APEX PLEASE HELP
To increase the electricity supply in the country, a government needs to build
a new power plant. Which of the following is a cost associated with the use
of nuclear power that should be factored into its decision?
A. Nuclear power produces radioactive waste.
B. Nuclear power does not depend on wind.
C. Nuclear power does not contribute to climate change.
D. Nuclear power can be produced both day and night.

The momentum of the blobs after the collision of a 1 kg blob of putty moving at 10 m/s with another 1 kg stationary blob will be 5 m/s.

The term "completely inelastic collision" is used to describe every time two masses cling together after colliding. Any inelastic collision will result in the internal energy of the objects being transformed into kinetic energy. Because of this, even though the system's energy is conserved (no outside forces are at action), its internal energy is changing in an unknowable and unpredictable fashion. This implies that the concept of energy conservation in inelastic collisions is absolutely meaningless to us. However, the conserved quantity that we can monitor is momentum.

Initial momentum is expressed as p = m1v1 + m2v2,

where, I denotes vector quantities.

v2 = 0  (because the second blob is at rest).

As a result, p=m1v1, |p|=m1|v1|=1*10= 10 kg*m/s,

The total amount of momentum is conserved in a closed system. The end momentum is 10 kg*m/s and is therefore also directed in the same direction as the beginning momentum.

The combined mass is now M=m1+m2= 1+1 = 2 kg due to the fact that two blobs are now clumped together. As a result, p = mv= 10 =2v; from this, v= 10/2 = 5 m/s, headed in the same direction as the first blob's starting velocity.

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1) The force acting on the object during the time interval 0-3 seconds is 1/3 N.

2) The force acting on the object during the time interval 6-10 seconds is -0.5 N.

3) There is no time interval in which no force acts on the object.

(i) Force acting on the object in time interval 0-3 seconds. Force acting on the object is equal to the product of its mass and acceleration, i.e.,F = ma.

In the given velocity-time graph, the acceleration of the object can be determined by determining the slope of the velocity-time graph from 0 to 3 seconds.

Slope = (change in velocity) / (change in time)= (20-0) / (3-0) = 20/3 m/s^2

Acceleration, a = slope= 20/3 m/s^2

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × 20/3= 1/3 N.

Therefore, the force acting on the object during the time interval 0-3 seconds is 1/3 N.

(ii) Force acting on the object in time interval 6-10 seconds. Similar to the first question, the force acting on the object in time interval 6-10 seconds can be determined by determining the acceleration of the object during this time interval.

The slope of the velocity-time graph from 6 seconds to 10 seconds can be determined as follows:

Slope = (change in velocity) / (change in time)= (-20-20) / (10-6) = -40/4= -10 m/s^2 (negative sign indicates that the object is decelerating)

Mass of the object, m = 50 g = 0.05 kg

∴ Force acting on the object, F = ma= 0.05 × (-10)= -0.5 N.

Therefore, the force acting on the object during the time interval 6-10 seconds is -0.5 N.

(iii) Time interval in which no force acts on the object. There is no time interval in which no force acts on the object. This is because, as per Newton's first law of motion, an object will continue to remain in a state of rest or uniform motion along a straight line unless acted upon by an external unbalanced force.In other words, if the object is moving with a constant velocity, there must be a force acting on the object to maintain its motion.

Therefore, there is no time interval in which no force acts on the object.

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Answer:

C. FEMA

Explanation:

Community Emergency Response team, known as CERT, constitutes a team of volunteers in the United States who do so to provide emergency responses to disasters e.g fire outbreak, search and rescue etc.

This set of volunteers in the CERT program are trained for these emergency situations by a local management agency such as the Federal Emergency Management Agency (FEMA). FEMA provides classroom and hands-on training needed to become a CERT volunteer.

Based on Newton's first  and second law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Newton's first law of motion first law of motion states that a body at rest or uniform motion in a straight line will continue in that path unless acted upon by an external force.

Newton's first law of motion is also called law of inertia because it depends on mass of the object.

An object with a greater mass will require greater force to be stopped or get moving.

Based on Newton's first law of motion most people would find it less painful to catch a flying baseball than a bowling ball flying at the same speed as the baseball because the mass of the baseball is smaller and will require smaller force to be stopped.

Also according to Newton's second law of motion, the force applied to an object is proportional to the product of mass and acceleration of the object. Thus, a baseball with smaller mass will require smaller force to be stopped.

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The initial velocity of the train  is 12.56 m/s.

The initial velocity of the train can be determined by using the first kinematic equation as shown below;

v = u + at

u = v - at

where;

u = 30.56 - (36 x 0.5)

u = 12.56 m/s

Thus, the initial velocity of the train  is 12.56 m/s.

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Accelerating objects are changing their velocity. Velocity is often thought of as an object's speed with a direction. Thus, objects which are accelerating are either changing their speed or changing their direction. They are either speeding up, slowing down or changing directions. Changing the velocity in any one of these three ways would be an example of an accelerated motion.

A ) The horizontal distance from the beetle, the archerfish should fire if it is to hit its target in the least time = 1.19 m

B ) The time beetle have to react = 0.93 s

T = ( \(u_{y}\) + √ \(u_{y}\)² - 2 g H ) / g

T = Total time taken

g = Acceleration due to gravity

H = Height above the ground

\(u_{y}\) = Y-component of initial velocity

u = 2 m / s

θ = 50°

H = 3 cm

\(u_{y}\) = u sin θ

\(u_{y}\) = 2 * sin 50°

\(u_{y}\) = 1.54 m / s

T = ( 1.54 + √ 1.54² - ( 2 * 9.8 * 3 ) ) / 9.8

T = ( 1.54 + √ 56.42 ) / 9.8

T = 9.1 / 9.8

T = 0.93 s

R = \(u_{x}\) T

\(u_{x}\) = u cos θ

\(u_{x}\) = 2 * cos 50°

\(u_{x}\) = 1.28 m / s

R = 1.28 * 0.93

R = 1.19 m

Therefore,

A ) The horizontal distance from the beetle, the archerfish should fire if it is to hit its target in the least time = 1.19 m

B ) The time beetle have to react = 0.93 s

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The young's modulus in a cantilever will be 3.92 x 10¹⁰ N/m².

Young's modulus (E) is a material property that indicates how easily it can stretch and deform and is defined as the ratio of tensile stress () to tensile strain (). Where stress denotes the amount of force applied per unit area ( = F/A) and strain denotes the extension per unit length

Given that the length is 1m which is suspended by a load of 150g. The depression is found to be 4cm. The thickness of the beam is 5mm and the breath is 3cm.

The young's modulus will be calculated by the formula below,

Y = (4gl³) / (bd³) x ( M / y )

Y = ( 4 x 9.81 x 1³ x 0.150 ) / ( 0.03 x 0.005³ x 0.04 )

Y = 3.92 x 10¹⁰ N/m².

Therefore, young's modulus will be 3.92 x 10¹⁰ N/m².

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The free body diagram of the squirrel motion, the weight of the squirrel is acting downwards while the air resistance is acting upwards.

The given parameters;

At a constant velocity downwards, the vertical acceleration is zero.

The downward force on the squirrel is calculated as follows;

W = mg - ma

W = m(g - a)

W = m(g - 0)

W = mg

W = 5 x 9.8

W = 49 N

The air resistance on the squirrel which is acting upwards is calculated as;

n = ma + mg

n = m(a + g)

n = m(0 + g)

n = mg

n = 5 x 9.8

n = 49 N

The free body diagram is presented below;

                                   ↑ n

                                   Ο

                                   ↓ W

Thus, in the free body diagram of the squirrel motion, the weight of the squirrel is acting downwards while the air resistance is acting upwards.

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a) The average density of the block can be calculated using the formula for density.Since the mass of the block is 1.80 N and the volume is 2.0 × 10∧5 \(m^{3}\), the average density is 0.9 kg/\(m^{3}\).

Mass is a measure of the amount of matter contained in an object. It is a fundamental physical property that is commonly used to measure the size of objects. Mass is usually measured in grams (g) or kilograms (kg) but can also be measured in other units such as ounces, pounds and tons. Mass is different from weight, which is a measure of the force of gravity on an object.

b) The normal force the floor of the vessel exerts on the submerged body can be calculated using the formula for buoyancy. In this case, the normal force is equal to 1000 kg/\(m^{3}\) × 2.0 × 10∧5 \(m^{3}\)× 9.81 m/\(s^{3}\), which is equal to 1.962× 10∧8 N.

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Answer:

The number of hailstones striking the window per unit time is:

n = 580 hailstones / 41 s = 14.1463 hailstones/s

The mass of each hailstone is 7 g = 0.007 kg, and its speed is 6.7 m/s. The kinetic energy of each hailstone is:

K = (1/2) * m * v^2 = (1/2) * 0.007 kg * (6.7 m/s)^2 = 0.167 N*m

The angle of incidence is 31°, so the angle between the hailstones and the normal to the window is 59°. The average force on the window is the rate of change of momentum of the hailstones. The momentum of each hailstone before the collision is:

p1 = m * v * cos(59°) * (-i) + m * v * sin(59°) * j

where i and j are the unit vectors in the x- and y-directions, respectively. The negative sign in front of the i-vector indicates that the hailstone is moving to the left (in the negative x-direction).

The momentum of each hailstone after the collision is:

p2 = m * v * cos(59°) * i + m * v * sin(59°) * j

The change in momentum of each hailstone is:

Δp = p2 - p1 = 2 * m * v * cos(59°) * i

The rate of change of momentum (i.e., the force) is:

F = n * Δp / Δt

where Δt is the time for each hailstone to strike the window. This time is equal to the width of the window divided by the component of the velocity perpendicular to the window, which is:

Δt = 1.346 m / (v * sin(59°)) = 1.346 m / (6.7 m/s * sin(59°)) = 0.139 s

Substituting the values, we get:

F = 14.1463 hailstones/s * 2 * 0.007 kg * 6.7 m/s * cos(59°) * (-i) / 0.139 s

F = 28.051 N * i

Therefore, the average force on the window is 28.051 N, in the negative x-direction.

Explanation:

Answer:

0.9 Amps

Explanation:

Ohm's law: Voltage = Current x Resistance

Rearrange equation:

Current =Voltage/Resistance

Voltage=6v

In a series circuit the total resistance is the sum of all the resistors so the total resistance = 0.1+0.15+0.2+0.25+6=6.7 Ohms

6/6.7 = 0.9 (1dp) Amps

Because it is a series circuit, the current is the same throughout the entire circuit, all the resistors have a current of 0.9 Amps.

Hope this helped!

Answer:

1. C

2. B

3. 5.4 m/s

Explanation:

The formula for speed is s = d/t.

Simply substitute the given and take note of the unit.

The solid sphere will reach the bottom first then hallow sphere due to moment of inertia.

The moment of inertia of a rigid body, also referred to as the mass moment of inertia, angular mass, second moment of mass, or more precisely, rotational inertia, is a property that establishes the torque required for the desired angular acceleration about a rotational axis, much like mass establishes the force required for the desired acceleration. A common mechanical measurement is the moment of inertia. The amount of torque required to modify the body's rate of rotation depends on the mass distribution of the body and the axis selected. For example, larger moments require more torque. The moment of inertia for a point mass is equal to the mass squared by the perpendicular distance from the axis of rotation. This is an extensive (additive) property. an immovable object's moment of inertia

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Answer:

Lost Mechanical Power = 7.7565 KW

Head Loss = 26.35 m

Explanation:

First, we will find the useful mechanical power used to transport water to the higher reservoir:

\(P_{useful} = \rho ghV\)

where,

P_useful = Useful mechanical Power = ?

ρ = density of water = 1000 kg/m³

g = acceleration due to gravity = 9.81 m/s²

h = height = 45 m

V = Volume flow rate = 0.03 m³/s

Therefore,

\(P_{useful} = (1000\ kg/m^3)(9.81\ m/s^2)(45\ m)(0.03\ m^3/s)\\P_{useful} = 13243.5\ W = 13.2435\ KW\)

Now, the lost mechanical power will be:

\(Lost\ Mechanical\ Power = Total\ Mechanical\ Power - Useful\ power\\Lost\ Mechanical\ Power = 21\ KW - 13.2435\ KW\\\)

Lost Mechanical Power = 7.7565 KW

Now, for the head loss:

\(Lost\ Mechanical\ Power = \rho g(Head\ Loss)V\\Head\ Loss = \frac{Lost\ Mechanical\ Power}{\rho gV} \\\\Head\ Loss = \frac{7756.5\ W}{(1000\ kg/m^3)(9.81\ m/s^2)(0.03\ m^3/s)} \\\)

Head Loss = 26.35 m

Answer:

Wow wouldn't even know what it says lol. Thank you have a goodnight

Longitudinal waves are those in which the displacement of the medium moves in the same plane as the wave's direction of travel.

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Answer:

Label the parts of the longitudinal wave.

Wavelength:C

Rarefactions:B

Compressions:A

Explanation:

I me and my

An open cluster is a group of up to a few thousand stars that were formed from the same giant molecular cloud, and are still loosely gravitationally bound to each other. In contrast, globular clusters are very tightly bound by gravity. ... Open clusters are very important objects in the study of stellar evolution.

Answer:

b.

Explanation:

It's b I sis thebksqjwnsx0qkqnsnd991isnd

Answer:

its b beacuse on the graph every second and the potision are 2 a seconded

The ratio of their amplitudes is 3.

The relation between energy and amplitude is as follows:

\(E_{1} = \frac{1}{2} KA_{1} ^{2}\)

\(E_{2} =\frac{1}{2} KA_{2} ^{2}\)

As, we know , one oscillation has 3.0 times the energy of a second one of equal frequency and mass i.e.,

\(E_{1} = 3E_{2}\)

So, \(\frac{1}{2} KA_{1} ^{2} = 3(\frac{1}{2}KA_{2} ^{2} )\)

\(A_{1} ^{2} = 3A_{2} ^{2}\)

\(\frac{A_{1}^{2} }{A_{2}^{2} } = 3\)

Therefore,  the ratio of their amplitudes is 3.

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Answer:

Explanation:

If a be grating element

a = 1 x 10⁻² / 11000

= .0909 x 10⁻⁵

= 909 x 10⁻⁹ m

for first order maxima , the condition is

a sinθ = λ where λ is wavelength

909 x 10⁻⁹ sin 49.67 = λ₁

λ₁ = 692.95  nm .

λ₂ = 909 x 10⁻⁹ sin 50.65

= 702.91 nm

λ₃ = 909 x 10⁻⁹ sin 52.06

= 716.88 nm

λ₄ = 909 x 10⁻⁹ sin 52.89

= 724.90 nm

692.95  nm ,  702.91 nm  , 716.88 nm , 724.90 nm .

Answer:

v=7.8

Explanation:

at rest v⁰ is zero

v²= v⁰t+1/2at²

=1/2×2.5×7²

=0.5×2.5×49

=7.8

The velocity of the object between 5 s and 9 s is 20 m/s.

The velocity of an object is the rate of change of displacement of the object with time.

Mathematically, the formula for velocity of an object is given as;

v = Δx/Δt

where;

v = (xf - xi) / (t₂ - t₁)

where;

From the given graph, we can infer the following;

xf, the final displacement of the object = 180 m

xi, the initial displacement of the object = 100 m

t₂, the final time of motion of the object = 9 seconds

t₁, the initial time of motion of the object = 5 seconds

v = (180 m - 100 m) / (9 s - 5 s)

v = (80 m) / (4 s)

v = 20 m/s

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Answer:

The vertical component of the velocity can be found using the formula:

V₀y = V₀ * sin(θ)

where V₀ is the initial velocity, θ is the angle of projection, and V₀y is the vertical component of the velocity.

Substituting the given values, we have:

V₀y = 48 * sin(53°)

Using a calculator, we can evaluate sin(53°) to be approximately 0.799:

V₀y = 48 * 0.799

V₀y ≈ 38.352

Therefore, the vertical component of the velocity with which the ball was launched is approximately 38 meters/second, which corresponds to option B.

Answer:

B.) 38 meters/second

Explanation:

Answer:

10 J

Explanation:

Using the idea of the first law of thermodynamics to answer this question.

The first law of thermodynamics simply restates energy conservation: Energy is not created nor is it destroyed it is simply transformed into other forms of energy. It can be stated in the following formula,

\(\boxed{\left\begin{array}{ccc}\text{\underline{The First Law of Thermodynamics:}}\\\\\Delta E_{int.}=Q-W_{by}\end{array}\right}\)

In a isothermal process the change in internal energy is equal to zero. So plug in what we know.

\(\Longrightarrow \Delta E_{int.}=Q-W_{by}\\\\\Longrightarrow 0=Q-10\\\\\Longrightarrow \boxed{Q=10 \ J}\)

Thus, 10 J of heat must be added to the gas.

For a rectangular storage tank filled with paraffin to a depth of 2 m, the volume, weight, mass of paraffin, and pressure at the bottom of the tank are:

a. The volume is 24 m³.

b. weight is 240,000 N,

c. mass is 24,490 kg, and

d. pressure is 23,530 Pa.

a) The volume of paraffin in the rectangular storage tank can be calculated using the formula:

Volume = Length x Width x Depth

Given:

Length = 4 m

Width = 3 m

Depth = 2 m

Substituting the values into the formula, we have:

Volume = 4 m x 3 m x 2 m

Volume = 24 m³

Therefore, the volume of paraffin in the tank is 24 cubic meters.

b) The weight of the paraffin can be calculated using the formula:

Weight = Volume x Density x Acceleration due to gravity

The density of paraffin varies, but we can assume a typical value of 10,000 kg/m³. The acceleration due to gravity is approximately 9.8 m/s². Substituting these values into the formula:

Weight = 24 m³ x 10,000 kg/m³ x 9.8 m/s²

Weight = 240,000 N

Therefore, the weight of the paraffin in the tank is 240,000 Newtons.

c) The mass of the paraffin can be calculated using the formula:

Mass = Density x Volume

Substituting the given values:

Mass = 10,000 kg/m³ x 24 m³

Mass = 24,490 kg

Therefore, the mass of the paraffin in the tank is 24,490 kilograms.

d) The pressure at the bottom of the tank due to the paraffin can be calculated using the formula:

Pressure = Weight / Area

The area of the bottom of the tank is equal to the length multiplied by the width. Substituting the values:

Area = 4 m x 3 m

Area = 12 m²

Pressure = 240,000 N / 12 m²

Pressure = 20,000 Pa

Therefore, the pressure at the bottom of the tank due to the paraffin is 20,000 Pascals (Pa).

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Answer:

Explanation:

An atom emits a photon (particle of light) when transitioning from a ground state to its excited state. To obey conservation of energy, the energy gained by the atom when an electron moves to a lower energy level is equal to the energy it loses in emitting the photon. (The energy of a photon is E = hf, where E is the energy, h is Planck's constant, and f is the frequency of the photon.) Conversely, when an atom absorbs a photon (as is the case in absorption spectra), the electron absorbing the photon moves to a higher energy level.

Answer:

d = 150 km

Explanation:

Speed of an airplane is 600 km/h

We need to find how far it travel in 1/4 hour.

We know that the speed of an object is given by distance travelled divided by the time taken. Let d is the distance covered in 1/4 hour. So,

\(v=\dfrac{d}{t}\\\\d=v\times t\\\\d=600\ km/h \times \dfrac{1}{4}\ h\\\\d=150\ km\)

So, it will cover 150 km.

The circuit is a series circuit since all of the components are connected in a single path.

The current that flows through each component is the same, and the voltage across each component is proportional to its resistance.

In this circuit, there are two resistors, R1 and R2, and a battery with an electromotive force (EMF) of E.

The voltage across each resistor can be determined using Ohm's law, which states that

V = IR,

where V is the voltage

           I is the current

           R is the resistance.
The total resistance of the circuit can be calculated using the formula:

R = R1 + R2.

Using Ohm's law, the current in the circuit can be found by dividing the voltage by the total resistance:

I = E / R
The voltage across each resistor can be found using

V1 = IR1 and V2 = IR2.

The total voltage of the circuit is equal to the sum of the voltages across each resistor

V = V1 + V2

Substituting the equations for V1 and V2 into the equation for V, we get;

V = I(R1 + R2)
Thus, we can use the following equations to solve for the different variables in the circuit:
R = R1 + R2
I = E / R
V1 = IR1
V2 = IR2
V = I(R1 + R2)
Using these equations, we can calculate the current, voltage, and power of the circuit.

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