To balance the equation in basic solution, we add 4OH⁻ ions on the left side and 3H₂O molecules on the right side. The coefficient of hydroxide ion is 4.
To balance the given equation in basic solution:
AlH⁴⁻ (aq) + H₂CO (s) → Al³⁺ (aq) + CH₃OH (aq)
First, let's balance the atoms other than hydrogen and oxygen. We have one Al on the left and one Al on the right, so Al is balanced. Similarly, we have one C on the left and one C on the right, so C is balanced as well.
Next, let's balance the hydrogen atoms. We have four H atoms in AlH⁴⁻ on the left and only one H atom in CH₃OH on the right. To balance the hydrogen, we need to add three H₂O molecules on the right side:
AlH⁴⁻ (aq) + H₂CO (s) → Al³⁺ (aq) + CH₃OH (aq) + 3H₂O (l)
Now, let's balance the oxygen atoms. We have four O atoms in H₂CO on the left and four O atoms in the three H₂O molecules on the right, totaling eight O atoms on the right. To balance the oxygen, we need to add four OH⁻ ions on the left side:
AlH⁴⁻ (aq) + 4OH⁻ (aq) + H₂CO (s) → Al³⁺ (aq) + CH₃OH (aq) + 3H₂O (l)
Now the equation is balanced. The coefficient of hydroxide ion (OH⁻) is 4.
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how many milliliters of a stock solution of 5.00 mm hno3hno3 would you have to use to prepare 0.200 ll of 0.550 mm hno3hno3 ?
You would have to use 11 milliliters of the stock solution of 5.00 mm HNO3 to prepare 0.200 L of 0.550 mm HNO3.
To calculate the volume of the stock solution required, we can use the formula:
C1V1 = C2V2
Where C1 is the concentration of the stock solution, V1 is the volume of the stock solution needed, C2 is the desired concentration of the final solution, and V2 is the final volume of the solution.
In this case, the concentration of the stock solution (C1) is 5.00 mm HNO3 and the desired concentration of the final solution (C2) is 0.550 mm HNO3. The final volume of the solution (V2) is 0.200 L.
Plugging these values into the formula, we have:
(5.00 mm HNO3)(V1) = (0.550 mm HNO3)(0.200 L)
Solving for V1, we get:
V1 = (0.550 mm HNO3)(0.200 L) / (5.00 mm HNO3)
V1 = 0.011 L
To convert this volume to milliliters, we multiply by 1000:
V1 = 0.011 L * 1000 mL/L
V1 = 11 mL
Therefore, you would have to use 11 milliliters of the stock solution of 5.00 mm HNO3 to prepare 0.200 L of 0.550 mm HNO3.
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A basketball weighs approximately 1.35 kg. What
is this mass in grams (g)?
Answer:
1,350 grams
Explanation:
1 kg is equivalent to 1,000 grams. To convert kg to g you can multiply by 1,000
\(1.35*1000=1350\)
or set it up as fractions and cross multiply, which will cause the unit of kg to cancel out
\(1.35kg*\frac{1000g}{1kg}\)
Lab: Limiting Reactant and Percent Yield
Student Guide
Pre-Lab Information
Purpose Explore the yield of a chemical reaction by identifying the limiting reactant, comparing the
theoretical and actual yields, and explaining the sources of error.
Time Approximately 45 minutes
Question While observing a chemical reaction, how can you tell which reactant is limiting?
Reaction The reaction of copper(II) chloride and aluminum is shown in this balanced equation:
3CuCl2 + 2Al 2AlCl3 + 3Cu
Hypothesis If a substance is the limiting reactant, then it will be fully consumed by the time the
reaction completes because it is the reactant that reacts completely and the reaction
cannot proceed further.
Summary You will react copper(II) chloride with different quantities of aluminum in two trials. You
will also calculate percent yield for Trial 2.
Answer:
pre lab information would be the thing you to ressearch the lab to get the information
Limiting Reactant and Percent Yield Lab Report attached
Calculate+how+many+grams+of+zinc+chloride+are+to+be+used+to+prepare+5+l+of+a+mouthwash+containing+0.1%+of+zncls
To prepare 5 L of a mouthwash containing 0.1% of ZnCl2,you would need approximately 0.014 grams (or 14.5 mg) of zinc chloride.
The percentage concentration of ZnCl2 in the mouthwash is given as 0.1%. This means that for every 100 parts of the mouthwash, 0.1 parts are ZnCl2.
To calculate the amount of ZnCl2 needed to prepare 5 L of mouthwash, we can use the following formula:
Amount of ZnCl2 = (Percentage concentration/100) × Volume of mouthwash
Plugging in the values, we have:
Amount of ZnCl2 = (0.1/100) × 5 L = 0.005 L
Since the density of ZnCl2 is approximately 2.907 g/mL, we can convert the volume to grams:
Amount of ZnCl2 = 0.005 L × 2.907 g/mL = 0.014535 g
Rounding off to the appropriate number of significant figures, the amount of ZnCl2 needed is approximately 0.0145 g, which can be rounded to 0.014 g.
To prepare 5 L of a mouthwash containing 0.1% of ZnCl2, you would need approximately 0.014 grams (or 14.5 mg) of zinc chloride.
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QUESTION 1How many molecules of C6H12O6 are in 200. grams of C6H1206?
To find the number of molecules we must apply for Avogadro's number. This number tells us that in one mole of any substance there are 6.022x10^23 molecules. So the first thing we will do is find the moles contained in 200 grams of C6H12O6 (Glucose).
The molar mass of glucose is 180.06g/mol. So, the moles of glucose will be:
\(molC_6H_{12}O_6=givengC_6H_{12}O_6\times\frac{1molC_6H_{12}O_6}{MolarMass,gC_6H_{12}O_6}\)\(molC_6H_{12}O_6=200.gC_6H_{12}O_6\times\frac{1molC_6H_{12}O_6}{180.06gC_6H_{12}O_6}=1.11molC_6H_{12}O_6\)Now, we apply for Avogadro's number. So, the molecules of glucose will be:
\(\begin{gathered} moleculesC_6H_{12}O_6=givenmolC_6H_{12}O_6\times\frac{6.022\times10^{23}molecules}{1molC_6H_{12}O_6} \\ moleculesC_6H_{12}O_6=1.11molC_6H_{12}O_6\times\frac{6.022\times10^{23}molecules}{1molC_6H_{12}O_6} \\ moleculesC_6H_{12}O_6=6.68\times10^{23}molecules \end{gathered}\)Answer: In 200 grams of C6H12O6 there are 6.68x10^23 molecules
Cellular respiration occurs? (2 points)
only in plant cells
only in animal cells
only in chlorophyll
in plant and animal cells
Answer:
in plant and animal cells
Explanation:
It happens in both and occurs in the mitochondria.
"The pH of an acid has nothing to do with the strength of the acid."
Explain why this statement is true. Include the following terms in your explanation
• dissociation
molarity
• strong
• weak
• neutral
• acidic
basic
Answer:The relationship between acid strength and the pH of a solution. ... Typical concentrations of these ions in solution can be very small, and they also ... Acidic solutions have pH values less than 7, and basic solutions have pH values ... p, O, H, end text, it is a little more common to use pH \text{pH} pHstart text, p, H, end text.
Explanation:Therefore a strong acid will contribute more H+ ions than a weak acid. Therefore, the pH of a strong acid solution will be higher than a weak acid solution.
Which of the following does not contribute to the tertiary structure of a protein?
A. Hydrogen bonds between side chains of amino groups
B. Hydrogen bonds between amine and carbonyl groups in the peptide backbone
C. Disulfide bonds between cysteine residues
D. Hydrophobic interactions between side chains of amino acids
E. Salt bridges between ionized groups in side chains of amino acids
The correct statement is B,Hydrogen bonds between amine and carbonyl groups in the peptide backbone.
A. Hydrogen bonds between side chains of amino groups
Hydrogen bonds between side chains of amino groups can contribute to the tertiary structure of a protein. These hydrogen bonds can form between the hydrogen atom of one amino group and the electronegative atom (such as oxygen or nitrogen) of another amino group in the side chain.
Hydrogen bonds between amine and carbonyl groups in the peptide backbone.
Hydrogen bonds between amine (NH) and carbonyl (C=O) groups in the peptide backbone are responsible for stabilizing the secondary structure of a protein, such as alpha-helices and beta-sheets. These hydrogen bonds form between the electronegative oxygen atom of the carbonyl group and the hydrogen atom of the amine group in the peptide backbone.
The tertiary structure of a protein is primarily determined by interactions such as disulfide bonds (C), hydrophobic interactions (D), and salt bridges (E). Disulfide bonds form between cysteine residues and contribute to the stabilization of protein structure.
Hydrophobic interactions occur between nonpolar side chains, causing them to cluster together in the protein's interior. Salt bridges involve the attraction between ionized groups of amino acids with opposite charges.
In summary, the correct statement is B. Hydrogen bonds between amine and carbonyl groups in the peptide backbone do not contribute to the tertiary structure of a protein but rather play a crucial role in stabilizing the secondary structure.
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Which set of elements has physical and chemical properties similar to phosphorus?
Aluminum, silicon, sulfur, & chlorine, , ,
Carbon, selenium, iodine, & radon
Oxygen, germanium, indium & mercury
Nitrogen, arsenic, antimony & bismuth
Nitrogen, arsenic, antimony & bismuth
Explanation:
Phosphorus belongs to the 15th group, that is nitrogen family.
Natures are decided by the number of valence electrons.
In a family, all elements have same outer electronic configuration or you say number of electrons.
General electronic con.: ns²np³
In the classical free electron model, the name(s) given to the neglect of electron ion interaction is/are
i. The independent electron approximation
ii. The free electron approximation
iii. The Drude electron - ion approximation
(i) Only
(ii) Only
(i) and (ii)
(iii) Only
in the classical free electron model, the neglect of electron-ion interaction is referred to as the free electron approximation. The correct option is (ii) Only.
This approximation assumes that the interaction between electrons and ions can be ignored, treating the electrons as free particles moving in a periodic potential without any significant influence from the ions. The independent electron approximation, on the other hand, assumes that the behavior of each electron can be considered independently of the others. The Drude electron-ion approximation incorporates electron-ion interactions and is not part of the classical free electron model. Therefore, the correct option is (ii) Only.
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ethane is burned with 50% excess air. the percentage conversion of the ethane is 90%; of the ethane burned, 25% reacts to form co and the balance reacts to form co2. calculate the molar composition of the stack gas on a dry basis and the mole ratio of water to dry stack gas.
The molar composition of the stack gas on a dry basis and the mole ratio of water to dry stack gas is 0.1143.
the equation is,
C2H6 + 7/202 → 2CO2 + 3H2O
1mol 3.5mol 2mol 3mol
for 100 mol GHG, & required = 100×3.5 mol
O2 required = 350 mol
O₂ fed = 1.5×350 mol
O₂ fed =525 mol
N2 fed = 0.79/0.21 X 525 mol
N2 fed =1975mol
Mole ratio of water to dry stack gas = Moles of water/Moles of dry stack
gas Without water
=270 mol / 2362.5 mol
= 0.1143
Mole ratio water to of dry stack gas = 0.1143
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Electricity is created when ____ move. electrons protons neutrons
Answer:
electrons
Explanation:
electricity is the flow of electrons through a conductor
Answer:
protons
Explanation:
and neutrons never move from object to object. The energy that comes from these charged particles is called electrical energy.
how many moles of sodium chloride will be produced from the neutralization of 2.4 moles of hydrochloric acid?
From the neutralization of 2.4 moles of hydrochloric acid sodium chloride will be produced 2.4 moles.
HCl + NaOH ⇄NaCl + H2O
1 moles of HCl and 1 moles of NaOH needed to produce 1 mole of NaCl .
2.4 moles of HCl and 2.4 moles of NaOH needed to produce 2.4 mole of NaCl .
When determining how much of a substance there is, the concept of a mole is helpful. When dealing with particles at the atomic (or molecular) level, it is well understood that even a single gram of a pure element includes a vast number of atoms. The mole notion is widely utilized in this context. The most common unit of measurement is the "mole," which is a count of many particles. The number 6.02214076*1023, commonly known as the Avogadro constant, is frequently denoted by the letter "NA". Among the elementary entities that can be represented in moles are atoms, molecules, monoatomic and polyatomic ions, as well as other particles (such as electrons)
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Based on the oxidation states of the atoms in this reaction, answer the questions. 4Fe(0) + 3O2(0) → 2Fe2(3+)O3(2-) How many electrons does the iron half-reaction lose? How many electrons does the oxygen half-reaction gain? What is the total number of electrons that are moved in this oxidation-reduction reaction?
Answer:
Twelve electrons
Explanation:
If we look at the product side, we will notice that iron lost twelve electrons and oxygen gained twelve electrons.
Hence, we have 4Fe^3+ and 2O3^2- showing twelve electrons lost/gained.
Answer:
How many electrons does the iron half-reaction lose?
12
How many electrons does the oxygen half-reaction gain?
12
What is the total number of electrons that are moved in this oxidation-reduction reaction? 12
Explanation:
Substances that can carry electric current under some conditions but not under others are called semiconductors.
You are on an alien planet where the names for substances and the units of measures are very unfamiliar
Nonetheless, you obtain 20 quibs of a substance called skvarnick.
You can trade this skvarnick for gold coins, but the vendors all measure skvarnick in units of sleps; not quibs.
5 quibs is equal to 3 sleps
If you have 20 quibs of skvarnick, how many sleps do you have?
For full points, you must show your work as well as showing the answer. Follow the steps of the conversion procedure as explained in the course.
Select the correct answer. what makes metals, in particular, good conductors of electricity? a. the ability of electrons to flow throughout the metal b. the absence of charged particles c. the high temperatures required to break metallic bonds d. the presence of positive and negative ions
Answer:
I believe the answer is A. Not completely sure though. : )
is a particle with a positive charge.:)
Ga X ha the molecular formula C5Hx. A ma of 1. 44g of X occupie a volume of 0. 32 dm3
at 2. 0 atm and
400 K. Find the value of x
[H = 1; C = 12; R= 0. 08 atm. Dm3. K-1. Mol-1]
The molecular formula for C5Hx in this question is C5H12
In this case, molecular formula can be determined by calculated the molecular weight relative for each molecule. The molecular weight relative for each molecule calculated by using ideal gas equation:
PV=mRT/Mr
with,
P = Pressure of the system
V = Volume occupied by gas
m = mass of C5Hx
R = ideal gas constant
T = Temperature of the system
Mr = molecular weight of C5Hx
2 x 0.32 = 1.44 x 0.08 x 400 /Mr
Mr = 1.44 x 0.08 x 400/ (2 x 0.32)
Mr = 72
Mr of C5Hx = 6 x 12 + 1 x X
72 = 60 + X
X = 12
C5Hx = C5H12
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2ca(s)+o2(g) → 2cao(s) δh∘rxn= -1269.8 kj; δs∘rxn= -364.6 j/k
Gibbs free energy change for the reaction at 29°C. is equal to -1378.93 KJ.
What is Gibbs's free energy?Gibbs free energy can be described as the enthalpy of the system minus the product of the temperature and entropy.
If the chemical reaction can be carried out under constant temperature ΔT = 0:
ΔG = ΔH – TΔS
The above equation is known as the Gibbs-Helmholtz equation.
ΔG > 0 non-spontaneous and endergonic and ΔG < 0 spontaneous and exergonic, ΔG = 0 is representing equilibrium.
Given the ΔS = -364 J/K, ΔH = -1269.8 KJ, T = 29°C = 29 + 273 = 302 K
ΔG = - 1269 - 302 × 364
ΔG = -1269 KJ - 109.93 KJ
ΔG = - 1378.93 KJ
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Your question is incomplete, most probably the complete question was,
2Ca(s)+O₂(g) → 2CaO(s)
ΔH∘rxn= -1269.8 kJ; ΔS∘rxn= -364.6 J/K
For this problem, assume that all reactants and products are in their standard states.
Calculate the free energy change for the reaction at 29°C.
What kind of intermolecular forces act between a chloromethane molecule and a chloroacetylene molecule
Dipole to Dipole force
Explanation:
A dipole to dipole forces exists between these molecules
Where do most fungi thrive?
Question :
Where do most fungi thrive ?
Answer :
Fungi are found all around the world and grow in a wide range of habitats, including deserts. Most grow on land (terrestrial) environments, but several species live only in aquatic habitats. Most fungi live in either soil or dead matter, and many are symbionts of plants, animals, or other fungi.
Source :
CK-12 , Edgenuity2020
Molarity and Dilution Problems Ws
Describe how you would prepare 5.00 liters of a 6.00M solution of potassium hydroxide. HELP ASAP!!!!!!! EXPLAIN PLS THANKS!!!!!!!!!
The amount of potassium hydroxide required 1683 g.
To prepare 5.00 liters of a 6.00M solution of potassium hydroxide, you will need to calculate the amount of potassium hydroxide required. To do this, use the formula:
\(mass (g) = volume (L) *\ molar mass * molarity (M)\)
Therefore, the mass of potassium hydroxide needed is:
mass (g) = 6.00 M * 5.00 L * 56.1 g/mol
mass (g) = 1683 g
Once you have calculated the amount of potassium hydroxide needed, you must weigh out the correct amount using a laboratory balance.
Next, you will need to transfer the potassium hydroxide to a glass container that can hold the 5.00 liters of solution.
Finally, you will add deionized water to the container until the total volume of the solution is 5.00 liters. Stir the solution until the potassium hydroxide is completely dissolved.
Your 6.00M solution of potassium hydroxide is now ready to use.
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One of the components in crude oil is octane, C8H₁8. Octane can be made into ethene and a product P, C,H,, as shown below. (i) C8H18 C₂H₂ + 2C₂H4 Р Name this type of reaction? 1
Answer: The type of reaction shown is a cracking reaction.
Explanation: Cracking is the process of breaking down larger hydrocarbons into smaller, more useful hydrocarbons. In this case, octane (C8H18) is being cracked into ethene (C2H4) and a product P (CxHy).
How many moles are there in 8.25 x 10^26 molecules of methane (CH4)?
Answer:
i dont know
Explanation:
because i dont know 45
10. If 3.5 kJ of energy are added to a 28.2 g sample of iron at 20°C, what
is the final temperature of the iron in kelvins? The specific heat of iron
is 0.449 J(g•K).
Answer:
569K
Explanation:
Q = 3.5kJ = 3500J
mass = 28.2g
∅1 = 20°C = 20 + 273 = 293K
∅2 = x
c = 0.449
Q = mc∆∅
3500 = 28.2×0.449×∆∅
3500 = 12.6618×∆∅
∆∅ = 3500/12.6618
∆∅ = 276.4220
∅2 - ∅1 = 276.4220
∅2 = 276.4220 + ∅1
∅2 = 276.4220 + 293
∅2 = 569.4220K
∅2 = 569K
When the temperature is increased, there is the increase in thermal energy of the system. The final temperature of the iron in kelvins is 570 K.
What is energy?The energy is the ability to do work.
Given is the energy Q = 3.5 kJ = 3500 J, mass of sample m = 28.2 g, specific heat of iron Cp = 0.449 J(g•K).
The initial temperature in kelvins is T1 = 20°C = 20 + 273 = 293K
The heat is related to the temperature difference as
Q = m c ∆T
Substitute the values into the expression,
3500 = 28.2 × 0.449 × ∆T
3500 = 12.6618 × (T2 -T1)
T2 - T1 = 276.4220
T2 = 276.4220 K +293 K
T2 = 569.4220K
The temperature of the iron is approximately 570 K.
Thus, the final temperature of the iron in kelvins is 570K.
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candy0993 please answer me
Answer:
hi this is candy0993
Explanation:
do you need something?
9. If one bulb of Christmas lights, connected in series is burned out, what will
happen to the other light bulbs?
A. All other bulbs will no longer work.
B. All other bulbs will continue to light
C. The brightness of the bulbs will increase.
D. The brightness of the bulbs will decrease.
10. Three light bulbs with resistances 2000 , 1600 , and 800 are connected in
series respectively. Which one has the highest brightness when the circuit is
plugged to a 220 V voltage source?
A. 800 2
B. 1600 2
C. 2000 2
D. none of the above
Answer:
A. all other bulbs will no longer work
How many moles are in 35.6 g of H2O
Answer:
Given
mass of H2O (m) =35.6g
molarmass (mr) = H2O ), 1x2+16=18g/mol
moles of H2O (n) =?
sln
n=m/mr
n=35.6g/18g/mol
n=1.978moles
the moles of H2O are 1.978moles
similarities of ancient and modern philosophy