At a concession​ stand, one hot dog and one hamburger cost ​$3.75 ​; one hot dog and cost ​$12.25 . Find the cost of one hot dog and the cost of one hamburger .

Answer:

y = - \(\frac{1}{5}\) x + 9

Step-by-step explanation:

the equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

y = 5x - 4 ← is in slope- intercept form

with slope m = 5

given a line with slope m then the slope of a line perpendicular to it is

\(m_{perpendicular}\) = - \(\frac{1}{m}\) = - \(\frac{1}{5}\) , then

y = - \(\frac{1}{5}\) x + c ← is the partial equation

to find c substitute (10, 7 ) into the partial equation

7 = - \(\frac{1}{5}\) (10) + c = - 2 + c ( add 2 to both sides )

9 = c

y = - \(\frac{1}{5}\) x + 9 ← equation of perpendicular line

Answer:

525

Step-by-step explanation:

i really dont know what it asking

Answer:

  15% less than its regular price

Step-by-step explanation:

If the toy is marked down 15% in June, its cost during June is 15% less than its regular cost. (It will be 85% of its regular cost.)

Answer:

I think the answer is Africa, I dunno.

Step-by-step explanation:

Answer:

4n  or  n × 4

Step-by-step explanation:

Product means the result of multiplying factors.

Factors are the numbers or variables (a number, unknown) that are multiplied.

Answer:

my nut is ytellow

Step-by-step explanation:

The evidence does not strongly support the claim that women with above-average looks earn significantly more than women with average looks.

To understand the findings, we need to discuss a few key concepts. First, let's clarify the null hypothesis (H0) and the alternative hypothesis (H1). In this case, the null hypothesis states that there is no relationship between physical appearance and income (β2 = 0), while the alternative hypothesis suggests that there is a relationship (β2 ≠ 0).

In this scenario, the one-sided p-value of 0.272 means that there is a 27.2% chance of observing a relationship between physical appearance and income as strong or stronger than what was found in the study, purely by chance, if there is actually no relationship (β2 = 0). Since this p-value is relatively high (greater than the commonly used threshold of 0.05), it implies weak evidence against the null hypothesis.

Therefore, based on the given information, the evidence does not provide sufficient statistical support to reject the null hypothesis that there is no relationship between physical appearance and income (H0: β2 = 0).

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The greatest common factor will be = 4k²

What is Factor?

A number or algebraic expression that divides another number or expression evenly—that is, without leaving any remainder. 3 and 6 are factors of 12 because 12 3 = 4 precisely and 12 6 = 2 precisely. The other 12 factors are 1, 2, 4, and 12.

Given,

polynomial = 16k³-4k²

= (4*4)k³ - (4k²) --- Factored by 4 *4

=4 (4k³) - 4k² --- associative property of multiplication

= 4( 4k²*k) - 4k² --- factored k³ as k² *k

= 4k² (k -4)---- commutative property of multiplication

The greatest common factor will be = 4k²

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The answers are:

a) The z-score for a light bulb that lasts 500 hours is -10.

b) For a sample of 20 light bulbs, the probability that the average lifespan will be less than 980 hours is approximately 0.0367, or 3.67%.

c) The z-score for a light bulb that lasts 400 hours is -12. This is even more unusual than a lifespan of 500 hours.

d) Given the lifespan follows a normal distribution with a mean of 1000 hours, 50% of the light bulbs will have a lifespan less than 1000 hours.

a) The z-score is calculated as:

z = (X - μ) / σ

Where X is the data point, μ is the mean, and σ is the standard deviation. Here, X = 500 hours, μ = 1000 hours, and σ = 50 hours. So,

z = (500 - 1000) / 50 = -10.

The z-score for a bulb that lasts 500 hours is -10. This is far from the mean, indicating that a bulb lasting only 500 hours is very unusual for this brand of bulbs.

b) If a customer buys 20 of these light bulbs, we're now interested in the average lifespan of these bulbs. . In this case, n = 20, so the standard error is

50/√20

≈ 11.18 hours.

z = (980 - 1000) / 11.18 ≈ -1.79.

The probability that z is less than -1.79 is approximately 0.0367, or 3.67%.

c) The z-score for a bulb with a lifespan of 400 hours can be calculated as:

z = (400 - 1000) / 50 = -12.

The probability associated with z = -12 is virtually zero. So the probability of getting a bulb with a mean lifespan of 400 hours is virtually zero.

d) The mean lifespan is 1000 hours, so half of the light bulbs will have a lifespan less than 1000 hours. Since the lifespan follows a normal distribution, the mean, median, and mode are the same. So, 50% of light bulbs will have a lifespan less than 1000 hours.

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Answer:

-63/2

Step-by-step explanation:

6( -5  1/4)

= 6(-21/4)

= -63/2

To answer this question, we need to use the information given in the problem. We know that 52% of all adults are shareholders, so the probability that a randomly selected adult owns shares of stock is 0.52.

To find the probability that a randomly selected adult did not own shares of stock, we can subtract this probability from 1 (since the sum of the probabilities of all possible outcomes must equal 1).

So, the probability that a randomly selected adult did not own shares of stock is:

1 - 0.52 = 0.48

Now, we can see that the information about shareholders having some college education is not needed to answer this question.

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Answer:

A.

Line A

Answer:

58.

\(135\pi \: {km}^{2} \)

59.

\(216\pi \: {km}^{2} \)

60.

\(324 \: {km}^{3} \)

61.

\(72 \sqrt{5 } \pi \: {m}^{2} \)

62.

\(72( \sqrt{5} + 2)\pi \: {m}^{2}\)

63.

\(240\pi \: {m}^{3} \)

Step-by-step explanation:

58. First, we have to find the length of the cone shaper by using the Pythagorean theorem:

\( {l}^{2} = {12}^{2} + {9}^{2} = 144 + 81 = 225\)

\(l > 0\)

\(l = \sqrt{225} = 15 \: km\)

Now, let's find the lateral surface (r = 9 km):

\(a(lateral) = \pi \times r \times l = \pi \times 9 \times 15 = 135\pi \: {km}^{2} \)

59. The area of total surface is equal to a lateral surface's and base surface's sum:

Let's find the area of the base first:

\(a(base) = \pi \times {r}^{2} = {9}^{2} \times \pi = 81\pi \: {km}^{2} \)

Now, let's find the area of total surface:

\(a(total) = 135\pi + 81\pi = 216\pi\: {km}^{2} \)

60. h = 12 km

\(v = \frac{1}{3} \times a(base) \times h = \frac{1}{3} \times 81\pi \times 12 = 324\pi \: {km}^{3} \)

61. r = 12m

h = 5m

Let's find the length of the cone shaper by using the Pythagorean theorem:

\( {l}^{2} = {12}^{2} + {6}^{2} = 144 + 36 = 180\)

\(l > 0\)

\(l = \sqrt{180} = 6 \sqrt{5} \: m\)

Now, let's find the area of the lateral surface:

\(a(lateral) = \pi \times r \times l = \pi \times 12 \times 6 \sqrt{5} = 72 \sqrt{5} \pi \: {m}^{2} \)

62.

\(a(base) = \pi \times {r}^{2} = 144\pi \: {m}^{2} \)

\(a(total) = 72 \sqrt{5} \pi + 144\pi = 72( \sqrt{5} + 2)\pi \: {m}^{2} \)

63.

\(v = \frac{1}{3} \times a(base) \times h = \frac{1}{3} \times 144\pi \times 5 = 240\pi \: {m}^{3} \)

I don't know if these answer are correct, though...

The long run behavior of the function f(x)=5(2)x+1 is that it approaches 1 as x approaches negative infinity and it approaches infinity as x approaches positive infinity.

The long-term behavior of the function f(x)=5(2)x+1 can be discovered by examining how the function behaves as x gets closer to negative and positive infinity.

As x→−[infinity], f(x) = 5(2)^ -∞+1 = 5(0)+1 = 1

As x approaches negative infinity, the value of the function approaches 1.

As x→[infinity], f(x) = 5(2)^ ∞+1 = 5(∞)+1 = ∞

As x approaches positive infinity, the value of the function approaches infinity.

As a result, the function f(x)=5(2)x+1 behaves in the long run in such a way that it approaches 1 as x approaches negative infinity and infinity as x approaches positive infinity.

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Step-by-step explanation:

\( \underline{ \underline{ \text{Given}} }: \)

\( \underline{ \underline{ \text{To \: find}}} : \)

Let E ( -3 , 2 ) be ( x₁ , y₁ ) & H ( 1 , -1 ) be ( x₂ , y₂ )

\( \underline{ \underline{ \text{Solution}}} : \)

\( \sf{Midpoint = ( \frac{x_{1} + x_{2}}{2} \: , \frac{ y_{1} + y_{2}}{2} )}\)

⟶ \( \sf{( \frac{-3 + 1}{2} \: , \frac{2 + ( - 1)}{2} )}\)

⟶ \( \sf{( \frac{-2}{2} \:, \frac{2 - 1}{2} )}\)

⟶ \( \sf{( -1 \: ,\frac{1}{2} )}\)

\( \pink{ \boxed{ \boxed{ \tt{Our \: final \: answer : \boxed{ \underline{ \tt{(-1 \: , \: \frac{1}{2} )}}}}}}}\)

Hope I helped ! ♡

Have a wonderful day / night ! ツ

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The median wait time for the speed slide is 2 times longer than the median wait time for the wave machine.

No, There is a lot of overlap between the two data sets.

We have,

Box plots:

Speed side

Median = 11

First quartile = 6

Third quartile = 12

IQR = 12 - 6 = 6

Wave machine

Median = 9

First quartile = 8

Third quartile = 14

IQR = 14 - 8 = 6

Now,

Difference between the median.

= 11 - 9

= 2

Now,

From the box plots, the wait time for the wave machine is longer than the speed side.

Thus,

The median wait time for the speed slide is 2 times longer than the median wait time for the wave machine.

No, There is a lot of overlap between the two data sets.

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Answer:

its 85 ...................

Step-by-step explanation:

25m -5mn +3m -7n

28m -5mn -7n

Answer:

13m-5mn-7n

Step-by-step explanation:

(5m×5)-(5m×n)+3m-7n

10m-5mn+3m-7n

collect like terms

10m+3m-5mn-7n

13m-5mn-7n

:)

Answer:

For a general point (x, y), a reflection across the line x = a transforms the point into:

(a + (a - x), y) = (2a - x, y)

So if we first do a reflection across the line x = 1, the new point will be:

(2*1 - x, y) = (2 - x, y)

And if we now do a reflection across the line x = 3, the new point will be:

(2*3 - (2 - x), y) = (6 - 2 + x, y) = (4 + x, y)

Now that we have the general formula we can solve the question.

For the point (-5, 2)

The generated point after the reflections is:

(4 + (-5), 2) = (-1, 2)

For the point (-1, 5)

The generated point after the reflections is:

(4 + (-1), 5) = (3, 5)

For the point (0, 3)

The generated point after the reflections is:

(4 +0, 3) = (4, 3)

The two places she can put lens and give object and image distances are 15cm and 75cm.

The Lens equation gives us:

1/f = 1/u + 1/v

From the problem we know that,

v=90-u

By solving

u² - 90u + 1125 = 0.

An optical system's focal length, which is the inverse of the system's optical power, indicates how strongly the system converges or diverges light. A system with a positive focal length is said to converge light, and one with a negative focal length is said to diverge light.

A negative focal length, on the other hand, indicates how far in front of the lens a point source must be located to form a collimated beam, for the special case of a thin lens in air, where a positive focal length is the distance over which initially collimated (parallel) rays are brought to a focus. For more generic optical systems, the focal length is merely the inverse of optical power and lacks any intuitive significance.

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Answer:

not 24 i got an 80 its not 24 though

Step-by-step explanation:

i dont know  how this helps but there you go

Answer:

y = \(\frac{1}{3}\) x + \(\frac{10}{3}\)

Step-by-step explanation:

The equation of a line in slope- intercept form is

y = mx + c ( m is the slope and c the y- intercept )

Calculate the slope m of H using the slope formula

m = \(\frac{y_{2}-y_{1} }{x_{2}-x_{1} }\)

with (x₁, y₁ ) = (0, - 3) and (x₂, y₂ ) = (3, - 2) ← 2 points on the line

m = \(\frac{-2+3}{3-0}\) = \(\frac{1}{3}\)

Parallel lines have equal slopes, thus

y = \(\frac{1}{3}\) x + c ← is the partial equation

To find c substitute (- 4, 2) into the partial equation

2 = - \(\frac{4}{3}\) + c ⇒ c = 2 + \(\frac{4}{3}\) = \(\frac{10}{3}\)

y = \(\frac{1}{3}\) x + \(\frac{10}{3}\) ← equation of parallel line

The mode is the most appropriate measure of center to represent the data in the graph because it reflects the most common value(s) observed in the dataset. In this case, the mode is 3.

The most appropriate measure of center to represent the data in the given line plot is the mode.

The mode is the value or values that occur most frequently in a dataset. In this case, we can observe the frequencies of the data points on the line plot:

There is one dot above 2, 4, 8, and 9.

There are two dots above 6 and 7.

There are three dots above 3.

Based on this information, the mode(s) of the dataset would be the values that have the highest frequency. In this case, the mode is 3 because it appears most frequently with a frequency of three. The other data points have frequencies of one or two.

The mode is particularly appropriate in this scenario because it represents the most common or frequently occurring value(s) in the dataset. It is useful for identifying the central tendency when the data is discrete and there are distinct peaks or clusters.

While the median and mean are also measures of center, they may not be the most appropriate in this case. The median represents the middle value and is useful when the data is ordered. However, the given line plot does not provide an ordered arrangement of the data points. The mean, on the other hand, can be affected by outliers and extreme values, which may not accurately represent the central tendency of the dataset in this scenario.

Therefore, the mode is the most appropriate measure of center to represent the data in the graph because it reflects the most common value(s) observed in the dataset. In this case, the mode is 3.

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Profitability index is 1.387. Thus, the correct option is (c) 1.387.

The formula for calculating the profitability index is:

P.I = PV of Future Cash Flows / Initial Investment

Where,

P.I is the profitability index

PV is the present value of future cash flows

The initial investment in the project is $30 million. The cash flow at the end of the first year is $2.85 million.

The present value of cash flows can be calculated using the formula:

PV = CF / (1 + r)ⁿ

Where,

PV is the present value of cash flows

CF is the cash flow in the given period

r is the discount rate

n is the number of periods

For the first-year cash flow, n = 1, CF = $2.85 million, and r = 11%.

Substituting the values, we get:

PV = 2.85 / (1 + 0.11)¹ = $2.56 million

To calculate the present value of all future cash flows, we can use the formula:

PV = CF / (r - g)

Where,

PV is the present value of cash flows

CF is the cash flow in the given period

r is the discount rate

g is the constant growth rate

For the subsequent years, CF = $2.85 million, r = 11%, and g = 3.85%.

Substituting the values, we get:

PV = 2.85 / (0.11 - 0.0385) = $39.90 million

The total present value of cash flows is the sum of the present value of the first-year cash flow and the present value of all future cash flows.

PV of future cash flows = $39.90 million + $2.56 million = $42.46 million

Profitability index (P.I) = PV of future cash flows / Initial investment

= 42.46 / 30

= 1.387

Therefore, the correct option is (c) 1.387.

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Answer:

x=2,-4

Step-by-step explanation:

b. r(t) = (cos(t), sin(t)), for 0 <= t <= pi. c. Sphere of radius 1 centered at the origin: r(u, v) = (cos(u) * sin(v), sin(u) * sin(v), cos(v)), for 0 <= u <= 2pi and 0 <= v <= pi.

b) Here are the parameterizations for a line segment connecting two points of your choice and half of a circle centered at the origin:

Line segment from (0, 0) to (1, 2): r(t) = (1 - t) * (0, 0) + t * (1, 2) = (t, 2t), for 0 <= t <= 1.

Half of a circle of radius 1 centered at the origin: r(t) = (cos(t), sin(t)), for 0 <= t <= pi.

c) Here are the parameterizations for a plane and a sphere:

Plane passing through (1, 0, 0), (0, 1, 0), and (0, 0, 1): r(u, v) = u * (1, 0, 0) + v * (0, 1, 0) + (1 - u - v) * (0, 0, 1), for 0 <= u <= 1 and 0 <= v <= 1.

Sphere of radius 1 centered at the origin: r(u, v) = (cos(u) * sin(v), sin(u) * sin(v), cos(v)), for 0 <= u <= 2pi and 0 <= v <= pi.

Note that for the plane parameterization, we used the fact that a plane passing through three non-collinear points can be parameterized by a linear combination of the points, with the coefficients summing to 1. For the sphere parameterization, we used spherical coordinates to express the position of each point on the sphere in terms of two angles, u and v.

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