be sure to answer all parts. describe the hybrid orbitals used by the central atom(s) and the type(s) of bonds formed in so2.

A compound is defined as two or more different elements bonded together in an ionic or covalent bonding arrangement.  Any individual compound has a fixed ratio of its elements.  The elements do not retain their individual chemical properties.  Thus, option "C" is correct.

A substance that has two or more different atoms which are chemically combined with each other in a fixed ratio by mass is known as a compound.

For example,

Here,  contains one atom of calcium and two atoms of chlorine which are chemically combined together in 1:2 ratio. Therefore, it is a compound.

Also, both chemical and physical properties of will be different from Ca and chloride.

Thus, option "C" is correct.

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Answer:

Atomic emission is more sensitive to flame instability than atomic absorption because during atomic emission, the intensity of the emitted light is proportional to the concentration of the element being measured. If the flame is unstable, it can cause fluctuations in the intensity of the light being emitted, which can lead to errors in the measurement of the element's concentration. In contrast, in atomic absorption, the intensity of the absorbed light is measured, which is less sensitive to flame instability since the amount of light absorbed by the element is proportional to its concentration regardless of the flame's stability.

Answer:

Atomic emission is more sensitive to flame instability than atomic absorption because atomic emission is based on the analysis of light emitted from excited atoms in the flame. In contrast, atomic absorption is based on light absorption by the flame's particles.

Flame instability can lead to changes in the temperature and pressure of the flame, which can affect the excited states of the atoms in the flame. When the flame is unstable, it can cause fluctuations in the number of excited atoms and the length of time they stay excited. This, in turn, can lead to fluctuations in the amount of light emitted by the excited atoms, making it more difficult to accurately measure the analyte concentrations in the sample using atomic emission spectroscopy.

On the other hand, atomic absorption spectroscopy is less sensitive to flame instability because the light absorption by the atoms in the flame is not as dependent on the excitation states of the atoms. The atoms in the flame absorb light at specific wavelengths regardless of their excited states. Hence, fluctuations in the excited state populations have less of an impact on the absorption signal. However, atomic absorption spectroscopy can still be affected by other factors, such as changes in the temperature and pressure of the flame and the presence of other interfering species in the sample.

Answer:

Hey there!

10000 gallons would be 37.85 cubic meters.

Let me know if this helps :)

Answer: 37.8501 m³

Explanation:

 10000.0 gal × 1 m³/264.2 gal

=37.8501 m³ (significant digits)

Answer:

Explanation:

Answer:

Idon't know if this helps but I think it is a linear structure and if I am wrong I am so sorry

Answer:

The southern hemisphere is currently experiencing "Summer"

Explanation:

The Southern hemisphere is experiencing summer because it is closer to the sun than the Northern Hemisphere and also, direct light is more hotter than indirect light.

So, first, let's try an EXPERIMENT!

Take a VERY bright flashlight or a very small laser that can't harm you or just burn a paper in 1 second.

Then, take a piece of paper, or maybe just your skin, (like your hand) and place it under the light or laser, (for the laser, you should probably take the paper), and place the light source right above your skin, then, after some time, when it gets hot, measure the temperature. (around like 30 seconds later),

Note down the temperature...

Now, do the same thing, accept, do it in a very weird angle, face it towards your paper or hand, but, do it in an angle. More than like 30 degrees. Then, after some time, note down the temperature.

You probably, noticed, that the direct light (the one with the straight light facing your paper or skin, was hotter). Look at the image below, and you can understand better.

So, the same thing applies to the earth. The southern hemisphere in this picture is facing more directly to the sun than the northern hemisphere. That is why your answer is

Thank you! Please mark me Brianliest!

Remember to have fun, and a nice day!

Answer:   summer

Explanation:

The learning activities titled "Hypothesis," "Variables and Hypothesis," and "Constructing a Hypothesis" all share certain similarities and differences. A question that arises in response to an observation is similar to a scientific research question in that both require some level of investigation to achieve an answer. However, scientific research questions are typically more specific and refined, with a defined methodology for obtaining data and verifying results.

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There are different ways to write an essay. The essay on the things that caused the Cuban Missile Crisis  is given below.

An American U-2 spy plane secretly captured images of Soviet nuclear missile construction locations on the island of Cuba in October 1962. Kennedy did not want the Soviet Union and Cuba to learn that the missiles had been found. He spent several days having covert meetings with his advisers to talk about the issue.

The deployment of Jupiter missiles in Turkey (and, to a lesser extent, Italy) was a crucial factor in both starting the Cuban Missile Crisis—Soviet Premier Nikita Khrushchev viewed them as a "bone" in his throat—and the covert Kennedy-Khrushchev deal that ended the crisis.

The "Tsar Bomba," a 58-megaton atmospheric nuclear weapon, detonates above Novaya Zemlya, becoming the most powerful bomb ever detonated.

Kennedy finally gave the go-ahead for a brigade of exiled Cubans to invade the island nation after much disagreement inside his cabinet. On April 17, 1961, the brigade reached the Bay of Pigs shoreline, but the mission failed spectacularly within two days.

Lastly, Castro wrote Soviet leader Nikita Krushchev, pleading with him to use the missiles and, if necessary, to sacrifice Cuba as the tensions of the Missile Crisis increased. Unbeknownst to Castro, Khrushchev had already agreed to withdraw the missiles from Cuba with President John F. Kennedy without telling Castro.

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(a) The optical transition in the He+ spectrum that has the same wavelength as the first Lyman transition of hydrogen is from the n=3 to n=2 energy level. (b)  The second ionization energy of helium (He) is -54.4 eV. (c)  The radius of the first Bohr orbit for He+ is approximately 0.2645 angstroms.

(a) To find the optical transition in the He+ spectrum with the same wavelength as the first Lyman transition of hydrogen (n=2 to n=1), we need to consider the energy levels of both systems.

The energy of an electron in the nth energy level of hydrogen is given by the formula: E = -13.6/n^2 electron volts (eV).

For the Lyman transition, we have n1=2 and n2=1, so the energy difference is:

ΔE_H = E_2 - E_1 = -13.6(1/1^2 - 1/2^2) = -10.2 eV.

Now, for He+, the energy levels are determined by the nuclear charge Z=2 instead of Z=1 for hydrogen. The energy levels in He+ are given by the formula: E = -13.6Z^2/n^2 eV.

For the optical transition with the same wavelength as the Lyman transition, we need to find the value of n for which the energy difference matches ΔE_H.

Setting the energy difference equal to ΔE_H, we have:

-13.6(2^2/n^2) = -10.2.

Solving this equation gives us n^2 = 8, so n = √8 = 2.83.

The optical transition in the He+ spectrum that has the same wavelength as the first Lyman transition of hydrogen is from the n=3 to n=2 energy level.

(b) The second ionization energy of He+ refers to the energy required to remove the second electron from the He+ ion. Since He+ already has only one electron, removing it will result in a neutral helium atom. The second ionization energy of He+ is the same as the ionization energy of neutral helium.

The ionization energy of neutral helium can be calculated using the formula:

\(\(\hat{v} = \frac{{-13.6Z^2}}{{n^2}}\)\), where Z is the nuclear charge (2 for helium) and n is the principal quantum number of the electron in the initial energy level.

To find the second ionization energy, we need to remove the second electron from neutral helium, which is in the n=1 energy level. Plugging in the values, we get:

\(\(\hat{v} = \frac{{-13.6 \times 2^2}}{{1^2}} = -54.4 \, \text{eV}\).\)

(c) The radius of the first Bohr orbit for He+ can be calculated using the Bohr radius formula:

r =\(\(\frac{{0.529 \times n^2}}{{Z}}\)\) angstroms.

For He+, Z = 2 and we need to consider the n = 1 orbit. Plugging in the values, we have:

r =\(\(\frac{{0.529 \times 1^2}}{{2}} = 0.2645\)\) angstroms.

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Answer:

okay I will help you just message me johnpatrick on messenger

Answer:

To calculate the number of moles of copper, we first need to determine the mass of copper present in the sample:

Mass of copper = 159 g (mass of copper(II) oxide) - 127 g (mass of copper)

Mass of copper = 32 g

Now, we can use the molar mass of copper to calculate the number of moles:

Molar mass of copper = 63.55 g/mol

Number of moles of copper = mass of copper / molar mass of copper

Number of moles of copper = 32 g / 63.55 g/mol

Number of moles of copper = 0.504 mol

Therefore, there are 0.504 moles of copper in the sample.

Explanation:

Answer:

B.Cu

Explanation:

n the reaction H2 is oxdized since it has lost electrons and Cu is reduced since it has gained electrons

The enthalpy change (ΔH) for the reaction CaC(s) + H2O(I) → Ca(OH)(ag) + CH4(g) is -3617.6 kJ.

To calculate ΔH for the reaction CaC(s) + H2O(l) → Ca(OH)2(ag) + CH4(g), we can use Hess's law, which states that the enthalpy change of a reaction is independent of the pathway taken and depends only on the initial and final states.

We can manipulate the given reactions to obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X (unknown value)

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's manipulate these equations to cancel out the common reactants and products and obtain the desired reaction:

(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) Ca(s) + 1/2O2(g) → CaO(s) ΔH = -635.5 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

Now, let's sum up the equations to obtain the desired reaction:(i) Ca(s) + 2C(graphite) → CaC2(s) ΔH = X

(ii) 2Ca(s) + O2(g) → 2CaO(s) ΔH = -1271 kJ

(iii) CaO(s) + H2O(l) → Ca(OH)2(ag) ΔH = -653.1 kJ

(iv) CH4(g) + 2O2(g) → CO2(g) + 2H2O(l) ΔH = -1300.0 kJ

(v) C(graphite) + 1/2O2(g) → CO(g) ΔH = -393.5 kJ

By adding equations (ii), (iii), (iv), and (v), we can cancel out CaO(s), H2O(l), and O2(g):

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -1271 -653.1 -1300.0 -393.5

2Ca(s) + 2C(graphite) + CH4(g) → 2Ca(OH)2(ag) + CO(g) ΔH = X -3617.6 kJ

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Answer:

A salt is a neutral ionic compound. Let's see how a neutralization reaction produces both water and a salt, using as an example the reaction between solutions of hydrochloric acid and sodium hydroxide. The overall equation for this reaction is: NaOH + HCI → H2O and NaCl.

Explanation:

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\(\\ \orange{MaggieEve}\)

Answer: c

Explanation:

The squirrel eats the grass, making it a primary consumer. Then, the squirrel is consumed by only one animal: the hawk.

Considering the definition of equilibrium constant, the equilibrium molar the symbolic expression for the equilibrium constant is  (\([CO_{2} ]^{4}\)×\([H_{2} O]^{6}\))÷ (\([C_{2}H_{6} ]^{2}\)×\([O_{2} ]^{7}\))

Equilibrium is a state of a reactant system in which no changes are observed as time passes, despite the fact that the substances present continue to react with each other.

The concentration of reactants and products at equilibrium is related by the equilibrium constant Kc. Its value in a chemical reaction depends on the temperature and the expression of a reaction aA + bB ⇄ cC + dD is

Kc= (\([C]^{c}\)×\([D]^{d}\))÷ (\([A]^{a}\)×\([B]^{b}\))

That is, the constant Kc is equal to the multiplication of the concentrations of the products raised to their stoichiometric coefficients by the multiplication of the concentrations of the reactants also raised to their stoichiometric coefficients.

The balanced reaction is:

2 C₂H₆(g) + 7 O₂(g) ⇆ 4 CO₂(g) + 6 H₂O(g)

The constant Kc can be expressed as:

Kc= (\([CO_{2} ]^{4}\)×\([H_{2} O]^{6}\))÷ (\([C_{2}H_{6} ]^{2}\)×\([O_{2} ]^{7}\))

Finally, the equilibrium molar concentration is  (\([CO_{2} ]^{4}\)×\([H_{2} O]^{6}\))÷ (\([C_{2}H_{6} ]^{2}\)×\([O_{2} ]^{7}\))

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Answer:

C. The amount of natural gas consumed in the U.S. will remain constant even if the population size changes.

Answer:

Explanation:

d =

m

V

m = d×V

V =

m

d

DENSITY

Density is defined as mass per unit volume.

d =

m

V

Example:

A brick of salt measuring 10.0 cm x 10.0 cm x 2.00 cm has a mass of 433 g. What is its density?

Step 1: Calculate the volume

V = lwh = 10.0 cm × 10.0 cm × 2.00 cm = 200 cm³

Step 2: Calculate the density

d =

m

V

=

433

g

200

c

m

³

= 2.16 g/cm³

MASS

d =

m

V

We can rearrange this to get the expression for the mass.

m = d×V

Example:

If 500 mL of a liquid has a density of 1.11 g/mL, what is its mass?

m = d×V = 500 mL ×

1.11

g

1

m

L

= 555 g

VOLUME

d =

m

V

We can rearrange this to get the expression for the volume.

V =

m

d

Example:

What is the volume of a bar of gold that has a mass of 14.83 kg. The density of gold is 19.32 g/cm³.

Step 1: Convert kilograms to grams.

14.83 kg ×

1000

g

1

k

g

= 14 830 g

Step 2: Calculate the volume.

V =

m

d

= 14 830 g ×

1

c

m

³

19.32

g

= 767.6 cm³

The mass of rock is 10 g.

We have sample of rock.

We have to determine its mass.

The density and mass of body are related as follows -

D = M / V

where -

V -  volume of the body.

M - mass of the body.

D - density of the body.

According to the question →

Using the formula discussed above -

D = M / V

M = D x V

M = 2.5 x 4 = 10 g

Hence, the mass of rock is 10 g

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Answer:

Explanation:

Here, we want to get what will happen when an Atthenius base interacts with water

By definition, an Arrhenius base increases the concentration of hydroxide ions in aqueous solutions

What this simply mean is that when an Arrhenius base comes in contact with water, the solution is expected to have an increase in the concentration of hydroxide ion. This can be measures pH wise and we expect an increase in the pH of the solution from 7

Answer:

1) 9 moles

2) 8.75 moles

3) 1.76 moles

4) 10.2 moles

Explanation:

Okay so mole ratio is 2:1

So, 9 moles of HI is required for 4.5 moles of Iodine gas

Mol ratio of water to CaCl2 is 2:1

So, 17.5 moles of water produced is (17.5/2) moles of CaCl2 i.e. 8.75 moles

Okay so mol ratio of Hydrogen to NH3 is 3:2

So, 2.64 moles of hydrogen is (2.64 * 2)/3 moles of NH3 i.e. 1.76 moles

Once again, mol ratio of Hydrogen to NH3 is 3:2

When 15.3 moles of hydrogen is used, (15.3 * 2)/3 moles of NH3 i.e. 10.2 moles

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Answer:

If n = 4, then the possible values of 1 and m depend on the equation or expression being used. Without more information, it is impossible to determine what the possible values of 1 and m might be. Can you please provide more context or information about the problem you are trying to solve?

The current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

To calculate the current in amperes, we need to use Faraday's laws of electrolysis and the stoichiometry of the reaction.

Faraday's laws state that the amount of substance produced or consumed during electrolysis is directly proportional to the quantity of electricity passed through the cell. The relationship is given by:

Q = nF

Where Q is the electric charge in coulombs (C), n is the number of moles of substance involved in the reaction, and F is Faraday's constant, which is equal to 96,485 C/mol.

In this case, the substance being produced is Cl2, and we know the mass of Cl2 produced, which is 4.8 x 10^5 g.

First, we need to calculate the number of moles of Cl2 produced:

Molar mass of Cl2 = 35.45 g/mol

Moles of Cl2 = mass / molar mass = (4.8 x 10^5 g) / (35.45 g/mol) ≈ 1.354 x 10^4 mol

Now we can calculate the quantity of electricity passed through the cell using Faraday's laws:

Q = nF

Q = (\(1.354 x 10^4\)mol) * (96,485 C/mol)

Q ≈ 1.308 x 10^9 C

The quantity of electricity is given in coulombs. To find the current, we need to divide this value by the time in seconds.

Given that the time is 18 hours, we convert it to seconds:

Time = 18 hours * 60 minutes/hour * 60 seconds/minute

Time = 6.48 x 10^4 seconds

Finally, we can calculate the current:

Current (I) = Q / Time

I = (1.308 x 10^9 C) / (6.48 x 10^4 s)

I ≈ 2.02 x 10^4 Amperes

Therefore, the current passing through the electrolytic cell is approximately 2.02 x 10^4 Amperes.

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0.595 moles of water can be made at 112.6 grams of \(HNO_{3}\) are consumed

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we use the equation's stoichiometry and molar masses.

To determine the number of moles of water produced when 112.6 grams of \(HNO_{3}\) are consumed, we need to use the molar mass of \(HNO_{3}\) and the stoichiometric coefficients of the balanced chemical equation.

The molar mass of \(HNO_{3}\) is calculated as follows:

1 mole of hydrogen (H) = 1 g/mol

1 mole of nitrogen (N) = 14 g/mol

3 moles of oxygen (O) = 3 × 16 g/mol = 48 g/mol

Adding these together, the molar mass of \(HNO_{3}\) is 1 + 14 + 48 = 63 g/mol.

Now, we can set up a conversion factor using the stoichiometry of the balanced equation:

From the equation: 5 + 6 \(HNO_{3}\) -> \(H_{2}SO_{4}\) + 6 \(NO_{2}\) + 2 \(H_{2}O\)

From the coefficients: 6 moles of \(HNO_{3}\) produce 2 moles of \(H_{2}O\)

To find the moles of water produced, we use the following calculation:

112.6 g \(HNO_{3}\) × (1 mol \(H_{2}O\) / 63 g \(HNO_{3}\)) × (2 mol \(H_{2}O\) / 6 mol \(HNO_{3}\)) = 0.595 mol \(H_{2}O\)

Therefore, when 112.6 grams of \(HNO_{3}\) are consumed, approximately 0.595 moles of water can be produced according to the given balanced equation and molar masses.

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Two key criteria that engineers must prioritize are efficiency and safety. By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

When developing a process, engineers need to consider several important criteria. Two key criteria that engineers must prioritize are efficiency and safety.

Efficiency is crucial in process development to ensure optimal use of resources, time, and energy. Engineers strive to design processes that maximize productivity, minimize waste, and reduce costs. This involves optimizing reaction conditions, streamlining workflow, and implementing automation where possible. Efficiency considerations also extend to energy consumption, raw material utilization, and overall process sustainability.

Safety is another critical aspect that engineers must prioritize. They need to identify and mitigate potential hazards associated with the process, ensuring the safety of both personnel and the environment. This involves conducting thorough risk assessments, implementing safety protocols, and designing equipment and systems with safety features. Engineers must also consider the safe handling and storage of materials, as well as potential risks during transportation and disposal.

By emphasizing efficiency and safety during process development, engineers can create robust and reliable processes that not only maximize productivity but also prioritize the well-being of personnel and the environment.

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Answer:

\(pH = - log(7.6 \times {10}^{ - 5} ) \\ pH = 4.12\)

Answer:

ok, here is your answer

Explanation:

AI-generated answer

To find the mass of oxygen that reacted, we need to use the Law of Conservation of Mass, which states that in a chemical reaction, the mass of the reactants equals the mass of the products.

First, we need to find the number of moles of hydrogen that reacted:

Molar mass of hydrogen (H₂) = 2.016 g/mol

Number of moles of H₂ = mass/molar mass = 46.2 g/2.016 g/mol = 22.92 mol

Next, we need to use the balanced chemical equation to find the number of moles of water produced:

hydrogen + oxygen → water

2H₂ + O₂ → 2H₂O

From the equation, we can see that for every 2 moles of H₂, 1 mole of O₂ is required to produce 2 moles of H₂O. Therefore, the number of moles of O₂ required to produce 22.92 moles of H₂O is:

Number of moles of O₂ = 1/2 x 22.92 mol = 11.46 mol

Finally, we can find the mass of oxygen that reacted by using its molar mass:

Molar mass of oxygen (O₂) = 32.00 g/mol

Mass of oxygen = number of moles x molar mass = 11.46 mol x 32.00 g/mol = 366.72 g

Therefore, the mass of oxygen that reacted is 366.72 g.

After the reaction is complete, no nitrogen and no hydrogen molecules remain, and 8.00 x 1014 molecules of NH3 are produced.

In the equation, nitrogen and hydrogen react at a high temperature, in the presence of a catalyst, to produce ammonia, according to the balanced chemical equation:N2(g)+3H2(g)⟶2NH3(g)The coefficients of each molecule suggest that one molecule of nitrogen reacts with three molecules of hydrogen to create two molecules of ammonia.

So, to determine how many molecules of ammonia are produced when four nitrogen and nine hydrogen molecules are present, we must first determine which of the two reactants is the limiting reactant.

To find the limiting reactant, the number of moles of each reactant present in the equation must be determined.

Calculations:
Nitrogen (N2) molecules = 4Hence, the number of moles of N2 = 4/6.02 x 1023 mol-1 = 6.64 x 10-24 mol
Hydrogen (H2) molecules = 9Hence, the number of moles of H2 = 9/6.02 x 1023 mol-1 = 1.50 x 10-23 mol

Now we have to calculate the number of moles of NH3 produced when the number of moles of nitrogen and hydrogen are known, i.e., mole ratio of N2 and H2 is 1:3.

The mole ratio of N2 to NH3 is 1:2; thus, for every 1 mole of N2 consumed, 2 moles of NH3 are produced.
The mole ratio of H2 to NH3 is 3:2; thus, for every 3 moles of H2 consumed, 2 moles of NH3 are produced.
From these mole ratios, it can be observed that the limiting reactant is nitrogen.

Calculation for NH3 production:
Nitrogen (N2) moles = 6.64 x 10-24 moles
The mole ratio of N2 to NH3 is 1:2; therefore, moles of NH3 produced is 2 × 6.64 × 10−24 = 1.33 × 10−23 moles.

Now, to determine how many molecules of NH3 are produced, we need to convert moles to molecules.
1 mole = 6.02 x 1023 molecules
Thus, 1.33 x 10-23 moles of NH3 = 8.00 x 1014 molecules of NH3 produced.

To find the amount of each reactant remaining after the reaction is complete, we must first determine how many moles of nitrogen are consumed, then how many moles of hydrogen are consumed, and then subtract these from the initial number of moles of each reactant.

The moles of nitrogen consumed = 4 moles × 1 mole/1 mole N2 × 2 mole NH3/1 mole N2 = 8 moles NH3
The moles of hydrogen consumed = 9 moles × 2 mole NH3/3 mole H2 × 2 mole NH3/1 mole N2 = 4 moles NH3
Thus, the moles of nitrogen remaining = 6.64 × 10−24 mol – 8 × 2/3 × 6.02 × 10^23 mol-1 = 5.06 × 10−24 mol
The moles of hydrogen remaining = 1.50 × 10−23 mol – 4 × 2/3 × 6.02 × 10^23 mol-1 = 8.77 × 10−24 mol

Finally, the number of molecules of each reactant remaining can be calculated as follows:
Number of N2 molecules remaining = 5.06 × 10−24 mol × 6.02 × 10^23 molecules/mol = 3.05 × 10−1 molecules ≈ 0 molecules
Number of H2 molecules remaining = 8.77 × 10−24 mol × 6.02 × 10^23 molecules/mol = 5.28 × 10−1 molecules ≈ 0 molecules.

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The complete equation for the neutralization reactions for the LiOH + HNO₂ is as :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

The Neutralization reaction is the reaction as in the chemical reaction in which the acid will reacts with the base and to produce the salt and the water molecule. The general equation of the chemical reaction is as :

HX  +  BOH  -->  BX  + H₂O

The reaction with the LiOH and the HNO₂ is :

LiOH  +  HNO₂ ---->  LiNO₂  +  H₂O

There is the combination of the H⁺ ions and OH⁻ ions that will form the water.

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