Angle c is congruent to which angles?
A. 1 and 2
B. 2 and 3
C. 3 and 4
D. 1 and 4

Answer:

It is 1024

Step-by-step explanation:

If you substitute y within the x, you will be able to simplify what the equation is (which is the first one)

No, it is not required to be accurate. The growth rates of the two functions can vary.

It's not necessary for log f(n) to equal log g(n). Depending on the equation's constants and the inputs to the two functions, the growth rates of the two functions may differ. For instance, log f(n) = 2 log n and log

g(n) = 3 log n,

which are not equal, if

f(n) = n2 and g(n) = n3.

In this instance, log f(n) is equal to (log n) and log g(n) to (log n3), indicating that the two functions grow at various rates. Likely not equal are log f(n) and log g(n) if

f(n) = n and g(n) = n2,

respectively. Log f(n) is defined as (log n) and log Therefore, the statement "log f(n) = (log g(n)" is not necessarily true.

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The point prevalence of brilliance at the end of Week 1 is 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 is 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 is 0.33 or 33%.

Using person-weeks as denominator, the incidence of brilliance over the course of the 10-week course is 0.017 or 1.7%

In epidemiology context, brilliance can be calculated through calculating point prevalence, cumulative incidence, and incidence rate. The provided data table can be used to determine the point prevalence, incidence, and incidence rate of brilliance among PHE 450 students. So, the calculations of point prevalence, cumulative incidence, and incidence rate based on the provided data are as follows:

The point prevalence of brilliance at the end of Week 1 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #8 was the only existing case of brilliance at the beginning of Week 1, so the point prevalence of brilliance at the end of Week 1 is; Point prevalence = 1 ÷ 12 = 0.08 or 8%.

The point prevalence of brilliance at the end of Week 2 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3 and Student #8 were existing cases of brilliance at the beginning of Week 2, so the point prevalence of brilliance at the end of Week 2 is; Point prevalence = 2 ÷ 12 = 0.17 or 17%.

The point prevalence of brilliance at the end of Week 3 can be calculated by the following formula; Point prevalence = Total number of existing cases at a given time ÷ Total population at that time

Student #3, #4, #6, and #8 were existing cases of brilliance at the beginning of Week 3, so the point prevalence of brilliance at the end of Week 3 is; Point prevalence = 4 ÷ 12 = 0.33 or 33%.

The incidence of brilliance can be calculated by the following formula; Incidence = Total number of new cases ÷ Total person-weeks of observation

Student #5 and Student #7 developed brilliance during the 10-week course, so the incidence of brilliance over the course of the 10-week course is; Incidence = 2 ÷ 120 = 0.017 or 1.7%.

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This is the sine model, y that represents the height above the ground of one of the blades of the windmill at any given time t.

Given that the blades of a windmill turn on an axis that is 30 feet from the ground. The blades are 10 feet long and complete 2 rotations every minute. Let's find the sine model, y. Let's begin by writing the sine function where y represents the height above the ground of one of the blades of the windmill at any given time t and the constant 30 represents the height of the axis. Let's take A to be the amplitude of the function since the blades oscillate between a minimum height of 20 feet above the ground and a maximum height of 40 feet above the ground. Let's also take T to be the period of the function since the blades complete two full rotations in one minute or 2π radians in one period.T = 1 minute = 2π radians per period∴ T = 2π/1 = 2πA = (40 − 30)/2 = 5

To obtain the vertical shift, let's find the average of the minimum and maximum heights since the sine function oscillates above and below the horizontal axis:y = Asin(ωt) + b Where A is the amplitudeω is the angular frequency b is the vertical displacement of the graph

The vertical shift, b = (20 + 40)/2 = 30Since the blades are completing two full rotations in one minute, we can convert this to radians per second as shown:2 rotations = 4π radians2 rotations per minute = 4π radians per minute4π radians per minute = 4π/60 radians per secondω = 4π/60 radians per second

Substituting the values into the sine function, we obtain:y = 5sin[(4π/60)t] + 30Explanation:To summarize the given problem, the blades of a windmill turn on an axis that is 30 feet from the ground. The blades are 10 feet long and complete 2 rotations every minute. We are to write a sine model, y. From the above explanation, we have found the amplitude (A), period (T), angular frequency (ω), and vertical displacement (b) of the sine function. We then substituted these values into the general form of the sine function to obtain the specific sine model:y = 5sin[(4π/60)t] + 30

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Answer:

The estimate of the standard deviation of the sampling distribution of sample proportions for this process is approximately 0.1265.

Given that the machine total defectives are #1=23, #2=15, #3=29 and #4=13

To find the estimate of the standard deviation of the sampling distribution of sample proportions for this process Formula used:

The formula for the standard deviation of the sampling distribution of sample proportions is given by the expression as, SD = √(pq/n)

Where, p = the proportion of successes

q = the proportion of failures

n = the sample size

Substitute the values in the formula

SD = √(pq/n)p

= 80/100

= 0.8 (as there are 80 defectives out of 100 items produced.)

q = 20/100 = 0.2 (as there are 20 non-defectives out of 100 items produced.)

n = Sample size = 100

Thus, SD = √(pq/n)SD

= √(0.8*0.2/100)SD

= √(0.016)SD

= 0.1265 (approximately)

Therefore, the estimate of the standard deviation of the sampling distribution of sample proportions for this process is approximately 0.1265.

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12 is the ending value of sum.

Ending value of sum=?

x = scnr.nextInt();

sum = 0;

for (i = 0; i < x; ++i) {

currValue = scnr.nextInt();

sum += currValue;

}

Input provided to the code 2 5 7 3.

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Answer:

\(4(s + 3)\)

\((s + 3) + (s + 3) + (s + 3) + (s + 3)\)

Answer:

f(g(x)) = 2x - 5

Step-by-step explanation:

If f(x) = 2x + 1 and g(x) = x - 3

Then to find the value of f(g(x)) we write x - 3 instead of x in the function f(x)

f(g(x)) = 2 (x-3) + 1 ➡ f(g(x)) = 2x -5

Answer:

\(\huge \boxed{f(g(x))=2x+-5}\)

Step-by-step explanation:

The functions are given,

\(f(x)=2x+1\)

\(g(x)=x-3\)

To find \(f(g(x))\), the input for the function f of x will be g of x.

\(f(g(x))=2(x-3)+1\)

Expand brackets.

\(f(g(x))=2x-6+1\)

Combine like terms.

\(f(g(x))=2x-5\)

Answer:

No

Step-by-step explanation:

The slopes of perpendicular lines must always be the negative reciprocal of each other. If one slope is negative, for the other to be perpendicular to it, it must be positive, and vise versa.

Answer:

No

Step-by-step explanation:

Interesting question. Subtle.

The formula for two lines to be perpendicular is m1 * m1 = -1 That means that two lines cannot be minus -- only 1 of them can be. The reason is that if both were minus when multiplied together would give a positive result -- not minus one. For example, suppose you have

y = x + 2  

y = 2x + 3.

These 2 lines will cross and they are not parallel, but neither are they perpendicular. I'm not going to solve this to find out where they cross -- that's not what you are asking.

Now suppose you have two other lines

y = - 2x + 3

y = 1/2 x + 1

These two lines should be perpendicular

-2 * 1/2 =  - 1 which is the condition of perpendicular.

Separate graphs have been uploaded to help you understand.

Answer:

$702.53

Step-by-step explanation:

178.74

36,52+18.92+25.93=81.37

178.74-81.37=97.37

300+100+205.16=605.16

605.16+97.37=702.53

The final balance is 702.53 dollars.

Answer: y = 2(x + 2)² - 5

Step-by-step explanation:

          We are going to use the completing the square method to transform this quadratic equation from standard form to vertex form.

Given:

     y = 2x² + 8x + 3

Factor the 2 out of the first two terms:

     y = 2(x² + 4x) + 3

Add and subtract \(\frac{b}{2} ^2\):

     y = 2(x² + 4x + 4 - 4) + 3

Distribute the 2 into -4 and combine with the 3:

     y = 2(x² + 4x + 4) - 5

Factor (x² + 4x + 4):

     y = 2(x + 2)² - 5

At an 8 percent discount rate, the present value of the cash flows is approximately $1,722,536.39. At a 16 percent discount rate, the present value is approximately $1,072,736.15.

To calculate the present value of the stream of cash flows, we need to discount each cash flow to its present value using the appropriate discount rate.
At an 8 percent discount rate:
The first payment of $150,000 is made immediately and does not need to be discounted. Its present value is $150,000.
For the remaining 19 payments of $150,000 each, we can use the formula for the present value of an ordinary annuity:

PV = PMT * [1 - (1 + r)^(-n)] / r
Where:

PV = Present value
PMT = Payment amount per period ($150,000)
r = Discount rate per period (8% or 0.08)
n = Number of periods (19)

Using this formula:
PV = $150,000 * [1 - (1 + 0.08)^(-19)] / 0.08
PV ≈ $1,722,536.39
Therefore, the present value of the cash flows at an 8 percent discount rate is approximately $1,722,536.39.

At a 16 percent discount rate, we repeat the same calculations:

PV = $150,000 * [1 - (1 + 0.16)^(-19)] / 0.16
PV ≈ $1,072,736.15
Therefore, the present value of the cash flows at a 16 percent discount rate is approximately $1,072,736.15.

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If 8% is the appropriate discount rate, the present value of this stream of cash flows is approximately $1,375,320.

To calculate the present value of a stream of cash flows, we can use the formula for the present value of an annuity. The formula is:

\(PV = C * [(1 - (1 + r)^(-n)) / r]\)

Where:

PV = Present value

C = Cash flow per period

r = Discount rate per period

n = Number of periods

In this case, the cash flow per period (C) is $150,000, the discount rate (r) is 8% (or 0.08), and the number of periods (n) is 19.

Let's calculate the present value using these values:

PV = $150,000 * \([(1 - (1 + 0.08)^(-19)) / 0.08]\)

PV ≈ $150,000 * [(1 - 0.2665) / 0.08]

PV ≈ $150,000 * (0.7335 / 0.08)

PV ≈ $150,000 * 9.1688

PV ≈ $1,375,320

Therefore, if 8% is the appropriate discount rate, the present value of this stream of cash flows is approximately $1,375,320.

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Answer:

14

Step-by-step explanation:

One fourth is 6 and one with is 4. So 4+6=10.24-10=14.

Answer:

14

Step-by-step explanation:

If you have 24 chickens, a quarter of 24 is 6. Then, a sixth of 24 is 4. 6+4=10. 24-10=14. So, he would have 14 chickens left.

Answer:

0.08

Step-by-step explanation:

5 ^-2 * cube root of 8

first of all, let us solve 5^-2

using the law of indices;

a^-2 = 1 / a ^2

following this law, we have;

5^-2 = 1 / 5^2

we know that 5^2 = 25

therefore,

5^-2 = 1 / 25

now, let is continue by solving the cube root of 8

now, there are three ways of solving this;

we could just simply think of any number that when multiplies itself three times times, it gives 8, or we could just simply use a calculator

regardless of what we use, we have to end up with the number 2 as the answer

leading is to our conclusion.

from all our solution, we have reduced our question to;

1 / 25 ( which is 5^-2) * 2 ( which is the cube root of 8 )

= 1 / 25 * 2 / 1

note that 2 is the same as 2 / 1. We put it like this when we want to carry out an operation on an integer ( e.g. 2) and and a fraction ( e.g. 1 / 25 )

so,

1 / 25 * 2 / 1 =

2 / 25 ( the two multiplies the 1 in 1 / 25 and the 25 multiplies the 1 in 2 / 1)

leaving our answer in decimal, we have;

0.08

hope this helps,

thanks!!!

Answer:

( x+4) (x+9)

Step-by-step explanation:

x^2 + 13x + 36

What 2 numbers multiply to 36 and add to 13

4*9 = 36

4+9 = 13

( x+4) (x+9)

Answer:

( x + 4)(x + 9)

That's your answer!!

Answer:

66

Step-by-step explanation:

Replace t with 9 in the equation.

\(28(1.1)^9\)

Simplify.

\(28(2.358)\)

\(66.023\)

Rounded, it equals 66

A mixture contains 200 oz of juice that contains 60% tomato juice and 100 oz vegetable juice that contains 20% tomato juice. The concentration tomato juice in the resulting mixture is 40%.

Percentage is used to represent a fraction of a hundred.

Let:

w1 = weight of tomato juice in juice 1

w2 = weight of tomato juice in vegetable juice

Hence,

w1 = 60% x 200 oz = 120 oz

w2 = 20% x 100 z = 20 oz

Total weight of tomato juice = 100 + 20 = 120 oz

Total weight of the mixture = 200 oz + 100 oz = 300 oz.

Hence, the concentration of the tomato juice in the final mixture is:

concentration = total weight of tomato juice/ total weight of mixture

                       = 120/300

                       = 2/5 = 40%

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The gravitational potential energy of the vacationers will decrease as they approach the end of the pier.

As the vacationers approach the end of the pier, their gravitational potential energy will decrease.

Gravitational potential energy is the energy an object possesses due to its position in a gravitational field. It depends on the height of the object and the acceleration due to gravity.

In this scenario, as the vacationers walk out on the horizontal pier, their height above the ground remains constant. Since the height does not change, the gravitational potential energy also remains constant.

However, as they approach the end of the pier, their distance from the center of the Earth decreases. As a result, the gravitational potential energy decreases because it is directly proportional to the distance from the center of the Earth.

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Answer:

∠ O = 61°, ∠ N = 119°

Step-by-step explanation:

In a parallelogram

Consecutive angles are supplementary

Opposite angles are congruent, thus

x + 2x - 3 = 180

3x - 3 = 180 ( add 3 to both sides )

3x = 183 ( divide both sides by 3 )

x = 61°

Thus

∠ O = ∠ M = x = 61°

∠ N = ∠ P = 2x - 3 = 2(61) - 3 = 122 - 3 = 119°

Answer:

17/15

Step-by-step explanation:

2 5/6 x 2/5

convert 2 5/6 into improper fraction

17/6 x 2/5

cancel out the greatest common factor which would be the 6 and the 2

17/3 x 1/5

multiply straight across

17/15

could also be written as 1 2/15 or 1.13

The algebraic representation that shows a dilation that is an enlargement is (5/2 x,5/2 y). (Option D)

A dilation is a type of transformation that changes the size of the shape or object.  It refers to a process of changing an object’s size by decreasing or increasing its dimensions by a scaling factor. A dilation produces an image that has the same shape as the original image but is a different size.

A dilation that results in a larger image is called an enlargement while a dilation that generates a smaller image is called a reduction. A dilation is described using the scale factor and the center of the dilation (which is a fixed point in the plane).

For a scale factor > 1, the image is an enlargement; for a scale factor < 1 and  > 0, the image is a reduction; and for a scale factor = 1, the figure and the image are congruent. Hence, for a point (x,y), algebraic representation that shows a dilation that is an enlargement is (5/2 x,5/2 y) as the scale factor is greater than 1. For the remaining options, the scale factor is between 0 and 1, hence they are reduction.

Note: The question is incomplete. The complete question probably is: Which of the following algebraic representation shows a dilation that is an enlargement? A) (1/3 x,1/3 y) B) (0.1x, 0.1y) C) (5/6 x,5/6 y) D) (5/2 x,5/2 y)

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Answer:

58g

Step-by-step explanation:

I'm assuming the mass of the Bottle is 8g for this answer.

1mL = 1g

So 50mL = 50g

8g + 50g = 58g

Therefore, the mass of the bottle + water inside of it is 58g

The value of x in the hexagon is 17.

A hexagon is a polygon with six sides. The sum of angles in a hexagon is 720 degrees.

Therefore, x can be found in the hexagon as follows:

we have to sum the whole angles to get x.

110 + 8x - 1 + 5x + 36 + 116 7x + 19 + 6x - 2 + 110 = 720

combine like terms

110 + 116 - 2 + 36 - 1 + 19 + 8x + 5x + 7x + 6x  = 720

278 + 26x = 720

subtract 278 from both sides of the equation

278 + 26x = 720

278 - 278 + 26x = 720 - 278

26x = 442

divide both sides by 26

x = 442 / 26

x = 17

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Answer:

if ur asking for the square root of it :

square root of √121 is 11

√121

√11×11

√11²

11

hope it helps

Step-by-step explanation:

Answer:

The answer is C

Step-by-step explanation:

Answer:

try c

Step-by-step explanation:

The ratio of the distance traveled by the tip of the hour hand to the distance traveled by the tip of the minute hand from noon to 3 p.m. is (12π)/(16π), which simplifies to 3/4.

To find the ratio of the distance traveled by the tip of the hour hand to the distance traveled by the tip of the minute hand from noon to 3 p.m., we need to consider their respective speeds.

The hour hand takes 12 hours to complete a full revolution around the clock, while the minute hand takes 60 minutes to complete a full revolution.

From noon to 3 p.m., the hour hand moves a quarter of a circle, which corresponds to 3 hours on the clock. The distance traveled by the tip of the hour hand is given by the circumference of a circle with a radius of 6 inches, which is 2π × 6 = 12π inches.

During the same period, the minute hand moves a three-quarter circle, corresponding to 180 minutes. The distance traveled by the tip of the minute hand is the circumference of a circle with a radius of 8 inches, which is 2π × 8 = 16π inches.

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For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

To determine the value of n₀ for which Algorithm A is better than Algorithm B when B uses n√n operations, we need to find the point at which the number of operations for Algorithm A is less than the number of operations for Algorithm B.

Algorithm A: 10n log n operations

Algorithm B: n√n operations

Let's set up the inequality and solve for n₀:

10n log n < n√n

Dividing both sides by n gives:

10 log n < √n

Squaring both sides to eliminate the square root gives:

100 (log n)² < n

To solve this inequality, we can use trial and error or graph the functions to find the intersection point. After calculating, we find that n₀ is approximately 459. Therefore, For n ≥ 459, Algorithm A is better than Algorithm B when B uses n√n operations.

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R-1.3: For \($n \geq 14$\), Algorithm A is better than Algorithm B when B uses \($n^2$\) operations.

R-1.4: Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

R-1.3:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n^2$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n^2$\)

\($10 \log n < n$\)

\($\log n < \frac{n}{10}$\)

To solve this inequality, we can plot the graphs of \($y = \log n$\) and \($y = \frac{n}{10}$\) and find the point of intersection.

By observing the graphs, we can see that the two functions intersect at \($n \approx 14$\). Therefore, for \($n \geq 14$\), Algorithm A is better than Algorithm B.

R-1.4:

Algorithm A: \($10n \log n$\) operations

Algorithm B: \($n\sqrt{n}$\) operations

We want to determine the value of \($n_0$\) such that Algorithm A is better than Algorithm B for \($n \geq n_0$\).

We need to compare the growth rates:

\($10n \log n < n\sqrt{n}$\)

\($10 \log n < \sqrt{n}$\)

\($(10 \log n)^2 < n$\)

\($100 \log^2 n < n$\)

To solve this inequality, we can use numerical methods or make an approximation. By observing the inequality, we can see that the left-hand side \($(100 \log^2 n)$\) grows much slower than the right-hand side \($(n)$\) for large values of \($n$\).

Therefore, we can approximate that:

\($100 \log^2 n < n$\)

For large values of \($n$\), the left-hand side is negligible compared to the right-hand side. Hence, for \($n \geq 1$\), Algorithm A is better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

So, for R-1.4, the value of \($n_0$\) is 1, meaning Algorithm A is always better than Algorithm B when B uses \($n\sqrt{n}$\) operations.

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Therefore, the center of pressure on the triangular sail is approximately (1.2, 0.9).

The center of pressure on a boat's sail that occupies a region R in the plane is given by

x = ∬R xydA/∬R ydA` and y = ∬R x²ydA/∬R xydA`.

To calculate the center of pressure on a triangular sail with vertices (0,0),(3,2) and (0,7) we will use the following formulas:

x = ∬R xydA/∬R ydA

y = ∬R x²ydA/∬R xydA

Remember that in this case, the region R in the plane is the triangular sail with vertices (0,0), (3,2), and (0,7).

Hence, the equations for x-bar and y-bar are:x-bar = ∬R xydA/∬R ydA= ∫(x=0 to x=3) ∫(y=0 to y=(7x/3))

=  xy dy dx/ ∫(x=0 to x=3) ∫(y=0 to y=(7x/3)) y dy dx= 42/35= 1.2 units (approx)

And,y-bar = ∬R x²ydA/∬R xydA= ∫(x=0 to x=3) ∫(y=0 to y=(7x/3)) x²y dy dx/ ∫(x=0 to x=3) ∫(y=0 to y=(7x/3)) xy dy dx= 63/70= 0.9 units (approx)

Therefore, the center of pressure on the triangular sail is approximately (1.2, 0.9).

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