Based on molecular orbital theory, the only molecule in the list below that has unpaired electrons is __________.a) C2b) N2c) F2d) O2e) Ne2

Approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M.

To determine the mass of glucose (C6H12O6) required to prepare a 0.215 M solution in 5000 mL, we need to use the formula:

Molarity (M) = moles of solute / volume of solution (in liters)

First, let's convert the volume of the solution from milliliters (mL) to liters (L):

5000 mL = 5000/1000 = 5 L

Now, we can rearrange the formula to solve for moles of solute:

moles of solute = Molarity (M) x volume of solution (L)

moles of solute = 0.215 M x 5 Lmoles of solute = 1.075 mol

Since glucose (C6H12O6) has a molar mass of approximately 180.16 g/mol, we can calculate the mass of glucose using the equation:

mass of solute = moles of solute x molar mass of solute

mass of glucose = 1.075 mol x 180.16 g/mol

mass of glucose = 194.0 g (rounded to three significant figures)

Therefore, approximately 194.0 grams of glucose (C6H12O6) would be required to prepare a 5000 mL solution with a concentration of 0.215 M. It's important to note that the molar mass of glucose used in this calculation may vary slightly depending on the level of precision required.

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Answer:

B

Explanation:

Newton's third law. states that:

Action and reaction are equal and opposite.

Answer:

\(\boxed {\boxed {\sf 0.3 \ mol \ NH_3}}\)

Explanation:

We need to use stiochiometry and a mole to mole conversion to solve this problem.

First, examine the chemical equation. Make sure it is balanced before doing any calculations.

\(N_2+3H_2 \rightarrow 2NH_3\)

It is balanced, so we can also use the coefficients to refer to molar amounts.

So, the equation is also saying that 1 mole of N₂ (no coefficient implies 1) and 3 moles of H₂ react to form 2 moles of NH₃.

\(1 \ mol \ N_2 + 3 \ mol \ H_2 \rightarrow 2 \ mol \ NH_3\)

Now we can use this information to make a ratio. We know that we have 0.45 moles of hydrogen, and we are trying to find the moles of ammonia.

According to the original equation, 3 moles of hydrogen produce 2 moles of ammonia. Let's make a ratio.

\(\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

We have 0.45 moles of hydrogen, so multiply by that number.

\(0.45 \ mol \ H_2 *\frac {3 \ mol \ H_2}{2 \ mol \ NH_3}\)

Flip the ratio so the units of moles of hydrogen cancel.

\(0.45 \ mol \ H_2 *\frac{2 \ mol \ NH_3 }{3 \ mol \ H_2}\)

\(0.45 *\frac{2 \ mol \ NH_3 }{3}\)

\(\frac {0.45 *2 \ }{3} mol \ NH_3\)

\(\frac {0.9 \ }{3} mol \ NH_3\)

\(0.3 \ mol \ NH_3\)

0.3 moles of ammonia are produced when 0.45 moles of hydrogen gas react with nitrogen gas.

Answer:

We often want to decrease the rates of certain reactions rather than speeding them up. For example, to prolong the shelf lives of certain foods, the chemical reactions by which they spoil must be slowed down.

Answer:

Fe2O3

Explanation:

get the ratio for both Fe and O using relative atomic mass and the percent as the mass

There are 2.64 × 1022 molecules of sucrose present in this serving of fruit dessert containing 15.0 g of sugar.

To determine the number of molecules of sugar present in the serving, we need to calculate the number of moles of sugar and then convert it to the number of molecules.

Given:

Mass of sugar (sucrose) = 15.0 g

Molar mass of sucrose (C12H22O11) = 342 g/mol

First, calculate the number of moles of sugar using the formula:

Number of moles = Mass of substance / Molar mass

Number of moles of sugar = 15.0 g / 342 g/mol ≈ 0.0439 mol

Next, we use Avogadro's number, which states that there are approximately 6.022 × 10^23 molecules in one mole of a substance. Therefore, to find the number of molecules of sugar:

Number of molecules = Number of moles × Avogadro's number

Number of molecules of sugar = 0.0439 mol × 6.022 × 10^23 molecules/mol ≈ 2.64 × 10^22 molecules

Therefore, there are approximately 2.64 × 10^22 molecules of sugar present in this serving.

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Answer:

1.70 L

Explanation:

From the question given above, the following data were obtained:

Pressure (P) = constant = 1.2 atm

Initial volume (V1) = 1.25 L

Initial temperature (T1) = 293 K

Final temperature (T2) = 398 K

Final volume (V2) =?

Since the pressure is constant, the gas is obeying Charles' law. Thus, we can obtain the new volume (V2) of the gas by applying the Charles' equation as shown below:

V1/T1 = V2/T2

1.25 / 293 = V2 /398

Cross multiply

293 × V2 = 1.25 × 398

293 × V2 = 497.5

Divide both side by 293

V2 = 497.5 / 293

V2 = 1.70 L

Therefore, the new volume of the gas is 1.70 L.

\(\\ \tt\Rrightarrow \nu=\dfrac{c}{\lambda}\)

\(\\ \tt\Rrightarrow \nu=\dfrac{3\times 10^8}{1000\times 10^{-9}}\)

\(\\ \tt\Rrightarrow \nu=0.003\times 10^{17}s^{-1}\)

\(\\ \tt\Rrightarrow \nu=3\times 10^{14}Hz\)

Answer:

Its B

Explanation:

Its pretty easy. Im three days late my bad my guy

Answer:

It's B

Explanation:

Answer:

KCI is rhe solute in a homogeneous mixture

Answer:

1. KCI is the solute in a homogeneous mixture.

Explanation:

Two ways in which scientists can exhibit ethical behavior are

Science can simply be defined as an intellectual and proven practical activity encompassing the systematic study of the structure and behaviour of the physical and natural world through observation and experiment.

So therefore, two ways in which scientists can exhibit ethical behavior are

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Answer:

(mass of A) x (% of A) + (mass of B) x (% of B) + (mass of C) x (% of C)

Explanation:

got it right

The average atomic mass of magnesium is 24.305 amu.

The mass of a single atom is too small to be measured directly, but chemists and physicists use the atomic mass unit (amu) to describe the mass of an atom.

The atomic mass unit is defined as 1/12th of the mass of a carbon-12 atom. Magnesium (Mg) has three isotopes: Mg-24, Mg-25, and Mg-26, with masses of 23.985 amu, 24.986 amu, and 25.983 amu, respectively.

These isotopes make up 78.99%, 10.00%, and 11.01%, respectively, of all naturally occurring Mg atoms.

The atomic mass of Mg can be calculated using the weighted average of the three isotopes as follows:Average atomic mass = (78.99/100 x 23.985 amu) + (10.00/100 x 24.986 amu) + (11.01/100 x 25.983 amu)Average atomic mass = 23.940 amu + 2.499 amu + 2.864 amuAverage atomic mass = 29.303 amu.

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Answer:

The number of yards is 792.

Explanation:

To convert 0.45 miles to yards it is necessary to use the equivalence from mile to feet, and then the equivalence from feet to yard:

So, it is 792 yards.

Answer:

Sodium hydroxide

Calcium sulfate

Ammonium cyanide

Aluminum sulfate

Explanation:

Just did it

The correct name for given compound is , NaOH (sodium hydroxide) , \(CaSO_{4}\) (Calcium sulfate) , \(NH_{4} CN\) (ammonium cyanide) and Al2(SO4)3 (aluminum sulfate).

A chemical compound can be defined as a substance made up of numerous identical molecules bound together through chemical bonds and made up of atoms from different elements.

Sodium hydroxide is the kind of organic compound which chemical formula is NaOH.

The name of given compound is :

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Answer:

D. The sun has less gravitational pull on Pluto because it is farther away.

The Kb for the conjugate base of HF, Fluoride ion is 1.470588 * 10^-11

The conjugate base of HF (hydrofluoric acid) is fluoride ion, F-

Ka of HF or hydrofluoric acid is given as 6.8 × 10⁻⁴

Kw = Ka * Kb

Where,

Kb = Base dissociation constant

Kw = Water dissociation constant or equilibrium constant

Ka = Acid dissociation constant

Kw = [H+] [OH-] = 1.0 X 10-14 at room temperature

The formula can be rewritten as,

Kb = (Kw / Ka)

     = (10^-14) / (6.8 * 10^-4)

     = 1.470588 * 10^-11

Therefore, the kb for the conjugate base of HF, Fluoride ion is 1.470588 * 10^-11

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Answer:

The common system of naming alcohol in its series is alcohol

Answer:

Most of the food energy that enters a trophic level is "lost" as heat when it is used by organisms to power the normal activities of life. Thus, the higher the trophic level on the pyramid, the lower the amount of available energy.

Explanation:

Answer:

C) only potential energy.

The energy of light with a wavelength of 589 nm is approximately 3.36 × 10^(-19) Joules.

To calculate the energy of light, we can use the equation E = hc/λ, where E represents the energy, h is Planck's constant (6.626 × 10^(-34) J·s), c is the speed of light in a vacuum (3.00 × 10^8 m/s), and λ is the wavelength of light.

Given that the wavelength is 589 nm (which is equivalent to 589 × 10^(-9) m), we can substitute the values into the equation:

E = (6.626 × 10^(-34) J·s × 3.00 × 10^8 m/s) / (589 × 10^(-9) m)

Simplifying the equation, we get:

E = (1.9778 × 10^(-25) J·m) / (5.89 × 10^(-7) m)

Dividing these values, we find:

E ≈ 3.36 × 10^(-19) J

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Answer:

1. The energy of the reactant is 50 KJ

2. The energy of the product is 100 KJ

3. The activation energy of the forward reaction is 200 KJ.

4. The activation energy of the reverse reaction is 150 KJ.

5. The energy of the forward reaction is +50 KJ

6. The energy of the reverse reaction is –50 KJ

7. Endothermic reaction

8. Exothermic reaction

Explanation:

1. Determination of the energy of reactant.

From the diagram given above, the energy of the reactant is 50 KJ

2. Determination of the energy of product.

From the diagram given above, the energy of the product is 100 KJ.

3. Determination of the activation energy of the forward reaction.

The activation energy is the energy between the reactant and the peak. It can be obtained as follow:

Energy of reactant (Eᵣ) = 50 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 50

Eₐ = 200 KJ

Thus, the activation energy of the forward reaction is 200 KJ

4. Determination of the activation energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy at the peak (Eₕ) = 250 KJ

Activation energy (Eₐ) =?

Eₐ = Eₕ – Eᵣ

Eₐ = 250 – 100

Eₐ = 150 KJ

Thus, the activation energy of the reverse reaction is 150 KJ

5. Determination of the energy of the forward reaction.

Energy of reactant (Eᵣ) = 50 KJ

Energy of product (Eₚ) = 100 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 100 – 50

ΔH = +50 KJ

Thus, the energy of the forward reaction is +50 KJ

6. Determination of the energy of the reverse reaction.

Energy of reactant (Eᵣ) = 100 KJ

Energy of product (Eₚ) = 50 KJ

Enthalpy change (ΔH) =?

ΔH = Eₚ – Eᵣ

ΔH = 50 – 100

ΔH = –50 KJ

Thus, the energy of the reverse reaction is –50 KJ

7. The forward reaction is endothermic reaction because the energy of the product is higher than the energy of the reactant which leads to positive energy of the forward reaction (+50 KJ).

8. The reverse reaction is exothermic reaction because the energy of the product is lesser than the energy of the reactant which leads to negative energy of the reverse reaction (–50 KJ). In a nut shell, we can say that the energy of the reverse reaction is exothermic because its energy of reaction is –50 KJ.

Answer:

Ketones and ketoacids are alternative fuels for the body that are made when glucose is in short supply. They are made in the liver from the breakdown of fats. Ketones are formed when there is not enough sugar or glucose to supply the body's fuel needs. This occurs overnight, and during dieting or fasting.

Explanation:

The structural formula of butanol is C4H9OH. It consists of a chain of four carbon atoms, with a hydroxyl (-OH) group attached to one of the carbon atoms. Butanol has several structural isomers, which have the same molecular formula but different structural formulas.

A structural isomer is a compound that has the same molecular formula as another compound but has a different arrangement of its atoms. A string of 4 C atoms are bonded above, below, left, and right to H, except the second C, which is bonded below to O, which is bonded below to H is a structural isomer of butanol.

This is called butan-2-ol. The structural formula of butan-2-ol is CH3CH(OH)CH2CH3. In this isomer, the hydroxyl group is attached to the second carbon atom in the chain, whereas in butanol, the hydroxyl group is attached to the first carbon atom in the chain.

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a) The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) the number of moles of O₂ required is approximately 1.004 moles.

c)  approximately 45 liters of H₂ and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O.

a) Balancing the chemical equation:

The balanced chemical equation for the reaction is: 2H₂ + O₂ → 2H₂O

b) Calculating the number of moles of the reactants needed to obtain 45 liters of H₂O:

From the balanced equation, we can see that for every 2 moles of H₂O produced, we need 2 moles of H₂ and 1 mole of O₂. Since the stoichiometry is based on moles, we need to convert the given volume of H2O into moles.

To convert volume to moles, we need to use the ideal gas law, PV = nRT. At standard temperature and pressure (STP), the molar volume of an ideal gas is 22.4 liters.

Given that we have 45 liters of H2O, we can calculate the number of moles as follows:

moles of H₂O = (volume of H₂O) / (molar volume at STP)

            = 45 liters / 22.4 liters/mol

            ≈ 2.008 moles of H₂O

Since the stoichiometry of the reaction is 2 moles of H₂O for every 2 moles of H₂, we need an equal number of moles of H₂. Therefore, the number of moles of H₂ required is also approximately 2.008 moles.

For O₂, since the stoichiometry is 1 mole of O₂ for every 2 moles of H₂O, we need half the number of moles of H₂O. Thus, the number of moles of O₂required is approximately 1.004 moles.

c)  the volume of the reactants:

Since the stoichiometry of the balanced equation is 2 moles of H₂for every 1 mole of O₂ and 2 moles of H₂O, we can deduce the volume of the reactants based on their molar volumes at STP.

For 2.008 moles of H₂, the volume can be calculated as follows:

volume of H₂= (moles of H₂) * (molar volume at STP)

            = 2.008 moles * 22.4 liters/mol

            ≈ 45 liters of H₂

For 1.004 moles of O₂, the volume can be calculated similarly:

volume of O₂= (moles of O₂) * (molar volume at STP)

            = 1.004 moles * 22.4 liters/mol

            ≈ 22.5 liters of O₂

Therefore, approximately 45 liters of H₂and 22.5 liters of O₂ are needed to obtain 45 liters of H₂O

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