as the distance from the nucleus increases, what happens?

Answer:

36

Explanation:

There are 6 Carbon atoms, 12 Hydrogen atoms, and 18 Oxygen atoms.

The vanilla extract can be used in the house to;

Vanilla beans are steeped in ethyl alcohol and water to produce vanilla extract, an aromatic, amber-colored liquid. pure vanilla extract is gotten through macerating and percolating vanilla pods in an ethanol and water mixture, vanilla extract is created.

In many Western sweets, particularly baked goods like cakes, cookies, brownies, and cupcakes, as well as custards, ice creams, and puddings, it is seen as a necessary component.

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The quantity weak acid present in solution is equal to the quantity of conjugate base created at the half equivalence point.

For weak acid/strong base titrations, the pH at the equivalence point is >7. This is because the solution consists of water, strong base (neutral) cations, and weak acid (base) anions. The pH at half the equivalence point volume (half the equivalence point) is the pKa.

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Answer:B

Explanation:

Answer:

wood burning and cookies baking

Explanation:

took the test <333

Answer:

Wood burning and cookies baking

Explanation:

To determine the relative molecular weights of methylene blue and potassium permanganate, a method known as 'osmometry' can be used.

Here's how to conduct the experiment :

Experiment Set-up

Step 1: Firstly, create a solution of a known concentration of methylene blue and potassium permanganate. The concentration of the solution should be around 0.01 M.

Step 2: Take an apparatus that includes a semi-permeable membrane and two containers. The semi-permeable membrane should be permeable to the solvent used but impermeable to the solute.

Step 3: Fill the two containers with the prepared solutions, methylene blue, and potassium permanganate.

Step 4: Place the semi-permeable membrane between the two containers.

Step 5: Observe the solution levels in both containers. In the initial stage, the solution level in the container containing methylene blue will be higher, while the container containing potassium permanganate will be lower.

Step 6: The process will continue until the solution levels in both containers become equal.

Step 7: Now, record the solution levels in both containers at equilibrium.

The Relative Molecular Weight Calculation

Step 8: Apply the following formula to calculate the relative molecular weight of the solute : Δπ= MRT

Δπ = change in osmotic pressure of the solution

M = molar concentration of the solution

R = universal gas constant (8.314 J/mol K)

T = temperature in Kelvin

If we take Methylene blue as solute and KCl as solvent, then at 25°C the osmotic pressure of the solution is given as :

Δπ = 0.51 atm

Substituting all values in the above formula, we get Δπ = MRT(i)

0.51 atm = M x 8.314 J/molK x 298 K(i)

M = 0.0206 mol/L

The relative molecular weight of Methylene blue is :

M = m/2.06 x 10^-2

where m is the mass of Methylene blue dissolved in 1 litre of solvent.

From the relative molecular weight calculated, we can get the actual molecular weight by multiplying it by the molar mass of the solvent used.

For example, if the solvent used is KCl, then the molecular mass of the solvent is 74.55 g/mol.

Therefore, the molecular weight of Methylene blue = Relative molecular weight x molar mass of the solvent.

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Answer:

homogeneous mixture

Explanation:

The correct classification for air is a homogeneous mixture.

Material is referred to as a mixture when two or more chemicals combine without undergoing a chemical reaction.

Heterogeneous and homogeneous mixtures are the two types of mixtures.

While homogeneous mixtures seem consistent throughout, heterogeneous mixtures have clearly discernible components.

A solution, which can be a solid, liquid, or gas, is the most typical kind of homogenous mixture.

Mixtures are composed of two or more different substances that have not been chemically mixed. The following is a list of mixture properties.

Each of the components in a mixture retains its unique features.

Component separation is simple to carry out.

The component's relative weights vary.

The classification for air is 78% nitrogen, 21% oxygen, 0.9% argon, 0.03% carbon dioxide, and 0.07% other gases.

This classification for air has the properties of a homogeneous mixture.

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Answer:

they move closer to each other

Answer:

They move closer to each other

Explanation:

Got it right on the test

Hope this helps :)

Answer:

259.5

Explanation:

The formula for density is mass/volume

Answer:

Earth is tilted on its axis

Explanation:

Whenever Earth is tilted on its axis, the tilt of the earth's rotational axis causes Nigeria to have longer days in the summertime, beginning in June, compared to the winter period. The tilting of the earth also causes Nigeria to experience longer nights in the winter.

The earth’s axis of rotation is tilted at an angle of 23.5 degrees compared to the earth's orbital plane. Such tilting of the earth is what causes Nigeria to experience longer hours during the day in the summer when the Northern Hemisphere is titled toward the sun starting around June 20 or 21.

The food sample contained starch and reducing sugar (carbohydrates).

The Benedict's test is used to test for the presence of reducing sugars, such as glucose, in a sample. When the Benedict's solution is added to a sample containing reducing sugars and heated, the solution will turn brick red.

The iodine test is used to test for the presence of starch in a sample. When iodine solution is added to a sample containing starch, it will turn blue-black.

So, in this case, the student can conclude that the food sample contained both starch and reducing sugars, as both tests produced positive results.

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The general equation for the reaction between bromine and an alkene is known as an addition reaction. In this reaction, the alkene's double bond is broken, and the bromine molecule adds to the carbon atoms involved in the double bond. The specific equation will depend on the structure of the alkene.

As an example, let's consider the reaction between bromine (Br2) and ethene (C2H4):

C2H4 + Br2 → C2H4Br2

In this reaction, the double bond of ethene is broken, and each carbon atom of the double bond forms a bond with one bromine atom, resulting in the formation of 1,2-dibromoethane (C2H4Br2). This reaction is often referred to as bromination of ethene.

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La fuerza de la gravedad depende de la masa (el peso) de cada objeto. La fuerza con que se atraen dos objetos es proporcional a su masa y disminuye rápidamente en el momento en que los separamos. De hecho, nosotros también atraemos objetos con ‘nuestra’ fuerza gravitatoria, pero pesamos tan poco que no podemos percibirlo. En cambio, el Sol es tan grande que es capaz de mantenernos girando a su alrededor a pesar de estar muy lejos. La Luna también ejerce su propia fuerza gravitatoria, pero, como es más pequeña y ligera que la Tierra, si nos pesásemos sobre su superficie veríamos que pesamos unas seis veces menos que en la Tierra.

Podríamos preguntarnos por qué la Luna no cae sobre la Tierra al igual que una manzana cae del árbol. La razón es que nuestro satélite nunca está quieto. Se mueve constantemente a nuestro alrededor. Sin la fuerza de atracción terrestre, se alejaría flotando en el espacio. Gracias a esta combinación de velocidad y distancia de nuestro planeta, la Luna siempre está en equilibrio, ni cae ni se aleja. Si se moviera más rápido, se alejaría, si se moviera con más lentitud, ¡caería!

Hemos dicho que la fuerza de la gravedad también depende de la distancia. Si nos alejásemos lo suficiente de la Tierra, escaparíamos a su fuerza de atracción. Y eso es lo que tratamos de hacer con las naves espaciales. Necesitamos superar la llamada ‘velocidad de escape’, que es aproximadamente 11,2 km/s (a esa velocidad, podríamos viajar de Londres a Nueva York ¡en tan solo 10 minutos!). Cuando un cohete alcanza esa velocidad, ya es libre para viajar por el sistema solar.

Dentro de una nave en órbita, no sentimos la fuerza de la gravedad terrestre. Los objetos no caen, sino que flotan, así que si saltas, no regresas al suelo. Es lo que les ocurre a los astronautas cuando están a bordo de una estación espacial que orbita alrededor de la Tierra.

Answer:

Explanation:

Balance the following reaction. A coefficient of "1" is understood. Choose option "blank" for the correct answer if the coefficient is "1." NH3 + O2 → N2 + H2O

2NH3 + 3/2O2 → N2 + 3H2O

you cannot have 3/2 of a molecules, so multiply all coefficients by "2"

4NH3 + 3O2 → 2N2+ 6H2O

there are 4 N on each side, 12 H on each side, 6 O on each side

the equation is balanced!

when balancing equations, you cannot change the subscripts in the compounds, you can only show with coefficients haw may molecules yous have

The estimated relative contribution of C3 plants is approximately 88%, while the estimated relative contribution of C4 plants is approximately 12% to the organic matter in Kenya's soil.

To determine the relative contribution of C3 and C4 plants to the organic matter in Kenya's soil, we can use the difference in stable carbon isotopic compositions (δ13C values) between these plant types.

C3 and C4 plants have distinct δ13C values due to differences in their carbon fixation pathways. C3 plants generally have δ13C values ranging from -22 to -33 permil, while C4 plants typically exhibit δ13C values from -9 to -16 permil.

Given that the stable carbon isotopic composition (δ13C) of the soil organic matter in Kenya is -18 permil, we can compare this value to the δ13C values of C3 and C4 plants to estimate their relative contributions.

Let's denote the relative contribution of C3 plants as "x" and the relative contribution of C4 plants as "y." Since the contributions of C3 and C4 plants sum up to 100%, we have the equation:

x + y = 100% (equation 1)

Now, let's assign the δ13C values to the contributions of C3 and C4 plants. Assuming the air δ13C value is -7 permil, we can write the following equations:

-18 = x * (-33) + y * (-16) + (-7) * (1 - x - y) (equation 2)

Solving equations 1 and 2 simultaneously will provide us with the relative contributions of C3 and C4 plants.

Using the given δ13C values and solving the equations, we find:

x ≈ 0.88 (or 88%)

y ≈ 0.12 (or 12%)

Therefore, the estimated relative contribution of C3 plants is approximately 88%, while the estimated relative contribution of C4 plants is approximately 12% to the organic matter in Kenya's soil.

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Answer:

\(c=0.309\ J/g^{\circ} C\)

Explanation:

The increase in heat, Q = 58.1 J

Mass, m = 89.4 g

The temperature increases from 23.4°C to 25.5°C. We need to find the specific heat of an unknown metal.

We know that the increase in heat is given by :

\(Q=mc\Delta T\\\\c=\dfrac{Q}{m\Delta T}\\\\c=\dfrac{58.1}{89.4\times (25.5-23.4)}\\\\c=0.309\ J/g^{\circ} C\)

So, the specific heat of an unknown metal is equal to \(0.309\ J/g^{\circ} C\).

The concentration of the NaOH solution is 10.00 g/dm³.

To calculate the concentration in g/dm³ of a solution of NaOH containing 0.25 moles in 1 dm³, we need to know the molar mass of NaOH.

The molar mass of NaOH is calculated as follows:

Na (Sodium) = 22.99 g/mol

O (Oxygen) = 16.00 g/mol

H (Hydrogen) = 1.01 g/mol

Molar mass of NaOH = 22.99 g/mol + 16.00 g/mol + 1.01 g/mol = 40.00 g/mol

Now, we can calculate the concentration (C) using the formula:

C = (moles of solute) / (volume of solution in dm³)

C = 0.25 moles / 1 dm³

C = 0.25 mol/dm³

To convert moles to grams, we can multiply the molar mass by the number of moles:

Concentration in g/dm³ = (0.25 mol/dm³) * (40.00 g/mol)

Concentration in g/dm³ = 10.00 g/dm³

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Answer:

Mg(HCO3)2 + 2HCl → 2CO2 + 2H2O + MgCl2

Explanation:

Mg(HCO3)2 + 2HCl → 2CO2 + 2H2O + MgCl2

A. The compound with the shorter retention time in a gas chromatograph equipped with a nonpolar column would be 1-chloropropane.

The retention time in gas chromatography is determined by the strength of the interactions between the sample molecules and the stationary phase (in this case, a nonpolar column). Nonpolar compounds tend to have stronger interactions with nonpolar stationary phases than polar compounds do.

1-chloropropane is a more nonpolar compound than 1-bromopropane, which has a polar bromine atom. Therefore, 1-chloropropane will have stronger interactions with the nonpolar stationary phase, resulting in a shorter retention time.

It's also worth noting that the retention time for each compound will depend on the specific conditions of the experiment, such as the column temperature and the flow rate of the carrier gas.

B. It is unlikely that the retention times for the same sample run on a gas chromatograph several days later would be identical to those obtained the first time. There are several reasons why the retention times may not be identical:

Column aging: The stationary phase of the column can degrade over time, leading to changes in the interactions between the sample molecules and the column. This can result in changes in the retention times.

Temperature variations: Small differences in the column temperature between the two runs could result in changes in the retention times, as temperature affects the strength of the interactions between the sample molecules and the stationary phase.

Injection variations: The sample injection process is not always perfectly reproducible, which could lead to variations in the retention times.

Contamination: The column and injection port can be contaminated over time with the sample or other compounds, leading to changes in the retention times.

Overall, while the retention times are expected to be similar, small variations due to these factors should be expected.

Answer:

Mathematical

Explanation:

It shows how to find the hypotenuse

Answer:

if my calculation are correct, it's 295 grams

Explanation:

because liters converted to grams is .1=100 so if you take 2.95 times 100, it equals 295

Answer:

the rate is faster, and the time of reaction is 28 seconds

Explanation:

i did the test

Answer:

The rate is faster, 28 seconds

Explanation:

The ratio of parent to daughter isotope is 1:3  The correct Option is (b).

Half life is the time when reaction has proceeded to react half of the initial concentration of reactant to make the product.

for the first half life results in the ratio of 1/2 parent to 1/2 daughter isotope i.e. the ratio of parent to daughter isotope is 1:1

In case of second half life results in the ratio of 1/4 parent to 3/4 daughter isotope i.e. the ratio of parent to daughter isotope is 1:3

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The car can go 30 miles on one gallon of gas.

Distance is the sum of an object's movements, regardless of direction. Distance can be defined as the amount of space an object has covered, regardless of its starting or ending position.

Vehicles running on compressed natural gas (CNG) operate similarly to those driven by gasoline and equipped with spark-ignited internal combustion engines. The engine operates similarly to a gasoline engine. In a fuel tank, or cylinder, usually at the back of the car, natural gas is kept.

Gallons of gas used by car = 4

distance covered by car = 120 miles

the distance which can be covered by Aubree's car on one gallon of gas =120/4 = 30 miles

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Gravity is a (n) force between objects and depends on an object's size and their distance apart.

Gravitational force is the attractive that exist between all object with mass an object with mass attracts another object with mass the magnitude of the force is directly proportional to the masses of the two objects and inversely proportional to the square of the distance between the two objects

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A white powdery chemical sedimentary rock that does not react to hydrochloric acid could be chalk or gypsum.

Chalk is a soft, porous form of limestone composed primarily of the mineral calcite (calcium carbonate).

It is commonly used for writing on blackboards or as a dietary supplement. Gypsum, on the other hand, is composed of calcium sulfate dihydrate and is often used in construction materials such as drywall.

When hydrochloric acid is applied to gypsum, there is no significant effervescence or bubbling, indicating the absence of a chemical reaction.

This distinctive property allows geologists and mineralogists to identify gypsum in various geological formations and helps differentiate it from other minerals that may react with acid.

Both chalk and gypsum are relatively soft and can be easily scratched with a fingernail. They do not react with hydrochloric acid, as their main constituent minerals are not soluble in acid.

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