From Newton's second law of motion, the magnitude of the force applied is 1022.4 N
What is Force ?Force can simply be defined as a pull or push. It is the product of mass and acceleration and it is a vector quantity.
Given that Avery hurls the 0.527-kg football to Tyrone the ball reaches Tyrone with a speed of 19.4 m/s Tyrone catches the pass bringing it to a dead stop in 0.010 seconds before heading up field.
The force F applied to the ball = mass × acceleration. That is,
F = ma
Where
m = 0.527 kgv = 19.4 m/st = 0.01 sF = ?a = ?Acceleration a = v/t
a = 19.4/0.01
a = 1940 m/s²
Force F = ma
F = 0.527 × 1940
F = 1022.4 N
Therefore, the force applied to the ball is 1022.4 N
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A possible set of quantum numbers to describe an
electron in a 4s subshell is
Quantum numbers are a set of four values used to describe the unique properties of an electron in an atom. The four quantum numbers are principal, azimuthal, spin and magnetic quantum numbers.
The principal quantum number is the value of n can be any positive integer (1, 2, 3, etc.).
Azimuthal quantum number- The value of l can be any integer from 0 to n-1, and each value of l is associated with a different shape of the orbital. For example, l=0 corresponds to an s orbital, l=1 corresponds to a p orbital, and l=2 corresponds to a d orbital.
Magnetic quantum number value range from -l to +l in integer increments, and each value of ml corresponds to a specific orientation of the orbital.
The spin quantum number value can be either +1/2 or -1/2, representing the two possible spin states of an electron
The possible set of quantum numbers for an electron in a 4s subshell are:
n = 4 (principal quantum number)
l = 0 (angular momentum quantum number)
m_l = 0 (magnetic quantum number)
m_s = +1/2 or -1/2 (spin quantum number)
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is the acceleration of a fluid particle necessarily zero in steady flow? explain.
No, the acceleration of a fluid particle is not necessarily zero in steady flow. In steady flow, the fluid properties at any point in the fluid remain constant over time, meaning that the fluid flow rate, velocity, and pressure do not change with time.
However, this does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. According to the continuity equation of fluid mechanics, the rate of fluid flow through any given area in the flow must remain constant in steady flow.
This means that if the cross-sectional area of a pipe carrying fluid decreases, the fluid velocity must increase to maintain a constant flow rate. As the fluid velocity changes, the acceleration of individual fluid particles can also change in response to the changing velocity.
In addition, the Navier-Stokes equations, which describe the motion of fluid particles, include terms for acceleration, which can be non-zero in steady flow if the fluid velocity is changing at a given point.
Therefore, even in steady flow, the acceleration of a fluid particle can be non-zero if there is a change in the fluid velocity at a given point. In summary, while steady flow implies that the fluid properties do not change over time.
It does not necessarily mean that the acceleration of individual fluid particles within the flow is zero. The acceleration can be non-zero if there is a change in the fluid velocity at a given point.
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If a ball is given a push so that it has an initial velocity of 6 m/s down a certain inclined plane, then the distance it has rolled after t seconds is given by the following equation s(t) = 6t + 5t2 (a) Find the velocity after 2 seconds. m/s (b) How long does it take for the velocity to reach 40 m/s? (Round your answer to two decimal places.)
The velocity after 2 seconds is 26 m/s. It takes 11.50 seconds to reach a velocity of 40m/s.
Given the equation s(t) = 6t + 5t²
Let's find the velocity after 2 seconds.
(a) Velocity = (ds)/(dt)
Differentiating s(t) with respect to t, we get; ds(t) / dt = 6 + 10t
At t = 2,ds(t) / dt = 6 + 10t = 6 + 10(2) = 26m/s
Therefore, the velocity after 2 seconds is 26 m/s.
(b) We are to find how long it takes for the velocity to reach 40m/s. We know that the initial velocity of the ball, u = 6m/s. Acceleration = gsinθ = 9.81 x sin (angle of inclination) = 9.81 x 0.3 = 2.943 m/s²From the first equation of motion, v = u + at
We know v = 40m/s, u = 6m/s, a = 2.943m/s² and t is what we are to find, hence the equation becomes;40 = 6 + 2.943(t)t = (40 - 6) / 2.943t = 11.50s
Therefore, it takes 11.50 seconds to reach a velocity of 40m/s.
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t is the estimated distance traveled through the air by a marshmallow that is launched from a 15- cm long launcher when it is placed 5 cm from the muzzle?
Answer:
10
Explanation:
15 cm minus 5 cm
The centripetal acceleration of a car moving around a circular curve at a constant speed of 22 m/s has a magnitude of 7.8 m/s ^2
. Calculate the radius of the curve.
The radius of the curve is \(\(62.05 \, \text{m}\)\)
The centripetal acceleration of an object moving in a circular path is given by the formula:
\(\[a_c = \frac{{v^2}}{{r}}\]\)
where \(\(a_c\)\) is the centripetal acceleration, \(\(v\)\) is the speed of the object, and \(\(r\)\) is the radius of the circular path.
Given that \(\(v = 22 \, \text{m/s}\) and \(a_c = 7.8 \, \text{m/s}^2\)\), we can rearrange the formula to solve for \(\(r\)\):
\(\[r = \frac{{v^2}}{{a_c}}\]\)
Substituting the given values:
\(\[r = \frac{{(22 \, \text{m/s})^2}}{{7.8 \, \text{m/s}^2}}\]\)
Calculating the result:
\(\[r = \frac{{484 \, \text{m}^2/\text{s}^2}}{{7.8 \, \text{m/s}^2}} \\\\= 62.05 \, \text{m}\]\)
Therefore, the radius of the curve is \(\(62.05 \, \text{m}\)\).
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The radius of the curve is 61.56 m.
The centripetal acceleration of a car moving around a circular curve at a constant speed of 22 m/s has a magnitude of 7.8 m/s². We are to calculate the radius of the curve. To find the radius of the curve, we use the formula for centripetal acceleration as shown below:a_c = v²/r
where a_c is the centripetal acceleration, v is the velocity of the object moving in the circular motion and r is the radius of the curve. Rearranging the formula above to make r the subject, we have:r = v²/a_c
Now, substituting the given values into the formula above, we have:r = 22²/7.8r = 61.56 m.
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what is the purpose of this experiment?group of answer choicesthe purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.the purpose of this experiment is to understand circuits.the purpose of this experiment is to comprehend ohm’s law and how to compare their percent difference from their experimental and theoretical values.the purpose of this law is to identify non-ohmic devices and how to convert those devices ohmic.
The purpose of this experiment is to understand series and parallel circuits, how to calculate their equivalent resistance, and how to construct the laboratory.
How do parallel circuits function?There are two or more paths that current to travel through in a parallel circuit. Each element of the parallel circuit has the same voltage applied to that too. The total current flowing from the source is equal to the sum of a currents through each path.
What is a parallel circuit example?When one route is blocked, electricity continues to flow thanks to a parallel circuit. Numerous lighting fixtures are a great example. Even if just one light in the fixture fails, led light stays on.
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The density of gold is 19.3 g/cm3. What is the volume of a 13 g gold nugget? (Density: D = m/v)
Answer:
Formula = D = m/v
Given value of D = 19.3 and m = 13g
19.3 = 13/v
V × 19.3 = 13
v = 13/19.3
v = 0.67
A man takes his dog for a walk. His motion is recorded on the coordinate plane below. On the plane, each block represents 1 km. a. The whole trip took 1.25 hours. What was the average velocity of the man? (2 points) 1.25 hr = 4500 sec. 28:125 m north 18:45 m east 28.125m south b. What was the average speed of the man?
a) The correct average velocity of the man is approximately 0.026928 km/h.
b) The correct average speed of the man is approximately 0.03726 km/h.
a) Average Velocity:
To calculate the average velocity, we need to determine the total displacement and divide it by the total time taken.
The north displacement is 28.125 m and the east displacement is 18.45 m. Since we are given that each block represents 1 km, we need to convert these distances to kilometers.
North displacement: 28.125 m ÷ 1000 = 0.028125 km
East displacement: 18.45 m ÷ 1000 = 0.01845 km
The total displacement can be calculated using the Pythagorean theorem:
Total displacement = √((0.028125 km)² + (0.01845 km)²) = √(0.000790039 km² + 0.0003409025 km²) ≈ √0.001130941 km² ≈ 0.03366 km
Since the total time taken is given as 1.25 hours, the average velocity is calculated by dividing the total displacement by the total time:
Average velocity = Total displacement ÷ Total time = 0.03366 km ÷ 1.25 hours ≈ 0.026928 km/h
Therefore, the correct average velocity of the man is approximately 0.026928 km/h.
b) Average Speed:
To calculate the average speed, we need to determine the total distance traveled and divide it by the total time taken.
The total distance traveled is obtained by summing up the north and east distances:
Total distance = 0.028125 km + 0.01845 km = 0.046575 km
Average speed = Total distance ÷ Total time = 0.046575 km ÷ 1.25 hours ≈ 0.03726 km/h
Therefore, the correct average speed of the man is approximately 0.03726 km/h.
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in the simulation, the charged particle is set to move in a direction that is initially perpendicular to the electric field. the friends instead consider that the charged particle is moving with some initial velocity parallel to the electric field. a discussion ensues. which of thana's statements is true? (assume the charged particle is moving within the field.)
In the simulation, the charged particle is set to move in a direction that is initially perpendicular to the electric field. The friends instead consider that the charged particle is moving with some initial velocity parallel to the electric field. A discussion ensues, and in this context, Thana's statement that is true is given below.
Assuming that the charged particle is moving within the field, the electric force acting on it depends on the velocity vector direction and the magnitude. The force acting on the charged particle is perpendicular to the direction of the magnetic field, and if the charged particle is set in a direction perpendicular to the magnetic field initially, it is expected to move along a circular path.
However, if the charged particle moves in a direction parallel to the magnetic field, there would be no change in its motion. As such, Thana's statement that is true is, "If the charged particle is moving in a direction parallel to the electric field, the magnetic force acting on it will be zero."The Lorentz force law is used to explain the behavior of charged particles that move in electric and magnetic fields.
This law states that a charged particle moving in a magnetic field will experience a force that is perpendicular to its velocity and the magnetic field. The magnitude of this force is proportional to the magnitude of the charge, the magnetic field strength, and the velocity of the charged particle.
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1. A car starts from the rest on a circular track with a radius of 300 m. It accelerates with a constant tangential acceleration of a = 0.75 m/s?. Determine the distance traveled and the time elapsed"
Starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², the car will travel a distance of approximately 0.2119 meters or 21.19 centimeters in 0.75 seconds.
To determine the distance traveled and the time elapsed by the car starting from rest on a circular track with a radius of 300 m and a constant tangential acceleration of 0.75 m/s², we can use the equations of circular motion.
The tangential acceleration is the rate of change of tangential velocity. Since the car starts from rest, its initial tangential velocity is zero (v₀ = 0).
Using the equation:
v = v₀ + at
where v is the final tangential velocity, v₀ is the initial tangential velocity, a is the tangential acceleration, and t is the time, we can solve for v:
v = 0 + (0.75 m/s²) * t
v = 0.75t m/s
The tangential velocity is related to the angular velocity (ω) and the radius (r) of the circular track:
v = ωr
Substituting the values:
0.75t = ω * 300
Since the car starts from rest, the initial angular velocity (ω₀) is zero. So, we have:
ω = ω₀ + αt
ω = 0 + (0.75 m/s²) * t
ω = 0.75t rad/s
We can now substitute the value of ω into the equation:
0.75t = (0.75t) * 300
Simplifying the equation gives:
0.75t = 225t
t = 0.75 seconds
The time elapsed is 0.75 seconds.
To calculate the distance traveled (s), we can use the equation:
s = v₀t + (1/2)at²
Since the initial velocity (v₀) is zero, the equation becomes:
s = (1/2)at²
s = (1/2)(0.75 m/s²)(0.75 s)²
s = (1/2)(0.75 m/s²)(0.5625 s²)
s = 0.2119 meters or approximately 21.19 centimeters
Therefore, the car travels a distance of approximately 0.2119 meters or 21.19 centimeters.
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Which element on the periodic table contains 13 protons?
Answer:
Al
Explanation:
From periodic table: Aluminum
a big summer movie has a running time of 96 minutes what is the movie's running time in seconds
Answer:
5,760
Explanation:
1 minute is equal to 60 seconds. so you will multiply 60 times 96. and that equals 5,760
Suppose you jump straight up with a velocity of 3 m/s. How high could you jump on the moon, where the acceleration due to gravity is about 1.6 m/s/s?
Answer:The maximum height you could jump on the moon with a velocity of 3 m/s is 4.5 meters.
Explanation:
To calculate the maximum height that you could jump on the moon, you can use the following formula:h = (v^2) / (2 * g)where h is the maximum height, v is the initial velocity, and g is the acceleration due to gravity. On the moon, g is approximately 1.6 m/s^2. Substituting the values, we get:h = (3^2) / (2 * 1.6) = 4.5 m
So the maximum height you could jump on the moon with a velocity of 3 m/s is 4.5 meters.
The acceleration of an object in uniform circular motion always points toward the center of the circle. Question 2 options: True False
Answer:
The answer is true. Hope this helps!
A frog leaps from flat ground at 6.32 m/s at a 36.3 angle. How long does it take to reach its maximum height? (Unit = s)
It takes .714 m to reach its maximum height.
The VERTICAL component is all we are interested in for this
Vertical velocity = 6.32 m/s sin 36.3° = 3.742 m/s
Vertical displacement = vo t - 1/2 at^2
= -1/2 at^2 + vo t
max occurs at - b/2a = -3.742/ (2(-1/2(9.81)) = .3814 sec
then vot-1/2 at^2 = 3.742 (.3814) - 1/2) (.3814^2) = .714 m
Vertical velocity: Vertical velocity of an object is its speed and direction on the vertical plane.
Vertical displacement: Vertical displacement is distance moved in a vertical direction.
Therefore, a frog that leaps from ground at 6.32 m/s at an angle of 36.3, it takes .714 m long to reach its maximum height.
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If a 3.5 gram ping pong ball were traveling to the right horizontally at 12 m/s, and a larger 12 g super ball were thrown directly behind it (also to the right) at 15 m/s so that the super ball bumped into and elastically collided with the ping pong ball, what would be the velocities of the two balls after the collision
Answer:
v = 14.32 m/s
Explanation:
According to the principle of conservation of linear momentum, both the momentum and kinetic energy of the system are conserved. Since the two balls are in the same direction of motion before collision, then;
\(m_{1} u_{1}\) + \(m_{2} u_{2}\) = (\(m_{1}\) + \(m_{2}\)) v
0.035 × 12 + 0.120 × 15 = (0.035 + 0.120) v
0.420 + 1.800 = (0.155) v
2.22 = 0.155 v
⇒ v = \(\frac{2.22}{0.155}\)
= 14.323
The velocity of the balls after collision is 14.32 m/s.
the inner planets—mercury, venus, earth, and mars—are believed to have been formed by . masses of cold hydrogen and helium collisions with large galaxies the combining of asteroid-sized debris
The inner planet Mercury, Venus, Earth, and Mars are believed to have been formed by the combination of asteroid-sized debris.
Exactly, what is space debris?Planets are formed through the collision of asteroid-sized space debris.
Space debris includes both naturally occurring meteoroids and man-made (artificial) orbital junk.
The majority of manufactured debris is in orbit around the Earth, unlike meteoroids, which are in orbit around the sun (thus the phrase "orbital" debris").
The collisions of micrometeoroids, which are dust-sized pieces of asteroids and comets, naturally produce some debris.
Operational satellites may become space trash due to their short lifespans.
Due to the elevated potential of collision with and damage to operational satellites, the building of space trash poses a particularly catastrophic threat to humankind's future in space exploration.
Additionally, it might harm the environment of Earth.
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A car enters a freeway with a speed of 6.5 m/s and accelerates to a speed of 24 m/s in 3.5 min. How far does the car travel while it is accelerating? (Hint: find the acceleration first)
a 3205.5 m
b 1548.75 m
c 76.13 m
d 761.3 m
Explanation:
Using Equations of Motion :
(1) v = u + at
24 = 6.5 + a * 210
a (Acceleration) = 0.083 m/s^2
(2) v^2 = u^2 + 2aS
S = 576 - 42.25 / 0.166
S (Distance travelled) = 3215.3 m
(Option A seems a typo since the answer is 3215.3 m)
what does it mean when a problem is asking for the ph of a concentration at a certain temperature if given kb
When a problem is asking for the pH of a concentration at a certain temperature if given kb, it means that the problem is asking for the acidity or basicity of a solution at a specific temperature that is determined by the given value of kb (base dissociation constant).
What is pH?pH is a measure of the hydrogen ion concentration in a solution that determines its acidity or basicity. pH values range from 0 to 14, with 7 being neutral, values less than 7 being acidic, and values greater than 7 being basic or alkaline. kb is the dissociation constant of a base, which is defined as the concentration of hydroxide ions (OH-) when the base is dissolved in water. It is related to the pH of the solution by the formula:
pOH = -log(kb) pH = 14 - pOH
At a given temperature, the dissociation of a base affects the pH of the solution. Therefore, if the value of kb is given, it can be used to determine the concentration of hydroxide ions and pH of the solution. The exact calculation may vary depending on the specific problem, but it generally involves the use of the given value of kb, the molar concentration of the base, and the equilibrium constant expression of the reaction.
Therefore, when a problem is asking for the pH of a concentration at a certain temperature, given Kb, it means you need to calculate the pH of the solution based on the provided base dissociation constant (Kb) and temperature.
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a 415-kg container of food and water is dropped from a airplane
Since the object is experiencing free fall, if you ignore air resistance, the time it will take the container to fall 300m to the ground is 7.82 seconds.
What is free fall?Any motion of a body in which gravity is the only force acting on it is referred to as free fall.
The object dropped from the airplane is experiencing free fall.
Ignoring air resistance, the only force acting on the container is the force of gravity which accelerate the container by a constant value.
The time taken for the object to reach the ground is determined using the formula of an object experiencing free fall as given below:
s = ut + ¹/₂gt²
where
h is the height above the ground = 300 m
u is the initial vertical velocity of the container and is equal to zero since the object starts from rest.
g is the acceleration of gravity = 9.8 m/s²
t is the time = ?
The equation above becomes;
h = ¹/₂gt² since u is zero
Solving the equation for t:
t = √2h/g
t = √2 * 300 / 9.8
t = 7.82 seconds.
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Complete question:
A 415-kg container of food and water is dropped from an airplane at an altitude of 300m. First, consider the situation ignoring air resistance. Then calculate the more realistic situation involving a drag force provided by a parachute.
1. If you ignore air resistance, how long will it take the container to fall 300m to the ground?
Can you think of a way to explain Hubble's Law other than the
standard Big Bang idea, which includes the concept of a Universe
with no center and no edge?
An alternative way to explain Hubble's Law without relying on the standard Big Bang idea of a universe with no center and no edge is through the concept of a "tired light" hypothesis.
According to this hypothesis, the redshift observed in distant galaxies is not due to their motion away from us in an expanding universe, but rather the result of photons gradually losing energy as they travel through space.
In the tired light scenario, the wavelength of light is thought to stretch over time due to interactions with matter or other unknown processes. As a result, the light from distant galaxies appears redshifted, mimicking the effect of cosmic expansion. This explanation implies that the universe may have a finite size and a center, challenging the notion of an infinite and uniformly expanding universe.
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a fighter jet is launched from an aircraft carrier with the aid of its own engines and a steam-powered catapult. the thrust of its engines is 1.80 105 n. in being launched from rest it moves through a distance of 87 m and has a kinetic energy of 4.30 107 j at lift-off. what is the work done on the jet by the catapult?
A fighter jet being launched from such an aircraft carrier using a steam-powered catapult and its own engines. Its engines produce 2.3 x 105 N of thrust.
What speed is reached when a jet fighter aircraft is fired from a slingshot on an aircraft carrier?
42 m/s On an aircraft carrier, a catapult is used to launch a jet fighter. Just at end of the sling, it takes 2 seconds to achieve velocity of 42 m/s. What is the catapult's length if the acceleration is constant?
How strong is the aircraft carrier's catapult?
Catapults A 48,000-pound aeroplane was launched 300 feet and increased in speed from 0 to 165 miles an hour in two seconds by four steam-powered catapults. On every
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What is the translational kinetic energy, in MeV, of a proton moving at 0.54 of the speed of light ?
We would apply the relativistic kinetic energy formula which is expressed as
KE = (y - 1)mc^2 = [1/√(1 - v^2/c^2 - 1]mc^2
where
m is the mass of proton
c is the speed of light
v is the speed of the proton
From the information given,
m = 1.67 x 10^-27 kg
c = 3 x 10^8 m/s
v = 0.54c
Thus,
KE = 1.67 x 10^-27 x (3 x 10^8)^2[1/√(1 - (0.54c/c)^2 - 1]
KE = 28.27 x 10^-12 J
We would convert from joules to mev
1 J = 6,241,509,343,260 MeV
28.27 x 10^-12 = 28.27 x 10^-12 x 6,241,509,343,260
KE = 176.48 Mev
the translational kinetic energy is 176.48 Mev
Different between
atmospheric presure and liquid
pressure
Explanation:
An atmosphere (atm) is a unit of measurement equal to the average air pressure at sea level but liquid pressure is exerted on the surface of an object in a liquid.
And they also differ in formulas. We can calculate atmospheric pressure in two ways. First we can get the atmospheric pressure by an instrument called barometer. And the second one is by usin this formula, atmospheric pressure = density of mercury x acceleration due to gravity x height of column of mercury. But this equation will only work if the atmospheric pressure is being measured by mercury.
But the formula for liquid pressure is defferent and the instrument used to measure the liquid pressure is also defferent.
The instrument used to measure the liquid pressure is pressure gauge. And the formula for the liquid pressure is density x height x gravity. Please give me a like and thank me.
please.
if a truck has the mass of 2,000 kilometres and a velocity of 35 m/s, what is the momentum
Answer:
70,000 kg.m/sExplanation:
The momentum of an object can be found by using the formula
momentum = mass × velocity
From the question we have
momentum = 2000 × 35
We have the final answer as
70,000 kg.m/sHope this helps you
A ball is thrown straight off a 150 meter high roof at 20 m/s.
How long does it take for the ball to hit the ground?
What was the ball's final downward velocity?
How far did the ball travel horizontally?
What was the ball's displacement?
Answer:
I'll try and find the answer for you:)
Explanation:
I can't promise you I will though
. Which will exert more pressure, 100 kg mass on 10 m3 or 50 kg mass on 4 m2? Give reason
The 50 kg mass on 4 m2 on will exert more pressure.
What is pressure?
Pressure is described as the force applied perpendicular to the surface of an object per unit area over which that force is distributed.
Mathematically pressure = force / area
From Newton's second law
force = mass x acceleration where Acceleration due to gravity = 9.8m/s²
Comparing both pressures where
P1 = 100x 9.8 / 10
p1 = 100 pa
p2 = 50 x 9.8/ 4
p2 = 125 pa
Therefore The 50 kg mass on 4 m2 on will exert more pressure since it exerts more pressure.
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Explain how energy balance sets planetary temperature? Imagine a planet colder than expected for energy balance and explain why it warms up just enough to achieve energy balance but no more (assume no greenhouse gases).
The planetary temperature energy balance is obtained by radiating back the absorbed radiation energy from outer-space, by the planet and thus acquiring thermal equilibrium.
What is the process of attaining thermal equilibrium by Earth?
The Stefan-Boltzmann law states that the more the temperature a planet has, the more it will radiate out to reach thermal equilibrium.
We know that outer space contains large masses of radiative energy freely distributed in its vast expanse. A small fraction of this energy is absorbed by the Earth through the atmosphere, surface land, clouds etc.
Now, radiative balance is achieved when a planet's surface continuously warms up until it reaches its peak at which point the same amount of absorbed energy can then be radiated back to space. The relative amount of energy radiated back by a planet is dependent upon the size of the planet.
A colder planet relatively absorbs lower amount of radiation energy from space. In some time, as the planet heats up enough, the energy is radiated back to the space attaining thermal equilibrium.
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Question 29 of 43
Which is true of infrared waves?
They have shorter wavelengths than X-rays.
They give off more energy than gamma rays.
Ο Ο Ο Ο
o They have longer wavelengths than ultraviolet waves.
They have higher frequencies than visible light waves
Infrared wave basically have shorter wavelengths than X-rays. The correct option is A.
What is infrared wave?A section of the electromagnetic radiation spectrum with wavelengths ranging from roughly 700 nanometers (nm) to one millimetre is known as infrared radiation (IR), or simply infrared (mm).
While shorter than radio waves, infrared waves are longer than visible light waves.
Infrared radiation has the ability to ease muscle tension and encourage local blood circulation.
Infrared radiation has been used in conventional medicine to treat conditions including autoimmune diseases and issues with wound healing in addition to relieving muscle pain and tension.
Infrared waves are shorter than radio waves but longer than visible light waves.
Thus, the correct option is A.
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The element radon is at the opposite end of the range, with the lowest specific heat of all naturally occurring elements. Radon's specific heat is 94 J/kg°C. If the
temperature of a 0.34 kg sample of radon is to be raised by 25°C, how much energy will have to be added to the radon?
Explanation:
Q = mc∆T
= (0.34 kg)(94 J/kg-°C)(25°C)
= 799 J