B. Directions: Identify what stage of human
development is being described. Choose
from the list of words inside the box.
ADULTHOOD
INFANCY
BIRTH
1. A child learns to walk, talk
and begin to be more self-sufficient at
this stage
2. A child is completely
dependent on the care of his parents in this
stage.
3. It is the stage that the boys
begin to experience changes in their
voice.
4. Boys and girls gain more
independence from their parents during
this stage.
5. Girls at this stage begin to
menstruate ad are now capable of
giving birth.​

Principal Components Analysis (PCA) is an exploratory method that uses measurements to summarize the data and reveal the underlying structure of the variables.

Principal Components Analysis involves the reduction of complex data sets with many variables to a smaller number of linear combinations of the original variables known as principal components. PCA is used to identify patterns in data by determining the correlation between variables and simplifying data for ease of interpretation.

The plot shows the correlation between different variables in the sampling sites, which include the mariculture centre and the marina. The plot shows that the variables are highly correlated with each other, and they can be summarized by the first two principal components.

The plot shows that the mariculture centre has higher mean concentrations of ammonia and phosphate than the marina.

The mean concentrations of ammonia and phosphate were 0.55 and 0.18 in the mariculture centre compared to 0.17 in the marina. This suggests that the mariculture centre has higher nutrient levels than the marina.

In conclusion, principal components analysis (PCA) is a useful tool for summarizing complex data sets and identifying patterns in data. The PCA plot shows the correlation between different variables in the sampling sites, and it reveals that the mariculture centre has higher nutrient levels than the marina.

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Answer:

:)

Explanation:

Gay-Lussac's Law states that the pressure of a given mass of gas varies directly with the absolute temperature of the gas, when the volume is kept constant.

Answer:

Because the interstellar medium is 97% hydrogen and 3% helium, with trace amounts of dust, etc., a star primarily burns hydrogen during its lifetime. A medium-size star will live in the hydrogen phase, called the main sequence phase, for about 50 million years. Once hydrogen fuel is gone, the star has entered “old age.”

Answer: for a star to start the process of become an old star it has to burn all the hydrogen in the star.

Explanation:

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Given that

• T1 = 290K,

• T2 = 250K

• V1 = 1L

• V2=...?

We will use Charles's law formula to determine the resulting volume

V1 / T1 = V2 / T2.

→V2 = (V1*T2 )/T1

=1*250/290

=0.86 L

This is true because when temperature decreases , volume also decreases .

Answer:

4.)33.2 g

Explanation:

(1.25E24/6.022E23)×15.99

There are several different routes of administration for medications and each has its own benefits and risks. The route of administration that is considered the safest in terms of purest ingredients and standardized dosing is oral administration.

Oral administration involves swallowing a pill or liquid medication. The medication then passes through the digestive system and is absorbed into the bloodstream through the small intestine. Oral administration is the most commonly used route of administration, and medications given orally are usually available in standardized dosages. The ingredients in the medication are also usually pure and free from contaminants.

In contrast, other routes of administration, such as intravenous (IV) administration, involve directly injecting medication into the bloodstream. This method can be risky if the medication is not prepared and administered correctly. There is also a risk of infection if proper sterile techniques are not followed.

In conclusion, oral administration is generally considered the safest route of administration in terms of purest ingredients and standardized dosing. However, it is important to note that each patient and medication is different, and healthcare professionals should always carefully evaluate the best route of administration for each individual case.

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The heat energy needed to change the 5.25  gram sample from a temperature of 49.5 to 40.5 °C is given 10.4  J. Then, the specific heat of the metal is 0.22 J/°C g.

Calorimetry is an analytical  technique used to determine the heat energy absorbed or released by  a system. The calorimetric equation relating the heat energy q with the mass of the substance, m, specific heat, c and temperature difference, ΔT is given as:

q = m c ΔT.

Given that the mass of the sample of iron = 5.25 g

temperature difference   ΔT = 49.5 - 40.5 = 9 °C

specific heat c = 0.450 J/ g °C.

The heat energy absorbed by the sample is calculated as follows:

10.4 J = 5.25 g ×  c J/ g °C × 9 °C.

Then,

c = 10.4 J / (5.25 g ×9 °C )

  = 0.22 J/ g °C

Therefore, the specific heat of the metal is 0.22 J/ g °C.

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Answer:

37.5 grams

Explanation:

The percent yield shows how much of the reactant have been converted to product. The percent yield is the ratio of actual yield to theoretical yield multiplied by 100%. It is given by the formula:

%yield = Actual yield/ theoretical yield × 100%

Given that theoretical yield = 50 grams and the percent yield is 75%.

Using the formula and substituting:

75% = Actual yield/ 50 g × 100%

75% / 100% = Actual yield / 50 g

0.75 = Actual yield / 50 g

Actual yield = 0.75 × 50 g

Actual yield = 37.5 grams

The combination of the given components yields -16.5.

To find the combination AV​/2 - 2By​ + 5CV​,

We need to substitute the given components of vectors A, B, and C into the expression.

Given:

Ax​ = 1.0

Ay​ = 2.0

Bx​ = 3.5

By​ = -4.0

Cx​ = -5.0

Cy​ = 6.

Substituting these values into the expression:

AV​/2 - 2By​ + 5CV​ = (Ax/2) - 2(By) + 5(Cx)= (1.0/2) - 2(-4.0) + 5(-5.0)

= 0.5 + 8.0 - 25.0

= -16.5

Therefore, the combination of the given components yields -16.5.

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Answer:

(a) Formation of the carbocation is the rate-determining step (RDS)

(c) Reactions at chiral carbons proceed with inversion of stereochemistry

Explanation:

SN1 reactions arenucleophilic substitution reactions in which the rate determining step is unimolecular.

The formation of a carbocation is the rate determining step. This depends on the electrophilicity of the leaving group. Thus the SN1 reaction mechanisms is dependent on the electrophile and not the nucleophile.

Polar and acidic solvents which can assist in the formation of the carbocation speeds up the rate determining step.

If the formation of carbocation occurs at a chiral center, both retention and inversion of stereochemistry are likely to occur.

Therefore, the correct options are A and C.

Explanation:

The given molecule is

H3C - C ≡ C - CH3

The numbering order is shown below:

H3C - C ≡ C - CH3

    1     2     3     4

So, the alkyne group is in the second position.

The carbon chain has four carbons.

Hence, the IUPAC name of the given compound is:

2-butyne.

The freezing point of the solution is -11.8 °C.

The boiling point of the solution is 103.31 °C.

To determine the freezing point of the solution, we can use the equation:

ΔTf = Kf * m

where:

ΔTf is the freezing point depression,

Kf is the cryoscopic constant (for water, Kf = 1.86 °C/m),

m is the molality of the solution (moles of solute per kilogram of solvent).

First, let's calculate the molality (m) of the solution:

Molar mass of ethylene glycol (C2H6O2):

C = 12.01 g/mol

H = 1.01 g/mol (x 6) = 6.06 g/mol

O = 16.00 g/mol (x 2) = 32.00 g/mol

Total molar mass = 12.01 g/mol + 6.06 g/mol + 32.00 g/mol = 50.07 g/mol

Number of moles of ethylene glycol (C2H6O2) = mass / molar mass

Number of moles = 30.8 g / 50.07 g/mol = 0.615 mol

Mass of water = volume x density = 96.6 mL x 1.00 g/mL = 96.6 g

Now, let's calculate the molality:

Molality (m) = moles of solute / mass of solvent (in kg)

Molality = 0.615 mol / 0.0966 kg = 6.36 mol/kg

Now we can calculate the freezing point depression (ΔTf):

ΔTf = Kf * m

ΔTf = 1.86 °C/m * 6.36 mol/kg = 11.8 °C

To find the freezing point of the solution, subtract the freezing point depression from the freezing point of pure water (0 °C):

Freezing point = 0 °C - 11.8 °C = -11.8 °C

To determine the boiling point of the solution, we can use the equation:

ΔTb = Kb * m

where:

ΔTb is the boiling point elevation,

Kb is the ebullioscopic constant (for water, Kb = 0.52 °C/m),

m is the molality of the solution (same value as calculated before: 6.36 mol/kg).

ΔTb = 0.52 °C/m * 6.36 mol/kg = 3.31 °C

To find the boiling point of the solution, add the boiling point elevation to the boiling point of pure water (100 °C):

Boiling point = 100 °C + 3.31 °C = 103.31 °C

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Pressure will it have if it's cooled is 0.264 atm

It is given that

volume of Hydrogen gas = 100.0 mL

pressure = 300 Torr

1 torr = 0.00132 atm

300 Torr = 0.396 atm

temperature 1 = 27°C = 300 K

temperature 2 = –73°C = 200 K

We have to find

pressure

Gay-Lussac's Law or Third Gas Law states that for a constant volume, the pressure is directly proportional to absolute temperature: P alpha T; also stated as P/T = K, where K is a constant, and similarly, P1/T1 = P2/T2

0.396/300 = P2/200

P2 = 0.396 x 200/300 = 0.264 atm

Hence, Pressure will it have if it's cooled is

0.264 atm

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Answer:

because we bystanders can see them through the sky and from the ground.

Explanation:

pls give brainliest im almost lvled up.

Answer:

Air pressure and the density of the air are also less at high altitudes. The layer above the troposphere is called the stratosphere. Nearly all of the water vapor and dust particles in the atmosphere are in the troposphere. That is why most clouds are found in this lowest layer, too.

Explanation:

The presence of crystals can affect the heat measurement of molten salt. Also, the molten salt must be super-cooled for constant pressure.

We can arrive at this answer because:

Furthermore, when in contact with water, the salt can cause pressure changes, which can impair the measurement of the calorimeter in relation to the salt. To prevent this from happening the salt must be super-frozen, thus maintaining a constant temperature.

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The balanced equations of the reaction are given below:

Overall equation: 2 H_O → H₂O₂ (l)

Equation 1: H_O ---> H_O (g)

Equation 2: H_O (g) → H₂O₂ (g)

Equation 3: H₂O₂ (g) → H₂O₂ (l)

A balanced equation is an equation of a chemical reaction in which the number of moles of atoms for all the elements in the reaction is equal on both sides of the reaction.

A balanced chemical equation is obtained from the law of conservation of matter that states matter can not be created or destroyed.

Balancing chemical equations involves the addition of numerical coefficients to the reactants and products.

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Answer: C

Explanation:

Answer:

sup

Explanation:

In the context of atomic orbital (AO) wavefunctions, the terms "radial node" and "nodal plane" refer to different aspects of the wavefunction's behavior.

A radial node is a region in the AO wavefunction where the probability of finding an electron is zero along the radial direction. In other words, it represents a spherical shell where the electron is unlikely to be found. The number of radial nodes is determined by the principal quantum number (n) of the orbital. For example, the 2s orbital has one radial node, while the 2p orbital has no radial nodes.

On the other hand, a nodal plane is a flat plane within the AO wavefunction where the probability of finding an electron is zero along a particular direction. It represents a surface that divides the orbital into two regions of opposite phases. The number of nodal planes is determined by the angular quantum numbers (l and m) of the orbital. For example, the 2s orbital has no nodal planes, while the 2p orbital has one nodal plane (the xz or yz plane).

Radial nodes arise from the radial part of the wavefunction because they depend on the distance from the nucleus. The radial part determines the distribution of the electron density as a function of distance, and the nodes correspond to regions where the density drops to zero.

On the other hand, nodal planes arise from the angular part of the wavefunction because they depend on the orientation and shape of the orbital. The angular part describes the angular distribution of the electron density around the nucleus, and the nodal planes correspond to regions where the phase of the wavefunction changes sign.

In summary, radial nodes are related to the distance from the nucleus and arise from the radial part of the wavefunction, while nodal planes are related to the orientation and shape of the orbital and arise from the angular part of the wavefunction. The 2s orbital has one radial node and no nodal planes, while the 2p orbital has no radial nodes and one nodal plane.

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Answer:

D is the answer

Explanation:

Answer:

acetone evaporates faster than hexane.

Explanation:

because acetone does nor participate in hydrogen bonding, so it's intermolecular forces are comparatively weaker, and it evaporates most quickly.

The carbonyl stretching frequency in the infrared spectrum depends on the nature of the carbonyl group and the adjacent functional groups or substituents. Based on this, we can rank the given molecules in terms of their carbonyl stretching frequency, from highest to lowest:

2,4-cyclohexadienone > 2-cyclohexenone > cyclohexenone > cyclohexanone

In general, a carbonyl group adjacent to an electron-withdrawing group will have a higher stretching frequency compared to a carbonyl group adjacent to an electron-donating group.

In 2,4-cyclohexadienone, the two carbonyl groups are conjugated with each other and with the double bonds in the ring, resulting in a very high carbonyl stretching frequency. In 2-cyclohexenone, the carbonyl group is conjugated with the double bond in the ring, resulting in a slightly lower stretching frequency.

In cyclohexenone, the carbonyl group is adjacent to a single double bond in the ring, resulting in a lower stretching frequency compared to 2-cyclohexenone. In cyclohexanone, the carbonyl group is not conjugated with any other functional group, resulting in the lowest carbonyl stretching frequency among the given molecules.

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Due to the interatomic Si-O bonds' substantial covalent character and directionality, which restricts the efficiency of atom packing, silicate materials have relatively low densities.

By sharing electrons among nearby atoms, covalent bonds produce a stable electron configuration. At least one electron from each atom will be shared by two atoms that are covalently connected. A 3D structure is created. The bonds between atoms are very directional because electrons are shared between them. Because of this directionality, atomic packing is less dense and results in low density.

The second most plentiful element on earth, silicon, is a crucial component of the mineral world. Due to its solid tetrahedral structure, it is very adaptable and used in a variety of ways in our daily lives.

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The decay constant, or the proportion of atoms that decay per unit time, can be calculated by using the half-life of oxygen-15 as a starting point. Since oxygen-15 has a 2 minute half-life, we can infer that:

t1/2 = 2 secondsThe formula below can be used to determine the decay constant () using the half-life:λ = ln(2) / t1/2= 2 minutes / ln(2)= 0.3466 minutes to one.The number of atoms that will still be present after the tube has been moved at 0.80c relative to Earth for 2 minutes can then be calculated using the decay constant. We'll apply the radioactive decay formula: = N0 * e^(-λt)where N is the number of atoms at time t and N0 is the number of atoms at the beginning.The decay constant is.t = the passing of timeKnowing N0 = 1000 and t = 2 minutes, and we recently determined that = 0.3466 minutes-1. The Lorentz factor, which measures the time dilation brought on by the motion of the tube, must be taken into consideration:= sqrt(1 - v2/c2) / 1.where v is the tube's speed (0.80c).the light speed, c= sqrt(1 - (0.80c)2/c2)γ = 1.67The moving tube's clocks show the following time has passed:t' = t, t' = 2, 1.67 t' = 1.1988 minutes, etc.We can now enter the values to determine how many atoms are still present:N = N0 * e^(-λt')N = 1000 * e (-0.3466 min -1 min 1.1988)N = 549.2Thus, the tube that was travelling at 0.80c in relation to Earth will have roughly 549 oxygen-15 atoms left within at the conclusion of the two minutes according to Earthly clocks.We




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Answer:

IUPAC name for Titin

Explanation:

The IUPAC name for Titin. This is the largest known protein and so has the longest chemical name. Written in full, it contains 189,819 letters.

════════ ∘◦❁◦∘ ════════

#you can see the formula in pic for more detail writting

Mg2+ + Cl- -> MgCl2

════════════════════

════════════════════

Answer:

Explanation:

To solve this problem, we need to use the balanced chemical equation for the reaction between hydrobromic acid (HBr) and magnesium hydroxide (Mg(OH)2):

2HBr + Mg(OH)2 -> MgBr2 + 2H2O

From the equation, we can see that 2 moles of hydrobromic acid react with 1 mole of magnesium hydroxide.

We are given the volume of the hydrobromic acid as 5.0 mL, but we do not know the number of moles of hydrobromic acid present. However, we do know the concentration and volume of the magnesium hydroxide used for the titration. We can use this information to calculate the number of moles of magnesium hydroxide used in the titration:

Molarity of Mg(OH)2 = 1.50 M

Volume of Mg(OH)2 used = unknown (we don't know how much was added to reach the endpoint)

We can assume that the reaction between the two solutions goes to completion and that all the magnesium hydroxide reacts with the hydrobromic acid present. Therefore, we can set up the following equation using the stoichiometry of the reaction:

2 moles HBr = 1 mole Mg(OH)2

moles of HBr = (moles of Mg(OH)2) / 2

Using the equation for molarity (M = moles / liters), we can calculate the number of moles of magnesium hydroxide used in the titration:

Molarity of Mg(OH)2 = moles of Mg(OH)2 / volume of Mg(OH)2

moles of Mg(OH)2 = Molarity of Mg(OH)2 x volume of Mg(OH)2

We don't know the volume of Mg(OH)2 used, but we can use the volume of hydrobromic acid and the balanced chemical equation to determine it. Since 2 moles of HBr react with 1 mole of Mg(OH)2, we can say that:

moles of Mg(OH)2 = (moles of HBr) / 2

Using the equation for molarity and the given volume of hydrobromic acid (5.0 mL or 0.005 L), we can calculate the number of moles of hydrobromic acid present:

Molarity of HBr = moles of HBr / volume of HBr

moles of HBr = Molarity of HBr x volume of HBr

Now we can combine the equations to solve for the unknown volume of magnesium hydroxide used in the titration:

moles of Mg(OH)2 = (Molarity of Mg(OH)2) x (volume of Mg(OH)2)

moles of HBr = 0.5 x moles of Mg(OH)2 (since 2 moles of HBr react with 1 mole of Mg(OH)2)

moles of HBr = (Molarity of HBr) x (volume of HBr)

Since the moles of HBr are the same in both equations, we can set them equal to each other:

(Molarity of HBr) x (volume of HBr) = 0.5 x (Molarity of Mg(OH)2) x (volume of Mg(OH)2)

Solving for the unknown variable, we get:

(Molarity of HBr) = (0.5 x (Molarity of Mg(OH)2) x (volume of Mg(OH)2)) / (volume of HBr)

(Molarity of HBr) = (0