Ava draws a rectangle on grid paper showing 4 for length and 6 for width. Ava says the area of the rectangle is 10 square units. Which explains Avas error and correctly solves for the area of the rectangle

The missing number in Sequence 2 is 780.

To find the missing number in Sequence 2, let's analyze the pattern:

In Sequence 1, the numbers increase by 1 each time: 126, 127, 128, 129, ...

In Sequence 2, the numbers seem to follow a pattern where each number is obtained by multiplying the corresponding number in Sequence 1 by a certain factor:

2 x 126 = 252

3 x 127 = 381

4 x 128 = 512

5 x 129 = 645

...

Looking at this pattern, we can see that the missing number in Sequence 2 should be:

6 x 130 = 780

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Answer:

it is b because I did the problem yes it is b

Answer:

840

Step-by-step explanation:

1st u have to multiple 280 by 3

Answer:

The answer is b.

Answer:

m= -1

Step-by-step explanation:

Answer:

  1600 boxes of cookies; 350 boxes of chocolates

Step-by-step explanation:

Let x and y represent the numbers of boxes of cookies and chocolates to order, respectively. The constraints seem to be ...

The objective function we want to maximize is ...

  p = 2.70x +2.45y

_____

Looking at the problem, we see that cookies yield the most profit, so we'd like to maximize the boxes of cookies sold within the allowed limits.

There are two limits on x:

  x ≤ 550 +3y

  x ≤ 1950 -y

x will be as large as it can be if it bumps up against these limits simultaneously:

  550 +3y = 1950 -y

  4y = 1400 . . . . . . . . . add y-550

  y = 350

  x = 1950 -350 = 1600

Profit will be maximized for an order of 1600 boxes of cookies and 350 boxes of chocolates.

_____

The "feasible region" of the solution is where the three constraint inequalities overlap. It is a quadrilateral with vertices at (0, 0), (550, 0), (1300, 650), and (1600, 350). We can reject the ones with x or y being 0. Per our analysis above, the solution of interest is (x, y) = (1600, 350), since it maximizes x.

The usual protocol for solving a linear programming model like this is to evaluate the objective function at each of the vertices. With a little thought about the problem, we have saved some evaluation effort.

Answer:

42

Step-by-step explanation:

Answer:

42

A. The average speed was 36 mph.

B. The average speed on the drive from LA to Irvine was 25mph.

C. The total time he spent driving to and from the meeting was about 3 hours and 5 minutes.

The reason that the point (3, 5) is not a solution to the given inequality is given below.

We are given that;

y > 2x + 1

Now,

The inequality y > 2x + 1 can be graphed by first graphing the boundary line y = 2x + 1. Since the inequality is strict (y >), we draw a dashed line to indicate that points on the line are not solutions to the inequality. Then, we shade the region above the line to indicate all points that satisfy the inequality.

If we have (3,5) as a point, we can see that it lies on the boundary line

y = 2x + 1.

Since the inequality is strict (y >), points on this line are not solutions to the inequality

Therefore, by the inequality the answer will be given above.

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The probability of P(A and B) based on the information given will be E. None of the above.

It should be noted that probability is used to illustrate the likelihood that something will occur.

In this case, P(A) = 0.1 and P(B) = 0.4. Therefore, the probability of P(A and B) will be

= P(A) + P(B)

= 0.1 + 0.4

= 0.5

Sine the value of 0.5 isn't given, the correct option is E.

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If over what interval does f(x) = 2x increase faster than g (X): A. 1

To determine over what interval f(x) = 2x increases faster than g(x) = x^2, we need to compare their derivatives. The derivative of f(x) is 2, which is a constant, and the derivative of g(x) is 2x. Therefore, f(x) increases at a constant rate of 2, while g(x) increases at a rate that depends on x.

To find the interval where f(x) increases faster than g(x), we need to find where the derivative of g(x) is less than 2. Setting 2x < 2 and solving for x, we get x < 1.

So, over the interval x < 1, f(x) = 2x increases faster than g(x) = x^2.

Therefore, the answer is A. 1.

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Step-by-step explanation:

please mark me as brainlest

Answer:

Step-by-step explanation:

For the first bag:

Price of the bag = $12

Number of balls in the bag = 15

Price per ball = Price of the bag / Number of balls

Price per ball for the first bag = $12 / 15 = $0.8

For the second bag:

Price of the bag = $15

Number of balls in the bag = 20

Price per ball = Price of the bag / Number of balls

Price per ball for the second bag = $15 / 20 = $0.75

Comparing the prices per ball, we find that the second bag has a lower price per baseball. Therefore, the second bag offers a better price for individual baseballs compared to the first bag.

Answer:

Step-by-step explanation:

To find out which bag prices individual baseballs lower, we can divide the total cost of each bag by the number of balls in the bag. This will give us the price per ball for each bag.

For the first bag, the price per ball is $12 / 15 = $0.80.

For the second bag, the price per ball is $15 / 20 = $0.75.

Therefore, the second bag prices individual baseballs lower.

Answer:

42 folds. This fact is mentioned in search results [1], [2], [3], [4], [5], and [7]. It is also noted in search result [6] that the answer may be 45 folds instead of 42, but this is in the context of a discussion on exponential growth and is not a commonly accepted answer to the question. Finally, search result [10] poses a similar question but provides the same answer of 42 folds to reach the moon.

Step-by-step explanation:

Step-by-step explanation:

If you want to sell the pens as individual items, there are 30 pens in total (15 red and 15 black), so you could sell them in 30 different ways. For example, you could sell the first red pen for 15 pesos, the second red pen for 14 pesos, the third red pen for 13 pesos, and so on, until you sell the last black pen for 1 peso.

If you want to sell the pens in boxes, you could sell the red pens and black pens separately or together. Here are the possible combinations:

1 box of red pens (15 pens) for 15 pesos

1 box of black pens (15 pens) for 15 pesos

2 boxes of red pens (30 pens) for 30 pesos

2 boxes of black pens (30 pens) for 30 pesos

1 box of red pens and 1 box of black pens (30 pens) for 30 pesos

Therefore, there are 5 ways to sell the pens in boxes.

Answer:

6

Step-by-step explanation:

x^2 + 4x + 4 is a perfect square trinomial that can be factored as (x + 2)^2.

Explanation:
To complete the expression x^2 + 4x + __ as a perfect square trinomial, we can take half of the coefficient of x (which is 4), square it, and then add it to the expression.

Half of 4 is 2, and 2 squared is 4, so we can add 4 to the expression to get:

x^2 + 4x + 4

This expression is a perfect square trinomial and can be factored as:

(x + 2)^2

Answer:

it is the there'd one

if this is wrong sorry

Answer:

Answer choice 1

Step-by-step explanation:

\(5^2\cdot 5^9= \\\\5^{2+9}= \\\\5^{11}\)

Therefore, the correct answer choice is choice 1. Hope this helps!

Answer:

answer is sister's.

Step-by-step explanation:

sisters mean more than one sister.

sisterses isn't a word.

sisters' also isn't a word.

sister's is a word and it means that she has possession of something or that she owns something.

The requried, probability that both the first digit in the last digit of the three-digit number is even numbers is 20%.

To count the number of three-digit numbers with distinct digits that can be formed using the digits 1, 2, 3, 5, 8, and 9, we can use the permutation formula:

P(n, r) = n! / (n-r)!

In this case, we have n = 6 (since we have 6 digits to choose from) and r = 3 (since we want to form three-digit numbers). Using the formula, we get:

P(6, 3) = 120

We can choose the first digit in two ways (2 or 8), and we can choose the last digit in three ways (2, 8, or 6). For the middle digit, we have four digits left to choose from (1, 3, 5, or 9), since we cannot repeat digits. Therefore, the number of three-digit numbers with distinct digits that have an even first and last digit is:

2 x 4 x 3 = 24

The total number of three-digit numbers with distinct digits is 120, so the probability that a randomly chosen three-digit number with distinct digits has an even first and last digit is:

24/120 = 0.2 or 20%

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Answer:

false

Step-by-step explanation:

false

I don't know if you meant

\(\vec F = (-3\,\vec\imath + 4\,\vec\jmath - 2\,\vec k)\,\mathrm N\)

or

\(\vec F = (-31\,\vec\imath + 43\,\vec\jmath - 2\,\vec k)\,\mathrm N\)

I'll assume the first force is correct.

The object in question undergoes a total displacement of

\(\vec d = (-4\,\vec\imath + 4\,\vec\jmath+4\,\vec k)\,\mathrm m - (4\,\vec\imath + \vec\jmath - 5\,\vec k)\,\mathrm m = (-8\,\vec\imath + 3\,\vec\jmath + 9\,\vec k)\,\mathrm m\)

Then the work W done by \(\vec F\) along this displacement is

\(W = \vec F \cdot \vec d = ((-3)\times(-8)+4\times3+(-2)\times9)=18\,\mathrm{Nm} = \boxed{18\,\mathrm J}\)

Another approach using calculus (it's overkill since \(\vec F\) is constant, but it doesn't hurt to check our answer): parameterize the line segment by

\(\vec r(t) = (1 - t)(4\,\vec\imath+\vec\jmath-5\,\vec k)\,\mathrm m + t(-4\,\vec\imath+4\,\vec\jmath + 4\,\vec k)\,\mathrm m \\\\ \vec r(t) = \left((4-8t)\,\vec\imath+(1+3t)\,\vec\jmath+(-5+9t)\,\vec k\right)\,\mathrm m\)

with 0 ≤ t ≤ 1.

Then the work W done by \(\vec F\) along the given path is equal to the line integral,

\(\displaystyle W = \int_0^1 \vec F(\vec r(t)) \cdot \frac{\mathrm d\vec r(t)}{\mathrm dt}\,\mathrm dt \\\\ W = \int_0^1 \left((-3\,\vec\imath+4\,\vec\jmath-2\,\vec k)\,\mathrm N\right) \cdot \left((-8\,\vec\imath+3\,\vec\jmath+9\,\vec k)\,\mathrm m\right) \,\mathrm dt \\\\ W = \int_0^1((-3)\times(-8)+4\times3+(-2)\times9)\,\mathrm{Nm}\,\mathrm dt \\\\ W = 18\,\mathrm{Nm} \int_0^1\mathrm dt \\\\ W = 18\,\mathrm{Nm} = \boxed{18\,\mathrm J}\)

You invested $3000 at 3% annual interest rate, and the remaining amount of $4000 - $3000 = $1000 was invested at 4% annual interest rate.

Let's assume you invested an amount, x, at 3% annual interest rate. This means the amount invested at 4% annual interest rate would be $4000 - x.

To calculate the interest earned from the investment at 3%, we multiply x by 3% (0.03). Similarly, the interest earned from the investment at 4% is calculated by multiplying ($4000 - x) by 4% (0.04).

According to the given information, the total interest earned from both investments is $130. So we can set up the equation:

0.03x + 0.04($4000 - x) = $130

Simplifying the equation:

0.03x + 0.04($4000 - x) = $130

0.03x + $160 - 0.04x = $130

-0.01x = $130 - $160

-0.01x = -$30

x = -$30 / -0.01

x = $3000

Therefore, you invested $3000 at 3% annual interest rate, and the remaining amount of $4000 - $3000 = $1000 was invested at 4% annual interest rate.

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Answer:

Area of the figure = 25.7 units²

Step-by-step explanation:

Area of the given figure = Area of rectangle ABCD - Area of the semicircle with diameter CD

Area of the rectangle ABCD = Length × Width

                                               = BC × AB

                                               = 8 × 4

                                                = 32 units²

Area of the semicircle = \(\frac{1}{2}\pi r^{2}\)

Here, r = radius of the semicircle

r = \(\frac{\text{Diameter}}{2}\)

r = \(\frac{1}{2}(CD)\)

r = \(\frac{4}{2}\)

r = 2 units

Therefore, area of the semicircle = \(\frac{1}{2}\pi (2)^2\)

                                                       = 2π

                                                       = 6.28 units²

Area of the given figure = 32 - 6.28

                                         = 25.72 units²

                                         ≈ 25.7 units²

Coordinates of P = \([(3 * xB + xC + 4 * xD) / 8, (3 * yB + yC + 4 * yD) / 8]\)

Coordinates of P = \([(4 * xC + 2 * xD + 3 * xE) / 9, (4 * yC + 2 * yD + 3 * yE) / 9]\)

Leave the directions of point B alone (x1, y1) and the directions of point D be (x2, y2). Then, at that point, the directions of P are:

\([(3x1 + x2)/4, (3y1 + y2)/4]\)

Let the directions of point A be (x1, y1) and the directions of point E be (x2, y2). Then, at that point, the directions of P are:

\([(x1 + 2x2)/3, (y1 + 2y2)/3]\)

Leave the directions of point B alone (x1, y1), the directions of point C be (x2, y2), and the directions of point D be (x3, y3). Then, at that point, the directions of P are:

\([(3x1 + x2 + 4x3)/8, (3y1 + y2 + 4y3)/8]\)

Leave the directions of point C alone (x1, y1), the directions of point D be (x2, y2), and the directions of point E be (x3, y3). Then, at that point, the directions of P are:

\([(4x1 + 2x2 + 3x3)/9, (4y1 + 2y2 + 3y3)/9]\)

These recipes can be inferred utilizing the weighted typical equation:

\([(w1x1 + w2x2 + ... + wnxn)/(w1 + w2 + ... + wn), (w1y1 + w2y2 + ... + wnyn)/(w1 + w2 + ... + wn)]\)

where wi is the heaviness of point I and (xi, yi) are the directions of point I. Subbing the given loads and facilitates into the equations for every issue gives the directions of P for each situation.

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The complete question is:

Find the coordinates of P that represent the weighted average of each set of points based on the given conditions. 12. Point B weighs three times as much as point D. 13. Point E weighs twice as much as point A. 14. Point B has a weight of 3 , point C has a weight of 1 , and point D has a weight of 4. 15. Point C has a weight of 4 , point D has a weight of 2 , and point E has a weight of 3.

Answer:

area of park with grass is 19cm^2

Step-by-step explanation:

area of park

= 5 ✖ 5

= 25cm^2

area of part with sand

= 2 ✖ 3

= 6cm^2

area of park with grass

= 25 - 6

= 19cm^2