Anna says that 5 1/3 is not a rational number because it’s not in the fraction form of a/b. Do you agree? plsss help

The percentage of returns that were greater than 30 percent is 16% and the percentage of returns that were below -24 percent is 2.5%..

The historical returns on a portfolio had an average return of 12 percent and a standard deviation of 18 percent. We can use the Empirical Rule to answer the questions about the percentage of returns that were greater than 30 percent and below -24 percent. The Empirical Rule states that for a bell-shaped distribution:

- 68% of the data falls within 1 standard deviation of the mean
- 95% of the data falls within 2 standard deviations of the mean
- 99.7% of the data falls within 3 standard deviations of the mean

a. What percentage of returns were greater than 30 percent?

30 percent is 1 standard deviation above the mean (12 percent + 18 percent = 30 percent). Therefore, according to the Empirical Rule, 68% of the data falls within 1 standard deviation of the mean, or between -6 percent and 30 percent.

This means that 32% of the data falls outside of this range, with 16% above 30 percent and 16% below -6 percent. So the percentage of returns that were greater than 30 percent is 16%.

b. What percentage of returns were below -24 percent?

-24 percent is 2 standard deviations below the mean (12 percent - 2*18 percent = -24 percent). Therefore, according to the Empirical Rule, 95% of the data falls within 2 standard deviations of the mean, or between -24 percent and 48 percent.

This means that 5% of the data falls outside of this range, with 2.5% above 48 percent and 2.5% below -24 percent. So the percentage of returns that were below -24 percent is 2.5%.

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Answer:

15%

Step-by-step explanation:

\(\frac{7225-8500}{7225}=-15\%\)

Answer:

D {(5,6), (8,6), (9,6)}

The International Society for Automation (ISA) promotes that we must treat fairly and respectfully all colleagues and co-workers, while also "recognizing each of their unique contributions and individual capabilities full of strengths and weaknesses".Therefore option A is correct.

The International Society for Automation (ISA) promotes that we must treat fairly and respectfully all colleagues and co-workers, while also recognizing each of their unique contributions and individual capabilities full of strengths and weaknesses.

ISA emphasizes constructive and supportive feedback to help aid in the development of employees, rather than judging their quality and/or quantity of work critically and rashly.

Providing financial support or other incentives may be helpful in boosting motivation, but ultimately, treating colleagues fairly and respectfully is key to fostering a positive work environment.

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The International Society for Automation (ISA) promotes that we must treat fairly and respectfully all colleagues and co-workers, while also "recognizing each of their unique contributions and individual capabilities full of strengths and weaknesses".Therefore option A is correct.

The International Society for Automation (ISA) promotes that we must treat fairly and respectfully all colleagues and co-workers, while also recognizing each of their unique contributions and individual capabilities full of strengths and weaknesses.

ISA emphasizes constructive and supportive feedback to help aid in the development of employees, rather than judging their quality and/or quantity of work critically and rashly.

Providing financial support or other incentives may be helpful in boosting motivation, but ultimately, treating colleagues fairly and respectfully is key to fostering a positive work environment.

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If cosine of x degrees equals three-fifths, the value of b is 7.

What is cosine ?

In mathematics, the trigonometric functions (also called circular functions, angle functions or goniometric functions) are functions of an angle. They relate the angles of a triangle to the lengths of its sides. The most common trigonometric functions are sine, cosine, and tangent. The reciprocal functions are cosecant, secant, and cotangent.

In this case, we are given that cos(x) = 3/5. From this, we can use the inverse cosine function (arccos) to find the value of x in degrees. However, this alone is not enough to determine the value of b.

In the given triangle LNM, we know that angle M measures 90 degrees and angle L measures x degrees. We also know that side LM measures 3b units and LN measures 20 units.

Using the Pythagorean theorem, we know that the length of MN, which is the hypotenuse, can be found by:

MN^2 = LM^2 + LN^2

We also know that

cos(x) = LM / MN

Therefore, we have:

3/5 = (3b) / (sqrt(3b^2 + 20^2))

b = 7

So , If cosine of x degrees equals three-fifths, the value of b is 7.

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Answer:

y = 9x - 5

Step-by-step explanation:

Slope Intercept Form:  y = mx + b

( m = slope and b = y-intercept form )

In a simple regression model, the unexplained variation in the response variable is determined by summing the squares of errors. This method, known as residual sum of squares (RSS), quantifies the discrepancy between the observed values and the predicted values by the regression model.

In a simple regression model, the goal is to find a line that best fits the relationship between a single predictor variable (X) and a response variable (Y). However, due to various factors and sources of variability, the observed values of the response variable may not perfectly align with the predicted values based on the regression line.

The errors, or residuals, are the differences between the observed values and the predicted values. To quantify the unexplained variation, the errors are squared to eliminate negative values and emphasize larger deviations. These squared errors are then summed up, resulting in the residual sum of squares (RSS).

By calculating the RSS, one can assess the amount of unexplained variation or "error" in the regression model. A smaller RSS indicates that the model provides a better fit to the data, as it suggests less unexplained variation. On the other hand, a larger RSS implies a less accurate fit, with more unexplained variation in the model.

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Given, radius of the earth is 6.36 × 10^6 m and its mass is 5.98 × 10^24 kg.

Applying formula of weight, we have:

W = mg where m = 10 kg and g is the acceleration due to gravity.

To calculate acceleration due to gravity (g),

formula is: g = GM/R²

where G is the gravitational constant= 6.67 × 10^-11 Nm²/kg², M is the mass of the earth = 5.98 × 10^24 kg, R is the radius of the earth= 6.36 × 10^6 m.

Now putting these values in the formula, we have:

g = GM/R²= 6.67 × 10^-11 × 5.98 × 10^24/ (6.36 × 10^6)²g = 9.81 m/s²

Therefore,Weight of the object can be calculated as;

W = mg = 10 × 9.81W = 98.1 N

(a) Using formula [2.10]:

Formula [2.10] is given by;

W = mgh/ R²

Where, h = height at which object is placed above the earth's surface.

Since the object is on the surface of the earth, h = 0.

Therefore,

W = mgh/ R²= (10 × 9.81 × 0)/ (6.36 × 10^6)²W = 0 N

(b) Using formula [2.12]:

Formula [2.12] is given by;

W = m (GM/ (R+h))²

Here, h = 0, therefore;

W = m (GM/R)²

= 10 × (6.67 × 10^-11 × 5.98 × 10^24/ 6.36 × 10^6)²

W = 98.05 N (Approximately)

Therefore, the weight of an object whose mass is 10 kg by using a) [2.10] is 0 N, and by using b) [2.12] is 98.05 N (Approximately).

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Answer:



Step-by-step explanation:

To check whether the given function is linear or not just simply check the degree of variables ie. of x and y.

here, in option A, C, E both x and y have degree as 1 so they are linear functions.

Whereas in option B, D, F either degree is 2 or 3 hence not a linear function.

14. B, D, F

---These functions all have x's with exponents. A linear function's x will only have an exponent of 1 (x^1). These 3 functions have exponents of 2 or 3.

Scatter Plot:

The scatter plot shows a strong/negative association between the age of a motorcycle and the sale price of the motorcycle because as the age of a motorcycle increases, the sale price of the motorcycle decreases.

Hope this helps!

Vertex: (1/5, -5), Axis of Symmetry: x = 1/5, Transformations: vertical stretch by 10, horizontal shift 1/5 right, and vertical shift 7 down.

Let's analyze the given function, Y = |10x - 2| - 7, and compare it to the parent function, Y = |x|.

Vertex: The vertex of the given function can be found by determining the x-coordinate that will make the expression inside the absolute value equal to zero. In this case, 10x - 2 = 0. Solving for x, we get x = 1/5. The corresponding y-coordinate is found by substituting x back into the function: Y = |10(1/5) - 2| - 7, which simplifies to Y = |-2| - 7 = 2 - 7 = -5. Thus, the vertex is at the point (1/5, -5).

Axis of Symmetry: Since the given function is an absolute value function, the axis of symmetry is vertical and goes through the x-coordinate of the vertex. In this case, the axis of symmetry is x = 1/5.

Transformation: Comparing the given function to the parent function, there are a few transformations applied:
1. Vertical stretch by a factor of 10 (due to the "10x" term)
2. Horizontal shift of 1/5 units to the right (due to the "-2" term inside the absolute value)
3. Vertical shift of 7 units down (due to the "-7" term outside the absolute value)

So, to summarize:
- Vertex: (1/5, -5)
- Axis of Symmetry: x = 1/5
- Transformations: Vertical stretch by 10, horizontal shift 1/5 right, and vertical shift 7 down.

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Complete Question

Compare the function with the parent function. Without graphing, what are the vertex, axis of symmetry, and transformation of the given function? Y=|10x-2|-7

Step-by-step explanation:

Area of circle= Πr²

Πr² = 132² m

r²=132²/Π m

=5546.23m

r =√5546.23

=74.473 m

The choice where y is a nonlinear function of x is option C: x y x + = −.

In this equation, the relationship between x and y is not a simple direct proportion or linear function. The presence of the exponent on x indicates a nonlinear relationship.

As x increases or decreases, the effect on y is not constant or proportional. Instead, it involves a more complex operation, in this case, the squaring of x and then subtracting it. This results in a curved relationship between x and y, which is characteristic of a nonlinear function.

Nonlinear functions can have various shapes and patterns, including curves, exponential growth or decay, or periodic behavior.

These functions do not exhibit a constant rate of change and cannot be represented by a straight line on a graph.

In contrast, linear functions have a constant rate of change and can be represented by a straight line.

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Answer:

Step-by-step explanation:

No.  Only if the inequality symbol < were replaced with =, ≤ or ≥, would the boundary line be a solid line.

False. A trigonometric equation with an infinite number of solutions is not necessarily an identity.

A trigonometric identity is an equation that holds true for all values of the variables involved. It is a fundamental property of trigonometric functions. On the other hand, a trigonometric equation with an infinite number of solutions means that there are multiple values of the variables that satisfy the equation, but it doesn't imply that the equation is true for all values.

For example, the equation sin(x) = 0 has an infinite number of solutions, which are x = 0, π, 2π, 3π, and so on. However, this equation is not an identity because it is not true for all values of x. It is only true when x is an integer multiple of π.

Therefore, it is important to distinguish between trigonometric identities that hold true for all values and trigonometric equations that have an infinite number of solutions but may not be true for all values.

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The statement "Increasing N increases the real effect of the independent variable" is false.

Increasing N, which presumably refers to the sample size or number of observations, does not necessarily increase the real effect of the independent variable. The real effect of the independent variable is determined by the nature of the relationship between the independent and dependent variables, not solely by the sample size.

In statistical analysis, increasing the sample size can lead to more precise and reliable estimates of the effect of the independent variable. With a larger sample size, the estimates of the effect tend to have smaller standard errors and narrower confidence intervals, which indicates more precision.

However, the actual effect of the independent variable remains unchanged.

The real effect of the independent variable is determined by the true relationship between the variables in the population. It is possible to have a strong and meaningful effect of the independent variable even with a small sample size if the relationship is robust.

Conversely, increasing the sample size does not necessarily make a weak or non-existent effect of the independent variable stronger or more significant.

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Therefore solution to this question is slope at (0,-1) is negative at (-2,2) is negative at (1,-3) is negative & (0,4) is also negative.

A slope field, which displays the slope of a differential equation along specific vertical and horizontal axes of the x-y plane, can be used to estimate the tangent slope at a particular point on a curve, where the curve is one possible solution to the differential equation.

Here,

For figure 1 slope field=

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\)

For figure 2 slope field=

\(\frac{dy}{dx} = xy-3\\\)

For figure 1 a solution passing through the point (0,-1)

therefore,

slope=

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\\\frac{dy}{dx}=\frac{-17(0)-2(-1)}{-1}=-2\)

so slope comes out to be negative

For figure 1 a solution passing through the point (-2,2)

\(\frac{dy}{dx}=\frac{-17x-2y}{y}\\\frac{dy}{dx}=\frac{-17(-2)-2(2)}{-1}=-30\)

so slope comes out to be negative

For the slope field in figure 2. a solution passing through the point (1.-3)

\(\frac{dy}{dx} = xy-3\\\\\frac{dy}{dx}=(1*-3)-3=-6\)

so slope comes out to be negative

\(\frac{dy}{dx} = xy-3\\\\\frac{dy}{dx}=(0*4)-3=-3\)

so slope comes out to be negative.

Therefore solution to this question is slope at (0,-1) is negative at (-2,2) is negative at (1,-3) is negative & (0,4) is also negative.

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Answer: No

Step-by-step explanation: because 12 out of 24 is 1/2 while 9/20 is a bit off of one half therefore no

Answer:

Option B

Step-by-step explanation:

Laws of indices:

1. \(a^{n}\) = \(\frac{1}{a^{-n}}\)  OR  \(a^{-n}\) = \(\frac{1}{a^{n}}\)

2. \(a^{n}\) × \(a^{m}\) = \(a^{n + m}\)

3. \(\frac{a^{n}}{a^{m}}\) = \(a^{n-m}\)

\(\frac{6}{3}\) × \(\frac{x^{2}}{x^{6}}\)

Method 1:

= \(2\) × \(\frac{1}{x^{6}.x^{-2}}\)

= \(\frac{2}{x^{6+(-2)}}\)

=\(\frac{2}{x^{6-2}}\)

= \(\frac{2}{x^{4}}\)

Method 2:

= \(2\) × \(x^{2-6}\)

= \(2\) \(x^{-4}\)

= \(\frac{2}{x^{4}}\)

∴Option B

Answer:

volume of cylinder: \(\sf 396\pi \ m^3\)

Explanation:

given:

solve:

\(\hookrightarrow \sf \pi r^2h\)

\(\hookrightarrow \ \sf \pi (6)^2(11)\)

exact:

\(\hookrightarrow \ \sf 396 \pi\)

in nearest tenth:

\(\hookrightarrow \ \sf 1244.1 \ m^3\)

Answer:

a. (-4,8)

Step-by-step explanation:

the two lines intersect at this point

Answer:

1/4

Step-by-step explanation:

there is 3 black marbles and 3+4+5=12 total marbles. 3/12=1/4

The first and second polygons are exactly the same, the only difference is that the second is bigger! If we look right the first polygon is 4 cm and the second is triple which means that we will have to triple the area of ​​the First polygon to discover the area of ​​the second polygon!

if the first polygon is 4 cm long and the second 12 cm means that the second polygon has three times the area of ​​the first polygon!

\((4 cm.3=12 cm)\\A-10 cm^{2}.3=30 cm^{2}\)

the second polygon has \(30 cm^{2}\)  of area

\(A=30 cm^{2}\)

With a speed of 6.67 ft/sec is the length of her shadow moving when she is 25 ft from the base of the pole.

Let H = the height of the pole.

h = the height of the woman.

x = the length of the woman's shadow.

s = the distance from the pole to the woman.

By similar triangles,  H/h = (s + x)/x  or  Hx = h(s + x).

Differentiating, H dx/dt = h(ds/dt + dx/dt)

15 dx/dt = 6(4+dx/dt)

15 dx/dt = 24 +6 dx/dt

15 dx/dt -6 dx/dt = 24

9 dx/dt = 24

dx/dt = 24/9 = 2.67 ft/sec for how fast her shadow was lengthening.

The speed of the length of her shadow would be this speed added to her traveling speed: 2.67 + 4 = 6.67 ft/sec.

Therefore, 6.67 ft/sec is the required answer.

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Answer:

10:25 and 100:2500

Step-by-step explanation:

just multiply both number by the same number

The value of the probability of choosing a green lollipop and a purple lollipop is, 8 / 45

We have to given that;

One bag contains 3 red lollipops and 2 green lollipops.

And, The other bag contains four purple lollipops and five blue lollipops.

Hence, The probability of choosing a green lollipop is,

P₁ = 2 / 5

And, The probability of choosing a purple lollipop is,

P₂ = 4 / 9

Thus, The value of the probability of choosing a green lollipop and a purple lollipop is,

P = P₁ ×  P₂

P = 2/5 × 4/9

P = 8/45

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Answer:

c)

Step-by-step explanation:

\(\frac{1}{2}\)(12*g) - h = \(\frac{1}{2}\)(12 * \(\frac{1}{4}\)) - \(\frac{1}{2}\) = 1/2 * 3 - 1/2 = 3/2 - 1/2 = 1

Milo needs to cover 12 miles in 48.6 minutes, as the percentage.

What is percentage?

A percentage that represents a tenth of a quantity. One percent, denoted by the symbol 1%, is equal to one-hundredth of something; hence, 100 percent denotes the full thing, and 200 percent designates twice the amount specified. A portion per hundred is what the percentage denotes. The percentage refers to one in a hundred. The % sign is used to denote it.

Milo can run 12 miles in 60 minutes.

She needs to reduce the time by 19%

So we have to calculate the 19%of 60

= 19/100* 60

=57/5 minutes

= 11.4

So the time he needs to achieve will be 60-11.4 = 48.6 minutes.

Hence, he needs to cover 12 miles in 48.6 minutes.

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Answer:

0.2 or 1/5 as fraction form

Step-by-step explanation:

Hope this helps?!

:)

Hi!

Given:

\(\frac{4}{5} *\frac{1}{4}\)

First, multiply the numerators.

\(4*1=4\)

Second, multiply the denominators.

\(5*4=20\)

Now we have:

\(\frac{4}{20}\)

Last, simplify. 20 and 4 can both be divided by 4.

\(\frac{4/4}{20/4} =\frac{1}{5}\)

Your answer is \(\frac{1}{5}\)

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