select the coefficient of the substance with the most complex chemical formula equal to 1  

For gas combustion reaction which is a reaction of hydrocarbons with oxygen produces CO₂ and H₂O (water vapor). can use steps:  

Balancing C, H and the last O  

Reaction

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)

give coefficient

aKOH (aq) + bHNO₃ (aq) ⇒ KNO₃ (aq) + cH₂0 (l)

K : left = a, right = 1⇒a=1

N : left = b, right =1, b=1

H: left = a, right a+b=2c⇒1+1=2c⇒2=2c⇒c=1

KOH (aq) + HNO₃ (aq) ⇒ KNO₃ (aq) + H₂0 (l)⇒ already balanced

The value of ΔH° for the reaction below is -126 kJ. __________ kj are released when 2.00 mol of NaOH is formed in the reaction?

2 Na2O2 (s) + 2 H2O (l) → 4NaOH (s) + O2 (g)

A) 252
B) 63
C) 3.9
D) 7.8
E) -126

Answers

"63" kj are released. A further solution is provided below.

The equation is:

\(2 Na_2O_2 (s) + 2 H_2O (l) \rightarrow 4NaOH (s) + O_2 (g)\)

Value of ΔH,

-126 kJ

As we know,

4 moles of NaOH - (-126) kJ  2 moles of NaOH - X

Now,

→ \(4\times X=-126\times 2\)

→     \(4X = -252\)

→       \(X = -\frac{252}{4}\)

→            \(= -63\)

Thus the above response is correct.

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A researcher observes a reaction and gathers the data in the table below. Observations Mass decreased after reaction Energy is released during reaction New substance is formed Which piece of evidence best identifies they type of reaction as nuclear or chemical? 1. Chemical, because energy is released during the reaction. 2.Nuclear, because energy is released during the reaction. 3.Nuclear, because the mass decreased after the reaction. 4.Chemical, because a new substance is formed.

Answers

The piece of evidence that best identifies the type of reaction as nuclear or chemical is: Chemical, because a new substance is formed. Option 4

In this scenario, the observation that a new substance is formed is a key characteristic of a chemical reaction. Chemical reactions involve the rearrangement of atoms to form different substances with distinct properties. The formation of a new substance indicates a chemical change has occurred.

The other pieces of evidence listed do not necessarily point to a nuclear reaction:

Chemical, because energy is released during the reaction: Energy can be released in both nuclear and chemical reactions, so this observation alone is not sufficient to determine the type of reaction.

Nuclear, because energy is released during the reaction: While energy can be released in nuclear reactions, it is not exclusive to them. Chemical reactions can also release energy, such as in exothermic reactions.

Nuclear, because the mass decreased after the reaction: This observation suggests a change in mass, which could be indicative of a nuclear reaction. However, it is important to consider that chemical reactions can also involve changes in mass, such as the formation of gases or dissolution of a solid.

Overall, the most conclusive evidence to identify the type of reaction is the formation of a new substance, which aligns with a chemical reaction.

Option 4

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The combustion of octane, C8H18, proceeds according to the reaction shown.

2C8H18(l)+25O2(g)⟶16CO2(g)+18H2O(l)

If 354 mol of octane combusts, what volume of carbon dioxide is produced at 15.0 ∘C
and 0.995 atm?

Answers

The concept ideal gas equation is used here to determine the volume of the carbondioxide. Combustion reactions are generally highly exothermic reactions. The volume of CO₂ is

A combustion is a chemical reaction in which a fuel undergoes oxidation as a result of the reaction with an oxidizing agent which causes the release of energy in the form of heat.

15.0 °C = 288 K

The ideal gas equation is:

PV = nRT

V = nRT / P

V = 354 × 0.0821 × 288 / 0.995 = 8412.3 L

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Becca is a forensic technician analyzing the fragments of a window. She sees that there is a hole in the window, and that the outside hole is smaller than the inside hole. What might she deduce from this information?

Answers

The observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

From the observation that the hole in the window is smaller on the outside than on the inside, Becca, as a forensic technician, might deduce the following:

The hole was caused by an impact from the outside: The smaller outside hole suggests that the force that created the hole originated from the outside and exerted more pressure on the window surface facing inward.

The object causing the hole was larger on the inside: The discrepancy in hole sizes implies that the object that struck the window had a larger size or diameter on the inside, and as it penetrated the glass, it compressed or fragmented the glass, resulting in a larger hole on the inside.

The object may have passed through the window: The difference in hole sizes indicates that the object may have penetrated the window, potentially passing through to the inside. This could suggest a break-in or an incident involving the window being struck from the outside.

Overall, the observation of a smaller outside hole than inside leads Becca to infer that an impact from the outside caused the hole, with a larger object striking and passing through the window from the inside.

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