Assume that 2.5 ATPs are generated per NADH and 1.5 ATPs per FADH2. What is the total number of ATPs generated from 9 acetyl-SCoA molecules?

Answer:

Explanation:

Balanced forces  are opposite in direction and equal in size.

Balanced forces are  in a state of equilibrium.

Answer:

Balanced forces are forces whose net amount remains zero.

This can take place when two equal forces are acting in opposite direction.

Balanced forces don't make any  change in the position of objects

Among various electrochemistry technologies, lithium-ion batteries are considered the most cost-efficient due to their widespread use, decreasing prices, and high energy density.

Lithium-ion batteries have emerged as the dominant technology for energy storage in portable electronics, electric vehicles, and renewable energy systems. They offer a combination of high energy density, long cycle life, and relatively low self-discharge rates compared to other electrochemical technologies. These factors make them highly cost-efficient in a variety of applications.

One example of the cost efficiency of lithium-ion batteries can be seen in the electric vehicle (EV) market. Over the years, advancements in lithium-ion battery technology and increased production scale have led to significant cost reductions. This has resulted in a decline in the prices of EVs, making them more accessible to consumers. The cost efficiency of lithium-ion batteries has also been demonstrated in the renewable energy sector. Energy storage systems based on lithium-ion batteries allow for efficient integration of intermittent renewable energy sources, such as solar and wind power, into the grid. This helps stabilize the grid and reduce reliance on fossil fuels.

Furthermore, the high energy density of lithium-ion batteries enables compact and lightweight designs, making them suitable for portable electronics like smartphones and laptops. This not only enhances user convenience but also contributes to cost efficiency by reducing material and transportation costs. Additionally, the long cycle life of lithium-ion batteries ensures durability and longevity, further enhancing their cost efficiency as they require fewer replacements over their lifespan.

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Answer:

B

A

C

Explanation:

LiClO4=  B) Lithium perchlorate

LiCl=         A) Lithium chloride

LiClO2=    C) Lithium chlorite

Hope this helps

The correct match of the formula to its name is LiClO₄ is Lithium perchlorate , LiCl is Lithium Chloride and LiClO₂ is Lithium Chlorite.

A common name is defined by the IUPAC as a name that unambiguously defines a chemical, yet does not follow the current systematic naming convention.

Therefore, The correct match of the formula to its name is LiClO₄ is Lithium perchlorate , LiCl is Lithium Chloride and LiClO₂ is Lithium Chlorite.

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Answer:

option B = A rat hides in its hole when it sees an approaching predator.

Explanation:

In order for any organisms, whether plants or animals to be able to keep being alive they have to develop a/some functions or abilities which is going to aid in their battle battle for survival, this concept is known as the Adaptive features of organisms.

From the question above, it can be seen that the oversized ears in bats is an adaptive features for them to get their food: as it helps them to use sound waves to detect the motion of their prey.

Unlike the bats, the rats adaptive features is to have a good running legs. This will help them to avoid getting eating by predators.

Answer:just saying he is correct

Explanation:

Answer:

Line 3 is incorrect

Explanation:

In line 3, the statements should be switched. Chemical reactions involve small amounts of energy and nuclear reactions involve enourmous amounts of energy. Lines 1 and 2 are correct.

VOTE ME FOR BRAINLIEST!!

Answer:

Line 3 is incorrect

Explanation:

i took the test and got it right

The balanced redox reaction is :  6Hg(1) + Cr₂O₇²⁻ + 8H₂O + 16H⁺ + 6e⁻ → 3Hg₂⁺ + 2Cr .

To balance the redox reaction in basic solution:

Cr₂O₇²⁻ (aq) + Hg(1) → Hg²⁺ (aq) + Cr³⁺ (aq)

Step 1: Assign oxidation states to each element:

Cr₂O₇²⁻: Cr has an oxidation state of +6, and each oxygen atom has an oxidation state of -2. Therefore, the total oxidation state of Cr₂O₇²⁻ is 2 × (+6) + 7 × (-2) = +6 - 14 = -8.

Hg(1): Mercury in its elemental form has an oxidation state of 0.

Hg²⁺: The oxidation state of Hg²⁻ is +2.

Cr³⁺: The oxidation state of Cr³⁺ is +3.

Step 2: Separate the reaction into two half-reactions, oxidation, and reduction.

Oxidation half-reaction: Hg(1) → Hg²⁺

Reduction half-reaction: Cr₂O₇²⁻ → Cr³⁺

Step 3: Balance the atoms and charges in each half-reaction.

Oxidation half-reaction: Hg(1) → Hg²⁺

Since there is no charge on either side, the atom is already balanced.

Reduction half-reaction: Cr₂O₇²⁻ → Cr³⁺

There are two Cr atoms on the left side and one Cr atom on the right side, so we need to balance the Cr atoms by adding a coefficient of 2 in front of Cr³⁺

Cr₂O₇²⁻ → 2Cr³⁺

Step 4: Balance the oxygen atoms by adding water (H₂O) molecules to the side that needs them.

There are 14 oxygen atoms on the left side (in Cr₂O₇²⁻) and 6 oxygen atoms on the right side (in 2Cr³⁺). To balance the oxygen atoms, we need to add 8 water molecules (H₂O) to the right side.

Cr₂O₇²⁻ + 8H₂O → 2Cr³⁺ + 14OH⁻

Step 5: Balance the hydrogen atoms by adding hydrogen ions (H⁺) to the side that needs them.

There are 16 hydrogen atoms on the right side (in 14OH⁻ and 2Cr³⁺). To balance the hydrogen atoms, we need to add 16 hydrogen ions (H⁺) to the left side.

Cr₂O₇²⁻ + 8H₂O + 16H⁺ → 2Cr³⁺ + 14OH⁻

Step 6: Balance the charges by adding electrons (e⁻) to the side that needs them.

The total charge on the left side is -2 (from Cr₂O₇²⁻) and the total charge on the right side is 0 (from 2Cr³⁺ and 14OH⁻). To balance the charges, we need to add 6 electrons (e⁻) to the left side.

Cr₂O₇²⁻ + 8H₂O + 16H⁺ + 6e⁻ → 2Cr + 14OH⁻

Now, the oxidation and reduction half-reactions are balanced.

Step 7: Combine the two half-reactions.

To combine the half-reactions, we need to ensure that the number of electrons (e⁻) is equal on both sides. Multiply the oxidation half-reaction by 6 to balance the electrons.

6Hg(1) → 3Hg²⁺ + 6e⁻

Now, we can combine the two half-reactions:

6Hg(1) + Cr₂O₇²⁻ + 8H₂O + 16H⁺ + 6e⁻ → 3Hg²⁺ + 2Cr

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Answer:

both are caused by heating

Answer:

the nuclear envelope disappears

Explanation:

Answer:

In the first stage of cell division, before metaphase, during which the chromosomes become visible as paired chromatids and the nuclear envelope disappears.

Explanation:

The acid dissociation constant Ka is 1.52 × \(10^{-5}\).

Acid dissociation constant:

Ka or the acid dissociation constant is the value that differentiates the weak and strong acids from each other and tells about the dissociation of the acid in the solution.

Dissociation of acid is:

HA ----> \(H^{+}\) + \(A^{-}\)

Initially, the concentration of the reaction is c and the final reaction is 0.

In the equilibrium, the concentration of the reactant is c( 1 - α ) and the final reaction is cα.

The dissociation constant formula:

\(K_{a}\) = cα × cα / c( 1 -α)

We know that [\(H^{+}\)] = cα.

pH = -log[\(H^{+}\)]

It is given that:

pH = 2.81

The concentration of hydrogen ions is  1.5 × \(10^{-3}\)

Substituting the value in the equation we get:

1.5 × \(10^{-3}\) = 1.46 α

α = 0.00102

\(K_{a}\) = (1.46 × 0.00102)² / 1.46( 1 - 0.00102)

    = 0.00002204/ 1.458

    = 0.0000152

    = 1.52 × \(10^{-5}\)

Therefore Ka is 1.52 ×\(10^{-5}\)

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Answer:

23%

Explanation:

Answer:

2.688 L

Explanation:

Here we use the formula:

(P1 x V1)/T1  =  (P2 x V2)/T2

where;

P1 = 417 mm of Hg

P2 = 576 mm of Hg

V1 = 4.78 L

V2 = X L

T1 = 497 K

T2 = 386 K

substituting the values in the formula:

(417 x 4.78)/497 = (576 x X)/386

1993.26/497  = 576X/386

(4.01058 x 386)/576 = X

2.688 L = X

The  new volume of the cylinder when pressure increases to 576 mm Hg

and temperature decreases to 386 K is 2.688 liters.

Pressure is defined as the force applied on an object perpendicular to it's surface per unit area over which it is distributed.Gauge pressure is a pressure which is related with the ambient pressure.

There are various units by which pressure is expressed most of which are derived units which are obtained from unit of force divided by unit of area . The SI unit of pressure is pascal .

It is a scalar quantity which is related to the vector area element with a normal force acting on it.It is distributed over solid boundaries and across arbitary sections of fluid normal to the boundaries at every point.

Here we use the formula:

(P₁x V₁)/T₁ =  (P₂ x V₂)/T₂

where;P₁ = 417 mm of Hg,P₂ = 576 mm of Hg,V₁= 4.78 L,V₂= X L,T₁ = 497 K,T₂ = 386 K

substituting the values in the formula:

(417 x 4.78)/497 = (576 x X)/386

1993.26/497  = 576 X/386

(4.01058 x 386)/576 = X

2.688 L = X

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Answer:

D i belive

Explanation:

Answer:

B When the molecule contains polar bonds.

Explanation:

AP-EXpert

The shape of a molecule affect its polarity, when the molecule contains polar bonds because polarity depends on polar bonds.

The polarization of a molecule greatly depends on the shape of the molecule. The net dipole moment occurs only due to the uneven distribution of electrons between the two atoms.

So we can conclude that the shape of a molecule affect its polarity, when the molecule contains polar bonds because polarity depends on polar bonds.

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The opposite of heterotroph is autotroph.

What is heterotroph?

An organism is referred to as a heterotroph if it consumes other plants or animals for food and energy. Its origins are in the Greek words hetero, which means "other," and trophe, which means "nutrition."

Examples - Human, birds, dogs, etc.

What is autotroph?

A primary producer, also known as an autotroph, is an organism that uses energy from light or inorganic chemical reactions to create complex organic chemicals from simple ones, such as carbon dioxide.

Example - plants, algae etc.

The opposite of heterotroph is autotroph.

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The rate law for the given reaction is Rate = 0.208[A], where the reaction is first-order and the rate constant (k) is 0.208 h⁻¹.

The rate law for the reaction is: Rate = k[A]
1. Since you are given that when ln[A] is plotted against time, a straight line with a slope of -0.208 h⁻¹ is obtained, we can infer that the reaction is a first-order reaction.

This is because a first-order reaction follows the integrated rate law equation: ln[A] = -kt + ln[A₀], where k is the rate constant, t is the time, and [A₀] is the initial concentration of A.
2. The slope of the straight line obtained is equal to the negative of the rate constant (k). In this case, the slope is -0.208 h⁻¹. So, k = 0.208 h⁻¹.
3. Now that we have determined the reaction to be first-order and found the rate constant (k), we can write the rate law for the reaction: Rate = k[A]. Since k = 0.208 h⁻¹, the rate law becomes: Rate = 0.208[A].
The rate law for the given reaction is Rate = 0.208[A], where the reaction is first-order and the rate constant (k) is 0.208 h⁻¹.

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Answer:

If this is for the "functional groups" question:

1. aldehyde

2. ketone

3. ester

4. carboxylic acid

Explanation:

Got them all right on edge.

The drop-down menus to identify the names of the structures in the table to the right

1. Aldehyde

2. Ketone

3. Ester

4. Carboxylic acid

A functional group in organic chemistry is a pool of atoms within molecules which bind jointly to react in predicted ways.

Examples of functional groups contain the group hydroxyl, ketone, amine, and ether.

Thus, these are the drop down menus.

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Answer:In the image tag alt is used to display an alternate 'thing' in case your image is unable to load properly due to whatever reason. This alternate 'thing' is in the form of text which describes what was the image all about. In your case it's so if it fails to load then whatever is written in the alt attribute will show up and if you had also left alt blank like in your defined question then the icon of the broken image will show up.

Explanation:

Answer:

Nonpolar molecules dissolve in nonpolar solvents through a process called dispersion forces or London forces.

In nonpolar molecules, the electrons are evenly distributed and there is no permanent dipole moment, which means that the molecule has no positive or negative poles. When nonpolar molecules are added to a nonpolar solvent, such as oil or hexane, the molecules are attracted to one another due to London dispersion forces.

London forces are due to temporary fluctuations in electron density within molecules, creating temporary dipoles. These temporary dipoles induce corresponding temporary dipoles in other nearby molecules, attracting them to each other. The strength of the London dispersion forces increases with the size of the molecule, since larger molecules have more electrons and a greater potential for temporary dipoles.

In general, nonpolar molecules bind together in nonpolar solvents through these weak intermolecular forces, allowing them to dissolve and form a homogeneous solution.

Explanation:

Speed of sound -- 1/5 mile per second

Pitch - -  it describes the loudness of a sound.

Vibrations - - 256 vibrations per second.

Amplitude - - describing the sound as high or low.

compression - - the part of the sound wave where molecules of air are pushed together.

Solids - - sound travels through this medium faster than through air.

The source of all sound - - middle C on the piano.

The speed of a sound is the distance traveled by a sound in a given time period.

Speed of sound = 1/5 mile per second

It is the position of a single sound in the complete range of sound.

It describes the loudness of a sound.

256 vibrations per second

describing the sound as high or low

The part of the sound wave where molecules of air are pushed together

sound travels through this medium faster than through air

middle C on the piano

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pitch - describing sound as high or low

256 vibrations per second - middle C on the piano

1/5 mile per second - the speed of sound

amplitude - the loudness of a sound

compression -  the part of the sound wave where molecules of air are pushed together

solids - sound travels through this medium faster than through air

vibrations - the source of all sound

The rate law for the reaction between iodide ion and dibromothane (C₂H₄Br₂) in methanol is determined to be Rate = k[C₂H₄Br₂][I], indicating that the reaction is first-order with respect to both reactants.

The rate constant (k) for the reaction is calculated to be approximately 4.88 M⁻¹s⁻¹ using the initial rate data from Experiment 1.

The rate of consumption of iodide ion (I) is estimated to be around 1.79 M/s when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M.

The activation energy (Ea) for the reaction is found to be approximately 51.3 kJ/mol using the Arrhenius equation and temperature data from Experiment 4.

To determine the rate law, we need to examine how the initial rates change with respect to the initial concentrations of the reactants. Let's consider the first experiment (Experiment 1) and compare it with the other experiments:

Experiment 1: [C₂H₄Br₂]₀ = 0.127 M, [I]₀ = 0.102 M, Initial rate = 6.45x10⁻² M/s

Experiment 2: [C₂H₄Br₂]₀ = 0.254 M (2 * [C₂H₄Br₂]₀), [I]₀ = 0.127 M (2 * [I]₀), Initial rate = 0.102 M/s (2 * Initial rate)

Experiment 3: [C₂H₄Br₂]₀ = 0.204 M (1.6 * [C₂H₄Br₂]₀), [I]₀ = 1.29x10⁻² M (0.126 * [I]₀), Initial rate = 0.204 M/s (3.16 * Initial rate)

From the comparisons above, we can see that doubling the initial concentrations of both reactants (Experiment 2) doubles the initial rate, indicating that the reaction rate is first-order with respect to both [C₂H₄Br₂] and [I].

The rate law for the reaction can be expressed as:

Rate = k[C₂H₄Br₂]ᵃ [I]ᵇ

Since the reaction is first-order with respect to both reactants, we have a = 1 and b = 1.

Therefore, the rate law for the reaction is:

Rate = k[C₂H₄Br₂][I]

To determine the rate constant (k), we can choose any of the experiments and use the given data. Let's use Experiment 1:

[C₂H₄Br₂]₀ = 0.127 M

[I]₀ = 0.102 M

Initial rate = 6.45x10⁻² M/s

Plugging these values into the rate law equation, we can solve for k:

6.45x10⁻² = k(0.127)(0.102)

k = 6.45x10⁻² / (0.127)(0.102)

k ≈ 4.88 M⁻¹s⁻¹

So, the rate constant for the reaction is approximately 4.88 M^(-1)s^(-1).

Now, to determine the rate of consumption of iodide ion (I) when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M, we can use the rate law:

Rate = k[C₂H₄Br₂][I]

Plugging in the given concentrations and the rate constant we just determined:

Rate = (4.88 M^(-1)s⁻¹)(0.74 M)(0.52 M)

Rate ≈ 1.79 M/s

Therefore, the rate of consumption of iodide ion when [C₂H₄Br₂]₀ = 0.74 M and [I]₀ = 0.52 M is approximately 1.79 M/s.

The Arrhenius equation is given as:

k = Ae^(-Ea/RT)

where k is the rate constant, A is the pre-exponential factor, Ea is the activation energy, R is the gas constant (8.314 J/(mol·K)), and T is the temperature in Kelvin.

From the given data, we have:

Experiment 1: T = 20°C = 293 K

Experiment 2: T = 20°C = 293 K

Experiment 3: T = 20°C = 293 K

Experiment 4: T = 40°C = 313 K

Let's consider Experiment 1:

[C₂H₄Br₂]₀ = 0.127 M

[I]₀ = 0.102 M

Initial rate = 6.45x10⁻² M/s

We can rearrange the rate law equation to solve for the pre-exponential factor (A):

A = k / ([C₂H₄Br₂]₀[I]₀)

Plugging in the values for Experiment 1:

A = (4.88 M⁻¹s⁻¹) / (0.127 M * 0.102 M)

A ≈ 37.80 s⁻¹

Now, we can use the Arrhenius equation with Experiment 4 to determine the activation energy (Ea):

k = Ae^(-Ea/RT)

Rearranging the equation:

ln(k) = ln(A) - (Ea/RT)

Taking the natural logarithm of the rate constant from Experiment 4:

ln(k) = ln(1.79 M/s)

Substituting the values into the equation:

ln(1.79 M/s) = ln(37.80 s^(-1)) - (Ea / (8.314 J/(mol·K) * 313 K))

Simplifying the equation:

ln(1.79) = ln(37.80) - (Ea / (8.314 * 313))

Now, solve for Ea:

Ea = -(ln(1.79) - ln(37.80)) * (8.314 * 313)

Ea ≈ 51,253 J/mol or 51.3 kJ/mol

Therefore, the activation energy for this reaction is approximately 51.3 kJ/mol.

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Answer:

La configuración electrónica del aluminio es: 1s² 2s² 2p⁶ 3s² 3p¹

Explanation:

El aluminio es un elemento semimetálico de número atómico Z= 13. Con el número atómico y el diagrama de Moeller se puede hallar su configuración electrónica:

1s² 2s² 2p⁶ 3s² 3p¹

3 half-lives have passed for 87.5% decomposition, and 17 half-lives for 99.999% decomposition.

To determine the number of half-lives that have passed, you can use the formula N = (log N0 - log N)/log 2, where N0 is the initial amount, N is the remaining amount, and log is the logarithmic function. For 87.5% decomposition, the remaining amount is 12.5% or 0.125N0, which means that N/N0 = 0.125. Plugging this into the formula, you get N = 3. For 99.999% decomposition, the remaining amount is 0.00001N0, which means that N/N0 = 0.00001. Plugging this into the formula, you get N = 5. For 87.5% decomposition, 12.5% remains. Let x be the number of half-lives: 0.125 = (1/2)^x. Solving for x, we get x ≈ 3 half-lives. For 99.999% decomposition, 0.001% remains. Using the same formula: 0.00001 = (1/2)^y. Solving for y, we get y ≈ 17 half-lives. So, 3 half-lives have passed for 87.5% decomposition, and 17 half-lives for 99.999% decomposition.

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Answer:True

Explanation: An anion has a larger radius than a neutral atom because it gains valence electrons. There are added electron/electron repulsions in the valence shell that expand the size of the electron cloud, which results in a larger radius for the anion.

hit the crown for me pls :)

Have a great day

Considering the chemical and physical properties of elements, the elements can be arranged into groups in the periodic table as follows:

Group 1 to 3 - metals

Group 14 - non-metals, metalloids, and metals

Group 15 to 18 - non-metals

Groups of elements refer to vertical columns or families that contain elements with similar chemical properties.

Each group in the periodic table has distinct properties and trends. For example:

These are just a few examples of the groups in the periodic table, and each group exhibits unique chemical properties and trends.

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Answer: B - Dilating the blood vessels and increasing blood supply the skin.

Explanation:

If body temperature rises, blood vessels in the skin dilate, allowing more blood to flow near the skin’s surface. This allows heat to dissipate through the skin and into the surrounding air.

87.9 milligrams of helium are produced by an initially pure 12.0 g 239pu after  20,000 years

The law of exponential decay is given by:

       N=N0 *e^ −λt  

where

   N0 is initial moles of plutonium

   λ is disintegration constant

   t=given time

         λ= ln2/T

  T is half life of  239pu

The number of atoms that have decayed equals the number of undecayed  atoms N subtracted from the initial atoms, that is:

         N0-N=  N0-N0*\(e^{-\frac{ln2 * t}{T} }\)

                   = N0(1-\(e^{-\frac{ln2 * t}{T} }\)  )

         N0=M*(\(N_{A}\))/M

         N0-N=1.3226  * \(10^{22}\)

\(m_{HE}\)=  \(\frac{(N0-N)*m_{HE}}{N_{A}}\)  

         = (1.3226  * \(10^{22}\)) *(4)  / (6.023 * \(10^{23}\)  )

        =0.0879 g

        = 87.9 mg

So ,87.9 milligrams of helium are produced.

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