An electron moved from a lower energy level to a higher energy level, and during the transition, a random amount of light was released. Option A
What exactly are these electrons?
An electron is a kind of subatomic particle that has a negative charge. It is possible for it to be free (meaning that it is not associated with the nucleus of any atom) or it may be tied to the nucleus of an atom.
Electrons are sub-atomic particles that may be found in each atom of any chemical element and can occupy different energy levels. These electrons are capable of transitioning between different energy levels.
Electrons may transition from a state with a lower energy level, also known as the ground state, to a state with a higher energy level, also known as an excited state. Alternatively, electrons can transition from a state with a higher energy level to a state with a lower energy level.
When an electron goes from a lower energy level to a higher energy level, the atom takes in more energy, but when the electron moves from a higher energy level to a lower energy level, the additional energy is expelled mostly in the form of light.
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if a car travels 1255 miles how many kilometers is that i mile = 1.609km
Answer:
2,019 km
Explanation:
Step 1: Given data
Distance traveled by the car (D): 1,255 mi
Step 2: Convert the distance traveled by the car to kilometers
To convert one unit into another, we use a conversion factor. In this case, the appropriate conversion factor between miles and kilometers is 1 mile = 1.609 km. The distance traveled by the car, in kilometers, is:
D = 1,255 mi × (1.609 km/1 mi) = 2,019 km
Describe how the thermal energy moves when a can of soda is taken out of the refrigerator and left on a counter for hours.
Course Activity: Oxidizing and Reducing Chemicals (CHEMISTRY EDMENTUM)
TASK 2 PART C:
-Compare the mass of the zinc strip from test tube 5 with the mass of the same strip measured in task 1, part A. Based on your observations of the metal strip, explain what factors may have added to its mass or caused a decrease in its mass. Which had the greater effect? Explain your reasoning.
PLEASEE GIVE A GOOD RESPONSE I'M SO LOST
The electrolytic reaction between Zn and Ag results in the oxidation of Zn and reduction silver metal. The oxidation of Zn make the Zn ions pass into the solution and its mass decreases.
What is electrochemical reaction ?An electrochemical cell converts chemical energy to electrical energy. It involves redox reaction of two metallic electrodes. The electrode with higher negative electrode potential undergo oxidation and one with lower negative or having positive potential undergoes reduction.
The electrode which undergo oxidation is consumed in the process and metal gets ionized. Ions move into the electrolyte. Whereas, the ions of the second electrode gets reduced into metallic state and deposits on the electrode.
In this case, Zn is oxidizing and it is consumed to reduce the silver metal on the cathode. Therefore, the mass of Zn metal decreases in the strip.
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An error during which cellular process would create a gene mutation?
An error during DNA replication would create a gene mutation.
During DNA replication, the genetic information in a cell is copied to make new DNA molecules. However, mistakes can occur during this process, leading to changes in the DNA sequence, which can result in a mutation. Mutations can also be caused by exposure to environmental factors, such as radiation or chemicals, which can damage the DNA molecule directly or affect the cellular processes involved in DNA replication.
Mutations can have a variety of effects on the organism, ranging from no effect to causing serious health problems or even death. Gene mutations can also be inherited from a parent, which can result in genetic disorders or predisposition to certain diseases. Therefore, it is important to understand the mechanisms of gene mutations and their potential impacts on organisms.
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Please help with all 4 questions will give brain!
12996 torr, which is the atmospheric pressure.
How much pressure do you have in a torr of air?One atmosphere is the standard unit for measuring atmospheric pressure. 1 atm equates to 14.6956 psi or 760 torr. One atmosphere of pressure will force the mercury (Hg) column in a mercury barometer to a height of 760 millimeters, according to the original Torricelli barometer design.
How much atmospheric pressure is typical?By definition, a standard atmosphere is equal to one atmosphere at sea level, which is equivalent to 101.325 kilopascals, 760 mm (29.92 inches) of mercury, 14.70 pounds per square inch, 1,013.25 millibars, and 1,013.25 103 dynes per square centimeter.
1atm = 760torr
17.1atm × 760torr= 12996torr
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volume reading
final: 28.5 mL
start: 7.5 mL
Total Volume: 21 mL
What is the Molarity of vinegar?
Based off the work information provided
The molarity of vinegar is 0.47368421 moles per liter.
To calculate this, we can use the following formula:
molarity = (initial_volume - total_volume_change) / final_volume
In this case, the initial volume is 7.5 mL, the total volume change is 21 mL, and the final volume is 28.5 mL. Plugging these values into the formula, we get:
molarity = (7.5 - 21) / 28.5 = -0.47368421
The negative value for molarity indicates that the solution is diluted. This is because the total volume of the solution increased by 21 mL, while the amount of solute (acetic acid) remained the same.
It is important to note that the molarity of a solution can change depending on the temperature. This is because the volume of a solution expands as it gets warmer. Therefore, it is important to measure the volume and temperature of a solution at the same time to get an accurate measurement of its molarity.
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Give the ligand name of cupper in a complex anion
The ligand name of copper in a complex anion depends on the specific complex. For example, in the complex anion [CuCl4]2-, the ligand is chloride. In [Cu(NH3)4(H2O)2]2+, the ligands are ammonia and water.
What are anions?Complex anions are negatively charged ions that contain one or more central metal ions surrounded by a group of ligands. These ligands are usually neutral molecules or anions that coordinate to the metal ion through a coordination bond.
Anions are negatively charged ions that have gained one or more electrons compared to their neutral state. They are formed when atoms or molecules gain electrons, typically by accepting an electron from another atom or molecule with a lower electronegativity. Examples of anions include chloride (Cl-), sulfate (SO42-), and nitrate (NO3-).
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How many years are there in 1.10 s?
Express your answer using three significant figures.?
Answer:
Below
Explanation:
Number of seconds in one year
3600 s/hr * 24hr/day * 365.25 day/yr = 31 557 600 s/yr
1.10 s / 31 557 600 s/yr = 3.49 x 10^-8 yr
A certain chemical reaction telesales 24.7 kk/g of heat for each gram of reactant consumed
The mass of reactant that would produce 800 Joules of heat is equal to 800 J × (1 kJ/1000 J)/(24.7 kJ/g).
How to calculate the mass of reactant?In order to determine the mass of reactant that would produce 800 Joules of heat, we would set up a conversion equation as follows:
Note: 1 kJ is equal to 1000 Joules.
Conversion:
1 gram = 24.7 kJ
X gram = 800 Joules
Therefore, the mass of reactant that would produce 800 Joules of heat is given by:
Mass = Heat × (conversion factor/rate of heat)
Mass = 800 J × (1 kJ/1000 J)/(24.7 kJ/g).
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Complete Question:
A certain chemical reaction releases 24.7 kJ/g of heat for each gram of reactant consumed. How can you calculate what mass of reactant will produce 800 Joules of heat?
Which of the following is the best description of the music Mussorgsky wrote to accompany the Gnome?
A. Bright, upbeat, lively
B. Major key, legato, fermatas
C. Dark, choppy, dynamic contrasts
D. Long flowing phrases
Dark, choppy, dynamic contrasts the following is the best description of the music Mussorgsky wrote to accompany the Gnome.
The composer Modest Mussorgsky is known for creating unique Russian music such as Night on Bald Mountain Pictures at an Exhibition, and the opera Boris Godunov. Mussorgsky is famous for his operas and songs. He discovered a new spelling of the voice that is highly melodic and yet also corresponds to the Russian language. His most famous opera is Boris Godunov.
He wrote the overture Night on the Mountain. Modest Petrovich Mussorgsky 1839-1881 was one of five Russian composers known as the Mighty Fists for their nationalist tendencies. Mussorgsky was one of music's greatest originals. Everything he composed was conceived in relation to the natural rhythms, melodies, and harmonies of Slavic folk music. Art songs by contrast are intended for performance by professional singers or at least carefully trained singers usually accompanied by a piano or instrumental ensemble.
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If 5.0 mL of 0.10 M NaOH is added to 50. mL of 0.10 M HCI, what will be the resulting
pH of the solution?
Round your answer to two decimal places.
Provide your answer below:
PH
Answer:
1.09
Explanation:
Keep in mind that the volume of the solution changes during this titration, so to compute the amount of hydronium that is neutralized during this addition of base (in order to calculate the final pH of the solution), we must calculate the moles of all species in solution initially present. Because both NaOH and HCl ionize completely:initial mol OH−=mol NaOH=(0.0050 L)(0.10 molL)=0.00050 mol OH−initial mol H3O+=mol HCl=(0.050 L)(0.10 molL)=0.0050 mol H3O+The acid is in excess, so all of the OH− present will neutralize an equivalent amount of H3O+, forming water. Thus we simply subtract the moles of hydroxide from the moles of hydronium in solution to find the resultant moles of H3O+ after this neutralization:final mol H3O+= initial mol H3O+−initial mol OH−final mol H3O+=0.0050 mol−0.00050 mol=0.0045 mol H3O+We now calculate the total volume of the solution by adding the volumes of acid and base initially combined: 0.050 L+0.0050 L=0.055 LTo get [H3O+], we divide the final moles of hydronium by the final solution volume:[H3O+]=final mol H3O+ total volume=0.0045 mol0.055 L≈0.08181molLFinally, to find pH:pH=−log[H3O+]=−log(0.08181)=1.09Since the hydronium concentration is only precise to two significant figures, the logarithm should be rounded to two decimal places.
PLEASE ANSWER!!!!!!!!
Scientists observe the polyatomic ion nitrate forming a compound with unknown element 'A' and predict that the chemical formula could be A2NO3. One of the scientists, Nadeen, states that this chemical formula would be impossible. Is Nadeen correct? Explain why or why not.
Answer:
knflnvwlknnffenfkw
Explanation:
Why are marine mammals so important
A compound composed of only carbon and hydrogen is 25.2% hydrogen by mass. The empirical formula for this compound is ?
Answer:
Since the compound contains 25.2% Hydrogen by mass and the compound is made of only carbon and hydrogen
Mass% of carbon = 100 - (mass% of hydrogen)
Mass% of carbon = 100 - 25.2
Mass% of carbon = 74.8%
Mass of each element in a given sample:
Let us take a 100 g sample of this compound
Since there is 25.2% hydrogen by mass, there is 25.2g hydrogen for every 100g of the compound
Similarly, there is 74.8 g carbon for every 100g of the compound
So, in a 100g sample:
Mass of Hydrogen = 25.2 grams
Mass of Carbon = 74.8 grams
Number of moles of each element in the 100g sample:
Moles of Carbon:
Molar mass of carbon = 12 g/mol
Number of moles = Given mass / molar mass
Number of moles = 74.8 grams / 12 g/mol
Moles of Carbon = 6.24 moles
Moles of Hydrogen:
Molar mass of Hydrogen = 1 g/mol
Number of moles = given mass / molar mass
Moles of Hydrogen = 25.2 / 1
Moles of Hydrogen = 25.2 moles
Empirical Formula:
The empirical formula of a compound is the simplest whole number ratio of the number of moles of the elements in the compound
Empirical formula = Moles of Carbon : Moles of Hydrogen
Empirical formula = 6.24 / 25.2
Since we need a whole number ratio, and these numbers don't simplify to be whole numbers. we will multiply both of them with a common number which will make them both whole
Multiplying both the numbers by 25 makes them whole
Empirical formula = 6.24 * 25 / 25.2 (25)
Empirical formula = 156 / 630
further simplifying the numbers, we can divide them both by 2
Empirical formula = 78 / 315
dividing these numbers by 3
Empirical formula = 16 / 105
Therefore, the ratios of the moles of carbon to the moles of Hydrogen in the empirical formula is: 16 : 105
Empirical formula = C16H105
How many moles of NaCl are there in 40.3 g of sodium chloride?
Please answer all the questions in the picture below
Thank you
Answer:
58.44277 gram
Explanation:
What is the energy of a photon of electromagnetic radiation with a wavelength of 963.5 nm? (c = 3.00 × 108 m/s, h = 6.63 × 10–34 J · s
Answer:
\(E=2.06\times 10^{-19}\ J\)
Explanation:
Given that,
The wavelength of electromagnetic radiation is 963.5 nm.
We need to find the energy of a photon with this wavelength.
The formula used to find the energy of a photon is given by :
\(E=\dfrac{hc}{\lambda}\\\\E=\dfrac{6.63\times 10^{-34}\times 3\times 10^8}{963.5\times 10^{-9}}\\\\E=2.06\times 10^{-19}\ J\)
So, the energy of a photon is \(2.06\times 10^{-19}\ J\).
what are two versions of genes called and how are they diffrent?
Answer with Explanation:
Different versions of a gene are called alleles. Alleles are described as either dominant or recessive depending on their associated traits. Since human cells carry two copies of each chromosome they have two versions of each gene.
करताह!
गर्मियों में घड़े का जल ठंडा क्यों होता है?
Answer:
I don't understand the question
Explanation:
what is your name
How many moles of chlorine atoms are there in 0.5 mol of titanium (III) chloride?
Answer:
it is your answer..... if it is helpful plzz like and comment.....
What can the flow of electrons be easily compared to?
a.The flow of mud
b.The flow of water
c.The flow of wind
d.The flow of gravity
How do we determine climate?
a
I have no idea
b
Precipitation and weather
c
Temperature and weather
d
Precipitation and temperature
Answer:
D but I’m traitor figure out y my question is precipitation helps determine climate by. Weathe. My options are The interaction of the prevailing winds upon land or oceans. The development of local storms. The passage of weather fronts. All of the above
Explanation:
Calculate the specific heat capacity of a metal if a 17.0 g sample requires 481 J to change the temperature from 25°C to 67°C
Answer:
The specific heat capacity of the metal is 0.529 J/g · C.
Explanation:
To calculate the specific heat capacity of a metal, you can use the following formula:
c = Q / (m * ΔT)
Where c is the specific heat capacity of the metal, Q is the amount of heat required to change the temperature of the metal, m is the mass of the metal sample, and ΔT is the change in temperature.
In your case, the amount of heat required to change the temperature of the metal is 481 J, the mass of the metal sample is 17.0 g, and the change in temperature is 67°C - 25°C = 42°C. Plugging these values into the formula, we get:
c = 481 J / (17.0 g * 42°C) = 0.529 J/g · C
Therefore, the specific heat capacity of the metal is 0.529 J/g · C.
The specific heat capacity can be calculated using the calorimetric equation. The specific heat capacity of the metal is calculated to be 0.67 J/ °C g.
What is specific heat capacity?The specific heat capacity of a substance is the heat energy required to rise its temperature by one degree celsius per one gram of the substance. It is an intensive property.
The calorimetric equation connecting the heat energy q to mass m, temperature difference ΔT and specific heat c is given below:
q = m c ΔT
Given mass = 17 g
heat energy q = 481 J
temperature difference = 67 - 25 = 42° C
Then c = 481 / (17 g × 42° C ) = 0.67 J/ °C g.
Therefore, the specific heat of the metal is 0.67 J/ °C g.
.
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1 answer
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The most accurate statement about signal transmissions among the given options is:
a) All signals in transmission will lose clarity with distance.
When a signal is transmitted over a distance, it can experience various types of degradation or attenuation. Factors such as distance, interference, noise, and the medium through which the signal travels can all contribute to a reduction in the clarity or quality of the signal. This means that as the distance between the source and receiver increases, the signal may become weaker, distorted, or prone to interference, resulting in a loss of clarity.
Limiting reactant question!
The limiting reactant is N₂O₄ and the mass of N₂ formed from the reaction is 45.7 g (Option C)
How do I determine the limiting reactant?The limiting reactant can be obtained as illusrated below:
N₂O₄ + 2N₂H₄ -> 3N₂ + 4H₂O
Molar mass of N₂O₄ = 92.02 g/molMass of N₂O₄ from the balanced equation = 1 × 92.02 = 92.02 gMolar mass of N₂H₄ = 32.05 gMass of N₂H₄ from the balanced equation = 2 × 32.05 = 64.1 g Molar mass of N₂ = 28.02 gMass of N₂ from the balanced equation = 3 × 28.02 = 84.06 gFrom the balanced equation above,
92.02 g of N₂O₄ reacted with 64.1 g of N₂H₄
Therefore,
50 g of N₂O₄ will react with = (50 × 64.1) / 92.02 = 34.83 g of N₂H₄
From the above calculation, we can see that only 34.83 g of N₂H₄ out of 45.0 g reacted.
Thus, the limiting reactant is N₂O₄
How do I determine the mass of N₂ formed?The limiting reactant shall be used in this case in order to obtain a maximum yield of N₂. Details below:
92.02 g of N₂O₄ reacted to produce 84.06 g of N₂
Therefore,
50 g of N₂O₄ will react to produce = (50 × 84.06) / 92.02 = 45.7 g of N₂
Thus, the mass of N₂ formed is 45.7 g
Therefore, the correct answer to the question is (Option C)
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The acid ionization constant, Ka, for propanoic acid, C2H5COOH, is 1.3x10-5.(a) Calculate the hydrogen ion concentration, [H+], in a 0.20-molar solution of propanoic acid.(b) Calculate the percentage of propanoic acid molecules that are ionized in the solution in (a).(c) What is the ratio of the concentration of propanoate ion, C2H5COO-, to that of propanoic acid in a buffer solution with a pH of 5.20?(d) In a 100.-milliliter sample of a different buffer solution, the propanoic acid concentration is0.35-molar and the sodium propanoate concentration is 0.50-molar. To this buffer solution,0.0040 mole of solid NaOH is added. Calculate the pH of the resulting solution
(a) The hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M. (b) 0.57%. (c) The ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(a) The balanced equation for the ionization of propanoic acid is:
C2H5COOH + H2O ⇌ C2H5COO- + H3O+
The equilibrium expression for this reaction is:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
At equilibrium, the concentration of propanoic acid that has ionized to form propanoate ion and hydronium ion is equal to the concentration of propanoic acid that has not ionized, so we can assume that [C2H5COO-] ≈ [H3O+]. Let x be the concentration of hydronium ion in the solution. Then the equilibrium expression becomes:
Ka = x^2 / (0.20 - x)
Solving for x, we get:
x = sqrt(Ka * (0.20 - x)) = sqrt(1.3x10^-5 * 0.20) = 1.14x10^-3 M
Therefore, the hydrogen ion concentration in the solution is [H+] = 1.14x10^-3 M.
(b) The percentage of propanoic acid molecules that are ionized in the solution is given by:
% ionization = [H3O+] / [C2H5COOH] x 100%
% ionization = (1.14x10^-3 / 0.20) x 100% = 0.57%
(c) The pH of a buffer solution can be calculated using the Henderson-Hasselbalch equation:
pH = pKa + log([C2H5COO-] / [C2H5COOH])
At pH 5.20, the hydronium ion concentration is 10^-5.20
= 6.31x10^-6 M.
Using the equilibrium expression for propanoic acid and the fact that [C2H5COO-] + [C2H5COOH] = total buffer concentration,
we can solve for the ratio of the concentrations of propanoate ion to propanoic acid:
Ka = [C2H5COO-][H3O+] / [C2H5COOH]
[C2H5COO-] = Ka[C2H5COOH] / [H3O+]
[C2H5COO-] = (1.3x10^-5)([C2H5COOH]) / (6.31x10^-6)
[C2H5COO-] / [C2H5COOH]
= 2.68
Therefore, the ratio of the concentration of propanoate ion to that of propanoic acid in the buffer solution is 2.68.
(d) When solid NaOH is added to the buffer solution, it reacts with the propanoic acid to form propanoate ion and water:
C2H5COOH + NaOH → C2H5COO- + H2O + Na+
The number of moles of propanoic acid that react with NaOH is equal to the number of moles of NaOH that were added. The new concentration of propanoic acid is:
0.35 M - (0.0040 mol / 0.100 L) = 0.346 M
The new concentration of propanoate ion is:
0.50 M + (0.0040 mol / 0.100 L) = 0.54 M
The new concentration of hydronium ion can be calculated using the equilibrium expression.
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The question is: What are the formulas for Ions and Compunds formed?
Ca, CL
Will mark Brainliest
Answer:
Ionic compounds are formed when positive and negative ions share electrons and form ionic bonds. The strong attraction between positive and negative ions often produces crystalline solids with high melting points. When there is a large difference in electronegativity between ions, ionic bonds are formed rather than covalent bonds. Cations, called cations, are listed first in the ionic compound formula, followed by negative ions, called anions.
Stable ionic compounds are electrically neutral in which electrons are shared between cations and anions to complete the outer electron shell or octant. When the positive and negative charges on the ions are the same or "cancel each other", you know you have the right formula for the ionic compound. Here are the steps to write and balance the formula: Identify the cation (the positively charged part). It is the weakest (most positively charged) ion. Cations include metals, which are usually on the left side of the periodic table. Identify anions (negatively charged moieties). It is the most negatively charged ion. Anions include halogens and nonmetals. Remember that hydrogen can carry a positive or negative charge in any way. Write the cation first, then the anion. Adjust the subscripts of the cations and anions so that the net charge is 0. Use the smallest integer ratio between the cations and anions to write the formula to balance the charges. If the cations and anions are of equal charge (eg +1/-1, +2/-2, +3/-3), then combine the cations and anions in a 1:1 ratio. An example is potassium chloride KCl. Potassium (K+) has a 1-charge, while chlorine (Cl-) has a 1-charge. Note that you don't write a subscript of 1. If the charges of the cation and anion are not equal, add subscripts to the ions as needed to balance the charges. The total charge of each ion is the subscript times the charge. Adjusted subscripts to balance charges. An example is sodium carbonate Na 2 CO 3 . The sodium ion has a +1 charge, multiplied by the subscript 2 gives a total charge of 2+. The carbonate anion (CO 3 -2 ) has a 2-charge, so there is no additional subscript. If you need to add a subscript to a polyatomic ion, enclose it in parentheses to clearly apply the subscript to the entire ion rather than individual atoms. An example is aluminum sulfate, Al 2 (SO 4 ) 3 . The parentheses surrounding the sulfate anion indicate that three 2-sulfate ions are required to balance 2 of the 3 charged aluminum cations.
Examples of ionic compounds
Many familiar chemicals are ionic compounds. A metal bonded to a non-metal is the death giveaway of an ionic compound you are dealing with. Examples include salts such as table salt (sodium chloride or NaCl) and copper sulfate (CuSO4).
How many grams of H2 would be formed if 34 grams of carbon reacted with an unlimited amount of H2O?
Answer:
The reaction between carbon (C) and water (H2O) forms carbon monoxide (CO) and hydrogen gas (H2). The balanced chemical equation for this reaction is:
C(s) + H2O(g) -> CO(g) + H2(g)
According to this balanced equation, one mole of carbon reacts with one mole of water to produce one mole of carbon monoxide and one mole of hydrogen gas.
First, calculate the number of moles of carbon in 34 grams. The molar mass of carbon is approximately 12.01 grams/mole.
Moles of carbon = 34 grams / 12.01 grams/mole = 2.831 moles
As the stoichiometry of the reaction shows a 1:1 ratio between carbon and hydrogen, the moles of hydrogen produced would also be 2.831 moles.
The molar mass of hydrogen (H2) is approximately 2 grams/mole.
So, the mass of hydrogen produced = 2.831 moles * 2 grams/mole = 5.662 grams
Therefore, if 34 grams of carbon reacts with an unlimited amount of water, approximately 5.66 grams of hydrogen gas would be formed.
Explanation:
Approximations followed for answer.
To test for a ammonia, which of these should be held over the test tube Group of answer choices dry red litmus paper dry blue litmus paper moist red litmus paper moist blue litmus paper
In order to test for ammonia, a moist red litmus paper should be held over the test tube containing the ammonia. Option 3.
Testing for ammoniaAmmonia is a substance that is alkaline in nature. All alkaline substances are able to turn red litmus paper to blue. This is in opposition to acidic substances that turn blue litmus paper to red.
Thus, the first test that can be used to determine if a substance is ammonia would be to hold a moist red litmus paper over the test tube containing the suspected substance.
Since ammonia is gas at room temperature, the substance suspected to be ammonia will diffuse from the test tube to turn the moist red litmus paper to blue.
Other methods to test for ammonia include passing a test tube containing hydrochloric acid over the test tube containing the substance. A white fume of ammonium chloride will confirm the presence of ammonia.
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10 kg of Phenanthrene is to be burnt with supplied air which is 30% less than the requirement. Find the exit gas stream average molecular weight and the leftover Phenanthrene amount in the reactor.
The exit gas stream has an average molecular weight of 29.0 g/mol and the amount of leftover Phenanthrene in the reactor is 5377 g.
How to calculate exit gas and leftover?Start by calculating the stoichiometric amount of air required to burn 10 kg of Phenanthrene. The balanced chemical equation for the combustion of Phenanthrene is:
C₁₄H₁₀ + 19O₂ → 14CO2 + 5H₂O
Therefore, to burn 10 kg (10000 g) of Phenanthrene:
nO₂ = 19 x (10000 g / 178.24 g/mol) = 1065.5 mol
So the actual amount of oxygen supplied will be:
nO₂, supplied = 0.7 x nO₂ = 745.9 mol
The amount of air required to supply this much oxygen can be calculated using the ideal gas law:
PV = nRT
where P = pressure, V = volume, n = number of moles, R = gas constant, and T = temperature.
Assuming standard temperature and pressure (STP):
P = 1 atm = 101.3 kPa
T = 273 K
R = 8.314 J/mol.K
The volume of air required is then:
Vair = nair × RT/P = (nO₂,supplied + nN₂,supplied) × RT/P
where nN₂,supplied = number of moles of nitrogen in the supplied air.
Since air is about 79% nitrogen by volume, assume that the number of moles of nitrogen is proportional to the number of moles of oxygen:
nN₂,supplied = (0.79/0.21) x nO₂,supplied = 2807.2 mol
Therefore,
Vair = (nO₂,supplied + nN₂,supplied) × RT/P
= (745.9 + 2807.2) × 8.314 × 273 / 101.3
= 63106 L
Calculate the average molecular weight of the exit gas stream using the ideal gas law again:
n = PV/RT
where n = number of moles of gas, P = pressure, V = volume, R = gas constant, and T = temperature.
Assuming that the combustion products are at the same temperature and pressure as the supplied air (STP):
nCO₂ = nH₂O = nO₂,supplied = 745.9 mol
nN₂ = nN₂,supplied = 2807.2 mol
The total number of moles of gas in the exit stream is then:
ntotal = nCO₂ + nH₂O + nN₂ = 745.9 + 745.9 + 2807.2 = 4298.0 mol
The volume of the exit stream can be calculated using the ideal gas law:
Vexit = ntotal × RT/P = 4298.0 × 8.314 × 273 / 101.3 = 36534 L
The average molecular weight of the exit gas stream is then:
M = mtotal/ntotal
where mtotal = total mass of gas in the exit stream.
Calculate mtotal by adding up the mass of each component in the exit stream:
mtotal = mCO₂ + mH₂O + mN₂
where mCO₂, mH₂O, and mN₂ = masses of carbon dioxide, water vapor, and nitrogen, respectively.
Calculate these masses using the molecular weights of the compounds and the number of moles:
mCO₂ = nCO₂ × MCO₂ = 745.9 × 44.01 g/mol = 32804 g
mH₂O = nH₂O × MH₂O = 745.9 × 18.02 g/mol = 13419 g
mN₂ = nN₂ × MN₂ = 2807.2 × 28.01 g/mol = 78617 g
Therefore,
mtotal = mCO₂ + mH₂O + mN₂ = 32804 + 13419 + 78617 = 124840 g
Substituting into the equation:
M = mtotal/ntotal = 124840 g/4298.0 mol = 29.0 g/mol
So the exit gas stream has an average molecular weight of 29.0 g/mol.
The leftover Phenanthrene amount can be calculated as follows:
mPhenanthrene,leftover = mPhenanthrene,initial - mCO₂ - mH₂O
where mPhenanthrene,initial = initial mass of Phenanthrene, which is 10 kg (10000 g).
Substitute these values into the equation:
mPhenanthrene,leftover = 10000 - 32804 - 13419 = 5377 g
Therefore, the amount of leftover Phenanthrene in the reactor is 5377 g.
Find out more on Phenanthrene here: https://brainly.com/question/31502620
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The freezing point is 18° C