Answer:
The average magnitude of magnetic field B= 0.0433/ d Tesla
(You have not provided length of side of loop, so if you divide this value by length you will get value of magnetic field.)
Explanation:
Induced emf
where B= magnetic field
d= breadth of rectangular piece
V= velocity with which the rectangular piece = o.o6m/s
n= no of turns = 10
EMF = 26mV
since d (breadth of the frame) is not given, I will use it as a variable
EMF= n×B×d×V ------------------(1) (EMF induced due to multiple turns)
From eq 1, we get
B= (EMF)/(n d V)
B= (26 X 0.001) / (10 d 0.06)
B= 0.0433/ d Tesla
Name two examples of conservative forces
If a loading ramp is placed next to a truck, at a height of 4 feet, and the ramp is 13 feet long, what angle does the ramp make with the ground extending from the ramp to the truck? (Round your answer to one decimal place.)
Answer:
The angle that the ramp makes with the ground extending from the ramp to the truck is approximately 17.5 degrees.
Explanation:
We can start by drawing a right triangle where the hypotenuse is the ramp, the height is 4 feet, and the base is the distance from the truck to the bottom of the ramp (the horizontal distance).
Since we know the length of the hypotenuse and the height of the triangle, we can use the sine function to find the measure of the angle:
sin(θ) = opposite/hypotenuse
sin(θ) = 4/13
Now, we can solve for θ by taking the inverse sine (sin^-1) of both sides:
θ = sin^-1(4/13)
Using a calculator, we get:
θ ≈ 17.5 degrees
In the district soccer championship finals, Elizabeth kicks a 0.78 kg soccer ball with a
force of 33.0 N. How much does she accelerate the soccer ball from rest in the
process?
Answer:
42.36 m/ s^2
Explanation:
First implement the formula f=m*a. f=33Nmass=0.78kg.where acceleration comes 42.36 m/ s^ 2
Elizabeth accelerates the soccer ball with an acceleration of 42.3 m/s² from rest in the process.
What is acceleration?Acceleration of an object can be defined as the rate of change of velocity of an object with respect to time. The acceleration of an object is a vector quantity with both magnitude and direction. Acceleration is also defined as the second derivative of position w.r.t. time and the first derivative of velocity of an object w.r.t. time.
According to Newton's second law of motion, the force is equal to the product of the mass and acceleration of an object.
F = ma
And, a = F/m
Therefore, the acceleration of a body is inversely proportional to the mass of the body.
Given, the force with which, Elizabeth kicks a soccer ball
F = 33.0 N
The mass of the soccer ball = 0.78 Kg
The acceleration of the soccer ball = 33/0.78 = 42.3 m/s²
Therefore, the acceleration of the soccer ball when it gets kicked is 42.3m/s².
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Look at the diagram At which position on the diagram, does the ball have the least kinetic energy and the greatest potential energy? A Letter A B Letter B C Letter C
How much work is done when a 40 N force is applied to slide a box 5 meters?
Answer:
200j
Explanation:
see in the figure
the answer is in the figure and above
1) The equilibrium constant Kc for the reaction N 2(g) + O 2(g) 2NO(g) at 1200 C is 1.00x 10^-5. Calculate the molar concentration of NO, N2 and O2 in equilibrium at 1200 C in a 1.00L container that initially had 0.114 mol of N2 and 0.114 mol of O2
2) A 2.0 mmol sample of Cl2 was closed inside a 2.0 L reaction vessel and heated to 1000k to study its dissociation into Cl atoms, Kc= 1.2x10^- 7 (a) Calculate the composition of the mixture in equilibrium. What is the percentage of decomposition of Cl2? (b) If 2.0 mmol of F2, Kc= 1.2x10^-4, is placed inside the container instead of chlorine, what will be its equilibrium composition at 1000k? Use your results from (a) and (b) to determine which is the most stable with respect to your atoms, Cl2 or F2, at 1000k
Explanation:
1) N₂ + O₂ → 2 NO
Kc = [NO]² / ([N₂] [O₂])
Set up an ICE table:
\(\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\N_{2}&0.114&-x&0.114-x\\O_{2}&0.114&-x&0.114-x\\NO&0&+2x&2x\end{array}\right]\)
Plug into the equilibrium equation and solve for x.
1.00×10⁻⁵ = (2x)² / ((0.114 − x) (0.114 − x))
1.00×10⁻⁵ = (2x)² / (0.114 − x)²
√(1.00×10⁻⁵) = 2x / (0.114 − x)
0.00316 = 2x / (0.114 − x)
0.00361 − 0.00316x = 2x
0.00361 = 2.00316x
x = 0.00018
The volume is 1.00 L, so the concentrations at equilibrium are:
[N₂] = 0.114 − x = 0.11382
[O₂] = 0.114 − x = 0.11382
[NO] = 2x = 0.00036
2(a) Cl₂ → 2 Cl
Kc = [Cl]² / [Cl₂]
\(\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\Cl_{2}&2.0&-x&2.0-x\\Cl&0&+2x&2x\end{array}\right]\)
1.2×10⁻⁷ = (2x)² / (2 − x)
1.2×10⁻⁷ (2 − x) = 4x²
2.4×10⁻⁷ − 1.2×10⁻⁷ x = 4x²
2.4×10⁻⁷ ≈ 4x²
x² ≈ 6×10⁻⁸
x ≈ 0.000245
2x ≈ 0.00049
2(b) F₂ → 2 F
Kc = [F]² / [F₂]
\(\left[\begin{array}{cccc}&Initial&Change&Equilibrium\\F_{2}&2.0&-x&2.0-x\\F&0&+2x&2x\end{array}\right]\)
1.2×10⁻⁴ = (2x)² / (2 − x)
1.2×10⁻⁴ (2 − x) = 4x²
2.4×10⁻⁴ − 1.2×10⁻⁴ x = 4x²
2.4×10⁻⁴ ≈ 4x²
x² ≈ 6×10⁻⁵
x ≈ 0.00775
2x ≈ 0.0155
F₂ dissociates more, so Cl₂ is more stable at 1000 K.
how much work is required to stop an electron which is moving with a speed of 1.10x10^6m/s
Work required to stop an electron which is moving with a speed of 1.10x10^6m/s is \(-\frac{3.971}{5^{19}\cdot \:1048576}\)
What is electron?There are three main types of particles in an atom: protons, neutrons, and an electron that is bonded to an atom. For a variety of reasons, electrons are different from other particles. They possess both wave-like and particle-like properties, exist outside of the nucleus, have a substantially lower mass than protons. A particle that is not composed of smaller parts is an electron, which is also an elementary particle. They are not elementary particles because quarks are assumed to make up protons and neutrons.
We can solve the problem by using the work-energy theorem: in fact, the work done on the electron must be equal to its change in kinetic energy, therefore
\(W=K_{f}-K_{i}\)
\(W=\frac{1}{2} mv^{2} - \frac{1}{2} mu^{2}\)
where,
m=9.11 × 10⁻³¹kg is the mass of the electron
v is the final velocity of the electron
u is the initial velocity of the electron
In the problem, we are told that the electron is initially moving at,
v = 1.90×10⁶ m/s
Therefore, the work required to stop it as
W = -1/2 mv²
W = -1/2 (1.10×10⁻³¹)(1.90×10⁶)²
\(W= -\frac{3.971}{5^{19}\cdot \:1048576}\\\)
and the work is negative since it is in the opposite direction to the motion of the electron.
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If you pull with a constant force of 400n , how much mechanical work does it take to pull pinball launcher back 0.2meters
If you pull with a constant force of 400 N for 0.2 meters, then the work done will be equal to 80 J.
What is Work?In physics, the word "work" involves the measurement of energy transfer that takes place when an item is moved over a range by an externally applied, at least a portion of which is applied within the direction of the displacement.
The length of the path is multiplied by the element of a force acting all along the path to calculate work if the force is constant. The work W is theoretically equivalent towards the force f times the length d, or W = fd, to portray this concept.
As per the given information in the question,
Force, f = 400 N
Displacement, d = 0.2 meters
\(Work done(W)=Force(f)*Displacement(d)\)
W = 400 × 0.2
W = 80 J.
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Given that the luminosity of a star is given as a function of its radius and temperature by the equation. I do not understand this last question in terms of what to put into the given equation.
The luminosity of this star in units of the solar luminosity would be: 483.7L.
How to calculate the luminosityTo calculate the luminosity, we would use the different values given and the formula for luminosity.
Temperature = 9305K
Star's radius = \(5.90 * 10^{9} m\\\)
Luminoisty of the star
Luminosity of the sun
= \(\frac{4π * (5.90 * 10^9)^2 * 5.67 * 10^-8 * 9305^4 W}{3.846 * 10^26 W}\)
= 483.7L
This is the unit for luminosity.
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3. Calculate the radii of the first five Fresnel zones if the distance from the light source to the wave surface is 1m, the distance from the wave surface to the observation point is also 1m and the light wavelength is 0.0000005m. (0.50mm; 0.71mm; 0.86mm; 1.0mm; 1.12mm).
The radii of the first five Fresnel zones is 3.6 mm.
Distance from the light source to the wave surface, d₁ = 1 m
Distance from the wave surface to the observation point, d₂ = 1 m.
Wavelength of the light used, λ = 5 x 10⁻⁶m = 5 μm
The expression for the radius of the Fresnel zones is given by,
rₙ = √[nλd₁d₂/(d₁ + d₂)]
Therefore, the radii of the first five Fresnel zones is,
r₅ = √[5 x 5 x 10⁻⁶x 1 x 1/(1 + 1)]
r₅ = √(25 x 10⁻⁶/2)
r₅ = 3.6 x 10⁻³m
r₅ = 3.6 mm
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How is a theory different from a law? Theories are factual statements, while laws can be used to make predictions. Theories cannot be modified over time, while laws can be modified over time. Theories are factual statements, while laws are modified over time. Theories can be modified over time, while laws cannot be modified over time.
Answer:
A scientific law describes an observed pattern found in nature without explaining it. The theory is the explanation.
Answer:
Explanation:A scientific law describes an observed pattern found in nature without explaining it. The theory is the explanation
Which of the following least represents an negative impact on Earth caused mostly by humans?
A) Deforestation
B) Urbanization
C) Erosion
D) Recycling
Answer:
A
Explanation:
because uhhh I'm doing the same test as you kinda LOL
4x The law of conservation of matter states that during a chemical reaction, the amount of matter
A
B
C
D
decreases.
stays the same.
disappears.
increases.o
The law of conservation of matter stated that during a chemical reaction, the amount of matter stays the same. Thus, option B is correct.
Matter can be changed into other forms either by physical or chemical changes. But through any of these changes matter remains constant. The amount of matter present before the chemical reaction will remain the same after the chemical reaction. Thus, the matter can neither be created nor destroyed.
The law of conservation of matter is defined as the law of conservation of mass. Hence, in a system, the mass or matter remains conserved, before and after the chemical reaction and it was given by Antonie Lavoisier.
The law of conservation of matter states that during a chemical reaction, the amount of matter remains the same. Thus, the ideal solution is option B.
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What would happen if I removed the battery from the circuit?
Answer:
The current would stop
Explanation:
Electric currents are interesting because they carry little to no momentum. As soon as you remove a power source, the whole current halts.
A rocket accelerates from rest at 27 m/s^2 for 11 s.
How far will it cover during this time?
Answer in units of m.
Answer:
297m
Explanation:
297 x 11
:)
What is 3^7*8^3*5^6?
Answer:
17496000000
Explanation:
I NEED HELP WITH THIS PLEASE
Answer:
D
Explanation:
One of the factors of increasing the rate of a reaction is increasing concentration. Therefore adding more people increases the number of people on the dance floor , therefore increasing the concentration increases the rate of reaction.
Four forces of magnitude 10N 5N 4N and 6N act on an object in the direction of north west east and south respectively find the magnitude and direction of their resultant
The magnitude and direction of the resultant force (F=10N+5N+4N+6N) when four forces of magnitude 10N, 5N, 4N, and 6N operate on an object in the directions of north, west, east, and south, respectively, is 25N.
What do you mean by magnitude?In terms of physics, magnitude is just "distance or quantity." It displays an object's size, direction, or motion in absolute or relative terms. It is employed to indicate the size or scope of something. The word "magnitude" in physics frequently denotes a size or quantity.. Something's magnitude is determined by its size. For example, a car moves faster than a bike with terms of speed. The speed difference between the car and the bike in this case is greater. It reveals the absolute or relative size or direction that an object moves when in motion.
What is magnitude of speed?Speed is defined as the magnitude of velocity, and the magnitude of the slope of the displacement-time graph provides the speed. Since the slope gets steeper as we move from A to B, Speed is increased as a result between points A and B.
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A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is ___ Newton.
A rope pulls a Tesla out of mud. The guy pulls a force F⊥ of 300N, and theta = 4.2°. The tension force T is 298.44__ Newton.
The problem describes a Tesla that is stuck in the mud and needs to be pulled out using a rope. the guy pulls a force F⊥ of 300N and that the angle between the rope and the horizontal plane is θ = 4.2°. The goal is to find the tension force T exerted by the rope.To solve for T, we'll need to use trigonometry. We can break the force vector into its horizontal and vertical components as follows:
Fx = F⊥ cosθ and Fy = F⊥ sinθ.
Since the rope is pulling the Tesla horizontally, the horizontal component of the force will be the tension force T. So we have:
T = Fx = F⊥ cosθ = (300 N) cos(4.2°) ≈ 298.44 N
Taking the cosine of the angle is necessary since it's the adjacent side that we're interested in, which is the horizontal component of the force. Therefore, the tension force exerted by the rope is approximately 298.44 N.
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Define electromagnetism
Answer:
the phenomenon of the interaction of electric currents or fields and magnetic fields.
The first P-wave of an earthquake travels 5600 kilometers from the epicenter and arrives at a seismic station at 10:05 a.m. At what time did this earthquake occur?
Ahhhhhh I have a Regent's test in 2 hours and I don't know how to solve this type of question! Any help would be appreciated.
Anyone know what the steps to do this are? I dont even need an answer, just how to get to it. Thank you!
The earthquake would occur 13 minutes before 10:05 a.m. which will be at 9.52 am.
The p-waves travel with a constant velocity of 7 km/s
The time can be calculated by using the formula
t = d / v
where
T1 = 10:05 a.m
d is the distance they take to travel from the epicenter
v is the speed of the p-waves
On average, the speed of p-waves is
v = 7 km/s
d = 5600 km (given)
Substituting the values in the formula;
t = d / v
t = 5600 ÷ 7
t = 800 seconds
Converting into minutes,
t = 800 ÷ 60
t = 13.3
≈ 13 mins
T1 - 13 mins = T2
10:05 - 13 mins = 9.52 am
It means the earthquake occurred prior 13 minutes, that is at 9.52 am.
Therefore, the earthquake occurred at 9.52 am.
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If you put a leash on a 12kg cat and try to take it for a walk, it will not be happy. Eventually it will refuse to walk and you will have to drag it home. If you are dragging the cat with a horizontal force of 55 N and the coefficient of friction between the cat and the grass is 0.3. What is the Acceleration of the cat
Answer: \(1.64 m/s^{2}\) (3 sig figs)
\(1.6 m/s^{2}\) (2 sig figs)
Explanation:
First we need to find the weight of the cat using F=ma (117.72 = 12 * 9.81)
Using 117.72 we can find the force of friction by doing F = μ * N (35.316 = 0.3 * 117.72)
After we find the friction force we simply subtract the friction force from the applied force (19.684 = 55 - 35.316)
Using 19.684 we can find the acceleration using F / m = a (19.684 / 12 = 1.64)
From there you reduce your answer to the number of sig figs, which I think is 2 unless otherwise specified.
A carnival ride starts at rest and is accelerated from an initial angle of zero to a final angle of 6.3 rad by a rad counterclockwise angular acceleration of 2.0 s2 What is the angular velocity at 6.3 rad?
The final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.
Final angular velocity of the carnival ride
The final angular velocity of the carnival ride is determined by applying third kinematic equation as shown below;
ωf = ωi + 2αθ
where;
ωf is the final angular velocity of the carnival ride = ?ωi is the initial angular velocity of the carnival ride = 0α is the angular acceleration = 2.0 rad/s²θ is the angular displacement of the carnival ride = 6.3 radωf = 0 + 2(2.0) x 6.3
ωf = 25.2 rad/s
Thus, the final angular velocity of the carnival ride at a displacement of 6.3 rad is 25.2 rad/s.
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Answer: 5.0 rad/s
Explanation: Because that’s what khan said so try it out.
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
A radio is rated as 50 W. Calculate the energy transferred in Joules by the radio when it has been switched on for 2 minutes?
The energy transferred in Joules by the radio when it has been switched on for 2 minutes would be 6000 Joules.
Energy transferPower is defined as the rate of energy transfer or the rate at which work is done, and is given by the equation:
Power = Energy transferred / Time
Rearranging the equation to solve for energy transferred, we get:
Energy transferred = Power x Time
We are given:
Power = 50 W
Time = 2 minutes = 120 seconds
Therefore, the energy transferred by the radio when it has been switched on for 2 minutes is:
Energy transferred = Power x Time = 50 W x 120 s = 6000 J
In other words, the energy transferred by the radio is 6000 Joules.
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an ideal gas at 20centigree In a press 1.5×10pa and compress,a.isothamally,b.adaibatically until it volume in 1/3 in each case reversible.calculate in each case the final pressure and temperature of d gas (the ratio all specific capacity=Cp/Cv=1.4
a) The final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\) and 293 K, respectively, while b) the final pressure and temperature for the adiabatic compression are\(5.58*10^5 Pa\) and 515 K, respectively.
a. Isothermal compression:
For an isothermal process, the temperature remains constant. Therefore, we can use the ideal gas law:
PV = nRT
where P is the pressure, V is the volume, n is the number of moles of gas, R is the gas constant, and T is the temperature.
Since the process is isothermal, we can write:
\(P_1V_1 = P_2V_2\)
where P1 and V1 are the initial pressure and volume, and\(P_2\)and\(V_2\)are the final pressure and volume.
We are given that the volume is compressed to 1/3 of its original volume, so\(V_2 = (1/3)V_1\). Substituting this into the equation above gives:
\(P_2 = (V_1/V_2)P_1 = 3P_1\) = \(4.5*10^5 Pa\)
To find the final temperature, we can use the ideal gas law again:
PV = nRT
Rearranging, we get:
T = PV/(nR)
Substituting the values we know, we get:
T = (\(1.5*10^5\)Pa)(V1)/(nR)
Since the process is isothermal, the temperature remains constant, so the final temperature is the same as the initial temperature:
T2 = T1 = 293 K
b. Adiabatic compression:
For an adiabatic process, there is no heat transfer between the gas and its surroundings. Therefore, we can use the adiabatic equation:
PV^γ = constant
where γ = Cp/Cv is the ratio of specific heats.
Since the process is adiabatic and reversible, we can write:
\(P_1V_1\)^γ = \(P_2V_2\)^γ
We are given that the volume is compressed to 1/3 of its original volume, so V2 = (1/3)V1. Substituting this into the equation above gives:
\(P_2 = P_1(V_1/V_2)\)^γ = \(P_1\)\((3)^{(1.4)\) = \(5.58*10^5 Pa\)
To find the final temperature, we can use the adiabatic equation again:
\(T_2 = T_1(P_2/P_1)\)^((γ-1)/γ) = T1(5.58/1.5)^(0.4) = 515 K
Therefore, the final pressure and temperature for the isothermal compression are \(4.5*10^5 Pa\)and 293 K, respectively, while the final pressure and temperature for the adiabatic compression are \(5.58*10^5\) Pa and 515 K, respectively.
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You will need to know that Force (N) is equal to mass (kg) multiplied by acceleration (m/s2) for this problem. A fearless space explorer has discovered a new planet with a frictionless surface! He pushes a large crate with a mass of 220kg a distance of 5.3 km, as he does so, it accelerates at a rate of 2m/s2. How much work has our intrepid hero done?
Our intrepid hero has done 2332 kJ of work pushing the crate on the frictionless surface of the newly discovered planet.
The work done by the space traveler can be determined utilizing the recipe W = F x d, where W is work, F is power, and d is distance. To find the power, we can utilize the recipe F = m x a, where m is mass and an is speed increase. Connecting the given qualities, we get F = 220 kg x 2 m/s^2 = 440 N.
Presently we can compute the work done by increasing the power by the distance: W = 440 N x 5.3 km = 2332 kJ. Accordingly, our fearless legend has done 2332 kJ of work pushing the container on the frictionless surface of the newfound planet.
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two spheres A and B are projected off the edge of a 1.0 m high table with the same horizontal velocity . sphere A has a mass of 20.g and sphere B has a mass of 10.g.
If both spheres leave the edge of the table at the same instant, sphere A will land
a. at some time after sphere B.
b. at the same time as sphere B.
c. at some time before sphere B.
d. There is not enough information to decide.
Answer:
c. because A will land first becuase its heavier :)
Explanation:
We can easily tell that a bowling ball rolling down an ally has energy of motion. But why would a scientist say that a white-hot piece of iron also has the energy of motion within it?
A white-hot iron piece has internal motion energy due to constant particle movement at the atomic and molecular levels, as per scientists. Thermal energy or heat energy is motion. Higher temperature means more kinetic energy and faster motion of atoms and molecules.
What is the energy of motion?White-hot iron vibrates atoms and molecules at high temperatures. Kinetic theory states that all matter is made up of moving particles. Motion occurs at the microscopic level, beyond eye view. Higher temperature = greater particle energy.
When a scientist refers to white-hot iron, they recognize its high temperature corresponds to increased kinetic energy and motion. Motion and energy at the atomic level are not visible like a bowling ball, but are fundamental traits of matter.
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why does pure water increase in volume when heated
Answer:
Pure water increases in volume when heated due to the phenomenon of thermal expansion. When water is heated, the kinetic energy of its molecules increases, causing them to move faster and spread out. This increased molecular movement leads to an increase in the average distance between water molecules, resulting in an expansion of the water.
Explanation:
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