arrange in descending order 11/31, 11/5,
11/12​

The rate of interest be required in order for Deondra to end up with $201,000 is 14.88%

percentage, a relative value indicating hundredth parts of any quantity.

Given that Deondra is going to invest $90,000 and leave it in an account for 15 years.

We have o find the interest rate, to the nearest hundredth of a percent, would be required in order for Deondra to end up with $201,000

A=PRT

201000=90000×R×15

201000=1350000R

Divide both sides by 1350000

R=0.1488×100

R=14.88

Hence, the rate of interest be required in order for Deondra to end up with $201,000 is 14.88%

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When x^3+2x^2+x+1 is divided by (x+1) then remainder is 1.

In the given question, we have to find what is remainder when x^3+2x^2+x+1 is divided by (x+1).

To find the remainder there are two ways. First we divide the x^3+2x^2+x+1 by (x+1). Second we find the value of from (x+1) by equating (x+1) equal to zero. The put the value of x in the expression x^3+2x^2+x+1.

In this we ca easily find the remainder.

Now we firstly find the value of x;

(x+1) = 0

Subtract 1 on both side we get;

x= −1

Now put x= -1 in the expression x^3+2x^2+x+1.

x^3+2x^2+x+1 = (−1)^3+2(−1)^2+(−1)+1

x^3+2x^2+x+1 = −1+2−1+1

x^3+2x^2+x+1 = 1

Hence, when x^3+2x^2+x+1 is divided by (x+1) then remainder is 1.

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The right question is:

What is remainder when x^3+2x^2+x+1 is divided by (x+1)?

The smallest x value allowed is x = 0, as shown as the leftmost point on the graph at (0,0).

The largest x value allowed is x = 11 because of the right-most point (11,100).

The domain is the set of any real number between those endpoints. We can pick any fractional or decimal number in this interval since time can be subdivided however you want, so the set of integers isn't enough.

Distance run by Lucy during her first week = 25.66 miles

Distance is the total movement of an object without any regard to direction. We can define distance as to how much ground an object has covered despite its starting or ending point.

We know 1 week has 7 days.

Distance run by Lucy in 1 day = 11/3 miles

Distance run by Lucy in 7 days or 1 week = (11/3) x 7

Distance run by Lucy in 7 days or 1 week = 77/3

Distance run by Lucy in 7 days or 1 week = 25.66 miles

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The correct choice is:

F. Infinitely many

To determine the number of solutions for the given linear system:

2x - 4y + 4z = 0

-x + 2y + 3z = 2

-x + 2y + 3z = 2

We can start by putting the system into an augmented matrix form:

[2 -4 4 | 0]

[-1 2 3 | 2]

[-1 2 3 | 2]

Now, let's perform row operations to simplify the matrix and identify the number of solutions:

R2 = R2 + R1

R3 = R3 + R1

[2 -4 4 | 0]

[1 -2 3 | 2]

[1 -2 3 | 2]

R2 = R2 - R3

[2 -4 4 | 0]

[0 0 0 | 0]

[1 -2 3 | 2]

Now, we can see that the second row is all zeros. This indicates that the system has infinitely many solutions. The equations are dependent, meaning that one equation is a linear combination of the others.

Therefore, for any chosen values of x, y, and z that satisfy the given equation (2x - 4y + 4z = 0), we can find corresponding values for the remaining variables that satisfy the other equations.

The correct choice is:

F. Infinitely many

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The factor of the expression will be (x + 1) and (x + 1). Then the product of two binomials will be (x + 1) and (x + 1).

It is a method for dividing a polynomial into pieces that will be multiplied together. At this moment, the polynomial's value will be zero.

The expression is given below.

⇒ x² + 2x + 1

Factorize the expression, then the factor of the expression will be

⇒ x² + x +  x + 1

⇒ x(x + 1)x + 1(x + 1)

⇒ (x + 1)(x + 1)

⇒ (x + 1)²

The product of two binomials will be (x + 1) and (x + 1).

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Answer:

2x

Step-by-step explanation:

\(\text{Perimeter}=2\cdot(4\text{x}+3)+2\cdot2\text{x}=\\\\=8\text{x}+6+4\text{x}=8\text{x}+4\text{x}+6=\boxed{12\text{x}+6}\)

By finding the distances between the vertices, we will see that the perimeter is 49.23 centimeters.

Remember that the distance between two points (a, b) and (c, d) is given by:

distance = √( (a - c)^2 + (b - d)^2)

Now we need to that for the 3 given vertices.

The first two are the points (-8, -7) and (5, -5), the distance is:

d = √( (-8  -5)^2 + (-7 + 5)^2) = 13.15

The second pair is (5, -5) and (7, 9), the distance is:

d' = √( (5  -7)^2 + (-5 - 9)^2) = 14.14

The last pair is (7, 9) and (-8, -7), this time the distance is:

d'' = √( (7 + 8)^2 + (9 + 7)^2) = 21.94

Adding the distances, we get that the perimeter is:

P = 13.15 + 14.14 + 21.94 = 49.23

So the correct option is B, 49.23 centimeters.

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Answer: 49.23 centimeters

Step-by-step explanation:

Answer:

Step-by-step explanation:

f(x) = -4cos(3x-pi) +2

compare to f(x) = A cos (B(x+C))+D

A is amplitude =4

Period is 2pi/B so period = 2pi/3

Phase shift is C so phase shift = -pi (this could be positive if it shifted to the left)

Midline is at D so midline is y=2

Answer:

To graph this line, move one of the points to positive three on the horizontal (side to side) line and negative six on the vertical (up and down) line. To get a slope of negative 1/2 you move down one point and right two points, and you continue until you reach the edge of the graph. Then you do the opposite on the way up (up one and left two).

Hope this helps!

Answer:  Plot the two points (3,-6) and (1, -5). Draw a straight line through those points.

See the graph below.

=============================================

Explanation:

Plot the point (3, -6)

The slope -1/2 means the rise is -1 and the run is 2

If we moved to the right, then we'd drop down 1 and move to the right 2. That would move us from (3,-6) to (5,-7)

We can go in reverse of this. So instead of "move down 1", we move up 1. We're going left instead of right.

-----------

So we start at (3,-6) and move up 1 and to the left 2 to arrive at (1,-5)

Two points on this line are (1, -5) and (3, -6)

Once we have two points, we have enough to graph the line.

See the graph below.

Point P₁(-8 + 9√2/2, 2√2, 4 - 3√2) is the required point on the ellipsoid whose tangent plane is perpendicular to the given line.

Given: The ellipsoid x² + 2y² + z² = 12.

To find: A point on the ellipsoid where the tangent plane is perpendicular to the line with parametric equations x=5-6, y = 4+4t, and z=2-2t.

Solution:

Ellipsoid x² + 2y² + z² = 12 can be written in a matrix form asXᵀAX = 1

Where A = diag(1/√12, 1/√6, 1/√12) and X = [x, y, z]ᵀ.

Substituting A and X values we get,x²/4 + y²/2 + z²/4 = 1

Differentiating above equation partially with respect to x, y, z, we get,

∂F/∂x = x/2∂F/∂y = y∂F/∂z = z/2

Let P(x₁, y₁, z₁) be the point on the ellipsoid where the tangent plane is perpendicular to the given line with parametric equations.

Let the given line be L : x = 5 - 6t, y = 4 + 4t and z = 2 - 2t.

Direction ratios of the line L are (-6, 4, -2).

Normal to the plane containing line L is (-6, 4, -2) and hence normal to the tangent plane at point P will be (-6, 4, -2).

Therefore, equation of tangent plane to the ellipsoid at point P(x₁, y₁, z₁) is given by-6(x - x₁) + 4(y - y₁) - 2(z - z₁) = 0Simplifying the above equation, we get6x₁ - 2y₁ + z₁ = 31 -----(1)

Now equation of the line L can be written as(t + 1) point form as,(x - 5)/(-6) = (y - 4)/(4) = (z - 2)/(-2)

Let's take x = 5 - 6t to find the values of y and z.

y = 4 + 4t

=> 4t = y - 4

=> t = (y - 4)/4z = 2 - 2t

=> 2t = 2 - z

=> t = 1 - z/2

=> t = (2 - z)/2

Substituting these values of t in x = 5 - 6t, we get

x = 5 - 6(2 - z)/2 => x = -4 + 3z

So the line L can be written as,

y = 4 + 4(y - 4)/4

=> y = yz = 2 - 2(2 - z)/2

=> z = -t + 3

Taking above equations (y = y, z = -t + 3) in equation of ellipsoid, we get

x² + 2y² + (3 - z)²/4 = 12Substituting x = -4 + 3z, we get3z² - 24z + 49 = 0On solving the above quadratic equation, we get z = 4 ± 3√2

Substituting these values of z in x = -4 + 3z, we get x = -8 ± 9√2/2

Taking these values of x, y and z, we get 2 points P₁(-8 + 9√2/2, 2√2, 4 - 3√2) and P₂(-8 - 9√2/2, -2√2, 4 + 3√2).

To find point P₁, we need to satisfy equation (1) i.e.,6x₁ - 2y₁ + z₁ = 31

Putting values of x₁, y₁ and z₁ in above equation, we get

LHS = 6(-8 + 9√2/2) - 2(2√2) + (4 - 3√2) = 31

RHS = 31

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Answer:

324 m³

Step-by-step explanation:

each cube = 3x3x3 = 27 m³

27 m³ 12 = 324 m³

Answer:

your answer is correct its option B

Step-by-step explanation:

hope it's helpful...

have a great day

The length of the rectangular box is given as follows:

1.59 inches.

The volume of a rectangular prism, with dimensions length, width and height, is given by the multiplication of these dimensions, as follows:

Volume = length x width x height.

A rectangular box weight 2.8 pounds, and each pound has 27.68 cubic inches, hence the volume in in³ is given as follows:

V = 2.8 x 27.68

V = 77.504 in³.

The width is of 7.70 inches and the height is of 7.75 - 1.41 = 6.34 inches, hence the length is obtained as follows:

7.70 x 6.34l = 77.504

l = 77.504/[7.70 x 6.34]

l = 1.59 inches.

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Answer: $105

Step-by-step explanation:

origional price multiplied by discount = x/ 100

150 x 30 = 4500/ 100= 45$ off

150- 45= 105

The approximation probability that two people in a group of seven have the same birthday is 0.0000007 or 7 in 10 million.

The approximation probability that two people in a group of seven have the same birthday can be determined using a formula.

To calculate the probability that two people in a group of seven have the same birthday, we can use an approximation formula.

The formula is given as:P(n) = 1 - (365!/(365^n *(365-n)!)) * (1/n!)

Where P(n) is the probability that at least two people share the same birthday, n is the number of people in the group, and the exclamation mark (!) is the factorial function.

For a group of seven people, we substitute n=7 in the formula, and we get:

P(7) = 1 - (365!/(365^7 *(365-7)!)) * (1/7!)This simplifies to:P(7) ≈ 1 - 0.9999993 = 0.0000007

Therefore, the approximation probability that two people in a group of seven have the same birthday is 0.0000007 or 7 in 10 million.

The probability is incredibly small, and it implies that it is unlikely for two people in a group of seven to have the same birthday.

This is because there are only 365 possible birthdays in a year, and the sample size of seven is too small to increase the likelihood of a match.

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Answer:

d

Step-by-step explanation:

here is the answer -option d

The simple interest on N40,000 for two years at 20% per annum is N16,000.

To calculate the simple interest, we can use the formula:

Simple Interest = (Principal * Rate * Time) / 100

Here, the principal is N40,000, the rate is 20% per annum, and the time is 2 years. Substituting these values into the formula, we get:

Simple Interest = (40,000 * 20 * 2) / 100 = 16,000

Therefore, the simple interest on N40,000 for two years at 20% per annum is N16,000.

This means that after two years, the total amount owed would be N56,000 As N40,000 is the principal and N16,000 is the interest by adding the principal and interest total amount can be obtained.

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Answer: 22/25

Step-by-step explanation:

54x+6x-30=7(x+2)+3x

60x-30=7(x+2)+3x

60x-30=7x+14+3x

60x-30=10x+14

60x-10x-30=14

60x-10x=14+30

50x=14+30

50x=44

x=22/25

Answer:

the answer is 13/103

Step-by-step explanation:

Answer:

D.

\(V = 20/3L\)

Step-by-step explanation:

Given

\(P = 5atm; V = 4L\)

Required

Determine V when P = 3atm

Boyles Law states that;

\(k = VP\)

When : \(P = 5atm; V = 4L\)

\(k = 5 * 4\)

\(k = 20\)

Using the same formula:

\(k = VP\)

When \(P = 3atm\)

We have:

\(20 = V * 3\)

Solve for V

\(V = 20/3L\)

Answer:

D.) The formula is k = VP, and when P = 3, V = 20/3

Step-by-step explanation:

This is right on edg. 2020

The value of x and y is (2, -2)

In its simplest form in algebra, the definition of an equation is a mathematical statement that shows that two mathematical expressions are equal. For instance, 3x + 5 = 14 is an equation, in which 3x + 5 and 14 are two expressions separated by an 'equal' sign.

The equations are:

3x+y = 4 ----Equation 1

2x-y = 6 ----Equation 2

Eliminating Y Multiply negative both side

-[3x +y = 4 ] -

-3x-y = -4 ----Equation 3

From eq. (2) to eq. (3)

2x-y = 6

-3x-y = -4

=> 5x = 10

x =2

The value of x substitute in eq. (1)

3x+y=4

3(2) + y =4

6 + y = 4

y = -2

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The given question is incomplete, complete question is:

Puzzle Three Solve the to systems of equations. To unlock puzzle three find the product of solution (ordered pair - x and y value) and then find the mean of all five products.3x + y = 42 x - y = 6

Given vertices of polygon JKLM are J(-4,-3), K(-4,-6), L(-1,-6), M(-1,-3). To determine the image coordinates of L', if the pre-image is reflected across y = -3. So the right option is (C) L’(-1,0)

we need to follow the below steps:

Step 1: Plot the points in the coordinate plane.

Step 2: Draw the line of reflection, y = -3. It is a horizontal line.

Step 3: Find the reflection image of point L(-1, -6) about y = -3.

So, let's plot these points in the coordinate plane.

Here is the graph of the polygon:graph{JKLM(-4,-3)(-4,-6)(-1,-6)(-1,-3)}

As we can see in the above graph, the line of reflection y = -3 is a horizontal line passing through the point (-1,-3).

Now, we need to find the image of the point L(-1,-6) reflected across the line y = -3.

Let's draw a line of reflection and points.

Here is the graph:

graph{JKLM(-4,-3)(-4,-6)(-1,-6)(-1,-3)l_ref(y=-3,-7,0)}

To find the image of point L across the line of reflection y = -3, we follow the below steps:

Step 1: Draw a perpendicular line from L to the line of reflection. It intersects the line of reflection at L1.  

Step 2: Find the distance between point L and L1.

Step 3: Draw a line through L1 parallel to the line of reflection.  

Step 4: The intersection of the line in Step 3 with y = -3 is the image of L across the line of reflection.

Let's apply these steps to find the reflection image of point L. Here is the graph:graph{JKLM(-4,-3)l_ref(y=-3,-7,0)L(-1,-6)L1(-1,-3)L2(-7,-3)L1L--L2--(1,-3)L-(-1,-3)L'(-1,0)}

Step 1: Draw a perpendicular line from L to the line of reflection. It intersects the line of reflection at L1.  So, here the perpendicular line is drawn as L1(-1, -3)

Step 2: Find the distance between point L and L1. The distance between L and L1 is 6 units. So, the distance between L' and L1 is also 6 units.

Step 3: Draw a line through L1 parallel to the line of reflection. Let's draw a line through L1 parallel to the line of reflection. The parallel line is L2 : y = -3

Step 4: The intersection of the line in Step 3 with y = -3 is the image of L across the line of reflection. Let's find the point where L2 intersects y = -3: -1 + 6 = 5. So, the point L' is (-1, 0).

Hence, the correct option is C. L’(-1,0).

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Answer:

10 sides,that is, a decagon or 10gon

Step-by-step explanation:

If the exterior angle is 36° then numbers of sides=

\(36 = \frac{360}{n} \)

Therefore

n=360°÷36°=10

Answer:

Step-by-step explanation:

The sum of the measures of the exterior angles in a convex polygon is 360°.And each exterior angle measure 36 degrees so Number of side will be 10.

360 : 36 = 10

To apply the Limit Comparison Test, we must find an appropriate series $∑b_n$ for comparison (this series must also have positive terms).

The most reasonable choice is $b_n=\frac{1}{n^2}$, so that $∑b_n$ is a p-series. Evaluate the limit below - as long as this limit is some finite value c>0, then either both series $∑a_n$ and $∑b_n$ converge or both series diverge.$$\lim_{n→∞} \frac{b_n}{a_n}$$$\lim_{n→∞} \frac{1/n^2}{3n^2+6}$$ Multiplying both numerator and denominator by $n^2$ gives:$$\lim_{n→∞} \frac{1}{3n^4+6n^2}$$ The denominator grows much faster than the numerator, so the limit of the fraction is zero:$$\lim_{n→∞} \frac{b_n}{a_n} = \lim_{n→∞} \frac{1/n^2}{3n^2+6} = 0$$ From what we know about p-series we conclude that the series $∑b_n$ is convergent. Finally, by the Limit Comparison Test we conclude that the series $∑a_n$ is convergent. Therefore, the series $∑a_n=∑_{n=1}^∞ \frac{3n^2+6}{n^2}$ is convergent using the Limit Comparison Test.

We must first find an appropriate series $∑b_n$ for comparison. The most reasonable choice is $b_n=\frac{1}{n^2}$, so that $∑b_n$ is a p-series.$$∑_{n=1}^∞ \frac{3n^2+6}{n^2}$$ Evaluate the limit below - as long as this limit is some finite value c>0, then either both series $∑a_n$ and $∑b_n$ converge or both series diverge.$$lim_{n→∞} \frac{b_n}{a_n}$$$$lim_{n→∞} \frac{1/n^2}{3n^2+6}$$ Multiplying both numerator and denominator by $n^2$ gives:$$lim_{n→∞} \frac{1}{3n^4+6n^2}$$

The denominator grows much faster than the numerator, so the limit of the fraction is zero:$$lim_{n→∞} \frac{b_n}{a_n} = \lim_{n→∞} \frac{1/n^2}{3n^2+6} = 0$$From what we know about p-series we conclude that the series $∑b_n$ is convergent.

Finally, by the Limit Comparison Test we conclude that the series $∑a_n$ is convergent.

Therefore, the series $∑a_n=∑_{n=1}^∞ \frac{3n^2+6}{n^2}$ is convergent using the Limit Comparison Test.

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The probability that a student walks to school is 7/15

The tree diagram represents the given parameter

From the tree diagram, we have the following parameters

P(Rain) = 2/5

P(Rain and walk) = 1/6

P(No rain) = 3/5

P(No rain and walk) = 2/3

The probability of walking to school is then calculated as

P = P(Rain) x P(Rain and walk) + P(No rain) x P(No rain and walk)

Substitute the known values in the above equation

So, we have

P = 2/5 x1/6 + 3/5 x 2/3

Evaluate the products

P = 1/15 + 6/15

Evaluate the sum

P = 7/15

Hence, the probability is 7/15

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The graph of a proportional relationship is a line through the origin or a ray whose endpoint is the origin

3. No because it's a line that doesn't go through the origin

4. Yes because it's a line through the origin

5. Yes because 1/3 = 2/6 = 3/9 = 4/12

6. No because 4/2 isn't equal to 8/5

7. Draw a graph just like 4., but change the y-axis

8. a. Let the equation be y = ax. 27 = 3a. a = 9. Therefore the equation is y = 9x.

8. b. 9

8. c. 9 * 5 = 45

9. a. The car travels 25 (> 18) miles per gallon of gasoline.

9. b. 25 * 8 - 18 * 8 = 7 * 8 = 56

Answer:

Must be in the middle.

Step-by-step explanation:

Let's say the vertex is F

the angle would be written as EFG

the angle WOULD NOT be written as FEG or EGF

Answer:

The transformation is

reflection in the x axis

That's ( x , - y)

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