Bài 1. Một chiếc xe trong 2 giờ đầu xe đi được quãng đường 40 km, trong 3 giờ tiếp theo xe đi được quãng đường 90 km. Tính tốc độ của xe trên cả quãng đường.

Given data

*The given mass of the person is m = 40 kg

*The value of the acceleration due to the gravity is g = 9.8 m/s^2

(A)

The reading on the scale is calculated when the elevator is stationary is given as

(B)

The formula for the reading on the scale when the elevator is moving up at constant speed is given as

(C)

The formula for the reading on the scale when the elevator accelerates upwards at 5.00 m/s^2 is given as

Substitute the known values in the above expression as

(D)

The formula for the reading on the scale when the elevator accelerates downwards at 5.00 m/s^2 is given as

Substitute the known values in the above expression as

Answer:

condensation, the process of changing from a gas to a liquid

Answer:

I need a picture dude or something more specific than the other kids were white gold and blue

Answer:

\(\dfrac{-1}{2}\)

Explanation:

We need to divide the second number by the first number and the numbers are 3/4,-3/8​.

First number = 3/4

Second number = -3/8

Dividing the second number by the first number.

So,

\(\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}\)

We know that,

\(\dfrac{\dfrac{a}{b}}{\dfrac{c}{d}}=\dfrac{a}{b}\times \dfrac{d}{c}\)

So,

\(\dfrac{\dfrac{-3}{8}}{\dfrac{3}{4}}=\dfrac{-3}{8}\times \dfrac{4}{3}\\\\=\dfrac{-1}{2}\)

So, the answer is (-1/2)

Answer:

To help push yourself to reach the goal, It can also help you pace yourself time wise

Explanation:

As the earth rotates on its own axis every 24 hours the hemisphere facing the sun will experience summer while the other hemisphere will experience winter in addition the earth rotates around the sun every 365.25 days with an axis tilt of 23.5 degrees.This allows for the hemisphere tilting towards from the sun to experience daylight while the area of the earth tilting away from the sun to experience night while the area of the earth tilting towards the sun to experience summer

The current in the 3.0 Ω resistor is mathematically given as

I_X=1.8A

This is further explained below.

The proportion of individual resistance to the overall resistance is the same as the current flowing through a branch to the current flowing through the whole system.

When the total current in a parallel circuit is already known, a shortcut approach for finding the branch currents in the circuit may be found via the use of a formula called the current divider formula.

In series circuits, the voltage drops across each resistor, but the current stays the same.

This is analogous to what happens in parallel circuits when the current splits between two branches.

The following diagram illustrates how the entire voltage is distributed across each resistor while maintaining the same amount of current throughout. Ohm's law states that V = I*R.

current dividers ruleis used when current is divided in parallel, such as it is in this case so we employ the current dividers rule as follows

Generally,  the equation for current dividers rule is mathematically given as

\(I_X=\frac{R_T}{R_X+R_T} I_T\)

where,

I_X = current

R_X = resistor

R_T = total resistance

I_T = sum of the current flowing into a network where R _X is connected in parallel with R_T

Therefore

\(I_X=\frac{9}{3+9} 2.4\)

I_X=1.8A

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The question addresses the stability of the atmosphere and the factors that determine convective stability or instability. It also explains the difference between the adiabatic lapse rate of dry air and wet saturated air.

a) The stability of the atmosphere is determined by the temperature profile and relative densities of the air cell and atmosphere. If the temperature of the surrounding atmosphere decreases with altitude at a rate greater than the adiabatic lapse rate of the air cell, the atmosphere is considered convectively stable.

In this case, the air cell will return to its original position. Conversely, if the temperature of the surrounding atmosphere decreases slower than the adiabatic lapse rate of the air cell, the atmosphere is convectively unstable. The air cell will continue moving in the same direction.

b) The adiabatic lapse rate refers to the rate at which temperature decreases with altitude for a parcel of air lifted or descending adiabatically (without exchanging heat with its surroundings). The adiabatic lapse rate of dry air is higher (around \(9.8^0C\) per kilometer) compared to the adiabatic lapse rate of wet saturated air (around 5°C per kilometer).

This difference arises because when water vapor condenses during the ascent of saturated air, latent heat is released, reducing the rate of temperature decrease. A diagram can illustrate the difference between the two lapse rates, showcasing their respective slopes.

c) When wet unsaturated air rises from the ocean surface, its temperature decreases at a rate equal to the dry adiabatic lapse rate. However, if the ambient lapse rate (temperature decrease with altitude) is higher than the adiabatic lapse rate for dry air, a temperature inversion layer forms at higher altitudes.

In this inversion layer, the temperature increases with altitude instead of decreasing. A schematic diagram can depict the temperature changes of the wet air in comparison to the ambient temperature, showing the inversion layer.

Cumulus clouds form at the altitude where the rising moist air reaches the level of the temperature inversion layer. These clouds are formed due to the condensation of water vapor as the air parcel cools to its dew point temperature.

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The total kinetic energy before the collision is equal to the total kinetic energy after the collision.

When a car and a truck collide and stick together to form a single, combined vehicle, it is referred to as a car-plus-truck system. When two bodies are moving in the same direction and collide, the final velocity of the resulting body is equal to the sum of the two initial velocities.The car-plus-truck system's velocity would be lower than it would be if the truck wasn't moving. This is due to the fact that the car and the truck now have a combined mass, which means that they have more kinetic energy to overcome. Therefore, when the truck has an initial velocity moving in the same direction as the car, the final velocity of the car-plus-truck system decreases.

Consider two objects that are in motion. These objects can be moving in the same direction or opposite directions. When they collide with one another, the final velocity of the system is determined by the combined mass of the objects and their initial velocities. If the two objects are moving in the same direction, their final velocity will be the sum of their initial velocities. In the case of a car and truck system, the final velocity of the combined mass would decrease if the truck has some initial velocity moving in the same direction as the car.When two objects collide, their kinetic energy is transferred between them. The total kinetic energy before the collision is equal to the total kinetic energy after the collision. In the case of a car-plus-truck system, if the truck has some initial velocity moving in the same direction as the car, the combined mass of the car and truck system will be higher. This results in a higher kinetic energy before the collision. Since the total kinetic energy after the collision is equal to the total kinetic energy before the collision, the final velocity of the car-plus-truck system decreases when the truck has some initial velocity moving in the same direction as the car.

In conclusion, when the truck has an initial velocity moving in the same direction as the car, the final velocity of the car-plus-truck system decreases. The final velocity is dependent on the combined mass of the system and the initial velocities of the objects. When two objects collide, their kinetic energy is transferred between them, resulting in a combined mass and kinetic energy that is higher than the initial values. The total kinetic energy before the collision is equal to the total kinetic energy after the collision.

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(A) perpendicular distance = (1/2) x 96 cm = 48 cm = 0.48 mSo, torque = force x perpendicular distance from the pivot= 42 N x 0.48 m= 20.16 Nm (B)The magnitude of the torque when the force is exerted perpendicular to the door is 20.16 Nm, and the magnitude of the torque when the force is exerted at an angle of 60° to the face of the door is 14.380 Nm.

We know that a person exerts a horizontal force of 42 N on the end of a door 96 cm wide. We need to find the magnitude of the torque if the force is exerted perpendicular to the door and at an angle to the face of the door.

(a) Torque when the force is exerted perpendicular to the door, the torque is given by the formula:

Torque = force x perpendicular distance from the pivot

We can see that the force is perpendicular to the door. So, the perpendicular distance from the pivot is equal to the distance of the line of action of the force from the pivot, which is half the width of the door.

Therefore, perpendicular distance = (1/2) x 96 cm = 48 cm = 0.48 mSo, torque = force x perpendicular distance from the pivot= 42 N x 0.48 m= 20.16 Nm

(b) Torque when the force is exerted at an angle to the face of the door

When the force is exerted at an angle to the face of the door, the torque is given by the formula: Torque = force x perpendicular distance from the pivot x sin θ

Here, θ is the angle between the force and the perpendicular to the door. We need to find the perpendicular distance from the pivot, which is equal to the distance of the line of action of the force from the pivot along the perpendicular bisector of the door. Let us assume that the angle between the force and the door is θ = 60°. In this case, the perpendicular distance from the pivot can be calculated as follows:

Perpendicular distance = (1/2) x 96 cm x sin 60°

= (1/2) x 96 cm x (sqrt(3)/2)

= 48 cm x (sqrt(3)/2)

= 41.569 cm

= 0.4169 m

So, torque = force x perpendicular distance from the pivot x sin θ= 42 N x 0.4169 m x sin 60°

= 14.380 Nm

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Answer: The time, t, is approximately 1.57 seconds

Explanation:

The data we have from the question;

Displacement = 2.0 meters

Acceleration due to gravity on the moon = 1.62

Initial velocity = 0 m/s

We can use the second equation of motion for this one;

S = ut + 1/2at²

Where:

- S is the displacement.

- u is the initial velocity.

- a is the acceleration.

- t is the time measured in seconds.

We are now ready to substitute;

2 = 0(t) + 1/2(1.62)t²

==> 2 = 0 + 0.81t²

==> 2/0.81 = 0.81t²/0.81

==> \(\sqrt{2.47}\) = \(\sqrt{t ^{2}\)

==> The time, t, is approximately 1.57 seconds

Hope this helped! Have a good day :D

a) 67.96 J  work is done by the Sammy against the current.

b) 3.46 m  is the gain in PE by Sammy.

c) 85.06 J is the total work that must be done by Sammy.

d) If Sammy takes 40 S to swim the distance, 85 power does sammy have to exert to do so.

a) The work done by Sammy against the current is given by the formula:

Work = force × distance × cos(theta)

where force is the net force acting on the salmon, distance is the distance travelled by the salmon, theta is the angle between the force and the direction of motion.

Here, the net force acting on Sammy is:

force = 5.00 N - 1.50 N = 3.50 N

The distance travelled by Sammy is 20 m. The angle between the force and the direction of motion is 10 degrees.

Therefore, the work done by Sammy against the current is:

Work = (3.50 N) × (20 m) × cos(10 degrees)

= 67.96 J (Joules)

b) The gain in potential energy by Sammy is given by the formula:

PE = mgh

where m is the mass of the salmon, g is the acceleration due to gravity, and h is the height gained by Sammy.

Here, the height gained by Sammy is the vertical distance travelled while swimming upstream against the current. This distance is given by:

h = distance × sin(theta)

= 20 m × sin(10 degrees)

= 3.46 m

Therefore, the gain in potential energy by Sammy is:

PE = (5.00 N ÷ 9.81 m/s^2) × (3.46 m) × 9.81 m/s^2

= 17.10 J (Joules)

c) The total work that must be done by Sammy is the sum of the work done against the current and the gain in potential energy:

Total work = Work against current + PE gain

= 67.96 J + 17.10 J

= 85.06 J (Joules)

d) The power that Sammy must exert to swim upstream against the current is given by the formula:

Power = work ÷ time

where work is the total work done by Sammy, and time is the time taken to swim the distance.

Here, the total work done by Sammy is 85.

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Acrobatic flips are a series of bodily motions in which the performer leaps into the air before rotating once or more while in the air.

A person who performs an acrobatic flip will first leap into the air before rotating once or more while in the air. Acrobatic flips are performed in a variety of sports and activities, including tricking, goal celebrations, cheering, free running, gymnastics, and acro dance.

The four steps to do a backflip are given below:-

1. Before you jump, stretch your muscles to avoid harm.

2. Find a cushioned area, like a foam pit or a gymnastics mat.

3. For the most protection, use a spotter.

4. Make a high squat by bending at the knees. Ring your arms forward and above your head as you leap upwards, pausing when they are just behind your back.

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Answer:

wave

Explanation:

A wave is defined as the disturbance that causes the movement of energy. The energy is transferred as the waves move from one place to another. A medium is required for the transfer of energy. Usually a wave travels through air or water. The process is carried on at a specific speed that is termed as the speed of propagation.

Even with infinitely powerful telescopes, we can look back in time only until the Cosmic Microwave Background (CMB), around 380,000 years after the Big Bang.

The Cosmic Microwave Background is the earliest observable stage of the universe's history. Before the CMB, the universe was in a hot, dense state known as the "opaque plasma" where photons were constantly scattered by charged particles, making it impossible to see through.

Approximately 380,000 years after the Big Bang, the universe cooled down enough for atoms to form, allowing photons to travel freely. This event is called "recombination," and the released photons created the CMB. Even with infinitely powerful telescopes, we cannot observe anything prior to the CMB because light did not travel freely in the opaque plasma.

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A 150-lb man carries a 25-lb can of paint up a helical staircase that encircles a silo with radius 30 ft. If the silo is 120 ft high and the man makes exactly three complete revolutions, the work done by the man against gravity in climbing to the top is 48,832 ft-lb.

The work done by a person in lifting an object against gravity is given by the formula W = F × d where W is the work done, F is the force applied, and d is the distance moved in the direction of the force. Since the man is moving up the helical staircase, the distance moved by him is equal to the height of the silo, which is 120 ft. The force applied by the man is equal to the weight of the man and the can of paint. This is given by F = 150 + 25 = 175 lb. The man makes exactly three complete revolutions, which means that the vertical distance covered by him is three times the height of the silo. This is equal to 3 × 120 ft = 360 ft. However, the vertical component of this distance is equal to the height of the silo, which is 120 ft. This means that the man moves horizontally by a distance of 360 − 120 = 240 ft. This distance is covered by the man in moving around the silo. The circumference of the silo is given by 2πr, where r is the radius of the silo. Therefore, the circumference of the silo is given by 2π × 30 ft = 60π ft. The man makes three complete revolutions, which means that he moves a horizontal distance of 3 × 60π ft = 180π ft. Therefore, the total distance moved by the man is given by d = √(120² + 180π²) ft ≈ 372.77 ft. Now, substituting the values of F and d in the formula for work, we getW = F × d= 175 lb × 372.77 ft= 65,216.75 ft-lbHowever, the man is carrying the can of paint in one hand. This means that he is doing work against gravity not only for himself but also for the can of paint. Therefore, the work done against gravity by the man for himself is 65,216.75 ft-lb, and the work done against gravity for the can of paint isW = 25 lb × 120 ft= 3,000 ft-lbTherefore, the total work done against gravity is given by 65,216.75 ft-lb + 3,000 ft-lb = 68,216.75 ft-lb ≈ 48,832 ft-lb.

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Answer:

mass= 3.5 kg

distance covered= 0.4m

inital speed = 1.5 m/sec

final speed = 0 m/sec

net force

formula for force :

\( \fbox{f = m.a}\)

In order to find the force we need to find the acceleration.

According to third equation of Kinematics-

\( \bold{ {v}^{2} = {u}^{2} + 2as}\)

where,

v= final velocity

u=inital Velocity

a=Acceleration

s=Distance covered

put the value in the above equation

0= (1.5)²+ 2a x 0.4

-2.25= 0.8a

a = -2.25/0.8

a= - 2.8125 m/sec²

now put the value 0f accleration in formula of force

F = 3.5 x - 2.8125

F= -9.84375 N

Given,

The temperature in Fahrenheit, F=57.39 °F

The temperature can be converted from degree Fahrenheit to degree celcius using the formula,

On substituting the known values,

Thus 57.39 °F in degree celcius is 14.11 °C

Hello User!

Answer:

Answer: 1.1 m/s east

It takes a person 42 seconds to swim in a straight line from the west end of a pool to the east end of the pool, a distance of 45 meters, the swimmer's velocity is approximately 1.1 m/s. The correct option is C.

The velocity is the rate of motion in a certain direction and is calculated by dividing 45 metres by 42 seconds. The swimmer in this instance is swimming towards the east side of the pool.

The swimmer's velocity can be calculated using the formula:

Velocity (v) = Distance (d) / Time (t)

Given that the distance is 45 meters and the time is 42 seconds:

Velocity (v) = 45 m / 42 s ≈ 1.0714 m/s

The swimmer's velocity is approximately 1.1 m/s.

Thus, the correct answer is C. 1.1 m/s east.

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Answer:

+131Joules

Explanation:

Energy can be expressed using below expresion.

ΔE = (q + w).........eqn(1)

q will be + be if heat is gained hence, q= 240 J

work "w" will be - ve if work is done by the system, hence w= -109 J

Then substitute into eqn(1)

Change in Internal energy=

= (240 -109 )

= +131J

The change in the internal energy of the system which does 109 J of work while 240 J of heat are added is +131 J

The change in the internal energy of the system can be obtained as illustrated below:

ΔU = Q + W

ΔU = 240 + (–109)

ΔU = 240 – 109)

ΔU = +131 J

Thus, the change in the internal energy of the system is +131 J

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The work done by the person is -1905.15 J.

Work is defined in a way that takes into account both the forces applied to the body and the total displacement of the body. A constant force F comes before this block. This force's objective is to move the body a specified amount (d) of distance in a straight line in the force's direction.

F = \(\mu_{k}\)N

N = mgcos(25°)

So, the work done by force of friction is given as

W= f· BC cos (180°)

= - \(\mu_{k}\) mg cos(25°) ×BC

= -0.65 ×(100+10)9.8 ×cos(25°) ×3

= -1905.15 J

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Answer:

120 m/s if m/s means miles per second than

Explanation:

15 × 8

Answer:

d = 120 m

Explanation:

Data:

Use the formula:

Replace with the data, and solve:

The distance is 120 meters.

Greetings.

I think the number 2, not sure

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

The potential at a point due to a charge is given by V = kQ/r, where k is Coulomb's constant (~\(9x10^9 Nm^2/C^2\)), Q is the charge, and r is the distance from the charge.

The total potential at the center of the square is the sum of the potentials due to each charge.

The distance of each charge to the center is half the diagonal of the square, which is \(\sqrt2 * side/2 = \sqrt2 * \sqrt4.5/2 = 1.5m.\)

The total potential is then V_total

= \(k * [(510^8/1.5) + (210^8/1.5) - (510^8/1.5) - (710^8/1.5)] = -2 * k * 10^8 / 1.5 \\= -1.2 x 10^9 V.\)

Thus, the total potential is then V_total = \(-1.2 * 10^9V\)

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The moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

The given parameters;

The moment of inertial of the wheel is calculated as follows;

\(I = I_{hoop} + 3I_{spoke}\\\\I = MR^2\ + \ 3(\frac{1}{3} mL^2)\\\\I = (4.3 \times 0.67^2) \ + \ (0.15 \times 0.67^2)\\\\I = 2.0 \ kgm^2\)

Thus, the moment of inertia of the wheel about an axis through its center and perpendicular to the plane of the wheel is 2.0 kgm².

"Your question is not complete, it seems to be missing the following information";

find the moment of inertial of the wheel about an axis through its center and perpendicular to the plane of the wheel.

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The engine used approximately 49.1 kilowatts (kW) of power to lift the bucket.

To calculate the power used by the engine to lift the bucket, we can use the formula:

Power = Energy / Time

Given that the potential energy of the bucket changes from 2.0 kJ to 110 kJ in 2.2 seconds, we can calculate the power as follows:

Power = (110 kJ - 2.0 kJ) / 2.2 s

Simplifying the calculation:

Power = 108 kJ / 2.2 s

Converting kJ to J:

Power = 108,000 J / 2.2 s

Calculating the power:

Power = 49,090.9 Watts or approximately 49.1 kW.

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Answer:

Explanation:

The gravitational potential energy of a body can be found by using the formula

GPE = mgh

where

m is the mass

h is the height

g is the acceleration due to gravity which is 9.8 m/s²

From the question we have

GPE = 10 × 9.8 × 5 = 590

We have the final answer as

Hope this helps you

Answer: Velocity = v = 35 m/s

Explanation:

Kinetic energy of an object is defined as the energy possess by an object due to its motion. Kinetic energy K.E of an object is equal to the half of the mass of that object multiplied by square of the object's velocity.

Mathematically,

v = 35 m/s