At 70 °C, the solubility of an unknown solute is 67.3 g/100.0 g of water. What mass of the solute can dissolve in 141.9 g of water at the same temperature?

(alt + F4) might be the answer you are looking

Explanation:

I'm not exactly sure how I came up with this answer but it is for sure the answer

Maintain ion balance, cells use various mechanisms such as ion pumps and channels to regulate the movement of ions across the membrane.

If the cytosol loses K+ ions through leak channels, it will become more negatively charged or more polarized. This is because K+ ions are positively charged and their loss creates an imbalance of charges in the cytosol, resulting in a net negative charge. This can affect various cellular processes that depend on proper ion balance, such as cell signaling and muscle contraction. To maintain ion balance, cells use various mechanisms such as ion pumps and channels to regulate the movement of ions across the membrane.

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If there is initially 0.420 atm of H2O2(g), the equilibrium partial pressures in atm of H2(g), O2(g), and H2O2(g) are 0.314 atm and if the volume is doubled, the total pressure of the system will be reduced to half of the original pressure due to the gas law.

a) Using the given equilibrium constant, we can set up an ICE (Initial, Change, Equilibrium) table to calculate the equilibrium partial pressures:

⇒            2H2O2(g) ⇌ 2H2(g) + O2(g)

Initial: 0.420 atm 0 atm 0 atm

Change: -x +2x +x

Equilibrium: 0.420-x 2x x

Substituting the values into the equilibrium constant expression:

⇒             Kc = [H2]^2[O2]/[H2O2]^2 = 7.109

⇒           7.109 = (2x)^2/(0.420-x)^2

Solving for x, we get x = 0.106 atm

Therefore, at equilibrium, the partial pressures of H2, O2, and H2O2 are:

⇒          PH2 = 2x = 0.212 atm

⇒          PO2 = x = 0.106 atm

⇒         PH2O2 = 0.420 - x = 0.314 atm

b) According to Le Chatelier's principle, the equilibrium will shift in the direction that opposes the change. When the volume is doubled, the system will try to reduce the pressure by shifting towards the side with fewer moles of gas. Since the reaction involves the formation of two moles of gas from two moles of reactants, the forward reaction will be favored to reduce the pressure. As a result, the partial pressure of H2O2(g) will increase to establish a new equilibrium.

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Answer:

Reactants

Explanation:

because a reactant is a substance or compound added to a system to cause a new product

Answer:

b

b

Explanation:

The missing component of the reaction is Chlorine gas (Cl₂).

Fastest way to predict the missing component is to balance the chemical equation by ensuring that the number of atoms on both sides of the equation is the same.

? + 2NaBr → 2NaCl + Br₂

The reactant "?" should be chlorine gas (Cl2). This is because when chlorine gas reacts with sodium bromide (NaBr), it displaces bromine to form sodium chloride (NaCl) and bromine gas (Br2).

The balanced equation will therefore be:

Cl₂ + 2NaBr → 2NaCl + Br₂

So, the missing components are: Cl₂

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Considering the combined law equation, the new pressure of the sample is 723.81 mmHg.

Boyle's law states that the pressure of a gas in a closed container is inversely proportional to the volume of the container, when the temperature is constant.

This law is expressed mathematically as:

P×V=k

where

Charles' law states that the volume of a gas in a closed container is directly proportional to the temperature of the container, when the temperature is constant.

This law is expressed mathematically as:

V÷T= k

where

Charles' law states that the pressure of a gas in a closed container is directly proportional to the temperature of the container, when the temperature is constant.

This law is expressed mathematically as:

P÷T= k

where

Combined law equation is the combination of three gas laws called Boyle's, Charlie's and Gay-Lusac's law:

(V×P) ÷T= k

Considering an initial state 1 and a final state 2, it is fulfilled:

(V₁×P₁) ÷T₁= (V₂×P₂) ÷T₂

In this case, you know:

Replacing in the definition of combined law equation:

(5 L× 760 mmHg) ÷273 K= (6 L× P₂) ÷312 K

Solving:

[(5 L× 760 mmHg) ÷273 K]× (312 K÷ 6 L)=  P₂

723.81 mmHg= P₂

Finally, the new pressure is 723.81 mmHg.

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Answer:

The answer is:

which metal has a soluble carbonate, chloride and sulfate?

A. Copper

B. Potassium

C. Zinc

D. Barium

The right answer is;

B_ Potassium

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Answer:

If there were multiple products, we can take each product and mixed with a sample of a pure compound that we suspect might be the same as the product. Then, we taking the melting point of this mixture that contains one of our product and pure sample. Then, we can observe the change in melting point, if there is no change in melting point or the melting stays in the same range of the pure compound. Then, the that product along with the pure sample are actually the same compound, not a mixture of two compounds. However, if the melting point for our pure sample compound changed or didn't stay in the same range after the mixing with on of our products. then we can conclude that this product and the pure sample are completely different compound, and indeed they are a mixture.

According to percent solutions, a  nitric acid solution that is 80% HNO₃ (by mass) contains 80 g HNO₃ and 20 g water.

Percent solution is defined as a convenient way to record concentration of solution.It is a expression which relates solute to solvent as,mass of solute/mass of solution ×100.There are two types of percentage solutions percent weight by volume and percent volume by volume .Advantages of using percent solutions is that molecular weight of compound is not required.

Thus, a  nitric acid solution that is 80% HNO₃ (by mass) contains 80 g HNO₃ and 20 g water.

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Answer:

Closed-toe shoes, long pants, a lab coat, safety glasses with side shields or splash goggles, and gloves.

Explanation:

Answer:

Al avanzar hacia la derecha por el período 5, el tamaño atómico, la energía de ionización y los electrones de valencia: A. disminuye, aumenta y aumentan, respectivamente.

Explanation:

El radio atómico representa la distancia que existe entre el núcleo y la capa de valencia, es decir la más externa. Por medio del radio atómico es posible determinar el tamaño del átomo.  En un período el tamaño atómico disminuye de izquierda a derecha pues en este sentido aumenta el  número atómico aumentando la carga nuclear mientras que el efecto pantalla y el número de  niveles permanecen constantes. En otras palabras, disminuye de izquierda a derecha debido a la atracción que ejerce el núcleo sobre los electrones de los orbitales más externos, disminuyendo así la distancia núcleo-electrón.

Al avanzar hacia la derecha por el período 5, el tamaño atómico disminuye.

La energía de ionización es la necesaria para remover un electrón a un átomo en estado  gaseoso. Mientras más lejos del núcleo esté el electrón, es más fácil removerlo porque se necesita  menos energía. Al aumentar el número atómico de los elementos de un  mismo período, se incrementa la atracción nuclear sobre el  electrón más externo, ya que disminuye el radio atómico y  aumenta la carga nuclear efectiva sobre él. Entonces en un período, al aumentar el número atómico, la energía de ionización aumenta.

Entonces, al avanzar hacia la derecha por el período 5, la energía de ionización y los electrones de valencia aumenta.

Los electrones de valencia  son los electrones que están en la última capa electrónica (llamados orbitales de valencia) y tienen una alta posibilidad de participar en una reacción química.

En cada período aparecen los elementos cuyo último nivel de su configuración electrónica coincide con el número del período, ordenados por orden creciente de número atómico. Por ejemplo, el período 3 incluye los elementos cuyos electrones más externos están en el nivel 3.

Los electrones de valencia aumentan en número a medida que se avanza en un período.

Entonces, al avanzar hacia la derecha por el período 5, los electrones de valencia aumentan.

Answer:

Option B is correct.

Explanation:

Since an iron nail is solid and have very large force of attraction between the particles therefore the particles can't move freely and could only vibrate at it's place.

Answer:

Option B is correct.

Explanation:

Since an iron nail is solid and have very large force of attraction between the particles therefore the particles can't move freely and could only vibrate at it's place.

Answer:

I think it is D

Explanation:

because i did this one

A cookbook is a small book that contains the recipes for preparing different types of meals.

A cookbook is a small book that contains the recipes for preparing different types of meals sometimes including continental dishes. The recipes in a cookbook are often invaluable for chefs.

A cookbook may contain the recipe for different types of diet such as;

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Answer:

50%

Explanation:

Expected measurement required = 10g

Actual measurement observed = 15g

The percentage error is given as proportion the difference between the actual and expected measurement or values and the expected value value expressed as a percentage.

[(Actual - Expected) / Expected] × 100%

[(15 - 10) / 10)] × 100%

(5 / 10) × 100%

0.5 × 100%

50%

Therefore, the percentage error in the measurement is 50%

Enthalpy, entropy, and Gibbs free energy are all negative for the exothermic reaction in instant cold packs.

Moment cold packs commonly contain water and ammonium nitrate, which respond exothermically to create ammonium and nitrate particles. This response is an illustration of an exothermic interaction, and that implies that intensity is delivered during the response.

The enthalpy change (ΔH) for this response is negative, and that implies that the response discharges heat. The entropy change (ΔS) for the response is additionally certain, and that implies that the response expands the problem or arbitrariness of the framework. The Gibbs free energy change (ΔG) for the response is negative, and that implies that the response is unconstrained and favors the development of items at the given circumstances.

The negative worth of ΔG demonstrates that the response is thermodynamically ideal and will continue unexpectedly. The negative worth of ΔH shows that the response discharges heat, which is consumed by the environmental factors, prompting a diminishing in temperature. The positive worth of ΔS demonstrates that the response expands the issue or haphazardness of the framework, which additionally adds to the lessening in temperature.

In this manner, the sign for enthalpy, entropy, and Gibbs Free Energy of the response occurring inside a moment cold pack are completely related, demonstrating that the response is exothermic, increments jumble, and is thermodynamically good.

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A medication prescription calls for dextrose 5% in water (d5w) 1,000 ml with 40 meq of potassium chloride to be infused at 125 ml/hr. 3 1 l bags will be needed over a 24 hr period.

To calculate how many 1 L bags of medication will be needed over a 24-hour period, we first need to determine how much medication will be infused per hour.
The prescription calls for dextrose 5% in water (d5w) 1,000 ml with 40 meq of potassium chloride to be infused at 125 ml/hr. Therefore, each hour, the patient will receive 125 ml of the medication, which contains 40 meq of potassium chloride.
To determine how many 1 L bags will be needed over a 24-hour period, we need to calculate how many 125 ml doses can be obtained from a 1 L bag.
1 L = 1000 ml
1000 ml / 125 ml/hr = 8 hours
So each 1 L bag will provide 8 hours' worth of medication.
To cover a 24-hour period, we will need 3 bags of medication:
3 bags x 8 hours per bag = 24 hours
Therefore, the answer is that 3 1 L bags of medication will be needed over a 24-hour period.

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Three 1 L bags of D5W with 40 meq of potassium chloride will be needed over a 24 hr period.

To determine how many 1 L bags of dextrose 5% in water (D5W) with 40 mEq of potassium chloride will be needed over a 24-hour period at an infusion rate of 125 mL/hr, follow these steps:

1. Calculate the total volume of the infusion required in 24 hours:
  Infusion rate (125 mL/hr) x Time (24 hours) = Total volume
  125 mL/hr x 24 hours = 3,000 mL

2. Convert the total volume from mL to L:
  Total volume (3,000 mL) ÷ 1,000 mL/L = 3 L

3. Determine the number of 1 L bags needed:
  Total volume in L (3 L) ÷ Volume of 1 L bag (1 L) = Number of bags
  3 L ÷ 1 L = 3 bags

So, over a 24-hour period, you will need 3 one-liter bags of D5W with 40 mEq of potassium chloride to be infused at 125 mL/hr.

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Answer:

ver explicacion

Explanation:

Zn (s) + 2HCl (ac) ---> ZnCl2 (ac) + H2 (g)

El zinc se oxida y el hidrógeno se reduce. HCl es el agente oxidante mientras que Zn es el agente reductor.

2Na (s) + H2SO4 (ac) ----> Na2SO4 (ac) + H2 (g)

El Na se oxida y el hidrógeno se reduce. El ácido sulfúrico es el agente oxidante, mientras que el sodio metálico es el agente reductor de tge.

Ca (OH) 2 (ac) + H2CO3 (ac) ------> CaCO3 (s) + 2H2O (l)

Esta no es una reacción redox ya que no hay cambios en el número de oxidación de izquierda a derecha.

Answer:

591.471 MILLIMETERS

Explanation:

Formula  

for an approximate result, multiply the volume value by 29.574

29.574*20=591.471

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No, the fact that a chemical process transfers heat to the surroundings does not necessarily mean that the process is spontaneous. The spontaneity of a process depends on the change in Gibbs free energy (ΔG). A spontaneous process is one that occurs without the need for external intervention and has a negative ΔG.

To determine if a process is spontaneous, you need to consider both the enthalpy change (ΔH) and the entropy change (ΔS). If the reaction has a negative ΔH (exothermic) and a positive ΔS (increase in disorder), the process is likely to be spontaneous.
So, while the transfer of heat to the surroundings is an important factor in determining the spontaneity of a chemical process, it is not the sole determinant.

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Answer:

Its C

Explanation:

Ok. You really know how.

Answer:

the answer would be b

Explanation:

The fundamental process that different chemical compounds emit different colors of light is because of different energy levels and the energy of photon emitted.

The compound are made up of atoms or elements .  when the electron jumps from lower energy state to higher energy state and the higher energy state are unstable so the electron will returns to its lower energy state in this state transition the electron emits light. these lights are different for every elements because of energy levels. the different compounds emits different color.

Thus, The fundamental process that different chemical compounds emit different colors of light is because of different energy levels and the energy of photon emitted.

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Answer:

D. 4Al + 3O2→2Al2O3

HCO3^- is best described as ao bicarbonate in.

The bicarbonate ion, HCO3^-, consists of one hydrogen atom (H+), one carbon atom (C), and three oxygen atoms (O) bonded together. It is a polyatomic ion that plays a crucial role in various biological and chemical processes. Bicarbonate ions are commonly found in the body and are involved in maintaining acid-base balance, particularly in blood and cellular environments.

In terms of acidity, HCO3^- can act as a weak acid. It has the ability to donate a proton (H+) in certain chemical reactions, contributing to the regulation of pH levels in the body. However, it is important to note that HCO3^- is primarily known as a bicarbonate ion and is more commonly involved in its role as a base rather than an acid.

In summary, HCO3^- is best described as a bicarbonate ion, which is involved in maintaining acid-base balance and acts as a weak acid in specific reactions describes HCO3^-. a proton donor a bicarbonate ion a weak acid common in the liver

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HCO3^- is known as the bicarbonate ion. It acts as a weak acid or a proton donor, assisting with pH regulation in the blood by buffering acid wastes from metabolic processes. It is also involved in respiratory regulation of acid-base balance.

HCO3^- is known as bicarbonate ion. It can act as a proton donor, thus making it a weak acid. In the body, bicarbonate ions and carbonic acid exist in a 20:1 ratio, helping to maintain blood pH balance. Bicarbonate ions prevent significant changes in blood pH by capturing free ions. During metabolic processes that release acid wastes such as lactic acid, bicarbonate ions help to buffer the acidity. These ions are even involved in respiratory regulation of acid-base balance, as they are crucial to the balance of acids and bases in the body by regulating the blood levels of carbonic acid. The stronger the acidic substance, the more readily it donates protons (H*). In contrast, bicarbonate is a weak base, meaning that it releases only some hydroxyl ions or absorbs only a few protons. Overall, the bicarbonate ion plays a critical role in various biological reactions and maintaining homeostasis.

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Answer:

1.725e+18

Explanation: