Answer the question below

Answer The Question Below

Answers

Answer 1

Answer:

the the right because opposites attract to each other


Related Questions

For questions 1 - 4 complete the representations for the four patterns below. Provide the mathematical
model. Complete the data table using the A value provided. Insert a graph using the data table you filled
out (you may use desmos ). (40pts)
Pattern with 1. Horizontal Line
2. Linear
3. Quadratic
4. Inverse
constant (A-value) A = 100
(Proportional)
A = 100
A= 100, B = 0
A = 100
Mathematical
Model
y =
y=
y =
y =
Y у
y у
Y у
у
Data Table Form
х
1
2
5
10
х
1
2
5
10
х
1
2
5
10
х
1
2
5
10
Graph Form

Answers

Answer:

Explanation:

1

2

3

The third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation.

What is a Linear Function?

A linear function is a function whose graph represents a straight line when the points are plotted, and also can be modelled by the equation, y = mx + b.

b is the value of y when x = 0 (y-intercept)

m is the slope or unit rate.

Thus, the third table shown in the diagram below can be modelled with the equation, y = x + 2, therefore, it represents a linear equation (see attachment). The last table has a constant slope of -3, hence it represents a linear function.

Table of functions

From the given table, we need to determine which of the table is a linear table. To determine that, we must check which of the table has a constant rate of change

Looking at the last table;

Slope = -4-(-2)/2-1

Slope = -4+1/1

Slope = -3

Since the last table has a constant slope of -3, hence it represents a linear function.

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At time t = 0, a static object at position x = 0 starts to move such that its position x(t) satisfies the equation
d^2x/dt^2 + dx/dt = te^-t
Using Laplace Transforms, determine the function x(t)

Answers

Based on the above illustration, the required function is `x(t) = t²e⁻ᵗ / 2`.

Given: The equation is, `d²x/dt² + dx/dt = te⁻ᵗ`.

Required:

Find `x(t)` using Laplace Transforms.

Let us apply the Laplace transform to both sides of the equation.

d²x/dt² → s² X(s) - s x(0) - x'(0)dx/dt → s X(s) - x(0)x(0) is 0 as the object starts from rest.

Putting the given value, `d²x/dt² + dx/dt = te⁻ᵗ` in the Laplace transform of the equation, we get (s² X(s) - s x(0) - x'(0)) + (s X(s) - x(0)) = 1 / (s + 1)²

On solving the above equation for `X(s)`, we get `X(s) = 1 / (s + 1)³`

On taking the inverse Laplace transform, we get, `x(t) = t²e⁻ᵗ / 2`

Hence, the required function is `x(t) = t²e⁻ᵗ / 2`.

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Calculate the magnitude of the gravitational force exerted by Venus on a 65 kg human standing on the surface of Venus. (The mass of Venus is 4.9x1024 kg and its radius is 6.1x106 m.) N Calculate the magnitude of the gravitational force exerted by the human on Venus. N For comparison, calculate the approximate magnitude of the gravitational force of this human on a similar human who is standing 3.5 meters away. N What approximations or simplifying assumptions must you make in these calculations? (Note: Some of these choices are false because they are wrong physics!) Treat the humans as though they were points or uniform-density spheres. Ignore the effects of the Sun, which alters the gravitational force that one object exerts on another. Treat Venus as though it were spherically symmetric. Use the same gravitational constant in (a) and (b) despite its dependence on the size of the masses.

Answers

To calculate the magnitude of the gravitational force exerted by Venus on a 65 kg human standing on the surface of Venus, we use Newton's Law of Universal Gravitation and it will be 6.3 x 10-6 N

This states that the gravitational force (F) between two masses (m1 and m2) separated by a distance (r) is given by the equation:

F = G * (m1 * m2) / r2

Where G is the gravitational constant, which is 6.67 x 10-11 Nm2/kg2. Using this equation and the given values, we have:

F = 6.67 x 10-11 * (4.9 x 1024 * 65) / (6.1 x 106)2

F = 3.3 x 105 N

To calculate the magnitude of the gravitational force exerted by the human on Venus, we use the same equation as before, but with the masses of the human and Venus reversed. This gives:

F = 6.67 x 10-11 * (65 * 4.9 x 1024) / (6.1 x 106)2

F = 4.0 x 10-6 N

For comparison, the approximate magnitude of the gravitational force of the human on a similar human who is standing 3.5 meters away can be calculated using the same equation. The masses of both humans are the same, so we have:

F = 6.67 x 10-11 * (65 * 65) / (3.5)2

F = 6.3 x 10-6 N

To calculate the gravitational force in both cases, we had to make the following approximations or simplifying assumptions:

Treat the humans as though they were points or uniform-density spheres.

Ignore the effects of the Sun, which alters the gravitational force that one object exerts on another

And Treat Venus as though it were spherically symmetric.

We also had to use the same gravitational constant in (a) and (b) despite its dependence on the size of the masses.

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A sample of gas is moved from a 5 liter container to a 2 liter container.

a.) What happens to the pressure of the gas with this change in volume (Assume there is no change in temperature)?

b.) Why does this change happen?

Answers

Answer:

Pressure would increase

Explanation:

This is because pressure is calculated by the number of times particles hit the container that they are stored it.

More collisions would lead to an increase in pressure.

So when you move a sample of has from a 5 litre container to a 2 litre container, pressure would increase as there is less space for particles to move around. This would mean that there would be more particles colliding with the container, and so an increase in pressure.

Hope this helps!

The change in pressure occurs because the same number of gas molecules are confined to a smaller volume, leading to more frequent collisions with the container walls and an increase in pressure.

a.) When a sample of gas is moved from a 5-liter container to a 2-liter container while keeping the temperature constant, the pressure of the gas will increase.

The relationship between pressure (P), volume (V), and temperature (T) for a given amount of gas is described by the ideal gas law:

PV=nRT

Where:

P is the pressure of the gas

V is the volume of the gas

n is the amount of gas (usually measured in moles)

R is the ideal gas constant

T is the temperature in Kelvin

Since the amount of gas (n) and the temperature (T) are constant in this scenario, we can simplify the equation to:

PV=constant

This means that as the volume (V) decreases, the pressure (P) must increase to keep the product of pressure and volume constant. In other words, as you reduce the volume of the container, the gas molecules will collide more frequently with the walls of the container, resulting in a higher pressure.

b.) This change in pressure happens due to the nature of gas molecules and their behavior. Gas molecules are in constant motion, moving in all directions. When the volume of the container is reduced, the same number of gas molecules now have less space to move around. As a result, they collide more frequently with the walls of the container.

These collisions exert a force on the walls, and pressure is defined as the force per unit area. With more frequent collisions, the force on the walls increases, and therefore the pressure increases. The gas molecules are essentially exerting more pressure per unit area because they have less space to spread out.

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A number of texas counties introduced electronic voting in the 2002 midterm election because:__________

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Texas introduced Electronic voting in the 2002 midterm election as a way to modernize the state's voting process, increase the accuracy of the results, and improve the security of the voting process.

A number of Texas counties introduced electronic voting in the 2002 midterm election because of several reasons.

Firstly, the introduction of electronic voting was an attempt to modernize the state's voting process. The older method of paper-based voting was viewed as slow and inefficient, with many people waiting in line for hours to cast their votes. In contrast, electronic voting promised to speed up the process and reduce waiting times, allowing more people to participate in the election.

Secondly, the use of electronic voting was also intended to increase the accuracy of the election results. The older paper-based system was prone to human error, with mistakes made in vote counting and tallying. By using electronic voting machines, the state hoped to eliminate such errors and produce more accurate results.

Finally, electronic voting was also viewed as a more secure method of voting. The machines were designed to prevent fraud and tampering, with several security features in place to prevent hacking or other unauthorized access.

The introduction of electronic voting in Texas was a significant step forward for the state, which had long been plagued by issues with its voting process. In previous elections, voters had often been forced to wait in line for hours to cast their votes, with many people giving up and leaving before they could vote. The use of electronic voting promised to reduce waiting times and make the process more efficient, ensuring that more people would be able to participate in the election.

Additionally, the introduction of electronic voting machines was also intended to increase the accuracy of the election results. In the past, the paper-based voting system had been prone to errors, with mistakes made in vote counting and tallying. By using electronic machines, the state hoped to eliminate such errors and produce more accurate results.

Finally, the use of electronic voting machines was also intended to increase the security of the voting process. With several security features in place to prevent fraud and tampering, the state hoped to ensure that the election results were fair and accurate.

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13. mass a (10 kg) is travelling west at 8 m/s and collides inelastically with mass b (30 kg) which is travelling east at 4 m/s. a) find the final velocity of both masses after the collision b) calculate the change in momentum of mass a. c) calculate the change in momentum of mass b d) what is the impulse mass a experiences? e) if the collision lasts for 0.06 seconds, find the net force on mass a.

Answers

a) The final velocity of mass A is 2 m/s and the final velocity of mass B is -6 m/s.b) The change in momentum of mass A is equal to 8 - 2 = 6 kg m/s.c) The change in momentum of mass B is equal to -12 - 6 = -18 kg m/s.d) The impulse experienced by mass A is 6 kg m/s.e) The net force on mass A is equal to 6 kg m/s / 0.06 s = 100 N.

After the collision, the momentum of the two-mass system must be conserved. The momentum of the system before the collision is equal to the momentum of the system after the collision. Therefore, the momentum of the two-mass system before the collision is equal to the momentum of the two-mass system after the collision.

Before the collision, the momentum of mass A is 8 kg m/s (10 kg times 8 m/s). The momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). Therefore, the total momentum of the two-mass system before the collision is equal to 8 - 12 = -4 kg m/s.

After the collision, the momentum of the two-mass system must also equal -4 kg m/s. Since mass A has a mass of 10 kg and mass B has a mass of 30 kg, we can set up the following equation:

10vA + 30vB = -4 kg m/s

Solving this equation for vB gives us the following expression:

vB = (-4 kg m/s - 10vA) / 30

We can substitute the initial velocity of mass A, 8 m/s, into this equation to get the final velocity of mass B:

vB = (-4 kg m/s - 10(8 m/s)) / 30

vB = -6 m/s

Since momentum must be conserved, the final velocity of mass A must be equal to the total momentum of the system (minus the momentum of mass B) divided by the mass of mass A. This gives us the following expression:

vA = (-4 kg m/s + 30(-6 m/s)) / 10

vA = 2 m/s

Therefore, the final velocity of mass A is 2 m/s and the final velocity of mass B is -6 m/s.

The change in momentum of mass A is equal to the initial momentum of mass A minus the final momentum of mass A.

The initial momentum of mass A before the collision is 8 kg m/s (10 kg times 8 m/s). The final momentum of mass A after the collision is 2 kg m/s (10 kg times 2 m/s). Therefore, the change in momentum of mass A is equal to 8 - 2 = 6 kg m/s.

The change in momentum of mass B is equal to the initial momentum of mass B minus the final momentum of mass B.

The initial momentum of mass B before the collision is -12 kg m/s (30 kg times -4 m/s). The final momentum of mass B after the collision is 6 kg m/s (30 kg times -6 m/s). Therefore, the change in momentum of mass B is equal to -12 - 6 = -18 kg m/s.

The impulse experienced by mass A is equal to the change in momentum of mass A divided by the time during which that change occurs. Since the change in momentum of mass A is 6 kg m/s and the time of the collision is likely instantaneous, the impulse experienced by mass A is 6 kg m/s.

The net force on mass A is equal to the impulse experienced by mass A divided by the time of the collision. Since the impulse experienced by mass A is 6 kg m/s and the time of the collision is 0.06 seconds, the net force on mass A is equal to 6 kg m/s / 0.06 s = 100 N.

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schematically plot the total cross section of u-238 as a function of neutron energies. if the spectrum has certain features on energy dependence, explain the cause of such feature.

Answers

To schematically plot the total cross section of U-238 as a function of neutron energies, we can use the information provided by the ENDF/B-VII.1 nuclear data library. This library contains the neutron cross-section data for various isotopes, including U-238.

The total cross section of U-238 represents the probability of a neutron interacting with a U-238 nucleus, leading to various outcomes such as scattering or absorption. The cross section typically depends on the energy of the incident neutron.

When plotting the total cross section of U-238 as a function of neutron energies, we usually observe several features. One notable feature is the presence of resonances. Resonances occur when the energy of the incident neutron matches the energy of a specific excited state in the U-238 nucleus.

These resonances can lead to significant increases in the cross section, creating peaks in the plot. The resonance peaks are caused by the increased probability of neutron-nucleus interactions at those specific energies. Resonances are typically observed in the MeV energy range.

Another feature that can be seen in the plot is the general trend of decreasing cross section as the neutron energy increases. This decrease occurs due to the decrease in the probability of neutron-nucleus interactions at higher energies.

In conclusion, the schematic plot of the total cross section of U-238 as a function of neutron energies displays resonances as peaks and a general decrease in cross section with increasing energy. These features arise from the specific excited states of the U-238 nucleus and the decreasing probability of interactions at higher energies.

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The vector u results when a vector u-v is added to the vector v. True or false?

Answers

It is false that the vector u results when a vector u-v is added to the vector v.

The basic definition of the vector it that it is any physical quantity that has a magnitude as well as direction and it follows vector laws of addition. i.e. Parallelogram law of vector addition or triangle law of vector addition.

Now, it is stated that the vector u results when a vector u-v is added to the vector v, this statement may or may not be true because we cannot be certain about it. Because we do not know the direction of the two vectors u and v. This is why we conclude that the statement is false.

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Halley’s comet orbits the Sun in an elliptical path as shown.During its orbit, it moves faster when it is closer to the Sun than when it is further away.What can you conclude about the comet’s potential energy as it approaches the Sun? Explain.

Answers

Given what we know, we can confirm that as Halley's comet moves closer to the sun, we can expect its potential energy to be near its maximum.

How do we know this?

We can conclude that its potential energy will increase as it comes closer to the sun, and will reach its maximum at the closest point to the sun. This is because the potential energy of an object is directly proportional to the force of gravity acting on that object. As Halley's comet approaches the sun, the sun's gravitational pull on the comet is stronger, and thus, its potential energy increases.

Therefore, given the relationship between gravity and potential energy, we can confirm that s Halley's comet moves closer to the sun, we can expect its potential energy to increase and be near its maximum.

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PLS HELP I OLY HAVE 2 MINS TO ANSWER THISSSS!!!!! 25PTS

Information on a graph between plotted points may not be accurate.

True
False

Answers

Answer:

I'M SO SORRY I SAW THIS TOO LATE :<

Explanation:

im pretty sure it's falseeee, information would probably be accurate

which characteristics cannot be inherited?
1) color of animal's hair
2) Hight of a plant
3) knowledge of facts
4) shape of a face

Answers

Answer:

3, knowledge of facts............

Transistors are 3-terminal semiconductor devices which can act as switches or
amplifiers. An NP-transistor can be switched "ON" by:
A. Applying large negative potential to the collector and small positive potential to
the base
(B. Applying small positive potential to the collector and large positive potential to
the base.
(C. Applying small positive potential to the emitter and large negative potential to
the base. D. Applying small negative potential to the emitter and large negative potential to
the base.

Answers

In an NP-transistor (NPN transistor), the base is typically made of p-type semiconductor material, while the emitter and collector are made of n-type semiconductor material.

To switch the transistor "ON" and allow current to flow through it, the base-emitter junction needs to be forward-biased. This means that the base terminal should have a higher positive potential than the emitter terminal.

By applying a small positive potential to the base (relative to the emitter) and a large NP-transistor to the collector, the base-emitter junction is forward-biased, allowing current to flow through the transistor and switching it "ON".The correct answer is (A) Applying large negative potential to the collector and small positive potential to the base.

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What is the converse of the statement "No pilots are mechanics"?
a. No mechanics are pilots.
b. Some mechanics are pilots.
c. All pilots are mechanics.
d. None of these

Answers

The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

The converse of a statement switches the subject and the predicate and negates both. In the original statement, the subject is "pilots" and the predicate is "mechanics."

The original statement states that there is no overlap between pilots and mechanics. In the converse statement, the subject becomes "mechanics" and the predicate becomes "pilots," and it still states that there is no overlap between the two groups.

Therefore, The converse of the statement "No pilots are mechanics" is No mechanics are pilots.

Hence, the correct option is A.

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Complete the passage to describe how electrons are represented in electron dot diagrams.
The maximum number of dots an electron dot diagram can have is The maximum number of dots drawn on
a side of a chemical symbol in an electron dot diagram is
ctivity

Answers

Answer:

The maximum number of dots an electron dot diagram can have is  

✔ eight

The maximum number of dots drawn on a side of a chemical symbol in an electron dot diagram is  

✔ two

Answer:

A: eight

B: two

Explanation:

I just did the assignment and got it correct.

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A container with a mass of 5 kg is lifted to a height of 8 m. How much work is done by the gravitational force

Answers

Answer:

work done=392J

Explanation:

work done =Mgh

DATA

M=5kg

g= 9.8

h=8m

W=Mgh

W=5*9.8*8

W=392J

The work done by the gravitational force is equal to -400 J.

What is gravitational force?

The gravitational force can be described as a force that attracts a body towards the center of the earth or any physical object that has mass. Every object has mass and exerts a gravitational pull on another object with mass.

Given, the mass of the container, m = 5 Kg

The height from the ground level, h = 8 m

The work done can be calculated by using the below-mentioned formula:

\(W = m\times g\times h\)

Where g is the gravitational acceleration.

As the container is lifted in the upward direction therefore the value of the g will be negative.

Substitute the values of m, g, and h in the above formula:

W =  5 × (-10) × 8

W = -400 J.

The negative sign shows that the work is done against the gravitational force.

Therefore, the work done by the gravitational force is equal to -400 J.

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If you were told an atom was an ion, you would know the atom must have a...
Neutral Charge
Charge
Negative Charge
Positive Charge
---- Thank you !

Answers

An ion has a negative charge

Answer:

option (b) charge

Explanation:

Leon is testing an unknown
substance and observes that the
substance retains its volume and
shape when placed in different
containers. Which phase of matter
is the substance most likely in?

Answers

The observation that a substance retains its volume and shape when placed in different containers indicates that the substance has a fixed volume and shape, which is a characteristic of a solid.

Solids have a fixed shape and volume because the particles that make up a solid are packed tightly together and held in a fixed position by intermolecular forces. As a result, solids maintain their shape and volume even when placed in different containers or when subject to external forces.

In contrast, liquids do not have a fixed shape, but rather take on the shape of their container. They do, however, have a fixed volume. This means that a liquid would change its shape to match the shape of its container, but its volume would remain constant.

Gases, on the other hand, do not have a fixed shape or volume. They take on the shape and volume of their container and are highly compressible.

Based on the observation that the substance retains its volume and shape when placed in different containers, it is most likely in a solid state. However, further testing may be needed to confirm this, as some liquids and even some gases can also exhibit a degree of fixed volume and shape under certain conditions.

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Which best describes the importance of mitosis to living organisms? genetic variation and growth growth and development development and sexual reproduction sexual reproduction and genetic variation

Answers

Answer:

b.

Explanation:

Mitosis is important for growth and development  of living organisms.

The major importance of mitosis is growth and development. The correct option is B.

What is mitosis?

Mitosis is the method by which a cell replicates as well as then segregates its chromosomes, and generates two identical nuclei in order to divide.

Mitosis is basically followed by the equal division of the cell's contents into two daughter cells with identical genomes.

Mitosis occurs in the following stages:

The chromosomes shorten a s well as thicken during the phase called as prophase.Metaphase - Chromosomes align in the equator of the cell. Chromatids separate at the centromere as well as move to opposite poles during anaphase. Telophase - The generation of two nuclei after nuclear envelopes reform around each chromosome group.

One cell divides once during mitosis to form two identical cells. Mitosis is primarily responsible for cell growth and replacement.

Thus, the correct option is B.

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An airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again midflight (at its fastest) 18km/min. 90 min passed between the 2 velocity measurements. What is the acceleration of the airplane?
720 km/min2
0.3 km/min2
2 km/min2
0.9 km/min2

Answers

The acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

How to calculate acceleration?

The acceleration of a moving substance can be calculated by dividing the change in velocity by the time taken as follows:

a = (v - u)/t

Where;

a = accelerationv = final velocity (km/min)u = initial velocity (km/min)t = time (minutes)

According to this question, an airplane was flying from Cincinnati to Denver. The velocity of an airplane was measured shortly after take off at 10km/min. The velocity was measured again mid-flight to be 18km/min.

a = (18km/min - 10km/min)/90min

a = 8km/min ÷ 90min

a = 0.09km/min²

Therefore, acceleration of an airplane that had an initial velocity of 10km/min and a final velocity of 18km/min covered over 90min is 0.09km/min².

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consider a copper rod that is 3.14 meters long, 2 cm in diameter, and has an electrical resistivity of 2x10-6 ohm-cm. what is the electrical resistance of the rod?

Answers

Resistance is denoted by the Greek symbol omega (), which also stands for the ohm, the unit of measurement. The formula states that R Equals L / A.

What does a metal's electrical resistance mean?

The difference in electric potential increases with increasing current. In contrast, a high electric resistance will result in a low current. Alternatively put, a metal with low resistance is a superior conductor. Electrons in the metal are slowed down if there is an electric resistance.

How is resistance determined?

By applying Ohm's Law, you can get the total resistance if you know the complete current and voltage through the entire circuit: R = One against / I. A parallel circuit, for instance, has a supply of 9 volts and a combined power of 3 amps. Total resistance (RT) is equal to 9 volts / 3 amps, or 3.

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what objectie lens provides the least total magnification

Answers

The objective lens provides the least total magnification is (c). Scan

Most compound microscopes include interchangeable objective lenses with various magnification strengths. Typical examples of these are 4x, 10x, 40x, and 100x objective lenses. This lens, when used with the eyepiece lens, will have the least magnification.

The lowest magnification power of any objective lens is that of a checking objective lens. 4x is a typical magnification for scanning objectives when combined with the 10x eyepiece lens' magnification power. Magnification is determined by dividing the image height by the object height. This enlargement is quantified by a mathematical quantity called "magnification."

The complete questions is,

Which objective lens provides the least total magnification?

A. Oil immersion B. Low power C. Scan D. High power

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Please Help!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!!

An electron is in motion at 4.0 × 10^6 m/s horizontally when it enters a region of space between two parallel plates, as shown, starting at the negative plate. The electron deflects downwards and strikes the bottom plate. The magnitude of the electric field between the plates is 4.0 x 10^2 N/C and separation between the charged plates is 2.0 cm.


Determine the horizontal distance travelled by the electron when it hits the plate.

Answers

Answer:

Given that

speed u=4*10^6 m/s

electric field E=4*10^3 N/c

distance b/w the plates d=2 cm

basing on the concept of the electrostatices

now we find the acceleration b/w the plates  to find the horizontal distance traveled by the electron when it hits the plate.

acceleration a=qE/m=\(1.6*10^{-19}*4*10^3/9.1*10^{-31} =0.7*10^{15}\)=\(7*10^{14}\) m/s

now we find the horizontal distance traveled by electrons hit the plates

horizontal distance

\(X=u[2y/a]^{1/2}\)

=\(4*10^6[2*2*10^{-2}/7*10^{14}]^{1/2}\)

=\(3*10^{-2}\)= 3 cm

A volume of 200.0 cm3 of water at a temperature of 4°C is in a container with a 1000-cm3 capacity. The container and its contents are heated to 95°C. What is the final volume of water in the container? Disregard any expansion of the container itself. βwater = 210 x 10-6 (°C)-1.

Answers

The final volume of water in the container after increasing the temperature is 203.8 m³.

From the given,

The initial volume of water (Vο) = 200 cm³

Initial temperature = 4°C = 4+273 = 277K

Final temperature = 95°C = 273+95 = 368 K

Volume expansion co-efficient = 210×10⁻⁶(°C)⁻¹

Final volume =?

β = 1/Vο (ΔV/ΔT),  β represents the volume expansion coefficient, ΔV change in volume, ΔT is the change in temperature, and Vο is the initial volume.

ΔV = β×Vο×ΔT

     = 210×10⁻⁶×200×(368-277)

    =  210×10⁻⁶×200×91

ΔV = 3.83 m³

ΔV = final volume - initial volume

final volume = ΔV + 200

                    = 3.82 +200

                    = 203.82 m³

Final volume = 203.82 m³.

Thus, the final volume of the water is 203.82 m³.

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Why are thire only large impact craters on Venus?
A. There are only large impact craters on Venus because only large meteors and asteroids survive their fall through the planet's thick and corrosive atmosphere.
B. There are only large impact craters on Venus because geological activity erodes impact craters over time.
C. There are only large impact craters on Venus because most smaller asteroids and meteors have been cleared out of the inner solar system over the last few billion years.
D. There are only large impact craters on Venus because the weather on the planet erodes impact craters over time.
E. There are actually impact craters of all sizes on the surface of Venus.

Answers

Venus has large impact craters due to the absence of erosive forces and the survival of only the largest meteors and asteroids through its thick atmosphere.

Option (A) is correct.

Venus, known as the sister planet of Earth, is characterized by its thick, corrosive atmosphere and extreme temperatures. Its surface lacks water and volcanic activity, and is instead marked by numerous large impact craters. This is due to the absence of erosive forces, like water, which would have gradually eroded the craters over billions of years. The craters formed on Venus as a result of asteroid and comet impacts over the past 4.6 billion years. However, the impact process on Venus differs from that on Earth. Venus' thick atmosphere burns up most smaller meteorites and asteroids upon entry, allowing only the largest ones to survive their descent. Consequently, only the large impact craters remain visible on the planet's surface today. Therefore, option (A) is correct. In summary, Venus bears only large impact craters as a consequence of the survival of substantial meteors and asteroids through its thick and corrosive atmosphere.

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How much time will it take for a bug to travel 7 meters across the floor if it is traveling at 2 m/s? (t = d/t)

Answers

It will take the bug a time of 3.5 seconds to travel 7 meters across a floor at a speed of 2 m / s

v = d / t

v = Velocity

d = Distance

t = Time

v = 2 m / s

d = 7 m

t = d / v

t = 7 / 2

t = 3.5 s

Velocity is the rate of change of distance at a given amount of time. It is denoted by v.

Therefore, it will take the bug 3.5 seconds

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if the net torque on an object is positive, in which direction does the object begin to rotate?

Answers

A related right-hand rule relates the rotational direction to the torque direction. Your fingers will curl in the rotational direction if you point your thumb in the direction of the torque.

Positive torques cause counterclockwise rotation while negative torques cause clockwise rotation. Because T1 is smaller than T2, the net torque would point in a clockwise direction. The system would start to accelerate clockwise if it were initially at rest. The torques in Example 2 are not in equilibrium because there is a net torque. The rotational equivalent of force is torque. So an object will rotate with an angular acceleration in response to a net torque.

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3*. An electron starts with an exit velocity v0 = 1.6 · 106 m/s and enters a uniform
electric field between the plates in the picture below. Assume that the field between the plates is uniform and that the electron enters the field just in between
the plates.

a) Determine the magnitude of the electric field if the electron just misses the top plate.
b) If the electrons had been replaced by a proton and the other input data are unchanged, had it then went to the wooden plates?
c) Is it reasonable to ignore gravity for the particles? Motivate.

3*. An electron starts with an exit velocity v0 = 1.6 106 m/s and enters a uniformelectric field between

Answers

The magnitude of the electric field if the electron just misses the top plate is 364 N/C.

Time taken by electron is given as

t = x / Vo

t = distance / speed

where, Vo = velocity = 1.6 × 10⁶ m/s

x = distance = 2 cm = 0.02 m

t = 0.02 / 1.6 × 10⁶ m/s = 1.25 × 10⁻⁸ s

acceleration of electron is given as :

a = (2 × y )/ t²

y = vertical distance

a = ( 2 × 0.01 / 2) /  (1.25 × 10⁻⁸ )²

a = 6.4 × 10¹³ m/s²

the electrical field expression is given as :

E = ( ma ) / q

E = (

E = 9.1 × 10⁻³¹ × 6.4 × 10¹³ ) / 1.6 × 10⁻¹⁹

E = 364 N /C

thus,  The magnitude of the electric field if the electron just misses the top plate is 364 N/C.

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Charge of uniform density 4.0 nC/m is distributed along the
x axis from x = 2.0 m to x = +3.0
m. What is the magnitude of the electric field at the
origin?

Answers

The magnitude of the electric field at the origin due to the charge distribution along the x-axis is zero, resulting in a net cancellation of the electric field contributions.

To find the magnitude of the electric field at the origin, we can use the principle of superposition. We divide the charge distribution into small segments, each with a length Δx and a charge ΔQ.

Given:

Charge density (ρ) = 4.0 nC/m

Range of distribution: x = 2.0 m to x = 3.0 m

We can calculate the total charge (Q) within this range:

Q = ∫ρ dx = ∫4.0 nC/m dx (from x = 2.0 m to x = 3.0 m)

Q = 4.0 nC/m * (3.0 m - 2.0 m)

Q = 4.0 nC

Next, we calculate the electric field contribution from each segment at the origin:

dE = k * (ΔQ / r²), where k is the Coulomb's constant, ΔQ is the charge of the segment, and r is the distance from the segment to the origin.

Since the charge distribution is uniform, the electric field contributions from each segment will have the same magnitude and cancel out in the x-direction due to symmetry.

Therefore, the net electric field at the origin will be zero.

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The electric force between two or more charged objects depends on which of the following quantities?

a. charge and distance between the charged objects
b. quantity of charges and their masses
c. charge and mass of charged objects
d. mass and distance between the charged objects

Answers

The electric force between two or more charged objects depends on the charge and the distance between the charged objects

What is Coulomb's law?

Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies

therefore F= kq1q2/r²

where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²

Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.

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A ladybug is resting on a 0.5 meter radius turntable that is rotating with a period of 2 seconds. The ladybug is halfway between the center and the edge. Use this information for the questions in this section.
What is the tangential distance travelled by the ladybug in one revolution?
What is the tangential velocity of the ladybug?
What is the angular distance traveled by the ladybug after one revolution?
What is the angular velocity of the ladybug?

Answers

(a) The tangential distance travelled by the ladybug is 1.57 m.

(b) The tangential velocity of the ladybug is 0.785 m/s.

(c) The angular distance traveled by the ladybug after one revolution is  0.5π radians.

(d) The angular velocity of the ladybug is 3.14 rad/s.

What is tangential distance travelled?

The tangential distance travelled by the ladybug is calculated as follows;

d = 0.5 ( 2πr )

d = ( πr )

d = π x 0.5 m = 1.57 m

The tangential velocity of the ladybug is calculated as follows;

v = d / t

where;

d is tangential distance

v = ( 1.57 m ) / ( 2 s )

v = 0.785 m/s

The angular distance traveled after after one revolution is calculated as follows;

2πr = 1 rev

2π x ( 0.25) = 1 rev

1 rev = 0.5π radians

The angular velocity of the ladybug is calculated as follows;

v = ωr

ω = v/r

ω = 0.785 m/s / 0.25 m

ω = 3.14 rad/s

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