at 25 oc the solubility of barium sulfate is 1.05 x 10-5 mol/l. calculate the value of ksp at this temperature.

Answer:

See explanation

Explanation:

The size of the hydration enthalpy of a system depends on the attraction between the ions and the water molecules. Stronger attractions exist between water and smaller ions. The smaller the ion, the higher the hydration enthalpy is.

In the first pair, Na+ is smaller than Cs+ hence Na+ has a larger change in hydration enthalpy.

In the second pair, Sr2+ is smaller than Rb+ hence Sr2+ has a larger change in hydration enthalpy.

In the third pair, Na+ is smaller than Cl- hence Na+ has a larger change in hydration energy.

F- is smaller than O2- hence F- has a larger change in hydration energy.

OH- is smaller than the SH- hence the OH- has a larger change in hydration energy.

Answer:

2Na + 2H2O → 2NaOH + H2

Explanation:

A balanced equation is an equation for a chemical reaction in which the number of atoms for each element in the reaction and the total charge are the same for both the reactants and the products.

Answer:

1:loses or gains energy

The concentration of the vial is 0.5 %. We will suppose that it is % w/v. The concentrarion % w/v is defined as:

% w/v = mass of solute in g/volume of solution in mL * 100

We have to find the mL that we have to administer to deliver 20 mg. Let's convert those mg into g. We know that there are 1000 mg in 1 g.

1000 mg = 1 g

mass of solute in g = 20 mg * 1 g/(1000 mg)

mass of solute in g = 0.020 g

Now that we know the concentration of the solution and the mass in grams of the medication, we can find the volume in mL.

% w/v = mass of solute in g/volume of solution in mL * 100

0.5 = 0.020 / volume of solution in mL * 100

volume of solution in mL = 0.5/(100 * 0.020)

volume of solution in mL = 0.25 mL

Answer: we need to administer 0.25 ml

Answer:

3

Explanation:

The arid and semi-arid regions located poleward of the equator on an idealized supercontinent represent the trade wind feature.

The constant east-to-west predominant winds that blow in the equatorial region of the Earth are known as the trade winds or easterlies. The trade winds are strongest during the winter and when the Arctic oscillation is in its warm phase, and they primarily originate from the northeast in the Northern Hemisphere and the southeast in the Southern Hemisphere.

For generations, sailing ship captains have exploited the trade winds to navigate the world's waters. As it descends, the temperature rises while the moisture content stays constant, lowering the relative humidity of the air mass, making subsident (sinking) air comparatively dry. This hot, dry air is referred to as trade wind.

Usually found above a marine tropical (warm and wet) air mass, this warm, dry air is often referred to as a superior air mass. A temperature inversion is a rise in temperature with height. A trade wind inversion is what it is called when it happens during a trade wind regime.

Learn more about trade winds here:

https://brainly.com/question/13432679

#SPJ4

In the given chemical reaction, H₂O (g) + C (s) ⇌ CO (g) + H₂ (g), if 0.1 M steam reacts with solid carbon, the equilibrium concentrations of H₂O, CO and H₂ are 0.058 M, 0.042 M and 0.042 M, respectively. The K for this reaction is 0.16.

Given,

Concentration of steam (H₂O) = 0.1 M

K = 0.16

The chemical reaction is given by: H₂O (g) + C (s) ⇌ CO (g) + H₂ (g
)We can write the equilibrium constant expression as:
Kc= [CO] [H₂] / [H₂O]

The balanced chemical equation of the reaction can be used to create an ICE table to determine the concentrations at equilibrium. The initial concentration of H₂O is 0.1M and the initial concentration of carbon is 1.0M. At equilibrium, the concentration of CO and H₂ are x M. Therefore, the concentrations at equilibrium are given below:

The answer is:   H₂O(g) + C(s) ⇌ CO(g) + H₂(g)
Initial concentration (M)0.1
Change in concentration (M)–x  –x+ x  + x

Equilibrium concentration (M)0.1–x   1–x + x  x

We can substitute the equilibrium concentrations of all the species in the equilibrium constant expression to obtain:
Kc = [CO] [H₂] / [H₂O]
Kc = x * x / (0.1 – x)
Kc = 0.16x2

Kc = 0.016 – 0.16x0.16x + 0.016

Kc = 0

Therefore, x ≈ 0.042 M

The equilibrium concentration of H₂O is 0.1 – 0.042 = 0.058 M
The equilibrium concentration of CO is 0.042 M
The equilibrium concentration of H₂ is 0.042 M.

to know more about Equilibrium visit:

brainly.com/question/30694482

#SPJ11

Among the options given, the hydrogen atom (H) is not one of the four groups attached to the alpha-carbon.

In an amino acid, the central (alpha) carbon is indeed bonded to four groups. These four groups are:

Amino group (-NH₂): This group consists of a nitrogen atom bonded to two hydrogen atoms. It is called the amino group and gives amino acids their name.

Carboxyl group (-COOH): This group consists of a carbon atom double-bonded to an oxygen atom and single-bonded to a hydroxyl group (-OH). It is called the carboxyl group and is responsible for the acidic properties of amino acids.

Hydrogen atom (H): A single hydrogen atom is also attached to the central carbon.

Side chain (R group): The fourth group attached to the alpha-carbon is the side chain, also known as the R group. The side chain varies among different amino acids and gives each amino acid its unique properties.

Therefore, among the options given, the hydrogen atom (H) is not one of the four groups attached to the alpha-carbon.

The completed question is given as,

All amino acids share a common structure, a central (alpha) carbon with four groups attached. Which of these is NOT one of the four groups attached to the alpha- carbon?

an R group

an ammonium group (-NH³⁺)

a carboxylate group (-COO)

a hydrogen atom

Learn more about amino acid from the link given below.

https://brainly.com/question/31442968

#SPJ4

To make a 50.0 mL solution of 1.7 M sodium carbonate (Na₂CO3), we need to determine the mass of Na₂CO3 required.

To calculate the mass of Na₂CO3 needed, we can use the formula:

Mass = Concentration x Volume x Molar Mass

First, we convert the given volume from milliliters to liters:

Volume = 50.0 mL = 50.0/1000 L = 0.05 L

Next, we substitute the given concentration and volume values into the formula:

Mass = 1.7 M x 0.05 L x Molar Mass of Na₂CO3

The molar mass of Na₂CO3 can be calculated by adding the atomic masses of sodium (Na), carbon (C), and three oxygen (O) atoms:

Molar Mass of Na₂CO3 = (2 x Atomic Mass of Na) + Atomic Mass of C + (3 x Atomic Mass of O)

After obtaining the molar mass value, we can substitute it into the formula and perform the calculation to determine the mass of Na₂CO3 required to make the 50.0 mL solution of 1.7 M sodium carbonate.

To know more about sodium carbonate click here:

https://brainly.com/question/24475802

#SPJ11

Explanation:

guess

exothermic because of the heat

A structural isomer is a compound that has the same number of atoms but is arranged differently. Therefore, to know which will be the structural isomer of the compound they give us, we must count the atoms of each compound.

When comparing the compounds we see that pent-2-yne has C5H8 just like 3-methylcyclobutene, therefore these two compounds are structural isomers.

The answer will be: 3-methylcyclobutene

2-hexanone is more reactive than 3-hexanone.

The reactivity of a ketone can be influenced by the position of the carbonyl group relative to the alkyl substituents. In the case of 2-hexanone and 3-hexanone, the position of the carbonyl group differs.

2-hexanone has the carbonyl group located on the second carbon of the hexane chain, whereas 3-hexanone has the carbonyl group on the third carbon. The reactivity of ketones typically increases as the carbonyl group is closer to the end of the alkyl chain.

In this case, 2-hexanone has a more reactive carbonyl group than 3-hexanone because it is closer to the end of the carbon chain. The proximity to the end of the chain allows for greater accessibility and interaction with nucleophiles during reactions.

The increased reactivity of 2-hexanone can be attributed to the greater electronic and steric effects experienced by the carbonyl group, which make it more susceptible to nucleophilic attack or other chemical transformations compared to 3-hexanone.

To learn more about ketones, here

https://brainly.com/question/30167255

#SPJ4

Answer:

Some examples of quantitative data include:

Revenue in dollars.

Weight in kilograms.

Age in months or years.

Length in centimeters.

Distance in kilometers.

Height in feet or inches.

Number of weeks in a year.

Qualitative data describes qualities or characteristics. It is collected using questionnaires, interviews, or observation, and frequently appears in narrative form. For example, it could be notes taken during a focus group on the quality of the food at Cafe Mac, or responses from an open-ended questionnaire

Explanation:

please add me as brainliest...

3. 426 g

4.  413.4 g

5. 1328.4 g

6. 192.4 g

7. 106.4 g

8. 0.617 mol

Given

moles and mass

Required

Conversion mole to gram

Solution

General formula :

mole (n) = mass : MW

3. 6 moles Cl₂(MW = 71 g/mol) :

= 6 moles x 71 g/mol

= 426 g

4. 5.3 moles CaF₂(MW=78 g/mol)

= 5.3 mol x 78 g/mol

= 413.4 g

5. 8.2 moles FeCl₃(MW=162 g/mol)

= 8.2 mol x 162

= 1328.4 g

6. 2.6 moles Li₂CO₃(MW=74 g/mol)

= 2.6 mol x 74 g/mol

= 192.4 g

7. 3.8 moles N₂(MW=28 g/mol)

= 3.8 mol x 28 g/mol

= 106.4 g

8. 100 g FeCl₃(MW=162 g/mol)

= 100 g : 162 g/mol

= 0.617 mol

Answer:

The homologous series of straight-chained alkanes

Explanation:

Butane belongs to Alkane homologous series.

Note -

A homologous series is a group of organic compounds having similar structures and similar chemical properties in which the successive compounds differ by CH₂ group.

Answer:

igneous,sedimentary,and metamorphic

Explanation:

Rocks are collections of minerals of various sizes and types. The three main rock types are igneous, sedimentary, and metamorphic. Crystallization, erosion and sedimentation, and metamorphism transform one rock type into another or change sediments into rock.

Answer:

5648.4 Joules

Explanation:

This problem can be solved by the calorimetry formula:

Q = C . m . ΔT

where ΔT indicates the change of temperature

Final T°  - Initial T°

m = mass

C = specific heat of water and Q = Heat

We do not have m, but we have the volume of water. We can obtain mass from density.

Volume of water = 10 cm . 4cm . 2.50 cm = 100 cm³

1 cm³ = 1 mL

Density of water = 1 g/mL

Therefore our 100 mL of water is the volume for 100 g. We replace data:

Q = 4.184 J/g°C . 100 g . (32°C - 18.5°C)

Q = 5648.4 Joules

Answer:

A: Entropy tends to increase in a system

Which is a statement of the second law of thermodynamics?

O A. Entropy tends to increase in a system.

O B. Molecular motion stops at absolute zero.

O C. The net reaction rate is zero at equilibrium.

O D. Energy cannot be created or destroyed.

ITS A

an arithmetical multiplier for converting a set of units to another set of units. For example, a foot is 12 inches, so if you were to convert three feet to inches the equation would be 3ft/Xin and you would multiply three by twelve to get 36 inches.

Answer:

\(V_{2} = 29.28\,L\)

Explanation:

Let assume that gas behaves ideally and experiments an isobaric and isothermal processes. The following relationship is applied to determined the final volume:

\(\frac{V_{1}}{n_{1}} = \frac{V_{2}}{n_{2}}\)

\(V_{2} = V_{1} \cdot \left(\frac{n_{2}}{n_{1}} \right)\)

\(V_{2} = (12.2\,L)\cdot \left(\frac{16.8\,moles}{7\,moles} \right)\)

\(V_{2} = 29.28\,L\)

Answer:

It is in the same phase as the reactants.

Explanation:

i took the test

particulates Is not an examples of primary air pollutants , but sulfur dioxide. carbon dioxide. tropospheric ozone. nitrogen oxide is a example of air pollutant.

Three gasses (O3) combine to form the odorless, colorless gas known as ozone, which occurs naturally in the atmosphere. Both the upper atmosphere of the Earth, known as the stratosphere, and the lower atmosphere, known as the troposphere, can contain it.

Ozone is created in the atmosphere as a result of chemical interactions involving pollutants released from various sources, including as paint evaporation, combustion, consumer products, factories, and other industrial sources.

To know more about air pollutants visits:

https://brainly.com/question/21683809

#SPJ1

The reaction of CH₃CH₂MgBr with CH₃COCH₂CH₃ gives the product , the right answer of choice is : an achiral product.

An achiral product is the identical with  its mirror image. the achiral compound is superimposable on its mirror image. an achiral product is the product which is as same as its mirror image . the achiral compound is superimposable. while the chiral object is not identical with its mirror image. the chiral compound is not superimposable it its mirror image.

Thus, an achiral product is formed by the reaction of the CH₃CH₂MgBr with CH₃COCH₂CH₃ which is superimposable to its mirror image.

To learn more about achiral here

https://brainly.com/question/25055449

#SPJ4

Answer:

0.694 cents per second

Explanation:

25x100=2500 cents per hour, 2500/60 = 41.67 per minute and 41.67/60=0.694 cents per second

Answer:

The reaction has a high activation energy

Explanation:

The burning of methane is a spontaneous reaction. Once the burning begins, the flame is able to sustain itself without any additional input of energy. It is an exothermic reaction in which energy is given out in the form of heat.

The reason why heat from the match is needed to start the burning of methane is that the activation energy of the combustion of methane is high. Activation energy is the energy that must be supplied in order for the collision of reactants to result in chemical reaction.

As long as the activation energy is high, the reaction can not occur without an external input of energy (e.g striking a match). Hence the answer.

It's important to know that the reaction must have the total mass involved before and after due to the law of conservation of mass. This means that the total mass number of the left side of the reaction must be equal to the right side. So, we have the following

Notice that 235 is the mass number of U, 1 is the mass number of the neutron, X represents the mass number of the unknown element, 141 represents the mass number of Ba, and 3 represents the mass number of three neutrons. This means X should have a mass number of 92, which is the element Kr.

Therefore, the mass number is 92 and the chemical symbol is Kr.

Chemical Indicator refers to a substance that changes color when there is a certain concentration of hydrogen ions in a solution.

Chemical indicators are any substances that provide a clear indication—typically a change in color—of the presence or absence of a certain chemical species, like an acid or an alkali, in a solution. One such chemical is methyl yellow, which gives an alkaline solution a yellow color. When introduced to acidic or alkaline solutions, substances are considered indicators when their color changes. There are several indicators that are frequently used in laboratories, including litmus, phenolphthalein, and methyl orange. Litmus paper: It turns red in acidic solutions and blue in basic ones. Methyl orange: This chemical exhibits a red color in an acidic solution and a yellow color in a basic solution.

Learn more about Chemical indicators

brainly.com/question/13748767

#SPJ4

When you are awake and your blood sugar levels are very low, you would expect the enzyme Glycogen phosphorylase to be activated in your liver cells. The correct answer is Option B.

Glycogen phosphorylase is responsible for breaking down glycogen into glucose molecules, which can be released into the bloodstream to raise blood sugar levels. This process is known as glycogenolysis and occurs when the body needs a quick source of glucose for energy.

Glycogen synthase, on the other hand, is involved in the synthesis of glycogen from glucose molecules and is typically active when blood sugar levels are high and there is excess glucose available for storage.

Hexokinase is an enzyme that initiates the first step of glucose metabolism, converting glucose into glucose-6-phosphate. It is not directly involved in glycogen breakdown or synthesis.

Protein Phosphatase-1 is an enzyme involved in regulating various cellular processes but is not directly involved in glycogen metabolism.

Therefore, the correct answer is Option B: Glycogen phosphorylase.

You can learn more about Glycogen phosphorylase at

https://brainly.com/question/17100824

#SPJ11

The hazardous substance in automobile exhaust that is also present in high concentration in tobacco smoke is acrolein.

Substance that tobacco smoke and the exhaust of automobiles contains a has it is substance called acrolein in very very high concentration.

Inhaling acrolein can give rise to several breathing problems like shortness in breathing and also irritation in lungs.

Acrolein is formed when the fats are overheated apart from automobiles and tobacco a very low amount of acrolein is also found in over used cooking oil.

To reduce acrolein from the automobile exhaust lead based adsorption substances are preferred to be used in automobile exhaust.

To know more about acrolein, Visit,

https://brainly.com/question/6224949

#SPJ4

Given data:H2O vapor content: 13 gramsH2O vapor capacity: 52 grams at 25 degrees Celsius 13 grams at 10∘C52 grams at 30∘CFormula used to find the dew point:$$\dfrac{13}{52}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$\frac{1}{4}=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$

Where A is the constantDew Point:It is the temperature at which air becomes saturated with water vapor when the temperature drops to a point where dew, frost or ice forms. To solve this question, substitute the given data into the formula.$$13/52=\dfrac{(A*3\pi)/(ln100)}{(17.27-A)}$$$$13(17.27-A)=3\pi A(ln100)$$By simplifying the above expression, we get$$A^2-17.27A+64.78=0$$Using the quadratic formula, we get$$A=9.9,7.4$$

The dew point is 7.4 since it is less than 10°C.More than 100:The term "More than 100" has not been used in the question provided.

To know more about temperature  visit:

https://brainly.com/question/7510619

#SPJ11