Based on this idea, predict the surface tension ranking of the following substances: • Decane (C10H22) • Hexane (C6H14) • Octane (C8H18) • Pentane (C5H12) Write your prediction in the space below

37.85 g of C₃H₃N can be produced when 21.6 g of C₃H₆ react with 21.6 g of NO, determined with the help of limiting reactants in the reactions.

The balanced equation for the reaction is:

4C₃H₆ (g) + 6NO (g) → 4 C₃H₃N (s) + 6H₂O (l) + N₂ (g)

We can use stoichiometry to calculate the mass of C₃H₃N produced from the given amounts of C₃H₆ and NO.

We must first identify which reactant is excess and which is limiting. We can do this by calculating the number of moles of each reactant:

moles of C₃H₆ = mass / molar mass

= 21.6 g / 42.08 g/mol

= 0.513 mol

moles of NO = mass / molar mass

= 21.6 g / 30.01 g/mol

= 0.720 mol

The stoichiometric ratio of C₃H₆ to NO is 4:6, or 2:3. Therefore, if we have 2 moles of C₃H₆, we need 3 moles of NO to react completely.

Let's check if there is enough NO to react with all the C₃H₆:

(0.513 mol C₃H₆) x (3 mol NO / 2 mol C₃H₆)

= 0.7705 mol NO

Since we only have 0.720 mol of NO, it is the limiting reactant. This means that all the NO will be consumed in the reaction, and any remaining C₃H₆ will be left over.

Now, we can use the balanced equation to calculate the amount of C₃H₃N produced from the 0.720 mol of NO:

(0.720 mol NO) x (4 mol C₃H₃N / 6 mol NO) x (104.15 g/mol C₃H₃N) = 37.85 g C₃H₃N.

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Answer:

C2H3O2 (acetate)

Explanation:

61.05 g C x 1 mol C / 12.01 g C = 5.083 mol C

7.65 g H x 1 mol H / 1.01 g H = 7.57 mol H

81.30 g O x 1 mol O / 16.00 g O = 5.081 mol O

Divide by lowest number

5.083 / 5.081 = approx. 1 mol C

7.57 / 5.081 = approx. 1.5 mol H

5.081 / 5.081 = 1 mol O

so ratio of moles in this compound are 1 mol C : 1.5 mol H : 1 mol O

Multiply by 2 to get whole number mol ratios

--> empirical formula is C2H3O2 (acetate)

Answer:

warm, dry downslope wind affecting Southern California - Santa Ana wind

a seasonally changing wind- monsoon

wind blowing from a valley up a mountain slope - valley breeze

generated by cold thunderstorm downdrafts - haboob

Explanation:

The Santa Ana wind occurs in early autumn. They bring hot and dry weather to areas around the South-West coast. They move at high speeds, affecting most parts of Southern California.

Monsoon is a seasonal wind that blows across Southern Asia. It usually blows in summer. It is a a seasonally changing wind.

Valley breeze is an example of convection current in nature. It is produced by rapid warming of the valley floor leading to the expansion of air making it to flow up the slopes. At night, radiation from the surface cools the slopes. This leads to the rise of cooler and denser air which drains into the valley.

Haboob is generated by cold thunderstorm downdrafts. It is associated with large sandstorms and dust storms.

The mole fraction of cesium chloride is 0.06296.

The mole fraction is the product of the number of molecules of a specific component in a mixture and its total molecular weight.

By mixing 60.0 g of water with 42.9 g of cesium chloride, a solution is created.

The volume of the solution is given as 63.3 ml.

The solute in this aqueous solution is cesium chloride. From their given masses and known molar masses, we require the moles of water and cesium chloride:

n( CaCl ) = 42.9 g × ( mol ) / ( 168.36 g )

n( CaCl ) = 0.254 mol

n( water ) = 60.0 g × ( mol ) / 18.01 g

n( water ) = 3.78 mol

Therefore, the mole fraction of cesium chloride solute will be:

( 0.254 mol ) / ( 0.254 mol + 3.78 mol ) = 0.06296

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Answer:

universal law of gravitation

Explanation:

According to Newton's law of gravitation, every particle in universe attracts every other particles with a force which is directly proportional to the product of their masses and inversely proportional to the square of distance between their centres!

Consider two particles having masses m1 and m2 and are apart r units, then the gravitational force acting between them is given by

\(F = G \cdot \frac{m1\cdot \: m2}{ {r}^{2} } \)

Where G is universal gravitational constant or proportionality constant!!

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A. Ammonia is the limiting reactant.

B. Theoretical yield of urea is 215.3 kg.

C. Percent yield for the reaction is 86.0%

D. The mass of the excess carbon dioxide left is approximately 54.1 kg.

a) To identify the limiting reactant, we should compare the amount of products formed from each reactant. The chemical equation for the formation of urea \((NH_2CONH_2)\) by combining ammonia \((NH_3)\) and carbon dioxide \((CO_2)\) is as follows:

\(2 NH_3 + CO_2 - > NH_2CONH_2 + H_2O\)

The stoichiometry of the balanced equation indicates that the ratio of ammonia to urea is 2:1.

We can find the number of moles for each reactant using the following masses:

Moles of ammonia = 122.0 kg / 17.03 g/mol = 7.17 mol

Moles of carbon dioxide = 211.4 kg / 44.01 g/mol = 4.80 mol

It takes 14.34 moles of ammonia to react completely with the available carbon dioxide because the ratio of ammonia to urea is 2:1. But the amount of ammonia we have is less than we need - only 7.17 mol. As a result, ammonia is the limiting reactant.

b. Based on the limiting reactant, it is possible to calculate the theoretical yield of urea. We can use the moles of ammonia, which is the limiting reactant, to calculate the moles of urea:

Moles of urea = 7.17 mol / 2 = 3.58 mol

We can determine the theoretical yield of urea using the molar mass of urea (60.06 g/mol) as a starting point:

Theoretical yield of urea = 3.58 mol * 60.06 g/mol = 215.3 kg

C. The actual yield (185.1 kg) is calculated by dividing it by the theoretical yield (215.3 kg), then multiplying the result by 100%.

Percent yield = (185.1 kg / 215.3 kg) * 100% = 86.0%

D. We can calculate the amount of non-limiting reactant that has not reacted yet to determine the excess reactant. Since ammonia is the limiting reactant, we must determine how much excess carbon dioxide there is:

Moles of excess carbon dioxide = Moles of carbon dioxide initially - Moles of carbon dioxide used

= 4.80 mol - (7.17 mol / 2) = 1.23 mol

We can determine the mass of excess carbon dioxide using the molar mass of carbon dioxide (44.01 g/mol):

Excess carbon dioxide = 1.23 mol * 44.01 g/mol = 54.1 kg

Therefore, the mass of the excess carbon dioxide left is approximately 54.1 kg.

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The air is too "rich" to burn above the upper limit, but the situation might soon deteriorate into danger: For instance, increasing the air in a space can quickly reduce the product's vapor percentage to levels that are within its flammability range, which could have explosive effects.

Flammable liquids and gases need to be handled and stored carefully since they have low flash points. Never assume that these items won't catch fire. You must continually keep in mind the safety precautions for handling and storing combustible products if you want to keep both you and your company safe.

To prevent them from getting engaged and stoking a fire, combustible objects including cardboard, paper towels, sawdust, and waste must be kept away from flammable storage spaces. All flammable liquid containers must be kept closed while not in use to further help avoid fires.

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answer and explanation

1 L = 1000 mL

and so to determine 7.8L we can o the calculation as follows

x mL = 1000 mL/ 1 L x 7.8 L/1 = 7800 mL/1 = 7800 mL

n = m / M

m = n × M

Nitrogen (N2) - a gas is always with an index 2 if we don't have shown how many molecules are there

m (N2) = 4,5 mol × (2×14.007 g/mol)

m (N2) = 4,5 mol × 28.014 g/mol = 126.063g

if you don't solve with the decimals in class just replace 14.007 with 14

also if you haven't learned abour gasses aways having index 2 then:

m (N2) = 4,5 mol × 14.007 g/mol = 63.0315g

In mercuric oxide percent by mass of mercury is 93 %.

The mercuric oxide molecular formula is HgO. When mercury is reacted with oxygen, then it forms the product mercuric oxide. Mercuric oxide has a molecular mass of 216 g/mol. It has a melting point of 500°C.

The balance equation for the reaction of decomposition of mercury oxide into mercury and oxygen is,

\(2HgO (s)→ 2Hg (l) + O _{2}(g)\)

Mass of mercury oxide = 28.4 g

Mass of the oxygen = 2 g

In mercuric oxide percent by mass of mercury is,

\(Mass ℅= \frac{Mass \: of \: Mercury }{Mass \: of \: Mercury \: oxide} \times 100\)

\(= \frac{28.4 - 2}{28.4} \times 100\)

= 93 %

Therefore, in mercuric oxide percent by mass of mercury is 93 %.

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Option c) NH4Cl will hydrolyze when dissolved in water.

Hydrolysis is a chemical reaction that occurs when a salt reacts with water, resulting in the formation of an acidic or basic solution. In this case, when NH4Cl (ammonium chloride) is dissolved in water, it undergoes hydrolysis.

The ammonium ion (NH4+) is the conjugate acid of ammonia (NH3), which is a weak base. When NH4Cl dissociates in water, the ammonium ion reacts with water to form NH3 and H3O+ (hydronium ion). This process is called hydrolysis.

NH4+ (aq) + H2O (l) ↔ NH3 (aq) + H3O+ (aq)

The formation of NH3 leads to an increase in the concentration of hydroxide ions (OH-) in the solution, making it slightly basic. At the same time, the presence of H3O+ ions makes the solution slightly acidic. Therefore, the hydrolysis of NH4Cl results in a slightly acidic and slightly basic solution.

In contrast, salts like NaCl and KCl do not undergo hydrolysis when dissolved in water because they consist of cations (Na+ and K+) and anions (Cl-) that do not react with water to form acidic or basic species.

Na2SO4 (sodium sulfate) is also an example of a salt that does not undergo hydrolysis. The sulfate ion (SO42-) does not react with water to form acidic or basic species, so the solution remains neutral.

Therefore, among the given options, only NH4Cl undergoes hydrolysis when dissolved in water.

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The question is incomplete. Find the full content below:

Which one of the following salts when dissolved in water will hydrolyse?

a) NaCl

b) KCl

c) NH4Cl

d)Na2SO4

It helps explain why there are 4 equivalent C-H bonds in CH4,It allows for a better representation of the arrangement of electrons in the molecule, and It helps explain why the dipole moment of the molecule is zero.

Hybridization is the process of combining two or more distinct entities to create a new, unique entity that has a combination of the characteristics of the original entities. It can be used to describe a wide range of phenomena, ranging from the breeding of plants and animals to the intermixing of different cultures.

In biology, hybridization is the process of combining the genetic material of two different species to create a hybrid organism.

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Since liquids are frequently flammable, they will transition into the vapor phase when the temperature is raised high enough.

The total vapor pressure above a mixture of two volatile liquids can be forecast using Raoult's law. In fact, the more volatile molecule will have a larger mole fraction in the vapor phase than in the liquid phase, resulting in a composition of the vapor that differs from that of the two liquids.

Condensation is the term for this action. The pressure exerted by a vapour with its condensed phases (solid or liquid) in a closed system at a specific temperature is referred to as vapour pressure, also known as vapour equilibrium pressure.

The partial pressures of the constituents dictate the composition of the vapour phase in equilibrium with the solution.

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Answer:

I believe its c

Explanation:

i'm doing it on edge, let me know if i'm wrong

Answer:

The answer is C.)Protons have an electrical charge, but neutrons have no charge.

Explanation:

I got it right on edge

Visible light and radio waves are both forms of electromagnetic radiation, which has a dual nature and can exhibit properties of both particles (photons) and waves.

The wave nature of electromagnetic radiation is characterized by its wavelength and frequency, which are related by the speed of light (c = λν). Visible light having a shorter wavelength and higher frequency than radio waves, which have longer wavelengths as well as lower frequencies.

The particle nature of electromagnetic radiation is characterized by photons, which are discrete packets of energy that behave like particles. The energy of a photon is directly proportional to its frequency (E = hν), where h is Planck's constant. When electromagnetic radiation interacts with matter, it can transfer its energy to electrons in the material, causing them to be excited to higher energy levels or even ionized (knocked out of the material).

In summary, electromagnetic radiation, including visible light and radio waves, has both wave-like and particle-like properties, depending on the way it is observed and the context in which it is being studied.

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--The given question is incomplete, the complete question is

"Visible light and radio waves are both example of _____ radiation, which has a dual nature, possessing the properties of both ______ and waves."--

The national ambient air quality standards (NAAQS) were set to regulate emissions from various sources, including industrial facilities, vehicles, and other sources that contribute to air pollution.

The NAAQS is a set of regulations established by environmental agencies to protect public health and the environment by controlling air pollution. These standards are designed to regulate emissions from a wide range of sources. Industrial facilities, such as power plants, factories, and refineries, are one of the key sources targeted by the NAAQS.

Emissions from vehicles, including cars, trucks, and motorcycles, are also regulated to reduce pollution. Other sources such as construction sites, residential wood burning, and agricultural activities may also fall under the purview of the NAAQS. By regulating emissions from these sources, the NAAQS aims to maintain air quality standards and ensure the well-being of communities and the environment.

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Answer:

density because it S.I unit is derived from fundamentals

Answer:15.9994 g/mol

Explanation:

In 1.75 mol of methane (CH4) is 1.05 x 10^24 molecules of methane (CH4).

The number of molecules present in 1.75 mol of methane (CH4) is calculated in the following way:

In order to calculate the number of molecules of a substance in a given amount of the substance, Avogadro's constant is required.

Avogadro's constant, 6.022 x 10^23 particles per mole, represents the number of particles per mole of the substance, whether it is molecules or atoms.

To calculate the number of molecules in a given amount of substance, the quantity of moles is multiplied by Avogadro's constant.

Therefore, the number of molecules of methane in 1.75 moles of methane can be calculated as follows:

1.75 mol CH4 x (6.022 x 10^23 molecules/mol) = 1.0535 x 10^24 molecules of CH4

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The pressure inside the flask is 0.976 atm (rounded to the thousandth place).

We can use the Ideal Gas Law, which states:

PV = nRT

where:

P = pressure

V = volume

n = number of moles

R = gas constant

T = temperature

We can rearrange this equation to solve for the pressure:

P = nRT/V

We are given the volume V = 9.5 L, the number of moles n = 0.85 g / 32 g/mol (since O2 has a molar mass of 32 g/mol), and the temperature T = 25.80C = 298.95 K. The gas constant R is 0.08206 L atm / (mol K).

Substituting these values into the equation, we get:

P = (0.85 g / 32 g/mol) * (0.08206 L atm / (mol K)) * (298.95 K) / (9.5 L)

P = 0.976 atm

Therefore, the pressure inside the flask is 0.976 atm (rounded to the thousandth place).

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Answer:

OB. the nervous system

Explanation:

The Medulla Oblongata helps to regulate important functions such as heartbeat and breathing.

The reaction can be characterized as an equilibrium reaction.

In a chemical reaction, the difference between the initial Gibbs free energy (ΔG(initial)) and the final Gibbs free energy (ΔG(final)) provides information about the spontaneity and direction of the reaction. The Gibbs free energy is a thermodynamic property that indicates the maximum work that can be obtained from a system at constant temperature and pressure.

When the initial Gibbs free energy (ΔG(initial)) is equal to the final Gibbs free energy (ΔG(final)), it suggests that the reaction has reached a state of equilibrium. In an equilibrium reaction, the forward and reverse reactions occur at the same rate, resulting in no net change in the concentrations of the reactants and products over time. At equilibrium, the reaction is balanced, and the system is stable.

The fact that the initial and final Gibbs free energies are the same (ΔG(initial) = ΔG(final) = 593 kcal/mol) indicates that the reaction has reached equilibrium. This implies that the reaction has achieved a balance between the forward and reverse reactions, with no further net change in the concentrations of the reactants and products.

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Explanation:

Cyclopropane is a cycloalkane conposed of three carbon atoms to form a ring. It has a rols as an inhalation anaesthetic. It is a cycloalkane and a member of cyclopropanes.

Answer:

Alkane

Explanation:

True. The voltage generated by a cell at standard state conditions is called the standard cell potential.

The standard state conditions refer to a specific set of conditions, such as a specific temperature and concentration of reactants, at which the cell is at equilibrium. The standard cell potential is a measure of the cell's ability to do work, and it is measured relative to a reference electrode. It is a useful concept in electrochemistry and is used to calculate the potential difference (voltage) that can be generated by a cell when it is not at standard state conditions.  

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If reddish stains appear on plumbing fixtures, it is likely that the water contains an elevated concentration of iron. Iron is a common mineral found in the Earth's crust, and it can dissolve in water sources, especially if the water is acidic or has low oxygen content.

When the iron-containing water comes into contact with the plumbing fixtures, the iron compounds undergo oxidation reactions, leading to the formation of reddish-brown stains. Iron staining is a common issue in households with well water or older plumbing systems. The presence of iron in water not only affects the appearance of fixtures but can also result in metallic tastes and odors in drinking water. Furthermore, iron deposits can accumulate in pipes, reducing water flow and potentially causing plumbing problems.

To address iron staining, water treatment methods such as oxidation, filtration, or sequestration can be employed. These techniques aim to remove or prevent the formation of iron compounds, improving the quality and aesthetics of the water. Regular maintenance of plumbing systems and periodic testing of water quality can help identify and address iron-related issues effectively.

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If the temperature inside the space is set higher than the cold level outside, the air conditioning (AC) system will not kick on.

If the temperature inside the space is set higher than the cold level outside, the air conditioning (AC) system will not kick on. The AC system is designed to cool the indoor space by removing heat from the air and lowering the temperature to the desired level. If the temperature setting on the AC is higher than the current temperature outside, it means that the desired indoor temperature is already higher than the ambient temperature. In this case, the AC system does not need to run as there is no need for cooling. The AC will only activate when the indoor temperature exceeds the set temperature and needs to be cooled to maintain the desired comfort level.

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The mass of oxygen gas in the unknown mixture is approximately 5.868 g. The mass of ethane gas in the unknown mixture is approximately 0.812 g. The mass percent of oxygen gas in the unknown mixture is approximately 71.83%.

To solve this problem, we need to determine the masses of oxygen gas and ethane gas in the unknown mixture, as well as the mass percent of oxygen gas.

Let's start by calculating the mass of water produced;

Mass of water = 1.48 g

Since water is composed of hydrogen and oxygen in a 2:1 ratio, the molar mass of water is:

Molar mass of water = 2(1.00784 g/mol) + 15.999 g/mol = 18.015 g/mol

Now we can calculate the number of moles of water produced;

Number of moles of water = Mass of water/Molar mass of water

= 1.48 g / 18.015 g/mol

≈ 0.082 mol

From balanced chemical equation for the combustion of ethane;

C₂H₆ + 7/2 O₂ → 2 CO₂ + 3 H₂O

We can see that 1 mole of ethane produces 3 moles of water. Therefore, the number of moles of ethane can be calculated as;

Number of moles of ethane = (Number of moles of water) / 3

≈ 0.082 mol / 3

≈ 0.027 mol

The molar mass of ethane (C₂H₆) is;

Molar mass of ethane = 2(12.011 g/mol) + 6(1.00784 g/mol)

= 30.0708 g/mol

Finally, we can calculate the mass of ethane;

Mass of ethane = Number of moles of ethane × Molar mass of ethane

≈ 0.027 mol × 30.0708 g/mol

≈ 0.812 g

Now, to determine the mass of oxygen gas, we subtract the mass of ethane and water from the total mass of the unknown mixture:

Mass of oxygen gas = Total mass of unknown mixture - Mass of ethane - Mass of water

= 8.16 g - 0.812 g - 1.48 g

≈ 5.868 g

Finally, we can calculate the mass percent of oxygen gas in the unknown mixture;

Mass percent of oxygen gas = (Mass of oxygen gas / Total mass of unknown mixture) × 100%

= (5.868 g / 8.16 g) × 100%

≈ 71.83%

Therefore;

The mass of oxygen gas in the unknown mixture is approximately 5.868 g.

The mass of ethane gas in the unknown mixture is approximately 0.812 g.

The mass percent of oxygen gas in the unknown mixture is approximately 71.83%.

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