Answer:
dagdagan mo hoy daya
Step-by-step explanation:
1733
at a race track, the average speed of the race cars is measured every lap. the box-and-whisker plot represents the average speed of a certain car for several laps. what is the range in the average speed?
The median of the given data is 131, which is the average of the two middle values of the box plot range.
The given box-and-whisker plot represents the average speed of a certain car for several laps. The median value is the middle value of the data when it is arranged in ascending or descending order. In this case, the median is the value that divides the box into two equal halves.
Since the box plot range is from 126 to 131 and 131 to 135, the median value would be the average of the two middle values, which are 131 and 131. Therefore, the median of the given data is (131+131)/2 = 131.
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Consider the overlapping generations model. Let the number of young people born each period be constant, at N. The fiat money stock changes at rate γ > 1, so that Mₜ = ᵧMₜ₋₁. Each young person born in period t is endowed with y units of the consumption good when young and nothing when old. (b) Draw the lifetime budget constraint on a diagram, with C₁ on the x-axis and C₂ on the vertical axis. (15%)
The lifetime budget constraint can be represented on a diagram by plotting C₁ on the x-axis and C₂ on the vertical axis.
How can the lifetime budget constraint be visually depicted on a diagram?The lifetime budget constraint illustrates the consumption possibilities for an individual over their lifetime. It shows the combinations of consumption in period 1 (C₁) and period 2 (C₂) that the individual can afford, given their initial endowment and borrowing constraints. The slope of the budget constraint represents the relative price of consumption in the two periods. The individual's budget constraint will shift outward if there is an increase in the initial endowment or a relaxation of borrowing constraints.
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Assume that the data are from ten randomly selected college students and for each student, the IQ score is measured before taking a training course and the IQ score is measured again after completion of the course. Each x value is the pre-course IQ score and each y value is the corresponding post-course IQ score.
x 105 103 118 137 95 89 89 79 103 103
y 111 108 112 107 108 110 110 109 118 110
a. Pose a key question that is relevant to the given data.
b. Identify a procedure or tool from this chapter or the preceding chapters to address the key question from part (a).
c. Analyze the data and state a conclusion.
a. Key question: Does completing the training course have a significant effect on the IQ scores of college students?b. Procedure/tool: Paired t-test or paired difference test can be utilized to analyze the data
To address the key question, we compare the pre-course (x) and post-course (y) IQ scores of the ten randomly selected college students. We calculate the differences between the pre-course and post-course IQ scores for each student: (-6, -5, -6, -30, 13, 21, 21, 30, 15, 7).
Next, we compute the mean difference, which is 7.2, and the standard deviation of the differences, which is 13.95.
Using a statistical software or calculator, we perform a paired t-test on the differences. Assuming a significance level of 0.05, we find that the calculated t-value is 0.517 and the corresponding p-value is 0.615.
Since the p-value is greater than the significance level, we fail to reject the null hypothesis. This means that there is not enough evidence to conclude that completing the training course has a significant effect on the IQ scores of college students based on the given data.
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Matthew’s math teacher gave him 6 tests. If his average was 72%, what was the sum of all of his tests? Show ALL of your work.
Raphael i h year old
a) Lily' age i Raphael' age divided by 3. Write an expreion in term of h for Lily' age
b) An expreion for Ethan' age i h6. Write a entence to decribe how Ethan' age compare with Raphael' age
a) When Lily's age is 20, and Raphael's age is divided by 3 then the expression of Lily's age in terms of h is h < 10.
b) Ethan's age is half of Raphael's age therefore, Ethan's age is half Raphael's age.
a) If Raphael is twice as old as his sister Lily, we can represent their ages as 2h and h, respectively, where h is Lily's age. The sum of their ages is less than 30, so we can write the equation:
2h + h < 30
Combining like terms, we get:
3h < 30
Dividing both sides by 3, we get:
h < 10
This is an expression of Lily's age in terms of h.
b) If Ethan's age is 16, and Raphael's age is twice Ethan's age, we can represent Raphael's age as 2 × 16 = 32.
Ethan's age is 16, which is half of Raphael's age of 32. Therefore, Ethan's age is half of Raphael's age.
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The question is -
Raphael is twice as old as his sister. The sum of their ages is less than 30.
a) Lily's age is 20, and Raphael's age is divided by 3. Write an expression in terms of h for Lily's age.
b) An expression for Ethan's age 16. Write a sentence to describe how Ethan's age compares with Raphael's age.
If the mug cost $6 last year and the price increased by 25%, how much did the mug cost this year?
Answer:7.5
Step-by-step explanation:
6*0.25=7.5
plsssss can anyone help me
Answer:
I will answer with the best of my ability and apologize for any and all inconveniences. The answer I have gotten is
.10445833
Find the value of the product (4a2 + 3b) (4a2+36) at a = 1, b = 2.
The final value of the product = 292
According to the given equation -
= (4a2+3b)x(4a2+36)
multiply the whole equation-
= 16a4+144+12a2b+108
as we can see that the values of a and b are given 1 and 2 respectively,
so putting the values of a and b in the equation we get -
= 16(1)4+144+12(1)2(2)+108
= 292
The product of the following equation will be = 292
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Question 3 (5 points)
Use the graph to solve the system of linear equations.
Оа
(-4,-4)
Ob
(-1.5,-1)
ос
(2,0)
Od
(-2,-2)
Answer:
D
Step-by-step explanation:
(-2,-2) is where both the lines intersect
Find fx and fy, and evaluate each at the given point. f(x, y) = exy2, (ln 2, 2)
The partial derivative with respect to x at the given point is 2e^4, and the partial derivative with respect to y at the given point is 8e^4.
To find the partial derivatives of f(x,y) = exy^2, we differentiate f with respect to x and y, treating the other variable as a constant. So,
fx(x,y) = y^2exy^2
fy(x,y) = 2xyexy^2
At the point (ln 2, 2), we have:
fx(ln 2, 2) = 2e^4
fy(ln 2, 2) = 8e^4
Therefore, the partial derivative with respect to x at the given point is 2e^4, and the partial derivative with respect to y at the given point is 8e^4.
These partial derivatives give us information about how the function changes in each direction at the given point.
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3,495 rounded to the nearest hundred
Answer:
3500
Step-by-step explanation:
9 rounds up the number 4 to 5
3500
Answer:
3,500
Step-by-step explanation:
because 9 is greater than 5 so u would round upward and that 495 would become a 500 but theres also the 3,000 so add the two together and you would get 3,500
х
x
320
X=
degrees.
SJSJSJSJS Ja
Answer:
122
Step-by-step explanation:
The exterior angle of a triangle is the sum of the opposite interior agnles
32+90 =x
122 =x
An exterior angle of a triangle is equal to the sum of its interior opposite angles.
\( \bf \large \hookrightarrow \: \: x \: = \: 32 \degree \: + \: 90 \degree \)
\(\bf \large \hookrightarrow \: \: x \: = \: 122 \degree\)
The talk-time battery life of a group of cell phone is normally distributed with a mean
of 5 hours and a standard deviation of 15 minutes.
b) What percent of the phones have a battery life between 4. 5 hours and 5. 25
hours? (include 1 decimal place WITHOUT the % sign)
The battery life of the phones follows a normal distribution with a mean of 5 hours and a standard deviation of 15 minutes. We need to calculate percentage without using the % sign and rounded to one decimal place.
To solve this problem, we need to convert the given battery life values into the same units as the mean and standard deviation. Since the mean is in hours and the standard deviation is in minutes, we convert 4.5 hours to minutes by multiplying it by 60, and 5.25 hours by multiplying it by 60.
The converted values are 270 minutes and 315 minutes, respectively. Next, we use the properties of a normal distribution to calculate the percentage of cell phones with a battery life between these two values. We can use a Z-table or a statistical calculator to find the corresponding Z-scores for these values. Once we have the Z-scores, we can find the percentage by subtracting the cumulative probability associated with the lower value from the cumulative probability associated with the higher value.
Using the Z-table or a statistical calculator, we find that the Z-score for 270 minutes is approximately -1.33, and the Z-score for 315 minutes is approximately 0.33. Subtracting the cumulative probability corresponding to -1.33 from the cumulative probability corresponding to 0.33 gives us the desired percentage.
Therefore, the percentage of cell phones with a battery life between 4.5 hours and 5.25 hours is approximately 62.8 (rounded to one decimal place without the % sign).
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Select all the correct answers. Exponential function fis represented by the table. x 0 1 2. B 4 f(x) -12 -4 0 2 3 Function gis represented by the equation g(x) –12() Which statements are true about the two functions? The functions have the same y-intercept. Both functions are increasing on all intervals of x. Both functions approach - as x approaches - Both functions approach the same value as x approaches The functions have the same x-intercept.
The functions have the same y-intercept. = true
Both functions are increasing on all intervals of x = true
Both functions approach - as x approaches = false
Both functions approach the same value as x approaches = false
The functions have the same x-intercept. = false
Midpoint of (2,4) and (2, -7)
Step-by-step explanation:
soln:
let,
(x1,y1) =(2,4)
(x2,y2)=2,-7)
Now,
By midpoint formula,
×= x1+x2
2
= 2+2
2
=4
2
=2,,
And,
Y=y1+y2
2
=4-7
2
= -3
2
Hence ,
The mispoint between points (2,4) and (2,-7) is (2,-3 )
2
That's driver pays all tall is using only nickels and dimes by throwing one coin at a time into the mechanical toll collector
Since nickel is 5 cents and a dime is 10 cents, the possible tolls that you can pay need to be multiplies of 5 cents.
Let on represent the number of a ways
for the number of different ways the bus
The driver can pay a toll of 5n rent first case.
The first case used in a nickel then there are ways to pay =
57 - 5 = 5 ( 1 - 1 ) cents
The second case: - The coin used is a dime, then
there is a long way to
pay 5n - 10 2 5 ( 1 - 2 ) cents -
Adding the numbers of sequence of all
In three cases, we then obtain
an = an - 1 an +2
Initially, when n 20 there is exactly I way to pay cents ( using no coins )
when an = 1 there is exactly I to way
to pay 5 cents ( using one tickle )
q =f .
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What is 16,850 rounded to the nearest ten thousands
Answer:
20,000
Step-by-step explanation:
To round numbers to the nearest ten thousand, make the numbers whose last four digits are 0001 through 4999 into the next lower number that ends in 0000. For example 54,424 rounded to the nearest ten thousand would be 50,000.
Rewrite as multiplication:17x2Multiply the numerator and the denominator:Simplify by dividing both the numerator and denominator by the GCF:Answer:
ANSWER
EXPLANATION
After we rewrite this as a multiplication we have to do the multiplication. The result is a fraction whose numerator is the product of the numerators of the fractions and the denominator is the product of the denominators,
\(\frac{2}{7}\times\frac{5}{2}=\frac{2\times5}{7\times2}=\frac{10}{14}\)Then, the GCF between the numerator and denominator is 2, so we have to divide both by 2,
\(\frac{10\div2}{14\div2}=\frac{5}{7}\)Hence, the answer is 5/7
histograms are used to a. determine the distribution of nonresponse errors. b. investigate the relation between two variables. c. construct cumulative distribution functions. d. construct cross tabulation tables. e. determine the empirical distribution of a variable.
Histograms are used to determine the empirical distribution of a variable. Therefore, option (e) is the correct one.
Histogram is used to summarize discrete or continuous data measured on an interval scale. It is often used to describe key features of the distribution of data in a practical way.
A histogram divides the range of possible values in a data set into different classes or groups. For each group, a rectangle is created with a base length equal to the range of values in that particular group and a length equal to the number of observations that fall into that group.
Histograms are similar to column charts, but there are no gaps between the bars. Histograms generally have equal width bars.
Thus, it can be concluded that histograms are used to determine the empirical distribution of a variable. Therefore, option (e) is the correct one.
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solve the equation using the quadratic formula. 3v^2+3=-v
Answer:
v=− 1± i √35 /6
Step-by-step explanation:
Solve the equation for v by finding a , b , and c of the quadratic then applying the quadratic formula.
Use the definition of Taylor series to find the first three nonzero terms of the Taylor series (centered at c) for the function f. f(x)=4tan(x), c=8π
\(f(x) = 4tan(8\pi) + 4sec^2(8\pi)(x - 8\pi) + 8sec^2(8\pi)tan(8\pi)(x - 8\pi)^2/2!\)
This expression represents the first three nonzero terms of the Taylor series expansion for f(x) = 4tan(x) centered at c = 8π.
What is the trigonometric ratio?
the trigonometric functions are real functions that relate an angle of a right-angled triangle to ratios of two side lengths. They are widely used in all sciences that are related to geometry, such as navigation, solid mechanics, celestial mechanics, geodesy, and many others.
To find the first three nonzero terms of the Taylor series for the function f(x) = 4tan(x) centered at c = 8π, we can use the definition of the Taylor series expansion.
The general formula for the Taylor series expansion of a function f(x) centered at c is:
\(f(x) = f(c) + f'(c)(x - c)/1! + f''(c)(x - c)^2/2! + f'''(c)(x - c)^3/3! + ...\)
Let's begin by calculating the first three nonzero terms for the given function.
Step 1: Evaluate f(c):
f(8π) = 4tan(8π)
Step 2: Calculate f'(x):
f'(x) = d/dx(4tan(x))
= 4sec²(x)
Step 3: Evaluate f'(c):
f'(8π) = 4sec²(8π)
Step 4: Calculate f''(x):
f''(x) = d/dx(4sec²(x))
= 8sec²(x)tan(x)
Step 5: Evaluate f''(c):
f''(8π) = 8sec²(8π)tan(8π)
Step 6: Calculate f'''(x):
f'''(x) = d/dx(8sec²(x)tan(x))
= 8sec⁴(x) + 16sec²(x)tan²(x)
Step 7: Evaluate f'''(c):
f'''(8π) = 8sec⁴(8π) + 16sec²(8π)tan²(8π)
Now we can write the first three nonzero terms of the Taylor series expansion for f(x) centered at c = 8π:
f(x) ≈ f(8π) + f'(8π)(x - 8π)/1! + f''(8π)(x - 8π)²/2!
Simplifying further,
Hence, \(f(x) = 4tan(8\pi) + 4sec^2(8\pi)(x - 8\pi) + 8sec^2(8\pi)tan(8\pi)(x - 8\pi)^2/2!\)
This expression represents the first three nonzero terms of the Taylor series expansion for f(x) = 4tan(x) centered at c = 8π.
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hii can i pls have help, i will give brainliest:D
Answer:
4
Step-by-step explanation:
half gallon is 64 oz. 256 ÷ 64 is 4
Answer
4
Step-by-step explanation:
1 gallon = 128 fluid ounces
1/2 gallon = 64 fluid ounces
Use gallons to convert 256 fl oz then multiply result by 2
256 / 128 = 2
2 x 2 = 4
4 half gallon containers
If my answer is incorrect, pls correct me!
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Does anyone know the answer to all these three?
Answer:
A. 0.7
B. 0.7
C. 0.07
Step-by-step explanation:
7/10=0.7
70/100=0.7
7/100=0.07
The Acme Corporation believes that the production of its product in its present facilities will assume logistic growth. These facilities limit production to at most 500 units per day. Presently 200 units per day are produced. The production will increase to 250 units per day in one year. What is the anticipated daily production 3 years from now? (Round down.) a) 402 units per day b) 346 units per day c) 385 units per day d) 323 units per day Allowing for roundoff, which of the following is equ
The anticipated daily production 3 years from now is approximately 385 units per day.
To determine the anticipated daily production 3 years from now, we can use the logistic growth model. The logistic growth model is given by the equation:
P(t) = K / (1 + A * e^(-k*t))
Where:
P(t) is the population (or in this case, daily production) at time t
K is the carrying capacity or the maximum production limit
A is the initial difference between the carrying capacity and the initial production
k is the growth rate
t is the time in years
Given the information:
Initial production (t = 0): 200 units per day
Production after 1 year (t = 1): 250 units per day
Maximum production limit (K): 500 units per day
We can use these values to find the growth rate (k) and the initial difference (A):
A = K - P(0) = 500 - 200 = 300
P(1) = K / (1 + A * e^(-k*1)) = 250
250 = 500 / (1 + 300 * e^(-k))
1 + 300 * e^(-k) = 500 / 250 = 2
300 * e^(-k) = 2 - 1 = 1
e^(-k) = 1/300
-k = ln(1/300)
k ≈ -5.703
Now, we can calculate the anticipated daily production 3 years from now (t = 3):
P(3) = K / (1 + A * e^(-k*3))
P(3) = 500 / (1 + 300 * e^(-5.703 * 3))
P(3) ≈ 385 units per day
Therefore, the anticipated daily production 3 years from now is approximately 385 units per day.
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PLS HELP FOR BRAINLIST!!!!!!!!There are 24 more students in a math class than in a history class. If the ratio of the students in the math class to the history class students is 11 : 5, how many students are in math class?
Answer:
11 - 5 = 6
24/6= 4
4 X 11 = 44
4 X 5 = 20
44 students in math class
On the last day of the fiscal year, a co-worker asks you to cut a check for $2,000 as a miscellaneous expense for supplies in order to complete a project for a VIP customer today. You notice the invoice looks a little different from other invoices that are usually processed. You know that by preparing the closing entries tomorrow, the miscellaneous expense will be set to zero for the beginning of the year. Should you write this check today and record the expense or write the check tomorrow? How would the company be affected if the check is written and the invoice ends up being erroneous?
Answer:
A. No, Should not in any way write the check today and neither record the expense or even write the check tomorrow.
B. The company will be affected if the check
was cut today and the expense was not recorded, which means that the net income of the current fiscal year will be increased by the amount of $2,000 while the net income of the next year will be reduced by the amount of $2,000 and this tend to happens due to some error.
Step-by-step explanation:
A. Based on accounting principle every debit entry must have a corresponding credit entry which means that in a situation where a check is been cut today for miscellaneous expense and for supplies the Miscellaneous expense account should be debited while the bank account should as well be credited based on the double entry principle because if not so the current year net income will wrongly shows and be higher with the amount of $2,000.
B. In a situation where the check was cut today and expense was recorded the following day or tomorrow it means that the current year financial statement net income will be increased by the amount of $2,000 while the amount shown in the balance sheet will decreased by the amount of $2,000.
Therefore I can issue a check today and as well record the expense the same day in which the check was issued.
Following are the solution to the given question:
When an invoice appears to just be distinct from those other bills which are typically handled, this should be filtered once the accountant receives the necessary verification regarding its accuracy/validity.This expense must be noted as well as the check must be written only after sufficient proof of its legitimacy/accuracy has indeed been acquired. This is possible to do it now and tomorrow, but after ensuring that the bill is right. If the accountant has been unable to gather relevant data or evidence through that he or she is uncertain about the accuracy of the invoice as of today, the expense must be recorded as well as the check is written today only after being certain the invoice is correct.Whereas if cost is reported today as well as the check was made, this will increase the overall cost for the current year now and reduce the operating earnings again for the current quarter. Whether it is later discovered that this invoice was incorrect, a reverse of accounting point of view for this invoice must be posted, reducing the expense for the following year and raising the net income for the next month.When an expense is recorded in the current year and subsequently reversed in the following year (due to an incorrect invoice), the income for the current year will be understated, while the income for the following year would be overstated by the amount of the cost.Furthermore, so because the cheque was written yesterday in the current year, the cash/bank balance will be recorded as lowered by the amount of this check for the current year. Whenever the check is reversed the following year, its cash/bank balance would be tallied with cash/bank balance as recorded by the bank.Learn more:
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Find the complement of the set given that u = {0, 1, 2, 3, 4, 5, 6, 7, 8}. (enter your answers as a comma-separated list.) the set of odd natural numbers less than 8
{ 0,2,4,6,8} is the complement of the set.
What is natural number in math?
Normative Numbers The numbers we use to count or place things in order are 1, 2, 3, 4, 5, 6, 7, 8, 9, 10, and 11. Complete numbers the range of numbers that includes zero and natural numbers.Is zero a natural number?
0 is not a natural number, so no. As we all know, natural numbers are positive integers with a range of 1 to infinity. However, we get a number when we combine 0 with a positive integer like 10, 20, or another number.u = {0, 1, 2, 3, 4, 5, 6, 7, 8}
Odd number less than 8 = { 1,3,5,7 }
complement = {0, 1, 2, 3, 4, 5, 6, 7, 8} - { 1,3,5,7 }
= { 0,2,4,6,8}
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8
9
16
18
24
27
36
32
45
Which number completes the table of equivalent ratios?
A)
38
B)
40
o
42
D)
44
Answer:
40
Step-by-step explanation:
...... ...... ...... ..... .
Whats the area?/ ty show work!
Answer:
25
Step-by-step explanation:
4 times 3 is 12
5 times 3 is 15
15 plus 12 is 25
Hello!
(4*3) + (3*5)
= 12+15
= 27
A cork has a mass of 3.00 grams and a volume of 16.0 cm3. Calculate the density.
Answer:
0.1875
Step-by-step explanation: